What is the area of the rooftop garden?

What Is The Area Of The Rooftop Garden?

Answers

Answer 1

The area of the rooftop garden as required in the task content is; 272 ft².

What is the area of the rooftop garden?

It follows from the task content that the area of the rooftop garden is to be determined.

As evident in the attached image; the rooftop garden was modelled as a composite figure of a rectangle and a triangle.

Therefore, the area of the rooftop garden is the sum of areas of the rectangle and the triangle.

Where the heights of the triangle is; 20 - 12 = 8 ft.

Therefore, we have;

Area = { (1/2) × 8 × 8 } + { 12 × 20}

Area = 32 + 240

Area = 272 ft².

Ultimately, the required area of the rooftop garden is; 272 ft².

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Related Questions

factorize the expression:
mn² + mnp + 3mn + 3mp

Answers

Answer:

(mn+3m)(n+p)

Step-by-step explanation:

Answer:

(mn + 3m)(n + p)

Step-by-step explanation:

Factorize by grouping:

\(mn^2+mnp\\mn(n+p)\\\\3mn+3mp\\3m(n+p)\\\\(mn+3m)(n+p)\)

Identify the type of data (qualitative/quantitative) and the level of measurement for the eye color of survet respondents.

Answers

Qualitative data depicts qualities or characteristics. This type of data is qualitative and nominal.

What is qualitative data?

Qualitative data are the conceptual and descriptive findings gathered by surveys, interviews, or observation. We can explore concepts and provide more context for quantitative findings by analyzing qualitative data.

Qualitative data exist as measures of "types" and can be represented by a name, symbol, or number code, whereas quantitative data exist as information on numerical variables (such as how many, how much, or how frequently).

Numbers are used to expressing measures of values or counts in quantitative data. Binary, nominal, and ordinal are the three primary forms of qualitative data.

Qualitative data comes in a wide variety of forms, including those used in statistics, work, and research. This type of data is qualitative and nominal.

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-5 -2q = 9


please help me

Answers

Answer:

q = -7

Step-by-step explanation:

-5 - 2q = 9

Add 5 to both sides of the equation.

-2q = 14

Divide both sides by -2.

q = -7

At the grocery store, Jamir bought a box of 12 Snickers Bars for $11.50. How much did he pay for each candy bar?

Answers

Answer:

138

Step-by-step explanation:

$ 11.50 x 12 = 138

it’s 1.04

because you have to divide

i need an answer for this question in the simplest radical form please

i need an answer for this question in the simplest radical form please

Answers

y³√45x⁷y⁵ in its simplest form is 3√5y⁵x³√x√y

What is Expression?

An expression is combination of variables, numbers and operators.

The given expression is y³√45x⁷y⁵

y³√9×5 x⁷y⁵

In the given expression x and y are the variables.

=y³3√5x³.√x. y²√y.

=y⁵.3√5x³√y√x

=3√5y⁵x³√x√y

Hence,y³√45x⁷y⁵ in its simplest form is 3√5y⁵x³√x√y

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An item sells for $75 and is on sale for 35% off. The sales tax is 9.8%. What is the final cost of the item?​

Answers

The final cost of the item after a 35% discount and 9.8% sales tax is $53.54.

The given problem is related to percentage discounts and sales tax and can be solved using the following steps:

Step 1: Firstly, we need to determine the discount amount, which is 35% of the original price. Let's calculate it. Discount = 35% of the original price = 0.35 x $75 = $26.25

Step 2: Now, we will calculate the new price after the discount by subtracting the discount amount from the original price.New Price = Original Price - Discount AmountNew Price = $75 - $26.25 = $48.75

Step 3: Next, we need to calculate the amount of sales tax. Sales Tax = 9.8% of New Price Sales Tax = 0.098 x $48.75 = $4.79

Step 4: Finally, we will calculate the final cost of the item by adding the new price and the sales tax.

Final Cost = New Price + Sales Tax Final Cost = $48.75 + $4.79 = $53.54

Therefore, the final cost of the item after a 35% discount and 9.8% sales tax is $53.54.I hope this helps!

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Somebody please help me! Question is due in 11 minutes!

Somebody please help me! Question is due in 11 minutes!

Answers

Answer:

Step-by-step explanation:

Find the length x.
HELPPP PLSSSS

Find the length x.HELPPP PLSSSS

Answers

Answer: My answer is 4. You may want another answer.

Step-by-step explanation:

visual studying

Refer to Table 4-1. Suppose that D2 and S1 are the prevailing demand and supply curves for a product. If the demand schedule changes from D2 to D1, then:
Price D 1 D 2 S 1 S 2
$12 5 9 19 14
$10 8 12 17 12
$8 11 15 15 10
$6 13 18 13 8
$4 16 21 11 6
$2 18 24 9 4
equilibrium price increases from $6 to $8.
equilibrium quantity increases from 13 to 18
equilibrium quantity decreases from 15 to 13.
equilibrium price decreases from $6 to $4.

Answers

The correct option is A, equilibrium price increases from $6 to $8.

What do you mean by Equilibrium?

In economics, equilibrium is a state in which the supply and demand for a product or service are balanced, resulting in a stable price. This can occur in a free market, where the price of a good or service is determined by the interaction of buyers and sellers.

Overall, equilibrium is a fundamental concept in many different fields, representing a state of balance or stability in a system or situation.

If the demand schedule changes from D2 to D1, then the demand curve shifts to the left. As a result, the new equilibrium point will be where the new demand curve (D1) intersects with the supply curve (S1).

From the table, we can see that the new equilibrium point is at a price of $8 and a quantity of 15. Therefore, the equilibrium price increases from $6 to $8, but the equilibrium quantity decreases from 15 to 13.

So the correct answer is: equilibrium price increases from $6 to $8.

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There are 53 regular pencils in the box and some colored pencils in the box. There are a total of 84 pencils. How many colored pencils are there?

Answers

Let be "x" the number of colored pencils in the box.

According to the information given in the exercise, there are 84 pencils in the box and 53 of them are regular pencils.

Knowing this information, you can set up the following equation:

\(x+53=84\)

Finally, you have to solve for the variable "x" in order to find its value. In order to do this, you can apply the Subtraction property of equality by subtracting 53 from both sides of the equation:

\(\begin{gathered} x+53-(53)=84-(53) \\ x=31 \end{gathered}\)

The answer is: There are 31 colored pencils in the box.

An airplane is flying at an airspeed of 600 km/hr in a cross-wind that is blowing from the northeast at a speed of 50km/hr. In what direction should the plane head to end up going due east?

Answers

The airplane should head approximately 4.76 degrees east of its intended direction to compensate for the crosswind and end up going due east.

To end up going due east, the airplane needs to counteract the effect of the crosswind and maintain a heading that compensates for the wind's direction and speed.

Since the crosswind is coming from the northeast, it forms a right triangle with the airplane's airspeed and ground speed vectors. The angle between the ground speed vector (due east) and the airspeed vector is the heading the plane should take.

Using trigonometry, we can calculate this angle. The opposite side of the triangle is the speed of the crosswind (50 km/hr), and the hypotenuse is the airspeed (600 km/hr).

Let's denote the angle as θ. We can use the sine function:

sin(θ) = opposite/hypotenuse

sin(θ) = 50/600

θ = sin^(-1)(50/600)

Evaluating this expression, we find θ ≈ 4.76 degrees.

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What are the minimum and maximum values of this?

What are the minimum and maximum values of this?

Answers

The minimum value is 0.5 and the maximum value is 3.5.

What are the minimum and maximum values of this?The minimum value of 1/n(x) + 2 over the interval 5≤ x ≤ 8 is 2.This is because 1/n(x) is a decreasing function and the smallest value it can take is 1/n(8) = 1/8. Adding 2 to this gives 2. The maximum value of 1/n(x) + 2 over the interval 5≤ x ≤ 8 is 5.This is because 1/n(x) is an increasing function and the largest value it can take is 1/n(5) = 1/5. Adding 2 to this gives 5. Overall, 1/n(x) + 2 takes on values between 2 and 5 over the interval 5≤ x ≤ 8.This is because 1/n(x) is a decreasing function over the interval and adding 2 to this makes the minimum value 2, while 1/n(x) is an increasing function over the interval and adding 2 to this makes the maximum value 5.The minimum and maximum values for the function 1n(x) +2 over the interval 5≤ x ≤ 8 can be determined by examining the graph of the function over the given interval.Since the function is increasing over the given interval, the minimum value of the function is equal to its value at the lower bound of the interval (x = 5), which is 1n(5) + 2 = 2.71.The maximum value of the function is equal to its value at the upper bound of the interval (x = 8), which is 1n(8) + 2 = 3.11.

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Complete the inequality. 13/18___ 11/14 < > =

Answers

Answer:

Your answer is <, Hope it helps.

Can someone help me I dont know what to do

Can someone help me I dont know what to do

Answers

Step-by-step explanation:

1. find P of semicircle

perimeter of a semicircle = pi×r+d

=3.14×5+10

=25.7

2.find P of rectangle

P=10×4=40cm

3. add P of semicircle and P of rectangle

25.7+40=65.7cm

complete the steps of the calculation to find the value of x​

complete the steps of the calculation to find the value of x

Answers

Answer:

99 + x = 4x

99 = 3x

x =33

.....

99 degrees + x = 4x
Because 99 degrees angle + angle x is vertical to 4x angle. That makes them congruent.
99+x=4x
Subtract x from both sides:
99=3x
Divide 3 to both sides
x=11

In the figure below, m/RSP = 79°, m P
What is m/QRP?
OA. 90°
OB. 60°
OC. 150°
OD. 50°
S
R
Note picture not drawn to scale

In the figure below, m/RSP = 79, mPWhat is m/QRP?OA. 90OB. 60OC. 150OD. 50SRNote picture not drawn to

Answers

Therefore , the solution of the given problem of angle comes out to be

m∠QRP =  50 degree.

What exactly is an angle?

In Euclidean space, an angle is a structure that consists of two poles who split at its apex and apex, which are located in its centre. The sides or loops are the name given to these rays. Combining two rays could result in an inclination within the planes in that they are located. Two planes can be combined to form angles as well. These are referred to as dihedral angles. Two line rays at their end points can be arranged in many ways to produce patterns in two dimensions.

Here,

Given :

m∠RSP = 79 , m∠SPR = 40 and m∠QRS = 111

To find the angle m∠QRP

So,

First find the angle ∠SRP

Thus ,

it is a triangle

79 + 40 + ∠SRP = 180

=> ∠SRP  = 180 - 79 -40

=>∠SRP = 61 degree

and

=> m∠QRP = m∠QRS  - ∠SRP

=> m∠QRP =  111 - 61

=> m∠QRP =  50 degree.

Therefore , the solution of the given problem of angle comes out to be

m∠QRP =  50 degree.

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Write the number for seventy-five million three hundred thousand

Answers

The answer is 75,300,000 hope this helps.

If 16 = 50
28 = 71
95 =48
44 = ?

Answers

Answer:

44 = 33 actually these are reasoning based q so don't worry only u have to think a little bit :)

Step-by-step explanation:

Given, 16 = 50

reverse the digis of 16 e.g., 61 and then, subtract 11 from 61 e.g., 611150

similarly, 28 <=> 82

82-1171

95 <=> 59

59-1148

then, you can say that

44 <=> 44

44-11 = 33

hence, answer is 33.

Hope this is helpful to u..

and please mark me as brainliest:)

Happy learning!!

question the line plots show the daily high temperature in two cities over 10 days. which conclusion can be drawn from the data? responses city 2 had fewer 80-degree days than city 1. city 2 had fewer 80-degree days than city 1. city 1 is generally much warmer than city 2. city 1 is generally much warmer than city 2. the weather is generally sunnier in city 2. the weather is generally sunnier in city 2. the variation in the daily high temperature is generally greater in city 1. the variation in the daily high temperature is generally greater in city 1.

Answers

The conclusion that can be drawn from the data is: "The variation in the daily high temperature is generally greater in city 1."

By observing the line plots of the daily high temperature in two cities over 10 days, we can analyze the variability in temperature between the cities.

In city 1, the line plot shows more fluctuations and irregular patterns, indicating greater variability in the daily high temperature. The temperatures vary significantly from day to day, with some days reaching high temperatures and others experiencing cooler temperatures.

On the other hand, in city 2, the line plot shows a more consistent pattern, with fewer fluctuations and a more stable trend in the daily high temperature. The temperatures tend to stay within a narrower range throughout the 10-day period.

Since the variation in temperature refers to the extent to which temperatures deviate from the average or fluctuate, the line plot suggests that city 1 has a greater variation in the daily high temperature compared to city 2.

Based on the line plots, we can conclude that the variation in the daily high temperature is generally greater in city 1. This indicates that city 1 experiences more significant temperature fluctuations and a wider range of temperatures compared to city 2.

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Help! i don't understand :/

Help! i don't understand :/

Answers

Answer:

Option C

Step-by-step explanation:

Given inequality is,

-3(2x - 4) ≤ 7(3 - x)

Solve the given inequality further,

-6x + 12 ≤ 21 - 7x

(-6x + 12) + 7x ≤ (21 - 7x) + 7x

x + 12 ≤ 21

(x + 12) - 12 ≤ 21 - 12

x ≤ 9 Or {x real | x ≤ 9}

Therefore, Option C will be the correct option.

Answer:

this is your answer look it once

Help! i don't understand :/

Elizabeth is organizing dessert plates with 15 brownies and 9 chocolate chip cookies. If she wants all the plates to be exactly the same with no brownies or cookies left over, what is the greatest number of dessert plates that Elizabeth can make?

Answers

Answer:

8 plates

Step-by-step explanation:

The reason for this is because 15 and 9 are both divisible by 3. 15 divided by 3 is 5 and 9 divided by 3 is 3. 5+3= 8. Therefore, you will need 8 plates.

Factor. Look for a GCF first.

5x^2-80

Answers

Answer:

5(x + 4)(x - 4)

Step-by-step explanation:

1. Factor out the GCF, 5:

5(x² - 16)

2. Rewrite 16 as a perfect square:

5(x² - 4²)

3. Factor the parenthesis by apply the difference of two squares formula x² - y² = (x + y)(x - y):

(x² - 4²) = (x + 4)(x - 4)

5(x + 4)(x - 4)

hope this helps :)

Answer:

\(5(x-4 )(x + 4)\)

Step-by-step explanation:

Given expression:

\(5x^2-80\)

To factor the expression, we need to determine the GCF (Greatest common factor). This can be done by listing the factors of 5x² and 80.

Factors of 80 ⇔ 1, 2, 4, 5, 8, 10, 20, 40, 80Factors of 5x² ⇔ 1, 5, x, x²

We can see that 1 and 5 are the common factors of 80 and 5x². Since 5 is greater than 1, the GCF (Greatest common factor) of 80 and 5x² is 5.

⇒ \(5(x^2-16)\)

Since 16 is a perfect square, 16 can be written as 4².

⇒ \(5(x^2-4^{2} )\)

When we use the rule a² - b² = [a - b][a + b], we get;

⇒ \(5(x-4 )(x + 4)\)

Therefore, the factorized form of \(5x^2-80\) is \(5(x-4 )(x + 4)\).

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If it takes four men three hours to dig two holes, how long does it take one man to dig three holes?

Answers

Answer:

it will take one man 18 hours to dig the three holes

Step-by-step explanation:

To solve this problem, we can set up a simple relation as follows:

4 men dig two holes in 3hours

4 men will dig 1 hole in x hours.

2 holes => 3 hours

1 hole => x hours

x = (1 X 3)/2 = 1.5 hours

Therefore, 4 men will dig 1 hole in 1.5 hours.

From this, we can find how long it will take 1 man to dig 1 hole

if 4men dig a hole in 1.5 hours

1 man will dig 1 hole in x hours

4 X 1.5 = 6 hours

1 man will dig 1 hole in 6 hours

finally, if 1 man digs a hole in 6 hours, it will take the man 6 hours X 3 to dig 3 holes = 18hours

it will take one man 18 hours to dig the three holes

in this problem, and are positive integers. when is written in base , its last digit is . when is written in base , its last two digits are . when is written in base , what are its last two digits? assume is positive.

Answers

This shows that has a remainder of 217 when divided by 343. Therefore, its last two digits in base 343 are 7 and 217.

To approach this problem, we need to use some basic rules of number systems.

When a number is written in base 10 (decimal), its last digit is determined by its remainder when divided by 10. For example, if a number ends with a 7, we know it leaves a remainder of 7 when divided by 10.

Similarly, when a number is written in base n, its last digit is determined by its remainder when divided by n. For example, if a number in base 5 ends with a 3, we know it leaves a remainder of 3 when divided by 5.

Now let's apply this to the given problem. We know that leaves a remainder of 1 when divided by 7 (since its last digit is 1 in base 7). This means that can be expressed as 7k + 1 for some positive integer k.

Similarly, we know that leaves a remainder of 36 when divided by 49 (since its last two digits are 36 in base 49). This means that can be expressed as 49m + 36 for some positive integer m.

To find the last two digits of in base 343, we need to find its remainder when divided by 343. We can start by expressing as a sum of multiples of 7 and 49:

= (7k + 1) + 6(49m + 36)

= 7k + 294m + 217

Now we need to express this sum as a multiple of 343 plus a remainder. We can do this by dividing 294m + 217 by 343:

294m + 217 = 343m + (294m + 217 - 343m)

= 343m + 7m + 217

= 343(m + 1) + 7m - 126

So we have:

= 7k + 343(m + 1) + 7m - 126

= 343(m + 1) + 7(k + m) - 126

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Many species are made up of several small subpopulations that occasionally go extinct but that are subsequently recolonized. The entire collection of subpopulations is referred to as a metapopulation. One way to model this phenomenon is to keep track only of the fraction of subpopulations that are currently extant. Suppose p(t) is the fraction of subpopulation that are extant at time t. The Levins model states that p(c) obeys the following differential equation: dp cp(1-p)- ep dt where c and e are positive constants reflecting the colonization and extinction rates respectively (a) What are the equilibria of this model in terms of the parameters? (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) (b) What are the conditions on the parameters for the nonzero equilibrium found in part (a) to lie between 0 and 1? e>c e=c e< c (c) What are the conditions on the parameters for the nonzero equilibrium found in part (a) to be locally stable? esc e

Answers

(a) The equilibria of the model can be found by setting dp/dt = 0 and solving for p. From the given differential equation, we have cp(1-p) - ep = 0. Rearranging this equation, we get cp - cp^2 - ep = 0. Factoring out p, we have p(cp - cp - e) = 0. Simplifying further, we find that the equilibria are p = 0 and p = (c - e)/c.

(b) To ensure that the nonzero equilibrium p = (c - e)/c lies between 0 and 1, we need the fraction to be positive and less than 1. This implies that c - e > 0 and c > e.

(c) The conditions for the nonzero equilibrium to be locally stable depend on the sign of the derivative dp/dt at that equilibrium. Taking the derivative dp/dt and evaluating it at p = (c - e)/c, we find dp/dt = (c - e)(1 - (c - e)/c) - e = (c - e)(e/c). For the equilibrium to be locally stable, we require dp/dt < 0. Therefore, the condition for local stability is (c - e)(e/c) < 0, which can be simplified to e < c.

In conclusion, the equilibria of the Levins model are p = 0 and p = (c - e)/c. The nonzero equilibrium lies between 0 and 1 when c > e, and it is locally stable when e < c.

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4. Marlisa has 23 seashells in her collection. She collects s more shells during a trip to the beach. Then she doubles the number of seashells in her collection by buying new shells at the souvenir shop Write an expression to find out how many seashells Marlisa has after her visit to the souvenir shop.​

Answers

Answer:

(23*2)+s

Step-by-step explanation:

Answer:

2(23+s)

Yep there ya goo

Simplify the expression 2(3+d-1)=

Answers

Answer:

4+2d

Step-by-step explanation:

2(3+d-1)

6+2d-2=6+(-2)+2d

=4+2d

Suppose a normal distribution has a mean of 98 and a standard deviation of 6. What is P(x<110)? (The greater than sign is actually greater than or equal to)

A. 0.975
B. 0.025
C. 0.16
D. 0.84

Answers

Using the normal distribution, the probability that x is less than 110 is:

A. 0.975.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean \(\mu\) and standard deviation \(\sigma\) is given by:

\(Z = \frac{X - \mu}{\sigma}\)

The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given as follows:

\(\mu = 98, \sigma = 6\)

The probability is the p-value of Z when X = 110, hence:

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{110 - 98}{6}\)

Z = 2

Z = 2 has a p-value of 0.975.

Hence option A is correct.

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How do you write
20/100

as a percentage?

Answers

Answer:

20%

Step-by-step explanation:

\( \frac{20}{100} \times 100\%\)

\( = 20\%\)

Answer: 20%

Step-by-step explanation:

% means out of 1

1 = 100%

20/100 = 20%

Please help I missed school for a while I don't know how to do this math I'm so behind right now


Using the trig functions of sin cos and tan set up the problem the trig function should be equal to a ratio reduce fractions if possible

Please help I missed school for a while I don't know how to do this math I'm so behind right now Using

Answers

The values of the trigonometric identities are;

1. tan X = 10/17

2.  tan X = 29/25

3. sin A = 24/25

4. tan C = 15/17

5. sin A = 8/17

6. cos A = 9/41

7. cos Z = 3/4

How to determine the trigonometric fractions

Note that fractions are the part of a whole number.

Also,

sin θ = opposite/hypotenuse

cosθ = adjacent /hypotenuse

tan θ = opposite/adjacent

1. tan X = opposite/ adjacent

tan X = 30/21 = 10/7

2. tan X = 29/25

3. sin A = opposite/hypotenuse

sin A = 24/25

4. tan C = opposite/adjacent

tan C = 30/34

tan C = 15/17

5. sin A = 16/34

sin A = 8/17

6. cos A = adjacent/hypotenuse

cos A = 9/41

7. sin A = 21/35

8. cos Z = 21/28

cos Z = 3/4

Hence, the fractions takes the function of the trigonometric identities.

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