What is angle m 2 ? What is angle m 1?

The total income and expenditure of Agri-small business limited in September is R 299596 and expenditure is R 193236.

Given that the expenses on petrol be R4850.00 at the end of September, balance is R 106360.00, usage on income of salaries be 25%, on electricity,rates and taxes be 11%, 42% of the remaining on insurance and investments.

We are required to find the total income and expenditure in September.

Generally the equation for insurance is mathematically given as :

Insurance=42% of the balance

Insurance=0.42*0.64A

Insurance=0.2688A.

Generally the equation for the total after all the other expenditures is mathematically given as:

Total expenditure after all other expenditures=0.64A-0.2688A

Total expenditures after all other expenditures=0.3712A.

Total expenditures after all other expenditures is as 111210 (106360+4850)

Equating both the equation and value:

111210=3712A

A=299596

The total income is 299596.

Therefore the calculation of expense is given as:

Expense=0.25A+0.11A+0.2688A+4850

Expense=0.6288A+4850

=0.6288*299596+4850

=193236

The expense is 193236.

Hence the total income and expenditure in September are "Income is R 299596 and expenditure is R 193236.

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The total income and expenditure of Agri-small business limited in September is R 299596 and expenditure is R 193236.

We have to find the total income and expenditure in September.

The equation for insurance is mathematically given as :

Insurance = 42% of the balance

Insurance=0.42*0.64A

Insurance=0.2688A.

Total expenditure after all other expenditures = 0.64A-0.2688A

Total expenditures after all other expenditures = 0.3712A.

Total expenditures after all other expenditures is as 111210 (106360 +4850)

Equating both the equation and value:

111210 = 3712 A

A = 299596

Thus The total income is 299596.

Therefore the calculation of expense is given as:

Expense=0.25A+0.11A+0.2688A+4850

Expense=0.6288A+4850

=0.6288*299596+4850

=193236

The expense is 193236.

Hence, the total income and expenditure in September are "Income is R 299596 and expenditure is R 193236.

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The prime factorization of the number 21 is:

21 = 3*7

We want to write the prime factorization of 21.

To do so, we just need to divide the number by prime numbers.

The first prime number we can try is 2, if we divide by 2 we get:

21/2 = 10.5

This is not an integer, so 2 is not a factor.

The next one is 3:

21/3 = 7

Now we can rewrite:

21 = 3*7

Where 3 and 7 are prime numbers, so that is the prime factorization.

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The probability of the second die landing on any number is 1/6. This is because there are six possible outcomes on a fair die (1, 2, 3, 4, 5, 6) and each outcome is equally likely. Therefore, the probability of the second die landing on any given number is 1/6.

To calculate the probability of the second die landing on a specific number, you can use the formula P(A) = number of favorable outcomes / number of possible outcomes. In this case, the number of favorable outcomes is 1 (since there is only one number that you want the second die to land on) and the number of possible outcomes is 6 (since there are six possible numbers that the second die can land on). Therefore, the probability of the second die landing on a specific number is 1/6.

In conclusion, the probability of the second die landing on any number is 1/6 and the probability of the second die landing on a specific number is also 1/6.

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The probability that he misses the train today is 0.135 or 13.5%.

P(Class runs late)=30%=0.30

P(Miss train ∣ Class runs late)=45%=0.45

General multiplication rule:

P(A and B)=P(A)×P(B ∣ A)

Using the general multiplication rule, we then obtain (and using that the student always catches his train if the class ends on time) :-

P( Miss train)=P( Miss train and Class runs late)=P(Class runs late)×P(Miss train ∣ Class runs late)

= 0.30×0.45

= 0.135

= or 13.5%.

So, the the probability that he misses the train today is 0.135 or 13.5%.

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Answer:

7.63*10^5

Step-by-step explanation:

The number of seniors that are in the school is 240.

The first step is to determine the number of seniors that prefer gym equipment.

Let:

number of students that prefer gym equipment = x

total number of seniors = number of students that prefer gym equipment + number of seniors that prefer computer

= 160 + x

probability that a senior prefers gym equipment = 1/3

[x / (160 + x)] = 1/3

In order to determine the value of x, take the following steps:

Multiply both sides of the equation by 3.

3x = 160 + x

Combine and add similar terms:

3x - x = 160

2x = 160

x = 160 / 2

x = 80

Total number of seniors = 160 + 80 = 240

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Using the limit definition we cannot determine the derivative at this point. The derivative may still exist at other points, but it is not defined at x = 8.

To obtain the derivative of f(x) = √(8 - x) using the limit definition, we start by applying the definition of the derivative:

f'(x) = lim(h→0) [f(x + h) - f(x)] / h

Substituting the function f(x) = √(8 - x) into the equation, we have:

f'(x) = lim(h→0) [√(8 - (x + h)) - √(8 - x)] / h

Next, we simplify the expression inside the limit:

f'(x) = lim(h→0) [(√(8 - x - h) - √(8 - x)) / h]

Multiply the numerator and denominator by the conjugate of the numerator  to eliminate the square root

f'(x) = lim(h→0) [(√(8 - x - h) - √(8 - x)) / h] * [(√(8 - x - h) + √(8 - x)) / (√(8 - x - h) + √(8 - x))]

Expanding and simplifying the numerator, we get:

f'(x) = lim(h→0) [(8 - x - h) - (8 - x)] / (h * (√(8 - x - h) + √(8 - x)))

This simplifies to:

f'(x) = lim(h→0) [-h / (h * (√(8 - x - h) + √(8 - x)))]

Canceling out the "h" in the numerator and denominator, we have:

f'(x) = lim(h→0) [-1 / (√(8 - x - h) + √(8 - x)))]

Taking the limit as h approaches 0, we get:

f'(x) = -1 / (√(8 - x) + √(8 - x))

Simplifying further by multiply the numerator and denominator by the conjugate of the denominator

f'(x) = -1 * (√(8 - x) - √(8 - x)) / [(√(8 - x) + √(8 - x)) * (√(8 - x) - √(8 - x))]

This simplifies to:

f'(x) = -√(8 - x) + √(8 - x) / (8 - x - (8 - x))

Finally, we have:

f'(x) = -√(8 - x) + √(8 - x) / 0

Since the denominator is 0, we cannot determine the derivative at this point using the limit definition.

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Answer:

if ur going left to right it would be d

Step-by-step explanation:

Step-by-step explanation:

subrated it's -7/12 tell me if u want sreps

Answer:

Step-by-step explanation:

finding the smallest possible distance from the line to the origin follows as

the normal vector=(-1,-2,1)

using direction vector we need to create the equation of the plane

-1(x-2)-2(y-3)+1(z+7)=0

we get;

-x+2-2y+6+z+7=0

-x-2y+z+13=0

x=2-t; y=2-3t; z=-7+t

on substituting;

-1(2-t)-2(3-2t)+1(-7+t)+13=0

-2+t-6+4t-7+t+13=0

we get;

t=1

so point is(1,1,-6)

distance from point to origin

d=\(\sqrt{(1^2+1^2+(-6)^2)}\)=\(\sqrt{38}\)

therefore

the answer is \(\sqrt{38}\)=6.16

Answer:

I want to say C

Figure jkl is simular to fugure jkl :)

Answer:

0.001

Step-by-step explanation:

Given (or we can find) :

First term : 216

Common ratio : 36/216 = 1/6

To find 8th term :

a₈ = ar⁸⁻¹

a₈ = (216)(1/6)⁷

a₈ = 216/279936

a₈ = 6³/6⁷

a₈ = 1/6⁴

a₈ = 1/1296

a₈ = 0.000771604938

a₈ = 0.001 (nearest thousandth)

Answer:

Step-by-step explanation:

well it  decides  on your parents but yeah tai is right pg 13 means 13 years old and.

TAI IS CORRECT BECUASE PG-13: Parents Strongly Cautioned, Some Material May Be Inappropriate for Children Under 13. This rating is a stronger caution for parents that content included may not be appropriate for children under 13 (pre-teen ages). This may include stronger language, extended violence or sexual situations and drug-use, and sex

13×4=52

Ok Multiplacation is a simple Math formula everyone can do so you have to do this:

13+13+13+13=52

Now do this:

13×4=52

Answer is 52

Based on Kamila's description, the dot plot that matches her description is Dot plot 1.

The presence of an outlier and the right-skewed distribution can be inferred from the high frequency of data points on the left side of the plot and the single data point that is much larger than the others on the right side.

What is frequency of dot plot?

The frequency in a dot plot refers to the number of dots or data points that appear in a particular bin or category. In a dot plot, each dot typically represents one data point, and the frequency of the dot is the number of data points that have that value. For example, if a dot plot shows the heights of students in a class, with bins for each inch, then the frequency of a particular bin would be the number of students whose height falls within that bin. The frequency can be represented by the number of dots in that bin or by a numerical value.

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I don't think I need to explain it, the answer is $111

Answer: $111

Step-by-step explanation:

Answer:

Step-by-step explanation:

6+4=10

10/2

answer =5

area = = a² * sin(β) * sin(γ) / (2 * sin(β + γ))

The solution to the systems of inequalities graphically is shaded S

From the question, we have the following parameters that can be used in our computation:

2x + 3y < 9

2y ≥ 4x + 6

Next, we plot the graph of the system of the inequalities

See attachment for the graph

From the graph, we have solution to the system to be the shaded region

This region is labelled S

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9514 1404 393

Answer:

Step-by-step explanation:

Let b represent the speed of runner B. then the ratio of speeds is ...

  b/(b+5) = 8/18

  18b = 8(b +5) . . . . cross multiply

  10b = 40 . . . . . . . . subtract 8b

  b = 4 . . . . . . . . . . . divide by 10

Runner B's speed is 4 mph; runner A's speed is 5 mph more.

Runner A is running at 9 mph; Runner B is running at 4 mph.

1. The all possible divisions of s, there exists a value k such that xy⁰z is not in L₁,  Hence, L₁ is not regular.

2.The all possible divisions of s, there exists a value k such that xy⁰z is not in L₂. Hence, L₂ is not regular.

3.The all possible divisions of s, there exists a value k such that xy⁰z is not in L₃,  Hence, L₃ is not regular.

4.The all possible divisions of s, there exists a value k such that xy⁰z is not in L₄, Hence, L₄ is not regular.

Let's use the pumping lemma to prove that L₁ = {0ⁿ1ⁿ2ⁿ | n ≥ 0, Σ = {0, 1, 2}} is not regular.

Suppose L₁ is regular and let p be the pumping length of L₁. Consider the string s = 0ᵖ1ᵖ2ᵖ. Since s is in L₁ and |s| ≥ p, according to the pumping lemma, s can be divided into three parts: s = xyz, where |xy| ≤ p, |y| > 0, and for all k ≥ 0, xyᵏz is in L₁.

Let's consider the possible divisions of s into x, y, and z:

If y contains only 0s or 1s, then pumping y will break the balance between the number of 0s, 1s, and 2s. Therefore, xy⁰z will not have an equal number of 0s, 1s, and 2s, violating the condition of L₁.

If y contains both 0s and 1s, pumping y will either increase the number of 0s or 1s in xy⁰z. Thus, xy⁰z will not have an equal number of 0s, 1s, and 2s, violating the condition of L₁.

If y contains only 1s or 2s, pumping y will either increase the number of 1s or 2s in xy⁰z. Thus, xy⁰z will not have an equal number of 0s, 1s, and 2s, violating the condition of L₁.

Let's use the pumping lemma to prove that L₂ = {ωωω | ω ∈ {a, b}*} is not regular.

Suppose L₂ is regular and let p be the pumping length of L₂. Consider the string s = aᵖbᵖaᵖbᵖaᵖbᵖ, where p is the pumping length. Since s is in L₂ and |s| ≥ p, according to the pumping lemma, s can be divided into three parts: s = xyz, where |xy| ≤ p, |y| > 0, and for all k ≥ 0, xyᵏz is in L₂.

Let's consider the possible divisions of s into x, y, and z:

If y contains only a's, then pumping y will either increase the number of a's in xy⁰z or break the balance of the number of a's, b's, and a's in xy⁰z. Thus, xy⁰z will not be of the form ωωω, violating the condition of L₂.

If y contains only b's, then pumping y will either increase the number of b's in xy⁰z or break the balance of the number of a's, b's, and a's in xy⁰z. Thus, xy⁰z will not be of the form ωωω, violating the condition of L₂.

If y contains both a's and b's, then pumping y will either increase the number of a's or b's in xy⁰z. Thus, xy⁰z will not be of the form ωωω, violating the condition of L₂.

Let's use the pumping lemma to prove that L₃ = {ωωᴿβ | ω, β ∈ {0, 1}⁺} is not regular.

Suppose L₃ is regular and let p be the pumping length of L₃. Consider the string s = 0ᵖ1ᵖ0¹1¹, where p is the pumping length. Since s is in L₃ and |s| ≥ p, according to the pumping lemma, s can be divided into three parts: s = xyz, where |xy| ≤ p, |y| > 0, and for all k ≥ 0, xyᵏz is in L₃.

Let's consider the possible divisions of s into x, y, and z:

If y contains only 0s, then pumping y will either increase the number of 0s in xy⁰z or break the reversal of the first ω and the second ωᴿ in xy⁰z. Thus, xy⁰z will not be of the form ωωᴿβ, violating the condition of L₃.

If contains only 1s, then pumping y will either increase the number of 1s in xy⁰z or break the reversal of the first ω and the second ωᴿ in xy⁰z. Thus, xy⁰z will not be of the form ωωᴿβ, violating the condition of L₃.

If y contains both 0s and 1s, then pumping y will either increase the number of 0s or 1s in xy⁰z. Thus, xy⁰z will not be of the form ωωᴿβ, violating the condition of L₃.

Let's use the pumping lemma to prove that L₄ = {1ⁱ0ʲ1ᵏ | i > j and i > k > 0} is not regular.

Suppose L₄ is regular and let p be the pumping length of L₄. Consider the string s = 1ᵖ0ᵖ1²ᵖ, where p is the pumping length. Since s is in L₄ and |s| ≥ p, according to the pumping lemma, s can be divided into three parts: s = xyz, where |xy| ≤ p, |y| > 0, and for all k ≥ 0, xyᵏz is in L₄.

Let's consider the possible divisions of s into x, y, and z:

If y contains only 1s, then pumping y will either increase the number of 1s in xy⁰z or break the inequality i > j in xy⁰z. Thus, xy⁰z will not satisfy the condition i > j, violating the condition of L₄.

If y contains only 0s, then pumping y will either increase the number of 0s in xy⁰z or break the inequality i > k in xy⁰z. Thus, xy⁰z will not satisfy the condition i > k, violating the condition of L₄.

If y contains both 1s and 0s, then pumping y will either increase the number of 1s or 0s in xy⁰z. Thus, xy⁰z will not satisfy the conditions i > j and i > k, violating the condition of L₄.

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Answer: b) 4lb

Step-by-step explanation:

Answer:Your answer is B

Step-by-step explanation:

64 oz is= to 4 lb

Step-by-step explanation:

The centre which is the mid point is x1 + X2/2. and y1+y2/2

which give -4+8/2 =2 i.e X= 2

and 9+(-7)/2 = 9-7/2 = 1

therefore, the centre is (2,1)

the radius is √x2-x1)^2 + (y2-y1)^2

= √-4-2)^2+(9-1)^2

=√36+64 =√100

= 10 units

The set of all possible outcomes is called the sample space. Thus in the context of a random experiment, the sample space is our universal set.

A sample space is a set of potential results from a random experiment. The letter "S" is used to denote the sample space. Events are the subset of possible experiment results. Depending on the experiment, a sample area could contain a variety of results.

The set of all potential outcomes or results of an experiment or random trial is referred to as the sample space in probability theory. The potential ordered outcomes, or sample points, are listed as elements in a set that is used to represent a sample space.

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Based on the information provided, it seems that you are encountering some issues with a module called "binary_finder."

The phrase "content loaded" suggests that you have loaded some content, possibly related to this module. "Binary not linear" indicates that the nature of the content or code you're dealing with is binary, which means it consists of zeros and ones.

You mentioned having two pictures, one showing the question code and another displaying an answer from Chegg, which you find insufficient. However, the actual content of those pictures was not provided. If you can share the code or describe the specific problem you're facing with the binary_finder module, I'll be happy to assist you further.

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To find the inverse function of F(x) = 2x - 3, we replace F(x) with y, swap the positions of x and y, and solve for y. The inverse function is f⁻¹(x) = (x+3)/2.

To find the inverse function of F(x) = 2x - 3, follow these steps

Replace F(x) with y. The equation now becomes y = 2x - 3.

Switch the positions of x and y, so the equation becomes x = 2y - 3.

Solve for y in terms of x. Add 3 to both sides: x + 3 = 2y.

Divide both sides by 2 (x + 3)/2 = y.

Replace y with the notation for the inverse function, f⁻¹(x): f⁻¹(x) = (x + 3)/2.

So, the inverse function of F(x) = 2x - 3 is f⁻¹(x) = (x + 3)/2.

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--The given question is incomplete, the complete question is given

" How do I find the inverse function of F(x) = 2x - 3"--

The Solution.

Writing the above equation in index form, we have

The Fourier series representation of the output \(y(t)\) for different inputs can be found by convolving the input signal with the impulse response \(h(t)\).

For the given input \(x(t) = 1\), the output can be found by convolving \(x(t)\) with \(h(t)\). The Fourier series representation of the output can be obtained by taking the Fourier transform of the convolved signal.

Since \(h(t)\) is an even function, the Fourier transform of \(h(t)\) is a real and even function. Thus, the Fourier series representation of the output will only contain cosine terms.

To calculate the Fourier series coefficients, we need to find the integral of the product of the impulse response and the cosine functions.

Using the property that \(\cos(at)\) is even and \(\int_{-\infty}^{\infty} \cos(at) \, dt = \pi \delta(a)\), where \(\delta\) is the Dirac delta function, we can simplify the calculation.

By evaluating the integrals, we can determine the values of the Fourier series coefficients, and thus, obtain the Fourier series representation of the output \(y(t)\).

In summary, to find the Fourier series representation of the output \(y(t)\) for the given inputs, we need to convolve the inputs with the impulse response \(h(t)\), calculate the Fourier series coefficients using the properties of even functions and the Dirac delta function, and then express the output in terms of the cosine terms.

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The height of 13 DVD cases is 273 mm.

Given that, the height of 6 DVD cases is 126 mm.

Proportional relationships are relationships between two variables where their ratios are equivalent. Another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other. That constant is known as the "constant of proportionality".

Let x be the height of 13 DVD cases.

So, 6 : 126 :: 13 : x

⇒ 6x =126×13

⇒ x= 21×13

⇒ x= 273 mm

Hence, the height of 13 DVD cases is 273 mm.

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