what is the boiling point of 0.600 m lactose in water? (kb for water is 0.512°c/m)

The speed of light when it passes through the new type of glass is 2.04×10^8  m/s.

What is refractive index:

Refractive Index is a value calculated from the ratio of the speed of light in a vacuum to that in a second medium of greater density.

The refractive index variable is denoted by the letter ' n '.

Here,

The refractive index of a new type of glass is 1.47

n = 1.47

The speed of light in air is c = 3×10^8 m/s

The formula for refractive index:

where v is the speed of light in new type of glass.

Substituting the values into the equation,

1.47 = 3×10^8 / v

v = 3×10^8 / 1.47

v = 2.04 ×10^8  m/s

Hence,

the speed of light when it passes through the new type of glass is 2.04×10^8  m/s

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Stefan's law states that the total energy radiated by a blackbody depends on the fourth power of the temperature of the blackbody.What is Stefan's Law?Stefan's law is the relationship between the amount of energy emitted by a blackbody, also known as the spectral radiance of a blackbody, and the temperature of that body.

The law says that the total energy radiated by a blackbody depends on the fourth power of the temperature of the blackbody.Stefan's law is a fundamental principle in physics and thermodynamics. It was discovered by Austrian physicist Josef Stefan in 1879 and later developed by Ludwig Boltzmann.The equation for Stefan's law is:J = σT4Where J is the spectral radiance of a blackbody,

T is the temperature of the blackbody, and σ is a constant known as the Stefan-Boltzmann constant. The value of the Stefan-Boltzmann constant is 5.67 x 10-8 W/m2K4.Explanation:Stefan's law states that the total energy radiated by a blackbody depends on the fourth power of the temperature of the blackbody.

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The zeroth, first and second laws of  thermodynamics can be applied to a boiling water.

We know that the study of thermodynamics would have to do with the transfer of heat form one object to the other.

In this case, we know that water is boiling, it is going to attain a thermal equilibrium in line with the zeroth law of thermodynamics. Then the transfer of heat between the water and the environment can be accounted for by the first and the second laws of thermodynamics. We can not be able to apply the third laws of thermodynamics to the system of a boiling water.

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Answer:

The observer hears a loud sound

Explanation:

In order to know if the observer hears a loud or a quiet sound, you need to know if there is a constructive or destructive interference between the sound waves of the loudspeakers.

You first calculate the distance between the observer and the loudspeakers.

The distances are given by:

d1: distance to loudspeaker A = 2.10m

d2: distance to loudspeaker B

\(d_2=\sqrt{(3.20m)^2+(2.10m)^2}=3.827m\)

Next, you calculate the wavelength of the sound waves by using the following formula:

\(\lambda=\frac{v_s}{f}\)

vs: speed of sound =  343 m/s

f: frequency of the waves = 400Hz

λ: wavelength

\(\lambda=\frac{343m/s}{400Hz}=0.8575m\)

Next, you calculate the path difference between the distance from the observer to the loudspeakers:

\(\Delta d=3.827m-2.10m=1.727m\)

You obtain a constructive interference (loud sound) if the quotient between the wavelength of the sound and the difference path is an integer:

\(\frac{\Delta d}{\lambda}=\frac{1.727m}{0.857}\approx2\)

Then, there will be a constructive interference, and the sound who the observer hears is loud.

Answer:

The x-component of \(F_{3}\) is 56.148 newtons.

Explanation:

From 1st and 2nd Newton's Law we know that a system is at rest when net acceleration is zero. Then, the vectorial sum of the three forces must be equal to zero. That is:

\(\vec F_{1} + \vec F_{2} + \vec F_{3} = \vec O\) (1)

Where:

\(\vec F_{1}\), \(\vec F_{2}\), \(\vec F_{3}\) - External forces exerted on the ring, measured in newtons.

\(\vec O\) - Vector zero, measured in newtons.

If we know that \(\vec F_{1} = (70.711,70.711)\,[N]\), \(\vec F_{2} = (-126.859, 46.173)\,[N]\), \(F_{3} = (F_{3,x},F_{3,y})\) and \(\vec O = (0,0)\,[N]\), then we construct the following system of linear equations:

\(\Sigma F_{x} = 70.711\,N - 126.859\,N +F_{3,x} = 0\,N\) (2)

\(\Sigma F_{y} = 70.711\,N + 46.173\,N+F_{3,y} = 0\,N\) (3)

The solution of this system is:

\(F_{3,x} = 56.148\,N\), \(F_{3,y} = -116.884\,N\)

The x-component of \(F_{3}\) is 56.148 newtons.

The false statement among Imad's comments is D. "Electric field lines are most dense around objects with the greatest amount of charge." Therefore,  option D is correct.

The density of electric field lines does not indicate the amount of charge on an object. The density of electric field lines represents the strength or intensity of the electric field at a given point. Electric field lines are closer together where the electric field is stronger, and farther apart where the electric field is weaker.

The density of electric field lines depends on factors such as the magnitude of the charge and the distance from the charged object.

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Answer:

D

Explanation:

Trees are obviously effected from deforestation.

Pollution effects the things trees need to grow (water, air).

Reduction removes parts of the tree, some parts being needed.

Answer: D

Explanation:Trees are obviously effected from deforestation.

Pollution effects the things trees need to grow (water, air).

Reduction removes parts of the tree, some parts being needed.

The range of the shots(projectiles) will be around 131.65 meters when the point of the cannon is set to 20 degrees above level. 

To decide the run of the shots, we have to calculate the horizontal distance that the shots will travel.

Ready to utilize the taking after kinematic condition to fathom for the run:

\(R = (v^2/g) * sin(2θ)\)

Where:

R = run

v = starting speed (25 m/s)

g = increasing speed due to gravity (9.81 m/s²)

θ = point of the cannon (20 degrees)

Substituting the given values into the condition, we get:

\(R = (25^2/9.81) * sin(2*20)\)

R = 131.65 meters

In this manner, the run of the shots will be around 131.65 meters. 

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The evaporation of the jogger's sweat is a process that leads to an increase in the entropy of the surroundings. This is because when water evaporates, its molecules become more disordered and spread out, increasing the randomness of the system. However, the jogger's body experiences a decrease in entropy as it loses water in the form of sweat.

Overall, the change in entropy of the universe will depend on the relative magnitudes of these two opposing effects.

Without more information about the jogger's surroundings and the details of the evaporation process, it is not possible to determine the sign or magnitude of the entropy change. It is possible that the decrease in entropy of the jogger's body is more significant than the increase in entropy of the surroundings, leading to a negative change in entropy of the universe. Alternatively, the increase in entropy of the surroundings could be more significant, resulting in a positive change in entropy. Without more information, the answer is not able to be determined with the given information.

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The mass and weight of object on moon is 0.0138kg  and 0.0229kg .

Since force is a vector quantity, we must consider the direction in which it acts. There are two main types of frictional force: static force (Fst) and sliding force (Fsl). Normal forces (FN) produce these forces acting perpendicular to the direction of motion, although they act in the opposite direction to the object's motion.

It is equivalent to the weight of the object plus the extra weight. For example, pushing down on a block of wood on a table increases the normal force and thus the frictional force.

me=12Kg

ge=10

gm=10/6= 1.66

M=?

me ge =M gm

M=me ge/gm

M=120/1.66

M=0.0138kg

W=mg =0.0138 x 10kg

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When light travels in a certain medium and falls on the surface of another medium a part of it turns back in the same medium This phenomenon is called Reflection.

A wavefront may alter its course at an interface between two different media and return to the first medium, a phenomenon known as reflection. Common examples are the reflection of light, sound, and water waves.

Reflection of light refers to the occurrence where light strikes an item and bounces back off its surface. Examples: using a flat mirror to reflect. by a spherical mirror's reflection. There are essentially two types of reflection that apply to light. While diffuse reflection is caused by rough surfaces that tend to reflect light in all directions, specular reflection is described as light reflected off a smooth surface at a specific angle.

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The financial advantage of discontinuing the Beta product line would be a disadvantage of $9,840,000. The financial advantage of buying 100,000 units from the supplier instead of making them would be an advantage of $4,700,000.The financial advantage of buying 75,000 units from the supplier instead of making them would be an advantage of $3,525,000.

To calculate the financial advantage or disadvantage of discontinuing the Beta product line, we need to compare the costs and revenues associated with the current situation and the proposed scenario.

Currently, the company produces and sells 80,000 Betas and 100,000 Alphas. If the Beta product line is discontinued, the sales representatives can increase Alpha sales by 13,000 units.

In the current situation:

Revenue from Beta sales = 80,000 units × $162 = $12,960,000

Revenue from Alpha sales = 100,000 units × $240 = $24,000,000

Total revenue = $12,960,000 + $24,000,000 = $36,960,000

In the proposed scenario:

Increased Alpha sales = 113,000 units × $240 = $27,120,000

Therefore, the financial advantage or disadvantage can be calculated as:

Financial Advantage = Revenue in proposed scenario - Revenue in current situation

Financial Advantage = $27,120,000 - $36,960,000 = -$9,840,000

The financial advantage of discontinuing the Beta product line would be a disadvantage of $9,840,000.

To determine the financial advantage or disadvantage of buying 100,000 units from the supplier instead of making them, we need to compare the costs of production with the purchase cost from the supplier.

Cost of producing 100,000 Alphas:

Direct materials cost = 100,000 units × $35 = $3,500,000

Direct labor cost = 100,000 units × $48 = $4,800,000

Variable manufacturing overhead = 100,000 units × $27 = $2,700,000

Traceable fixed manufacturing overhead = 100,000 units × $35 = $3,500,000

Variable selling expenses = 100,000 units × $32 = $3,200,000

Common fixed expenses = 100,000 units × $30 = $3,000,000

Total cost of producing 100,000 units = $3,500,000 + $4,800,000 + $2,700,000 + $3,500,000 + $3,200,000 + $3,000,000 = $20,700,000

Cost of buying 100,000 units from the supplier = 100,000 units × $160 = $16,000,000

Therefore, the financial advantage or disadvantage can be calculated as:

Financial Advantage = Cost of producing - Cost of buying

Financial Advantage = $20,700,000 - $16,000,000 = $4,700,000

The financial advantage of buying 100,000 units from the supplier instead of making them would be an advantage of $4,700,000.

Similarly, to determine the financial advantage or disadvantage of buying 75,000 units from the supplier instead of making them, we follow the same calculations as in question 9, but with the quantities adjusted accordingly.

Cost of producing 75,000 Alphas:

Direct materials cost = 75,000 units × $35 = $2,625,000

Direct labor cost = 75,000 units × $48 = $3,600,000

Variable manufacturing overhead = 75,000 units × $27 = $2,025,000

Traceable fixed manufacturing overhead = 75,000 units × $35 = $2,625,000

Variable selling expenses = 75,000 units × $32 = $2,400,000

Common fixed expenses = 75,000 units × $30 = $2,250,000

Total cost of producing 75,000 units = $2,625,000 + $3,600,000 + $2,025,000 + $2,625,000 + $2,400,000 + $2,250,000 = $15,525,000

Cost of buying 75,000 units from the supplier = 75,000 units × $160 = $12,000,000

Therefore, the financial advantage or disadvantage can be calculated as:

Financial Advantage = Cost of producing - Cost of buying

Financial Advantage = $15,525,000 - $12,000,000 = $3,525,000

The financial advantage of buying 75,000 units from the supplier instead of making them would be an advantage of $3,525,000.

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Answer:

Climate scientists compare the tree growth records to local weather records. For locations where a good statistical match exists between tree growth and temperature or precipitation during the period of overlap, the ring widths can be used to estimate past temperature or precipitation over the lifetime of the tree.

Answer: In both ionic and molecular bonds, the resulting compound is stabilized because each atom's outer electronic orbital is full.

Explanation:

Molecular bonds are also called covalent bonds. A covalent bond is formed by sharing of electrons between two or more atoms.

For example, atomic number of hydrogen is 1 and atomic number of nitrogen is 7 (2, 5). In order to attain stability hydrogen atom needs to gain one electron whereas nitrogen needs to gain 3 electrons.

Hence, 3 atoms of hydrogen chemically combine with one atom of nitrogen by sharing electrons and thus it forms the compound \(NH_{3}\).

Ionic bonds are the bonds formed by transfer of electrons from one atom to another.

For example, atomic number of sodium is 11 (2, 8, 1) and atomic number of chlorine is 17 (2, 8, 7). In order to attain stability sodium needs to lose one electron whereas chlorine needs to gain one electron.

Hence, when sodium combines chemically with chloride then sodium will transfer its 1 valence electron to the chlorine atom and thus it forms the compound NaCl.

Therefore, we can conclude that in both ionic and molecular bonds, the resulting compound is stabilized because each atom's outer electronic orbital is full.

Answer:

D. 539,000 J

Explanation:

I got it right on edge 2022

Answer:

Photosynthesis is the process of using water, carbon dioxide and sunlight to produce sugar. The process of photosynthesis requires specialized cellular structures called chloroplasts to capture energy from the Sun and converted into chemical energy.

Explanation:

The correct answer is (d) - the two key starting assumptions of theoretical models of galaxy evolution are that (1) hydrogen and helium gas, along with dark matter, filled all of space and (2) some regions of the universe were slightly denser than others. These initial conditions set the stage for the formation of structures, including galaxies and clusters of galaxies, through the processes of gravitational collapse and star formation. The exact details of how these processes work and how they give rise to the observed properties of galaxies are the subject of ongoing research in astrophysics. However, the starting assumptions provide a framework for understanding the basic ingredients and forces at play in the evolution of the universe as a whole.
The correct answer to your question is option d: (1) Hydrogen and helium gas, along with dark matter, filled all of space and (2) some regions of the universe were slightly denser than others. These two key starting assumptions of theoretical models of galaxy evolution are essential for understanding how galaxies formed and evolved over time.

Initially, the universe was predominantly filled with hydrogen and helium gas, which are the lightest and most abundant elements, as well as dark matter. Dark matter, although not directly observable, is believed to make up a significant portion of the universe's total mass and plays a crucial role in the formation and evolution of galaxies.

The second assumption acknowledges that the distribution of these gases and dark matter was not perfectly uniform across the universe. Some regions were slightly denser than others. This uneven distribution led to the formation of gravitational potential wells, where matter began to accumulate and form into galaxies. Over time, as the universe expanded and cooled, these denser regions acted as the seeds for the formation of large-scale structures, including galaxy clusters and superclusters.

By considering these two key starting assumptions, theoretical models of galaxy evolution can accurately predict and explain the observed properties of galaxies and their distribution in the universe.

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A new pipe with a diameter of approximately 27.2 inches is required to triple the discharge capacity from 15 cfs to 45 cfs, assuming the same slope and roughness coefficient.

To determine the diameter of the new pipe required to triple the discharge capacity from 15 cfs to 45 cfs, we can use the Manning's equation. The equation relates the discharge capacity, cross-sectional area, hydraulic radius, slope, and roughness coefficient of the conduit to each other.

First, we can calculate the cross-sectional area and hydraulic radius of the existing 18-inch concrete conduit using the given values:

Cross-sectional area (A) = π/4 * d^2 = π/4 * (18/12)^2 = 1.767 ft^2

Hydraulic radius (R) = A/P = A/(2*(d/12)) = 1.767/(2*(18/12)) = 0.983 ft

where d is the diameter of the conduit.

Next, we can calculate the head loss due to friction, which is given by the formula:

hf = S * L

where S is the slope of the conduit and L is the length. In this case, S is given as 0.02 and L is unknown. We can use the Manning's equation to solve for L:

15 = (1.486/n) * (A * R^(2/3) * S^(1/2)) * (L^(1/2))

where n is the roughness coefficient, which is given as 0.013. Solving for L, we get:

L = (15/(1.486/0.013) * (1.767 * 0.983^(2/3) * 0.02^(1/2)))^2 = 431.3 ft

Now, we can use the continuity equation to calculate the cross-sectional area and hydraulic radius of the new pipe required to triple the discharge capacity. The continuity equation states that the flow rate (discharge capacity) remains constant between two sections of a conduit, so we have:

Q_old = Q_new

A_old * v_old = A_new * v_new

where v is the velocity of the flow.

Solving for A_new, we get:

A_new = A_old * (Q_new/Q_old) = 1.767 * (45/15) = 5.301 ft^2

Using the expression for hydraulic radius (R = A/P), we can solve for P_new, which is the wetted perimeter of the new pipe. For a circular pipe, P_new = π * d_new. Substituting this expression into the hydraulic radius equation, we get:

R_new = A_new/(π * d_new)

Substituting the values for A_new and R_new into the Manning's equation, we can solve for the new pipe's diameter (d_new):

Q_new = (1.486/n) * (A_new * R_new^(2/3) * S^(1/2))

45 = (1.486/0.013) * (5.301/(π * d_new) * R_new^(2/3) * 0.02^(1/2))

d_new = 27.2 inches

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One revolution of the propeller corresponds to a rotation of 2π radians, so that the propeller has an initial angular velocity of

10 rev/s = (10 rev/s) • (2π rad/rev) = 20π rad/s

The propeller thus has an angular velocity ω at time t of

ω = 20π rad/s - (2.0 rad/s²) t

so that at t = 40 s, its angular speed is reduced to

20π rad/s - (2.0 rad/s²) (40 s) = (20π - 80) rad/s

Convert this to a rotation rate by dividing this result by 2π :

(20π - 80) rad/s = ((20π - 80) rad/s) • (1/(2π) rev/rad) ≈ -2.73 rev/s

which would suggest that the propeller has started to turn in the opposite direction at a rate of 2.73 rev/s.

Answer:

Filtration is a method for separating an insoluble solid from a liquid. When a mixture of sand and water is filtered: the sand stays behind in the filter paper (it becomes the residue ) the water passes through the filter paper (it becomes the filtrate )

Explanation:

Listo!

The  Newton's second law and kinematics we find the answer is:

Kinematics studies the movement of the body, which is a vector magnitude for which stone in a horizontal circular motion must be subjected to an acceleration that changes the direction of the speed even when its magnitude is constant, this acceleration is called centripetal.

              a = v / r²

Where a is the acceleration, v the speed anf r the radius of circle

Newton's second law states that force is proportional to the mass of the body and its acceleration

             F = m a

Where the bold indicate vectors, F is the force , m tha mass and a the acceleration.

Using these two expressions we see that the stone is subjected to a force directed towards the center of the circle. When this force becomes zero (breaks the rope) there is nothing to change the direction of the velocity at the point of rupture and the stone must follow with this velocity tangential to the point of rupture of the rope.

This is expressed in Newton's first law, which says:

In conclusion, we use the  Newton's second law and kinematics when the rope breaks the body is nine with constant velocity and with a direction tangential to the trajectory at the point.

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Complete question is;

Margy is trying to improve her cardio endurance by performing an exercise in which she alternates walking and running 100.0 m each. If Margy is walking at 1.4 m/s and accelerates at 0.20 m/s² during one of the running portions, what is her final velocity at the end of the 100.0 m? Round your answer to the nearest tenth.

Answer:

6.5 m/s

Explanation:

We are told that she is walking at 1.4 m/s and accelerates at 0.20 m/s².

Thus;

Initial velocity; u = 1.4 m/s

Acceleration; a = 0.2 m/s²

Distance; s = 100 m

From Newton's equation of motion, we know that;

v² = u² + 2as

Where v is final velocity.

Thus;

v² = 1.4² + 2(0.2 × 100)

v² = 41.96

v = √41.96

v ≈ 6.5 m/s

The distance traveled by object 1 is greater than the distance traveled by object 2.

The shortest distance between two points is a straight line. More distance is covered when the path of motion is curved.

The distance traveled by each object at different time is compared as follows;

\(at \ t_ A , \ \ \ d_1>d_2 \ \ \ (d_2 = 0)\\\\at \ t_B, \ \ d_1 > d_2 \\\\at \ t_C, \ \ \ d_2 > d_1 \\\\at \ t_D \ \ \ d_1 = d_2\\\\at \ t_f \ \ \ d_2 > d_1 \ \ \ (d_1 = 0)\)

The major distinguishing distance traveled by each occurs at \(t_B\) and \(t_C\).

\(d_{(t_B)} > d_{(t_C)} \\\\d_1 > d_2\)

Thus, we can conclude that the distance traveled by object 1 is greater than the distance traveled by object 2.

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Answer:

Due to intense solar heating near the equator, the warm, moist air is forced up into the atmosphere like a hot air balloon.

Explanation:

Hope this helps you!

Answer:1500 calorie

Explanation:

Given

volume of water \(V=50\ ml\)

Initial temperature \(T_i=22^{\circ}C\)

Final temperature \(T_f=52^{\circ}C\)

We know,

specific heat of water is \(c=1\ calorie/gm-^{\circ}C\)

the density of water is \(\rho=1\ gm/ml\)

The heat required to raise the temperature

\(\Rightarrow Q=mc\Delta T\\\Rightarrow Q=\rho \cdot V\times c\times \Delta T\\\Rightarrow Q=1\times 50\times 1\times (52-22)\\\Rightarrow Q=1500\ cal.\)

1500 calories is required

Answer:

The air will stop pouring out of the hole in the tire when the pressure inside the tire is equal to atmospheric pressure

Explanation:

The question relates to equilibrium conditions

The given parameters are;

The condition of the pressure of the air in the tire, P = Pressurized, P > Atmospheric pressure

The pressurized air is let out of the tire through a hole made by a nail

Therefore;

When the pressure inside the tire is more than atmospheric pressure, the force per unit area of the air from the side of the hole inside the tire is more than the force per unit area acting in the opposite direction and the pressure forces the air out of the tire

Therefore, the air continues pouring out of the hole in the tire up to the point when the pressure inside the tire becomes equal to atmospheric pressure, at which point the force per unit area of the air on either side of the hole are equal.

For the same reason that you can skate around a curve at constant speed but not with constant velocity.

The DIRECTION you're going is part of your velocity, but it's not part of your speed.

If the DIRECTION changes, that's a change of velocity.

The object doesn't have to change speed to have a different velocity. A change of direction is enough to do it.

And any change of velocity is called acceleration.

Answer:

Which parental qualities promote healthy child development? Check all that apply.

patient

dependable

lenient

disciplined

wealthy

Explanation:

A, B, D