Explanation:
Refractive Index is a value calculated from the ratio of the speed of light in a vacuum to that in a second medium of greater density. The refractive index variable is most commonly symbolized by the letter ‘n’ or n’ in a descriptive text and mathematical equations.
What does Newtons second law explain? (Stemscopes)
Answer:
hey!!
Newton's second law of motion, also known as the law of acceleration, explains the relationship between an object's mass, the applied force, and its resulting acceleration. The law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, Newton's second law can be expressed as:
F = ma
Where:
F represents the net force acting on the object,
m represents the mass of the object, and
a represents the acceleration produced by the force.
In simpler terms, Newton's second law states that the force acting on an object determines how much it accelerates. A larger force applied to an object will result in a greater acceleration, while a smaller force will produce a smaller acceleration. Additionally, if the mass of the object is increased, the same force will produce a smaller acceleration, and vice versa.
This fundamental law of motion helps us understand how forces and masses interact to produce motion. It is widely applicable and plays a crucial role in fields such as physics, engineering, and everyday life when studying the behaviour of objects in motion.
i hope this helps you :)
An airplane travels at 500.0 km/hr W. It encountered a south bound cross-wind and ends up with a velocity of 625 km/hr SW. What was the velocity of the cross-wind? Be sure to record your answer to the correct precision!
Answer:
The velocity of the cross-wind was 375 km/hr South
Explanation:
The given speed of the airplane, v₀ = 500.0 km/hr W
The direction the airplane is headed = West
The direction of the wind encountered = Southbound wind
The final velocity of the airplane, R = 625 km/hr
The final direction of the airplane = South West SW
Let vₐ represent the velocity of the cross-wind
Therefore, we have the given velocities in vector form as follows;
R = -500.0·i - vₐ·j
Also, we have;
\(\left | R \right | = 625 = \sqrt{v_0^2 + v_a^2} = \sqrt{(-500)^2 + (-v_a)^2}\)
625² = (-500)² + (-vₐ)²
(-vₐ)² = 625² - (-500)² = 140625
-vₐ = 375
vₐ = -375 km/hr North = 375 km/hr South
The velocity of the cross-wind = vₐ = 375 km/hr South
A motor car is traveling at a steady speed of 30m/s. The engine provides the force needed to oppose the force of air resistance, 1600N
(Calculate the work done by the car each second against the force of air resistance)
If a motor car is traveling at a steady speed of 30m/s then the work done by the car each second against the force of air resistance is 48,000 J.
To calculate the work done by the car each second against the force of air resistance, we need to use the formula for work, which is:
work = force x distance
In this case, the distance is not given, but we know that the car is traveling at a steady speed of 30m/s. We can use this information to calculate the distance traveled in one second:
distance = speed x time
distance = 30m/s x 1s
distance = 30m
Now we can calculate the work done by the car against the force of air resistance:
work = force x distance
work = 1600N x 30m
work = 48,000 J
Therefore, the work done by the car each second against the force of air resistance is 48,000 J.
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What is the main difference between speed and velocity
Answer:
Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.
Explanation:
Answer:
Speed refers to the distance taken at a specific time interval. Velocity is the speed in a certain direction.
Which of the following does NOT describe a structural feature of a volcano? A. vent. B. vesicle. C. fissure. D. magma chamber.
B. Vesicle does NOT describe a structural feature of a volcano.
A vent, fissure, and magma chamber are all structural features, while a vesicle refers to a small cavity in volcanic rock, formed by trapped gas bubbles during the solidification of lava. A vent is an opening in the Earth's surface that allows volcanic material to escape. A fissure is a large crack in the Earth's surface that allows lava to flow. A magma chamber is a large underground reservoir containing molten rock. A vesicle is an air pocket inside rocks formed by the expansion of gases during volcanic eruptions.
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A roller coaster car rapidly picks up speed as it rolls down a slope. As it starts down the slope, its speed is 4 m/s. But 3 seconds later, at the bottom of the slope, its speed is 22 m/s. What is its average acceleration?
plz, show the equation.
Answer:
6m/s²
Explanation:
Given parameters:
Initial velocity = 4m/s
Time = 3s
Final velocity = 22m/s
Unknown:
Average acceleration = ?
Solution:
Acceleration is the rate of change of velocity with time taken.
Acceleration = \(\frac{Final velocity - Initial velocity }{Time}\)
Acceleration = \(\frac{22 - 4}{3}\) = 6m/s²
Compare and contrast how sound is heard by a person who observes a moving car to a person who is moving with the moving car.
When comparing and contrasting how sound is heard by a person observing a moving car versus a person moving with the car, the primary difference lies in the Doppler effect, this occurs when the source of sound is moving relative to the observer and the sound intensity.
For the person observing the moving car, the pitch of the sound will change due to the car's motion. As the car approaches the observer, the sound waves compress, resulting in a higher pitch. Conversely, as the car moves away, the sound waves expand, leading to a lower pitch. In contrast, for the person moving with the car, the sound remains constant because the relative motion between the sound source and the observer is the same, this individual will not experience the Doppler effect and will hear the car's sound at its original pitch.
Furthermore, the observer at rest may experience varying sound intensity due to the car's changing distance. On the other hand, the person moving with the car will have a relatively consistent sound intensity, as their distance from the sound source remains constant. Overall, the Doppler effect and sound intensity are the key factors that differentiate the auditory experience between these two scenarios.
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pls help me i know the answer but i have no idea how it comes.
Explanation:
Equivalent Resistance of R1 and R2 in parallel
= R1 * R2 / R1 + R2
= 1800 / 90
= 20 Ohms
Ammeter measures current flowing through the circuit :
V = I * R
I = V / R
I = 9 / 20
I = 0.45 A
____________ occurs when heat is transferred into an object through motion or movement; an example would be boiling water. a conduction b convection c radiation d heat
Its a Conduction NO FOR REAL ITS A
Answer:
c, convection
Explanation:
edge 2020
Suppose you are pushing a stalled car. As the gets going, you need less and less force to keep it going. For the first 15 m, your force decreases at a constant rate from 210.0 N to 40.0 N. How much work did you do on the car? Draw a force-displacement graph to represent the work done during this period.
Answer:
1875 j
Explanation:
f * d = work
your AVERAGE force is (210+ 40)/2 = 125 N
125 * 15 = 1875 j
The work done during this period will be 1875 J.. if the body is displaced in the same direction of the force it will be positive.
What is work done?Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.
Work may be zero, positive and negative.it depends on the direction of the body displaced
The given data in the problem is;
F is the average force applied by the worker
d is the displacement = 15 m
The average force is ;
\(\rm F_{AVG} = \frac{F_1+F_2}{2} \\\\ F_{AVG} = \frac{210+40}{2} \\\\ F_{AVG}=125 \ J\)
The work done by the worker will be;
\(\rm W= Fd \\\\\rm W= F_{AVG}d \\\\W= 125 \times 15 \\\\ \rm W=1875 \ J\)
Hence the work done during this period will be 1875 J.
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1 point
The Sun is a massive star at the center of our Solar System. The planets
closest to the Sun are terrestrial planets, and those farther away are gas
giants. Which force maintains this arrangement of the Solar System? *
Electromagnetism
Friction
Gravity
Torsion
Answer:
Gravity
Explanation:
It is gravity because the sun's gravity pulls all the planets towards itself and keeps the planets in the sun's orbit
i need help plssssssss
The object with the greatest inertia is 8 kg bowling ball.
option A is the correct answer.
What is Newton's first law of motion?Newton's first law of motion states that a body at rest or uniform motion in a straight line will continue in that form unless it is acted upon by an external force.
Newton's first law of motion is also called the law of inertia because it depends on the mass of the object.
The inertia of a body or an object is the measure of the reluctance of the body or object to start moving when it is at rest or to to stop moving when it is in motion.
The inertia of an object depends on the mass of the object, thus the greater the mass of an object the greater the inertia of the object and vice versa.
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AYE I NEED HELP!
Which two things balance and keep a main sequence star in equilibrium?
Answer:
While self-gravity pulls the star inward and tries to make it collapse, thermal pressure (heat created by fusion) pushes outward. These two forces cancel each other out in a main sequence star, thus making it stable.
Explanation:
what is the defining characteristic of the trojan asteroids?
The defining characteristic of Trojan asteroids is their location in space. They are asteroids that share the orbit of a planet, leading or following the planet in its path around the sun. Specifically, Trojan asteroids are located in stable points known as Lagrange points, which are positions in space where the gravitational forces of two large objects, such as a planet and the sun, are balanced by the centripetal force of a smaller object.
Trojan asteroids are named after the mythical Trojan Horse from the Trojan War, because their discovery in the late 19th century was seen as a "hidden" population of asteroids that were difficult to detect due to their location in the same orbit as Jupiter. Today, Trojan asteroids have been found associated with several planets in the Solar System, including Mars, Neptune, and even Earth.
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Two boys, Shrijan having weight 600N and Shrijesh having weight
300N are playing see-saw. If Shrijan is sitting at 2m from fulcrum,
where should Shrijesh sit from fulcrum to balance Shrijan?
Answer:
to be balanced moments should be equal
4m
Explanation:
\(fd = fd \\ 600 \times 2 = 300 \times x \\ \frac{600 \times 2}{300} = x \\ 4m\)
Answer:
4m
Explanation:
fd=fd
600×2× x
300
4m ans
describe the energy transformations on a pendulum (kinetic and potential)
Answer:
Explanation:
As a pendulum swings, its potential energy converts to kinetic and back to potential. ... During the course of a swing from left to right, potential energy is converted into kinetic energy and back.
Answer:
Once the weighted end of the pendulum is released, it will become active as gravity pulls it downwards. Potential Energy Is Converted To Kinetic Energy. which is the energy exerted by a moving object. An active pendulum has the most kinetic energy at the lowest point of it's swing when the weight is movin.
HOPE THIS HELPS!!
Consider a planet of mass m that has a circular orbit of radius r around a star of mass M >> m. The planet's Hill radius ry is defined such that at this distance from the planet toward the star, the forces on an orbiting test mass will be in balance. a. At such a distance rh from the planet, and r - rh from the star, write out the combined acceleration gtot from the star's gravity and the planet's gravity, as well as the centrifugal acceleration from orbiting the star with the same period as the planet. b. Now set this &tot = 0, and solve for ry in terms of m, M, and r, under the approximations m
a. The combined acceleration gtot at distance rh from the planet in a circular orbit around the star with radius r is given by gtot = -(GM/r^2)rh + (Gm/r^2)(r - rh) + (v^2/rh), where G is the gravitational constant, M is the mass of the star, m is the mass of the planet, and v is the orbital velocity of the planet.
b. Setting gtot = 0 and solving for ry, the Hill radius is approximately given by ry = r[(m/3M)^(1/3)]. This approximation assumes that m << M and that the orbit of the planet is circular. The Hill radius is the maximum distance from the planet where its gravity dominates over the star's gravity and where objects can be stably bound to the planet.
To calculate the combined acceleration, we must consider the gravitational forces of both the star and the planet on an orbiting test mass at distance rh from the planet.
The centrifugal acceleration is also included as it must be balanced by the gravitational forces. Setting gtot to zero and solving for ry involves algebraic manipulation and the use of the approximation that m << M and the orbit is circular.
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A vehicle is travelling with uniform velocity along a straight, level stretch of highway. The combined force due to the rolling friction and air resistance is - 5000 N. What is the applied force on the vehicle as it moves?
Answer:
The applied force on the vehicle is 5,000 N
Explanation:
From the question, we have the following parameters of the motion of the vehicle;
The form of the velocity with which the vehicle is travelling = Uniform velocity
The direction of motion of the vehicle = Along a straight and level stretch of the highway
The combined force which acts as resistance to the vehicle's motion = 5,000 N from rolling friction and resistance of the air opposite to the direction of motion
A vehicle travelling with uniform velocity has zero acceleration, therefore;
The acceleration of the vehicle, a = 0 m/s²
According to Newton's Second Law of Motion, we have;
Force, F = Mass, m × Acceleration, a
∴ The net force of acting on the vehicle, F = m × a
Where;
m = The mass of the vehicle
a = The acceleration of the vehicle = 0 m/s²
∴ F = m × 0 = 0
The net force on the vehicle = 0, therefore;
The applied force + The force of rolling friction and air resistance = 0
We therefore have;
The applied force + 5,000 N = 0
∴ The applied force = 0 - 5,000 N = -5,000 N
The applied force, F = 5,000 N in the direction of motion.
The object in this diagram has a mass of 2 kg.
According to this diagram, what is the acceleration of this object?
A. 0 m/s2
B. 4 m/s2
C. 7 m/s2
D. 11 m/s2
Answer:
\(4 ms^{-2}\)
Explanation:
Normal force - should be the reaction from the surface it's on - nullifies the weight of the object. At this point the only force is of \(22-14 = 8N\) from whoever is pushing the square and the friction, towards the right. At this point we divide the force by the mass of the object to obtain an acceleration of \(8/2 = 4 ms^{-2}\)
a baseball bat strikes a ball head-on with an average force of 2.0 × 104 newtons. if the bat stays in contact with the ball for a distance of 5.0 × 10-3 meter, what kinetic energy will the ball acquire from the bat?
o 1.0 x 10^2 J
o 2.0 x 10^2 J
o 2.5 x 10^1 J
o 4.0 x 10^2 J
The kinetic energy of the bat which strikes the ball with the force of 2 x 10⁴ N is a) 1.0 x 10² J
The force at which the bat strikes the ball = 2 x 10⁴ N
The distance traveled by the ball = 5 x 10⁻³ m
The work done by the bat is the kinetic energy of the bat. Thus, the formula to find the kinetic energy of the bat is
K.E = F x d
where K.E is the kinetic energy of the bat
F is the force of the bat
d is the distance traveled by the ball.
Let us substitute the known values in the above equation, we get
K.E = 2 x 10⁴ x 5 x 10⁻³
= 10 x 10
= 1.0 x 10² J
Therefore, the kinetic energy of the bat is 1.0 x 10² J
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Consider a material that can exist in two distinct phases, and , depending on the pressure and temperature. At any point along the coexistence line in the phase diagram, the Gibbs free energy of the two phases is the same: G (P, T) = G (P, T). In this problem, you will derive some useful properties of the slope of the coexistence line.
The coexistence line is a function P(T). Imagine the system is at coexistence. Write down the
expression for how G changes if you make a small change in pressure and temperature, and
do the same for G. If you want to stay on the coexistence line after such a change, you
cannot change P and T independently; you have to change them in a specific ratio.
a) Calculate this ratio dP/dT in terms of the entropies and volumes of the two phases.
b)Rewrite the expression you found in part a) in terms of this latent heat ΔH and the change in volume ΔV = V – V.
c) Let’s assume that we are interested in the transition from a liquid (Phase ) to a gas (Phase ). The gas has a much greater than volume, so you can assume that ΔV ≈ V. Use the
ideal gas to simplify the expression for the slope of the coexistence line.
d) the coexistence line between the solid and liquid phases of water has a negative slope. Given your result from part b), what does that imply for the densities of ice and liquid water?
For the transition from solid to liquid, ΔH is positive (endothermic process), so V₂ - V₁ must be negative (liquid water is more dense than ice). As a result, liquid water has a density that is higher than ice.
a) From the definition of the Gibbs free energy, we have:
dG = -S dT + V dP
At coexistence, we have G(P,T) = G(P,T).
∂G/∂T|P = ∂G/∂T|P
(∂G/∂P|T) (dP/dT) = - (∂G/∂T|P)
At coexistence, the two phases have the same Gibbs free energy, so we can write:
(∂G/∂P|T) (dP/dT) = - (∂G/∂T|P) = S
Rearranging, we get:
dP/dT = - (S / (∂G/∂P|T))
b) From the definition of the latent heat of a phase transition, we have:
ΔH = TΔS - PΔV
At coexistence, we have ΔG = 0, so ΔG = ΔH - TΔS = 0. Solving for ΔS, we get:
ΔS = ΔH / T
Using the Maxwell relation (∂S/∂P)_T = (∂V/∂T)_P, we can write:
(∂G/∂P|T) = - S / (∂S/∂P|T) = - V / (∂V/∂T|P)
Substituting these expressions into the result from part a), we get:
dP/dT = (ΔH / T) / (V₂ - V₁)
where V₁ and V₂ are the volumes of phases and 2, respectively.
c) Assuming the gas phase is an ideal gas, we can write:
PV = nRT
Taking the derivative of both sides with respect to T at constant P, we get:
V dP/dT + P = nR/ P
Solving for dP/dT, we get:
dP/dT = (nP/ V²) [(∂V/∂T)_P - (R/V)]
At coexistence, we have ΔG = 0, so ΔG = ΔH - TΔS = 0. Solving for ΔH and using the relation ΔV ≈ V₂ - V₁ = V₂ (since the gas volume is much greater than the liquid volume), we get:
ΔH = TΔS = TΔ(V₂ - V₁) ≈ TV₂ΔV
Substituting this expression and the ideal gas law into the result from part c), we get:
dP/dT = nR/V₂
d) From the result in part b), we have:
dP/dT = (ΔH / T) / (V₂ - V₁)
Since the coexistence line has a negative slope, dP/dT is negative. Therefore, ΔH and V₂ - V₁ must have opposite signs.
An endothermic process is a chemical or physical change that absorbs heat from its surroundings. An endothermic process involves a system gaining energy from its surroundings, which lowers the ambient temperature. This process is the opposite of an exothermic reaction, which releases energy in the form of heat.
One common example of an endothermic process is the melting of ice. When heat is applied to ice, the ice absorbs the energy and begins to melt, but the temperature of the surroundings does not increase. Instead, the heat energy is absorbed by the ice, causing its molecules to move faster and eventually break free from their solid structure. Endothermic processes are also used in many industrial applications, such as refrigeration and air conditioning.
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3. Since Aspeon is not expected togrow, Emily believes that the following equations can be used in the valuation analysis: (1) S=[EBIT−kd(D)](1−ks)
(2) V=S+D
(3) P=(V−D0)/n0
(4) n1=n0−D/P
(5) VL=VU+TD
The equations mentioned by Emily in the valuation analysis for Aspeon are as follows:
1) Equation (1): This equation represents the value of equity (S) and calculates it based on the EBIT (earnings before interest and taxes), the tax shield provided by debt (D), and the required return on debt (kd) and equity (ks). It implies that the value of equity is equal to the adjusted EBIT after deducting the tax shield from debt.
2) Equation (2): This equation calculates the total enterprise value (V) by adding the value of equity (S) and debt (D). It represents the total worth of the company, considering both equity and debt.
3) Equation (3): This equation calculates the price per share (P) by dividing the total enterprise value (V) minus the initial debt (D0) by the number of shares (n0). It represents the price per share based on the valuation of the company.
4) Equation (4): This equation calculates the new number of shares (n1) by subtracting the dividend (D) from the initial number of shares (n0) divided by the price per share (P). It represents the adjusted number of shares after the payment of dividends.
5) Equation (5): This equation calculates the levered value (VL) by adding the unlevered value (VU) with the tax shield value (TD). It represents the value of the company after considering the tax advantages of debt.
These equations provide a framework for valuation analysis, considering factors such as earnings, taxes, debt, and equity. They help assess the value and financial implications of Aspeon's growth prospects.
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pennies used to be called coppers. how do you suppose they got this nickname?
Answer:
because pennies are made from copper
Explanation:
If the inside of a container has a surface area of 20cm², what will be the pressure on each square inch of the container if 117.6kg of force are applied to the container?
Answer:
Explanation:
given :-
force applied = 117.6N
Area = 20 m^2
Pressure =?
solution:-
Pressure = Force / Area
= 117.6 N / 20 m^2
= 5.88 Pascals
Hope it helps :D!
Explanation:
A small, spherical bead of mass 3.00 g is released from rest at t 5 0 from a point under the surface of a viscous liquid. The terminal speed is observed to be vT 5 2.00 cm/s. Find (a) the value of the constant b that appears in Equation 6.2, (b) the time t at which the bead reaches 0.632vT, and (c) the value of the resistive force when the bead reaches terminal speed.
The acceleration of the bead in the viscous liquid at terminal speed is zero, from which the value of the constant b, can be determined.
(a) The constant b is approximately 1.4715 kg/s.(b) The time at which the bead reaches 0.632·\(v_T\), is approximately 2.038 × 10⁻³ seconds.(c) The value of the resistive force when the bead reaches terminal velocity is 0.02943 N.Reasons:
The mass of the bead, m = 3.00 g
Time at which the mass is released, t = 0
Terminal velocity of \(v_T\) = 2.00 cm/s = 0.02 m/s
(a) The equation 6.2, obtained online is presented as follows;
\(\overrightarrow R = -b \cdot \overrightarrow v\)
Where;
\(\overrightarrow R\) = The resistive force = m·a
\(\overrightarrow v\) = The relative velocity of the object
a = The acceleration of the object
We get;
m·g - b·v = m·a
At the terminal velocity, \(v_T\), we have;
a = 0
Therefore;
m·g - b·\(v_T\) = m × a = 0
m·g = b·\(v_T\)
\(b= \dfrac{m \cdot g}{v_T}\)
Therefore;
\(b= \dfrac{0.003 \, kg \times 9.81 \, m/s^2}{0.02 \, m/s} = 1.4715 \, kg/s\)
b = 1.4715 kg/s.
(b) From, m·g - b·v = m·a, and \(a = \dfrac{dv}{dt}\), we have;
\(m \cdot \dfrac{dv}{dt}= m \cdot g - b\cdot v\)
Which gives;
\(\right. \dfrac{dv}{dt}= \mathbf{g - \dfrac{b}{m} \cdot v}\)
The expression for v obtained by differential equation is expressed as follows;
\(v = \dfrac{m \cdot g}{b} \cdot \left(1 - e^{-b \cdot t/m} \right)\)
Which gives;
\(v = \mathbf{v_T \cdot \left(1 - e^{-b \cdot t/m} \right)}\)
Therefore, when the bead reaches 0.632·\(v_T\), we get;
\(1 - e^{-b \cdot t/m}\) = 0.632
\(e^{-b \cdot t/m}\) = 1 - 0.632 = 0.368
\(t= \dfrac{ln(0.368)}{-\dfrac{1.4715}{0.003} } \approx 2.038 \times 10^{-3}\)
The time at which the bead reaches 0.632·\(v_T\), t ≈ 2.038 × 10⁻³ s.
(c) The value of the resistive force at terminal velocity, \(v_T\), is \(\overrightarrow F_R = -b \cdot v_T\)
Which gives;
\(\overrightarrow F_R\) = 1.4715 kg/s × 0.02 m/s = 0.02943 N.
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pls help 50 points
im really lost
Barium have 2 valence electrons.
Neon is a noble gas with 8 valence electrons
Carbon and silicon both have same valence electrons that is 4...
Hope it helps you to not get lost lol
Answer: silicon and carbon
Explanation:
barium has 2 valance electronsNeon has 8 valence electronsSilicon has 4 valence electronsCarbon has 4 valence electrons
signals generated by transducers are normally of the order of
Signals generated by transducers are normally of the order of microvolts to millivolts.
What are transducers?
Transducers are electrical components that transform energy from one form into another. They are electrical sensors that generate an electrical signal based on the quantity being assessed.
A transducer is a device that transforms a physical quantity such as force, pressure, or temperature into an electrical signal. This electrical signal can then be amplified, filtered, or measured in other ways.
Some common examples of transducers include microphones, strain gauges, accelerometers, and thermocouples.
What are the signals generated by transducers?
The signals generated by transducers are normally of the order of microvolts to millivolts. The magnitude of the signal generated depends on the quantity being assessed, as well as the type and sensitivity of the transducer.
In order to use the signal generated by a transducer, it is usually necessary to amplify and filter the signal to remove noise and unwanted frequencies. This can be done using an amplifier or other signal processing equipment.
Overall, the signals generated by transducers are a crucial part of many electronic systems and are used in a wide variety of applications.
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what are similar things that convex and concave have in common ?
Answer:
they are both curved surfaces
Explanation:
What causes the movement of deep ocean currents?
2. What is the net force exerted on a 80.0 kg race-car driver while the race
car is accelerating from 0 to 50.0 m/s in 5.50 s?*
Answer:
The net force exerted on the race-car driver is 727.3 N
Explanation:
Acceleration
According to Newton's second law of motion, the acceleration of an object a is directly proportional to the net force F and inversely proportional to the object's mass m:
\(F=m.a\)
Since we don't have the value of the acceleration, we must use the kinematic equations to calculate it.
The main formula for accelerated motion is:
\(v_f=v_o+a.t\)
Where vf is the final speed of the object, vo is its initial speed, a is the acceleration, and t is the time.
The race-car driver accelerates from vo=0 to 50 m/s in t=5.5 s. We can calculate the acceleration, solving the above equation for a:
\(\displaystyle a=\frac{v_f-v_o}{t}\)
\(\displaystyle a=\frac{50-0}{5.5}\)
\(a=9.09\ m/s^2\)
Now we calculate the net force:
\(F=80\ Kg\cdot 9.09\ m/s^2\)
\(\boxed{F=727.3\ N}\)
The net force exerted on the race-car driver is 727.3 N