What is the area of the square?
5 cm
200 cm?
O 100 cm
O 25cm
2
O 60cm
I need how you did it too

9514 1404 393

Answer:

Step-by-step explanation:

Let t represent the number of touchdowns scored. Then 35-t is the number of field goals, and the total score is ...

  7t +3(35 -t) = 193

  4t = 88 . . . . . . . . . . simplify, subtract 105

  t = 22

  35 -t = 13

The team scored 22 touchdowns and 13 field goals.

The zeros of the polynomial are: x = 1/2 (with multiplicity 1), x = 3 (with multiplicity 1), and x = 5/2 (with multiplicity 1).We have found all three real zeros of the polynomial, which confirms that there are no complex zeros.

f(x) = 2x³ - 112x² + 27x - 41x + 15

To find the zeros and their multiplicities of this polynomial, we can begin by using Descartes' Rule of Signs. Let's consider the sign changes in the coefficients:

There are 2 sign changes in the coefficients (from 2x³ to -112x² and then to 27x, and finally to -41x and 15), which means there are either 2 or 0 positive real zeros.

There are no sign changes when we replace x with -x, which means there are either 0 or 2 negative real zeros.

Thus, there can be either 0, 2, or 4 real zeros, but we cannot determine their exact number or location with Descartes' Rule of Signs alone.

Next, we can use the Upper and Lower Bound Theorem to limit our search for rational zeros. According to this theorem, any rational zero of the polynomial must be of the form p/q, where p is a factor of the constant term (15 in this case) and q is a factor of the leading coefficient (2 in this case). Therefore, the possible rational zeros of the polynomial are:

±1/2, ±1, ±3/2, ±5, ±15/2, ±30

We can use synthetic division or long division to check these possible rational zeros and see which ones are actually zeros of the polynomial. Doing so, we find that the rational zeros of the polynomial are:

x = 1/2 (with multiplicity 1), x = 3 (with multiplicity 1), and x = 5/2 (with multiplicity 1).

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The second ladder touches the wall approximately 11 feet higher than the shorter ladder, or equivalently, around 8 feet 8 inches higher.

Let's denote the height at which the second ladder touches the wall as h. We can set up a proportion based on the similar right triangles formed by the ladders and the building:

(6 6 feet) / (h) = (9 9 feet) / (5 5 feet 9 9 inches + h)

To solve for h, we can cross-multiply and solve the resulting equation:

(6 6 feet) * (5 5 feet 9 9 inches + h) = (9 9 feet) * (h)

Converting the measurements to inches:

(66 inches) * (66 inches + h) = (99 inches) * (h)

Expanding and rearranging the equation:

4356 + 66h = 99h

33h = 4356

Solving for h:

h = 4356 / 33 = 132 inches

Converting back to feet and inches:

h ≈ 11 feet

Therefore, the second ladder touches the wall approximately 11 feet higher than the shorter ladder, or equivalently, around 8 feet 8 inches higher.

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On solving, we get \(\rm x=1.25\)

Given that  \(\log _{3}( x+1)=\log_{6}(5-x) \)

Let,

            \(\rm y=\log _{3} (x+1) \;and\;\\y=\log_{6} (5-x) \)

Graphically, both equations obtained by the graph shown in the given diagram

Here,graphs intersects each other at point (1.25,0.74).

For the equation\(\log _{3}( x+1)=\log_{6}(5-x)\) ,The solution will be the Point of intersection between the graphs ie. \(x=1.25\)

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The sum of the two complex numbers will give:

(-4 + i) + (10 - 5i) = 6 - 4i

So the correct option is the third one.

Let's assume we have two complex numbers which are:

A = a + bi

B = c + di

The sum between these two complex numbers is:

A + B = (a + bi) + (c + di)

Taking i as a common factor we can rewrite:

(a + bi) + (c + di) = a + c + (b + d)i

And that is the general sum.

Here we want to solve:

(-4 + i) + (10 - 5i)

Again, if we take i as a common factor we can rewrite:

-4 + 10 + (1 - 5)*i

6 - 4i

So the correct option is the third one.

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Answer:

I would think J because they gained the same amount

Answer:

Step-by-step explanation:

The limitation of cross-sectional research among the given choices is: Differences between age groups may be due to different experiences.

Explanation:

The limitation of cross-sectional research is that differences between age groups may be due to different experiences. Cross-sectional research is a type of observational study design that collects data at a single point in time from a sample of individuals of different ages, groups, or populations. This type of research is used to study differences between groups, such as age, gender, or socioeconomic status.

However, one of the main limitations of cross-sectional research is that the differences observed between groups may not necessarily be due to age or any other factor of interest, but rather due to different experiences, histories, or social contexts. For instance, if researchers find that older adults perform worse on a cognitive test than younger adults, it is unclear whether this difference is due to age-related decline, or to factors such as education, occupation, or health.

Other limitations of cross-sectional research include the inability to establish causal relationships between variables, the possibility of selection bias or confounding, and the inability to track changes over time. Additionally, the other options presented in the multiple-choice question, such as test-wise effects, drop-out rates, and questionnaire completion by children, are not specific limitations of cross-sectional research, but rather potential issues that may affect any type of research design.

Therefore, the limitation of cross-sectional research is that differences between age groups may be due to different experiences.

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The number of cars that must be made to minimize the unit cost is 300 cars which is determined by differentiation.

Differentiation is a mathematical process that determines the instantaneous rate of change of a function based on one of its variables. The most common example is velocity, which is the rate of change of displacement with respect to time. Anti-differentiation is the inverse of finding a derivative.
Differentiation is used to calculate the rate of change of quantities in real time.

Since, we have been given the cost function to be function \((cx)= 1.1^{2} - 660x+107,357\) then we have to find the first differentiation in order to get the value and this will be:-

\((cx)= 1.1^{2} -660x+107,357\\2.2x=660\\x=\frac{660}{2.2} \\x=300\)

Therefore, the number of cars that must be made to minimize the unit cost is 300 cars.

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The 98 feet of fencing is required to fence a rectangular yard by using the wall of the house as one side of the rectangle and then enclosing the other three sides with the fence.

Given that a contractor wants to fence a rectangular yard by using the wall of the house as one side of the rectangle and then enclosing the other three sides with the fence. The yard has an area of 600 square feet, we need to find out how many feet of fencing are needed.Area of the rectangular yard is given as 600 square feet.Let the width of the rectangular yard be x feet.

So, the length of the rectangular yard will be 600/x feet as area=length×breadth.Now, perimeter of the rectangular yard= length + breadth + length+ house wall length= 2(length)+ house wall length.(Because one side is the house wall, so no need to consider it for perimeter.)Perimeter= 2(length)+ house wall length. As per the given data, one side is the wall of the house and we need to enclose the other three sides with fencing.

So, the perimeter of the rectangular yard will be the fencing required.So, Fencing required= Perimeter= 2(length)+ house wall length.Now, area= length×breadth or 600= x(600/x)= 600 .Therefore, breadth= 600/x.Now, perimeter= 2(length)+ house wall length = 2(x+ 600/x) + x = 2x+ 1200/x.Total fencing required will be 2x+1200/x. So, by putting values of x, we can find the answer as follows: For x = 20, Fencing required= 2(20)+1200/20= 40 + 60= 100 ft.For x = 24, Fencing required= 2(24)+1200/24= 48 + 50= 98 ft

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To determine if the bolts vary by more than the required variance, we can conduct a hypothesis test. The null hypothesis (H₀) states that the variance of the bolts is equal to or less than the required variance (σ² ≤ 0.025), while the alternative hypothesis (H₁) states that the variance is greater than the required variance (σ² > 0.025).

Next, we need to determine the critical value(s) of the test statistic. Since we are testing for variance, we will use the chi-square distribution. For a one-tailed test with α = 0.01 and 14 degrees of freedom (n-1), the critical value is 27.488.

Now, we can compare the test statistic to the critical value. The test statistic is calculated as (n-1) * s² / σ², where n is the sample size (15), s² is the sample variance (0.1587²), and σ² is the required variance (0.025).

If the test statistic is greater than the critical value, we reject the null hypothesis and conclude that the bolts vary by more than the required variance. Otherwise, we fail to reject the null hypothesis.

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To determine if the bolts vary by more than the required variance, we can conduct a hypothesis test. The null hypothesis (H₀) states that the variance of the bolts is equal to or less than the required variance (σ² ≤ 0.025), while the alternative hypothesis (H₁) states that the variance is greater than the required variance (σ² > 0.025).

Next, we need to determine the critical value(s) of the test statistic. Since we are testing for variance, we will use the chi-square distribution. For a one-tailed test with α = 0.01 and 14 degrees of freedom (n-1), the critical value is 27.488.

Now, we can compare the test statistic to the critical value. The test statistic is calculated as (n-1) * s² / σ², where n is the sample size (15), s² is the sample variance (0.1587²), and σ² is the required variance (0.025).

If the test statistic is greater than the critical value, we reject the null hypothesis and conclude that the bolts vary by more than the required variance. Otherwise, we fail to reject the null hypothesis.

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The probability of running out of anchovies before the evening is over is approximately 0.058, or 5.8%. We must presume that the number of pizzas ordered with anchovies follows a binomial distribution with parameters n = 60 (the total number of pizzas) and p = 0.08 in order to answer this issue using the normal approximation for the binomial distribution. (the probability of ordering anchovies on a pizza). 

The standard deviation of this binomial distribution is given by = sqrt(np(1-p)) = sqrt(60 x 0.08 x 0.92) = 2.03, and the mean is given by = np = 60 x 0.08 = 4.8.

Now, we need to determine the likelihood that we will need to prepare more than eight anchovy-topped pies before the evening is through in order to determine the likelihood that we will run out of anchovies. (since we only have enough anchovies for 8 pizzas).

This is equivalent to finding the probability that the number of pizzas with anchovies is greater than 8, or P(X > 8), where X is the number of pizzas with anchovies.

To use the normal approximation for the binomial distribution, we need to standardize the variable X using the standard normal distribution. This gives us:

z = (X - μ) / σ = (8 - 4.8) / 2.03 = 1.57

Using a standard normal table or calculator, we can find the probability that z is greater than 1.57, which is approximately 0.058. Therefore, the probability of running out of anchovies before the evening is over is approximately 0.058, or 5.8%.

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Answer:

Be Nice & Have Manners.

Step-by-step explanation:

Try to be nice and have manners. Being thankful for the clothes you have is always the top priority. Let them browse different kinds of clothes online or in person, and see if there are clothes that you and your parents agree on that you can wear.

Answer:$8.25 per pizza

Step-by-step explanation:

divide the money spent by the pizzas and find the ratio

Answer:

D. 188/250

Step-by-step explanation:

Total number attending concert is 250

Total number of adults AND tickets purchased in advance:

48 + 100 + 40 = 188

Divide by 250:

\(\frac{188}{250}\)

The probability that the randomly selected person attending the concert is an adult or has purchased the ticket in advance is 188/250.

Probability is simply the possibility of getting an event. Or in other words, we are predicting the chance of getting an event.

The value of probability will be always in the range from 0 to 1.

Given a table which shows when the tickets for a concert are sold and the types of tickets that are sold.

The probability of A or B can be calculated as,

P(A or B) = P(A) + P(B) - P(A and B)

Let A denote the people is an adult.

Let B denote the people who has purchased the ticket in advance.

P(A) = 148/250

P(B) = 140/250

P(A and B) = 100/250

Probability that a randomly selected person attending the concert is an adult or has purchased the ticket in advance is,

P(A or B) = 148/250 + 140/250 - 100/250

              = 288/250 - 100/250

               = 188/250

Hence the required probability is 188/250.

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The set of points where the function is continuous is: {(x, y) | e^xy ≠ 1}

A continuous function is one in which a small change in the input results in a small change in the output.

The formal definition of a continuous function is as follows:

A function f(x) is continuous at a point x = a if the limit of f(x) as x approaches a is equal to f(a), i.e. lim x→a f(x) = f(a).

A function is continuous if it is continuous at every point in its domain.

A function is said to have a point of discontinuity if it is not continuous at that point. This means that the limit of the function does not exist at that point or that the limit does exist, but it is not equal to the function value.

So, in the given function H(x, y) = (e^x + e^y) / (e^xy - 1), the function is continuous at all points (x, y) except where e^xy = 1.

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To determine the maximum amount Jaxson can borrow for a 20-year mortgage with a monthly payment of $1,125 and an annual interest rate of 4.8% (compounded monthly)

We can use the formula for the present value of an annuity:

P = M * (1 - (1 + r)^(-n)) / r

Where:

P = Amount borrowed (to be determined)

M = Monthly payment = $1,125

r = Monthly interest rate = Annual interest rate / 12 = 4.8% / 12 = 0.004

n = Total number of payments = 20 years * 12 months/year = 240

Substituting the given values into the formula:

P = $1,125 * (1 - (1 + 0.004)^(-240)) / 0.004

Calculating the expression inside the parentheses:

(1 + 0.004)^(-240) ≈ 0.354296

Substituting this value into the formula:

P = $1,125 * (1 - 0.354296) / 0.004

P ≈ $1,125 * 0.645704 / 0.004

P ≈ $177,824.75

Therefore, to the nearest dollar, the maximum amount Jaxson can borrow is $177,825.

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The area below the curve is equal to 10 - 3π / 2 square units. (Correct choice: B)

In this problem we need to determine the area below the curve for the interval x ∈ [- 4, 7]. Mathematically speaking, this area can be found by means of definite integrals. Given that we find a piecewise function formed by five expressions, the area is the sum of several subintervals.

The areas can be represented by using the following area formulas:

Triangle

A = 0.5 · w · l

Semicircle

A = 0.5π · R²

Rectangle

A = w · l

Where:

Please notice the area above the x-axis is positive and the area below the x-axis is negative. Finally, we find the net area below the curve:

A = 0.5 · 2 · 2 - 0.5π · 2² + 0.5 · 2 · 2 + 2 · 2 + 0.5π · 1² + 1 · 2

A = 2 - 2π + 2 + 4 + 0.5π + 2

A = 10 - 1.5π

A = 10 - 3π / 2

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Answer:

b=sqrt7

Step-by-step explanation:

16=9+b^2

Based on the equation that relates the distance traveled by the plane going from Boston to Philadelphia, the time it would take for the plane to travel 280 miles is 48 minutes

You can use the formula given to find the amount of time taken by the plane to travel 280 miles.

The formula is;

d=350t

distance travelled = 350 x time

Solving for time taken gives;

280  = 350 x time

Time = 280 / 350

Time = 0.8 hours x 60 minutes per hour

Time = 48 minutes

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Answer:

Incorrect Answer Below

Step-by-step explanation:

Problem: We have a total of 28 candies that need to be divided evenly between 4 students.

(Incorrect) Solution: In order to solve this problem we can seperate the total number of candies into single digits and then divide each digit by 4 like so...

2 / 4 = 0.5

8 / 4 = 2

Now that we have the answer of both of these divisions we can simply add these values together to get the number of candies each student will get

0.5 + 2 = 2.5 candies

Answer:

x5

Step-by-step explanation:

Answer:

(x - 1) (x + 4)

Step-by-step explanation:

Option D: There is not enough evidence to suggest that the average percent increase of company sales after an advertising campaign is different from 17 percent.

The marketing manager wants to test the claim that the percent increase in company sales after an advertising campaign is different from 17 percent. To do this, a z-test statistic was calculated, which came out to be 2.43. The marketing manager wants to know if there is enough evidence to reject the null hypothesis. The significance level, or alpha, is given as 0.01.

To determine if there is enough evidence to reject the null hypothesis, we need to compare the test statistic to the critical value(s) and the p-value.

First, let's determine the type of test we should use. Since the alternative hypothesis is that the percent increase is different from 17 percent, we need a two-tailed test.

Next, we compare the test statistic to the critical value(s) based on the significance level. Since the significance level is 0.01, we need to find the critical value(s) that split the alpha evenly between the two tails of the distribution. In this case, the critical value(s) would be ±2.58 (which corresponds to an alpha of 0.005 for each tail).

Now, let's compare the test statistic (2.43) to the critical value(s) (±2.58). Since the test statistic falls within the range of the critical value(s), we do not have enough evidence to reject the null hypothesis.

Lastly, let's consider the p-value. The p-value is the probability of observing a test statistic as extreme as the one calculated, assuming the null hypothesis is true. In this case, the p-value is given as 0.015. Since the p-value is greater than the significance level (0.01), we do not have enough evidence to reject the null hypothesis.

Based on these results, we can conclude that there is not enough evidence to suggest that the average percent increase of company sales after an advertising campaign is different from 17 percent.

COMPLETE QUESTION:

Understand and interpret the test-statistic and p-value Question A marketing manager would like to test the claim that the percent increase of company sales after an advertising campaign is different than 17 percent. If the z, test statistic was calculated as z = 2.43, does the marketing manager have enough evidence to reject the null hypothesis? Assume a = 0.01. Move the blue dot to choose the appropriate test (left, right, or two-tailed). Then, use the graph below to show the test statistic, p-value, and the rejection region to make a conclusion about the hypothesis test. Move the blue dot to choose the appropriate test Significance level = 0.01 a=0.01 a=0.025 a=0.05 a=0.1 Move the blue dot to choose the appropriate test Significance level = 0.01 a=0.01 a=0.025 a=0.05 a=0.1 a/2 = 0.005 a/2 = 0.005 p-value= 0.015 D Ź T Ő tes statistic = 2. test statistic = 2.43 Z= 2.58 Z= -2.58 powered by Select the correct answer below:

A.There is enough evidence to suggest the average percent increase of company sales after an advertising campaign is greater than 17 percent. B. There is not enough evidence to suggest the average percent increase of company sales after an advertising campaign is greater than 17 percent.

C. There is enough evidence to suggest the average percent increase of company sales after an advertising campaign is not 17 percent.

D. There is not enough evidence to suggest the average percent increase of company sales after an advertising campaign is not 17 percent.

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Answer:

hi i think the answer shouldbe 34/43 as its out of 43 and there is 34 people on the internet. I think this should be write but it may  be wrong. if this is right please vote for brainliest. i hope my answer is right and this helps bye.

At the optimal level where the present worth of cost is $3 million, the B/C ratio is 0 that is present worth of cost that optimizes the benefit/cost ratio.

To find the present worth of cost that optimizes the benefit/cost ratio, we need to solve the given equation:

(PW of benefits)² - 18 * (PW of cost) + 54 = 0

Let's solve this equation to find the present worth of cost.

By rearranging the equation, we have:

(PW of benefits)² = 18 * (PW of cost) - 54

Taking the square root of both sides, we get:

PW of benefits = √(18 * (PW of cost) - 54)

To optimize the benefit/cost ratio, we want to find the value of PW of cost that minimizes the denominator. In this case, we can consider the derivative of the benefit/cost ratio with respect to the PW of cost and set it equal to zero to find the minimum value. Taking the derivative of the benefit/cost ratio with respect to the PW of cost, we get:

d(B/C) / d(PW of cost) = -18 / (PW of benefits)

= -18 / √(18 * (PW of cost) - 54)

Setting the derivative equal to zero, we have:

-18 / √(18 * (PW of cost) - 54) = 0

Solving this equation, we find that PW of cost = $3 million.

Therefore, the present worth of cost for the project that optimizes the benefit/cost ratio is $3 million. To calculate the B/C ratio at the optimal level, we substitute the value of PW of cost into the equation:

(PW of benefits)² - 18 * (PW of cost) + 54 = 0

(PW of benefits)² - 18 * 3 + 54 = 0

(PW of benefits)² = 0

PW of benefits = 0

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Al-Fatihah is an Islamic prayer recited during the five daily prayers. Comparing radio and television in reading Al-Fatihah from its beginning requires an analysis of how each medium conveys the prayer to its audience. Radio precedes television in reading Al-Fatihah from its beginning.

This is because radio broadcasting began in the early 1900s while television broadcasting began in the late 1940s.

This delay can range from a few seconds to a few minutes depending on several factors such as the geographical location of the audience, the strength of the signal, and the quality of the receiver. Therefore, the time difference between radio and television in reading Al-Fatihah can vary depending on the factors mentioned above.

Mathematically, the time difference between radio and television can be calculated using the formula: d = s / tWhere d is the distance between the transmitter and the receiver, s is the speed of the signal, and t is the time it takes for the signal to reach the receiver.

In this case, d is the distance between the broadcasting station and the audience, s is the speed of the signal which is constant (i.e., the speed of light), and t is the time it takes for the signal to reach the audience. Since the speed of light is approximately 299,792,458 m/s, the time it takes for the signal to reach the audience can be calculated using the following formula:t = d / s

Therefore, the time difference between radio and television in reading Al-Fatihah can be calculated by subtracting the time it takes for the radio signal to reach its audience from the time it takes for the television signal to reach its audience. This difference can range from a few milliseconds to a few minutes depending on the factors mentioned above.

In network concepts, the time difference between radio and television in reading Al-Fatihah can be affected by the bandwidth of the network. The bandwidth is the amount of data that can be transmitted over a network in a given time. If the bandwidth is low, it can cause a delay in the transmission of the signal which can affect the time difference between radio and television.

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The program segment is not correct with respect to the given initial and final assertions.

To verify that the program segment x := 2; z := x * y; if y > 0 then z := z + 1 else z := 0 is correct with respect to the initial assertion y = 3 and the final assertion z = 6, we need to check that the program produces the expected values of x, y, and z at every step.

1. Initial assertion: y = 3

This is given in the problem statement.

2. x := 2

After executing this statement, we have x = 2.

3. z := x * y

After executing this statement, we have z = x * y = 2 * 3 = 6.

4. if y > 0 then z := z + 1 else z := 0

Since y = 3 > 0, this condition is true and we execute the first branch of the if statement. Therefore, we have z := z + 1, which gives z = 6 + 1 = 7.

5. Final assertion: z = 6

This assertion is not satisfied, since we have z = 7 instead of z = 6.

Therefore, the program segment is not correct with respect to the given initial and final assertions.

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Answer: Step 3 was Gabi's mistake

The solution of the Gabi's equation is m = 28. the Gabi's mistake was division in step 3.

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Step 1:  Distribute

0.1(0.5m + 6) = 2

(0.1 * 0.5m) + (0.1 * 6) = 2

0.05m + 0.6 = 2

Step 2:  Subtract 0.6 from both sides

0.05m + 0.6 - 0.6 = 2 - 0.6

0.05m = 1.4

Step 3:  Divide both sides by 0.05

0.05m / 0.05

= 1.4 / 0.05

m = 28

Hence, the solution of the Gabi's equation is m = 28. the Gabi's mistake was division in step 3.

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Considering the definition of an inequality, the maximum number of days that Ariana can rent the car while staying within her budget is 5 days.

An inequality is the existing inequality between two algebraic expressions, connected through the signs:

An inequality contains one or more unknown values.

Solving an inequality consists of finding all the values ​​of the unknown for which the inequality relation holds.

In this case, you know that:

Being "x" the number of days that Ariana can rent the car, the inequality in this case is

30.42x + 0.06×450 ≤200

Solving:

30.42x + 27 ≤200

30.42x ≤200 - 27

30.42x ≤173

x ≤173÷ 30.42

x≤ 5.687

Finally, the maximum number of days is 5 days.

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