What is the atomic number of an atom?

Answer:

\(m=406.26g\)

Explanation:

Hello,

In this case, since the density is defined as the degree of compactness of a substance and it mathematically defined as the ratio of the mass and volume:

\(\rho = \frac{m}{V}\)

By knowing that its density is 1.11 g/mL, the mass in 366 mL is:

\(m=\rho V=366mL*1.11\frac{g}{mL}\\ \\m=406.26g\)

Regards.

The moles of NH4+ ions that are dissolved in 0.750 kg of H2O when the concentration of (NH4)3po4 ( ammonium phosphate) is 0.400 m is 0.9 mol

0.400 moles (NH4)3PO4 is dissolved in water.

So it is 0.4x0.75=0.3 mol (NH4)3PO4 in 0.75 kg water

1 mol (NH4)3PO4 contains 3 NH4+ ions .

So we have 0.3x3=0.9 mol NH4+ ions in 0.75 kg water

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Answer:

In order to figure out how many molecules of water are present in that  

48.90-g

sample, you first need to determine how many moles of water you have there.

As you know, a mole is simply a very large collection of molecules. In order to have one mole of something, you need to have exactly  

6.022

⋅

10

23

molecules of that something - this is known as Avogadro's number.

In order to get to moles, you must use water's molar mass. A substance's molar mass tells you the mass of one mole of molecules of said substance.

Water has a molar mass of  

18.015 g/mol

. This means that one mole of water molecules has a mass of  

18.015 g

.

So, to sum this up,  

6.022

⋅

10

23

molecules of water will amount to  

1 mole

of water, which in turn will have a mass of  

18.015 g

.

Explanation:

Answer:

\(pH=10.45\)

Explanation:

Hello,

In this case, for the dissociation of the given base, we have:

\(base\rightleftharpoons OH^-+CA\)

Whereas CA accounts for conjugated acid and OH⁻ for the conjugated base. In such a way, equilibrium expression is:

\(Kb=\frac{[OH^-][CA^+]}{[base]}\)

And in terms of the reaction extent \(x\) we can write:

\(1.6x10^{-6}=\frac{x*x}{0.05M-x}\)

For which the roots are:

\(x_1=-0.000284M\\x_2=0.000282M\)

For which clearly the result is the positive root which also equals the concentration of hydroxyl ions and we can compute the pOH:

\(pOH=-log([OH^-])=-log(0.000282)\\\\pOH=3.55\)

And the pH:

\(pH=14-pOH=14-3.55\\\\pH=10.45\)

Regards.

The pH of the solution is 10.45.

Let us represent codeine with the generic formula BH. We can set up the ICE table as follows;

              :B(aq) + H2O(l) ⇄ BH(aq)  + OH^-(aq)

I            0.05                        0                0

C           -x                            +x                +x

E        0.05 - x                      x                  x

We know that the Kb of codeine is 1.6 x 10^-6, Hence;

1.6 x 10^-6 = x^2/0.05 - x

1.6 x 10^-6 (0.05 - x ) =  x^2

8 x 10^-8 - 1.6 x 10^-6x =  x^2

x^2 +  1.6 x 10^-6x - 8 x 10^-8 = 0

x = 0.00028 M

The concentration of hydroxide ions = 0.00028 M

Given that pOH = - log[0.00028 M]

pOH = 3.55

pH + pOH = 14

pH = 14 - 3.55

pH = 10.45

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Yes, elements in the 7th period of the periodic table can experience the inert pair effect. The inert pair effect is observed when the valence s-electrons of heavier elements (particularly in Groups 13-15) are less likely to participate in chemical bonding compared to their p-electrons.

This effect becomes more pronounced as you move down the periodic table.In the 7th period, elements such as polonium (Po), astatine (At), and tennessine (Ts) exhibit the inert pair effect. This is due to the increasing size of the atoms and the relativistic effects that come into play at higher atomic numbers.

The increased size and relativistic effects cause the s-electrons to be more strongly influenced by the attractive force of the positively charged nucleus, making them less available for bonding.

As a result, elements experiencing the inert pair effect tend to exhibit oxidation states lower than what might be expected based on their position in the periodic table. This effect has significant implications for the chemical behavior and reactivity of these elements.

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Answer:

what is the question i don't understand

There are approximately 6.022 × 10^23 atoms in 12 grams of Carbon-12 (12C).

The number of atoms in a given amount of a substance can be calculated using Avogadro's number, which represents the number of atoms or molecules in one mole of a substance. Avogadro's number is approximately 6.022 × 10^23.

Carbon-12 is a specific isotope of carbon, with an atomic mass of 12 atomic mass units (amu). One mole of Carbon-12 has a mass of 12 grams. Since one mole of any substance contains Avogadro's number of particles, in the case of Carbon-12, it contains 6.022 × 10^23 atoms.

Therefore, if we have 12 grams of Carbon-12, which is equal to one mole, we can conclude that there are approximately 6.022 × 10^23 atoms in this amount of Carbon-12.

In summary, 12 grams of Carbon-12 contains approximately 6.022 × 10^23 atoms. Avogadro's number allows us to relate the mass of a substance to the number of atoms or molecules it contains, providing a fundamental concept in chemistry and enabling us to quantify and understand the microscopic world of atoms and molecules.

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Answer:

56.96 grams

Explanation:

To find the mass of 1.78 moles of O2, we need to use the molar mass of O2, which is the mass of one mole of O2.

The chemical formula for O2 is O-O or simply O2. The molar mass of O2 is the sum of the atomic masses of two oxygen atoms, which can be found on the periodic table.

The atomic mass of oxygen (O) is approximately 16.00 g/mol. So the molar mass of O2 is:

Molar mass of O2 = 2 x atomic mass of O

= 2 x 16.00 g/mol

= 32.00 g/mol

Therefore, the mass of 1.78 moles of O2 is:

Mass = number of moles × molar mass

= 1.78 mol × 32.00 g/mol

= 56.96 g

So the mass of 1.78 moles of O2 is 56.96 grams.

Answer:

B. ΔG > 0, Q > K

Explanation:

For reverse reaction to take place Q should be greater than K

Since reverse reaction should be spontaneous, forward reaction should be non spontaneous.

So, for forward reaction, ΔG > 0

Hence, the correct answer is B

Answer:

A. The reaction shifts to the right (products) and the concentrations of I and H₂ decrease.

Explanation:

If gas is removed from the system at equilibrium, the system will try to compensate for the loss by shifting the reaction in a direction that produces more gas molecules. This is known as Le Chatelier's principle, which states that a system at equilibrium will respond to a disturbance by shifting in a way that minimizes the effect of the disturbance.

In this case, since gas is being removed from the system, the reaction will shift to the side that produces more gas molecules. Looking at the balanced equation, we can see that 2HI(g) has a greater number of gas molecules compared to H₂(g) and I₂(g). Therefore, the system will shift to the right (products) to produce more HI(g) and reestablish equilibrium.

Answer

Na₂CO₃

Procedure

Considering the equation: CaCO₃(s) ↔ Ca₂(aq) + CO₂

The common-ion effect is used to describe the effect on an equilibrium when one or more species in the reaction are shared with another reaction. This effect will be based on Le Chatelier's principle.

In this case, a common ion will be the carbonate ion, which is a polyatomic ion with the formula of CO₃²⁻. This will come from the Na₂CO₃.

Given that the effect is affecting the reagent, the equilibrium will shift towards the products.

To determine the number of moles of gas in the sample, we can use the Ideal Gas Law: PV = nRT

n = PV/RT

n = (1.99 atm)(85.81 L) / (0.0821 Latm/(molK) * 397.15 K)

n = 6.51 moles

Therefore, there are 6.51 moles of gas in the sample.

An ideal gas is a theoretical gas composed of randomly moving point particles not subject to intermolecular interactions.

The ideal gas law describes the behavior of ideal gases, which relates the pressure, volume, temperature, and number of moles of a perfect gas. Natural gases do not strictly obey the ideal gas law, particularly at high pressures and low temperatures where intermolecular interactions become significant.

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The concentration of Fe²⁺ in a sample with an absorbance of 0.872, determined through the calibration curve \(y = 0.0042x + 0.012\), is 205 µg/dL.

In many analytical techniques, it is common to prepare calibration curves from standard solutions to determine the concentration of an unknown analyte. In this problem, we want to determine the concentration of Fe²⁺ and the following linear regression is made:

\(y = 0.0042x + 0.012\)

where,

The concentration of Fe²⁺ in a sample with an absorbance of 0.872 is:

\(y = 0.0042x + 0.012\\x = \frac{y - 0.012}{0.0042} = \frac{0.872 - 0.012}{0.0042} = 205 \mu g/dL\)

The concentration of Fe²⁺ in a sample with an absorbance of 0.872, determined through the calibration curve \(y = 0.0042x + 0.012\), is 205 µg/dL.

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The concentration of chloride ions when 2.5 g of FeCl is dissolved in 150 mL of water is approximately 0.54 M.

To determine the concentration of chloride ions when 2.5 g of FeCl is dissolved in 150 mL of water, we need to consider the molar mass of FeCl and perform some calculations.

The molar mass of FeCl is 55.85 g/mol (for iron) + 35.45 g/mol (for chlorine), which gives a total molar mass of 91.3 g/mol for FeCl.

First, we need to calculate the number of moles of FeCl present in 2.5 g of the compound. This can be done using the formula:

moles = mass / molar mass

moles of FeCl = 2.5 g / 91.3 g/mol = 0.027 moles

Next, we convert the volume of water from milliliters (mL) to liters (L):

volume of water = 150 mL = 150/1000 L = 0.15 L

Now, we can calculate the concentration of chloride ions (Cl-) using the formula:

concentration (Cl-) = moles of Cl- / volume of water

Since FeCl dissociates into one Fe3+ ion and three Cl- ions, the number of moles of Cl- is three times the moles of FeCl:

moles of Cl- = 3 * moles of FeCl = 3 * 0.027 moles = 0.081 moles

concentration (Cl-) = 0.081 moles / 0.15 L = 0.54 M.

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Since Na2SO4 + 2CuSO4 = 2NaSO4 + Cu2SO4 has an equal number of each element in its reactants and products, the equation is balanced.

A chemical equation that is balanced has the same number of each type of atom on both sides of the equation. Subscripts are a component of the chemical formulas for the reactants and products that show how many atoms of the previous element there are in each.

Count the atoms on each side first. Next, alter one of the compounds' coefficients. Finally, count the atoms once more, and then repeat steps two and three until the equation is balanced.

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The average atomic mass of titanium on the given planet is approximately 46.68164 atomic mass units (u). The average atomic mass may vary depending on the specific isotopic composition of titanium found on different celestial bodies or regions.

To calculate the average atomic mass of titanium on the given planet, we need to consider the natural abundances and masses of each isotope of titanium.

The average atomic mass is calculated by multiplying the natural abundance of each isotope by its respective mass and summing them up.

Let's perform the calculation step by step:

Step 1: Multiply the abundance of each isotope by its mass:

(73.700% * 45.95263 u) + (15.000% * 47.94795 u) + (11.300% * 49.94479 u)

Step 2: Calculate the individual contributions from each isotope:

= (0.737 * 45.95263) + (0.150 * 47.94795) + (0.113 * 49.94479)

Step 3: Add up the individual contributions:

= 33.84765431 + 7.1921925 + 5.64179347

Step 4: Sum up the contributions:

= 46.68164 u

Therefore, the average atomic mass of titanium on the given planet is approximately 46.68164 atomic mass units (u).

It's important to note that the calculation assumes the provided natural abundances are accurate and representative of the titanium isotopes on that planet.

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The given statement " The reaction 2NaOH(s) —> Na₂O(s) + H₂O(g) is a combustion reaction is false as it is the decomposition reaction.

The decomposition reaction can be explained as the chemical reaction in which the one reactant will breaks down into the two or the more products. The Decomposition reaction is the processes in the reaction the chemical species will break into the simpler parts. the, decomposition reactions require the energy input.

The general representation of the equation of the decomposition reaction is as :

AB → A + B.

The chemical equation is :

2NaOH(s) —> Na₂O(s) + H₂O(g)

This is called as the decomposition reaction.

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Answer:

An alloy is a homogeneous mixture

Explanation:

D

An alloy, a metallic substance composed of two or more elements, as either a compound or a solution is a homogeneous mixture. The correct option is d.

An alloy is a mixture of chemical elements of which at least one is a metal. Unlike chemical compounds with metallic bases, an alloy will retain all the properties of metal in the resulting material, such as electrical conductivity, ductility, opacity, and lustre, but may have properties that differ from those of pure metals, such as increased strength or hardness.

In some cases, an alloy may reduce the overall cost of the material while preserving important properties. In other cases, the mixture imparts synergistic properties to the constituent metal elements such as corrosion resistance or mechanical strength. Alloys are defined by a metallic bonding character. The alloy constituents are usually measured by mass percentage for practical applications, and in atomic fraction for basic science studies.

Alloys are usually classified as substitutional or interstitial alloys, depending on the atomic arrangement that forms the alloy.

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Answer:

6.78 × 10⁻³ L

Explanation:

Step 1: Write the balanced equation

Mg₃N₂(s) + 3 H₂O(g) ⇒ 3 MgO(s) + 2 NH₃(g)

Step 2: Calculate the moles corresponding to 10.2 mL (0.0102 L) of H₂O(g)

At STP, 1 mole of H₂O(g) has a volume of 22.4 L.

0.0102 L × 1 mol/22.4 L = 4.55 × 10⁻⁴ mol

Step 3: Calculate the moles of NH₃(g) formed from 4.55 × 10⁻⁴ moles of H₂O(g)

The molar ratio of H₂O to NH₃ is 3:2. The moles of NH₃ produced are 2/3 × 4.55 × 10⁻⁴ mol = 3.03 × 10⁻⁴ mol.

Step 4: Calculate the volume corresponding to 3.03 × 10⁻⁴ moles of NH₃

At STP, 1 mole of NH₃(g) has a volume of 22.4 L.

3.03 × 10⁻⁴ mol × 22.4 L/mol = 6.78 × 10⁻³ L

The temperature increase from 20 °C to 46 °C indicates that the reaction between zinc and copper sulfate solution is exothermic, with heat being released into the surroundings.

In the given reaction between zinc and copper sulfate solution, the temperature change can provide insights into the type of heat change occurring during the reaction. Based on the provided information, the initial temperature of the copper sulfate solution was 20 °C, and the final temperature of the mixture after the reaction was 46 °C.

The temperature increase observed in this reaction indicates an exothermic heat change. An exothermic reaction releases heat energy into the surroundings, resulting in a temperature rise. In this case, the reaction between zinc and copper sulfate solution is exothermic because the final temperature is higher than the initial temperature.

During the reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper metal. This displacement reaction is known as a single displacement or redox reaction. Zinc is more reactive than copper and therefore replaces copper in the compound.

The formation of new chemical bonds during the reaction releases energy in the form of heat. This energy is transferred to the surroundings, leading to an increase in temperature. The heat released is greater than the heat absorbed, resulting in a net increase in temperature.

The exothermic nature of this reaction can be explained by the difference in bond energies between the reactants and products. The breaking of bonds in the reactants requires energy input, while the formation of new bonds in the products releases energy.

In this case, the energy released during the formation of zinc sulfate and copper metal is greater than the energy required to break the bonds in copper sulfate and zinc.

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The electronic configuration which represents a transition element is 1s²2s²2p⁶3s²3p⁶4s²3d⁷

Transition elements are placed between the metallic S-block elements and nonmetallic P-block elements in the periodic table. They are D-block elements and have features similar to both metals and nonmetals, to some extent. This is why they are called transition elements.

One remarkable feature of these elements happens during the addition of electrons to them. Contrary to S and P-block elements, electrons are added to the penultimate shell, not the last shell. These elements often feature partially filled d-orbitals and have multiple oxidation states.

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Answer:

Explanation:

Answer:

V=2.33361811192L or 2.3x10

Explanation:

Using Charles law V1/T1=V2/T2 Remember to convert celcius to kelvin by using the standard temperature 273.15K

3L/(78C+273.15)=V/273.15

Answer:

\(0.004058 = 40.58 \times {10}^{ - 4} \\ thank \: yo\)

Answer:

12.8 g

Explanation:

Step 1: Write the balanced neutralization reaction

Al(OH)₃ + 3 HCl ⇒ AlCl₃ + 3 H₂O

Step 2: Calculate the moles corresponding to 17.9 g of HCl

The molar mass of HCl is 36.46 g/mol.

17.9 g × 1 mol/36.46 g = 0.491 mol

Step 3: Calculate the moles of Al(OH)₃ that completely react with 0.491 moles of HCl

The molar ratio of Al(OH)₃ to HCl is 1:3. The reacting moles of Al(OH)₃ are 1/3 × 0.491 mol = 0.164 mol

Step 4: Calculate the mass corresponding to 0.164 moles of Al(OH)₃

The molar mass of Al(OH)₃ is 78.00 g/mol.

0.164 mol × 78.00 g/mol = 12.8 g

Coenzyme q carries electrons from complex I to complex III  and complex II to complex III  in the electron-transport chain.

Coenzyme q  (CoQ), also known as ubiquinone, is the electron carrier in the electron transport system (ETS) present on the inner membrane of mitochondria.

Ubiquinone is a ubiquitous quinone, which accepts electrons from complex II ( succinate dehydrogenase) and  reduces to ubiquinol ( reduced form)

The purpose of the ETS is to generate an H+ ion concentration, by carrying electrons obtained from NADH AND \(FADH_{2}\)   produced by the Krebs cycle and glycolysis in the mitochondrial matrix. This  H+ ion potential will be used by ATP synthase to generate ATP.

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The inner mitochondrial membrane contains CoQ, a key part of the mitochondrial electron transport chain (ETC), which moves electrons from complexes I and II to complex III to provide energy for proton translocation to the intermembrane gap.

An organelle called a mitochondrion can be found in the cells of the majority of Eukaryotes, including mammals, plants, and fungi. Adenosine triphosphate, which is produced by aerobic respiration in mitochondria with their double membrane structure, is used as a source of chemical energy throughout the entire cell.

Coenzyme Q10 takes electrons from reducing equivalents produced during the metabolism of fatty acids and glucose and then transports them to electron acceptors as part of the mitochondrial electron transport chain.

Ubiquinone, also known as coenzyme Q, is a lipophilic molecule that is found in all tissues and cells and is mostly found in the inner mitochondrial membrane. It is generally known that Coenzyme Q is an essential part of the oxidative phosphorylation process in mitochondria.

Thus, The inner mitochondrial membrane contains CoQ, a key part of the mitochondrial electron transport chain (ETC).

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