What is the average speed of a dancer who moves 4 meters across the stage in 16 seconds?

The x and y components of the sum of these two vectors are -1 unit and 4 unit respectively.

In physics, a vector is a quantity with both a magnitude and a direction. It is often represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity.

Given that the two vectors A and B have components (0, 1) and (-1, 3), respectively.

Hence,

The x component of the sum of these two vectors is = 0+ (-1)unit  = -1 unit.

the y component of the sum of these two vectors is = 1 + 3 unit  = 4 unit.

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Explanation:

Given that,

35 m/s at 57° from the x-axis.

Speed, v = 35 m/s

Angle, θ = 57°

Horizontal component,

\(v_x=v\cos\theta\\\\=35\times \cos(57)\\\\=19.06 m/s\)

Vertical component,

\(v_y=v\sin\theta\\\\v_y=35\times \sin(57)\\\\=29.35\ m/s\)

Hence, this is the required solution.

Answer:

i believe it would be C

Explanation:

Answer:

The correct option is b: 30 N.

Explanation:

First, we need to find the acceleration due to gravity (a):

\( y_{f} - y_{0} = v_{o}t - \frac{1}{2}a(\Delta t)^{2} \)   (1)

Where:

\(y_{f}\): is the final vertical position (obtained from the graph)

\(y_{0}\): is the initial vertical position (obtained from the graph)

v₀: is the initial speed = 0 (it is released from rest)

Δt: is the variation of time (from the graph)

From the graph, we can take the following values of height and time:

t₀ = 0 s → \(t_{f}\) = 5 s

y₀ = 300 m → \(y_{f}\) = 225 m

Now, by entering the above values into equation (1) and solving for "a" we have:

\( a = 2\frac{y_{0} - y_{f}}{(t_{f} - t_{0})^{2}} = 2\frac{300 m - 225 m}{(5 s - 0)^{2}} = 6 m/s^{2} \)

Finally, the weight of the object is:

\( W = ma = 5 kg*6 m/s^{2} = 30 N \)

Therefore, the correct option is b: 30 N.

I hope it helps you!                                                                                                            

Answer:

The height is the same

Explanation:

Because they were at the same height but they fell at different velocities

Answer:

reducing the voltage of electric current in the coil

Explanation:

Answer:

B. Movement of electrons

Hope this helps!! may I have brainliest? :)

Answer:

Movenment of electrons

Explanation:

Examples of following forces mentioned -

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Answer:

the answer is true.......

The measurement of length and time is calculated the average speed with the expression

         \(v_{avg} = \frac{\Delta x}{\Delta t}\)

Average velocity is defined as the change in displacement between the interval time

      \(v_{avg} = \frac{\Delta x}{\Delta t}\)

where \(v_{avg}\) is the average velocity, Δx is the displacement in the interval, and Δt the time.

To carry out this measurement, it must be taken into account that the velocity is a vector, for which we define a reference system, it can be a vertical axis with the upward direction as positive, therefore the downward displacement is negative.

A tape measure is placed and the interval during which the scalar distance measurement is performed is defined, the most as is to use time as an independent variable (controlled by the researcher) that is measured with a stopwatch.

The displacement is measured for each given time interval and these two quantities are divided. The sign of the velocity is negative because it goes down

Using the measurements of length and time, the average velocity is calculated with the expression

         \(v_{avg} = \frac{\Delta x}{\Delta t}\)t

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For this circuit, the voltage is 4.2 V. then power given is 0.9 W and receiving across 55Ω resistance is 0.07 W and that of 30Ω resistance is 0.14 W. Resistor are connected in parallel, its equvalent resistance is R₁R₂/R₁+R₂.

Both resistor are connected in parallel hence their equivalent resistance in parallel combination is given as,

R = 55*30/(55+30)

R = 19.4 Ω

Power given to the circuit is,

P = V²/R = 4.2/19.4 = 0.9 W

Receiving power taken from 55Ω resistor

P = V²/R = 4.2/55 = 0.07 W

Receiving power taken from 30Ω resistor

P = V²/R = 4.2/30 = 0.14 W

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\({ \qquad\qquad\huge\underline{{\sf Answer}}} \)

Here we go ~

So,

[ taking unit vector along north be \({ \sf \hat{j}} \) ]

[ taking unit vector along west be \({ \sf \hat{i}} \) ]

\( \qquad \dashrightarrow\sf \: V_{wr}= V_{w} - V_{r }\)

[ where \({ \sf V_{wr}= } \) Relative velocity of wind with respect to runner ]

\( \qquad \dashrightarrow\sf \: V_{wr}= - 3 \hat{ j} - ( - 4 \hat{i})\)

\( \qquad \dashrightarrow\sf \: V_{wr}= - 3 \hat{ j} + 4 \hat{i}\)

That is : 3 m/s towards south and 4 m/s towards east.

So, it makes an angle of 37° with south, and 53° with East.

[ The resultant is depicted by yellow arrow in attachment ]

\( \qquad \dashrightarrow\sf \: |V_{wr} | = \sqrt{3 {}^{2} + 4 {}^{2} }\)

\( \qquad \dashrightarrow\sf \: |V_{wr} | = \sqrt{9 + 16 }\)

\( \qquad \dashrightarrow\sf \: |V_{wr} | = \sqrt{25 }\)

\( \qquad \dashrightarrow\sf \: |V_{wr} | = 5 \: \: m/s\)

\( \dashrightarrow \sf \tan( \alpha) = \dfrac{b\: \sin \theta}{b + a \sin( \theta) } \)

\({\sf \theta }\) = angle between the two vectors ( along east and south) i.e 90°

\( \dashrightarrow \sf \tan( \alpha) = \dfrac{4\: \sin (90 \degree)}{3+ 4 \cos( 90 \degree) } \)

\( \dashrightarrow \sf \tan( \alpha) = \dfrac{4 \times 1}{3+( 4 \times 0)} \)

\( \dashrightarrow \sf \tan( \alpha) = \dfrac{4}{3} \)

\( \dashrightarrow \sf \alpha = \tan {}^{ - 1} \bigg( \dfrac{4}{3 } \bigg)\)

\( \dashrightarrow \sf \alpha = 53 \degree\)

So, it's direction is 53° east from south ~

Answer:

Option 1.

Explanation:

To know which option is correct, let us calculate the net force in each case to know which will move to the right direction.

Option 1:

Force to the right (Fᵣ) = 8 N

Force to the left (Fₗ) = 6 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 8 – 6

Fₙ = 2 N to the right

Option 2:

Force to the right (Fᵣ) = 8 N

Force to the left (Fₗ) = 10 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 10 – 8

Fₙ = 2 N to the left

Option 3:

Force to the right (Fᵣ) = 10 N

Force to the left (Fₗ) = 10 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 10 – 10

Fₙ = 0 (no movement)

Option 4:

Force to the right (Fᵣ) = 10 N

Force to the left (Fₗ) = 13 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 13 – 10

Fₙ = 3 N to the left

From the illustrations made above, only option 1 has a net force toward the right direction. Therefore, only option 1 will have an acceleration towards the right direction.

Answer:

Option 1

Explanation:

The amount the needle on the meter is deflected A. increases

This phenomenon can be explained by Faraday's law of electromagnetic induction. According to this law, when a magnetic field (created by the bar magnet) passes through a coil of wire, it induces an electric current in the wire. This induced current generates its own magnetic field, which interacts with the magnetic field of the bar magnet.

The deflection of the meter needle is a result of this induced current. When the number of coils of wire is increased, there is a greater number of wire loops for the magnetic field to pass through. This leads to a stronger induction of electric current, resulting in a larger deflection of the meter needle.

By increasing the number of coils, more magnetic flux is linked with the wire, resulting in a higher induced electromotive force (emf) and a greater current. This increased current produces a stronger magnetic field around the wire, leading to a larger deflection on the meter. Therefore, increasing the number of coils of wire enhances the magnetic field interaction, resulting in an increased deflection of the meter needle. Therefore, Option A is correct.

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Answer:

one beta particle

Explanation:

Since the atomic number of 131_I_53 increases by one to 131_Xe_54, we have the release of a beta particle since only a beta particle can cause a change in atomic number without a change in mass number. Since a beta particle is one electron, ₋₁⁰e, our nuclear equation is

¹³¹I₅₃ → ¹³¹X₅₄ + ₋₁⁰e

The atomic and mass numbers on both sides are balanced

mass number 131 = 131 + 0 = 131

atomic number 53 = 54 - 1 = 53

Thus a beta particle is emitted

Correct. When new user profiles are created, the default profile is utilised. Umama wants to configure Group Policy settings to enable User Experience Virtualization (UE-V).

You can enable or disable User Experience Virtualization using this Group Policy setting (UE-V). Only versions of UE-V 2.x and earlier are affected by this setting. Use the Enable UE-V setting in Wind ows 10, version 1607, for UE-V. The location of the settings template catalogue and the location of the settings storage location are two crucial settings that she must set up.

A programme called Micro soft UE-V (User Experience Virtualization) enables users to switch between Wind ows devices while keeping their current operating system (OS) and application settings.

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The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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Answer:a vertical expanse of water stretching between the surface and the floor of a body of water

Explanation:

Answer:

The answer should be A) 0m/s

Explanation:

It is stopped on the train tracks therefore it is not moving.

Please tell me if I am wrong because I'm not 100% sure on this. Hope it's right and that it helped you.

Although it is true that scientific models and hypotheses have been updated and improved over time, this is not sufficient justification to reject science as a whole or to doubt what scientists claim.

Models aid in our comprehension of systems and their characteristics. An atomic model, for instance, depicts what an atom's structure may like based on what is known about how atoms function. It may not accurately represent the precise makeup of an atom. Models are frequently condensed.

Over time, this atomic model has evolved. The model was used by scientists to make predictions. Their trials occasionally yielded unexpected outcomes that did not match the pre-existing model. The model was modified by scientists so that it could account for the fresh data.

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Speed of the rock at the bottom of the cliff is 44.3 m/s.

Kinetic energy of the rock at the bottom of the cliff is 4915 J.

Work done by air resistance is -2250 J

Average force exerted by the air on the rock is 11.25 N.

a) The speed of the rock at the bottom of the cliff can be calculated using the equation:

v = √(2gh)

where v = final velocity, g = acceleration due to gravity (9.81 m/s²), and h = height of the cliff (200 m).

Plugging in the values:

v = √(2 x 9.81 x 200) = 44.3 m/s

Therefore, the speed of the rock at the bottom of the cliff is 44.3 m/s.

b) The kinetic energy of the rock at the bottom of the cliff can be calculated using the equation:

KE = (1/2)mv²

where KE = kinetic energy, m = mass of the rock (5 kg), and v = velocity (44.3 m/s).

Plugging in the values:

KE = (1/2) x 5 x (44.3)² = 4915 J

Therefore, the kinetic energy of the rock at the bottom of the cliff is 4915 J.

c) The work done by air resistance can be calculated using the work-energy principle:

Work done by air resistance = KE_initial - KE_final

where KE_initial = initial kinetic energy of the rock, and KE_final = final kinetic energy of the rock (at terminal velocity).

Since the rock was initially at rest, its initial kinetic energy is zero. At terminal velocity, the kinetic energy of the rock is:

KE_final = (1/2)mv_terminal²

where m = mass of the rock (5 kg), and v_terminal = terminal velocity (30 m/s).

Plugging in the values:

KE_final = (1/2) x 5 x (30)² = 2250 J

Therefore, the work done by air resistance is:

Work done by air resistance = 0 - 2250 = -2250 J

The negative sign indicates that the work done by air resistance is in the opposite direction to the motion of the rock.

d) The average force exerted by the air on the rock can be calculated using the equation:

Work done by air resistance = Force x Distance

where Force = average force exerted by air on the rock, and Distance = distance travelled by the rock.

Rearrange the equation to solve for Force:

Force = Work done by air resistance / Distance

Plugging in the values:

Force = -2250 / 200 = -11.25 N

Therefore, the average force exerted by the air on the rock is 11.25 N. The negative sign indicates that the force is in the opposite direction to the motion of the rock.

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Answer:

Agricultural Engineer.

Agricultural Food Scientist.

Agricultural Inspector.

Agricultural Manager.

Agricultural Specialist.

They are;

Answer:

The kinetic energy = 2.35Mev

Explanation:

The standard value of the given mass of the elements are:

Mo= 1.007276U

Mn= 1.008665

M(Al)= 26.9815392u

We can now calculate Q

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

i) The initial deceleration of the car is -1.6 m/s² and  the time taken is 5 seconds

ii) The final deceleration is -1 m/s²

iii) The total dispalcement = 1016 m

The initial deceleration of the car is given by the formula below:

v² = u² + 2as

where;

Solving for a;

12² = 20² + 2 * a * 80

a = -1.6 m/s²

Time taken, t = v - u / a

t = 12 - 20 / (-1.6)

t = 5 seconds

Final deceleration:

a = v - u / t

a = 0 - 12 / 12

a = -1 m/s²

iii) Displacement at constant velocity = 12 * 1 * 60

Displacement at constant velocity = 720 m

Final displacement, s = ut + 0.5at²

s = 12 * 12 + 0.5 * 1 * 12²

s = 216 m

Total dispalcement = 80 + 720 + 216

Total dispalcement = 1016 m

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Answer:

True

Explanation:

Answer: 39.2m/s

Explanation:

Due to the free falling body, the acceleration of the ball is 9.8 m/s^2, and its initial velocity is 0 m/s.

V(t) = g*t

The change of velocity from t=1 to t=5:

Delta V = 9.8*(5-1) = 39.2 m/s

There are 36 ounces of yellow paint.

Both blue and yellow paint reflect intermediate wavelengths. Therefore, if you mix blue and yellow paint the mixture will appear green. I have found that blues and greens produce predominantly cyan or turquoise tones but mixing colors is never the right thing to do with darker or lighter grays.

Mixing blue and green makes him a tertiary color on the color wheel, teal. Blue-green is similar to turquoise or the color of the sea. This is one of the most common and popular tertiary colors. For a light aqua color mix cobalt blue with white. The primary colors are red blue and yellow. Primary colors cannot be mixed with other colors. They are the source of all other colors.

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