The angular momentum of the ball rotating on the end of the thin string is approximately 6.375 kg·m²/s.
The angular momentum (L) of a rotating object can be calculated using the formula:
L = I * ω,
where I is the moment of inertia and ω is the angular velocity.
Given:
Mass of the ball (m) = 0.340 kg
Radius of the circle (r) = 1.25 m
Angular speed (ω) = 12.0 rad/s
To find the moment of inertia (I) for a ball rotating on the end of a string, we can use the formula for a point mass rotating about an axis:
I = m * r²,
where m is the mass and r is the distance from the rotation axis.
Substituting the given values:
I = (0.340 kg) * (1.25 m)²
= 0.53125 kg·m².
Now we can calculate the angular momentum:
L = I * ω
= (0.53125 kg·m²) * (12.0 rad/s)
≈ 6.375 kg·m²/s.
Therefore, the angular momentum of the ball rotating on the end of the thin string is approximately 6.375 kg·m²/s.
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what is the relathion shop between perriod and frequency
Frequency is inversely proportional to the time period. That is, f = 1/T.
What is frequency?This refers to the number of waves that passes a fixed place in a given amount of time. Frequency is measured in hertz, this is equal to one event per second.
What is period, T ?
This refers to the time needed for one complete cycle of vibration to pass a given point. A period is measured in seconds.
Note: AS the frequency of a wave increases, the period of the wave decreases. Frequency and Period are in reciprocal relationships.
Mathematically :
f = 1/T
T =Total time,Period
f = Frequency
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How to describe the motion, and velocity of a moving man
Answer:
You can describe the motion of an object by its position, speed, direction, and acceleration. An object is moving if its position relative to a fixed point is changing. Even things that appear to be at rest move.
Explanation:
Not affected by acids a physical or chemical?
What are three things you already know about the game of baseball?
Answer:
The Positions are, Pitcher, Catcher, First base, second base, third base, shortstop, left field, Center field, and right field. Some pitches that they throw are, 4-seam fastball, Curveball, 2-seam fastball, Slider, Knuckleball, 12-6 Curve, Knucklecurve, Slurve, Changeup, Splitter, Cutter, Split-finger fastball, Sinker, Palm ball, Eephus pitch, Screwball, Cut Fastball, Circle Changup, and Forkball. I think thats all the piches i know.
circular motion of charges: a charged particle of mass 0.0050 kg is subjected to a 7.0 t magnetic field which acts at a right angle to its motion. if the particle moves in a circle of radius 0.10 m at a speed of 3.0 m/s, what is the magnitude of the charge on the particle?
Charged particles in a circle with a radius of 0.10 m and a speed of 3.0 m/s experience a 7.0 T magnetic field perpendicular to their velocity. The particle has a charge that is roughly 0.0214 Coulombs in size.
To find the magnitude of the charge on the particle, we can use the equation for the centripetal force experienced by a charged particle in a magnetic field:
F = qvB
Where:
F is the centripetal force
q is the charge on the particle
v is the velocity of the particle
B is the magnetic field strength
In circular motion, the centripetal force is given by:
\(F = \frac{{mv^2}}{{r}}\)
Where:
m is the mass of the particle
v is the velocity of the particle
r is the radius of the circle
Since the centripetal force is also equal to qvB, we can equate the two expressions:
\(\frac{{mv^2}}{{r}} = qvB\)
Simplifying the equation:
mv = qrB
Rearranging the equation to solve for the charge (q):
\(q = \frac{{mv}}{{rB}}\)
Given:
m = 0.0050 kg (mass of the particle)
v = 3.0 m/s (velocity of the particle)
r = 0.10 m (radius of the circle)
B = 7.0 T (magnetic field strength)
Substituting the values into the equation:
\(q = \frac{{0.0050 \, \text{{kg}} \cdot 3.0 \, \text{{m/s}}}}{{0.10 \, \text{{m}} \cdot 7.0 \, \text{{T}}}}\)
Calculating the value:
q ≈ 0.0214 C
Therefore, the magnitude of the charge on the particle is approximately 0.0214 Coulombs.
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which rocking motion ceases first, the surface or internal seiche? why?
The surface motion will typically cease first due to these environmental factors, while the internal seiche motion can continue for much longer. The strength and direction of the wind can also affect the duration of a rocking motion, as surface waves can be easily dispersed by high winds.
A rocking motion is caused by a sudden change in the distribution of water due to events such as earthquakes or tsunamis. It can result in the surface or internal seiche motion. When it comes to which of these rocking motions ceases first, the answer is that the surface motion usually stops first due to wind resistance and other environmental factors.
However, the internal seiche motion can continue for much longer, as it is not affected by these factors in the same way as surface motion. Internal seiches are caused by the changes in density between layers of water in a body of water, which can cause a wave-like motion that can travel through the water over long distances.
These waves are typically slower and less noticeable than surface waves, but they can still cause significant damage in certain circumstances. When it comes to stopping a rocking motion, there are several factors that can influence the duration of the motion. One of the most significant factors is the depth of the water, as waves will continue to propagate until they reach the bottom of the body of water.
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A rocket, launched from rest, steadily increases speed to 33m/s over a 3.6s
interval before exhausting all the fuel. The rocket continues upward but slows
steadily to a stop 2.8s after running out of fuel.
How far did the rocket rise while burning fuel?
Answer:4 miles
Explanation:
Astronaut X of mass 50kg floats next to Astronaut Y of mass 100kg while in space, as shown in the figure. The positive direction is shown. Astronaut X applies a force against Astronaut Y such that the kinetic energy of each astronaut as a function of time is shown in the graph. What is the change in momentum of the two-astronaut system and the change in momentum of each astronaut from immediately before the force was applied to immediately after the force was applied?
Answer:
C
Explanation:
The change in momentum of x has to be the opposite of the change in momentum of Y because the momentum is just transferred from one to another. But I'm still trying to figure it out how to calculate.
The change in momentum of the system is zero, change in momentum of astronaut X is -100 Kg·m/s and change in momentum of astronaut Y is 100 Kg·m/s.
To find the correct statement among all other options, we need to know more about the conservation of linear momentum.
What is linear momentum?Linear momentum of an object is the product of its mass and velocity of it.
What is conservation of linear momentum?In the absence of net external force, the linear momentum of a system remains constant.
How does the conservation of linear momentum apply to find the linear momentum of the two-astronaut system? The two astronaut system includes the both astronauts X and Y. When the astronaut X was applying force on astronaut Y, there is no external force on the system. Here we can not take the force applied by astronaut X as external force because the astronaut X is a part of the system. Since, there is no external force acting on the system, so the linear momentum of the system both before and after the force applied by astronaut X is zero.Therefore, the change in momentum of the two astronaut system is 0.How do we find linear momentum from kinetic energy?Kinetic energy = 1/2 × mass × velocity².So, 2 × mass × kinetic energy = ( mass × velocity )² = momentum²Or momentum = \(\sqrt{2 × mass × kinetic energy }\)What is the change in linear momentum of astronaut X?Before the force applied by astronaut X, astronaut X was constant with respect to astronaut Y. So its linear momentum is 0.After the application of force, the astronaut X has kinetic energy 100 J. So its momentum is \(\sqrt{2 × 50 × 100 }\) or 100 Kg·m/s.So, change in linear momentum of astronaut X is -100 Kg·m/s. Negative sign due to the motion of astronaut X along the opposite direction that of astronaut Y.What is the change in linear momentum of astronaut Y?Similarly, astronaut Y was at constant before the application of force. So, its linear momentum is 0.After the force applied by astronaut X, the astronaut Y has kinetic energy 50J. So, its linear momentum is \(\sqrt{2 × 100 × 50}\) or 100 Kg·m/s.So, change in linear momentum of astronaut Y is 100 Kg·m/s.Thus, we can conclude that option (c) is correct.
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A wave with a frequency of 10 Hz and wavelength of 12m has what velocity?
The equations you will need:
v = λ x f λ=v/f f=v/λ
Answer:
120
Explanation:
lambda = 12
f=10
10×12=120
whats an example of newtons 3rd law?
Answer:
Newton's Third Law states that "For every action, there is an equal and opposite reaction." An example of this law is the following scenario:
Imagine you are pushing a heavy box across the floor. According to Newton's Third Law, the box will exert an equal and opposite force back on you, making it harder to push. The more force you apply to the box, the greater the force it will exert back on you. This reaction force is what makes it difficult to push the box. The same idea applies when jumping off a diving board or jumping on a trampoline - the force you apply to the board or trampoline is equal and opposite to the force it applies back on you.
If this inclined plane moves 3 cm to the left how high will it lift the object
Answer:
It would lift the object to the same height than before you move it 3 centimeters to the left. You see, the height doesn't change if you move the inclined plane horizontally, because height is a vertical variable.
Therefore, if the inclined plane has a height of 1 meters, then the object will be lifted 1 meters up, no matter if you move the inclined plane 50 meters horizontally, it won't change its height.
Gamma-ray bursts from space were first detected by the ___________ satellites launched by the Defense Department (and later this information was shared with American scientists.) In 1991, NASA launched the __________ Observatory to identify and study more gamma ray bursts. This space observatory revealed that the bursts were distributed _________________ around the sky; they did not come more often from the plane of the Milky Way Galaxy. These early observations could not pinpoint the location of the gamma-ray bursts because they did not have sufficient________________ It was not until the launch of ____________________the satellite in 1996 that we got precise enough locations so that other telescopes could find the afterglow of a burst. These observations showed that the bursts were located in ________________
Gamma-ray bursts from space were first detected by the Vela satellites launched by the Defense Department (and later this information was shared with American scientists.) In 1991, NASA launched the Compton Gamma Ray Observatory to identify and study more gamma-ray bursts.
This space observatory revealed that the bursts were distributed isotropically around the sky; they did not come more often from the plane of the Milky Way Galaxy. These early observations could not pinpoint the location of the gamma-ray bursts because they did not have sufficient positional accuracy. It was not until the launch of the BeppoSAX satellite in 1996 that we got precise enough locations so that other telescopes could find the afterglow of a burst. These observations showed that the bursts were located in other galaxies.
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What determines an object’s mass?
A. Amount of matter
B. Amount friction
C. Amount of force
D. Amount gravity
Answer: D
Explanation:
Four students measured the acceleration of gravity. The accepted value for
their location is 9.78 m/s2. Which student's measurement has the largest
percent error?
A. Student 4: 10.01 m/s²
B. Student 2: 9.75 m/s²
C. Student 3: 9.45 m/s²
D. Student 1: 9.83 m/s²
Answer:
9.45 m/s
Explanation:
the brakes on a car exert a frictional force of 6000 n in getting the car to stop. if the work done by the brakes is 120,000 j in coming to a stop, how many meters did the car travel after the driver applied the brakes? a. 6 m b. 20 m c. 0.05 m d. 7.2 x 108 m
After the driver applied the brakes, the car traveled 20 m.Additionally, the issue was outlined in detail below.
Speed is defined as the amount of distance covered in a given amount of time. It refers to how quickly a body moves.Speed is a scalar quantity that consists solely of the velocity vector's magnitude. Speed lacks direction since it is a scalar variable and only possesses magnitude.
A=F(s)
frictional force F=6000N
When two surfaces come into contact with one another, frictional force acts to move them either in the same direction or in the opposite way.
A=120000J
s=A/F
s=120000J/6000N
s=20m
with in 20 m the car travel after the driver applied the brakes.
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multimode fiber is capable of longer transmission distances than single mode fiber.
The given statement "multimode fiber is capable of longer transmission distances than single mode fiber" is incorrect. The multimode fiber is not capable of longer transmission distances than single mode fiber.
What is single mode fiber?
Single mode fiber is the type of fiber optic cable that carries light directly down the fiber. The core diameter of single mode fiber is much smaller than that of multimode fiber. The small core reduces the dispersion of light. Single mode fiber can be used to transmit data over longer distances than multimode fiber because it has a lower attenuation rate.
What is multimode fiber?
Multimode fiber is the type of fiber optic cable that carries light down the fiber in many modes. In multimode fiber, the diameter of the core is large and is measured in 50 to 100 microns. Multimode fiber is used for short-distance communication. The data transmission rate is slower, but the larger core allows for a higher bandwidth than single mode fiber.Multimode fiber is less expensive than single mode fiber, but it has a shorter transmission distance. In contrast, single mode fiber is more expensive but offers longer transmission distances due to its low attenuation rate.
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A 3 Kg ball at the end of a string is spun in a circle. If the length of the string is 2 m and the velocity of the ball is 6 m/s, what is the centripetal acceleration of the ball? What is the centripetal force on the ball?
A car is 180 inches long. A truck is 75 percent longer than rhe car. how long is the truck
The length of the truck that is 75 percent longer than the car is 315 inches.
What is the length of the truck?
The length of the truck that is 75 percent longer than the car is determined from the percentage increment of the truck from the car.
The length of the car is given as 180 inches, then the length of the truck that is 75 percent longer than the car is calculated as follows;
Lt = ( 75 % + 100 % ) x Lc
where;
Lt is the length of the truckLc is the length of the carLt = ( 175% ) x Lc
Lt = ( 1.75 ) x 180 inches
Lt = 315 inches
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The larger container of water contains more heat that can be used for heat conduction.
Yes, that statement is correct. The larger container of water will have more heat energy available for heat conduction due to its larger volume and higher mass. This means that it will take longer to heat up or cool down compared to a smaller container with less water. Additionally, the larger surface area of the container also allows for more efficient heat transfer through convection and radiation. Therefore, a larger container of water can be more effective for providing heat to a space or conducting heat through a system.
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What is the major difference between matter at the nanoscale and matter at larger scales such as millimeters or inches?
The major difference between matter at nanoscale and matter at larger scales is that matter at nanoscale can change its physical, biological and chemical properties in the way we know it on larger scales.
A nanometer is a billions of meter (1 nm = 10⁻⁹ m), it is bigger than an atom, but smaller than a millimeter. The standard symbol is "nm"
Examples:
A DNA molecule is 2 nanometers in diameter.A sheet of paper is about 100.000 nanometers thick.A hair is about 80.000 to 100.000 nanometer wide.At nanoscale the physical, chemical and biological properties of materials differ from the properties of matter above this point the properties of material are caused by the mass or the volume effects.
Example:
The copper becomes extremely rigid at nanoscale, rather than bendable as in copper wires seen in everyday use.What is nanotechnology?It is the science that studies the very small materials particles as atomic, molecular and supramolecular scale. It is used in design, characterization, production and application of matter.
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In the figure, a lump of wet putty moves in uniform circular motion as it rides at a radius of 23.0 cm on the rim of a wheel rotating counterclockwise with a period of 6.50 ms. The lump then happens to fly off the rim at the 5 o'clock position (as if on a clock face). It leaves the rim at a height of h=1.30 m from the floor and at a distance d=2.30 m from a wall. At what height on the wall does the lump hit?
The lump hits the wall at a height of 1.09 m.
To determine the height on the wall where the lump hits, we need to analyze the projectile motion of the lump after it leaves the rim of the wheel. Since the motion is in a vertical plane, we can treat the horizontal and vertical components separately.
Calculate the horizontal distance traveled by the lump. The period of rotation of the wheel is 6.50 ms, which corresponds to a frequency of 1/6.50 ms. In one complete revolution, the lump travels a distance equal to the circumference of the wheel, which is 2π times the radius. Therefore, the horizontal distance traveled by the lump is:
Distance = (2π)(0.23 m) = 1.45 m
Next, we can analyze the vertical motion of the lump. The lump is launched with an initial vertical velocity of 0 since it leaves the rim horizontally. The time of flight can be determined using the equation:
Time = (2 × height) / gravity
Substituting the given values, we have:Time = (2 × 1.30 m) / 9.8 m/s² = 0.265 s
Now, we can calculate the vertical distance traveled by the lump during this time using the equation:
Distance = (1/2) × acceleration × time²
Substituting the acceleration due to gravity (-9.8 m/s²) and the time of flight (0.265 s), we have:
Distance = (1/2) × (-9.8 m/s²) × (0.265 s)² = -0.335 m
Since the lump started at a height of 1.30 m, the final vertical position will be:
Final height = Initial height + Distance
Final height = 1.30 m - 0.335 m = 0.965 m
However, since the lump was launched horizontally, it will hit the wall at the same height as the starting point, which is 0.965 m or approximately 1.09 m.
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If the velocity of a bycycle is 10 m/s, how long does it take to cover a distance of 18 km? plzzz help me
Answer:
1800 seconds
Explanation:
Given,
Distance ( d ) = 18 km
Velocity ( v ) = 10 m/s
To find : Time ( t ) = ?
Distance in km need to be converted to m.
1 km = 1000 m
18 km
= 18 x 1000
= 18000 m
So,
d = 18000 m
Formula : -
v = d / t
t = d / v
= 18000 / 10
t = 1800 seconds.
Therefore,
1800 seconds long, it will take to cover a distance of 18 km.
Your answer would 1800 seconds.
You're welcome ;)
Para el siguiente conjunto de medidas, calcule EL ERROR RELATIVO PORCENTUAL: 1.34 m, 1.35 m, 1.37 m y 1.36 m
Answer:
Ver explicacion abajo
Explanation:
En este caso para poder calcular el error relativo porcentual, es necesario calcular primero el error absoluto, que se calcula de la siguiente forma:
Error absoluto = Resultado exacto - aproximación
Sin embargo, no tenemos el resultado exacto de las medidas, pero podriamos conocerlo tomando el promedio de estas medidas y este es el que tomaremos como el verdadero resultado de las medidas:
Promedio de medidas = 1.34 + 1.35 + 1.37 + 1.36 / 4
Promedio de medidas = 1.355 m
Ya que tenemos el promedio, podemos calcular el error absoluto de cada medida y luego el error relativo porcentual:
Ea1 = 1.355 - 1.34 = 0.015
Ea2 = 1.355 - 1.35 = 0.005
Ea3 = 1.37 - 1.355 = 0.015
Ea4 = 1.36 - 1.355 = 0.005
Ya que tenemos los 4 errores absolutos, es posible calcular el porcentual:
%error relativo = (Error absoluto / resultado exacto) * 100
Aplicando la expresión con cada uno de los valores tenemos:
%Er1 = (0.015/1.34) * 100 = 1.12%
%Er2 = (0.005/1.35) * 100 = 0.37%
%Er3 = (0.015/1.37) * 100 = 1.09%
%Er4 = (0.005/1.36) * 100 = 0.37%
Espero que te sirva.
find the differential-mode input resistance, based on the small-signal differential input voltage and current for the bjt differential pair
The differential-mode input resistance of a BJT differential pair can be found by dividing the differential-mode input voltage by the differential-mode input current.
How to find differential-mode input resistance for BJT differential pair?To find the differential-mode input resistance of a BJT differential pair based on the small-signal differential input voltage and current, you can follow these steps:
Identify the small-signal model of the BJT differential pair. The small-signal model typically includes two transistors, each with their respective input and output terminals.Determine the differential-mode input voltage (Vd) and differential-mode input current (Id) values for the small-signal analysis. The differential-mode input voltage is the voltage difference between the two input terminals, and the differential-mode input current is the current flowing into or out of one input terminal while the other remains grounded.Apply Kirchhoff's voltage law (KVL) to the differential input circuit to relate the differential-mode input voltage and the input resistance.The input resistance (Rin) is defined as the ratio of the differential-mode input voltage to the differential-mode input current:Rin = Vd / Id.
Substitute the given values of Vd and Id into the equation to calculate the differential-mode input resistance (Rin).It's important to note that the differential-mode input resistance is specific to the small-signal analysis and represents the input impedance of the BJT differential pair when only the differential-mode signal is considered.
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Can someone please help me. I think it D but I wanna make sure kk and thank you What is the main purpose of an scientific investigation A) to persuade with bias B) to teach an lesson C) to form an opinion D) to test a hypothesis
Answer: I believe it to be D.
which is not a general characteristic of starburst galaxies?
Starburst galaxies is simply known as the rate at which the galaxy is now converting gas into stars. The statement that is not a general characteristic of starburst galaxies is that The "starburst" is thought to be caused by the presence of a supermassive black hole in the galaxy's center.
The starburst galaxy is also regarded as the free quantity of gas with which stars can be formed.They are known to be rare. A starburst is known to be an astrophysical process. It is the process of star formation happening at a rate that is large when compared to the rate that is often observed.
See full question below
Which is not a general characteristic of starburst galaxies?
The "starburst" is thought to be caused by the presence of a supermassive black hole in the galaxy's center. The observed features that us to classily a galaxy as a 'starburst" galaxy must be only temporaryphenomena in the galaxy' Supernovae occur so frequently that their effects combine to drive a galactic wind that blows material into intergalactic space. The galaxy's rate of star formation is many times higher than the rate of star formation in the Milky WayLearn more from
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the magnitude of the normal force acting on a person with mass of 70 kg standing at rest on the flat ground would be ?
Answer:
\(f = mg \\ = 70 \times 9.8 = |f| \)
What angle is necessary to keep a 10 kg box motionless if the coefficient of static friction between the box and the ramp is 0.55?
a.33.4°
b.28.8°
c.56.6°
d.45.0°
The angle necessary to keep a 10 kg box motionless, given a coefficient of static friction of 0.55 between the box and the ramp, is 33.4°, which corresponds to Option A.
To determine the angle, we can use the relationship between the coefficient of static friction, the angle of the incline, and the gravitational force acting on the box. The maximum static friction force can be calculated using the formula:
Friction force = coefficient of static friction * Normal force
The Normal force can be found by decomposing the gravitational force acting on the box into components parallel and perpendicular to the incline. The perpendicular component (Normal force) is equal to the weight of the box (mass * gravitational acceleration).
Since the box is motionless, the friction force must be equal to the component of the gravitational force acting parallel to the incline:
Friction force = Component of weight parallel to incline
By substituting the given values and solving for the angle, we find:
coefficient of static friction = tan(angle)
angle = arctan(coefficient of static friction)
angle = arctan(0.55) ≈ 33.4°
Therefore, the correct answer is Option A, 33.4°.
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Acceleration occurs when an object changes its ____________________ or ____________________ or both.
Answer:
Acceleration occurs when an object changes its VELOCITY or DIRECTION or both.
Explanation:
Answer:
When the velocity of an object changes it is said to be accelerating. Acceleration is the rate of change of velocity with time. ... Acceleration occurs anytime an object's speed increases or decreases, or it changes direction. Much like velocity, there are two kinds of acceleration: average and instantaneous. answer velocity or direction.
hope this helps!
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Force: Adding vectors (find resultant force)
50N north plus 50N west Plus 50N north west