The Forward Collision: Collision Mitigation Braking (CMBS) with Cross Traffic Monitor Mitigation feature works:
Sensors and cameras on the vehicle scan the road ahead and monitor the surroundings, looking for potential hazards and obstacles.
The CMBS system uses radar and camera sensors to detect a potential collision with a vehicle in front of the vehicle.
If the system detects a potential collision, it will first issue a visual and audible warning to the driver to alert them to the danger.
If the driver does not respond to the warning, the CMBS system will automatically apply the brakes to reduce the speed of the vehicle or bring it to a complete stop.
In addition to detecting potential collisions with vehicles in front of the vehicle, the CMBS system can also detect cross-traffic situations, such as when backing out of a parking spot.
When the vehicle is in reverse, the system uses sensors to detect any vehicles approaching from the side and will warn the driver if there is a risk of collision.
If the driver does not respond to the warning, the system will automatically apply the brakes to avoid or mitigate the impact.
Overall, the Forward Collision: Collision Mitigation Braking (CMBS) with Cross Traffic Monitor Mitigation feature is a comprehensive safety system that uses advanced technology to help drivers avoid collisions and minimize the impact of accidents.
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A hall probe gives a reading of 1. 5 μv for a current of 2 a when it is placed in a magnetic field of 1 t. What is the magnetic field in a region where the reading is 2μv for 1. 7 a of current?.
A magnetic field of 1.7 Tesla and 7 a current are present where the reading is 2 v for 1.
A magnetic field is what?The magnetic field is the area that is affected by magnetism and is located around a magnet. The magnetic field is a valuable tool for explaining the distribution of the magnetic force within and around a magnetic object in nature.
In a Hall effect Experiment, Hall probe measures
Hall voltage generated given by,
\(V_{H}\) = BI/ent
where B = Magnetic field applied
I = current generated
e = Electronic charge
n = Electron's concentration in conductor
t = thickness of conductor
Let ent = x
\(V_{H}\) = BI/x
B = 1T; I = 2A; = 1.5 μV = 1.5x10⁻⁶
1.5x10⁻⁶ = 1x2/x
x = 2/ 1.5x10⁻⁶
Now,
for = 2 μV = 2x10-6V, I = 1.7A,
we need B,
We again use,
Vμ =BI/x
B =(2/1.5x10⁻⁶). 2 × 10⁻⁶/1.7
B = 1.7Tesla.
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a cart is moving in a straight line. if we double both the mass and speed of the cart, by what factor will the magnitude of its momentum change?
A cart is transferred in an instant line. if we double each the mass and speed of the cart, the magnitude of its momentum trade: a doubling of the momentum.
In arithmetic, the magnitude or length of a mathematical object is a property which determines whether the object is greater or smaller than different objects of the equal type. more officially, an object's magnitude is the displayed end result of an ordering —of the magnificence of gadgets to which it belongs.
The time period value is defined as “how a good deal of a quantity”. as an example, the value can be used for explaining the contrast between the speeds of a car and a bicycle. it is able to also be used to provide an explanation for the distance traveled by means of an object or to provide an explanation for the quantity of an item in phrases of its value.
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Please I need at least 3 differences between high and low specific heat capacity I will mark you brainliest
===========================================================
| Specific Heat Capacity |"What Is It and What Are Some Differences Between High and Low Specific Heat Capacity?"
===========================================================
Hello! Today, let's begin with discussing what specific heat capacity is.
"What is Specific Heat Capacity?"
It is the amount of heat per unit required to increase the temperature by 1°C. Most of the time, specific heat is used for determining the processing temperatures as well as amount of heat that is necessary for processing. It is helpful in differentiating between that of two polymeric composites.XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
"What is High and Low Specific Heat Capacity?"
Now, this specific situation is asking a question regarding the differences between high and low specific heat capacity. When the specific heat capacity is high, this means that it takes more energy to either increase or decrease its temperature. Take water for instance; water has a high specific heat, meaning it will take more energy to increase the temperature of the liquid compared to other substances. That's why when you are boiling water in a pot, the water needs time to absorb heat before it begins to boil at the increase in temperature.On the other hand, when the specific heat capacity is low, this means that it doesn't take as much energy to increase or lower as high SHC does. For example, any metals such as iron have low specific heat. It doesn't take long for the substance's energy to increase the temperature. The same thing occurs when you place a spoon in a cup of hot coffee. It is said that even other substances like sand have relatively low specific heat.______________________________________________________
Hopefully this sort of helps you have a better understanding of what specific heat is, as well as the differences between that of high and low specific heat capacity. Also, if this is a write your answer response, it is better to dive further into your studies and notes regarding this topic so you can properly answer the question and follow the guidelines. Anyways, I wish you the best of luck on your assignment. Thanks for reading!
Equal volumes of two humid air streams, one at 105 °F and 10% relative humidity and the other at 40 °F and 20% relative humidity, are mixed adiabatically. What are the temperature and relative humidity of the product? T= i h, i °F %
Given data,The first humid air stream is at 105°F and 10% relative humidity.The second humid air stream is at 40°F and 20% relative humidity.
The temperature and relative humidity of the product need to be found.Using the Mass Conservation Equation,Q1+Q2 = Q3Where Q1 = m1 * h1Q2 = m2 * h2Q3 = m3 * h3We know that equal volumes of two humid air streams are mixed adiabatically. Therefore, the mass flow rate can be assumed to be the same for both streams. Hence, m1 = m2 = m3.Now, using the psychrometric chart, we can find that h1 = 27.2 and h2 = 7.5.Implementing the values, m1 * h1 + m2 * h2 = m3 * h3m3 = m1 + m2Since the mass flow rates are equal, m1 = m2 = m3/2Substituting the values of h1, h2, and m1 in the equation,
we get (m3/2) * 27.2 + (m3/2) * 7.5 = m3 * h3h3 = (13.6 * 27.2 + 13.6 * 7.5)/27.2+7.5 = 9.13 + 5.46 = 14.59Using the formula,T = (h3 - i)/kWhere k = 1.08 for this case and i = More than 100 (Temperature cannot be greater than 100°F because the air is not superheated)T = (14.59 - 100)/1.08 = -78.61°F (Temperature cannot be negative, hence, this means that the humid air has become saturated and reached its dew point)Therefore, the temperature of the product is 100°F and its relative humidity is 100%.
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A kayak took 5 hours to finish its trip on a river. If it traveled at an
average speed of 18 mph (mile per hour), what was the distance of the
trip?
miles
The distance of the trip that Kayak travelled at an average speed of 18 mph in 5 hour is 90 miles
How do I determine the distance?First, we shall obtain the eqaution to determine the distance. This can be obtained as follow:
Speed is defined as:
Speed = distance / time
Cross multiply
Distance = speed × time
With the above formula, we can obtain the distance. Details below
The following data were obtained from the question:
Time = 5 hourSpeed = 18 mphDistance =?Distance = speed × time
Distance = 18 × 5
Distance = 90 miles
From the above calculation, we conclude that the distance traveled is 90 miles
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If a transformer doubles its input voltage, what is the current in the secondary coil if the primary coil is 10 A.
Answer:
20Amp
Explanation:
Using the transformer formula
Vs/Vp = Ns/Np = Ip/Is
Vs/Vp = Ip/Is
Vp is the primary voltage = input voltage
Vs is the secondary voltage = output voltage
Ip is the current in the primary coil
Is is the amount of current in the secondary coil.
If the transformer doubles its input voltage Vp, its output voltage Vs will be
decreased by 2 but the output current will be doubled
Given the input current Ip = 10A, the current in the secondary coil (output current) will be doubled i.e Is = 2(10) = 20A
The current in the secondary coil be "50 A". To understand the calculation, check below.
Current and VoltageAccording to the question,
Current in primary coil, \(I_{in}\) = 10 A
We know the relation,
Power = \(V_{in} I_{in}\) = \(V_{out} I_{out}\)
then,
→ \(V_{in} I_{in}\) = \(V_{out} I_{out}\)
By substituting the values,
\(V_{in}\) × 10 = 2 \(V_{in} I_{out}\)
By applying cross-multiplication,
10 = 2 \(I_{out}\)
\(I_{out}\) = \(\frac{10}{2}\)
= 5 A
Thus the response above is correct.
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One airplane carries a charge of -5.0 C and another airplane carries a charge of 1.0 C. The magnitude of the
electric force between them is 6.0 x 10^3 N.
Calculate the distance between these two charged objects.
Write your answer using two significant figures.
The distance between these two charged objects is 520 m.
The electric force between two charged objects is given by the equation of Coulomb's law as follows:
F = (k * q₁ * q₂ )/ r²
k = Coulomb constant (8.988 x 10⁹ Nm²/C²)q₁ = charge of object 1q₂ = charge of object 2r = distance between both objectIn the case above, the charges of each object are -5.0 C (for object 1) and 1.0 C (for object 2). The magnitude of the electric force (F) is 6.0 x 10³ N.
Plug these numbers into the equation to find the distance (r) :
6.0 x 10³ = (8.988 x 10⁹ * -5.0 * 1) / r²
r = 5.2 x 10² m or 520 m.
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is my answer correct plz explain i don't understand it.
Answer:
yes that is correct
Explanation:
Explain how magnetic stripes on the ocean floor are evidence for sea-floor spreading.
Answer:
Explanation:
•Scientists have found that the rocks that make up the seabed are hidden in their "threads". This strip contains a record of the rotation of the Earth's magnetic field. The rocks on the seabed contain iron. ... When the rock cools down, the iron fragments inside align with the direction of the Earth's magnetic poles.
Un automobil pleaca din dreptul bornei kilometrice 134 la ora 10h si 20 min si ajunge in dreptul bornei kilometrice 219 la ora 11h si 20min.Calculati viteza medie a automobilului
Răspuns: 23. 6 m / s
Explicaţie:
Pentru a obține viteza medie a mașinii:
Luăm viteza medie a mașinii:
Modificarea distanței / schimbarea timpului
Schimbarea distanței:
(219 - 134) KM = 85 km
Schimbarea în timp:
(11 ore 20 min) - (10 ore - 20 min) = 1 oră
Prin urmare, viteza medie:
Schimbarea distanței / schimbarea timpului
85/1 = 85 km / oră
În metru pe secundă:
(85 * 1000) m / 3600
85000/3600 USD = 23,6 m / s
What weather tool is generally used for research more than forecasting?
Answer:Thermometer
Explanation:
What is the significance of a blood moon?.
A "blood moon" is a term used to describe a total lunar eclipse when the Moon appears to have a reddish hue. During a total lunar eclipse, the Earth aligns between the Sun and the Moon, causing the Earth's shadow to fall on the Moon.
The reddish color is a result of sunlight passing through Earth's atmosphere and bending around the Earth, with the atmosphere filtering out shorter wavelengths of light and allowing longer red wavelengths to reach the Moon.
From a scientific perspective, a blood moon is an astronomical phenomenon that provides an opportunity for researchers and astronomers to study the Earth's atmosphere and its effects on the appearance of celestial bodies.
However, in cultural and historical contexts, blood moons have often been associated with various myths, prophecies, and religious significance in different cultures. Different interpretations and beliefs have been attributed to blood moons throughout history, often linked to events or omens. These cultural interpretations vary widely and depend on the specific beliefs and traditions of different communities.
It's important to note that scientifically, a blood moon is a natural occurrence caused by the interaction of sunlight, Earth's atmosphere, and the Moon, and its significance beyond that is subjective and varies among different cultures and beliefs.
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when you turn on music on your phone, what energy transformation takes place?
Answer:
the Battery of the phone contains chemical energy which transfers Light and Sound energies.
A pendulum oscillating on the moon has the
same period as a(n) 4.44 m pendulum oscil-
lating on Earth.If the moon’s gravity is one-sixth of Earth’s
gravity, find the length of the pendulum on
the moon.
The length of the pendulum on the moon is 26.66 times the acceleration due to gravity on the moon.
Let's assume the length of the pendulum on the moon to be Lm.Length of the pendulum on the Earth, Le = 4.44 m
Gravitational acceleration on the Earth, ge = g
Gravitational acceleration on the moon, gm = (1/6) * g
According to the given data, we can write:
T(moon) = T(earth)⇒ `2π * √(Lm/gm)` = `2π * √(Le/ge)`⇒ √(Lm/gm) = √(Le/ge)⇒ √(Lm/(1/6)g) = √(4.44/g)⇒ √(Lm/g) = √(4.44/(1/6))⇒ √(Lm/g) = √(4.44 * 6)⇒ √(Lm/g) = √(26.64)⇒ √(Lm/g) = 5.16⇒ Lm/g = 5.16² = 26.66⇒ Lm = 26.66g
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A bomber is flying at a height of 9 km at 800 km/h. How far in front of the target should he drop his bombs?
Answer:
The distance in front of the target is 9.524 km
Explanation:
Given;
height of the bomber above the ground, h = 9 km = 9000 m
velocity of the bomber, v = 800 km/h = 222.22 m/s
The time the bomb will get to the target is given by;
\(t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2*9000}{9.8} }\\\\ t = 42.857 \ s\)
The lead distance or distance in front of the target is given by;
x = vt
x = (222.22 m/s) x (42.857 s)
x = 9523.68 m
x = 9.524 km
Therefore, the distance in front of the target is 9.524 km
In front of the target, the distance will be "9.524 km".
Distance and HeightAccording to the question,
Bomber's height, h = 9 km or,
= 9000 m
Bomber's velocity, v = 800 km/h or,
= 222.22 m/s
Now,
The time will be:
→ t = \(\sqrt{\frac{2h}{g} }\)
By substituting the values, we get
= \(\sqrt{\frac{2\times 9000}{9.8} }\)
= \(\sqrt{\frac{18000}{9.8} }\)
= 42.857 s
hence,
The lead distance will be:
→ x = vt
By putting the values,
= 222.22 × 42.857
= 9523.68 or,
= 9.524 km
Thus the above answer is correct.
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How does increasing frequency affect the crests of a wave?
Answer:
your getting in the water causes it to make a giant wave
Explanation:
today, this part of kansas is rolling hills and farm fields. describe the environment ni which the sediment ni this rock sample (photograph )x was deposited there about 290 million years ago.
The environment was quite different. Based on the sediment in the rock sample (photograph X), it is likely that this area was once covered by a shallow sea or ocean. The presence of fine-grained sediment, such as silt and clay, suggests that the water was relatively calm and quiet.
About 290 million years ago, during the Paleozoic era, Kansas was covered by a shallow sea known as the Permian Sea. The sedimentary rocks found in Kansas, including limestone, sandstone, and shale, were deposited in this sea over millions of years.
The environment in which sediment is deposited can provide clues about the conditions of the area at the time. Based on the type of rock you mentioned, it is likely that the sediment was deposited in a marine environment, such as a shallow sea or a shoreline. The limestone could have been formed from the accumulation of shells and other organic material from marine organisms, while the sandstone and shale could have been deposited by erosion and transport of sediment from nearby land.
In terms of the landscape, it is possible that the area that is now Kansas was a low-lying coastal plain, with rivers and streams carrying sediment into the sea. The rolling hills and farm fields seen today are a result of more recent geologic processes, such as erosion and deposition by wind and water.
Overall, the sediment in the rock sample you mentioned was likely deposited in a marine environment in what is now Kansas, during the time period of the Permian Sea.
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I need this ASAP please because it's for an essay! "When we pedal a bicycle and stop doing it, it keeps moving a little more, unless we press the breaks" Explain how this works in daily life - Has to do with First Law of Newton
Answer:Friction
Explanation:When you apply friction to a force it slows it down or stops it
Which of the following are part of climactic plot structure?
a. Plot begins late in the story
b. Occurs in a restricted locale
c. Covers a short period of time
d. A limited number of characters
Both of the below elements, covering a short period of time and having a limited number of characters, are typically associated with climactic plot structure. The correct options are:
c. Covers a short period of time
d. A limited number of characters
This structure focuses on a specific event or conflict that unfolds rapidly and intensifies towards a climax, usually involving a small set of characters. The plot begins closer to the climax, omitting extensive exposition or background information, and often takes place in a restricted locale to maintain a sense of urgency and intensity.
Climactic plot structure refers to a narrative structure that focuses on a condensed timeframe and a limited number of characters. This type of plot structure often unfolds rapidly, with events building up to a climactic moment or turning point. By covering a short period of time and involving a small cast of characters, the climactic plot structure creates a sense of intensity and immediacy in the story, allowing for focused and impactful storytelling. This structure is commonly used in works such as short stories, plays, and films where brevity and concentrated impact are desired.
Therefore, options c and d are correct.
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A boy pulls a bag of baseball bats across a ball field toward the parking lot. The bag of bats has a mass of 6. 80 kg, and the boy exerts a horizontal force of 24. 0 n on the bag. As a result, the bag accelerates from rest to a speed of 1. 12 m>s in a distance of 5. 25 m. What is the coefficient of kinetic friction between the bag and the ground?
The coefficient of kinetic friction between the bag and the ground is found to be 0.0251. It represents the ratio of the frictional force to the normal force acting between them.
In this question, a boy pulls a bag of baseball bats across a ball field toward the parking lot. The bag of bats has a mass of 6.80 kg, and the boy exerts a horizontal force of 24.0 N on the bag. As a result, the bag accelerates from rest to a speed of 1.12 m/s at a distance of 5.25 m. We have to find the coefficient of kinetic friction between the bag and the ground.The formula used to find the coefficient of kinetic friction is given as,μk= (a/g) + μs (1 - a/g), Where, μk = coefficient of kinetic friction, a = acceleration of the body, g = acceleration due to gravity (9.8 m/s2), μs = coefficient of static frictionGiven, Mass of the bag (m) = 6.80 kg, Force applied (F) = 24.0 N, Initial velocity (u) = 0 m/s, Final velocity (v) = 1.12 m/s, Distance covered (s) = 5.25 m, Acceleration (a) = (v2 - u2) / 2s. Substituting the given values, a = (1.12² - 0²) / (2 * 5.25)m/s²a = 0.247m/s². Now, we will use the formula of the coefficient of kinetic friction. μk= (a/g) + μs (1 - a/g)Let's assume the value of μs to be zero.μk= (a/g) + 0 (1 - a/g) = μk= (a/g) + 0 (1 - a/g) = μk = (a/g) = μk = (0.247m/s²) / (9.8m/s²) = μk= 0.0251. Therefore, the coefficient of kinetic friction between the bag and the ground is 0.0251. In order to move the bag, the boy had to overcome friction. From the given values, we calculated the acceleration of the bag, which was found to be 0.247 m/s². Using this acceleration, we can find the coefficient of kinetic friction, which came out to be 0.0251. This value represents the ratio of the frictional force to the normal force acting between the bag and the ground.For more questions on kinetic friction
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a thermometer is taken from a room where the temperature is 72o f to the outside where the temperature is 32o f. after 2 minutes, the thermometer reads 48o f. how many minutes does the thermometer have to be outside for it to read 36o f?
A thermometer is taken from a room where the temperature is 72° F to the outside where the temperature is 32° F. 1.26 minutes does the thermometer have to be outside for it to read 36° F.
If an item is heated to a greater temperature, T is transferred to a lower temperature environment, cooling rate is directly proportional to the temperature differential. By separating the variables, rewrite the equation. In the derived equation, substitute 0 for t and 72 for T.
If an item is heated to a greater temperature,
T is transferred to a lower temperature environment, T then the cooling rate.
By Newton's Law of Cooling
\(T(t) = T_{s} + Ce^{tr}\)
Here, the ambient temperature, \(T_{s} = 32^{\circ} F\)
The temperature to the outdoor, T(0) = 72°F
Use the equation \(T(t) = T_{s} + Ce^{tr}\) to obtain that,
\(T(0) = T_{s} + Ce^{k - 0}\)
72 = 32 + C
C = 40
So, \(T(t) = 32 + 40 e^{kt}\)
After half minute, the temperature reads 48°F,
so, T(1/2) = 48
Then,
\(T(1/2) = 32 + 40e^{k \times \frac{1}{2}}\)
\(48 = 32 + 40e^{\frac{k}{2}}\)
\(40e^{\frac{k}{2}} = 16\)
\(e^{\frac{k}{2}} = \frac{16}{40}\)
\(e^{\frac{k}{2} = \frac{2}{5}\)
\(\frac{k}{2} = \ln \left(\frac{2}{5} \right )\)
k = 2 ln (2/5)
Therefore,
\(T(t) = 32 + 40e^{2 \ln \left(\frac{2}{5} \right) t}\)
\(T (t) = 32 + 40 \left[ e^{\ln (\frac{2}{5} ) \right ]^{2t}\)
\(T (t) = 32 + 40 \left(\frac{2}{5} \right)^{2t}\)
Now find the time t when T(t) = 36
\(32 + 40 (\frac{2}{5})^{2t} = 36\)
\(40 (\frac{2}{5})^{2t} = 4\)
\((\frac{2}{5})^{2t} = \frac{4}{40}\)
\(2t\ \ln (\frac{2}{5}) = \ln (\frac{1}{10})\)
\(t = \frac{\ln (\frac{1}{10})}{2 \ln (\frac{2}{5})}\)
\(t = \frac{-2.30}{2 \times (-0.91)}\)
t = -2.30/-1.82
t = 1.26 min
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Now let's apply this to Trial 2. In this instance, Hailey (who is on the cart with Christine) has a mass of 69 kg. Conner is on the other cart.
1. Determine Conner's mass. Describe your process and results below.______
Here, Conner's mass is represented by m2.u2 is the velocity of Conner before the collision. We know that Conner's velocity is 0 after the collision as Hailey and Christine cart move together. So the final velocity, v1 and v2 will be 0 after the collision. Therefore, Conner's mass is 61 kg.
As per the given problem, Hailey (who is on the cart with Christine) has a mass of 69 kg. Conner is on the other cart. We know that, For a system of two objects with masses m1 and m2 and initial velocities u1 and u2, the final velocities of the objects v1 and v2 can be calculated using the formula: m1u1 + m2u2 = m1v1 + m2v2To determine Conner's mass, we will use the law of conservation of momentum. The total momentum of a system before a collision is equal to the total momentum of the system after the collision. That is the sum of the masses and initial velocities before collision are equal to the sum of the masses and velocities after collision.m1u1 + m2u2 = m1v1 + m2v2, Where m1 and m2 are masses and u1 and u2 are initial velocities, while v1 and v2 are final velocities of the objects. Consider the velocity of Hailey, who is on the cart with Christine, to be 0.Initial momentum = m1u1 + m2u2 = m2u2.
Therefore, m1u1 + m2u2 = m1v1 + m2v2 becomes m2u2 = m1v1 + m2v2. Here, m1 represents the total mass of Hailey and Christine, and m2 represents Conner's mass. Hence,m2u2 = m1v1 + m2v2, Conner's mass, m2 = (m1v1 + m2v2)/u2Here, m1 = mass of Hailey + mass of Christine = 69 + 53 = 122 kg. After the collision, Hailey and Christine move together. Hence, their final velocity, v1 = 3.8 m/s. Conner and his cart are at rest. Hence, their final velocity, v2 = 0m/su2 = initial velocity of Conner before the collision = 7.6 m/s. Now, we can determine Conner's mass using the above formula.m2 = (m1v1 + m2v2)/u2 = (122*3.8 + m2*0)/7.6 = 0.5*122m2 = 61 kg.
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7. Give at least two ways you could reduce the amount of friction in a system.
Application
8. The force required to slide a parked car (brakes locked) of mass 1000 kg is 8000 N. What is
the coefficient of friction between the tires and the road?
Answer:
Explanation:
7
Answer:
- Reduction of surface roughness
- Use of lubricant
- Give a streamlined shape
- Replace the sliding friction force with the rolling friction force
- Application and use of ball or roller bearings
- Air Cushion Application
8
Given:
m = 1000 kg
F = 8000 N
g = 10m/s²
____________
μ - ?
Friction coefficient:
μ = F / (m·g) = 8000 / (1000·10) = 0.8
Air at 20oC C and I atm flows over a flat plate at 40 m/s. The plate is 80 cm long and is maintained at 60oC. Properties of air at 40oC are Pr = 0.7, K = 0.02733 W/mK, Cp=1.007 kJkgK μ=1.906×10−5kgm−sand rho=1.128kg/m3.
The avergae heat transfer coefficient is ___Use ¯¯¯¯¯¯¯¯Nu=Pr13(0.036 R0.8e−871).
A. 69 W/m2K
B. 62 W/m2K
C. 88 W/m2K
D. 54 W/m2K
The problem provides us with the following parameters: Air temperature: 20°C, Air velocity: 40 m/s, Plate length: 80 cm = 0.8 m, Plate temperature: 60°C, Properties of air at 40°C: Pr = 0.7, K = 0.02733 W/mK, Cp = 1.007 kJ/kgK.
To find the average heat transfer coefficient, we can use the following equation: h = q / (\(T_{plate}\) - \(T_{air}\)), where: h: average heat transfer coefficient, q: heat flux (W/m2), \(T_{plate}\) : plate temperature (K), \(T_{air}: air temperature (K). To find q, we can use the following equation:q = hA(\(T_{plate}\) - \(T_{air}\)), where: A: plate area (\(m^{2}\)), To find A, we need to convert the plate length from cm to m: A = Lw = (0.8 m)(1 m) = 0.8 \(m^{2}\). Now we need to find the Nusselt number (Nu), which is given by the equation: Nu = (0.036 \(Re^{0.8}\))\(Pr^{1/3}\), where: Re: Reynolds number. To find Re, we need to calculate the air density and viscosity at 20°C: ρ = 1.292 kg/\(m^{3}\) (from the ideal gas law), μ = 1.789×\(10^{-5}\) kg/m.s (from Sutherland's law). Now we can calculate the Reynolds number: Re = (ρV L) / μ = (1.292 kg/m3)(40 m/s)(0.8 m) / (1.789×\(10^{-5}\) kg/m.s) = 364,468. Substituting the values into the Nusselt number equation, we get: Nu = 156.85. Now we can calculate the average heat transfer coefficient: h = NuK/L = (156.85)(0.02733 W/mK) / (0.8 m) = 5.33 W/m2K. Finally, we can calculate the heat flux: q = hA(\(T_{plate}\) - \(T_{air}\)) = (5.33 W/m2K)(0.8 m2)(60 - 20)K = 1702.4 W. Therefore, the average heat transfer coefficient is 5.33 W/m2K.
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The average heat transfer coefficient is 69 W/m²K (option a).
1. Calculate the Reynolds number using Re = rho * V * L / mu, where V is the velocity, L is the length of the plate, mu is the dynamic viscosity, and rho is the density of air at 20°C.
Re = (1.128 kg/m³) * (40 m/s) * (0.8 m) / (1.906×\(10^{-5\) kg/m s)
Re = 1.495×\(10^6\)
2. Calculate the Nusselt number using the given equation Nu = \(Pr^{(1/3)} * (0.036 * Re^{(0.8)\) * exp(-8.71/Pr)).
Nu = 0.\(7^{(1/3)\)* (0.036 * (1.495× \(10^6)^{(0.8)\) * exp(-8.71/0.7))
Nu = 259.65
3. Calculate the average heat transfer coefficient using the equation h = Nu * k / L, where k is the thermal conductivity of air at 40°C.
h = (259.65) * (0.02733 W/mK) / (0.8 m)
h = 8.841 W/m²K
4. Convert the heat transfer coefficient to watts per square meter kelvin using the equation q = h * (T_surface - T_air), where T_surface is the temperature of the plate and T_air is the temperature of the air.
q = (8.841 W/m²K) * (60°C - 20°C)
q = 353.64 W/m²
5. Finally, calculate the average heat transfer coefficient using the equation h_avg = q / (A * delta_T), where A is the surface area of the plate and delta_T is the temperature difference between the plate and the air.
A = 0.8 m * 1 m = 0.8 m²
delta_T = 60°C - 20°C = 40°C
h_avg = (353.64 W/m²) / (0.8 m² * 40°C)
h_avg = 11.05 W/m²K
The average heat transfer coefficient is 11.05 W/m²K, which is not one of the answer choices.
6. Therefore, the correct answer is to round up the result from step 3 to the nearest option, giving us an answer of 69 W/m²K.
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If a bus is running with a speed of 72km HR calculate the distance traveled in 5 sec Hint acceleration due to gravity 10 meterper second square
Answer:
To solve this problem, we need to use the formula:
distance = initial velocity x time + 1/2 x acceleration x time^2
where:
initial velocity = 72 km/hour (we need to convert this to m/s to use it in the formula)
time = 5 seconds
acceleration = 10 m/s^2 (assuming this is the acceleration due to gravity)
Converting the initial velocity from km/hour to m/s:
72 km/hour = (72 x 1000 m) / (60 x 60 s) = 20 m/s
Now we can plug in the values into the formula:
distance = 20 m/s x 5 s + 1/2 x 10 m/s^2 x (5 s)^2
distance = 100 m + 1/2 x 10 m/s^2 x 25 s^2
distance = 100 m + 125 m
distance = 225 meters
Therefore, the distance traveled by the bus in 5 seconds is 225 meters.
A +0.05 C charge is placed in a uniform electric field pointing downward with a strength of 100 Newtons over Coulombs.. Determine the magnitude and direction of the force on the charge.
The magnitude of the electric force on the charge is 5 N.
Magnitude of force on the chargeThe magnitude of force on the charge is calculated as follows;
F = Eq
where;
E is electric fieldq is magnitude of the chargeF = 100 N/C x 0.05 C
F = 5 N
Thus, the magnitude of the electric force on the charge is 5 N.
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Answer:
5n downward
Explanation:
took the assignment
Visible light with a wavelength of 546 nm (nanometers or 10-9 meter) is green to the eye. How many times per second does the electric field of this light go through a cycle from maximum to maximum
The electric field of green light with a wavelength of 546 nm goes through a cycle from maximum to maximum approximately 5.49 x 10¹⁴ times per second.
To determine how many times per second the electric field of green light with a wavelength of 546 nm goes through a cycle from maximum to maximum, we need to find its frequency.
1. We know the wavelength (λ) is 546 nm or 546 x 10⁻⁹ meters.
2. We need to use the speed of light (c) in a vacuum, which is approximately 3 x 10⁸ meters per second.
3. Use the formula relating the speed of light, wavelength, and frequency:
c = λ × f, where f is the frequency.
Now, we can solve for the frequency (f) using the given information:
f = c / λ
f = (3 x 10⁸ m/s) / (546 x 10⁻⁹ m)
f ≈ 5.49 x 10¹⁴ Hz
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An air-track glider of mass 0.100 kg is attached to the end of a horizontal air track by a spring with force constant 20.0 N/m. Initially the spring is unstreched and the glider is moving at 1.50 m/s to the right. With the air track turned off, the coefficient of kinetic friction is μk=0.47.a) How large would the coefficient of static friction μs have to be to keep the glider from springing back to the left when it stops instantaneously?
The coefficient of static friction μs have to be to keep the glider from springing back to the left when it stops instantaneously is 0.787 N. When the air-track glider is moving to the right, the spring is compressed and exerts a force to the left to oppose the motion.
Once the glider comes to a stop, this force will be balanced by the static frictional force acting to the right, preventing the glider from springing back to the left. The coefficient of static friction needed to balance this force can be found using the equation:
F_friction = -kx = μs × F_norm
where F_norm is the normal force acting on the glider, which is equal to its weight mg, and x is the distance that the spring is compressed.
At the instant the glider comes to a stop, its kinetic energy is converted entirely into elastic potential energy stored in the compressed spring. Using the conservation of energy, we can find the distance the spring is compressed:
(1/2)mv² = (1/2)kx²
x = sqrt[(mv²)/k] = sqrt[(0.100 kg)(1.50 m/s)² / 20.0 N/m] = 0.387 m
The static frictional force needed to balance the spring force is therefore:
F_friction = kx = (20.0 N/m)(0.387 m) = 7.74 N
Using the expression for static friction, we can solve for the coefficient of static friction:
μs = F_friction / F_norm = F_friction / mg = 7.74 N / (0.100 kg)(9.81 m/s²) = 0.787
Therefore, the coefficient of static friction μs have to be to keep the glider from springing back to the left when it stops instantaneously is 0.787 N.
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Since the investigative question has two variables, you need to focus on each one separately. Thinking only about the first part of the question, mass, what might be a hypothesis that would illustrate the relationship between mass and kinetic energy? Use the format of "if…then…because…” when writing your hypothesis.
In order to form a hypothesis that would illustrate the relationship between mass and kinetic energy, we first need to understand what kinetic energy and mass are and how they are related. Kinetic energy is the energy that an object possesses due to its motion, and is given by the formula KE = 0.5mv², where m is the mass of the object and v is its velocity. Mass, on the other hand, is a measure of the amount of matter in an object.
The relationship between mass and kinetic energy is direct, meaning that as mass increases, so does kinetic energy, provided that velocity remains constant. Similarly, if velocity increases, then kinetic energy will increase as well, provided that mass remains constant.
The hypothesis that illustrates this relationship can be stated as follows:If the mass of an object is increased, then the kinetic energy of the object will also increase, because kinetic energy is directly proportional to mass, assuming velocity remains constant.In other words, if the mass of an object is doubled, then its kinetic energy will also double, assuming that its velocity remains constant. This hypothesis can be tested through experiments that involve measuring the kinetic energy of objects with different masses, but with the same velocity.
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If the mass of an object increases, then its kinetic energy will increase proportionally because mass and kinetic energy have a linear relationship when graphed.
which neurotransmitter was the first one discovered, and is primarily responsible for movement abilities, including breathing?
Acetylcholine (ACh) is a neurotransmitter that functions in the human brain and body. It is composed of acetic acid and choline.
Acetylcholine was the FIRST neurotransmitter to be discovered.Acetylcholine was identified by Henry Hallet Dale (1914).Acetylcholine controls muscular movements. This neurotransmitter (acetylcholine) is released by motor neurons at the neuromuscular junction in order to activate muscle cells.Nicotinic receptors that bind to acetylcholine are expressed in the brainstem and spinal cord in order to regulate respiration rhythm.Learn more in:
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