What is the acceleration of an object traveling a constant 50 m/s for 15 s?

Answer:

\(v = \sqrt{ \frac{2gm}{r} } \)

where, g = universal gravitational constant,G

Answer:

It would not be possible to rise on your tiptoes in this position because of the principle of the conservation of angular momentum. When you try to rise on your tiptoes, your body will rotate around the axis formed by the edge of the door, which is perpendicular to the plane of the door. However, since your body is already in contact with the door, the door will prevent your body from rotating and your feet will stay fixed on the ground. Therefore, you will not be able to rise on your tiptoes in this position.

Explanation:

This exercise is impossible to do because it requires both strength and balance. The position of the body is unnatural and so it is difficult to maintain balance while lifting the toes up.

Additionally, the door’s edge provides no support and so the body cannot be stabilized in order to rise on the toes. Furthermore, the door’s edge is likely to be hard and uncomfortable to be in contact with and so it is difficult to concentrate and focus on the task of rising on the toes.

The exercise also requires a great deal of strength in the calves and legs, as well as in the core, in order to be able to lift the body up on the toes. Without the necessary strength, it is impossible to sustain the effort of rising on the toes, even if the balance and stability is successfully maintained.

Know more about exercise here

https://brainly.com/question/13128077#

#SPJ11

Answer:

The average densities of both matches the expected density for objects made from water ice.

Explanation:

Charon's density is 1.2 to 1.3 g / cm3, while Pluto's density is 1.8 to 2.1 g / cm3. This was discovered in many researches and measurements of these two celestial bodies, with the objective of understanding them and promoting efficient scientific knowledge.

With the measurements of the average densities between pluto and Charon it was possible to conclude several statements about them. Firstly, it is possible to see that the two formed independently and at different times, in addition to indicating the existence of few rocks in charon, which is consistent with the average density of objects made mostly of water ice.

The formula for the mass remaining after t years for a sample of radium-226 with an initial mass of 100mg is given by \($M(t) = 100 \times 0.5^{t/1590}$\). After 1000 years, the mass is approximately 87mg. The mass will be reduced to 30mg after approximately 2167 years.

(a) The decay of radium-226 follows an exponential decay model, where the amount of radium remaining decreases by half every 1590 years. The formula for the mass remaining after t years can be derived using the half-life concept. Let M(t) represent the mass remaining after t years, then the equation can be written as \($M(t) = 100 \times 0.5^{t/1590}$\). Here, 100 represents the initial mass of the sample, and 0.5 is the decay constant derived from the half-life.

(b) To find the mass after 1000 years, we substitute t = 1000 into the formula: \($M(1000) = 100 \times 0.5^{1000/1590}$\). Evaluating this expression gives us approximately 87mg.

(c) To determine when the mass will be reduced to 30mg, we need to solve the equation \($M(t) = 30$\) for t. Substituting M(t) and rearranging the equation gives us \($100 \times 0.5^{t/1590} = 30$\). Solving this equation, we find t ≈ 2167 years. Therefore, it will take approximately 2167 years for the mass of the radium-226 sample to be reduced to 30mg.

To learn more about radium-226 refer:

https://brainly.com/question/29028571

#SPJ11

Water boils at exactly 100°C (212°F) at normal atmospheric pressure. This is known as the boiling point of water, and it is the temperature at which water transitions from a liquid to a gas (steam) at normal atmospheric pressure. The boiling point of a substance is the temperature at which the vapor pressure of the liquid is equal to the atmospheric pressure, and for water, this occurs at 100°C. The boiling point of water can vary depending on factors such as the altitude and the atmospheric pressure, but at sea level and at normal atmospheric pressure, water boils at exactly 100°C.

That's a pretty good intuitive definition of a theory .

The specific latent heat of fusion for the substance in question 1a is 80 kJ/kg, and the specific latent heat of vaporization for the substance in question 1b is 250 kJ/kg.

To learn more about The specific latent heat of fusion refer to:

https://brainly.com/question/87248

#SPJ1

The magnitude of the point charge that creates an electric field of 80,000 N/C at a distance of 0.285 m is approximately 2.057 x 10⁻⁶ C.

To determine the magnitude of the point charge that creates an electric field of 80,000 N/C at a distance of 0.285 m, we can use the formula for the electric field strength due to a point charge.

The formula is given by: E = k x (q / r²)

where:
- E is the electric field strength,
- k is the electrostatic constant (k = 8.99 x 10⁹ N m²/C²),
- q is the magnitude of the point charge, and
- r is the distance from the point charge.

In this case, we are given that the electric field strength is 80,000 N/C and the distance is 0.285 m.

Plugging these values into the formula, we can solve for the magnitude of the point charge (q):

80,000 N/C = (8.99 x 10⁹ N m²/C²) x (q / (0.285 m)²)

To isolate q, we can multiply both sides of the equation by (0.285 m)² and divide by 8.99 x 10⁹ N m²/C²:

q = (80,000 N/C) x (0.285 m)² / (8.99 x 10⁹ N m²/C²)

Simplifying this expression, we find:

q ≈ 2.057 x 10⁻⁶ C

So, the magnitude of the point charge that creates an electric field of 80,000 N/C at a distance of 0.285 m is approximately 2.057 x 10⁻⁶ C.

To know more about charge visit:

https://brainly.com/question/28721069

#SPJ11

Answer:

\(\boxed {\boxed {\sf 1440 \ Joules}}\)

Explanation:

Kinetic energy can be found using this formula:

\(E_k= \frac{1}{2} mv^2\)

The mass is 20 kilograms and the velocity is 12 meters per second.

\(m= 20 \ kg \\v= 12 \ m/s\)

Substitute the values into the formula.

\(E_k= \frac{1}{2} (20 \ kg)(12 \ m/s)^2\)

Solve the exponent first.

\(E_k= \frac{1}{2} (20 \ kg)(144 \ m^2/s^2)\)

Multiply the numbers in parentheses.

\(E_k= \frac{1}{2} (2880 \ kg*m^2/s^2)\)

Multiply by 1/2 or divide by 2.

\(E_k=1440 \ kg*m^2/s^2\)

\(E_k= 1440 \ J\)

The object's kinetic energy is 1440 Joules.

To determine the angle at which the ball was thrown, we can use the equations of projectile motion.

Vertical component: v_y = v * sin(θ)

Horizontal component: v_x = v * cos(θ)

Δy = v_y * t + (1/2) * g * t^2

Since the ball reaches a maximum height, Δy = 3.0 m, and the acceleration due to gravity is approximately 9.8 m/s^2, we can rearrange the equation to solve for time (t):

3.0 = 0 * t + (1/2) * 9.8 * t^2

t ≈ √0.6122

t ≈ 0.7837 s

Now that we have the time taken to reach the maximum height, we can calculate the vertical component of the initial velocity:

v_y = v * sin(θ)

0 = 10 * sin(θ)

To learn more about  projectile motion follow:

https://brainly.com/question/12860905

#SPJ11

The direction of acceleration of the flea is upward and the magnitude of acceleration is given by: a = \(\frac{F_{breeze}  - mg}{m}\) where \(F_{breeze}\) is the force exerted by the breeze on the flea, m is the mass of the flea, g is the acceleration due to gravity, and a is the resulting acceleration of the flea.

When the flea jumps, it exerts a force straight down on the ground, which according to Newton's third law, results in an equal and opposite force exerted by the ground on the flea, causing it to move upward. However, the breeze blowing parallel to the ground exerts a force on the flea in the opposite direction to its motion, which reduces the upward force exerted by the ground, and hence the acceleration of the flea.

To calculate the magnitude of acceleration of the flea, we need to find the net force acting on the flea. This is given by the difference between the force exerted by the breeze and the gravitational force acting on the flea, which is given by mg. The direction of the net force is upward since the force exerted by the breeze is in the opposite direction to the motion of the flea.

The magnitude of acceleration can then be calculated using Newton's second law, a =\({F_{net}/m\), where\(F_{net}\) is the net force and m is the mass of the flea.

Therefore, the direction of acceleration of the flea is upward and the magnitude of acceleration is given by: a = \(\frac{F_{breeze}  - mg}{m}\) where the force exerted by the breeze, F_breeze, and the mass of the flea, m, are given in the problem statement. The acceleration due to gravity, g, is approximately 9.8 m/s².

To know more about direction of acceleration, refer here:

https://brainly.com/question/25415733#

#SPJ11

(a) It will take 2 seconds for the ball to pass the man moving in the downward direction.

(b) The maximum height attained by the ball is 20 meters.

(c) The ball will take 2+2\sqrt{2} seconds to hit the ground.

(a) How long will it take the ball to pass the man moving in the downward direction?

We can use the equation of motion:

v = u + at,

where:

v = final velocity (0 m/s since the ball will momentarily stop when passing the man),

u = initial velocity (20 m/s upwards),

a = acceleration (due to gravity, -10 m/s²),

t = time.

Substituting the known values we get:

0 = 20 - 10t.

Simplifying the equation:

10t = 20,

t = 20/10,

t = 2 seconds.

Therefore, it will take 2 seconds for the ball to pass the man moving in the downward direction.

(b) What is the maximum height attained by the ball?

To find the maximum height attained by the ball, we can use the following equation:

v² = u² + 2as,

where:

v = final velocity (0 m/s at the maximum height),

u = initial velocity (20 m/s upwards),

a = acceleration (acceleration due to gravity, -10 m/s²),

s = displacement.

The maximum height will be achieved when v = 0. Rearranging the equation, we get:

0 = (20)² + 2(-10)s.

Simplifying the equation:

400 = -20s.

Dividing both sides by -20:

s = -400/-20,

s = 20 meters.

Therefore, the maximum height attained by the ball is 20 meters.

(c) How long will it take the ball to hit the ground?

To find the time it takes for the ball to hit the ground, we can use the following equation:

s = ut + (1/2)at²,

where:

s = displacement (60 meters downwards),

u = initial velocity (20 m/s upwards),

a = acceleration (acceleration due to gravity, -10 m/s²),

t = time.

Rearranging the equation, we get:

-60 = 20t + (1/2)(-10)t².

Simplifying the equation:

-60 = 20t - 5t².

Rearranging to form a quadratic equation:

5t² - 20t - 60 = 0.

Dividing both sides by 5:

t² - 4t - 12 = 0.

Solving the equation using the quadratic formula, we get:

t = (4 ± sqrt(16 + 4 x 12)) / 2

t = (4 ± 4sqrt(2)) / 2

t = 2 ± 2sqrt(2)

Since time cannot be in negative terms, we ignore the negative value of t.  Therefore, the time it takes for the ball to hit the ground is:

t = 2 + 2sqrt(2) seconds

To read more on Newton's Law of Motion, click:

https://brainly.com/question/10187134

\( \\\)

(a) How long will it take the ball to pass the man moving in the downwards direction ?

Using Equation of Motion:-

\( \large\bigstar \: \: \: { \underline { \overline{ \boxed{ \frak{v = u + at}}}}}\)

where:-

Plugging in Values:-

\( \large \sf \longrightarrow \: v = u + at\)

\( \large \sf \longrightarrow \: 0 = 20 + ( - 10)t \: \)

\( \large \sf \longrightarrow \: 0 - 20=( - 10)t \: \)

\( \large \sf \longrightarrow \: - 10t = - 20\: \)

\( \large \sf \longrightarrow \: t = \frac{ - 20}{ - 10} \\ \)

\( \large \sf \longrightarrow \: t = 2 \: secs \\ \)

Therefore, it will take 2 seconds for the ball to pass the man moving in the downward direction.

________________________________________

\( \\\)

(b) What is the maximum height attained by the ball ?

→ To solve the given problem, we can use the equations of motion

Using Equation of Motion:-

\( \large\bigstar \: \: \: { \underline { \overline{ \boxed{ \frak{ {v}^{2} = {u}^{2} + 2as}}}}}\)

where:

Plugging in Values:-

\( \large \sf \longrightarrow \: {v}^{2} = {u}^{2} + 2as\)

\( \large \sf \longrightarrow \: {(0)}^{2} = {(20)}^{2} + 2( - 10)s\)

\( \large \sf \longrightarrow \: 0 = 400 + 2( - 10)s\)

\( \large \sf \longrightarrow \: 400 + (- 20)s = 0\)

\( \large \sf \longrightarrow \: 400 - 20 \: s = 0\)

\( \large \sf \longrightarrow \: - 20 \: s = - 400\)

\( \large \sf \longrightarrow \: \: s = \frac{ - 400}{ - 20} \)

\( \large \sf \longrightarrow \: \: s = 20 \: metres\)

Therefore, the maximum height attained by the ball is 20 meters.

________________________________________

\( \\\)

(c) How long will it take the ball to hit the ground ?

Using Equation of Motion:-

\( \large\bigstar \: \: \: { \underline { \overline{ \boxed{ \frak{ s= ut + \frac{1}{2}a{t}^{2}}}}}}\)

where:

Plugging in Values:-

\( \large \sf \longrightarrow \: s= ut + \frac{1}{2}a{t}^{2}\)

\( \large \sf \longrightarrow \: -60= 20t + \frac{1}{2}(-10){t}^{2}\)

\( \large \sf \longrightarrow \: -60= 20t + \frac{-10}{2}\times{t}^{2}\)

\( \large \sf \longrightarrow \: -60= 20t + (-5)\times{t}^{2}\)

\( \large \sf \longrightarrow \: -60= 20t-5\times{t}^{2}\)

\( \large \sf \longrightarrow \: 20t-5{t}^{2}+60\)

\( \large \sf \longrightarrow \: {t}^{2}-4t-12\)

\( \large \sf \longrightarrow \: t=\frac{-b \pm\sqrt{{b}^{2}-4ac}}{2a} \)

\( \large \sf \longrightarrow \: t=\frac{-(-4) \pm\sqrt{{(-4)}^{2}-4(1)(-12)}}{2(1)} \)

\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{16-4(-12)}}{2} \)

\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{16-(-48)}}{2} \)

\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{16+48}}{2} \)

\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{64}}{2} \)

\( \large \sf \longrightarrow \: t=\frac{4 \pm 8}{2} \)

\( \large \sf \longrightarrow \: t=\frac{4 + 8}{2} \qquad or \qquad t=\frac{4 - 8}{2} \)

\( \large \sf \longrightarrow \: t=\frac{12}{2} \qquad or \qquad t=\frac{-4}{2} \)

\( \large \sf \longrightarrow \: t=6 \qquad or \qquad t= -2 \)

Since time cannot be negative , Therefore, it will take 6 secs to hit the ground!!

________________________________________

\( \\\)

✅

Glucose is more stable than fructose, as indicated by the positive standard free energy change (+0.35 kJ/mol) for the conversion of glucose to fructose.

Yes, enzymatic catalysis is expected for this reaction, as the high activation energy (66 kJ/mol) suggests that the reaction is kinetically unfavorable under standard biochemical conditions.

The equilibrium constant for the conversion of glucose to fructose at 25°C can be determined using the equation ΔG = -RTln(K), where ΔG is the standard free energy change, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant. By rearranging the equation, K = e^(-ΔG/RT), and substituting the given values, the equilibrium constant can be calculated.

Glucose is more stable than fructose based on the positive standard free energy change (+0.35 kJ/mol) for the conversion of glucose to fructose. A positive value for ΔG indicates that the reaction proceeds in the non-spontaneous direction, with fructose being less stable than glucose.

Enzymatic catalysis is expected for this reaction due to the high activation energy (66 kJ/mol) under standard biochemical conditions. Activation energy represents the energy barrier that must be overcome for a reaction to occur. In this case, the high activation energy suggests that the conversion of glucose to fructose is not favorable without the assistance of enzymes. Enzymes lower the activation energy by providing an alternative pathway for the reaction, allowing it to proceed more readily.

To calculate the equilibrium constant for the conversion of glucose to fructose at 25°C, we can use the equation ΔG = -RTln(K), where ΔG is the standard free energy change, R is the gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin (25°C = 298 K), and K is the equilibrium constant. By rearranging the equation, we have K = e^(-ΔG/RT). Substituting the given value of ΔG (+0.35 kJ/mol) and the appropriate units for R and T, we can calculate the equilibrium constant.

Lean more about ΔG = -RTln(K):
brainly.com/question/32400487

#SPJ11

Explanation:

Correct Answer: Option D

Explanation

X L=V/I=24/1.5=16Ω

L = XL/2πf=16/2π50

= 0.05H

hope this helps you.

Answer:

Hello There!!

Explanation:

I believe the answer is=>5.1 x 10-2H

Here's the explanation:↬

•XL= V/I= 24/1.5= 16Ω

•L= XL/2πf= 16/2π50

So the answer is 0.05H.

hope this helps,have a great day!!

~Pinky~

The merry-go-rotational round's acceleration may be computed using the following formula: (final rotational velocity - starting rotational velocity) / time Equals rotational acceleration.

Using the provided values, we get: Rotational acceleration = (12.5 s x (18.6 rad/s - 2.5 rad/s 1.368 rad/s2 rotational acceleration As a result, the merry-go-rotational round's acceleration is 1.368 rad/s2. This suggests that the merry-go-rotational round's velocity is growing at a rate of 1.368 rad/s2. In other words, the rotational velocity of the merry-go-round increases by 1.368 radians per second for every second that passes. Understanding rotational acceleration is crucial in engineering and physics because it is used to describe the motion of spinning items like gears and wheels, which can affect their performance and stability.

learn more about  velocity  here:

https://brainly.com/question/17127206

#SPJ4

Answer:

Explanation: Part A:

The initial momentum of the two-car system is:

p = m1v1 + m2v2

After the collision, the two cars will be stuck together and move as one. The final momentum of the system is:

p' = (m1 + m2) v'

where v' is the final velocity of the two-car system. Since momentum is conserved, we have:

p = p'

Therefore,

m1v1 + m2v2 = (m1 + m2) v'

The force of friction opposing the motion of the car is:

Ff = μk N

where N is the normal force, which is equal to the weight of the cars:

N = (m1 + m2) g

The force of friction causes the two-car system to decelerate until it comes to a stop. The deceleration is given by:

a = Ff / (m1 + m2)

Substituting the expression for Ff, we get:

a = μk g

The distance the cars will move until they stop is given by:

d = v'² / (2a)

Substituting the expression for v' and a, we get:

d = (m1v1 + m2v2)² / (2μk g (m1 + m2)²)

Therefore, the expression for the distance the cars will move until they stop is:

d = (m1v1 + m2v2)² / (2μk g (m1 + m2)²)

Part B:

Since the two cars lock together and move as one after the collision, the direction of their movement will be determined by the vector sum of their initial velocities. To find the direction of the cars' movement after the collision, we can use the law of conservation of momentum in the x and y directions separately.

In the x-direction, the initial momentum is:

p_x = m1v1 + m2v2

After the collision, the two cars will move in the x-direction only, so the final momentum in the x-direction is:

p'_x = (m1 + m2) v'_x

where v'_x is the final velocity in the x-direction.

Since momentum is conserved in the x-direction, we have:

p_x = p'_x

Substituting the expressions for p_x and p'_x, we get:

m1v1 + m2v2 = (m1 + m2) v'_x

Therefore,

v'_x = (m1v1 + m2v2) / (m1 + m2)

In the y-direction, the initial momentum is:

p_y = 0 + 0 = 0

After the collision, the two cars will move in the y-direction only, so the final momentum in the y-direction is:

p'_y = (m1 + m2) v'_y

where v'_y is the final velocity in the y-direction.

Since momentum is conserved in the y-direction, we have:

p_y = p'_y

Substituting the expressions for p_y and p'_y, we get:

0 = (m1 + m2) v'_y

Therefore,

v'_y = 0

This means that the two cars will move in the x-direction only, and the direction of their movement after the collision is given by:

θ = tan⁻¹(v2/v1)

The magnetic field at the center of a circular coil is ul/2r.

It can be considered that the entire circular coil is divided into a large number of current elements, each of length dl. According to Biot-Savart law, the magnetic field dB  at the centre O of the coil due to current element I ,dl  is given by,

dB = u0 I (dl x r)/ 4πr^3

r is the position vector.

after solving we get that

dB = uIdlsinФ/4πr^2

and after solving again we get, since the turn of the coil is 1.

B = uI/2r

Hence the magnetic field at the center of a circular coil is ul/2r.

To learn more about magnetic field, visit here,

https://brainly.com/question/23096032

#SPJ4

Answer:

Explanation:

Main Answer:

The equation acceleration = v/time can be proven using the fundamental definitions of acceleration, velocity, and time. Acceleration is defined as the rate of change of velocity, and velocity is the rate of change of displacement with respect to time. Let's consider an object moving with an initial velocity v0 and final velocity v in a time interval t.

Explanation:

The change in velocity, Δv, can be calculated as the final velocity minus the initial velocity, Δv = v - v0. Similarly, the change in time, Δt, is the final time minus the initial time, Δt = t - t0.

By substituting these values into the equation for acceleration, we have:

acceleration = Δv/Δt

Now, substituting Δv = v - v0 and Δt = t - t0, we get:

acceleration = (v - v0)/(t - t0)

Since v0 and t0 represent the initial velocity and time, respectively, we can rewrite the equation as:

acceleration = (v - v0)/t

By rearranging the equation, we find:

acceleration = v/t

Thus, we have proved that acceleration is equal to v/time.

Internal Link:

For a similar explanation on Brainly.com, you can visit the following link:

Answer:

The value of the resistance is 3.99 kΩ

Explanation:

The value of the resistance, given that a heart pacemaker fires 89 times a minute, and each time a 36.0-nf capacitor is charged to 0.632 of its full voltage, is 3.99 kΩ.

How to determine the value of the resistance?

We know that a pacemaker fires 89 times per minute, charging a 36.0-nf capacitor each time, and the capacitor is charged to 0.632 of its full voltage.

The formula for determining the time constant is: τ = RC and the formula for determining the voltage of a capacitor as it charges is: Vc = Vmax(1 - e^(-t/τ)) Using the following information, we can compute the value of the time constant:

τ = RCτ = (0.632Vmax * C) / IV max = 9 V The value of the time constant is τ = RC = (0.632Vmax * C) / I = (0.632 * 9 * 10^-3) / I = 5.67 * 10^-3 / I To find the value of the resistance, R, we'll use the frequency of the pacemaker (f = 89/60 Hz), which is the number of times it fires per second.

RC = 1/fRC = (5.67 × 10^-3)/IR = RCfR = [(5.67 × 10^-3)/I](89/60)R = 3.99 kΩ

Therefore, the value of the resistance, given that a heart pacemaker fires 89 times a minute, and each time a 36.0-nf capacitor is charged to 0.632 of its full voltage, is 3.99 kΩ.

To know more about resistance here :

https://brainly.com/question/76343

#SPJ11

The second pile driver must be raised to a height of 1.5m.

Assume the mass of the first pile driver is m and its height is h. Therefore, the potential energy (PE) of the first pile driver is given by:

PE1 = m * g * h

where g is the acceleration due to gravity.

Now, let's find the potential energy of the second pile driver, which has twice the mass of the first pile driver. The mass of the second pile driver is 2m.

To have the same amount of potential energy as the first pile driver, the second pile driver must be raised to a certain height, let's call it h2.

Therefore, the potential energy (PE2) of the second pile driver is given by:

PE2 = (2m) * g * h2

Since we want the potential energy of both pile drivers to be equal, we can set up an equation:

PE1 = PE2

m * g * h = (2m) * g * h2

We can cancel out the mass and acceleration due to gravity:

h = 2 * h2

Now we can solve for h2:

h2 = h / 2

Plugging in the value of h as 3.0m, we have:

h2 = 3.0m / 2

h2 = 1.5m

Therefore, the second pile driver, with twice the mass of the first pile driver, must be raised to a height of 1.5m in order to have the same amount of potential energy.

Here's a visual representation of the work:

First pile driver:

Potential energy (PE1) = m * g * h

Second pile driver:

Potential energy (PE2) = (2m) * g * h2

Since PE1 = PE2, we have m * g * h = (2m) * g * h2

Cancelling out mass and acceleration due to gravity, we get h = 2 * h2

Solving for h2, we find h2 = h / 2

Plugging in the value of h, we have

h2 = 3.0m / 2

    = 1.5m

Therefore, the second pile driver must be raised to a height of 1.5m.

To know more about potential energy refer here

https://brainly.com/question/24284560#

#SPJ11

Answer:the power source

Explanation:

Answer:

A. The power source

Explanation:

Just took the quiz

To determine the semimajor axis and period of the elliptic orbit, as well as the speeds at aphelion and perihelion, we can apply Kepler's laws of planetary motion. By using the given distance and speed values, along with the mass of the star, we can calculate these parameters.

In Kepler's laws of planetary motion, the semimajor axis (a) represents half the length of the major axis of the elliptic orbit, and the period (T) is the time taken by the planet to complete one orbit. For part a), we can use the third law of planetary motion, which states that the square of the period is proportional to the cube of the semimajor axis (T^2 ∝ a^3). By rearranging this equation and substituting the given distance and speed values, we can solve for the semimajor axis and period.

For part b), the eccentricity (e) determines the elongation of the orbit. The speed of the planet at aphelion (V_aphelion) and perihelion (V_perihelion) can be calculated using the formula V = √[G * (M + m) / r], where G is the gravitational constant, M is the mass of the star, m is the mass of the planet, and r is the distance between them. By substituting the values, we can determine the speeds at aphelion and perihelion using the given eccentricity.

To learn more about Kepler's laws of planetary motion : brainly.com/question/12813684

#SPJ11

Answer:

the one going faster would prolly stop and the one it hit would start rolling the opposite direction it was. like think about if u were playing pool.

Explanation:

If no external forces act on a moving object, it will continue moving at the same speed. This is known as Newton's First Law of Motion, also called the law of inertia.                                                                                                                                            

In the absence of any external forces, an object in motion will continue moving with a constant velocity. This means that the object will not slow down or speed up unless acted upon by an external force.
If no external forces act on a moving object, it will follow Newton's first law of motion, also known as the law of inertia. According to this law, an object in motion will continue moving at the same speed and in the same direction unless acted upon by an external force. Therefore, the correct answer to your question is option (a): the object will continue moving at the same speed. This law explains the natural tendency of objects to maintain their current state of motion, whether at rest or in motion.

Learn more about Newton's First Law of Motion here:
https://brainly.com/question/29775827

#SPJ11

Answer:

3×x for both .they did the same amount.

A maritime polar air mass has relatively higher moisture and is relatively cooler than the tropical air mass.

Maritime polar (mP) is cold but moist due to its origination over the oceans. The desert region air masses (hot and dry) are designated by ‘cT’ for ‘continental tropical’. As these air masses move around the earth they can begin to acquire additional attributes.

The continental Tropical (cT) air mass originates in arid or desert regions in the middle or lower latitudes, principally during the summer season. It is strongly heated in general, but its moisture content is very low.

Continental tropical air masses are extremely hot and dry. Arctic, Antarctic, and polar air masses are cold. The qualities of arctic air are developed over ice and snow-covered ground. Arctic air is deeply cold, colder than polar air masses

Maritime Polar (mP) air masses develop over the polar areas of both the Northern and the Southern hemispheres. They generally contain considerably more moisture than the cP air masses. As they move inland in middle and high latitudes, heavy precipitation may occur.

Learn more about air masses:

https://brainly.com/question/18347829?referrer=searchResults

a) The motion of the object between 15 s to 30 s is increasing velocity, to a constant velocity and finally a decreasing velocity.

(b) The average velocity of the object between 0 and 15 seconds is 0.167 m/s.

(c) The position of the object at 5.0 seconds is 0.5 m.

(d) Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.

(a) The motion of the object between 15 s to 30 s can be described as increasing velocity, to a constant velocity and finally a decreasing velocity.

(b) The average velocity of the object between 0 and 15 seconds is calculated as;

average velocity = total displacement / total time

average velocity = (2.5 m - 0 m ) / ( 15 s - 0 s ) = 0.167 m/s

(c) The position of the object at 5.0 seconds is calculated as follows;

at 5.0 seconds, the position of the object is traced from the graph as 0.5 m.

(d) The motion of the object between 30 and 40 seconds is calculated as;

velocity = ( 0 m - 4 m ) / ( 40 s - 30 s ) = - 0.4 m/s

Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.

Learn more about displacement - time graph here: https://brainly.com/question/19144777

#SPJ1

The process of converting food into energy is called cellular respiration. This process occurs in the mitochondria of cells and involves.

the breakdown of glucose and other organic molecules in the presence of oxygen to produce ATP, the primary source of energy for cellular activities. Cellular respiration is a complex series of biochemical reactions that involves several stages, including glycolysis, the Krebs cycle, and oxidative phosphorylation. These stages involve the transfer of electrons and protons between different molecules and the production of ATP through a process called chemiosmosis. The overall reaction of cellular respiration can be summarized as: glucose + oxygen → carbon dioxide + water + ATP.

Learn more about  energy is called here;

https://brainly.com/question/30666198

#SPJ11

Answer:

d

Explanation:

im pretty sure. just makes the best sense. If im wrong im very sorry.

Answer:

D

Explanation:

because its right