What is cyanosis? Describe several physical and/or chemical factors that might create cyanosis in a patient and how cyanosis can be reversed.

Answer:

Each organ (roots, stems, and leaves) include 3 tissue types, ground, vascular, and dermal. Different cell types comprise each tissue type, and the structure of each cell type influences the function of the tissue it comprises.

Explanation:

In short I'd say the cells look different because they have different functions.

Whereas the majority of proteins pass through the Golgi on their way to other cell destinations,

In plant cells, the Golgi gear is the key organelle for polysaccharide and glycolipid synthesis, protein glycosylation, and protein classification towards various cellular sections either by vesicular shuttles or through the maturation of cisternae from the cis‐ to the trans‐face, a digit of membrane proteins reside in the dissimilar Golgi.

Plants move proteins inside these cells. This procedure, known as protein transport, is the footing for a complex biological response mechanism. During every second of a plant cell's life, a host of protein transports take place.

So we can conclude that  There are many storage proteins in plant tissues that gather into protein storage compartments.

Learn more about proteins here: https://brainly.com/question/884935

#SPJ1

The claim that a control disc, which typically contains water, has no antibiotic effects is True.

An ideal antibiotic is an antibacterial drug that, regardless of the site of infection, eradicates or prevents the growth of all pathogenic bacteria in the host while having no adverse effects on the host's healthy gut flora or beneficial gut microbes.

Antibacterial medications' interactions with their target bacteria can be either bacteriostatic or bactericidal. Bacteriostatic medications cause a reversible growth inhibition; once the treatment is removed, bacterial growth resumes. The target microorganisms are killed by bactericidal medications, in contrast.

To know more about antibiotic visit:-

https://brainly.com/question/17988226

#SPJ1

Answers:

Column A : Column B

1 : C

2 : B

3 : A

Here, the hypothesis is "plants communicate with their neighbors in response to stress", dependent variable is the amount of the stress hormone in the plants, and the independent variable is the exposure to stress (applied 3 times a day for 10 days), standardized variables are plants used, duration of the stressor, amount of stress hormone. The control group is the plant that is not exposed to stressor.

Here, the control group is the group of plants that are not exposed to stress, and the control groups plants are experimented or tested with the other plants to get the result of the stress hormone on the plants.

Hence, here, the hypothesis is "plants communicate with their neighbors in response to stress", dependent variable is the amount of the stress hormone in the plants, and the independent variable is the exposure to stress (applied 3 times a day for 10 days), standardized variables are plants used, duration of the stressor, amount of stress hormone. The control group is the plant that is not exposed to stressor.

Learn more about the control group here.

https://brainly.com/question/1443608

#SPJ9

Answer:

the third option is the right one.

Explanation:

m RNA gets its information from DNA and then sends it to rRNA which will later turn the message into a protein.

Answer:

Choice B i had this question a long time ago ;)

Explanation:

Answer:

The sex of sea turtle offspring depends on the incubation temperature.

Explanation:

1.) In low incubation temperatures (26°C) and high incubation temperatures (36°C), a large number of sea turtle embryos die.

2.) In temperatures 30°C and below, no males hatch, and in temperatures 34°C and above, no females hatch. This suggests that the sex of the hatchlings is affected by incubation temperature.

3.) The correct answer is: The sex of sea turtle offspring depends on the incubation temperature.

Derived characters are those that emerge at some point during evolution, and are expressed by all the subsequent groups. Derived characters shared by protist, plants, fungi, and animals are: eukaryotic organisms, autotroph or heterotroph, cell membrane, nuclei with DNA, mitochondria.

The derived character is any trait that a group passes to the descendants.

Through evolution, the characters change, and new changes are added.

When referring to a derived character, we mean that all the subsequent species in the cladogram, after the character emerged, carry the trait.

In the exposed example, we need to describe characters expressed by protists, plants, fungi, and animals.

You can learn more about derived character at

https://brainly.com/question/9983215

#SPJ1

Answer:

Multiple Sclerosis

Explanation:

Multiple sclerosis (MS) is the most common neurodegenerative and demyelinating inflammatory disease in adults between 18 and 35 years of age and is the second leading cause of neurological disability in young adults. This pathology is considered an organ-specific autoimmune disorder, characterized by multiple focal areas of demyelination called plaques or lesions, which are accompanied by different degrees of gliosis, inflammation and neuroaxonal damage. It usually manifests itself in coordination and balance problems, muscle weakness, difficulties in thinking and memorizing and sensations of numbness, as well as other symptoms. Diagnosis of MS is based on a clinical evaluation in which all symptoms, as well as the signs (overactive reflexes, incoordination, weakness of specific muscle groups, etc.) of the disease are documented. Magnetic resonance imaging (MRI) is used to obtain cross-sectional images of the brain and spinal cord, which can detect the small areas of inflammation and scarring in the brain typical of MS.Lumbar puncture is an analysis of a sample of cerebrospinal fluid (CSF), which has the function of cushioning the brain and spinal cord, to evaluate the abnormalities that occur in patients with MS. The most common CSF abnormality found in 80-90% of MS patients is an increase in the number of cells and proteins of the immune system (immunoglobulins), suggesting inflammation or a strong immune response. This test is particularly useful to diagnose patients who experience a slow and progressive decline in their functions without exacerbation pictures; that is, people with primary progressive multiple sclerosis, especially when no abnormalities are detected in the MRI images of the brain. CSF evaluation can also be used to exclude infections difficult to distinguish from multiple sclerosis.

A proteoglycan is a molecule composed of a protein core and linked glycosaminoglycan (GAG) chains.

1st choice: Large multidomain proteoglycan: The protein core is typically composed of multiple domains, and is often glycosylated and sulfated.

2nd choice: A heterotrimeric protein shaped like a cross and binds to integrins: This heterotrimeric protein is known as talin, and it is composed of three subunits- the talin head, talin rod and talin tail.

3rd choice: A rod-like molecule that cross-links type iv collagen, perlecan and laminin: This molecule is known as nidogen, and it is composed of two distinct domains- an N-terminal globular domain and a C-terminal rod-like domain.

4th choice: A trimeric protein with a triple-helix structure, that forms a two-dimensional sheet: This molecule is known as laminin, and it is composed of three distinct subunits- alpha, beta and gamma.

To learn more about protein click here https://brainly.com/question/29776206

#SPJ4

A purebred tomato plant with red fruit and yellow flowers was crossed with a purebred tomato plant with golden fruit and white flowers, and the map distance is 15, which is in option C. If the promoter region is damaged, RNA polymerase can't bind, which is in option E.

The map distance indicates the distance between two genes that are present on the chromosomes, and when the map distance becomes more than 50%, it indicates the two genes are present on different chromosomes. Here, the red fruit and white flowers and the golden fruit and yellow flowers are recombinants, while the other two are wild types.

Hence, the map distance is 15, which is in option C, and if the promoter region is damaged, RNA polymerase can't bind, which is in option E.

Learn more about the map distance here.

https://brainly.com/question/15014414

#SPJ1

The key difference  is that aerobic respiration requires oxygen, and anaerobic respiration does not.

Aerobic respiration in a cell is when glucose breaks down with help of oxygen and yields carbon dioxide, water, and with the release of energy. Thus end products are \(CO_2}\) and \(H_{2}O\) .The process of releasing energy takes a much longer time. Example it occurs in plants and animals.

Anaerobic respiration  in a cell, is the process of breaking down  glucose without the use of oxygen then it yields to the end products  \(CO_{2}\) (carbon dioxide), alcohol and energy. It is a fast process. Example human muscle cells, and bacteria.

The equation for aerobic cellular respiration
\(C_{6} H_{12} O_{6} + 6O_{2}\) ⇒ \(6CO_{2} + 6H_{2}O\) + ATP(energy)
Glucose   + oxygen ⇒ carbon dioxide + water +energy.

learn more about aerobic and anaerobic respiration at
brainly.com/question/28688557

Answer:

Tthe frequency of the green-winged allele in the next generation will be 46%

Explanation:

For a trait controlled by a pair of alleles A and a in a given population of organisms, the Hardy-Weinberg equilibrium equation is given as:

p² + 2pq + q² = 1; also p + q = 1

Where, p² gives the frequency of h0m0zygous dominant (AA) individuals in a population, 2pq gives the frequency of heterozygous (Aa) individuals, and q² gives the frequency of h0m0zygous recessive (aa) individuals. Also, p gives the frequency of the dominant allele and q is the frequency of the recessive allele in the given population.

In the given population of moths, the green-winged allele is recessive while the brown-winged allele is dominant. When a Hardy-Weinberg equilibrium is established, the frequency of moth h0m0zygous for the recessive allele in the population is 21%.

This means that, q² = 21% = 0.21

The frequency of the green-winged (recessive) allele is q.

Since q² = 0.21

q = √0.21

q = 0.46 = 46%

Therefore, the frequency of the green-winged allele in the next generation will be 46%

The frequency of the green-winged allele in the next generation will be 46%.

If the population is now in Hardy-Weinberg equilibrium, what will be the frequency of the green-winged allele in the next generation using the given information.

that, q² = 21% = 0.21

The frequency of the green-winged (recessive) allele is q.

Since q² = 0.21

q = √0.21

q = 0.46 = 46%

The Hardy-Weinberg equilibrium is a principle saying that the genetic variation in a population will remain consistent from one generation to the next in the absence of disturbing factors.

Thus, the frequency of the green-winged allele in the next generation will be 46%

To learn more about Hardy-Weinberg equilibrium click here:

https://brainly.com/question/25006087

Answer:

C6H12O6 + 6O2 → 6CO2 + 6H2O

Explanation:

Continental crust, Oceanic Crust,  Lithospheric Plate The age of material on a tectonic plate depends in part on what type of crust it is composed .

What is Oceanic Crust?

Oceanic crust is the outermost layer of the Earth's lithosphere which forms the ocean floor. It is composed of mafic igneous rocks such as basalt and gabbro. It is typically 5 to 10 km thick and is the youngest layer of the Earth's lithosphere.

Oceanic crust is formed by seafloor spreading at mid-ocean ridges, which occur when two tectonic plates are pulling apart from each other. This causes molten material from the mantle to rise up and cool, forming new oceanic crust. The newly formed crust then moves away from the mid-ocean ridge in both directions, forming a diverging boundary. As it moves away from the ridge, the oceanic crust cools and becomes denser and denser.

To learn about more Oceanic Crust

https://brainly.com/question/252883

#SPJ1

41) The nucleic acids carried by viruses usually consist of either DNA or RNA, option B is the correct answer.

42)  The fact that is not true about viruses is that Viruses replicate by binary fission. option D is the correct answer.

43)The simplest viruses consist of RNA or DNA in a protein coat covered with lipid envelope. option D is the correct answer.

44) Glycoprotein spikes protruding from the outer surface of viral envelopes function as factors that bind to host cells. option B is the correct answer.

45) The fact that is  NOT true about viral envelopes is that the envelope lipids and carbohydrates are derived from the host. option C is the correct answer.

This refers to a very simple microorganism that infects cells and is capable of causing disease. Viruses can multiply only inside infected cells, hence they are not considered to be alive.

Learn more about viruses on

https://brainly.com/question/16862334

#SPJ1

Based on the information, we can infer that the measurement that could be the least probable is caudal peduncie depth strandard error. Also, the trend is for lake values to be higher than river values.

To identify the values we must analyze the table and identify they are not the trends. In this case we can infer that the tendency is for the values of the lake to be higher than the values of the river because all the values of the lake are higher than those of the river.

On the other hand, we can infer that the value that could be the least successful is the peduncie depth strandard error because it shows equal values. However, if we take into account the previous values, it should not be the same in both cases.

Learn more about lakes in: https://brainly.com/question/858802

#SPJ1

Answer:

0999

Explanation:

beep boop beep boop

UwU

Answer: Bone Marrow texture best described as a Thick Beefy Butter

Explanation: Raw Bone Marrow will smell fresh and slightly sweet. When cooked, its aroma deepens considerably to that of roasted fatty beef.

Answer:

d.) A gram-positive group that includes the Actinobacteria

Explanation:

The best description of high G+C bacteria is option d) A gram-positive group that includes the Actinobacteria.

High G+C bacteria, also known as high guanine-cytosine bacteria, refer to a group of bacteria characterized by a high proportion of guanine (G) and cytosine (C) nucleotide bases in their DNA. This characteristic can be determined by analyzing the DNA composition of bacteria.

Option d) states that high G+C bacteria belong to a gram-positive group that includes the Actinobacteria. This is the most accurate description of high G+C bacteria. Actinobacteria are a phylum of gram-positive bacteria, known for their high G+C content. They are characterized by their filamentous growth and the formation of branching networks of hyphae, similar to fungi. Actinobacteria include a diverse range of organisms, such as the genus Streptomyces, which produce many antibiotics, and Mycobacterium, which includes the species responsible for tuberculosis and leprosy.

Options a), b), and c) are not accurate descriptions of high G+C bacteria. Option a) mentions gram-negative bacteria and includes spirochetes, planctomycetes, and the CFB (Cytophaga-Flavobacterium-Bacteroides) group, which are not specifically associated with high G+C content. Option b) refers to a gram-positive group that includes the Bacilli, which generally do not have a high G+C content. Option c) mentions gram-negative bacteria composed of five classes, but it does not specifically address high G+C content.

Therefore, option d) is the most accurate description of high G+C bacteria, as it correctly identifies them as a gram-positive group that includes the Actinobacteria.

To learn more about Gram-negative bacteria, here

https://brainly.com/question/31619469

#SPJ2

Answer: this is false fish only have water flow through there gills not mouths and thay dont have to be swimming

A female who also had his father's hemophilia, which is a Turner-syndrome X-linked condition. The correct response is C, meaning that both of her parents had nondisjunction during meiosis and produced the gamete that caused the condition.

The most prevalent sex chromosomal anomaly in females is the Turner-syndrome, commonly known as congenital ovarian hypoplasia syndrome. It happens when either one or both of the X chromosomes are absent. Meiosis I, meiosis II, or anaphase of mitosis can all result in nondisjunction. Microtubules pull sister chromatids, also known as homologous chromosomes during meiosis I, to the opposing poles of the cell during anaphase. When the separation does not take place, both sister chromatids or homologous chromosomes are drawn to one pole of the cell. Increased nuchal translucency, nuchal cystic hygroma, coarctation of the aorta/left-sided cardiac abnormalities, brachycephaly, horseshoe kidney, polyhydramnios, oligohydramnios, or non-immune fetal hydrops are aberrant ultrasound findings that can be used to diagnose Turner syndrome in utero.

To learn more about Turner-syndrome from the given link: https://brainly.com/question/2487843

#SPJ4

The complete question is:

A human female with Turner X-linked trait hemophilia as did his father. Which of her syndrome expresses the parents underwent nondisjunction during meiosis, giving rise to the gamete responsible for the syndrome?

A. her mother

B. her father

C. both parents

D. neither parent

E. It is impossible to determine

Answer: your answer is letter C

Explanation: upward urban growth will increase pollution as the number of people will increase .

1. Develop a hypothesis: Sienna hypothesized that plants move toward light. 2. Set up the experiment: Sienna placed one plant near a window and another in a dark room with a small opening that allowed light to come through. 3. Observe and record: Sienna checked the plants every few days and recorded the direction of their growth. 4. Analyze the data: Sienna examined the recorded data to determine the direction of growth for each plant over the six-week period. 5. Draw conclusions: Based on the data analysis, Sienna drew conclusions about whether the plants moved toward the available light source or not.

1. Sienna developed a hypothesis that plants move toward light. This is the initial step where she formulates her prediction based on prior knowledge or observations.

2. Sienna set up the experiment by placing one plant near a window and another in a dark room with a small opening that allowed light to come through. This step ensures that there are two distinct conditions to compare the plant growth.

3. Every few days, Sienna checked the plants and recorded the direction of their growth. This step involves making regular observations and documenting the changes in plant growth over time.

4. After six weeks, Sienna gathered all the recorded data, which included the direction of growth for each plant. This data would serve as the basis for further analysis.

5. Sienna analyzed the data by examining the recorded observations. She compared the direction of growth for each plant and looked for patterns or differences between the plant near the window and the one in the dark room.

6. Based on the data analysis, Sienna drew conclusions about whether the plants moved toward the available light source or not. This step involved interpreting the data and determining if the hypothesis was supported or refuted by the evidence gathered from the experiment.

By following this sequence of steps, Sienna was able to study movement in plants and draw conclusions about their response to light.

For more such questions on hypothesis, click on:

https://brainly.com/question/1511064

#SPJ8

Answer:

A

Explanation:

Anthropology is the study of people, society and cultures. At least that is what I think.