Answer:
113.1in^2 (round to 1dp)
Step-by-step explanation:
to calculate the area of a circle, you use the formula π\(r^{2}\) where r is the radius which in this case is 6 and the square of 6 is 36 so its 36π
which equals 113.0973355in^2 and 113.1in^2 if you round it to 1 decimal place
The formula for the area of a circle is:
Area = π x (radius)^2
where π (pi) is a mathematical constant approximately equal to 3.14159, and the radius is half of the diameter.
Given that the diameter of the circle is 12 in, we can find the radius by dividing the diameter by 2:
radius = diameter / 2 = 12 in / 2 = 6 in
Now we can substitute this value into the formula for the area:
Area = π x (radius)^2 = π x (6 in)^2
Using a calculator to approximate π as 3.14159, we get:
Area ≈ 3.14159 x (6 in)^2 ≈ 113.1 in^2
Therefore, the area of the circle with a diameter of 12 in is approximately 113.1 square inches.
Graduating seniors must present three projects as part of a major requirement and must select them from a list of 10 possible projects. In how many ways can this be done? a 120b 720 c other:
ANSWER
120 ways
EXPLANATION
We want to see how many ways 3 projects can be selected from 10 possible projects.
Since there is no particular order for the selection, we will use combinuation.
We have:
\(\begin{gathered} ^{10}C_3\text{ = }\frac{10!}{(10\text{ - 3)! 3!}} \\ \text{ = }\frac{10!}{7!\text{ 3!}} \\ =\text{ 120 ways} \end{gathered}\)That is the answer.
Please find the Y for both of these equation
4x - y = 4
X-2y=-6
Answer:
1). y= -4+ 4x
2). y= 3+ x/2
Step-by-step explanation:
hope this helps !
Can someone help please
ASAP
Answer:
see explanation
Step-by-step explanation:
using the tangent ratio in the right triangle
tan A = \(\frac{opposite}{adjacent}\) = \(\frac{BC}{AB}\) = \(\frac{5}{11}\) , then
∠ A = \(tan^{-1}\) ( \(\frac{5}{11}\) ) ≈ 24.4° ( to 1 decimal place )
tan C = \(\frac{opposite}{adjacent}\) = \(\frac{AB}{BC}\) = \(\frac{11}{5}\) , then
∠ C = \(tan^{-1}\) ( \(\frac{11}{5}\) ) ≈ 65.6° ( to 1 decimal place )
using Pythagoras' identity in the right triangle
the square on the hypotenuse is equal to the sum of the squares on the other two sides, that is
AC² = AB² + BC² = 11² + 5² = 121 + 25 = 146 ( take square root of both sides )
AC = \(\sqrt{146}\) ≈ 12.08 ( to 2 decimal places )
Erica And Amy started biking in opposite directions at the same time from the same place. Erica biked at a speed of 6 meters per second and Amy biked at a speed of 4 meters per second. How soon were they exactly one km apart?
Answer:
100 seconds
i hope this helps
If rafael pays $75 monthly for health insurance how much will he have paid after two years
Monthly payment: $75
Number of months in 2 years: 24
Then, the answer is the product of the number of months (24) and the monthly payment ($75):
\(\begin{gathered} \$75\cdot24 \\ \\ \therefore\$1800 \end{gathered}\)Find the area of the figures given
Answer:
A: 12.5
B: 36
C: 40
D: 88
Step-by-step explanation:
those are the answers
A rectangular patio has a length of (1 + 2x) yards and a width of (2 - 3x) yards. Which correctly describes the area and perimeter of the patio?
Area of the patio is -6x² + x + 2 square yards and perimeter of the patio is 6 - 2x yards.
What is a yard?A yard is a unit of measurement used to measure length or distance in both the US customary system and the British imperial system. One yard is equal to 3 feet or 36 inches. In the US customary system, a yard is equal to 0.9144 meters, while in the British imperial system, it is equal to 0.9144 meters or 3 feet. Yards are commonly used for measuring larger distances, such as in construction or landscaping, as well as in some sports like American football and cricket.
The area of the rectangular patio is given by multiplying its length by its width, so the area is:
A = (1 + 2x)(2 - 3x)
Now using distributive property we get,
A = 2 - 3x + 4x - 6x²
Simplifying further, we get:
A = -6x² + x + 2
Therefore, the area of the patio is described by the quadratic equation -6x² + x + 2.
To find the perimeter of the patio, we add up the lengths of all four sides. The length and width are given as (1 + 2x) and (2 - 3x), respectively, so the perimeter is:
P = 2(1 + 2x) + 2(2 - 3x)
Simplifying this expression, we get:
P = 2 + 4x + 4 - 6x
P = 6 - 2x
Therefore, the perimeter of the patio is described by the linear equation 6 - 2x.
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the center of a semisimple lie algebra {\displaystyle {\mathfrak {g}}}{\mathfrak {g}} is trivial proof. t/f
Answer:
False. The center of a semisimple Lie algebra is usually not trivial.
Step-by-step explanation:
The center of a semisimple Lie algebra is the set of elements of the Lie algebra that commute with all other elements in the algebra. In most cases, the center of a semisimple Lie algebra is not trivial, meaning it contains at least one non-zero element. For example, the center of the simple Lie algebra sl(2,C) contains the two-dimensional Lie algebra spanned by the scalar matrices I and -I. The center of the Lie algebra so(5,C) is spanned by the five-dimensional Lie algebra spanned by the matrices diag(1,1,1,-1,-1). These examples demonstrate that the center of a semisimple Lie algebra is usually not trivial.
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Five-Number Summary
Greenville Oaktown
minimum = 1 minimum = 2
Q1 = 8 Q1 = 6
median = 12 median = 8
Q3 = 16 Q3 = 9
maximum = 22 maximum = 15
Construct a box-and-whisker plot of the data for each city on the same number line using the
five-number summaries.
A box-and-whisker plot, also known as a box plot, is a data visualization technique used to summarize and display the distribution of a set of values.
The five-number summary, which includes the minimum value, the first quartile (Q1), the median, the third quartile (Q3), and the maximum value, is used to create the box plot. In this case, we are comparing the data for two cities, Greenville and Oaktown.
The five-number summary for each city is provided in the question: Greenville: minimum = 1 Q1 = 8 median = 12 Q3 = 16 maximum = 22 Oaktown: minimum = 2 Q1 = 6 median = 8 Q3 = 9 maximum = 15 To construct a box-and-whisker plot for each city on the same number line, we will use the following steps:
1. Draw a number line with the minimum and maximum values for both cities.
2. Draw a vertical line at the first quartile (Q1) for both cities.
3. Draw a box from Q1 to Q3 for both cities.
4. Draw a vertical line at the third quartile (Q3) for both cities.
5. Draw whiskers from the box to the minimum and maximum values for both cities.
6. Label each box-and-whisker plot with the name of the corresponding city. The resulting box-and-whisker plot for Greenville and Oaktown on the same number line is shown below:
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NO LINKS!!! URGENT HELP PLEASE!!!
Solve ΔABC using the Law of Sines
1. A = 29°, C = 63°, c = 24
2. A = 72°, B= 35°, c = 21
Answer:
1) B = 88°, a = 13.1, b = 26.9
2) C = 73°, a = 20.9, b = 12.6
Step-by-step explanation:
To solve for the remaining sides and angles of the triangle, given two sides and an adjacent angle, use the Law of Sines formula:
\(\boxed{\begin{minipage}{7.6 cm}\underline{Law of Sines} \\\\$\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}$\\\\\\where:\\ \phantom{ww}$\bullet$ $A, B$ and $C$ are the angles. \\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides opposite the angles.\\\end{minipage}}\)
Question 1Given values:
A = 29°C = 63°c = 24As the interior angles of a triangle sum to 180°:
\(\implies A+B+C=180^{\circ}\)
\(\implies B=180^{\circ}-A-C\)
\(\implies B=180^{\circ}-29^{\circ}-63^{\circ}\)
\(\implies B=88^{\circ}\)
Substitute the values of A, B, C and c into the Law of Sines formula and solve for sides a and b:
\(\implies \dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}\)
\(\implies \dfrac{a}{\sin 29^{\circ}}=\dfrac{b}{\sin 88^{\circ}}=\dfrac{24}{\sin 63^{\circ}}\)
Solve for a:
\(\implies \dfrac{a}{\sin 29^{\circ}}=\dfrac{24}{\sin 63^{\circ}}\)
\(\implies a=\dfrac{24\sin 29^{\circ}}{\sin 63^{\circ}}\)
\(\implies a=13.0876493...\)
\(\implies a=13.1\)
Solve for b:
\(\implies \dfrac{b}{\sin 88^{\circ}}=\dfrac{24}{\sin 63^{\circ}}\)
\(\implies b=\dfrac{24\sin 88^{\circ}}{\sin 63^{\circ}}\)
\(\implies b=26.9194211...\)
\(\implies b=26.9\)
\(\hrulefill\)
Question 2Given values:
A = 72°B = 35°c = 21As the interior angles of a triangle sum to 180°:
\(\implies A+B+C=180^{\circ}\)
\(\implies C=180^{\circ}-A-B\)
\(\implies C=180^{\circ}-72^{\circ}-35^{\circ}\)
\(\implies C=73^{\circ}\)
Substitute the values of A, B, C and c into the Law of Sines formula and solve for sides a and b:
\(\implies \dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}\)
\(\implies \dfrac{a}{\sin 72^{\circ}}=\dfrac{b}{\sin 35^{\circ}}=\dfrac{21}{\sin 73^{\circ}}\)
Solve for a:
\(\implies \dfrac{a}{\sin 72^{\circ}}=\dfrac{21}{\sin 73^{\circ}}\)
\(\implies a=\dfrac{21\sin 72^{\circ}}{\sin 73^{\circ}}\)
\(\implies a=20.8847511...\)
\(\implies a=20.9\)
Solve for b:
\(\implies \dfrac{b}{\sin 35^{\circ}}=\dfrac{21}{\sin 73^{\circ}}\)
\(\implies b=\dfrac{21\sin 35^{\circ}}{\sin 73^{\circ}}\)
\(\implies b=12.5954671...\)
\(\implies b=12.6\)
What is the value of 21 over 4 − 32 over 5?
In linear equation, -1.15 is the value of 21 over 4 − 32 over 5.
What in mathematics is a linear equation?
An algebraic equation B. y=mx+b (where m is the slope and b is the y-intercept) containing simple constants and first-order (linear) components, such as the following, is called a linear equation. The above is sometimes called a "linear equation in two variables" where x and y are variables.
An equation with only one variable is called a univariate linear equation. It contains the expression Ax + B = 0. where A and B are any two real numbers and x is an ambiguous variable with only one possible value.
(21/4) - (32/5)
= 21 * 5 - 32 * 4/ 20
= 105 - 128/20
= -1.15
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Brand A has a box of 25 forks for 1.99 and Brand B has a box of 42 totals for 3.89. What is the unit price for each brand and what brand is a better buy based on unit price
Answer:
Brand A
Step-by-step explanation:
Brand A has a box of 25 forks for 1.99
Take the price per fork
1.99 /25 = .0796
.08 per fork
Brand B has a box of 42 totals for 3.89
3.89 / 42
.092319048
.09 per fork
5. Use the formula
A = ¹h(b₁ + b₂) to
find the area of the
trapezoid.
The area of the
trapezoid is
9 cm
3 cm
5 cm
-1.5 cm
21
27 square centimeters.
29.3
The area of the trapezoid \(36^{2}\) centimeters
To use the formula A = ¹h(b₁ + b₂) to find the area of a trapezoid, you need to know the height (h) and the lengths of the two parallel bases (b₁ and b₂).
For example,
The formula for finding the area of a trapezoid is A = ¹h(b₁ + b₂),
Where A represents the area of the trapezoid, h represents the height, and b₁ and b₂ represent the lengths of the two parallel bases.
By plugging in the given values for the height and bases and performing the necessary arithmetic operations, you can find the area of the trapezoid.
It's important to remember to use the correct units and follow the order of operations to obtain the correct result.
If the height of the trapezoid is 9 cm, the lengths of the two bases are 3 cm and 5 cm, you can plug these values into the formula to find the area :
A = ¹h(b₁ + b₂)
= ¹(9)(3 + 5)
= ¹(9)(8)
= 36 square centimeters
So, the area of this trapezoid is 36 square centimeters.
If you have different values for the height and bases, you can use the same formula to find the area.
Just make sure to use the correct units and follow the order of operations (parentheses first, then multiplication and division, then addition and subtraction).
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In Rebecca's neighborhood, 89% of the houses have garages and 48% have a
garage and a pool. What is the probability (in percent) that a house in her
neighborhood has a pool, given that it has a garage? Round your answer to 1
decimal place.
why are there two of these?
Answer:
53.9
Step-by-step explanation:
89% of all houses have garages and 48% have garages and pools. We try to find houses with a pool that have a garage. Let's assume that there are 100 houses in her neighborhood. then 89 of them have garages and 48 of them have garages and pools. 48 / 89 = about 0.5393. Conver this to percent and we get 53.9
Chuck is picking up pecans in his yard. He discovered that 2 out of every 15 pecans are bad. If he picks up 840 pecans, about how many will be bad in the group?
Answer:
Who picks up that many pecans?
Step-by-step explanation:
i get bored after like 30. jeez.
The equation
Ax+By=−18
A
x
+
B
y
=
−
18
goes through the coordinates (-3, 10) and (6, -2).
By solving a system of equations, we will see that the equation is:
-4*x - 3*y = -18
How to find the equation?We know that the linear equation:
A*x + B*y = -18
We know that this linear equation passes through the points (-3, 10) and (6, -2), then replacing these values in the equation we will get two equations:
A*-3 + B*10 = -18
A*6 + B*-2 = -18
So we have a system of equations:
-3A + 10B = -18
6A - 2B = -18
if we add the two times the first equation and the second one we get:
2*(-3A + 10B) + 6A - 2B = 2*(-18) - 18
18B = -3*18
B = -3
by replacing that value of B in one of the equations we will be able to solve it for A.
6*A - 2*(-3) = -18
6*A + 6 = -18
6*A = -18 - 6 = -24
A = -24/6 = -4
The equation is:
-4*x - 3*y = -18
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somone answer pleaseeeeeee
Answer:
C.) 2^10
Step-by-step explanation:
You would add the exponents which in this case are 3 and 7 getting 10 as your exponent.
Answer: C)
Step-by-step explanation: If you do 2^3 x 2^7 = 1024 also 2^10 = 1024
(3.2 x 104)x(1.4 x 102)
Answer:
47523.84
Step-by-step explanation:
An observer stands 400 ft away from a launch pad to observe a rocket launch. The rocket blasts off and maintains a velocity of 300 ft/sec. Assume the scenario can be modeled as a right triangle. How fast is the observer to rocket distance changing when the rocket is 300 ft from the ground?
Let's draw the scenario to understand it better:
From the figure, the information given are:
\(\frac{dy}{d\text{t}}=\text{ 300 ft./sec}\)Question:
\(\text{What is }\frac{dD}{dt}\text{ at y = }300\text{ ft.}\)Step 1: We write a function that relates the quantities in the diagram using Pythagorean
Theorem.
\(\text{ 400}^2\text{ + }y^2=D^2\)Step 2: Differentiate with respect to t.
\(2y\frac{dy}{dt}=\text{ }2D\frac{dD}{dt}\)Now we wish to plug in specific numbers for every quantity in the above equation except for dD/dt. However, we notice that we don’t have a specific value for D at y = 400 ft. So first we need to find D at y = 400 ft. using the Pythagorean Theorem.
\(400^2\text{ + }300^2=D^2\)\(D\text{ = }\sqrt[]{400^2+300^2}\)\(D\text{ = 500 ft.}\)Step 3: Finish the problem by plugging in numbers for every quantity in the equation
containing dD/dt.
\(2(300)(300)\text{ = 2(500)}(\frac{dD}{dt})\)\(\frac{dD}{dt}=\text{ }\frac{2(300)(300)}{2(500)}\)\(\frac{dD}{dt}=\text{ }\frac{180,000}{1000}\)\(\frac{dD}{dt}=180\)Conclusion: When the rocket is 300 ft. feet from the ground, the distance between the observer and the rocket is increasing at a rate of 180 ft./sec.
What is the absolute value of -3.75
Answer:
the absolute value of -3.75 is 3.75
What is the answer to 11.24 divided by 9
Answer:
1.24
Step-by-step explanation:
oahsofhasdf0as0dfadera
if you are asked to find the value of the 100th term of a sequence, would you use the explicit formula for that sequence or the recursive formula?
An arithmetic sequence is a sequence of integers with its adjacent terms differing with one common difference.
We know that,
An arithmetic sequence is a sequence of integers with its adjacent terms differing with one common difference.
The explicit formula for any arithmetic series is given by the formula,
a_n = a_1 + (n-1)d
where d is the difference and a₁ is the first term of the sequence.
The major distinction between recursive and explicit formulas is that a recursive formula returns the value of a particular term depending on the preceding term, whereas an explicit formula returns the value of a given term based on its location.
When the value of the first term and the common difference is known then an explicit formula is used, while the recursive formula will be used when the value of the previous value is known and the value of the common difference is known.
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complete question:
what is the difference between the explicit formula and recursive formula for sequences when would you use one over the other
What is the probability that both events will occur? Two dice are tossed. Event A: the first die is a 5 or 6. Event B: The second die is not a 1
Answer: The probability that both events A and B will occur is 5/18 or 0.28.
Step-by-step explanation:
To determine the probability that both events A and B will occur, we need to calculate the probabilities of each event separately and then multiply them together.
Event A: The probability of rolling a 5 or 6 on the first die is 2 out of 6 (since there are two favorable outcomes out of six possible outcomes on a fair six-sided die). Therefore, the probability of event A is 2/6 or 1/3.
Event B: The probability of not rolling a 1 on the second die is 5 out of 6 (since there are five favorable outcomes out of six possible outcomes). Therefore, the probability of event B is 5/6.
To find the probability that both events A and B occur, we multiply the probabilities:
Probability(A and B) = Probability(A) * Probability(B) = (1/3) * (5/6) = 5/18.
Alex and Tim are going to race. Tim gives Alex a 50 meter head start. Alex
walks 2 meters per second. Tim walks 4 meters per second. When will the
two tie?
Answer:
After 3 min
Step-by-step explanation:
So becuase Tim is walking and Tim gave Alex a 50 meter head start so after 3 min they will tie each other.
It is estimated that 78% of drivers use their turn signal.
Part A: What is the probability that exactly 3 drivers use their turn signal if a police
officer pulls over five drivers? (5 points)
Part B: What is the probability the next driver using their turn signal that the police
officer pulls over is the fifth driver? (5 points) (10 points)
I
Answer:
A) 0.23
B) 0.14
Step-by-step explanation:
Part A)
To solve this question, we'll have to use the Bernoulli formula.
The formula claims that the probability to get \(k\) successes out of \(n\) attempts is given by \(\binom{n}{k}p^k(1 - p)^{n - k}\).
In our case, \(n = 5\), \(k = 3\), and \(p = 0.78\).
Therefore, the probability that 3 out of the 5 drivers use their turn signal is
\(\binom53 \times 0.78^3 \times 0.22^2 \to 0.23\)
Part B)
We are told that the police officer pulled over 5 drivers, 3 of them using turn signals. In this part, we are asked "what is the probability that the 5th driver uses the turn signal and only 2 of the previous four drivers use turn signals?".
\(0.78 \times \binom42 \times 0.78^2 \times 0.22^{4-2}\\\to 0.14\)
Find the exponential function f(x) = Ca² whose graph passes through the points (0,4) and (2, 16).
Question 5
Find a formula for the exponential function f(x) = Ca passing through the points
(-1,-) and (1, 20)
I need help asap
The exponential function that passes through the points (-1,-y) and (1,20) is f(x) = -20eˣ.
We need to use the given points to form two equations and solve for the constants in the exponential function.
For the first problem:
Let (0,4) and (2,16) be the given points.
Since the function is of the form f(x) = Ca², we have:
f(0) = C(0)² = 4
f(2) = C(2)² = 16
Simplifying each equation:
C = 4
4a² = 16
a² = 4
a = ±2
Therefore, the exponential function that passes through the points (0,4) and (2,16) is f(x) = 4(2)² = 16 or f(x) = 4(-2)² = 16.
For the second problem:
Let (-1,y₁) and (1,y₂) be the given points.
Since the function is of the form f(x) = Ca, we have:
f(-1) = Ca = y₁
f(1) = Ca = y₂
Simplifying each equation:
C =y₁/a
C =y₂/a
Equating both expressions for C, we have:
y₁/a = y₂/a
y₁=y₂
Therefore, the exponential function that passes through the points (-1,-y) and (1,20) is f(x) = -20eˣ.
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Let f(x)
f'(x) =
-
=
1
v2x2+5x+3
Question Help:
(Use sqrt(N) to write √N)
Video Written Example
The derivative of the function \(f(x) = \frac{1}{\sqrt{2x^2 + 5x + 3}}\) is \(f'(x) = -\frac{4x + 5}{2((x + 1)(2x + 3))^\frac{3}{2}}\)
How to calculate the derivative of the functionFrom the question, we have the following parameters that can be used in our computation:
\(f(x) = \frac{1}{\sqrt{2x^2 + 5x + 3}}\)
Factor the expression
So, we ave
\(f(x) = \frac{1}{\sqrt{(x + 1)(2x + 3)}}\)
The derivative of the function can be calculated using as follows:
\(f'(x) = (-\frac{1}{2})((x + 1)(2x + 3))^{-\frac{1}{2} - 1} \cdot \frac{d}{dx}[(x + 1)(2x + 3)]\)
Next, we have
\(f'(x) = -\frac{\frac{d}{dx}(x + 1) \cdot (2x + 3) + (x + 1) \cdot \frac{d}{dx}(2x + 3)}{2((x + 1)(2x + 3))^\frac{3}{2}}\)
Differentiate
\(f'(x) = -\frac{1 \cdot (2x + 3) + (x + 1) \cdot 2}{2((x + 1)(2x + 3))^\frac{3}{2}}\)
This gives
\(f'(x) = -\frac{2x + 3 + 2x + 2}{2((x + 1)(2x + 3))^\frac{3}{2}}\)
Evaluate the like terms
\(f'(x) = -\frac{4x + 5}{2((x + 1)(2x + 3))^\frac{3}{2}}\)
Hence, the derivative of the function is \(f'(x) = -\frac{4x + 5}{2((x + 1)(2x + 3))^\frac{3}{2}}\)
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The perimeter of the triangle below is 68 units. Find the value of y
Which of these tables lists all the possible outcomes of flipping 3 coins? (Each row represents one outcome.) Choose all answers that apply: Choose all answers that apply:
Answer:
Table B
Step-by-step explanation:
The table B shows possible outcomes of flipping 3 coins.
What is Outcome in Experiment?A probability experiment is a test in which we execute a series of trials to determine the likelihood of an event occurring in the future. A probability experiment's results may reveal a previously unknown truth or lead us to learn anything about the likelihood (or chance) of an occurrence occurring in the future.
Given:
If three coins are flipped then the possible outcomes are:
{ HHH,
HHT,
HTH
THH,
TTT,
TTH,
THT,
HTT}
So, there total 8 number of outcomes.
But in table 1 the number of outcomes is 5.
Thus, table B shows possible outcomes of flipping 3 coins.
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Waiting Line Models:Movies tonight is a typical video and dvd movie rental outlet for home-viewing customers. During the weeknight evening, customers arrive at Movies Tonight with an arrival rate of 1.25 customers per minute. The checkout clerk has a service rate of 2 customers per minute/ Assume Poisson arrivals and exponential service times.a. What is the probability that no customers are in the system?b. What is the average number of customers waiting for service?c. What is the average time a customer waits for service to begin?d. What is the probability that an arriving customer will have to wait for service to begin?e. Do the operating charachteristics indicate that the one-clerk checkout system provides and acceptable level of service?
Answer:
Probability [No customers in system] = 0.375Customers waiting for service = 25/24Average time customer wait = 1.25/1.5May be waitPer customer average time = 1.33 (Approx)Step-by-step explanation:
Given:
Arrival rate λ = 1.25 min
Mean μ = 2
Computation:
(a) Probability [No customers in system]
Probability [No customers in system] = 1-[λ/μ]
Probability [No customers in system] = 1-[1.25/2]
Probability [No customers in system] = 0.375
(b) Customers waiting for service
Customers waiting for service = λ²/ [μ(μ-λ)]
Customers waiting for service = 1.25²/ [2(2-1.25)]
Customers waiting for service = 25/24
(c) Average time customer wait
Average time customer wait = λ / [μ(μ-λ)]
Average time customer wait = 1.25/ [2(2-1.25)]
Average time customer wait = 1.25/1.5
(d) May be wait because Customers waiting for service = 25/24
(e) Per customer average time
Per customer average time = 1/(μ-λ)
Per customer average time = 1/(2-1.25)
Per customer average time = 1.33 (Approx)