Answer:
Alpha particles are Helium nuclei consisting of 2 protons and two neutrons (mass number 4, atomic number 2, no electrons and so carry a 2+ charge).
Explanation:
You stand 300 cm away from a tuning fork with .0085 W of power. What is theintensity?
Given:
The distance from the tuning fork is d = 300 cm
The power is P = 0.0085 W
To find the intensity.
Explanation:
The intensity is defined as the power per unit area.
Wavelets are in the shape of sphere.
The intensity can be calculated by the formula
\(I=\frac{P}{4\pi d^2}\)On substituting the values, the intensity will be
\(\begin{gathered} I=\frac{0.0085}{4\times3.14\times(3)^2} \\ =\text{ 7.52}\times10^{-5}\text{ W/m}^2 \end{gathered}\)The intensity o
how long does it take to get to the titanic from the surface
Considering the depth and the speed, it would take approximately 2.5 to 3 hours to get to the Titanic from the surface.
The time it takes to get to the Titanic from the surface depends on various factors, such as the depth of the Titanic wreck and the speed of the vessel you are using to reach it. The Titanic is located approximately 12,500 feet (3,800 meters) below the surface of the ocean.
Assuming you are using a submarine or a deep-sea diving vessel, it typically takes around 2.5 to 3 hours to reach a depth of 12,500 feet. This is because these vessels generally have a cruising speed of about 4 to 5 knots (4.6 to 5.8 miles per hour).
Therefore, considering the depth and the speed, it would take approximately 2.5 to 3 hours to get to the Titanic from the surface.
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5). A body of mass 75kg lying on a surface of
μ = 0.4 move in the direction of a horizontal force
of 300N applied to it.
a). Calculate the
i). friction force
ii). acceleration of the body
b). Explain the result in aii).
Explanation:
a) i) Calculation of the friction force:
The friction force can be determined using the equation:
friction force = coefficient of friction * normal force
The normal force is equal to the weight of the object, which can be calculated as:
normal force = mass * gravitational acceleration
where the gravitational acceleration is approximately 9.8 m/s².
normal force = 75 kg * 9.8 m/s² = 735 N
friction force = 0.4 * 735 N = 294 N
ii) Calculation of the acceleration of the body:
Now, we can calculate the acceleration using Newton's second law:
net force = mass * acceleration
Since the applied force and the friction force act in opposite directions, the net force can be calculated as:
net force = applied force - friction force
net force = 300 N - 294 N = 6 N
mass = 75 kg
6 N = 75 kg * acceleration
acceleration = 6 N / 75 kg = 0.08 m/s²
b) Explanation:
In part (a), we calculated the friction force to be 294 N and the acceleration of the body to be 0.08 m/s². The positive acceleration indicates that the body is moving in the direction of the applied force.
The friction force opposes the motion of the body and acts in the opposite direction to the applied force. In this case, the applied force of 300 N is greater than the friction force of 294 N. As a result, the net force acting on the body is 6 N in the direction of the applied force.
The small net force of 6 N, compared to the body's mass of 75 kg, results in a relatively low acceleration of 0.08 m/s². This indicates that the body will accelerate slowly in the direction of the applied force due to the presence of friction.
Overall, the friction force and the resulting acceleration of the body are determined by the coefficient of friction (μ) and the mass of the object. In this case, the body experiences a relatively high friction force, leading to a small acceleration.
Si un conductor tiene una longitud de 4 metros y una sección de 2 mm^2 calcule su resistencia, si su coeficiente de resistividad es de 0.10(Ωmm^2/m)
Answer:
R = 0.2 Ω
Explanation:
Para aplicar el concepto de resistencia de un conductor electrico, consideramos la siguiente formula:
R = ρ . l / S
Donde l es la longitud del conductor
S la superficie
y ρ el coeficiente de resistividad
Primero necestiamos hacer ciertas conversiones:
ρ = 0.10 ×10⁻⁶ (Ω . m²/m)
S = 2 mm² → 2 ×10⁻⁶ m²
R = 0.10 ×10⁻⁶ (Ω . m²/m) . 4m / 2 ×10⁻⁶ m²
Dentro de la formula simplificamos las unidades, los metros de ρ con la longitud y ambos m². De esa forma la unidad de R queda en Ω (ohmios).
Resolvemos:
R = 0.10 ×10⁻⁶ Ω . 4 / 2 ×10⁻⁶
R = 0.2 Ω
A 9.0V battery supplies a 2.5mA current to a circuit for 5.0hr.
a.) How much charge has been transferred from the negative tothe positive terminal?
b.) How much work has been done on the charges that passedthrough the battery?
a.) To calculate the charge transferred from the negative to the positive terminal, we can use the formula Q = I x t, where Q is the charge, I is the current, and t is the time. In this case, the current is 2.5mA, which is 0.0025A, and the time is 5.0 hours, which is 18000 seconds. Therefore, Q = 0.0025 x 18000 = 45 C (Coulombs).
b.) To calculate the work done on the charges that passed through the battery, we can use the formula W = V x Q, where W is the work done, V is the voltage and Q is the charge. In this case, the voltage is 9.0V and the charge is 45 C, which we calculated in part a. Therefore, W = 9.0 x 45 = 405 J (Joules).
In summary, the charge transferred from the negative to the positive terminal of the 9.0V battery is 45 C and the work done on the charges that passed through the battery is 405 J.
Here's a step-by-step explanation for both parts:
a.) To find the charge transferred, we'll use the formula Q = I × t, where Q is the charge, I is the current, and t is the time.
1. Convert the given values to the appropriate units: Current (I) = 2.5 mA = 0.0025 A and Time (t) = 5.0 hr = 18000 s (since 1 hr = 3600 s).
2. Now, use the formula Q = I × t: Q = 0.0025 A × 18000 s = 45 C (Coulombs).
So, 45 Coulombs of charge have been transferred from the negative to the positive terminal.
b.) To find the work done, we'll use the formula W = Q × V, where W is the work, Q is the charge, and V is the voltage.
1. We already know Q = 45 C and V = 9.0 V.
2. Use the formula W = Q × V: W = 45 C × 9.0 V = 405 J (Joules).
So, 405 Joules of work have been done on the charges that passed through the battery.
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An electrical generating plant operates at a boiler temperature of 220°C and exhausts the unused heat into a nearby river at 18°C. What is the maximum theoretical efficiency of the plant? (0°C = 273 K)
The maximum theoretical efficiency of the plant is defined as η = 1 - T(cold) / T(hot). The maximum theoretical efficiency is 40.97% of the plant.
The theoretical maximum efficiency is Carnot's efficiency, defined as the heat engine traveling between two temperatures. T(hot) is the higher temperature and T(cold) is the lower temperature.
From the givens,
T(hot) = 220°C = 220+273 K = 493 K
T(cold) = 18°C = 18 + 273 K = 291 K
The maximum theoretical efficiency,
η = 1 ₋ T(cold) / T(hot)
= 1₋(291) / 493
= 493 ₋ 291 / 493
= 0.4097 ×100
= 40.97%
The maximum efficiency of the plant is 40.97 %.
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A car starts with velocity of 3m/s and moves in a straight line with a constant acceleration if the velocity at the end of 5sec is 5.5 m/s find the uniform acceleration and the distance travelled in 10sec
Answer:
\huge{\underline{\underline{.........Answer.........}}}
.........Answer.........
Given:-
u = 0.3 m/s
v = 5.5 m/s
t = 5 seconds
Explanation:-
Case-1
Acceleration = ?
From the first law of motion.
v = u + atv=u+at
a = \frac{v - u}{t}a=
t
v−u
a = \frac{5.5 - 0.3}{5}a=
5
5.5−0.3
a = \frac{5.2}{5}a=
5
5.2
a = 1.04a=1.04
\boxed{\boxed{a = 1.04 m/s^2}}
a=1.04m/s
2
So,the acceleration produced is 1.04 m/s^2.
Case-2
Distance travelled = ?.
From second equation of motion.
s = ut + \frac{1}{2} a {t}^{2}s=ut+
2
1
at
2
s = 0.3 \times 10 + \frac{1}{2} \times1.04 \times 100s=0.3×10+
2
1
×1.04×100
s = 3 + \frac{1}{2} \times 104s=3+
2
1
×104
s = 3 + 52s=3+52
s = 55 \: meterss=55meters
\boxed{\boxed{s = 55 meters}}
s=55meters
So,the distance travelled is 55 meters.
Explanation:
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What is a major difference between economic wants and economic needs? A- needs have a greater degree of scarcity than wants B- Needs are more important to survival than wants C- needs play a greater role in the economy then wants D- needs require more labor to satisfy than wants
Answer:
B because Needs are things that are essential to life but wants are just extra.
Explanation:
For example food and water is needed for life but a want would be to have the latest I phone
A major difference between economic wants and economic needs is: B- Needs are more important to survival than wants.
Economic wants can be defined as the goods and services that are desired by consumers but are not important for their survival. Some examples of economic wants are mobile phone, automobile cars, computer, clothes, television, furniture, etc.
Economic needs can be defined as the goods and services that are required by the people or consumers for their daily survival. Some examples of economic needs are: shelter, food, water, land, air, etc.
In conclusion, economic wants are less important because they are just our different desires in life but economic needs are very important and significant for the daily survival of humans because they are the basics of life.
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what is the resolution (in arcseconds) of a lens of diameter 100 cm?
A lens with a diameter of 100 cm has a theoretical resolution limit of about 0.011 arcseconds for visible light observations.
The resolution of a telescope or lens is determined by its aperture size and the wavelength of the observed light. The theoretical limit of resolution is given by the Rayleigh criterion, which states that the smallest angular separation between two objects that can be resolved is approximately equal to the wavelength of the observed light divided by the aperture diameter.
For a lens of diameter 100 cm, the resolution can be estimated as:
resolution = wavelength / aperture diameter
Assuming a typical visible light arcseconds of 500 nm (5 x 10^-7 m), we can convert this to arcseconds using the formula:
1 radian = 206265 arcseconds
Therefore, the resolution in arcseconds is:
resolution = (wavelength / aperture diameter) * (180 / pi) * 3600 * 206265
resolution = (5 x 10^-7 m / 100 m) * (180 / pi) * 3600 * 206265
resolution ≈ 0.011 arcseconds
So a lens with a diameter of 100 cm has a theoretical resolution limit of about 0.011 arcseconds for visible light observations.
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A bus accelerates at -0.5 m/s2 for 12.5 seconds . If the bus had an initial speed of 31 m/s, what is its new speed? A. 12.25m/s B. 37.25m/s C. 24.75m/s D. 6.25m/s
Answer:
37.5m/s
Explanation:
a=(v-u)/t
0.5 = (v - 31) / 12.5
v - 31 = 0.5 x 12.5
v - 31 = 6.25
V = 6.25 + 31
v = 37.25m/s
Inducing magnetic properties on a substance means you are
aligning the electrons to spin in the opposite direction
aligning the electrons to spin in the same direction
pairing up electrons to spin together
separating electrons to move freely in the substance
Inducing magnetic properties on a substance means you are aligning the electrons to spin in the same direction, 2nd option.
How are magnetic properties induced?The magnetic intensity is the magnetic field produced solely by the electric current flowing in a solenoid. The magnetic property of a material is induced by an external magnetic field. When a material is exposed to an external magnetic field, it becomes magnetized.
A strong magnetic field is produced when the majority of electrons in an atom spin in the same direction. The magnetic field's direction is determined by the direction of electron spin.
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which type of scale has all the properties of an interval scale with the additional attribute of representing absolute quantities, characterized by a meaningful absolute zero?
The type of scale that has all the properties of an interval scale with the additional attribute of representing absolute quantities, characterized by a meaningful absolute zero, is a ratio scale.
The type of scale that has all the properties of an interval scale with the additional attribute of representing absolute quantities, characterized by a meaningful absolute zero is a ratio scale. In a ratio scale, the values not only have an order and equal intervals but also a true, non-arbitrary zero point.
This means that ratios of values are meaningful, and one can meaningfully say that a value is, for example, twice or half of another value. Examples of ratio scales include measurements of weight, length, time, temperature in Kelvin, and counts of discrete objects. Ratio scales provide the most precise and informative type of measurement and are widely used in scientific and statistical analysis.
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An object is attached to a spring and experiences a restoring force of 50 N . The spring constant is found to be 150N/m. How far the object displaced from equilibrium?
Answer:
Photosynthesis is a process used by plants and other organisms to convert light energy into chemical energy that, through cellular respiration, can later be released to fuel the organism's activities.
Explanation:
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Ignore friction. A 20. Lb. Object was lifted to a height of 10 feet by a force of 30. Lb. (a) How much work (ft.Lb) is done by the force? (b) Find the change in potential energy (ft.Lb) of the object
(a) The work done by force in lb-ft is 300 lb-ft.
(b) The change in potential energy of the object is 200 lb-ft.
Work done by forceThe work done by force in lb-ft is calculated as follows;
W = Fd
W = 30 x 10
W = 300 lb-ft
Change in potential energyThe change in potential energy of the object is calculated as follows;
ΔP.E = P.Ef - P.Ei
ΔP.E = 20 x 10 - 0 = 200 lb-ft
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Which of ONE of the following four elements has the most metallic properties?
The atomic numbers of the elements are listed below.
12
14
16
17
Answer:
12 (Magnesium- Mg)
Explanation:
Looking at the four numbers, we have:
Magnesium, Silicon, Sulfur, and Chlorine.
We can eliminate two of the answers immediately just by looking at the periodic table.
Sulfur and Chlorine are on the nonmetal side of the periodic table. So that's definitely not it. That leaves Magnesium and Silicon.
Silicon is a Metalloid. Magnesium is an Alkaline earth Metal.
Metaloids are elements that have a mix of both metal and nonmetal properties (luster, how it feels, etc.). Since it's a MIX and Magnesium is just straight METAL-
We can say Magnesium has the most metallic properties.
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What is quantum tunneling
Quantum tunneling can be described as a quantum mechanical process where wavefunctions can penetrate through a potential barrier.
In which system Quantum tunneling can be observed?The transmission via the potential barrier can be finite and also depend upon the barrier width as well as barrier height. The wave functions have the probability of disappearing on one side and reappear on the remaining side.
The 1st derivative of the wave functions is generally continuous. In the steady state, the probability flux is spatially uniform and no wave or particle is eliminated. Tunneling can occur with barriers of thickness about 1 to 3 nm and smaller.
Quantum tunneling plays a crucial role in phenomena such as nuclear fusion and α-radioactive decay of atomic nuclei. Quantum tunneling has applications in the tunnel diode, in scanning tunneling microscope, and in quantum computing.
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Quantum tunneling is a phenomenon in quantum mechanics where wavefunctions can pass through a potential barrier. It is a process that defies classical physics, where particles would be expected to bounce back when they encounter a barrier.
In quantum mechanics, particles are described by wavefunctions, which are mathematical representations of their quantum states. These wavefunctions can extend into regions that are classically forbidden, such as inside a potential barrier.
The probability of a particle "tunneling" through the barrier depends on various factors, including the width and height of the barrier. The wavefunctions have a certain probability of disappearing on one side of the barrier and reappearing on the other side.
One important characteristic of quantum tunneling is that the first derivative of the wavefunctions is generally continuous. This means that there is a smooth transition between the regions before and after the barrier. In the steady state, the probability flux is spatially uniform, meaning that no waves or particles are lost during the tunneling process.
Quantum tunneling has significant implications in various areas of physics. It plays a crucial role in phenomena such as nuclear fusion and alpha-radioactive decay of atomic nuclei. It also has practical applications, such as in tunnel diodes, scanning tunneling microscopes, and quantum computing.
Quantum tunneling is a fascinating phenomenon in quantum mechanics where particles can pass through potential barriers that classical physics would consider impossible to overcome.
In classical physics, particles are confined to their energy levels and cannot pass through energy barriers unless they have enough energy to overcome them. However, in quantum mechanics, particles can exhibit wave-like behavior and their wavefunctions can extend beyond the physical boundaries we would expect them to be confined to.
When a particle encounters a potential barrier, there is a probability that its wavefunction can penetrate through the barrier and appear on the other side. This means that even if the particle does not have enough energy to overcome the barrier classically, there is still a chance that it can "tunnel" through the barrier and continue its motion on the other side.
The probability of tunneling depends on factors such as the width and height of the potential barrier. In some cases, the wavefunction can completely disappear on one side of the barrier and reappear on the other side.
Quantum tunneling is not limited to any specific system but can occur in a wide range of phenomena. It has been observed in nuclear fusion, where particles overcome the Coulomb repulsion barrier and fuse together. It also plays a role in the alpha decay of atomic nuclei. Additionally, quantum tunneling has practical applications in devices like tunnel diodes, which exploit this phenomenon to create unique electrical behavior.
Overall, quantum tunneling is a fundamental concept in quantum mechanics that allows particles to defy classical limitations and pass through barriers that would be impossible to overcome classically.
1. A ball is moving at 6 m/s and has a momentum of 24 kg-m/s. What is the ball's mass?
Answer:
4.0 kg
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How much work is done in lifting 30 kg of bricks to a height of 20 m?
Answer:
5,886 Joules or 5.886 KJ.
Explanation:
FORMULA IN FINDING WORK is
W = F x D
Where W is working;
F is force; and
D is distance
However, let us first discuss what work is.
When there is an object being moved by a force through a certain distance, the measure of energy transfer is what we call WORK.
One of the most common units used in work is JOULES (commonly used as a unit of energy). It is the work by which 1 Newton (1N = 1 kg.m/sec²) of force is used/expended through a distance of 1 meter (1m).
Refer to the problem.
It is said that the 30 kg set of bricks is to be raised to a height of 20 meters. As we see, there is no force given. But recall that force (F) is the product of the mass (m) of an object and its acceleration (a)
F = ma
However, in the formula, (g = 9.81 m/s²) or acceleration due to gravity is used in replacement of (a) because the object is moving upward.
So now we have
F = mg
Thus, we have the new work formula as
W = (mg)(D)
Substituting the given values, we have
W = (mg)(D)
W = (30kg)(9.81 m/s²)(20m)
W = 5,886 kg.m²/sec² or W = 5,886 Joules
The work done in lifting the bricks is 5,886 Joules or 5.886 KJ.
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when silk is rubbed with glass what silk is transferred?
Answer:
When glass rod is rubbed with silk clothes, glass quickly loses electrons, and silk takes electrons out of the glass rod
The following arbitrary measurements are made and the errors sited are the aximum errors A = 15.21 +0.01, B = 10.82 +0.05, C = 11.00+ 0.03. If D= A + B + C; (a) Calculate the maximum error in D. (b) if the errors sited are standard errors, calculate the standard error in D.
Maximum error in the result of the sum of measurement is equal to the sum absolute error of the individual observed measurements
(a) The maximum error in D is 0.09
(b) The standard error in D is approximately 0.034
The procedure for arriving at the above values is as follows;
The given measurements and the sited errors are;
A = 15.21 + 0.01
B = 10.82 + 0.05
C = 11.00 + 0.03
D = A + B + C
(a) Required parameter;
To calculate the maximum error in D
The equation for the propagation of error in addition is presented as follows;
Given that we have;
x = a + b
Therefore;
x + ±Δx = (a ± Δa) + (b ± Δb) = a + b ± (Δa + Δb)
∴ Δx = Δa + Δb
From the above formula, we have;
Where;
D = A + B + C
The maximum error in D = The sum of the maximum error in A, B, C
∴ The maximum error in D = 0.01 + 0.05 + 0.03 = 0.09
(b) Required parameter:
To find the standard error in D
The standard error is the sampling distribution's standard deviation, SD
Variance = SD²
The combined variance, SD² = The sum of the squares of individual standard deviations
Given that the standard errors represents the standard deviation, we get;
The combined variance, SD² = 0.01² + 0.05² + 0.03²
The combined variance, SD = √(0.01² + 0.05² + 0.03²) = 0.059
\(Standard \ error = \dfrac{SD}{\sqrt{n} }\)
Where n = 3, for the three measurement, we get;
\(Standard \ error = \dfrac{\sqrt{0.01^2 + 0.05^2 + 0.03^2} }{\sqrt{3} } \approx 0.034\)
The standard error in D is approximately 0.034
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a ball is thrown directly downward with an initial speed of 8.85 m/s, from a height of 29.9 m. after what time interval does it strike the ground?
It takes approximately 0.902 seconds time interval for the ball to strike the ground.
To determine the time interval it takes for the ball to strike the ground, we can use the equations of motion. Since the ball is thrown directly downward, we can assume that the initial velocity (u) is negative (-8.85 m/s), and the acceleration due to gravity (g) is positive (9.8 m/s²).
The equation to calculate the time of flight (t) is
t = (v - u) / g
Where:
v = final velocity (when the ball strikes the ground)
u = initial velocity
g = acceleration due to gravity
In this case, the final velocity when the ball strikes the ground is 0 m/s (as it comes to rest). So, substituting the given values into the equation, we have
t = (0 - (-8.85)) / 9.8
t = 8.85 / 9.8
t = 0.902 seconds
Therefore, it takes approximately 0.902 seconds for the ball to strike the ground.
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HELP ME 20 POINTS!!!Assume that the average volume of an adult human body is one-tenth
cubic meter (0.10 m) and that there are two billion (2.0 x 109)
adults in the world.
a. What would be the total volume of all the adults in the world?
b. Compute the length of one edge of a cubic container that has a
volume equal to the volume of all the adults in the world.
a). (2.0 x 10^9) x (0.1) = 2.0 x 10^8 cubic meters
b). The edge of a cube with that volume is
(2.0 x 10^8) ^ 1/3 = about 585 metres
(about 0.36 of a mile)
==> I'm pretty sure there are actually more than 2 billion adults in the world, since the total population is well over 7 billion now.
3 What is the displacement of a satellite when it makes a complete round along its circular path?
Answer:
0
Explanation:
The displacement is zero since it goes in a full circle and ends up where it started.
In this experiment, we could learn the difference between resistors in series and parallel. And we can see the relationship of the resistances, current and voltage in circuit which related to Ohm’s Law.
Introduction:
Ohm’s law is the most fundamental relationship between the quantities of electric potential (voltage), electric current, and resistance. It is valid for many circuits. When two or more devices are connected in a circuit with a variable power supply, they can be arranged in two different ways: a series connection or a parallel connection. In a series circuit, there is only one path for the current to flow therefore all parts of a series circuit have the same current. In a parallel circuit, each device has a connection to the power supply, independent of the other device. The current divides, with some passing through each parallel branch.
Equipments:
Ammeter, Resistors
Power supply, Ohmmeter
Voltmeter, Wires
Procedure:
Part I: Light Bulbs.
Series
Parallel
Connect 3 bulbs in series and set the power supply to 2.6 - 3.0V. We observed the brightness of the bulbs. Those light bulbs are very dim. Then we connect 3 bulbs in parallel and set the same voltage. Those light bulbs are very bright.
After this experiment, we can tell that 3 bulbs in series shared the voltage from the power supply therefore the brightness of 3 bulbs are dimmer than the brightness of 3 bulbs when we set in parallel connection. Voltage of 3 bulbs in parallel have the same voltage of each other and equal to the voltage from power supply.
Part II: Resistors in Series.
R1 R2 R3 Series
Set up the series circuit as shown. And then we set the power supply to ~ 15.0V so we can measure the current and the voltage of each resistor in the circuit.
Current
(A)
Voltage
(V)
Resistance
()
R1
0.032
3.50
109.4
R2
0.032
10.41
325.3
R3
0.032
1.06
33.1
Compare to the known resistances:
Experimental Result
Known Resistance
Percent Error
R1
109.4
100
9.4%
R2
325.3
330
1.4%
R3
33.1
33
0.3%
V = Vị + V + V3 = 3.50 + 10.41 + 1.06 = 14.97(V)
As we saw, the total voltage of 3 resistor equal to the voltage of the power supply (15V).
Resistors in Parallel.
R1 Parrallel
Set up the circuit in parallel as shown, set the power supply to ~5.0V
Current
(A)
Voltage
(V)
Resistance
()
R1
0.046
5.0
108.7
R2
0.015
5.0
333.3
R3
0.145
5.0
34.5
Compare to the known resistances:
Experimental Result
Known Resistance
Percent Error
R1
108.7
100
8.7%
R2
333.3
330
1.0%
R3
34.5
33
4.5%
I lit 12+ 13 = 0.046 + 0.015 + 0.145 = 0.206(A)
Is I =I1+I2+I3 ?
Yes, in a parallel circuit, the total current flowing through the circuit is equal to the sum of the current flowing through each individual resistor.
In this experiment, we learned the difference between resistors in series and parallel and their relationship to Ohm's Law. In a series connection, all components share the same current, while in a parallel connection, the current divides between components. We observed that light bulbs connected in series were dimmer compared to those in parallel due to voltage sharing.
By measuring current and voltage across resistors in series and parallel circuits, we compared experimental results to known resistance value and observed that total voltage in series equals the power supply voltage, and the sum of the currents in parallel equals the total current. This confirms the relationship of resistances, current, and voltage according to Ohm's Law.
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How many hours in 480 minutes?
480 minutes is equal to 8 hours.
Any specific period of time that is used to measure or represent duration on a regular basis is referred to as a unit of time.
The second, which is specified as about 9 billion oscillations of the caesium atom, is the fundamental unit of time in the International System of Units and, by extension, throughout the majority of the Western world.
There are 60 minutes in one hour. To convert minutes to hours, we can use the following formula:
Time in hours = Time in minutes ÷ 60
So, to find the number of hours in 480 minutes, we can plug in the values into the formula:
Time in hours = 480 minutes ÷ 60
Time in hours = 8 hours
Therefore, there are 8 hours in 480 minutes.
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A car goes from rest to 25 m/s in 10 seconds. Determind the acceleration of the car.
Answer:
2.5m/s^2
Explanation:
a=velocity/time
a=25m/s/10s
a=2.5m/s^2
when heated the temperature of a water sample increased from 15°C to 39°C. Is absorbed 41840 joules of heat. what is the mass of the sample
Answer:
Mass of water: 43 g
Explanation
hope it helps
1. When building a house using bricks a damp course is laid just above the brick foundation. Explain why the damp course is necessary
Answer:
Damp Proofing:
Explanation:
The presence of damp proofing is very necessary to maintain the health of a structure. DPC plays an important role in all types of buildings and it should be necessary to know about the importance, requirements, and properties of DPC. In many of the buildings all over the world, the rising damp may be due to a damaged damp-proof course, or sometimes, there may be not any damp proof course in a building.
A hiker walks 5.0 kilometers due north for twenty minutes. He turns due west and travels 12 kilometers in 60 more minutes. Then he walks 7.0 kilometers due north in forty minutes. What is the average speed of the hiker when traveling north?
Answer:
The hikers average speed due north is 0.2 km per minute.
Explanation:
Speed is the ratio of distance moved by a body to the time taken.
i.e speed = \(\frac{distance}{time}\)
Since the hiker walks due north and due west, then his average speed due north can be determined by;
Average speed = \(\frac{total distance due north}{total time taken}\)
Total distance due north = 5.0 + 7.0
= 12.0 km
Total time taken = 20 + 40
= 60 minutes
= 1 hour
Average speed due north= \(\frac{12}{60}\)
= \(\frac{1}{5}\)
= 0.2
Average speed due north = 0.2 km/minute
The hikers average speed due north is 0.2 km per minute.
What is the energy conversion in an incandescent lightbulb?
Answer:
An incandescent bulb use electrical energy
Explanation: