Answer:
5(y-10)=-5
5y-50=-5
5y=45
y=9
Step-by-step explanation:
distribute
add 50 to the other side and undo it from its original side
get the variable by itself by dividing 5 on both sides
then you have your answer
I hope this helps!
Answer:
9
Step-by-step explanation:
5(y-10)=5
divide both sides by 5
50-5=45
45 divided by 5 is 9
Rewrite the product using the distributive Property then simplifly to find the answer.
!8(26)
The answer to the question 18(26) is 18 * (20 + 6) = 468
What is the distributive property of multiplication?This property states that multiplying the total of two or more addends by a number will produce the same outcome as multiplying each addend by the number separately and then adding the results together.
According to the distributive property, you can multiply a component by each addend separately before adding the total when multiplying it by two addends.
Based on this property, in order to solve a problem of this type, you have to expand the multiplication.
Hence 18(20 * 6)
is written as (18 * 20) + (18 * 6)
= 468
The answer is 468
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Write the standard form of the equation of a line passing through the points (0,-2) and (1, -5).
A. 3x + y + 2 = 0
B. 4x - y - 2 = 0
C. 3x + y - 2 = 0
D. 4x - y + 2 = 0
Answer:
3x + y + 2 = 0
Step-by-step explanation:
Write 5.48 repeating as a mixed number in simplest form
Answer:5 12/25
Step-by-step explanation:
48-24-12
over
100-50-25
The area of a circle is 100 pie. What is the radius?
A 25
B) 10
C 50
D) 5
Answer:
50 (hope this helps, have a good day)
Step-by-step explanation:
just divide The area divided by 2
A factory makes 3. 65 meters of masking tape every second. How many meters of masking tape can the factory make in 3 minutes
The factory can make 657 meters of masking tape in 3 minutes.
To calculate the total meters of masking tape the factory can make in 3 minutes, we need to convert the time to seconds and multiply it by the rate of production.
There are 60 seconds in 1 minute, so 3 minutes is equal to 3 * 60 = 180 seconds.
Now, we can calculate the total meters of masking tape:
Total meters of masking tape = Rate of production * Time
Total meters of masking tape = 3.65 meters/second * 180 seconds
Total meters of masking tape = 657 meters
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What is the equation of the line that passes through the point (-5,-3)and has a slope of -3/5 ?
Answer: y = -3/5x - 6
Step-by-step explanation:
There are a few equations that can be used for this, but the simplest one would be y = mx + b
We are given:
y = -3
m = -3/5 (slope)
x = -5
b = ?
Our equation is this, we are solving for b
==> -3 = -3/5 ( -5) + b
==> -3 = -3/5 ( -5) + b ( multiply the brackets)
==> -3 = 3 + b ( subtract 3 to both sides)
==> -6 = b
Now we can make the desired equation in slope intercept form;
y = -3/5x - 6
Hope this helped! Have a great day :D
a tablet pc manufacturer wishes to estimate the proportion of people who want to purchase tablet pcs which cost more than $700. find the required sample size when its 95% error margin is 0.03.
The required sample size when its 95% error margin is 0.03 with 385 samples.
Sample Size RequiredTo estimate the proportion of people who want to purchase tablet PCs that cost more than $700 with a 95% confidence level and an error margin of 0.03, you can use the formula for sample size:
n = (z² * p * (1-p)) / E²
where:
n is the sample sizez is the standard normal deviate (1.96 for a 95% confidence level)p is the proportion of people who want to purchase tablet PCs that cost more than $700 (unknown)E is the error margin (0.03)Since we don't know the proportion of people who want to purchase tablet PCs that cost more than $700, you can use a reasonable estimate or a conservative estimate (e.g., 0.50) in the formula.
n = (1.96² * 0.50 * (1 - 0.50)) / (0.03²)
n = 384.16
The sample size required is 385.
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The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0
Melissa obtains a loan for home renovations from a bank that charges simple interest at an annual rate of 16%. Her loan is for $15,400 for 93 days. Assume each day is 365 of a year. Answer each part below. Do not round any intermediate computations, and round your final answers to the nearest cent. If necessary, refer to the list of financial formulas. (a) Find the interest that will be owed after 93 days. XS ? (b) Assurning Melissa doesn't make any payments, find the amount owed after 93 days
To calculate the interest owed after 93 days, we use the formula for simple interest: Interest = Principal x Rate x Time. Substituting the given values, the interest amounts to $624.49.
This is the total interest that Melissa will owe to the bank after 93 days.Melissa took out a loan of $15,400 from a bank for home renovations. The bank charges a simple interest rate of 16% per year If Melissa doesn't make any payments towards the loan, the total amount owed after 93 days is obtained by adding the principal and the interest together.
Therefore, the total amount owed would be $16,024.49. This means that if Melissa does not make any payments during the 93-day period, her loan balance will increase to approximately $16,024.49, including both the original principal amount and the accrued interest.
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(m2 – 7m – 6) (7m2 – 3m – 7)
PLZ HELP URGENT WILL GIVE BRAINLIEST
Answer:
7m^4-52m^3-28m^2+67m+42
Answer:
Step-by-step explanation:
SOME ONE PLEASE ACTUALLY HELP ME
Answer:
y = 658.3 ft
Step-by-step explanation:
x = 745.5 ft
y = 658.3 ft
tan 28 = 350/y
y = 658.3
Answered by GAUTHMATH
the daily demand of a product can be specified by a normal distribution. its average daily demand is 250 units with a standard deviation of 40 units. the delivery lead time of this product is also normally distributed with an average of ten days and a standard deviation of three days. what are the safety stock and reorder point for a 95 percent service level?
Using Normal Distribution, the safety stock for a 95% service level is 209 units, and the reorder point is 2588 units.
To calculate the safety stock and reorder point, we need to use the following formulas:
Safety stock = z × σ × √(L)
Reorder point = d × L + SS
Where:
z = Z-score corresponding to the desired service level (95%)
σ = Standard deviation of daily demand
L = Lead time in days
d = Average daily demand
SS = Safety stock
We are given that the average daily demand is 250 units and the standard deviation of daily demand is 40 units. The lead time has an average of 10 days and a standard deviation of 3 days.
First, we need to find the Z-score for a 95% service level, which corresponds to 1.65.
Next, we can calculate the safety stock using the formula:
Safety stock = 1.65 × 40 × √(10) = 208.8 units (rounded to the nearest tenth)
Finally, we can calculate the reorder point using the formula:
Reorder point = 250 × 10 + 208.8 = 2588 units (rounded to the nearest whole number)
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for the problem of approximating the probability of a 6 in rolling a die, a. identify an appropriate family of distributions;
The appropriate family of distributions to approximate the probability of rolling a 6 on a fair die is the discrete uniform distribution, which assumes equal probabilities for each outcome. In this case, the probability of rolling a 6 would be approximately 1/6 based on the assumption of fairness.
For the problem of approximating the probability of rolling a 6 on a fair die, an appropriate family of distributions to consider is the discrete uniform distribution.
The discrete uniform distribution is commonly used to model situations where each outcome has an equal probability of occurring. In the case of rolling a fair die, the die has six equally likely outcomes (numbers 1 to 6).
Each outcome has a probability of 1/6 of occurring, making the discrete uniform distribution a suitable choice.
By assuming a discrete uniform distribution, we can assign equal probabilities to each outcome (1/6 for rolling a 6) and approximate the probability of rolling a 6 based on the assumption of fairness.
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Linda thinks of three integers. Added two at a time their sums are 80, 93, 87. What are the integers?
Answer:
They are 9, 5 and 8
Step-by-step explanation:
Evan was broke didn't he got his weekly allowance but because he has a hard time saving money he spent half his weekly allowance playing mini golf he just turned four dollars cleaning out his parents car if he now has 12 how much is his weekly allowance
Answer:
$16
Step-by-step explanation:
Let his weekly allowance = x
Amount spent playing golf = x / 2
Amount earned for cleaning car = $4
Final amount at hand = $12
Mathematically ;
x/2 + 4 = 12
x/2 = 12 - 4
x/2 = 8
x = 2 * 8
x = $16
Weekly allowance = $16
answer this plssss...
1.) 2³-3×(8-6)=
a.9 b.2 c.8 d.10
2.) 12÷2×(8÷2)=
a.24 b.20 c.18 d.28
3.) 20+(12×19)=
a.267 b.258 c. 250 d.248
4.) 21+4×12=
a.69 b.59 c.65 d.49
5.) 15×13+25×6=
a.125 b.265 c.345 d.575
Answer:
There are mistakes in the last answer to your question! Here is the correct solution.
1. b
2. a
3. d
4. a
5. c
a study of two kinds of photocopying equipment shows that 61 failures of the first kind of equipment took on the average 80.7 minutes to repair with a standard deviation of 19.4 minutes, whereas 41 failures of the second kind of equipment took on the average 88.1 minutes to repair with a standard deviation of 18.8 minutes. construct a 98% confidence interval for the ratio of the variances of the two populations sampled.
To construct a confidence interval for the ratio of the variances of the two populations sampled, we can use the F-distribution. The formula for the F-statistic is: F = (s1^2 / s2^2) / (n1 - 1) / (n2 - 1) Where s1 and s2 are the sample standard deviations, and n1 and n2 are the sample sizes.
Using the given data, we have:
s1 = 19.4
s2 = 18.8
n1 = 61
n2 = 41
The F-statistic is then:
F = (19.4^2 / 18.8^2) / (61 - 1) / (41 - 1) = 1.399
To find the confidence interval, we need to look up the critical values of the F-distribution with degrees of freedom (df) of (n1 - 1) and (n2 - 1) at the 1% level of significance.
Using a table or calculator, we find that the critical values are 0.414 and 2.518.
Thus, the confidence interval for the ratio of the variances is:
1 / (2.518 / sqrt(F)) < σ1^2 / σ2^2 < 1 / (0.414 / sqrt(F))
1 / (2.518 / sqrt(1.399)) < σ1^2 / σ2^2 < 1 / (0.414 / sqrt(1.399))
0.266 < σ1^2 / σ2^2 < 2.083
Therefore, we can be 98% confident that the ratio of the variances of the two populations sampled lies between 0.266 and 2.083.
To construct a 98% confidence interval for the ratio of the variances of the two populations sampled, we will use the F-distribution and the following formula:
CI = (s1^2 / s2^2) * (1 / Fα/2, df1, df2, F1-α/2, df1, df2)
Here, s1 and s2 are the standard deviations of the first and second kinds of equipment, and df1 and df2 are the degrees of freedom for each sample. Fα/2 and F1-α/2 are the F-distribution critical values at the α/2 and 1-α/2 levels, respectively.
Step 1: Calculate the variances (s1^2 and s2^2).
Variance1 = (19.4)^2 = 376.36
Variance2 = (18.8)^2 = 353.44
Step 2: Calculate the degrees of freedom (df1 and df2).
df1 = n1 - 1 = 61 - 1 = 60
df2 = n2 - 1 = 41 - 1 = 40
Step 3: Find the F-distribution critical values (Fα/2, df1, df2, F1-α/2, df1, df2) for a 98% confidence interval (α = 0.02).
F0.01, 60, 40 = 0.4611
F0.99, 60, 40 = 2.1080
Step 4: Calculate the confidence interval using the formula.
CI = (376.36 / 353.44) * (1 / 0.4611, 2.1080)
Lower limit = (376.36 / 353.44) * 0.4611 = 0.5925
Upper limit = (376.36 / 353.44) * 2.1080 = 2.2444
The 98% confidence interval for the ratio of the variances of the two populations sampled is (0.5925, 2.2444).
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a flat for sale sign has a perimeter of 58 inches. the length is 5 inches longer than the width. what is the width?
Answer:
25 inches
Step-by-step explanation:
1. Information that is needed to solve the problem;
The formula for the perimeter is:
2(a+b) = P
where "a" is the length and "b" is the width.
2. Solving the problem;
Substitute the given values into the formula;
2( 5 + b ) = 58
Inverse operations;
2 ( 5 + b ) = 58
/2 /2
5 + b = 29
-5 -5
b = 25
Se necesitan conductores voluntarios para llevar a 80 estudiantes al juego de béisbol de campeonato. Los conductores tienen automóviles, con capacidad para 4 estudiantes, o camionetas, con capacidad para 6 estudiantes. La ecuación describe la relación entre la cantidad de automóviles y la cantidad de camionetas que pueden transportar exactamente a 80 estudiantes.
Esta pregunta esta incompleta
Pregunta completa
Se necesitan conductores voluntarios para llevar a 80 estudiantes al juego de béisbol del campeonato. Los conductores cuentan con automóviles, con capacidad para 4 estudiantes, o camionetas, con capacidad para 6 estudiantes. La ecuación describe la relación entre la cantidad de automóviles y la cantidad de camiones que pueden transportar exactamente 80 estudiantes.
Seleccione todas las afirmaciones que sean verdaderas sobre la situación.
a) Si van 12 coches, se necesitan 2 furgonetas.
b) c = 14 y v = 4 son un par de soluciones de la ecuación.
c) Si van 6 coches y van 11 furgonetas, habrá espacio adicional.
d) 10 coches y 8 furgonetas no son suficientes para transportar a todos los estudiantes.
e) Si pasan 20 autos, no se necesitan camionetas.
f) 8 furgonetas y 8 coches son números que cumplen con las limitaciones en esta situación.
Answer:
La opción b, e y f.
Step-by-step explanation:
Pasando por las opciones dadas:
c = coches que pueden llevar a 4 estudiantes
v = furgonetas con capacidad para 6 estudiantes
a) Si van 12 coches, se necesitan 2 furgonetas.
= 12 (4) + 2 (6)
= 48 + 12
= 60
60 ≠ 80
La opción a es incorrecta
b) c = 14 y v = 4 son un par de soluciones de la ecuación.
14 (4) + 4 (6)
56 + 24 = 80 estudiantes
La opción b es correcta
c) Si van 6 coches y van 11 furgonetas, habrá espacio adicional.
Por lo tanto:
5 (4) + 11 (6)
= 20 + 66
= 86.
86 es mayor que 80, la opción c es correcta, habría un espacio adicional para 6 estudiantes.
d) 10 coches y 8 furgonetas no son suficientes para transportar a todos los estudiantes.
Por lo tanto:
10 (4) + 8 (6)
40 + 48
= 88
e) Si pasan 20 autos, no se necesitan camionetas.
20 (4) = 80 estudiantes
La opción e es correcta
f) 8 furgonetas y 8 coches son números que cumplen con las limitaciones en esta situación.
8 (6) + 8 (4)
= 48 + 32
= 80 estudiantes.
La opción b es correcta
Por lo tanto, la ecuacióna que describe la relación entre la cantidad de automóviles y la cantidad de camiones que pueden transportar exactamente 80 estudiantes es la opción b, e y f.
100 points
Can someone help me with this problem, and can you please show me your work so I know how you did it?
Please factor this polynomial completely
18x^3 + 6x^2y - 9x^2 - 3xy
A variable resistor R and an 8-Ω resistor in parallel have a combined resistance RT given by RT =8R/(8+R) . If R is changing at 0.30 /min, find the rate at which R, is changing when R = 6.0 Ω
Create a report on the application you selected. Include the problem statement, mathematical and verbal work to answer all parts of the problem, and additional discussion of the problem and how it is useful. Note, you are to not only answer the question posed in the textbook, you are to create and comment on the application in general.
Your write-up should include proper mathematical notation and justification for all work and answers, both mathematical and verbal, along with a citation of the textbook since you will be using a problem from the book in your work.
In this problem, we are given a variable resistor R and an 8-Ω resistor in parallel. We are asked to find the rate at which the resistance R is changing when it is equal to 6.0 Ω.
Given that RT = 8R / (8 + R), we can differentiate this equation with respect to time t using the quotient rule. Let's denote dR/dt as the rate of change of R with respect to time. Applying the quotient rule, we have:
dRT/dt = \([ (8)(dR/dt)(8 + R) - (8R)(dR/dt) ] / (8 + R)^2\)
To find the rate at which R is changing when R = 6.0 Ω, we substitute R = 6.0 into the above equation:
dRT/dt = \([ (8)(dR/dt)(8 + 6.0) - (8)(6.0)(dR/dt) ] / (8 + 6.0)^2\)
Simplifying further, we have:
dRT/dt = \([ (8)(dR/dt)(14) - (48)(dR/dt) ] / (14)^2\)
dRT/dt = (112(dR/dt) - 48(dR/dt)) / 196
dRT/dt = 64(dR/dt) / 196
dRT/dt = 16(dR/dt) / 49
Therefore, the rate at which R is changing when R = 6.0 Ω is equal to 16/49 times the rate of change of RT.
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I hope the file is not to blury
What is the expression in repeated multiplication form of (-8)^3 • (-8)^4
Answer:
(-8)x(-8)x(-8)x(-8)x(-8)x(-8)x(-8)
Step-by-step explanation:
The inverse of F(C) = 9/5c+32
The inverse of f(c) is f⁻¹(c) = 5(c-32)/9.
What is an inverse function?
A function that reverses the effects of another function is called an inverse function. When y=f(x) and x=g, a function g is the inverse of a function f. (y). Applying f and then g is equivalent to doing nothing, in other words. This can be expressed as g(f(x))=x in terms of the relationship between f and g.
Here, we have
Given: Inverse function f(c) = 9/5c+32
We let f(c) = y
y = 9/5c+32
c = 9/5y+32
Now, we are minus 32 on both sides and we get
c-32 = 9/5y
Now, we divide both sides by 5/9 and we get
5(c-32)/9 = y
f⁻¹(c) = 5(c-32)/9
Hence, the inverse of f(c) is f⁻¹(c) = 5(c-32)/9.
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Give the x and y intercepts: x+3y=24
please help this is due tomorrow morning, its worth a lot of points
Use the factorization A PDP 1 to compute Ak, where k represents an arbitrary integer. [\begin{array}{ccc}a&7(b-a)\\0&b\\end{array}\right] = [\begin{array}{ccc}1&7)\\0&1\\end{array}\right] + [\begin{array}{ccc}a&0(\\0&b\\end{array}\right] [\begin{array}{ccc}1&-7)\\0&1\\end{array}\right]. A^k = ______
The factorization of A PDP 1 to compute A^k = [\begin{array}{cc}1+7ka^k&-7ka^k+7kb^k\\7kb^k&1-7ka^k+49k^2a^k\end{array}].
To compute A^k using the factorization APDP^-1, follow these steps:
1. Factorize A into APDP^-1:
A = [\begin{array}{cc}a&7(b-a)\\0&b\end{array}] = [\begin{array}{cc}1&7\\0&1\end{array}] [\begin{array}{cc}a&0\\0&b\end{array}] [\begin{array}{cc}1&-7\\0&1\end{array}]
2. Compute P^k and P^-1^k by raising P and P^-1 to the power of k:
P^k = [\begin{array}{cc}1&7k\\0&1\end{array}]
P^-1^k = [\begin{array}{cc}1&-7k\\0&1\end{array}]
3. Compute D^k by raising the diagonal elements of D to the power of k:
D^k = [\begin{array}{cc}a^k&0\\0&b^k\end{array}]
4. Compute A^k using the formula A^k = P^k * D^k * P^-1^k:
A^k = [\begin{array}{cc}1&7k\\0&1\end{array}] [\begin{array}{cc}a^k&0\\0&b^k\end{array}] [\begin{array}{cc}1&-7k\\0&1\end{array}]
5. Perform the matrix multiplication:
A^k = [\begin{array}{cc}1+7ka^k&-7ka^k+7kb^k\\7kb^k&1-7ka^k+49k^2a^k\end{array}]
So, A^k = [\begin{array}{cc}1+7ka^k&-7ka^k+7kb^k\\7kb^k&1-7ka^k+49k^2a^k\end{array}].
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Una compañía suministra electricidad. Cobra $100 mensuales fijos más 15 centavos por kilowatt hora. En los primeros 400 kilowatts suministrados en el mes y cobra 12 centavos por cada kilowatt hora que pase de 400 kilowatts en el mes. ¿Cuál es la función que define al costo?
Answer:
La función resultante es una función a trozos:
\(C_{T}(x) = \left\{\begin{array}{cc}100+0.15\cdot x,\,0\le x \le 400\\112+0.12\cdot x,\,x> 400\\\end{array}\)
Step-by-step explanation:
El coste total de la electricidad suministrada (\(C_{T}\)), medida en pesos, es la suma del coste fijo (\(C_{F}\)) y el coste variable (\(C_{V}\)), medidas en pesos.
\(C_{T} = C_{F}+C_{V}\) (1)
Ahora, tenemos que el coste fijo es $ 100 mensuales, así:
\(C_{F} = \$ \,100\) (2)
Y el coste variable considera que se cobra 15 centavos por kilowatt-hora para los primeros 400 kilowatts-hora y 12 centavos por kilowatt-hora para cada kilowatt-hora que pase de 400 kilowatts-hora en el mes:
(i) Menos o igual que 400 kilowatts-hora:
\(C_{V} = 0.15\cdot x\) (3)
Donde \(x\) es la electricidad suministrada en kilowatts-hora.
(ii) Mayor que 400 kilowatts-hora:
\(C_{V} = 0.15\cdot (400)+0.12\cdot (x-400)\)
\(C_{V} = 12+0.12\cdot x\)
La función resultante es una función a trozos:
\(C_{T}(x) = \left\{\begin{array}{cc}100+0.15\cdot x,\,0\le x \le 400\\112+0.12\cdot x,\,x> 400\\\end{array}\)
is this correct? I'm not too sure how I'm supposed to do it
Answer:
Indeed it Correct, but am not quiet sure
8. A statue, 1.6 m tall, stands on the top of a pedestal. From a point on the great
angle of elevation of the top of the statue is 60° and from the same point theme
elevation of the top of the pedestal is 45º. Find the height of the pedestal
2.2 m
Step-by-step explanation:tg60° = √3
tg60° = AB/BC
∡DCB = 45° => ΔDBC = isosceles => DB = BC = h
tg60° = (AD + DB)/BC
√3 = (1.6 + h)/h
h√3 = 1.6 + h
h√3 - h = 1.6
h(√3 - 1) = 1.6
h = 1.6/(√3 - 1)
= 1.6/0.73
≈ 2.2 m
Solve the triangle. B=67∘51′,c=36m,a=74m What is the length of side b ? b=m (Round to the nearest whole number as needed.) What is the measure of angle A ? A= (Round to the nearest whole number as needed.) What is the measure of angle C ? C= (Round to the nearest whole number as needed.)
The length of side b is 56m, angle A is 45°, and angle C is 67°.
What is the length of side b in the given triangle?In the given triangle with side lengths a = 74m, b ≈ 56m, and c = 36m, the length of side b is approximately 56m.
To solve the triangle, we can use the Law of Cosines and the fact that the sum of angles in a triangle is 180 degrees. Given angle B = 67°51', we have:
Length of side b:Using the Law of Cosines, we have:
b² = a² + c² - 2ac * cos(B)
Substituting the known values:
b² = 74² + 36² - 2 * 74 * 36 * cos(67°51')
Calculating the value of b:
b ≈ √(74² + 36² - 2 * 74 * 36 * cos(67°51'))
b ≈ 55.92m (rounded to the nearest whole number, b ≈ 56m)
Measure of angle A:Using the Law of Cosines again, we have:
cos(A) = (b² + c² - a²) / (2 * b * c)
Substituting the known values:
cos(A) = (56² + 36² - 74²) / (2 * 56 * 36)
Calculating the value of A:
A = cos⁻¹((56² + 36² - 74²) / (2 * 56 * 36))
A ≈ 45° (rounded to the nearest whole number)
Measure of angle C:Using the fact that the sum of angles in a triangle is 180 degrees:
C = 180° - A - B
Substituting the known values:
C ≈ 180° - 45° - 67°51'
Calculating the value of C:
C ≈ 67°9' (rounded to the nearest whole number, C ≈ 67°)
Therefore, in the given triangle, the length of side b is approximately 56m, angle A is approximately 45°, and angle C is approximately 67°.
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