What is the answer to \(-9(\sqrt{x} -9) -9\)

Answer:

16+2.36=18.36

Step-by-step explanation:

( what expressions did they give u to pick?)

It will take 7 men 42 hours to complete the job if they work at the same rate.

If it takes 4 men 6 hours to repair a road, it means that the total work done is 1 job.

The number of man-hours required to complete the job is the product of the number of men and the number of hours

= 4 men x 6 hours

= 24 man-hours

Now, let's find out how many hours it will take for 7 men to do the same job. We can set up a proportion using the man-hours:

4 men / 24 hours = 7 men / x hours

4x = 7 (240)

4x = 168

x = 168 / 4

x = 42

Therefore, it will take 7 men 42 hours to complete the job if they work at the same rate.

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The simplified form of the trigonometric expression cscθ - cosθ cotθ is cscθ - 1.

To simplify the given expression, let's start by expressing each trigonometric function in terms of sine and cosine. The reciprocal of the sine function is the cosecant function (csc), and the reciprocal of the tangent function is the cotangent function (cot).

cscθ - cosθ cotθ can be written as cscθ - cosθ (cosθ/sinθ).

To simplify further, we can combine the terms with a common denominator. The common denominator is sinθ, so we need to multiply cscθ by sinθ to get a common denominator.

This gives us (1/sinθ)(sinθ) - cosθ (cosθ/sinθ).

Now, simplifying the expression, we have 1 - \(cos^2(Θ)/sinΘ.\)

Using the trigonometric identity sin^2θ + cos^2θ = 1, we can replace cos^2θ with 1 - sin^2θ.

Substituting, we get \(1 - (1 - sin^2θ)/sinθ.\)

Simplifying further, we have \(1 - 1/sinθ + sin^2θ/sinθ.\)

Finally, combining the terms, we get 1 - cscθ + sinθ.

Therefore, the simplified form of cscθ - cosθ cotθ is cscθ - 1.

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The equations that correctly apply properties of operations include:

The equation of 15 b + 10c = 5 ( 3b+ 2c ) is correct in using the property of operations because it uses the distributive property correctly.

a + a + a = 3a uses the repeated addition property, to show that when you add the same number a certain number of time, the result is the same as multiplying that number by the certain number of times.

6 ( 3 + y ) = 18 + 6y like option B, uses the distributive property correctly.

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Answer:

4/5 i dont get the question but this is what 8/10 is equal to

Step-by-step explanation:

Answer:

-3.68 = n

Step-by-step explanation:

1. Simplify

-2.04-12= n- 3+2n

2. Isolate n

-2.04-12+3=n+2n

3. Simplify

-11.04=3n

4. Divide both sides by 3

-3.68 = n

To find the 99% confidence interval for the difference in the proportion of people that live in a city who identify as a gambler and the proportion of people that live in a rural area who identify as a gambler.

Given, Sample 1: $n_1 = 272$, number of successes $= 82$,Sample 2: $n_2 = 95$, number of successes $= 60$,

The proportion of people that live in a city who identify as a gambler is,

$$\large\bar{p}_1

= \frac{\text{Number of people who identified as a gambler in sample 1}}{\text{Sample size of sample 1}}

= \frac{82}{272} = 0.3015$$

The proportion of people that live in a rural area who identify as a gambler is,$$\large\bar{p}_2

= \frac{\text{Number of people who identified as a gambler in sample 2}}{\text{Sample size of sample 2}}

= \frac{60}{95}

= 0.6316$$

The sample size of both the samples are greater than 30.

Hence, we can assume that the sampling distribution is approximately normal.

The standard error of the difference in sample proportions is,$$\large\sqrt{\frac{\bar{p}_1(1-\bar{p}_1)}{n_1} + \frac{\bar{p}_2(1-\bar{p}_2)}{n_2}}$$$$\large\sqrt{\frac{0.3015(1-0.3015)}{272} + \frac{0.6316(1-0.6316)}{95}} = 0.0882$$The critical value $z_{\alpha/2}$ for a 99% confidence level is $2.576$.

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The requried, 140% is equivalent to 7/5 as a fraction, 1 2/5 as a mixed number, and 2 as a whole number.

To write 140% as a fraction, we first recognize that "percent" means "per hundred," so 140% can be written as the fraction 140/100. We can simplify this fraction by dividing both the numerator and denominator by their greatest common factor (GCF), which is 20:

140/100 = 7/5

To write 7/5 as a mixed number, we divide the numerator by the denominator and express the result as a whole number plus a fraction. In this case:

7 ÷ 5 = 1 with a remainder of 2

So 7/5 can be written as the mixed number 1 2/5.

To write 7/5 as a whole number, we can round it to the nearest whole number. Since 7/5 is greater than 1.5 and less than 2.5, it rounds to 2.

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The statement "there is a strong relationship showing that as the number of days increases, the height of the plants increases" is correct.

It is defined as the relation between two variables, which is a quantitative type and gives an idea about the direction of these two variables.

\(\rm r = \dfrac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{{[n\sum x^2- (\sum x)^2]}}\sqrt{[n\sum y^2- (\sum y)^2]}}\)

Here, the value of the correlation coefficient is 0.85

As we know, when the value of r is near to 1, the correlation is strong.

And when r > 1, the relation between x and y such that as x increases, y also increases.

Thus, the statement "there is a strong relationship showing that as the number of days increases, the height of the plants increases" is correct.

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a) The probability that a tire will be too narrow is 0.252492. b)The probability that a tire will be too wide is 0.091211. c) , the probability that a tire will be defective is 0.252492 + 0.091211 = 0.343703.

a. To calculate the probability that a tire will be too narrow, we need to find the area under the normal distribution curve that falls below the lower specification limit.

Using the Z-score formula, we calculate the Z-score for the lower specification limit as follows:

Z = (Lower specification limit - Mean) / Standard deviation

Z = (22.8 - 23) / 0.15

Z = -0.666667

Next, we find the corresponding area from the standard normal distribution table or using a calculator. The area to the left of Z = -0.666667 is approximately 0.252492.

b. To calculate the probability that a tire will be too wide, we need to find the area under the normal distribution curve that falls above the upper specification limit.

Using the Z-score formula, we calculate the Z-score for the upper specification limit as follows:

Z = (Upper specification limit - Mean) / Standard deviation

Z = (23.2 - 23) / 0.15

Z = 1.333333

Next, we find the corresponding area from the standard normal distribution table or using a calculator. The area to the right of Z = 1.333333 is approximately 0.091211.

c. The probability that a tire will be defective is the sum of the probabilities of it being too narrow and too wide, since being outside the specification limits indicates a defect.

Therefore, the probability that a tire will be defective is approximately 0.252492 + 0.091211 = 0.343703.

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The equation can only have a solution if 2 < sin(5x/2 - x/2) or sin(5x/2 - x/2) < -2.

First, let's simplify the equation by using the identity sin A - sin B = 2 cos((A+B)/2)sin((A-B)/2). Applying this identity, we get:

sin(5x/2 - x/2) = 2 cos(3x/2)sin(x/2)

Next, we can use the fact that -1 ≤ sin(x) ≤ 1 for any angle x to obtain:

-2 ≤ 2 cos(3x/2)sin(x/2) ≤ 2

However, neither of these inequalities has a solution since the range of the sine function is [-1, 1]. Therefore, the equation has no solutions in the interval [0, 2π].

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Complete Question:

The number of solutions of the equation sin 5x/2 − sin x/2 = 2  in [0,2π] is

To calculate the molecular weight of a gas with a density of 1.524 g/l at STP, we can use the ideal gas law: PV = nRT. At STP, the pressure (P) is 1 atm, the volume (V) is 22.4 L/mol, and the temperature (T) is 273 K. The molecular weight of the gas with a density of 1.524 g/L at STP is approximately 32.0 g/mol.

Rearranging the equation, we get n = PV/RT.

Next, we can calculate the number of moles (n) of the gas using the given density of 1.524 g/l. We know that 1 mole of any gas at STP occupies 22.4 L, so the density can be converted to mass by multiplying by the molar mass (M) and dividing by the volume: density = (M*n)/V. Rearranging the equation, we get M = (density * V) / n.

Substituting the given values, we get n = (1 atm * 22.4 L/mol) / (0.0821 L*atm/mol*K * 273 K) = 1 mol. Then, M = (1.524 g/L * 22.4 L/mol) / 1 mol = 34.10 g/mol. Therefore, the molecular weight of the gas is 34.10 g/mol.

To calculate the molecular weight of a gas with a density of 1.524 g/L at STP, you can follow these steps:

1. Recall the ideal gas equation: PV = nRT

2. At STP (Standard Temperature and Pressure), the temperature (T) is 273.15 K and the pressure (P) is 1 atm (101.325 kPa).

3. Convert the density (given as 1.524 g/L) to mass per volume (m/V) by dividing it by the molar volume at STP (22.4 L/mol). This will give you the number of moles (n) per volume (V):

  n/V = (1.524 g/L) / (22.4 L/mol)

4. Calculate the molar mass (M) of the gas using the rearranged ideal gas equation, where R is the gas constant (8.314 J/mol K):

  M = (n/V) * (RT/P)

5. Substitute the values and solve for M:

  M = (1.524 g/L / 22.4 L/mol) * ((8.314 J/mol K * 273.15 K) / 101325 Pa)

6. Calculate the molecular weight of the gas:

  M ≈ 32.0 g/mol

Therefore, the molecular weight of the gas with a density of 1.524 g/L at STP is approximately 32.0 g/mol.

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Answer:

Which one do we answer?

The measure of ZAFD is 50 degrees.

Based on the given information:

ZCFE is congruent to ZCFA.

mZCFB = 68°.

mZEFD = 62°.

To find the measure of ZAFD, we can use the fact that angles in the same segment of a circle are equal.

Since ZCFE and ZCFA are congruent, angle ZCFE is equal to angle ZCFA.

Therefore, mZCFA = mZCFE.

Now, let's find the measure of angle ZCFE:

mZCFE = mZCFB + mZEFD (Angle Addition Postulate)

mZCFE = 68° + 62°

mZCFE = 130°

Since ZCFA is congruent to ZCFE, we can conclude that mZCFA is also equal to 130°.

Now, to find the measure of ZAFD, we need to consider the angles in the quadrilateral ZAFD.

The sum of the angles in a quadrilateral is always 360°.

mZAFD + mZAFB + mZBFD + mZBFA = 360°

We know that mZAFB and mZBFD are equal to 90° because they are right angles (angle AFB and angle BFD are right angles in the diagram).

Therefore, we can rewrite the equation as:

mZAFD + 90° + 90° + mZBFA = 360°

Simplifying:

mZAFD + 180° + mZBFA = 360°

Rearranging the equation:

mZAFD + mZBFA = 360° - 180°

mZAFD + mZBFA = 180°

We know that mZBFA is equal to mZCFA, which is 130°.

Substituting the known values into the equation:

mZAFD + 130° = 180°

Subtracting 130° from both sides:

mZAFD = 180° - 130°

mZAFD = 50°

Therefore, the measure of ZAFD is 50 degrees.

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The answer to this question is no, f(x) itself is not necessarily differentiable even if f(x)^2 is differentiable.

Here is a counterexample to justify this:
Consider the function f(x) = |x|. This function is always positive for all x∈R, so f(x)>0 for all x∈R. However, f(x) is not differentiable at x=0, as there is a sharp corner at that point.

Now, let's look at f(x)^2. This is equivalent to (|x|)^2, which simplifies to x^2. The function x^2 is differentiable for all x∈R, so f(x)^2 is differentiable even though f(x) itself is not differentiable.

Therefore, we can conclude that even if f(x)^2 is differentiable, f(x) itself is not necessarily differentiable.

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Answer:

-2x(6x⁴ - 7x² + x - 5)

= -12x⁵ + 14x³ - 2x² + 10x

Answer:

See screenshot

Step-by-step explanation:

<m(lkj)+<m(ghi)=180°

34°+<m(ghi)=180°

180°-34°=<m(ghi)

146°=<m(ghi)

The measure of arc BC is 720 times the measure of angle BAC.

Given that AC is the diameter of the circle and AB is a chord with a length of 16 units, we need to find BC (the length of the other chord) and mBC (the measure of angle BAC).

To find BC, we can use the property of chords in a circle. If two chords intersect within a circle, the products of their segments are equal. In this case, since AB = BC = 16 units, the product of their segments will be:

AB * BC = AC * CE

16 * BC = 2 * r * CE (AC is the diameter, so its length is twice the radius)

Since the area of the circle is given as 289 square units, we can find the radius (r) using the formula for the area of a circle:

Area = π * r^2

289 = π * r^2

r^2 = 289 / π

r = √(289 / π)

Now, we can substitute the known values into the equation for the product of the segments:

16 * BC = 2 * √(289 / π) * CEBC = (√(289 / π) * CE) / 8

To find mBC, we can use the properties of angles in a circle. The angle subtended by an arc at the center of a circle is double the angle subtended by the same arc at any point on the circumference. Since AC is a diameter, angle BAC is a right angle. Therefore, mBC will be half the measure of the arc BC.

mBC = 0.5 * m(arc BC)

To find the measure of the arc BC, we need to find its length. The length of an arc is determined by the ratio of the arc angle to the total angle of the circle (360 degrees). Since mBC is half the arc angle, we can write:

arc BC = (mBC / 0.5) * 360

arc BC = 720 * mBC

Therefore, the length of the arc BC equals 720 times the length of the angle BAC.

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Answer:

(x + 3)(x + 2) = 9

x^2 + 5x + 6 = 9

x^2 + 5x = 3

Step-by-step explanation:

length * width = area

(x + 3)(x + 2) = 9

Expand

x^2 + 5x + 6 = 9

Subtract 6 from both sides

x^2 + 5x = 3

Answer:

5 × 5 + 25 - 10

= 25 + 25 - 10

= 50 - 10

= 40

Answer: 1

Step-by-step explanation:

4)

\(\displaystyle\\\frac{(sin\theta+cos\theta)^2}{1+2sin\theta cos\theta}=\\\\\frac{sin^2\theta+2sin\theta cos\theta+cos^2\theta}{1+2sin\theta cos\theta} =\\\\\frac{sin^2\theta+cos^2\theta+2sin\theta cos\theta}{1+2sin\theta cos\theta} =\\\\\frac{1+2sin\theta cos\theta}{1+2sin\theta cos\theta} =\\\\1\)

Answer:

The answer is 1

Step-by-step explanation:

The solution is in the image below

Mountain Mack can carve 30 fishing lures and 36 duck decoys in a week.

Mountain Mack spends his time carving fishing lures and duck decoys. It is stated that if he spends all of his time carving fishing lures, he can carve 30 lures in a week. Similarly, if he spends all of his time carving duck decoys, he can carve 25 decoys in a week. Additionally, for every 5 duck decoys Mountain Mack carves, he must give up 6 fishing lures.

To determine the number of fishing lures and duck decoys Mountain Mack can carve in a week, we need to consider the trade-off between the two activities. Let's assume that Mountain Mack spends x amount of time carving fishing lures and y amount of time carving duck decoys in a week.

From the given information, we know that if Mountain Mack spends all of his time carving fishing lures, he can carve 30 lures in a week. Therefore, we can set up the equation:

x = 30

Similarly, if Mountain Mack spends all of his time carving duck decoys, he can carve 25 decoys in a week. Hence, we can set up another equation:

y = 25

Now, let's consider the trade-off between fishing lures and duck decoys. For every 5 duck decoys carved, Mountain Mack must give up 6 fishing lures. This means that for every 5 units of y (duck decoys), he loses 6 units of x (fishing lures). We can express this relationship as:

(5/6)y = x

Now we have a system of equations:

x = 30

y = 25

(5/6)y = x

To solve this system, we can substitute the value of x from the first equation into the third equation:

(5/6)y = 30

y = (6/5) * 30

y = 36

Now that we have the value of y, we can substitute it back into the second equation to find x:

x = 30

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The percent of attendance figures that differs from the mean by 1500 persons or more is 6.68%.

From the question above, Mean μ = 10,000

Standard Deviation σ = 1,000

The formula for z-score is :

z = (x-μ) / σ

Where, x = observation

z = z-score

Mean μ = 10,000

Standard Deviation σ = 1,000

From the above formula, let's calculate z-score for x = 11,500

z = (x-μ) / σ

z = (11,500 - 10,000) / 1000

z = 1.5

Now, find the probability of attendance figures that differs from the mean by 1500 persons or more.

P(z ≥ 1.5) = 0.0668

To find the percentage, we need to multiply the above value by 100.

P(z ≥ 1.5) × 100 = 0.0668 × 100 = 6.68%

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Answer:

-----------------

Find each area and then find their difference.

The difference is:

Answer:

1+1=2

Step-by-step explanation:

2=1+1

Answer:

8

Step-by-step explanation:

18-12

12-X

X=12*12/18

X=8mm

Answer:

Step-by-step explanation:

step one:

This problem is focused on ratios and fractions

from the problem statement, Martin has 5/6 pizza

Liam has 4 times more of what Martin have

step two:

so we can express what Liam has as

=(5/6)*4 = 20/6or

=5/6+5/6+5/6+5/6= 20/6

= 20/6

step three:

we can reduce both numerator and denominator

= 10/3

Hence Liam has 10/3 pizza

Quantity of pizza that Liam has is;

3 full pizzas and a third of a pizza.

Martin has 5/6 of a pizza.

Thus;

Quantity of pizza that Martin has = 5/6

Now we are told that Liam has 4 times as much as Liam, then;

Quantity of pizza Liam has = 4(5/6) = 10/3

This translates to 3⅓ pizza

Thus, in conclusion, Liam has 3 full pizzas and a third of a pizza.

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The structure of the error term in the given model is an example of first-order autocorrelation or serial correlation. The correct answer is A.

This is because the current error term (εt) is linearly related to the past two error terms (εt-1 and εt-2) through the autoregressive coefficients (rho1 and rho2). This implies that the errors are not independently and identically distributed (i.i.d), violating one of the assumptions of the classical linear regression model.

Option A is therefore the correct answer.

Option B is incorrect because the Durbin-Watson test is used to detect the presence of autocorrelation, not any other type of error structure.

Option C is incorrect because perfect multicollinearity refers to a situation where two or more predictor variables are perfectly correlated with each other, leading to numerical problems in estimation.

Option D is incorrect because heteroskedasticity refers to a situation where the variance of the error term is not constant across observations, leading to biased and inefficient estimates of the regression coefficients. The correct answer is A.

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Spherical harmonics are an integral part of quantum mechanics. They describe the shape of the orbitals, which electrons occupy in atoms. Moreover, the spherical harmonics provide the angular distribution of a wave in spherical coordinates. In 3D, the spherical harmonics can be written as:

Ylm(θ, φ) = √(2l + 1)/(4π) * √[(l - m)!/(l + m)!] * Plm(cosθ) * e^(imφ)

Here, l and m are known as the angular quantum numbers. They define the shape and orientation of the orbital. Plm(cosθ) represents the associated Legendre polynomial, and e^(imφ) is the exponential function. The spherical harmonics have various forms, including:

Y1,1 = -Y1,-1 = 1/2 √(3/2π) sinθe^(iφ)

Y1,0 = 1/2 √(3/π)cosθ

Y2,2 = 1/4 √(15/2π)sin²θe^(2iφ)

Y2,1 = -Y2,-1 = 1/2 √(15/2π)sinθcosφ

Y2,0 = 1/4 √(5/π)(3cos²θ-1)

Y0,0 = 1/√(4π)

The spherical harmonics have various applications in physics, including quantum mechanics, electrodynamics, and acoustics. They play a crucial role in understanding the symmetry of various systems. Hence, the spherical harmonics are an essential mathematical tool in modern physics. Thus, this is how one can show another form for spherical harmonics.

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