What is supersymmetry?

Answer:

20 Minutes

Explanation:

Well we know Mph (Miles per hour) is distance over time : \(\frac{distance}{time} \\\)

R (rate) = 60

d (distance) = 20

t (time) = Unknown

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

 R = \(\frac{d}{t} \)  

   ↓

60 = \(\frac{20}{t}\)

   ↓

 t = \(\frac{20}{60} \)

    ↓

 t = \(\frac{1}{3} \)  or 0.3333

So basically it would take one third of an hour. Lets change these units to minutes.

60 * 0.333333 = 20

So it would take you 20 minutes to drive 20 miles on a bus that drives 60 mph

Hope that helps

~Siascon~

Answer:

In a concave mirror, the image is real if the distance of the object from the mirror is greater than the focal length and virtual if it is less than the focal length. If the object is at the focus the image is formed at infinity. In a convex mirror, the image is always virtual.

Answer:

B,D,E

Explanation:

Engineering design has to do with the overall process of the design and the production of new products.

Engineering design has to do with the overall process of the design and the production of new products. Now the process of engineering design involves many components and all these are taken into account when a new product is being designed.

As such, the stage of technological design in which each action would occur is;

Define a need and research related information- identify a problem

Establish criteria and prepare the initial design -  Design a solution

Build and test a prototype - implement a solution

Redesign and retest as necessary - Evaluate a solution

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answer: 1 design a solution 2 evaluate a solution 3 identify a problem 4 implement a solution

Explanation: i know

The ratio of the sun's gravitational force on the moon to the earth's gravitational force on the moon is approximately 2:1.

The gravitational force that an object with mass exerts on another object with mass is directly proportional to the masses of the objects and inversely proportional to the square of the distance between them. This is known as the universal law of gravitation.

                        The force of gravity between the moon and the earth is stronger than the force of gravity between the moon and the sun because the moon is much closer to the earth than it is to the sun. The sun's gravitational force on the moon is about 46% of the earth's gravitational force on the moon.

                             This means that the ratio of the sun's gravitational force on the moon to the earth's gravitational force on the moon is approximately 2:1 .

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The correct option is 2. It is greater at higher temperatures, but only in the case of a moving observer and a stationary source. The Doppler effect is a change in the frequency of a wave caused by the relative motion of the source and observer.

This effect can be noticed in both sound waves and light waves. Sound waves require a medium for transmission and it is not applicable to vacuum. The frequency of the sound wave depends on the medium in which the wave is traveling. As the temperature of the medium increases, the speed of sound also increases. This means that the frequency of sound waves also changes, and hence the Doppler effect changes.

The Doppler effect is greater at higher temperatures but only in the case of a moving observer and a stationary source. The reason is that the temperature of the medium affects the speed of sound, but not the relative motion of the source and observer.

Therefore, option 2, which states that the Doppler effect is greater at higher temperatures, but only in the case of a moving observer and a stationary source.

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The engine of an aircraft propeller delivers an amount of power 171 hp to the propeller at a rotational velocity of 2410 rev/min. This is a false statement.

Power can be defined as the amount of work completed in a given amount of time. Watt (W), which is derived from joules per second (J/s), is the SI unit of power. Horsepower (hp), which is roughly equivalent to 745.7 watts, is a unit of measurement sometimes used to describe the power of motor vehicles and other devices.

With out knowing mass of the propeller, it can't be concluded about its  rotational velocity - no mater how much power is applied on it.

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When the Bowen ratio is low and negative, it means the surface is wet, and the latent heat flux is significant, while the sensible heat flux is minor. Because of Arctic sea ice's nature, the Bowen ratio is expected to be small and negative.

During summer, the Arctic sea ice's surface temperatures are often above 0° C, with a temperature inversion expanding from the surface to altitudes of some hundred meters.

For such conditions, the sensible heat flux H is expected to be positive, while the latent heat flux H L is expected to be small or zero. The Bowen ratio B is expected to be small and negative.

Let us discuss each term in more detail. Sensible heat flux (H):The rate of heat transfer from the Earth's surface to the atmosphere due to the temperature difference is referred to as the sensible heat flux. The earth surface warms up due to solar radiation, and then the warm surface transfers heat to the cooler air. The air then heats up and rises, creating convection currents that aid in the heat transfer process.

Sensible heat flux is positive when heat moves from the surface to the atmosphere.Latent heat flux (H L ):The heat required for a phase transition, such as a liquid converting to a gas, is referred to as latent heat. The energy required to convert a material from one phase to another is referred to as latent heat. Evaporation and transpiration are the two main processes that contribute to the latent heat flux.

Because Arctic sea ice's surface temperature is typically above the melting point of ice during summer, the latent heat flux is expected to be small or zero.

Bowen ratio (B):The Bowen ratio is a measure of the ratio of sensible heat flux to latent heat flux. It's a dimensionless quantity that helps to understand the surface's evapotranspiration efficiency.

When the Bowen ratio is low and negative, it means the surface is wet, and the latent heat flux is significant, while the sensible heat flux is minor. Because of Arctic sea ice's nature, the Bowen ratio is expected to be small and negative.

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1. Sensible heat flux (H) is negative, indicating heat transfer from the surface to the atmosphere.
2. Latent heat flux (H_L) is positive, indicating heat transfer from the atmosphere to the surface through evaporation.
3. Bowen ratio (B) is negative, indicating that the sensible heat flux is larger than the latent heat flux. The magnitude of the Bowen ratio can vary depending on the specific conditions.

In summer, surface temperatures over Arctic sea ice are often above 0°C, and there is a temperature inversion that extends from the surface to altitudes of a few hundred meters.

1. Sensible heat flux (H): The sensible heat flux is the transfer of heat between the surface and the atmosphere due to temperature differences. In this case, the sensible heat flux is expected to be negative. This means that heat is being transferred from the surface (warmer) to the atmosphere (cooler). The magnitude of the sensible heat flux can vary depending on the temperature difference between the surface and the atmosphere, but it is generally larger when the temperature difference is greater.

2. Latent heat flux (H_L): The latent heat flux is the transfer of heat between the surface and the atmosphere due to the evaporation and condensation of water. In this case, the latent heat flux is expected to be positive. This means that heat is being transferred from the atmosphere (warmer) to the surface (cooler) through the process of evaporation. The magnitude of the latent heat flux depends on factors such as the availability of moisture and the temperature difference between the surface and the atmosphere. It can be larger when there is more moisture available for evaporation and when the temperature difference is greater.

3. Bowen ratio (B): The Bowen ratio is the ratio of sensible heat flux to latent heat flux. It provides information about the relative importance of sensible and latent heat transfer processes. In this case, the Bowen ratio is expected to be negative. This indicates that the sensible heat flux is larger than the latent heat flux. The magnitude of the Bowen ratio can vary depending on the specific conditions, but it is generally larger when the sensible heat flux is dominant.

To summarize:
- Sensible heat flux (H) is negative, indicating heat transfer from the surface to the atmosphere.
- Latent heat flux (H_L) is positive, indicating heat transfer from the atmosphere to the surface through evaporation.
- Bowen ratio (B) is negative, indicating that the sensible heat flux is larger than the latent heat flux. The magnitude of the Bowen ratio can vary depending on the specific conditions.

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They have a limited supply in nature, therefore if they are used excessively, they will become exhausted.

Today, we recognise that using fossil fuels has a negative impact on the environment. Fossil fuels produce and utilise local pollutants, and their continued use permanently alters the temperature of our entire world.

Wastes from combustion sources are those that result from carbon pollution (i.e., coal, oil, natural gas). Included in this are all ash and particles taken out of the flue gas.

The fossile fuel is limited in nature. So, it should not waste energy from fossil fuels.

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The first law of thermodynamics provides a fundamental principle for energy conservation in thermodynamic systems. It states that the change in internal energy (ΔU) of a system is equal to the heat added to the system (q) minus the work done by the system (w).

According to the first law of thermodynamics, the energy of a system can neither be created nor destroyed, only transferred or converted from one form to another. As a result, there are two ways to quantify energy change in a system: as a result of heat transfer and as a result of work done. The first law of thermodynamics is expressed mathematically as follows:

ΔU = q - w

where ΔU is the change in internal energy, q is the heat added to the system, and w is the work done by the system.

Therefore, to express q in terms of ΔU and w:q = ΔU + w. This equation allows us to quantify the relationship between heat, work, and the change in internal energy of a system, providing a basis for analyzing and understanding energy transfers in various processes.

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The net force on the +10C charge is zero

Let's label the charges as follows:

Charge 1: +10C (located at point A)

Charge 2: -20C (located at point B)

Charge 3: +16C (located at point C)

The direction of the force on the +10C charge will depend on the sign of the charges and their relative positions.

The force on Charge 1 due to Charge 2 can be calculated as:

F12 = k * (q1 * q2) / r^2

where k is the Coulomb constant (9 × 10^9 N m^2 C^-2), q1 is the charge of Charge 1 (+10C), q2 is the charge of Charge 2 (-20C), and r is the distance between the charges (the distance from point A to point B). Since Charge 2 is negative, the force will be attractive (toward Charge 2).

Similarly, the force on Charge 1 due to Charge 3 can be calculated as:

F13 = k * (q1 * q3) / r^2

where q3 is the charge of Charge 3 (+16C), and r is the distance between the charges (the distance from point A to point C). Since Charge 3 is positive, the force will be repulsive (away from Charge 3).

To find the net force on Charge 1, we need to add the vector forces due to Charges 2 and 3 using vector addition.

Let's assume that the distance between Charges 1 and 2 (r12) is 1 meter, and the distance between Charges 1 and 3 (r13) is 2 meters. Then, we can calculate the magnitudes of the forces:

F12 = 9 × 10^9 * (10 * (-20)) / 1^2 = -1.8 × 10^11 N

F13 = 9 × 10^9 * (10 * 16) / 2^2 = 1.8 × 10^11 N

The net force on Charge 1 can be calculated as:

Fnet = F12 + F13

Fnet = -1.8 × 10^11 + 1.8 × 10^11

Fnet = 0 N

Therefore, the net force on the +10C charge is zero, which means it is in equilibrium and will not experience any net force due to the other charges.

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The static friction coefficient is higher than the kinetic friction coefficient.

What is static friction?

Friction is the obstruction or resistance that prevents one solid object from rolling or sliding over another. F indicates this. Any solid and liquid layer motion is opposed by a force. When two materials slide over one another, this force is created. There is friction all around us. For instance, when we walk, the ground is in contact with our feet. When we walk, one foot advances while the other moves backward, applying pressure to the ground. When this force is applied to the ground, the ground applies an equal and opposing force to our feet. One of the laws of motion is being followed in this situation.

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If you cover half a camera lens with opaque tape, the images produced will be dimmer.

When you cover half of the camera lens with opaque tape, it'll cause the quantity of light entering the camera to decrease. If you cover the camera lens halfway, the pictures taken will be dimmer since the tape is preventing the light from entering half of the lens. Images with less contrast, less brightness, and half of the image will be darker than the other half.

You won't be able to take a complete, clear photograph since the tape will produce an obstruction in the picture.

The reason is that when half the lens is covered with opaque tape, the resulting images will be dimmer and not cut in half.

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Take the upward and to-the-right directions to be positive (so down and to-the-left are negative).

The vertical forces acting on the object cancel, 6 N - 6 N = 0.

The horizontal forces exert a net force of 20 N - 3 N = 17 N. This net force is positive, so it points to the right. So the answer is A.

The amount of energy that 4.967×10^4 gallons of gasoline correspond to is 5.638×10^6 mega-joules (MJ).

Gasoline is a commonly used fuel in vehicles, and its energy content is measured in mega-joules (MJ). The energy content of gasoline can vary slightly depending on factors such as the blend and composition, but on average, it is approximately 120 MJ per gallon.

To calculate the total energy content of 4.967×10^4 gallons of gasoline, we can multiply the energy content per gallon (120 MJ) by the number of gallons:

4.967×10^4 gallons * 120 MJ/gallon = 5.9604×10^6 MJ

Rounding the result to three significant figures, we get 5.638×10^6 MJ.

In summary, 4.967×10^4 gallons of gasoline correspond to approximately 5.638×10^6 mega-joules (MJ) of energy.

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The momentum of the probe after the retrorocket ceases to fire is 9.9 * 10^7 Kg m/s

We know that the momentum of an object has to do with the product of the mass and the velocity of an object. The momentum of an object is a vector quantity and the direction of the momentum is the direction of the velocity of the object that is in motion.

According to the Newton second law of motion, we know that the rate of change of the momentum is equal to the impressed force that is acting on the body.

We know that;

\(F_{t}\) = \(p_{f}\) -\(p_{i}\)

F = force

t = time taken

\(p_{f}\)= final velocity

\(p_{i}\) = initial velocity

\(p_{f}\) = \(F_{t}\)  + -\(p_{i}\)

\(p_{f}\) = (2.0 * 10^6 * 12 s) + 7.5 * 10^7

\(p_{f}\)  = 2.4 * 10^7 + 7.5 * 10^7

\(p_{f}\)  = 9.9 * 10^7 Kg m/s

Hence, the momentum of the retrorocket is 9.9 * 10^7 Kg m/s.

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Missing parts;

A  space probe is traveling in outer space with a momentum that has a magnitude of  7.5 * 10^7 kgm/s. A retrorocket is fired to slow down the probe. It applies a force to the probe that has a magnitude of 2.0  * 10^6 N and a direction opposite to the probe's motion. It fires for a period of 12 s. Determine the momentum of the probe after the retrorocket ceases fire.

Answer:

serial in which container is filled

Solid -base of container

Liquid- above solid

Gas- above liquid

Explanation:

If any mixture of  matter in different state (that solid , liquid or gas )are kept in any container, then substance with higher density will be settled at lowest surface first and similarly the substance with lowest density will be at upper part of container.

In the given container we have to keep solid, liquid and gas

based on this

solid will be at surface of container

above sold will be liquid

above liquid will be presence of Gas

serial in which container is filled

Solid -base of container

Liquid- above solid

Gas- above liquid

It is not accurate to say that artificially selected animals are "lucky." These animals have been specifically bred for desired traits, rather than relying on natural selection.

Artificial selection, also known as selective breeding, is the process of intentionally breeding animals with desired traits in order to create offspring with those traits.

It is true that animals resulting from artificial selection often have better traits than their naturally bred counterparts. This is because the process of selective breeding allows humans to control which traits are passed on from one generation to the next, resulting in animals with specific and desired traits. For example, selective breeding has been used to produce dogs with specific physical and behavioral characteristics, such as the ability to retrieve or herd.

Therefore, while animals resulting from artificial selection may have better traits than naturally bred animals, it is important to carefully consider the potential consequences and ethical implications of selective breeding. It is not simply a matter of luck, but rather a deliberate process with both benefits and drawbacks.

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To find the average acceleration of the sports car, we need to calculate the change in velocity and divide it by the time taken.

Given:

Initial velocity, u = 0 (as the car starts from rest),

Final velocity, v = 95 km/h,

Time, t = 4.3 s.

First, let's convert the final velocity from km/h to m/s:

v = 95 km/h = (95 * 1000) m/3600 s = 26.39 m/s.

Now, we can calculate the average acceleration using the formula:

Average acceleration (a) = (Change in velocity) / (Time)

                     = (v - u) / t

                     = (26.39 m/s - 0) / 4.3 s

                     = 6.13 m/s².

Therefore, the average acceleration of the sports car is 6.13 m/s².

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The velocity of the truck is (90000 N - 5T) / (5443 kg) and the tension in the cord is T Newtons.

Mass of truck (Tj) = 3407 kg

Mass of RV (m) = 2036 kg

Force applied by tires (Ff) = 9 kN (kilo Newton)

Time (t) = 5 s

Velocity of truck (V) = ?

Tension in cord (T) = ?

The given situation can be represented by the following diagram:

               Truck (Tj)

                 |  |

                 |  |

                 |  |---------> Tension in cord (T)

                 |  |

                 |  |

                 |  |

               RV (m)

We know that the truck is pulling the RV behind it with the help of a cable, which means both of these objects are connected to each other with a cable. Therefore, the cable will have the same tension (T) at both ends. Also, the direction of motion of the truck and the RV will be the same, so the cable will be in tension.

Using Newton's second law of motion, we can find the acceleration (a) of the truck and the RV.

a = F / m

a = net force / mass

We can assume that the force of friction is acting opposite to the direction of motion, so it will be a negative force. Therefore, the net force acting on the truck and the RV will be:

Fnet = Ff - T

where Ff is the force applied by the tires (which is acting to the right) and T is the tension in the cable (which is acting to the left).

Therefore,

a = (Ff - T) / (Tj + m)

Substituting the given values in the above equation:

a = (9000 N - T) / (5443 kg)

Now, we can use the kinematic equation to find the velocity of the truck at time t = 5 s.

v = u + at

where,

u = initial velocity = 0 (because the truck starts from rest)

v = final velocity (which is to be found)

t = time = 5 s

a = acceleration (which we have just found above)

Substituting the values in the above equation:

v = 0 + at

v = 0 + at

v = a*t

v = [(9000 N - T) / (5443 kg)] * 5

v = (90000 N - 5T) / (5443 kg)

Therefore, the velocity of the truck at time t = 5 s is (90000 N - 5T) / (5443 kg), and the tension in the cord is T Newtons.

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Answer:

F_B = 0.12N

Explanation:

In order to calculate the magnetic force on the charge, you use the following formula:

\(\vec{F_B}=q\vec{v}\ X\ \vec{B}\)          (1)

q: charge of the particle = 4μC = 4*10^-6 C

v: speed of the charge = 7.5*10^4 m/s

B: magnitude of the magnetic field = 0.4T

The direction of the motion of the charge is perpendicular to the direction of the magnetic field. Then, the magnitude of the magnetic force is:

\(F_B=qvBsin90\°\\\\F_B=(4*10^{-6}C)(7.5*10^4 m/s)(0.4T)=0.12N\)

The magnetic force on the charge is 0.12N

Answer:

18 valence electrons in the 4th shell

Explanation:

1 - 2 electrons

2 - 8 electrons

3 - 8 electrons

4 - 18 electrons

Answer:

Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system. Ideally, the device preserves the input power and simply trades off forces against movement to obtain a desired amplification in the output force. The model for this is the law of the lever.”

Explanation:

a person can pull approximately 60% of their own weight horizontally along the ground in good conditions. So if we need a 500 lb pull to get something done and we have a single groundman who weighs 200 lb and can therefore generate around 120 lb of pull, how can we accomplish this 500 lb pull? The simple answer is that the groundman can go find 4 or 5 good friends who are willing to drop everything and come and help him pull on the rope.

The VCE voltage drop in saturation for a typical BJT can be assumed to be between 0.1V and 0.3V.

The voltage drop across the collector and emitter (VCE) of a bipolar junction transistor (BJT) when it is in saturation depends on several factors such as the type of BJT, the collector current, and the biasing conditions.

However, as a general rule of thumb, the VCE voltage drop in saturation for a typical BJT can be assumed to be between 0.1V and 0.3V, depending on the specific characteristics of the transistor. This value may vary based on the operating conditions and the specific transistor used.

It's worth noting that the VCE voltage drop in saturation is typically lower than the voltage drop in the active region, where the BJT behaves as a current amplifier. In the active region, the VCE voltage drop can range from a few tenths of a volt up to several volts, depending on the transistor's characteristics and operating conditions.

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