What is the absolute value of -46.6?

The Pressure at bottom B is Greater then bottom of tank A.

Pressure is an expression of force exerted on a surface per unit area.

If a force F is applied on area A , then pressure P=F/A.

Given:

As, we know from the formula

Pressure = Force/ Area

So, Pressure is inversely related to Area.

Now, tank A has Greater area than Tank B.

Then, the Pressure exert at bottom B is greater than bottom tank A.

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Answer:

4/7

Step-by-step explanation:

3/ 7 ÷ 3/ 4

Copy dot flip

3/7 * 4/3

Rewrite

3/3 * 4/7

1 * 4/7

4/7

Answer:

Step-by-step explanation:

Use KCF method

K - Keep the first fraction

C - Change  division to multiplication

F -Flip the second fraction

\(\frac{3}{7}\) ÷ \(\frac{3}{4}\)

\(=\dfrac{3}{7}*\dfrac{4}{3}\\\\\\=\dfrac{4}{7}\)

Answer:

Step-by-step explanation:

Nick's age = x years

Lina's age =3*x = 3x

After 6 years,

Lina's age = 3x + 6

Nick's age = x + 6

3x + 6 = 2*(x+6)

3x + 6 = 2*x + 2*6

3x + 6 = 2x + 12      {Subtract 6 form both sides}

3x +6 - 6 = 2x + 12 - 6

3x  = 2x + 6    {subtract 2x from both sides}

3x - 2x = 2x + 6 - 2x

x = 6

Nick's age = 6 years

Lina's age =3*6 = 18 years

Answer:

Lina is 18 and Nick is 6

Step-by-step explanation:

(a) P(X≤2) = 0.9298, (b) P(X>8) = 0.0001, (c) P(X=4) = 0.1937, (d) P(5≤X≤7) = 0.1163.

To calculate these probabilities, we use the binomial probability mass function (PMF). The PMF for a binomial random variable X with parameters p and n is given by:

P(X=k) = C(n, k) * p^k * (1-p)^(n-k) where C(n, k) is the binomial coefficient, defined as C(n, k) = n! / (k! * (n-k)!).

(a) P(X≤2): We need to calculate P(X=0), P(X=1), and P(X=2) and sum them up. Using the PMF, we find:

P(X≤2) = P(X=0) + P(X=1) + P(X=2)

= C(10, 0) * 0.10^0 * (1-0.10)^(10-0) + C(10, 1) * 0.10^1 * (1-0.10)^(10-1) + C(10, 2) * 0.10^2 * (1-0.10)^(10-2)

= 0.9298

(b) P(X>8): We need to calculate P(X=9) and P(X=10) and sum them up. Using the PMF, we find:

P(X>8) = P(X=9) + P(X=10)

= C(10, 9) * 0.10^9 * (1-0.10)^(10-9) + C(10, 10) * 0.10^10 * (1-0.10)^(10-10)

= 0.0001

(c) P(X=4): Using the PMF, we have:

P(X=4) = C(10, 4) * 0.10^4 * (1-0.10)^(10-4)

= 0.1937

(d) P(5≤X≤7): We need to calculate P(X=5), P(X=6), and P(X=7) and sum them up. Using the PMF, we find:

P(5≤X≤7) = P(X=5) + P(X=6) + P(X=7)

= C(10, 5) * 0.10^5 * (1-0.10)^(10-5) + C(10, 6) * 0.10^6 * (1-0.10)^(10-6) + C(10, 7) * 0.10^7 * (1-0.10)^(10-7)

= 0.1163

Therefore, the probabilities are: P(X≤2) = 0.9298, P(X>8) = 0.0001, P(X=4) = 0.1937, and P(5≤X≤7) = 0.1163.

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The sample will weigh approximately 0.1667 oz after taking 3/4 of the original specimen.

To determine how much the sample will weigh after taking 3/4 of a specimen, you can multiply the weight of the original specimen by the fraction that remains (1 - 3/4).

Given:

Weight of the original specimen = 2/3 oz

Fraction remaining after analysis = 1 - 3/4 = 1/4

Calculate the weight of the sample.

Weight of the sample = Weight of the original specimen * Fraction remaining

Weight of the sample = (2/3) oz * (1/4)

To simplify the calculation, let's express 2/3 as a decimal:

2/3 = 0.6667

Weight of the sample = 0.6667 oz * (1/4)

Weight of the sample ≈ 0.1667 oz

Therefore, the sample will weigh approximately 0.1667 oz after taking 3/4 of the original specimen.

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Answer:

100/x/100

Step-by-step explanation:

Step-by-step explanation:

The rate at which the population of the city was growing was an average of 1.5 million people per year, which can be expressed as an integer or reduced fraction as 3/2.

To break this down further, this means that the city's population was increasing by an average of 416,666 people each month or 14,053 people each day.

This is an impressive rate of growth, especially when considering that the city was already quite large at 5.2 million people. This growth can be attributed to a number of factors, including high levels of immigration, a strong economy, and a booming job market.

Moreover, the growth in population can be seen as a testament to the city's quality of life and its ability to attract new residents.

The population of the city in 1980 was 5.2 million and by 1992 it had grown to 7.6 million. This shows that the rate at which the population of the city was growing was an average of 1.5 million people per year, which can be expressed as an integer or reduced fraction as 3/2.

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The slope of the new road is zero.

A line's slope is determined by how its y coordinate changes in relation to how its x coordinate changes. y and x are the net changes in the y and x coordinates, respectively. Therefore, it is possible to write the change in y coordinate with respect to the change in x coordinate as,

m = Δy/Δx where, m is the slope

Given:

Take points from the Graph (5, 0) and (5, 4).

Slope of a line = m = tanθ

where θ is the angle made by the line with the x−axis.

For a line parallel to y−axis ,θ= π/2.

​

∴m = tan π/2 = undefined

The new road will therefore have 0° of inclination if it is perpendicular to D street because if they are perpendicular and D street is vertical, the new road is level and has 0° of inclination.

An horizontal line now has zero slope.

The new road has a zero slope as a result.

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The probability of running out of anchovies before the evening is over is approximately 0.058, or 5.8%. We must presume that the number of pizzas ordered with anchovies follows a binomial distribution with parameters n = 60 (the total number of pizzas) and p = 0.08 in order to answer this issue using the normal approximation for the binomial distribution. (the probability of ordering anchovies on a pizza). 

The standard deviation of this binomial distribution is given by = sqrt(np(1-p)) = sqrt(60 x 0.08 x 0.92) = 2.03, and the mean is given by = np = 60 x 0.08 = 4.8.

Now, we need to determine the likelihood that we will need to prepare more than eight anchovy-topped pies before the evening is through in order to determine the likelihood that we will run out of anchovies. (since we only have enough anchovies for 8 pizzas).

This is equivalent to finding the probability that the number of pizzas with anchovies is greater than 8, or P(X > 8), where X is the number of pizzas with anchovies.

To use the normal approximation for the binomial distribution, we need to standardize the variable X using the standard normal distribution. This gives us:

z = (X - μ) / σ = (8 - 4.8) / 2.03 = 1.57

Using a standard normal table or calculator, we can find the probability that z is greater than 1.57, which is approximately 0.058. Therefore, the probability of running out of anchovies before the evening is over is approximately 0.058, or 5.8%.

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The best answer to submit for (515 x 0.0025) + 24.57 is 25.8575.

A decimal is a number with a whole and a fractional component. Decimal numbers, which are in between integers, are used to express the numerical value of full and partially whole amounts. Decimal notation is the name for the method used to represent numbers in the decimal system. The Hindu-Arabic numeral system has been expanded to include non-integer values.

To find the answer to the expression (515 x 0.0025) +24.57, we can simplify it by performing the multiplication and addition in the correct order:

(515 x 0.0025) + 24.57 = 1.2875 + 24.57 = 25.8575

Therefore, the best answer to report is C. 25.8575.

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Let be x the amount the owner withdrew. Then, we can write and solve the following equation:

Answer

The owner withdraws $2,000.

In graph theory, a clique is a subset of vertices where every pair of distinct vertices is connected by an edge, and an independent set is a set of vertices where no two vertices are connected by an edge. We have shown that G has two distinct independent sets of size 2.

Given that G is a graph with n ≥ 3 vertices, having a clique of size n-2 and no cliques of size n-1, we need to prove that G has two distinct independent sets of size 2. Consider the clique of size n-2 in G. Let's call this clique C. Since the graph has no cliques of size n-1, the remaining two vertices (let's call them u and v) cannot both be connected to every vertex in C. If they were, we would have a clique of size n-1, which contradicts the given condition. Now, let's analyze the connection between u and v to the vertices in C. Without loss of generality, assume that u is connected to at least one vertex in C, and let's call this vertex w. Since v cannot form a clique of size n-1, it must not be connected to w. Therefore, {v, w} forms an independent set of size 2. Similarly, if v is connected to at least one vertex in C (let's call this vertex x), then u must not be connected to x. This implies that {u, x} forms another independent set of size 2, distinct from the previous one.

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The full snippet would look like this: Histograms are used for data sets that are wide and cover more of a range. Histograms break down the range into smaller groups. These interval groups are called classes.

To identify the missing words in the fragment it is necessary to know the definition of histogram and its functions.

A histogram is a term used in statistics to refer to a graphical representation of a variable in the form of bars, where the area of each bar is proportional to the frequency of the values represented.

Generally, this graphical tool is used to tabulate large data sets. To do this, histograms divide these groups into smaller fractions.

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Kevin's statement is incorrect because there are numbers greater than 0.39 that have a 3 in the tenths place.

Kevin's statement is incorrect. Here are three numbers less than one that show that it is possible to form a number greater than 0.3 with a 3 in the tenths place:

0.63 = 0.3 x 2.1

0.48 = 0.3 x 1.6

0.45 = 0.3 x 1.5

In fact, it's possible to form a number with any digit in the tenths place by multiplying 0.3 by a number greater than or equal to 1. For example, 0.3 x 4 = 1.2, which has a 2 in the tenths place.

For example, we can form the number 0.43, which is greater than 0.39 and has a 3 in the tenths place. We can also form 0.53 and 0.73, which are also greater than 0.39 and have a 3 in the tenths place.

Therefore, Kevin's statement is incorrect, and there are indeed numbers greater than 0.39 that have a 3 in the tenths place.

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As per the given data, r'(t) · r''(t) = \(108e^{(2t)} - 72e^{(-2t)} + 72te^{(2t)\).

To discover t(zero), we want to alternative 0 for t inside the given feature r(t). This offers us:

\(r(0) = 3e^{(2(0)}), 3e^{(-2(0)}), 3(0)e^{(2(0)})\\\\= 3e^0, 3e^0, 0\\\\= 3(1), 3(1), 0\\\\= 3, 3, 0\)

Therefore, t(0) = (3, 3, 0).

To find r''(0), we need to locate the second one derivative of the given feature r(t). Taking the by-product two times, we get:

\(r''(t) = (3e^{(2t)})'', (3e^{(-2t)})'', (3te^{(2t)})''= 12e^{(2t)}, 12e^{(-2t)}, 12te^{(2t)} + 12e^{(2t)}\)

Substituting 0 for t in r''(t), we have:

\(r''(0) = 12e^{(2(0)}), 12e^{(-2(0)}), 12(0)e^{(2(0)}) + 12e^{(2(0)})\\\\= 12e^0, 12e^0, 12(0)e^0 + 12e^0\\\\= 12(1), 12(1), 0 + 12(1)\\\\= 12, 12, 12\)

Therefore, r''(0) = (12, 12, 12).

Finally, to discover r'(t) · r''(t), we need to calculate the dot made of the first derivative of r(t) and the second spinoff r''(t). The first spinoff of r(t) is given by using:

\(r'(t) = (3e^{(2t)})', (3e^{(-2t)})', (3te^{(2t)})'\\\\= 6e^{(2t)}, -6e^{(-2t)}, 3e^{(2t)} + 6te^{(2t)\)

\(r'(t) · r''(t) = (6e^{(2t)}, -6e^{(-2t)}, 3e^{(2t)} + 6te^{(2t)}) · (12, 12, 12)\\\\= 6e^{(2t)} * 12 + (-6e^{(-2t)}) * 12 + (3e^{(2t)} + 6te^{(2t)}) * 12\\\\= 72e^{(2t)} - 72e^{(-2t)} + 36e^{(2t)} + 72te^{(2t)\)

Thus, r'(t) · r''(t) = \(108e^{(2t)} - 72e^{(-2t)} + 72te^{(2t)\).

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Answer: True

Step-by-step explanation:

because a polygon has equal sides and are easy to measure.

They will be equal at the same altitude at x= 48 seconds

Assume the question is when the planes will be at the same altitude.

A is 2184+30.25x, where x is the number of seconds.

The aircraft B is 75.75x

They will be equal at the same altitude if

75.75x=2184+30.25x

Collecting like terms and making x the subject of the relation

75.75x -30.25x = 2184

45.5x = 2184

Making x the subject

x = 2184/45.5

x=48 seconds

The two airplanes  will be at the same altitude at 48 seconds

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Answer:

5 year

3 inches every year 48 minus 32 equals 16 3 Inches divided into 16 equal 5.333333 round it equals 5 years y = 5 years

Y = 3(-3) + 4 = -5 when x is equal to 3. Hence, the final set of negative x- and y-coordinates is (-3, -5).

A set of numbers known as coordinates describes a point or object's location in a given space or coordinate system. When representing a spot's location in a plane or three-dimensional space, coordinates are frequently expressed as x or triples in mathematics. Depending also on system being utilised, several values can be used to represent coordinates, although often, integers or real numbers are used to express them.

given

We can substitute negative values for x and solve for y to obtain three pairs of negative x and y coordinates that lie on the line y = 3x + 4.

With x = 1, y = 3(-1), plus 4, equals 1. Hence, one set of negative x and y coordinates is (-1, 1).

Y = 3(-2) + 4 = -2 when x is equal to 2. In light of this, another set of negative x- and y-coordinates is (-2, -2).

Y = 3(-3) + 4 = -5 when x is equal to 3. Hence, the final set of negative x- and y-coordinates is (-3, -5).

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The probability of of a random student having blue eyes and dark hair

 is 35% .

let consider the total students in the school be (U) = 100%

out of them ,

students having blue eyes (A) = 60%

students having  dark hair (B) = 55%

students with neither blue eyes nor dark hair (A∪B)' = 20%

let the students with blue eyes and dark hair be (A∩B) = x %

Then according to the set theorem

U = n(A∪B) + n(A∪B)'

U = n(A) + n(B) - n(A∩B) + n(A∪B)'

100 = 60 + 55 - x +20

∴ x = 60 + 55 +20 - 100

x = 35 %

So the probability of random student having blue eyes and dark hair is 35% .

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The expression is simplified to give 2(9x + 2√3x - 5)

First, we need to know that surds are mathematical forms that can no longer be simplified to smaller forms

From the information given, we have that;

(2√3x - 2)(3√3x + 5)

expand the bracket, we get;

6√9x² + 5(2√3x) - 6√3x - 10

Find the square root factor

6(3x)  + 10√3x - 6√3x - 10

collect the like terms, we have;

18x + 4√3x - 10

Factorize the expression, we have;

2(9x + 2√3x - 5)

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The value of vector v with  Initial point: (4, 8, 0) and Terminal point: (4, 1, 8) is v = <0, -7, 8> ||v|| = 10.6301

v/||v|| = <0, -0.6585, 0.7526> .

To find the vector v with the given initial and terminal points, we subtract the coordinates of the initial point from those of the terminal point. That is,

v = <4-4, 1-8, 8-0> = <0, -7, 8>

To find the magnitude of v, we use the formula:

||v|| = sqrt(v1^2 + v2^2 + v3^2) = sqrt(0^2 + (-7)^2 + 8^2) = sqrt(113) ≈ 10.6301

To find a unit vector in the direction of v, we divide v by its magnitude:

v/||v|| = <0, -7, 8>/sqrt(113) ≈ <0, -0.6585, 0.7526>

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Answer:

Question 1

The greatest number of treasure chest you can fill = 23

Step-by-step explanation:

Gold coins = 46

Diamonds = 115

Rubies = 184

To determine the greatest number of treasure chests you can fill, find the highest common factors of 46, 115 and 184

46 = 1, 2, 23, 46.

125 = 1, 5, 23, 115

184 = 1,2,4,8,23,46,92,184

The highest common factors of 46, 115 and 184 is 23

The greatest number of treasure chest you can fill = 23

Number of gold coins in each chest = 46/23

= 2

Number of diamonds in each chest = 115 / 23

= 5

Number of rubies in each chest = 184 /23

= 8

Question 2

Nickels = 246

Dimes = 312

Quarters = 204

Find the highest common factor of 246, 312, 204

246 = 1, 2, 3, 6, 41, 82, 123, 246

312 = 1, 2, 3, 4, 6, 8, 12, 13, 24, 26, 39, 52, 78, 104, 156, 312.

204 = 1, 2, 3, 4, 6, 12, 17, 34, 51, 68, 102, 204

The highest common factor of 246, 312, 204 is 6

How many are in your group?

6 members

There are 6 members in your group that each person got the same exact amount of each coin with no coins remaining.

Number of nickels each person receive = 246 / 6

= 41

Number of dimes each person receive = 312 / 6

= 52

Number of quarters each person receive = 204 / 6

= 34

7h-15h+40=-72

40+72=15h-7h

112=8h

h=14

Answer:I think it’s 52

Step-by-step explanation:

Answer:

I belive it is 3 and 4

Step-by-step explanation:

sorry if it is wrong

a. Total amount of fencing needed = perimeter of the rectangular area excluding one length of the side close to the river = F = l + 2w

b. F = 44 ft

c. The width (w) = 45 ft.

Perimeter of rectangle = 2(length + width)

a. Total amount of fencing needed = perimeter of the rectangular area excluding one length of the side close to the river = l + 2w

F = l + 2w

b. w = 12 ft

l = 20 ft

Amount of fencing needed, F = l + 2w = 20 + 2(12)

F = 44 ft

c. F = 120 ft

l = 30 ft

Substitute F = 120 and l = 30 into F = l + 2w to solve for w

120 = 30 + 2w

120 - 30 = 2w

90 = 2w

90/2 = w

w = 45

The width (w) = 45 ft.

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The perimeter of the triangle is (30+x) cm

A triangle is a closed, 2-dimensional shape with 3 sides, 3 angles, and 3 vertices. A triangle is also a polygon.

Perimeter is the distance around the edge of a shape.

To find the perimeter of a triangle , we add all the sides together.

Two sides are 22 cm and 8cm

Represent the other sides of the triangle by x

therefore the perimeter will be calculated as:

22+8+x

P = (30+x)cm

therefore the perimeter of the triangle is( 30+x)cm for any value of x

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Answer:

17°

Step-by-step explanation:

angle 3 and angle 2 are complementary angles and their sum is equal to 90° if angle 3 is = 73° then angle 2 is 90 - 73 = 17°

We have to find the probability of selecting a white ball on the second draw given that the first ball drawn was green.

We know that probability of selecting a green ball and then a white ball without replacement is 0.15, so we can write:

We also know that the probability of selecting a green ball in the first draw is 0.65:

Then, we can use this to find the conditional probability of selecting a white ball on the second draw given that the first ball drawn was green can be calculated as:

Answer: the probability is 0.231.

Answer:

The answer is 10

Step-by-step explanation:

The longer leg of this triangle is √3 times longer than the shorter leg. Since the longer leg is 5√3, then the shorter leg will be 5. The hypotenuse is twice the size of the shorter leg, so 5*2 is 10.