The buoyant force on a helium balloon in air, if the balloon is spherical with a diameter of 28.5 cm, is 14.91 N.
To find the buoyant force on a helium balloon in air, we need to use the formula: FB = V * ρ * g where FB is the buoyant force, V is the volume of the object, ρ is the density of the fluid and g is the acceleration due to gravity. Here, the fluid is air. Given that the diameter of the spherical balloon is 28.5 cm. The radius is given by:
r = d/2 = 28.5/2 cm = 14.25 cm.
The volume of a sphere is given by the formula:
V = (4/3) * π * r³.
Substituting the values, we get:
V = (4/3) * π * (14.25)³ cm³= 11437.91 cm³.
We know that the density of air is approximately 1.29 kg/m³.
We convert the density of air to the appropriate units of cm³ as:
1 kg/m³ = 1 g/L = 1 g/cm³ = 0.001 g/cm³.
Hence, density of air in g/cm³ = 1.29 * 0.001 g/cm³ = 0.00129 g/cm³. The acceleration due to gravity, g = 9.8 m/s². We need to convert this to cm/s² as the remaining values are in cm and g. 1 m = 100 cm. Hence, g in cm/s² = 9.8 m/s² * 100 cm/m = 980 cm/s². Substituting the values in the formula: FB = V * ρ * g= 11437.91 * 0.00129 * 980 g.cm/s²= 14.91 N.
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The student continues to slowly increase the frequency of the sound waves emitted by the speaker without making any other changes to the setup. The student hears additional resonances at two higher frequencies, fi and f2.
As the frequency of the sound waves increases, the system reaches points where it exhibits resonance, which are the frequencies fi and f2.
Resonance occurs when the frequency of the sound waves matches the natural frequency of the system, causing it to vibrate more intensely and produce a louder sound.When the student slowly increases the frequency of the sound waves emitted by the speaker, they hear additional resonances at two higher frequencies, fi and f2.To learn more about frequency of the sound waves, visit:
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Less massive objects are measured in........
- grams
-mL
-Kg
Answer:
kg
Explanation:
Convert 74°F to °C using the following formula °C = 5/9 (°F-32)
Answer:
Your answer to your question is: 23.33333
( The decimal three is infinite :) )
How to convert fahrenheit to celsius?
First: To convert 74 f to c, you should remember that f equals a c minus 74 into 32 then multiply final value to 5/9.
Second: First, minus 74 into 32 and then finaly multiply to 5/9.
Third: Applying to formula - (74 - 32)*5/9 is equal to 23.33.
Fourth: Hence, the answer is 74 f = 23.33 c.
(sorry I'm bit late )
Thus, your answer is 23.33333
If it takes 50 j of energy to move 10 c of charge from point a to point b, what is the magnitude of the potential difference between points a and b?
Answer:
the magnitude will not be equal coz point a us greater than point B
Please help! This is due in 10 minutes!! I will mark brainliest asap
What is the height of the image? Round the answer
the nearest whole number.
Characteristic
Value
cm
What type of mirror most likely formed this image?
Focal length
13 cm
Distance of object from mirror
8 cm
Distance of image from mirror
-21 cm
Height of object
4 cm
Answer:
11 cm and concave
Explanation:
edge 2021
Answer:
it is -21, The top part is correct it is only the second part this is the first part.
Explanation:
A force of 100N acts on a body of mass 20kg. The force accelerates the body from rest until it attains a velocity of 20ms-1 . Through what distance the force acts?
Okay, let's break this down step-by-step:
* There is a force of 100N acting on the body.
* The mass of the body is 20kg.
* The body accelerates from rest to a velocity of 20ms^-1.
To calculate the distance over which this force acts:
1) Calculate the acceleration: Force / Mass = 100N / 20kg = 5ms^-2
2) Calculate the displacement (distance traveled) using: displacement = 1/2 * acceleration * time^2
Since the acceleration is constant, we can set the initial velocity to 0 and final velocity to 20ms^-1.
Then: time = (20ms^-1) / 5ms^-2 = 4s
3) Displacement = 1/2 * 5ms^-2 * 4s^2 = 20m
Therefore, the force of 100N acts on the body over a distance of 20m to accelerate it from rest to 20ms^-1.
Let me know if you have any other questions!
In the absence of friction, explain why the horizontal component of a projectile’s velocity is a constant.
Answer:
This downward force and acceleration results in a downward displacement from the position that the object would be if there were no gravity. The force of gravity does not affect the horizontal component of motion; a projectile maintains a constant horizontal velocity since there are no horizontal forces acting upon it
Go to the roller coaster simulation and click on the “launch” button. Pay attention to the pie chart as the roller coaster moves and fill in the blank. Be sure to keep this website open because there will be several questions related to it. The kinetic energy as the roller coaster goes downhill.
Answer:
increases
Explanation:
Answer:
increases
Explanation:
A bike is traveling at a speed of 15 m/s. The mass of the bike is 30 kg. What is the kinetic
energy of the bike?
Answer:
3375 JExplanation:
The kinetic energy of an object can be found by using the formula
\(k = \frac{1}{2} m {v}^{2} \\ \)
m is the mass
v is the velocity
From the question we have
\(k = \frac{1}{2} \times 30 \times {15}^{2} \\ = 15 \times {15}^{2} \\ = {15}^{3} \: \: \: \: \: \: \: \: \: \: \)
We have the final answer as
3375 JHope this helps you
I need help with my homework
Answer:
The answer is B.
Explanation:
This is because the loyalists did not agree with fighting back against Britain and wanted to remain a part of Britain, while the other answers show examples of people who wanted to break away from or rebel against Britain
Question 11
Drop a ball off of a roof that is 12.2 m above the ground.
How much time will it take for the ball to reach the ground?
1.58s
O-2.49s
O 1.6s
O2.49s
5
calculate the velocity of an object moved around a circle with a radius of 1.65m and an acceleration of 3.5 m/s^2
Answer:
2.4m/s
Explanation:
he atmosphere exerts a pressure of 14.7 lbf/in.2 on top of the 6-in.-diameter piston. the absolute pressure of the air inside the cylinder is 16 lbf/in.2 the local acceleration of gravity is g
The absolute pressure of the air inside the cylinder is 16 lbf/in
1.3psig.
A straightforward idea is pressure—the measurement of force in a certain space.
There are several approaches of comprehending the strain, nevertheless, depending on the query.
Here are some tips for differentiating pressure measurement types and units when describing when and why such pressure measurements are employed.
Calculate the mass of the piston by applying the equilibrium condition.
∑F_y=0
p_(air)A_(piston)- p_(atm)A_(piston)-m_(piston)g=0
(p_(air)-p_(atm))A_(piston)-m_(piston)g=0
m_(piston)=(p_(air)-p_(atm))A_(piston)/g ______(1)
Calculate the area of the piston,
A_piston= πD^2/4
=π×D^2/4
=π×6^2/4
=28.274 in^2
By substituting the value in m_(piston)=(p_(air)-p_(atm))A_(piston)/g
=(16.14.7 lbf/in.^2)(28.274 in.^2)/32.2 ft/s^2(32.2 ft/s^2/1lbf)
=36.756 lbm
b)
Calculate the gage pressure if the air,
p_(gage) = p_(abs)-p_(atm)
p_(gage)=16-14.7
=1.3psig
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How much work is needed to move an object 20 meters with 40 newtons of force?
a) 800 J
b) 850 N
c) 875 W
d) 825 m
Answer:
a) 800 J
Explanation:
Work is said to be done when a force induces movement over a distance in an object. The amount of work done (W) is calculated by multiplying the force by the distance traveled.
That is;
W = F × d
Where;
W = work done (J or N/m)
F = force (N)
d = distance (m)
In the information given in this question, F = 40N, d = 20m
Hence,
Work done = 40N × 20m
Work done = 800N/m or 800 J
A shopping cart is given an initial velocity of 4 m/s and experiences a constant acceleration of 4 m/s2. What is the magnitude of the cart’s displacement after the first 4 s of its motion?
Answer:
48m
Explanation:
Initial velocity = 4m/s Acceleration = 4m/s² Time = 4s Displacement = ?From Second equation of motion ,
\(\longrightarrow \) s = ut + 1/2at²
\(\longrightarrow \) s = 4*4 + 1/2*4*(4)² m
\(\longrightarrow \) s = (16 + 2 * 16) m
\(\longrightarrow \) s = ( 16 + 32 )m
\(\longrightarrow \) s = 48 m
water flowing through a garden hose of diameter 2.76 cm fills a 20.0-l bucket in 1.15 min. (a) what is the speed of the water leaving the end of the hose? incorrect: your answer is incorrect. m/s
The Speed of water flowing by 2.76 diameter is 0.1634m/s.
Given -
Diameter= 2.76cm
Amount = 20l
time= 1.15 min
The flow of water is continuous and remains unaffected with distribution of mass.
To compute the speed of the water leaving the end of the hose-
V= 2.76 + 1= 3.76cm
For 20 l equivalent length is 3.76cm
For 1 l equivalent length(x) = 3.76/20
x= 0.188
\(Speed = distance /time\)
= 0.188/1.15
=0.1634m/s
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Sometimes scientists gather information that contradicts accepted theories or explanations. if the new information is replicated many times, the accepted theory that it contradicts will often be updated or modified to reflect the new information. based on this, it can be determined that scientific knowledge is durable in part because a. new information on accepted theories is never discovered. b. experiments are never performed more than once. c. scientists ignore information that contradicts accepted theories. d. it is open to change as new information is learned.
Scientists occasionally gather data that deviates from conventional ideas or interpretations. The widely held idea that the new information contradicts will frequently be revised or changed to take into account the new information if it is repeatedly verified.
Empirical evidence is the foundation of scientific knowledge. It is strong and lasting since it is the end product of all the prior study and testing that was done. But science also acknowledges that all of this information is a product of human endeavor and that it may contain numerous errors. Therefore, once a new idea is discovered and repeatedly confirmed, scientific knowledge is adaptable enough to take it into account and evolve.
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Why would a flare be observed in visible light, when they are so much brighter in X-ray and ultraviolet light?
Answer:
Because it radiates a spectre of frequencies, this means that it radiates in a continuous range of frequencies, ones with more intensity (like x-ray and ultraviolet) and others with less intensity (like the visible light). While most of the radiation is not in the visible range, there still is a part of the radiation in the visible spectre. And while this part is not the most intense part, the radiation is so large that we can see a very bright visible light.
If an object was 1 mm across, how big would it be if it was magnified 10 times?
If an object was 1 mm across and it was magnified 10 times, it would be 10 mm across. Magnifying an object is essentially enlarging the object to make it appear bigger than it actually is.
The process of magnification is done by using a magnifying glass, microscope or telescope to focus the rays of light on the object. Magnification is used for various purposes such as reading, science, and even for entertainment.
For example, a magnifying glass can be used to closely observe the details of a small object, while a microscope can be used to study the structure of a cell. Similarly, a telescope is used to observe distant objects in the night sky. Magnification can also be used to create a magnified image of an object which can be viewed on a computer screen.
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Dua titik yang bermuatan listrik yang sama, mula-mula berjarak 5 cm dan saling tarik menarik dengan gaya 225 N. Agar kedua titik muatan tersebut gaya tarik menariknya menjadi 25 N, maka seharusnya jarak kedua titik muatan itu menjadi….
Answer:
15 cm
Explanation:
Dari pertanyaan yang diberikan di atas, diperoleh data sebagai berikut:
Gaya 1 (F₁) = 225 N
Jarak terpisah 1 (d) = 5 cm
Gaya 2 (F₂) = 25 N
Jarak terpisah 2 (d₂) =?
Kita dapat memperoleh persamaan yang berkaitan dengan gaya dan jarak muatan dua titik dengan menggunakan rumus berikut:
F = Kq₁q₂ / d²
Perbanyak silang
Fd² = Kq₁q₂
Menjaga Kq₁q₂ konstan, kita memiliki:
F₁d₁² = F₂d₂²
Dengan rumus di atas maka diperoleh jarak sebagai berikut:
Gaya 1 (F₁) = 225 N
Jarak terpisah 1 (d) = 5 cm
Gaya 2 (F₂) = 25 N
Jarak terpisah 2 (d₂) =?
F₁d₁² = F₂d₂²
225 × 5² = 25 × d₂²
225 × 25 = 25 × d₂²
5625 = 25 × d₂²
Bagilah kedua sisinya dengan 25
d₂² = 5625/25
d₂² = 225
Hitung akar kuadrat dari kedua sisi
d₂ = √225
d₂ = 15 cm
Oleh karena itu, muatan dua titik harus berjarak 15 cm untuk memiliki gaya tarik 25 N
What volume of 2. 00 M HCl in liters is needed to react completely (with nothing left over) with 0. 500 L of 0. 500 M Na2CO3
To react completely with 0.500 L of volume of 0.500 M Na2CO3, you would need 0.250 L of 2.00 M HCl.
Write down the balanced chemical equation for the reaction between HCl and Na2CO3:
2 HCl + Na2CO3 → 2 NaCl + H2O + CO2
Determine the stoichiometry of the reaction:
From the balanced equation, we can see that 2 moles of HCl react with 1 mole of Na2CO3.
Calculate the number of moles of Na2CO3:
Given that the volume of Na2CO3 solution is 0.500 L and the concentration is 0.500 M, we can use the formula:
Moles = Concentration × Volume
Moles of Na2CO3 = 0.500 M × 0.500 L = 0.250 moles
Use the stoichiometry to determine the number of moles of HCl needed:
According to the stoichiometry of the balanced equation, 1 mole of Na2CO3 reacts with 2 moles of HCl.
Therefore, to react with 0.250 moles of Na2CO3, we would need 2 × 0.250 = 0.500 moles of HCl.
Convert moles of HCl to volume:
Given that the concentration of HCl is 2.00 M, we can use the formula:
Volume = Moles / Concentration
Volume of HCl = 0.500 moles / 2.00 M = 0.250 L
Convert the volume to liters:
The final answer is 0.250 liters of 2.00 M HCl are needed to react completely with 0.500 L of 0.500 M Na2CO3.
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The can be obtained by using the balanced chemical equation: Na2CO3 + 2 HCl → 2 NaCl + H2O + CO2 Write the balanced chemical equation for the reaction.
Na2CO3 + 2 HCl → 2 NaCl + H2O + CO2
Calculate the number of moles of Na2CO3. Using the formula n = c × V, where n is the number of moles, c is the concentration, and V is the volume, we get:
n = c × V
= 0.500 M × 0.500 L
= 0.250 mol
Calculate the number of moles of HCl required.The balanced chemical equation shows that 2 moles of HCl react with 1 mole of Na2CO3. Hence, the number of moles of HCl required can be calculated as follows
:n(HCl) = 2 × n(Na2CO3)
= 2 × 0.250 mol
= 0.500 mol
Calculate the volume of 2.00 M HCl required.The number of moles of HCl required is 0.500 mol. Using the formula V = n/c, where V is the volume, n is the number of moles, and c is the concentration, we get:
V = n/c
= 0.500 mol ÷ 2.00 M
= 0.250 L
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What was the pythagoras known for.
Answer:
Pythagorean theorem
Explanation:
.
Answer:best known in the modern day for the Pythagorean Theorem
Explanation:Pythagoras himself came up with the theory that numbers are of great importance for understanding the natural world, and he studied the role of numbers in music. Although the Pythagorean theorem bears his name, the discoveries of the Pythagorean theorem and that the square root of 2 is an irrational number were most likely made after his death by his followers.
Hope this helps!! Brainlist?plz
give 3 examples that gives distance
Answer:
d(P1,P2) = (x2 x1)2 + (y2 y1)2 + (z2 z1)2. This can be proved by repeated application of the Pythagorean Theorem. Example The distance between P1 = (2,3,1) and P2 = (8,5,0) is d(P1,P2) = (8 2)2 + (5 3)2 + (0 1)2 = 36 + 64 + 1 = 101 10.05.
Explanation:
The body can get water from milk, juices, fruits, and vegetables.
Answer: yes it can but not enough to stay hydrated and keep your body going but you cant get water from milk lol
Explanation: hope this helpes
Answer:
Yes This would be True hope this helps
Explanation:
Juan rides his horse with a constant
speed of 18 km/h. How far can he travel
in 1/2 hour?
Answer:
He traveled 9km
Explanation:
To do this problem you need to use the equation which is Speed= distance/time and this problem gives you the speed which is 18 km/h and it gives you the time 1/2 hour so you write the equation 18= d/ 1/2 which his distance is 9km
If D=-5i +6j -3k and E= 7i +8j + 4k
Find D × E and show that D is perpendicular to E
To find the cross product of vectors D and E, we can use the formula:
D × E = (Dy * Ez - Dz * Ey)i - (Dx * Ez - Dz * Ex)j + (Dx * Ey - Dy * Ex)k
Given:
D = -5i + 6j - 3k
E = 7i + 8j + 4k
Calculating the cross product:
D × E = ((6 * 4) - (-3 * 8))i - ((-5 * 4) - (-3 * 7))j + ((-5 * 8) - (6 * 7))k
= (24 + 24)i - (-20 - 21)j + (-40 - 42)k
= 48i + 41j - 82k
To show that D is perpendicular to E, we need to demonstrate that their dot product is zero. The dot product is given by:
D · E = Dx * Ex + Dy * Ey + Dz * Ez
Calculating the dot product:
D · E = (-5 * 7) + (6 * 8) + (-3 * 4)
= -35 + 48 - 12
= 1
Since the dot product of D and E is not zero, it indicates that D and E are not perpendicular to each other. Therefore, D is not perpendicular to E.
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Which quantities are equal in a dynamic equilibrium?.
The quantities that are equal in a dynamic equilibrium include the rates of the forward and reverse reactions, as well as the concentrations of the reactants and products.
A dynamic equilibrium is defined as a situation in which the forward and reverse rates of a reaction are equal and the concentrations of the reactants and products remain constant. It is a state in which there is no further net change in the concentration of the reactants and products.
In a dynamic equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction. The concentrations of the reactants and products may not be the same numerical value, but their ratios are constant at equilibrium.
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What should be done in order to decrease the gravitational force between two objects?
O Decrease the distance between the two objects.
O Increase the mass of one of the objects.
O Increase the mass of both of the objects.
O Increase the distance between the two objects.
Answer:
Decrease the distance between the two objects
Increase the distance between the two objects to decrease the gravitational force between two objects.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
The gravitational constant, denoted by the capital letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's theory of general relativity.
f = Gmm/r²
Increase the distance between the two objects to decrease the gravitational force between two objects.
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What is the velocity of a car that travelled a total of 75 km north in 1.5 hrs?