What is the average power necessary to move a 35 kg block up a frictionless 30° incline at 5 m/s? 68 W 121 W 343 W 430 W 860 W

If a sample contains 6911 joules of energy, the equivalent amount of energy expressed in terms of food calories is 1651 calories. One calorie is equivalent to 4.184 joules.

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Answer:

Length: meter

Volume: cubic meter

Mass: kilogram

Temperature: kelvin

Explanation:

Answer:

length = meter/m

mass = kilogram/kg

volume = cubic meter/m^3

temperature = kelvin/o K

Explanation:

SI unit and abbreviations

Mechanical ptosis of the left and right eyelids is reported with code(s) H02.413.

Ptosis, also called Blepharoptosis is characterized by the drooping of eyelids due to any abnormality associated with the structures that keep the eyelids elevated.

Ptosis is classified into congenital, aponeurotic, neurogenic, and mechanical ptosis. The illness results in drooping of the upper eyelid due to weight or mass.

It is also caused by many syndromes such as Horner's syndrome and Myasthenia Gravis.

The ICD-10 code is H02.413 which comes under the eye and adnexa category under the WHO. Thus, option A is correct.

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Answer:

\(E=5\times 10^{-5}\ J\)

Explanation:

Given that,

A spring is compressed by 0.1 cm or 0.001 m

The spring constant of the spring, k = 100 N/m

The elastic potential energy in the spring is given by :

\(E=\dfrac{1}{2}kx^2\\\\E=\dfrac{1}{2}\times 100\times 0.001^2\\\\E=5\times 10^{-5}\ J\)

So, the elastic potential energy of the spring is equal to \(5\times 10^{-5}\ J\).

The total magnetic field of the alpha particle will be = 1.974 x 10⁻⁴ T .

Magnetic field is a region around a magnetic material or a moving electric charge within which the force of magnetism acts.

Magnetic field due to moving charge =

\(B=\dfrac{\mu_oq}{4\pi}\times \dfrac{v}{r^2}\)

q is charge moving with velocity v and r is distance from point at which field is calculated .

For alpha particle

\(B_1=\dfrac{\mu_o}{4\pi}\times \dfrac{2\times 1.6\times 10^{-19]\times 2.8\times 10^{5}}}{(8.25\times 10^{-9})^2}}\)

= 0.1316 x 10⁻³ T

For electron

\(B_2=\dfrac{\mu_o}{4\pi}\times \dfrac{1.6\times 10^{-19}\times 2.8\times 10^{5}}{(8.25\times 10^{-9})^2}\)

= .0658 x 10⁻³ T .

Both these magnetic field will be same in direction because direction of equivalent current is same for both the particles .

Hence

Total magnetic field

= B₁ + B₂ = .1974 x 10⁻³

= 1.974 x 10⁻⁴ T .

Hence the total magnetic field of the alpha particle will be = 1.974 x 10⁻⁴ T .

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The resistance value of the multiplier resistor should be 3990 ohms.

To convert a galvanometer into a voltmeter, a multiplier resistor is connected in series with the galvanometer. The purpose of the multiplier resistor is to limit the current passing through the galvanometer and to scale the voltage being measured.

In this case, we want the maximum scale reading of the voltmeter to be 20V. The galvanometer has a full scale current of 50 and an internal resistance of 200 ohms.

To calculate the resistance value of the multiplier resistor, we can use Ohm's Law and the principle of voltage division. Ohm's Law states that V = IR, where V is the voltage, I is the current, and R is the resistance.

Since the maximum scale reading of the voltmeter is 20V, we can set up the equation as follows:

Vmax = Ic * (Rg + Rm)

Where Vmax is the maximum scale reading, Ic is the full scale current of the galvanometer, Rg is the internal resistance of the galvanometer, and Rm is the resistance of the multiplier resistor.

Substituting the given values, we have:

20 = 50 * (200 + Rm)

Simplifying the equation, we get:

Rm = (20 - 50 * 200) / 50

Calculating the value, we find:

Rm = -3990 ohms

However, resistance cannot be negative, so we take the absolute value:

Rm = 3990 ohms

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The answer is 76 Ω.  because it includes the derivation and calculation process.

To make a DC voltmeter with a maximum scale reading Vmax = 20V using a galvanometer with a full-scale current Ic = 50 and an internal resistance r = 200 ohms, we need a resistor Rm in series with the galvanometer.

The resistance value of this multiplier resistor Rm can be calculated as follows:Vmax = IRm + IcR Where,

Vmax = 20V,

Ic = 50,

R = 200 ohms

Rm = (Vmax - IcR)/I

=(20 - 50×200)/50

=-3800/50

=-76 ΩSo,

the resistance value of the multiplier resistor should be -76 Ω.

However, since it's impossible to have a negative resistor, the value of the resistor should be rounded off to 76 Ω. Hence, the answer is 76 Ω.  because it includes the derivation and calculation process.

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Answer: The answer is C. Find the slope of the tangent at any point.

(P4.33) A dielectric cube of side a, centered at the origin, carries a "frozen- in" polarization" P = kr, where k is a constant.(a)The total bound charge is given by Q_b, and since it is proportional to a^3, the bound charges will add up to zero only if k = 0. Otherwise, there will be a non-zero net bound charge.(P4.35)The total bound charge on the surface is given by Q_b, which is equal to -2χ_e q.

Problem 4.33, we have a dielectric cube of side length a centered at the origin. The polarization is given as P = kr, where k is a constant.

To find the bound charges, we need to consider the divergence of the polarization. The bound charge density, ρ_b, is given by:

ρ_b = -∇ · P

In this case, since P = kr, we can calculate the divergence:

∇ · P = ∂(krx)/∂x + ∂(kry)/∂y + ∂(krz)/∂z

= k + k + k

= 3k

Therefore, the bound charge density is:

ρ_b = -3k

To check if the bound charges add up to zero, we need to integrate the bound charge density over the volume of the cube:

Q_b = ∫∫∫ ρ_b dV

Since the polarization is "frozen-in" and the cube is centered at the origin, we can integrate over the volume of the cube:

Q_b = ∫∫∫ (-3k) dV

= -3k ∫∫∫ dV

= -3k (Volume of the cube)

= -3k (a^3)

The total bound charge is given by Q_b, and since it is proportional to a^3, the bound charges will add up to zero only if k = 0. Otherwise, there will be a non-zero net bound charge.

Problem 4.35, we have a point charge q embedded at the center of a sphere with linear dielectric material of susceptibility χ_e and radius R.

To find the electric field, polarization, and bound charge densities, we can use Gauss's Law for dielectric materials. The electric field inside the dielectric sphere is given by:

E = q / (4πε_0 χ_e R^2) * r

where r is the radial distance from the center.

The polarization, P, is related to the electric field by:

P = χ_e ε_0 E

Substituting the expression for E, we get:

P = χ_e q / (4πR^2) * r

The bound charge density, ρ_b, is given by:

ρ_b = -∇ · P

Since P only has a radial component, the divergence simplifies to:

∇ · P = ∂(χ_e q / (4πR^2) * r)/∂r

= χ_e q / (2πR^2)

Therefore, the bound charge density is:

ρ_b = -χ_e q / (2πR^2)

To find the total bound charge on the surface of the sphere, we integrate the bound charge density over the surface area:

Q_b = ∫∫ ρ_b dA

Since the bound charge is on the surface, we can integrate over the surface area of the sphere:

Q_b = ∫∫ (-χ_e q / (2πR^2)) dA

= -χ_e q / (2πR^2) ∫∫ dA

= -χ_e q / (2πR^2) (Surface area of the sphere)

= -χ_e q / (2πR^2) (4πR^2)

= -2χ_e q

The total bound charge on the surface is given by Q_b, which is equal to -2χ_e q. The negative bound charge is located on the surface of the sphere, compensating for the positive charge at the center.

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Answer:

96.04Pa

Explanation:

height=3.5m

gravity=9.8%

density=9.8/3.5

=2.8

Preassure=h×g×d

=3.5×9.8×2.8

=96.04Pa

Answer:

Democritus and Dalton has similar ideas about the atom, but Democritus based his theory more on reason than science. ... His ideas were similar to those of Democrites in that he believed that atoms were indivisible and that atoms of one substance are all alike but are different from atoms of another substance.

Explanation:

PLS MAKE ME AS BRAINLIST

Answer:

Democritus and Dalton has similar ideas about the atom, but Democritus based his theory more on reason than science. ... His ideas were similar to those of Democrites in that he believed that atoms were indivisible and that atoms of one substance are all alike but are different from atoms of another substance.

Explanation:

Answer:

Eccentricity is found by the distance from a focus to the center of an ellipse along the semi-major axis divided by the semi-major axis length.

Remember that the sun is always a focus point to a planet orbiting around the sun.

11)  The semi-major axis length is (180+220)/2 = 200

      220-200= 20 <= distance from focus to the center of the ellipse along the semi-major axis length

        e= 20/200 = 0.1

Here's the answer for the next question too :)

12)  (147.2+152.1)/2= 149.65

       152.1-149.65= 2.45

        e= 2.45/149.65 = 0.0164

Explanation:

yahoo answered these questions 8 years ago O.o

The eccentricity of the orbit of a planet whose distance from the sun varies from 180 million to 220 million km is 0.1.

A conic section's eccentricity is a non-negative real integer that defines its form. More precisely, two conic sections are comparable if and only if their eccentricities are the same. The eccentricity may be thought of as a measure of how much a conic section deviates from being circular.

Eccentricity is calculated by dividing the distance from a focus to the center of an ellipse along the semi-major axis by the length of the semi-major axis.

Since the sun is always the focal point for planets orbiting around the sun. Therefore, we can write,

The semi-major axis length = (180 +220) / 2

                                             = 200

Now, the length of the semi-major axis from the focus to the center of the ellipse is,

Length = 220 - 200 = 20

Further, the eccentricity can be written as,

e= 20/200 = 0.1

Hence,  The eccentricity of the orbit of a planet whose distance from the sun varies from 180 million to 220 million km is 0.1.

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Answer:

The answer is C Elastic energy

Explanation:

when a spring moves there is elastic energy traveling through it

Answer:

he is right it’s D

Explanation:

if u could not read his hand writing

Answer:

5730 yr

Explanation:

25  = 100 (1/2)^11460/x       where x = half life

.25 = (1/2)^11460/x

log .25 / log.5   = 11460/x

x = 5730 yr

Answer:

inductance and genorator

Explanation:

Inductance is the tendency of an electrical conductor to oppose a change in the electric current flowing through it. The flow of electric current creates a magnetic field around the conductor. The field strength depends on the magnitude of the current, and follows any changes in current.

in which electrical wave changed into mechanical wave

The statement that she can use to describe the characteristics of all types of forces is forces act in pairs. The correct option is A.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force.

The third law of motion by Newton states that equal but diametrically opposed forces always act in pairs.

There is an equal but opposite reaction to every action, to put it another way. This means that when you push against a wall, the wall pushes back against you with an equal amount of force.

Thus, the correct option is A.

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Light reflecting off an object in the environment follows a path that enters the eye and travels through the cornea, pupil, and lens, which help to focus the light onto the retina. The photoreceptors, including the rods and cones, then detect the light and convert it into electrical signals that are transmitted to the brain via the optic nerve.

Photoreceptors detect light reflecting off an object in the environment after the light enters the eye and travels through several structures. The cornea, pupil, and lens help to focus the light onto the retina, where the photoreceptors are located. The rods and cones, which are types of photoreceptors, then convert the light into electrical signals that can be processed by the brain. These signals are transmitted via the optic nerve, which connects the eye to the brain. The brain then interprets the signals to create a visual image of the object that reflected the light.

In conclusion, the path that light follows as it reflects off an object in the environment and is detected by photoreceptors involves several structures within the eye, including the cornea, pupil, lens, and retina. The photoreceptors then convert the light into electrical signals that are transmitted to the brain via the optic nerve. This process ultimately results in the brain creating a visual image of the object.

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After six half-lives, 1/64th (or 0.015625) of the original sample of radioactive atoms remains.

A fraction of 1/64 of the radioactive atoms remains after six half-lives. This is because the rate of decay of a radioactive material is exponential, meaning that each half-life will reduce the amount of radioactive atoms by half. After 6 half-lives, the amount of radioactive atoms remaining is 1/2 multiplied by itself 6 times, which equals 1/64.

The fraction of radioactive atoms is the fraction of atoms in a sample that are unstable and decaying. This fraction can be determined by measuring the rate of decay of the sample over time. The fraction is usually expressed as a percentage, and it is related to the half-life of the sample, which is the time it takes for half of the atoms in the sample to decay.

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The magnetic field strength required to scan the mass range between 16 and 300 for singly charged ions is 0.0398 T.

The magnetic field strength required to focus the ion at a particular mass-to-charge ratio is given by the equation:

B = (V × r) ÷ (B² × 2 × (mB ÷ q))

where V is the accelerating voltage, r is the radius of the magnetic sector, B is the magnetic field strength, m is the mass of the ion, and q is its charge.

Since we are dealing with singly charged ions, q = 1. We know the values of V₁ and B₁ for CH⁴⁺ ions. Therefore, we can use the above equation to find the radius r of the magnetic sector:

r = (V₁ × m) / (B₁² × 2 × q)

We can now use this value of r and the above equation to find the magnetic field strength B₂ required to scan the mass range between 16 and 300:

B₂ = The atomic mass of CH₄ is 16 u.

The ions with mass-to-charge ratio of 16 and 300 have masses of 16 u/q and 300 u/q, respectively.

For singly charged ions, we have

m ÷ q = mass ÷ charge = mass.

B₂ = √((V₁ × 16 u) ÷ (2 × r)) ÷ 1.00 + √((V₁ × 300 u) ÷ (2 × r)) ÷ 1.00

√((V₁ × m) ÷ (2 × q × r))

V₁ = 3.00 x 10³ V, B₁ = 0.126 T

Using the above equations, we can calculate the value of r:

r = (V₁ × m) / (B₁² × 2 × q)

= (3.00 x 10³ V × 16 u) / (0.126 T)² × 2 × 1

= 3.08 x 10⁻³ m

Substituting the values of r and V₁ in the equation for B:

B₂ = √((V₁ × 16 u) ÷ (2 × r)) ÷ 1.00 + √((V₁ × 300 u) ÷ (2 × r)) ÷ 1.00

B₂ = √((3.00 x 10³ V × 16 u) ÷ (2 × 3.08 x 10⁻³ m)) ÷ 1.00 + √((3.00 x 10³ V × 300 u) / (2 × 3.08 x 10⁻³ m)) ÷ 1.00

B₂ = 0.0398 T

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The complete question is:

When a magnetic sector mass spectrometer was operated with an initial accelerating voltage (V1) of 3.00 x 103 V, a magnetic field (B1) of 0.126 T was required to focus the CH4 + ion on the detector.

What magnetic field strength would be required to scan the mass range between 16 and 250 for singly charged ions if the accelerating voltage is held constant?

Answer:

Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system. Ideally, the device preserves the input power and simply trades off forces against movement to obtain a desired amplification in the output force. The model for this is the law of the lever.”

Explanation:

a person can pull approximately 60% of their own weight horizontally along the ground in good conditions. So if we need a 500 lb pull to get something done and we have a single groundman who weighs 200 lb and can therefore generate around 120 lb of pull, how can we accomplish this 500 lb pull? The simple answer is that the groundman can go find 4 or 5 good friends who are willing to drop everything and come and help him pull on the rope.

If a cube has a mass of 72.9 g and the dimension of the 3 cm side, its density would be

It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.

As given in the problem Use the data from the following figures to answer the questions below. The cube has a mass of 72.9 g and the cube has a dimension of 3 cm.

The volume of the cube = a³

                                        =3³

                                        =27 cm³

As given the mass of the cube is 72.9 g.

Density = mass/volume

              = 72.9 g/27 cm³

              =2.7 g/cm³

Thus, the density of the cube comes out to be 2.7 g/cm³.

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The question is incomplete the complete question is,

If a cube has a mass of 72.9 g and the dimension of the 3 cm side, What is its density in g/cm3?

Answer:

speed

Explanation: because formula for speed is distance over time

The ball was in the air for approximately 8.08 seconds.

Applying the kinematic equations of motion y = \(vi*t + (1/2)at^2\)

At the maximum height of the ball, its vertical velocity is zero.

0 = \(vi + at_m_a_x_v_i = -at_m_a_x\)

Since the ball was hit at an angle of 45°, we know that the initial velocity can be split into horizontal and vertical components:vix = \(vicos(45 degrees)viy = vi\sin(45 degrees)\)

The time it takes for the ball to reach its maximum heighty_max = \(viyt_m_a_x + (1/2)at_m_a_x^20 = viyt_max + (1/2)at_max^2t_m_a_x = viy/(-a)\)

Substituting in the values for vi and viy, we get:t_max =\((125 m)/(vi*sin(45 degrees))/(-9.8 m/s^2) = 4.04\)

applying the equation for the horizontal distance traveled by the ball:x = vix*twhere vix is the horizontal component of the initial velocity.

Substituting in the values for vix and t, we get:x = \((vi*cos(45 degrees))*t\)

Since the ball is in the air for the same amount of time in the horizontal and vertical directions, we can use the value of t_max we calculated earlier to find the total time the ball was in the air:t_total = 2*t_max = 8.08 s to find the horizontal distance traveled by the ball:x = (vi*cos(45°))t_total = \((vi\sqrt{(2)/2)} *t_t_o_t_a_l\)

Substituting in the values for vi and t_total, we get:x = (125 m)/(sin(45°)*(-a))*sqrt(2) = 456 m (rounded to three significant figures)

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The ball was in the air for approximately 17.95 seconds.

Using the given information, we can use the equations of projectile motion to find the time the ball was in the air. We know that the vertical component of the ball's initial velocity is equal to the horizontal component of the ball's initial velocity. We can use the formula t = 2 * (V * sin(angle)) / g where t is the time, V is the initial velocity, angle is the launch angle, and g is the acceleration due to gravity. Plugging in the values, we get:

t = 2 * (125m/s * sin(45°)) / 9.8m/s² = 2 * (88.39m/s) / 9.8m/s² ≈ 17.95s

Therefore, the ball was in the air for approximately 17.95 seconds.

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A lunar eclipse occurs when earth's shadow fall on moon.

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A massive and fast moving bowling ball must have a large momentum while a light and slow moving tennis ball must have a small momentum. However, a fast tennis ball may have the same momentum as a slow rolling bowling ball due to its high velocity. Given two objects of the same size but of different materials, the heavier (denser) object will fall faster because the drag and buoyancy forces will be the same for both, but the gravitational force will be greater for the heavier object.

\( \)

The abiotic, or non-living, variables, as well as the physical, biotic, or living, factors, determine the distribution of plants and animals on a worldwide scale.

Plants and animals have a wide range of tolerances for temperature extremes. Both physically and behaviorally, animals react to changes in temperature.

For instance, mammals and birds are hot-blooded creatures (endotherms), which means they use their own metabolism to generate heat to sustain relatively high body temperatures.

Other species (such as insects, reptiles, amphibians, and fish among others) are classified as cold-blooded (ectotherms), and they control their body temperatures by using the ambient temperature or the temperature of their surroundings.

Since various soils have varied mineral contents, water contents, microbes, etc., soil type affects the type and range of species that may develop in a certain location.

The global distribution of biomes is influenced by precipitation and mean temperature. Only creatures that can preserve water may be found in deserts, despite the fact that water is essential for vital processes.

Competitive interactions have been seen to be one of the major factors that diminish populations of plants and animals from their main habitats; plants and animals compete for space.

The strength and direction of energy flow within a system, the variety of communities, and the amount and dispersion of plant and animal species all depend on predation.

In the absence of interaction with one another, mutualism raises the equilibrium densities of the interacting species over their densities at carrying capacity.

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Answer:

do u have a picture of the question?

Explanation:

it would be easier to solve

The distance of dodo is 150 cm.

The distance between a lens's center and its focal point is its focal length. A focal point is a location on the principal axis where, following refraction via the lens, light rays parallel to the principal axis either actually meet or appear to meet.

Given parameters:

the focal length of David's lens is: f = 50 cm.

magnification is: m = -0.50

We have to find: distance of dodo, that is, object's distance : u = ?

We know that:

u =f( 1/m -1)

⇒ u = 50(-1/0.50-1) = - 150 cm.

Hence, distance  is 150 cm.

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20 m/sec fast would a 0.40 kg football have to be thrown to have a momentum of 8 kg m/s.

It is measured by "mass velocity," since momentum depends on velocity, and it also depends on the direction of the body's motion. Since velocity and mass are both scalar quantities, momentum is also a vector quantity.

Given that,

mass of football (m) = 0.40 kg

momentum (p) = 8 kg.m/sec

As we know,

p = mv

8 kg.m/sec = 0.40 kg × v

v = (8 kg.m/sec ÷ 0.40 kg)

v = 20 m/sec

Now, 20 m/sec fast would a 0.40 kg football have to be thrown to have a momentum of 8 kg m/s.

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