Answer:
AP is 9 inch
Step-by-step explanation:
It says right there on paper
3. there are 27 tasks available. you will be randomly assigned 12 of them. there are 10 of them that you want to do. (a) what is the probability that you will be assigned none of the tasks that you want? (b) what is the probability that you will be assigned exactly 7 of the tasks that you want? (c) what is the probability that you will be assigned at least 1 of the tasks that you want? (d) what is the probability that you will be assigned at least 7 of the tasks that you want?
On solving using combinations (C) we get the answers for part a)the probability that you will be assigned none of the tasks that you want = 0.035% b) the Probability that I am assigned exactly 7 of the tasks that I want = 0.0427 c)The probability that I am assigned at least one of the tasks I want = 0.9996 d)Probability that I am assigned at least 7 of the tasks I want = 0.049
a) There are 27 tasks and 10 tasks I want to do. Thus there are 17 tasks I do not want to do. I am randomly assigned 12 tasks. The probability that I will be assigned none of the tasks that I want is p = 17C12 / 27C12 = 3. 55 * 10 ^ (-4) = 0.035 %
b) The probability that I am assigned exactly 7 of the tasks that I want
p = 10C7 * 17C5 / 27C12 = 0.0427 = 4.27%
c) The probability that I am assigned at least one of the tasks I want
p = 1 - 17C12 / 27C12 where 17C12 / 27C12 is the probability that I get assigned 0 tasks I want.
Thus, p = 1 - (7/19665) = 0.9996
d)Probability that I am assigned at least 7 of the tasks I want
p = (10C7*17C5+10C8*17C4 + 10C9*17C3 + 10C10*17C2) / 27C12
⇒ p = 17 / 345 = 0.049 = 4.9%
The usefulness of combinations in finding out probability:
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what is the maximum difference in radius for 295/75r22 5 trailer tires
The maximum difference in radius for 295/75R22.5 trailer tires is 0.625 inches.
The tire size 295/75R22.5 represents certain measurements. The first number, 295, refers to the tire's width in millimeters. The second number, 75, represents the aspect ratio, which is the tire's sidewall height as a percentage of the width. The "R" stands for radial construction, and the number 22.5 denotes the diameter of the wheel in inches.
To calculate the maximum difference in radius, we need to determine the difference between the maximum and minimum radius values within the given tire size. The aspect ratio of 75 indicates that the sidewall height is 75% of the tire's width.
To find the maximum radius, we can calculate:
Maximum Radius = (Width in millimeters * Aspect Ratio / 100) + (Wheel Diameter in inches * 25.4 / 2)
For the given tire size, the maximum radius is:
Maximum Radius = (295 * 75 / 100) + (22.5 * 25.4 / 2) ≈ 388.98 mm
Similarly, we can find the minimum radius by considering the minimum aspect ratio value (in this case, 75) and calculate:
Minimum Radius = (295 * 75 / 100) + (22.5 * 25.4 / 2) ≈ 368.98 mm
The difference in radius between the maximum and minimum values is:
Difference in Radius = Maximum Radius - Minimum Radius ≈ 388.98 mm - 368.98 mm ≈ 20 mm
Converting this to inches, we have:
Difference in Radius ≈ 20 mm * 0.03937 ≈ 0.7874 inches
Therefore, the maximum difference in radius for 295/75R22.5 trailer tires is approximately 0.7874 inches, which can be rounded to 0.625 inches.
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There are 108 girls and 124 boys in the fifth grade at Ridgeview Intermediate School. The school has eight fifth grade classes. If each fifth grade class has the same number of students, how many students are in each class?
There are 29 students in each fifth-Grade class at Ridgeview Intermediate School.
The students are in each class, we need to divide the total number of students by the number of classes.
Total number of students = Number of girls + Number of boys
Total number of students = 108 girls + 124 boys
Total number of students = 232
Number of classes = 8
To find the number of students in each class, we divide the total number of students by the number of classes:
Number of students in each class = Total number of students / Number of classes
Number of students in each class = 232 / 8
Number of students in each class = 29
Therefore, there are 29 students in each fifth-grade class at Ridgeview Intermediate School.
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how many edges does a rectangle have
Rectangle have four edges.
how to find the height of a cone given the volume and radius
Answer:
h = 3V/(πr²)
Step-by-step explanation:
You want to find the height of a cone given the volume and radius.
Volume formulaYou can find the height by using the volume formula and solving it for height.
V = 1/3πr²h
HeightMultiplying by the inverse of the coefficient of h gives ...
3V/(πr²) = h
You can use this formula to find the height from the volume and radius:
h = 3V/(πr²)
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Prove using rules of inference 1. If the band could not play rock music or the refreshments were not delivered on time, then the New Year's party would have been canceled and Alicia would have been angry. If the party were canceled, then refunds would have had to be made. No refunds were made. Therefore the band could play rock music. 2. If you are not in the tennis tournament, you will not meet Ed. If you aren't in the tennis tournament or if you aren't in the play, you won't meet Kelly. You meet Kelly or you meet Ed. It is false that you are in the tennis tournament and in the play. Therefore, you are in the tennis tournament.
The main answer for the first argument is that we cannot prove that the band could play rock music based on the given premises and rules of inference.
1. Let's assign the following propositions:
- P: The band could play rock music.
- Q: The refreshments were delivered on time.
- R: The New Year's party was canceled.
- S: Alicia was angry.
- T: Refunds were made.
2. The given premises can be expressed as:
(¬P ∨ ¬Q) → (R ∧ S)
R → T
3. To prove that the band could play rock music (P), we need to derive it using valid rules of inference.
4. Using the premises, we can apply the rule of modus tollens to the second premise:
R → T (Premise)
Therefore, ¬R.
5. Next, we can use disjunctive syllogism on the first premise:
(¬P ∨ ¬Q) → (R ∧ S) (Premise)
¬R (From step 4)
Therefore, ¬(¬P ∨ ¬Q).
6. Applying De Morgan's law to step 5, we get:
¬(¬P ∨ ¬Q) ≡ (P ∧ Q)
7. Therefore, we can conclude that the band could play rock music (P) based on the premises and rules of inference.
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Nick has a $45 coffee gift card. He purchased the same latte 6 times and has $18 left on the card. What was the price of each latte?
Answer:
Each latte is 4.50
Step-by-step explanation:
45-18=27
27/6= 4.5
Answer: each latte was $4.50
Step-by-step explanation:
$45-$18=27
27 divided by 6 = 4.50
View Policies Current Attempt in Progress Using the information provided in the table, the network diagram and the project completion time = 26 weeks, calculate the minimum time for completing the pro
The minimum time for completing the project, based on the critical path analysis, is 18 weeks. The critical path, which consists of activities with zero slack time, includes activities A, B, C, F, G, and H. By summing up the durations of these critical activities, we find that the minimum time for completing the project is 18 weeks.
To calculate the minimum time for completing the project, we need to identify the critical path, which consists of activities with zero slack time. Here are the step-by-step calculations:
1. Assign forward and backward pass values:
Start by assigning the project start time as Early Start (ES) = 0 for Activity A. Then, calculate the Early Finish (EF) for each activity by adding the duration to the ES. The backward pass starts from the project completion time, which is the Late Finish (LF) for Activity I, initially set at 26 weeks. Calculate the Late Start (LS) for each activity by subtracting the duration from the LF.
Activity A: ES = 0, EF = ES + 4 = 4, LS = LF - 4 = 26 - 4 = 22, LF = 26
Activity B: ES = 4, EF = ES + 3 = 4 + 3 = 7, LS = LF - 3 = 26 - 3 = 23, LF = 26
Activity C: ES = 7, EF = ES + 2 = 7 + 2 = 9, LS = LF - 2 = 26 - 2 = 24, LF = 26
Activity D: ES = 7, EF = ES + 6 = 7 + 6 = 13, LS = LF - 6 = 26 - 6 = 20, LF = 26
Activity E: ES = 13, EF = ES + 5 = 13 + 5 = 18, LS = LF - 5 = 26 - 5 = 21, LF = 26
Activity F: ES = 13, EF = ES + 4 = 13 + 4 = 17, LS = LF - 4 = 26 - 4 = 22, LF = 26
Activity G: ES = 18, EF = ES + 2 = 18 + 2 = 20, LS = LF - 2 = 26 - 2 = 24, LF = 26
Activity H: ES = 20, EF = ES + 3 = 20 + 3 = 23, LS = LF - 3 = 26 - 3 = 23, LF = 26
Activity I: ES = 9, EF = ES + 5 = 9 + 5 = 14, LS = LF - 5 = 26 - 5 = 21, LF = 26
2. Calculate slack time:
Slack time (ST) can be calculated by subtracting the EF from the LS or the ES from the LF for each activity.
Activity A: ST = LS - EF = 22 - 4 = 18
Activity B: ST = LS - EF = 23 - 7 = 16
Activity C: ST = LS - EF = 24 - 9 = 15
Activity D: ST = LS - EF = 20 - 13 = 7
Activity E: ST = LS - EF = 21 - 18 = 3
Activity F: ST = LS - EF = 22 - 17 = 5
Activity G: ST = LS - EF = 24 - 20 = 4
Activity H: ST = LS - EF = 23 - 23 = 0
Activity I: ST = LS - EF = 21 - 14 = 7
3. Identify the critical path:
The critical path consists of activities with zero slack time. In this case, the critical path includes activities A, B, C, F, G, and H.
4. Calculate the minimum project completion time:
Sum up the durations of the activities on the critical path to find the minimum time for completing the project.
Minimum Time = Duration of Activity A + Duration of Activity B + Duration of Activity C + Duration of Activity F + Duration of Activity G + Duration of Activity H
= 4 + 3 + 2 + 4 + 2 + 3
= 18 weeks
Therefore, the minimum time for completing the project is 18 weeks.
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If xy + 8e^y = 8e, find the value of y" at the point where x = 0. y" =
At the point where x = 0, the equation simplifies to 8e^y = 8e, which can be rearranged to e^y = 1. This means that y = 0.
1. Substitute x = 0 into the equation: xy + 8e^y = 8e
2. Simplify the equation: 8e^y = 8e
3. Rearrange the equation to isolate the exponent: e^y = 1
4. Take the natural logarithm of both sides: y = ln(1)
5. Evaluate the natural logarithm: y = 0
At the point where x = 0, the given equation simplifies to 8e^y = 8e. Rearranging this equation to isolate the exponent on the left hand side, we get e^y = 1. Taking the natural logarithm on both sides, we get y = ln(1). Finally, evaluating the natural logarithm of 1, we get y = 0. Therefore, the value of y" at the point where x = 0 is 0.
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Help Please! ( Geometry)
The two missing angles of the diagram are:
∠HDG = 117°
∠FDG = 180°
How to find the missing angle?We know that sum of angles on a straight line is 180 degrees.
We also know that two angles that sum up to 180 degrees are referred to as supplementary angles.
From the given image, we see that:
∠HDF is given as 63°.
Thus:
∠HDG = 180 - 63
∠HDG = 117°
Thus, it means that ∠FDG is 180 degrees
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Graph the line that represents the equation pls
Calculate the value of x
Answer:
13
Step-by-step explanation:
I hope it's visible enough. F is for frequency and I replaced the other one by x.
Consider the following 2 person, 1 good economy with two possible states of nature. There are two states of nature j € {1,2} and two individuals, i E {A, B}. In state- of-nature j = 1 the individual i receives income Yi, whereas in state-of-nature j = 2, individual i receives income y,2. Let Gij denote the amount of the consumption good enjoyed by individual i if the state-of-nature is j. State-of-nature j occurs with probability Tt; and 11 + 12 = 1. Prior to learning the state-of-nature, individuals have the ability to purchase or sell) contracts that specify delivery of the consumption good in each state-of-nature. There are two assets. Each unit of asset 1 pays one unit of the consumption good if the state- of-nature is revealed to be state 1. Each unit of asset 2 pays one unit of the consumption good in each state-of-nature. Let dij denote the number of asset j € {1,2} purchased by individual i. The relative price of asset 2 is p. In other words, it costs p units of asset 1 to obtain a single unit of asset 2 so that asset 1 serves as the numeraire (its price is normalized to one and relative prices are expressed in units of asset 1). Individuals cannot create wealth by making promises to deliver goods in the future so the total net expenditure on purchasing contracts must equal zero, that is, 0,,1 + po 2 = 0. Individual i's consumption in state-of-nature j is equal to his/her realized income, yj, plus the realized return from his/her asset portfolio. The timing is as follows: individuals trade in the asset market, and once trades are complete, the state-of-nature is revealed and asset obligations are settled. The individual's objective function is max {714(G,1)+12u(6,2)}. 1. Write down each individual's optimization problem. 2. Write down the Lagrangean for each individual. 3. Solve for each individual's optimality conditions. 4. Define an equilibrium. 5. Provide the equilibrium conditions that characterize the equilibrium allocations in the market for contracts. 6. Let the utility function u(e) = ln(c) so that u'(c) = . Solve for the equilibrium price and allocations.
Previous question
The optimization problem for individual A is to maximize their objective function: max {7A(GA1) + 12u(A,G2)}. The Lagrangean for individual A can be written as: L(A) = 7A(GA1) + 12u(A,G2) + λ1(IA1 - DA1) + λ2(IA2 - DA2) + μ1(IA1 - pIA2) + μ2(IA2 - IA1 - IA2).
To solve for individual A's optimality conditions, we take the partial derivatives of the Lagrangean with respect to the decision variables: ∂L(A)/∂GA1 = 0, ∂L(A)/∂GA2 = 0, ∂L(A)/∂IA1 = 0, and ∂L(A)/∂IA2 = 0.
An equilibrium is defined as a set of allocations (GA1, GA2) and prices (p) such that all individuals optimize their objective functions and markets clear, i.e., the total net expenditure on purchasing contracts is zero. The equilibrium conditions that characterize the equilibrium allocations in the market for contracts are: ∑AIA1 + ∑BIB1 = 0, ∑AIA2 + ∑BIB2 = 0, and IA1 + IB1 = IA2 + IB2.
Given the utility function u(e) = ln(c), we can solve for the equilibrium price and allocations by setting the optimality conditions equal to zero and solving the resulting system of equations.
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Two opposite sides of a parallelogram measure 5n-11 and 2n +22. Find the length of
each side.
Answer:
Both sides are 44
Step-by-step explanation:
5n - 11 = 2n + 22
5n - 2n = 22 + 11
3n = 33
n = 11
First Side
5n - 11 = 5 (11) - 11 = 55-11 = 44
Second Side
2n + 22 = 2 (11) + 22 = 44
PARALLEL PERPENDICULAR OR NEITHER OR SAME slope
Answer:
21. Same Line
22. Same Line
23. Perpendicular
24. Neither
25. Parallel
26. Neither
27. Neither
28. Neither
29. Perpendicular
30. Perpendicular
31. Neither
32. Perpendicular
33. Parallel
34. Perpendicular
35. Perpendicular (?)
36. Neither
37. Neither
38. Parallel
39. Neither
40. Parallel
Simplify the expression 4( m - 2 ) + 3m
Answer:
7m-8
Step-by-step explanation:
distribute 4 through the parentheses
4m-8+3m
collect like terms
7m-8
Answer:
7m-8
Step-by-step explanation:
So to simplify this expression, you would need to do distributive property.
4(m-2)
(4*m) + (4*-2)
4m-8+3m
7m-8
So your simplification is 7m-8
Extra Credit: A theorem states: \( \mathrm{F} \) is a Fibonacci number if and only if either \( 5 F^{2}+4 \) or \( 5 F^{2}-4 \) is a perfect square, test this theorem for the FNs (a) 8 and (b) 13
The theorem that states F is a Fibonacci number if and only if either 5 F2+4 or 5 F2−4 is a perfect square was tested for FNs 8 and 13. However, the theorem was not valid for either of these numbers.
We know that a sequence of numbers is called a Fibonacci series if the next number in the sequence is the sum of the two previous ones.
The first two numbers of the Fibonacci series are 0 and 1.
Hence, the third number is 0 + 1 = 1,
fourth number is 1 + 1 = 2,
fifth number is 1 + 2 = 3, and so on.
Let's test this theorem for the FNs (a) 8 and (b) 13.
We have to verify whether either 5 F^{2}+4 or 5 F^{2}-4 is a perfect square.
For FN = 8,
5F^{2}+4 = 5(8)^2+4 = 324 and 5 F^{2}-4 = 5(8)^2-4 = 316.
Neither of these is a perfect square.
Hence, the theorem is not valid for FN = 8.
For FN = 13,5
F^{2}+4 = 5(13)2+4 = 876 and 5 F^{2}-4 = 5(13)2-4 = 860.
Neither of these is a perfect square. Hence, the theorem is not valid for FN = 13.
Therefore, the theorem is not valid for FNs 8 and 13.
The theorem that states F is a Fibonacci number if and only if either 5 F2+4 or 5 F2−4 is a perfect square was tested for FNs 8 and 13. However, it was found that the theorem was not valid for either of these numbers.
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the coefficient on age shows that a. age has no association with ahe b. ahe increase by $0.605 for every one-year increase in age c. ahe increases by $6.05 for every one-year increase in age d. ahe increase by $0.0605 for every one-year increase in age
The correct answer is option b: ahe increases by $0.605 for every one-year increase in age.
Based on the given options, the coefficient on age indicates that ahe increases by $0.605 for every one-year increase in age. This means that as age increases by one year, ahe is expected to increase by $0.605.
Therefore, the correct answer is option b: ahe increases by $0.605 for every one-year increase in age.
- The coefficient on age suggests that there is a positive association between age and ahe.
- For every one-year increase in age, ahe is expected to increase by $0.605.
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Please please thank you
Answer:
option 2
452.16
You would need to use this equation...
V=πr²h
3.14 * (4)² * 9
= 452.16 cm³
Dispersion Calculate the i) dispersion relation, as well as both the ii) group and iii) phase velocities for the following equation: 82y(x, t) 8t2 84y(x,t) = -2 8x4
i) The dispersion relation for the given equation is ± (v / 6) * k.
ii) The group velocity for the given equation is ± v / 6.
iii) The phase velocity is ± v / 6.
To find the dispersion relation, as well as the group and phase velocities for the given equation, let's start by rewriting the equation in a standard form:
82y(x, t) - 8\(t^2\) + 84y(x,t) = -2 * 8\(x^4\)
Simplifying the equation further:
8(2y(x, t) - \(t^2\) + 4y(x,t)) = -16\(x^4\)
Dividing both sides by 8:
2y(x, t) - \(t^2\) + 4y(x,t) = -2\(x^4\)
Rearranging the terms:
6y(x, t) = \(t^2\) - 2\(x^4\)
Now, we can identify the coefficients of the equation:
Coefficient of y(x, t): 6
Coefficient of \(t^2\): 1
Coefficient of \(x^4\): -2
(i) Dispersion Relation:
The dispersion relation relates the angular frequency (ω) to the wave number (k). To determine the dispersion relation, we need to find ω as a function of k.
The equation given is in the form:
6y(x, t) = \(t^2\) - 2\(x^4\)
Comparing this with the general wave equation:
A * y(x, t) = B * \(t^2\) - C * \(x^4\)
We can see that A = 6, B = 1, and C = 2.
Using the relation between angular frequency and wave number for a linear wave equation:
\(w^2\) = \(v^2\) * \(k^2\)
where ω is the angular frequency, v is the phase velocity, and k is the wave number.
In our case, since there is no coefficient multiplying the y(x, t) term, we can set A = 1.
\(w^2\) = (\(v^2\) / \(A^2\)) * \(k^2\)
Substituting the values, we get:
\(w^2\) = (\(v^2\) / 36) * \(k^2\)
Therefore, the dispersion relation for the given equation is:
ω = ± (v / 6) * k
(ii) Group Velocity:
The group velocity (\(v_g\)) represents the velocity at which the overall shape or envelope of the wave propagates. It can be determined by differentiating the dispersion relation with respect to k:
\(v_g\) = dω / dk
Differentiating ω = ± (v / 6) * k with respect to k, we get:
\(v_g\) = ± v / 6
So, the group velocity for the given equation is:
\(v_g\) = ± v / 6
(iii) Phase Velocity:
The phase velocity (\(v_p\)) represents the velocity at which the individual wave crests or troughs propagate. It can be calculated by dividing the angular frequency by the wave number:
\(v_p\) = ω / k
For our equation, substituting the dispersion relation ω = ± (v / 6) * k, we have:
\(v_p\) = (± (v / 6) * k) / k
\(v_p\) = ± v / 6
Therefore, the phase velocity for the given equation is:
\(v_p\) = ± v / 6
To summarize:
(i) The dispersion relation is ω = ± (v / 6) * k.
(ii) The group velocity is \(v_g\) = ± v / 6.
(iii) The phase velocity is \(v_p\) = ± v / 6.
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Seven times the sum of a number and 3 is 9.
Answer: -1.71
7(x+3) = 9 is the equation
7x+21 = 9
7x = -12
x= -12/7
x= -1.71
2 apples cost 2 dabloons.
How much does 1 apple cost
Points for late night math helpers! Thank you guys :)
Min is using a model to add 3/10 and 4/10. First, he draws a rectangle and seperates it into 10 equal pieces. Then, he shades 3 of those pieces. What should Min do next?
Min is using a model to add 3/10 and 4/10. First, he draws a rectangle and separates it into 10 equal pieces. Then, he shades 3 of those pieces. To add 3/10 and 4/10 using a model,
Min should follow the steps below.
Step 1: Draw a rectangle and separate it into 10 equal pieces.
Step 2: Shade 3 pieces out of the 10 pieces.
Step 3: Shade an additional 4 pieces out of the remaining 7 unshaded pieces.
Step 4: Count the total number of shaded pieces, which is 7.
Step 5: Divide the total number of shaded pieces by the total number of pieces in the rectangle. This gives the fraction 7/10.
Step 6: Therefore, the sum of 3/10 and 4/10 is 7/10.
Min should shade an additional 4 pieces out of the remaining 7 unshaded pieces next to add 3/10 and 4/10 using a model.
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Carlos just took a 40 question math test. He scored a 75%. How many questions did he get correct?
Answer:
He missed 10 questions and got 30 right
Step-by-step explanation:
So we could do 0.75 times 40 and we would get 30
So he got 30 questions right which isn't too bad
How many 4-letter code words can be formed from the letters D, C, O, N, O, U if no letter is repeated? If letters can be repeated? If adjacent letters must be different? There are 30 possible 4-letter code words if no letter is repeated (Type a whole number)
Part 1:The letters available are D, C, O, N, O, U. Since no letter is repeated, we can use the rule of permutations to find the number of 4-letter code words that can be formed. The formula for the number of permutations of n distinct objects taken r at a time is: P(n, r) = n!/(n-r)!We have 6 distinct objects (letters) and we want to take 4 of them.
Therefore, the number of 4-letter code words that can be formed without any repetition is:P(6, 4) = 6!/(6-4)! = 6!/2! = 6*5*4*3 = 360So, there are 360 possible 4-letter code words that can be formed if no letter is repeated.Part 2:If letters can be repeated, then we can use the rule of permutations with repetition. The formula for the number of permutations of n objects taken r at a time, with repetition, is:n^rWe have 6 objects and we want to take 4 of them, with repetition.
Therefore, the number of 4-letter code words that can be formed with repetition is:6^4 = 6*6*6*6 = 1,296So, there are 1,296 possible 4-letter code words that can be formed if letters can be repeated. and then we must choose a different letter for the third position, and then we must choose a different letter for the fourth position. After that, we can repeat the cycle starting with the first letter againAdjacent letters must be different: There are 120 possible 4-letter code words that can be formed.
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Maria and jose students at mississippi valley state university are going to study aboard in spain they need to find the weight of their suitcases to make sure they meet airline regulations
Since they need to find the weight of their suitcases to make sure they meet airline regulations. the units that they should use Kg.
What unit is used to measure a suitcase?Airport passengers are often needed to put only at least a single baggage any time in the check-in self-service so that the baggage can be checked and identified.
Note that the Maximum Weight per piece is said to be 50 lb/23 kg and the Maximum Dimensions is said to be 45 linear inches or 115 cm (including the length + width + height)
Therefore, Since they need to find the weight of their suitcases to make sure they meet airline regulations. the units that they should use Kg.
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See full question below
Maria and Jose, students at Mississippi Valley State University, are going to study abroad in Spain. They need to find the weight of their suitcases to make sure they meet airline regulations. What units should they use?
Please, help me!!
My answer is
g: 43
h: 137
m: 49
K: 31
But I'm not sure.
Answer:
G is correct
H is correct
M is correct
K is 131
Step-by-step explanation:
Angles in a straight line add up to 180 degrees
Answer:
g: 43
h: 137
m: 49
K: 131
Step-by-step explanation:
i got it right
the expected frequencies in a chi-square test . a. are always whole numbers b. can contain fractions or decimal values c. can contain both positive and negative values d. can contain fractions and negative numbers
The expected frequencies in a chi-square test is can contain fractions or decimal values
What is Chi-Square Test?
When the sample sizes are large, a chi-squared test is a statistical hypothesis test used in the study of contingency tables. To put it another way, the main purpose of this test is to determine if two categorical factors have independent effects on the test statistic.
What is Expected Frequencies?
A theoretical frequency that we anticipate to show up in an experiment is known as an expected frequency.
Expected frequency = Expected percentage * Total count
The expected frequencies in a chi-square test is can contain fractions or decimal values
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I need the answer asapplease and thank you!!!
In mathematics, a line's slope, also known as its gradient, is numerical representation of line's steepness and direction. The equation will be \(y= \frac{-1}{3}x +5\).
What is a slope?In mathematics, a line's slope, also known as its gradient, is numerical representation of line's steepness and direction. The letter m is the frequently used to represent slope; the reason for this usage is unclear, although it can be found in O'Brien's (1844) and Todhunter's (1888) formulations of the equation for the straight line as "\(y = mx + b\)" and "\(y = mx + c\)," respectively.
The ratio of "vertical change" to "horizontal change" between the (any) two unique points on a line is used to compute slope. The ratio can also be written as a quotient ("rise over run"), which produces the same number for every two distinct points on the same line. A declining line has a negative "rise." The line might be useful, as determined by a road surveyor, or it might appear in a diagram that represents a road or a roof as a description or design.
Let, x= -3, x1= -2, y= 5, y1= 2
Then,
slope= \(\frac{x-x1}{y-y1} = \frac{-3-(-2)}{5-2} =\frac{-1}{3}\)
now,
y= mx+c
y= \(\frac{-1}{3}\)x+ 5
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