What is an angle that is supplementary to FGA? ​

Answer

Area of the real dining hall = 72 m²

Explanation

The area of any rectangular shape is given as

Area = L × W

where

L = Length of the rectangle

W = Width of the rectangle

For this question, we have been given the dimensions of the dining hall in the drawing and told that

5 cm in the drawing = 6 m in reality

So, if the real length of the dining is L

5 cm = 6 m

10 cm = L

We can write a mathematical relationship by cross multiplying

(5) (L) = (10) (6)

5L = 60

Divide both sides by 5

(5L/5) = (60/5)

L = 12 m

If the real width of the dining hall is W

5 cm = 6 m

5 cm = W

We can write a mathematical relationship by cross multiplying

(5) (W) = (5) (6)

5W = 30

Divide both sides by 5

(5W/5) = (30/5)

W = 6 m

So, for the real dining hall,

Length = 12 m

Width = 6 m

Area = Length × Width

Area = 12 × 6

Area = 72 m²

Hope this Helps!!!

5 weeks -> $20

Divide 5:

1 week -> $4

Replace week with "w" and $ with "s"

\(w=4s\)

Answer: 6x + 2y

Step-by-step explanation:

Answer:

work is shown and pictured

The set of ordered pairs of A and C represents a linear function.

The graph of a linear function is a straight line. The following is the form of a linear function.

a + bx = y = f(x).

One independent variable and one dependent variable make up a linear function. x and y are the independent and dependent variables, respectively.

Given ordered pairs:

A (-2,8) (0,4) (2,3) (4,2)

B (1,2) (1,3) (1,4) (1,5)

C (-2,7) (0,12) (2,17) (4,22)

D (3,5) (4,7) (3,9) (5,11)​

The definition of a linear function is the relationship between input and output values.

Range refers to the set of output values, and domain refers to the set of input values.

The fact that an input value cannot have two different output values is the most significant attribute of functions (which defines them). Having stated so, observe how sets B and D include pairings that defy this rule.

Therefore, since each input value only produces one output value, the correct solutions are A and C.

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The complete question:

Which set of ordered pairs X Y could represent a linear function of x

A (-2,8) (0,4) (2,3) (4,2)

B (1,2) (1,3) (1,4) (1,5)

C (-2,7) (0,12) (2,17) (4,22)

D (3,5) (4,7) (3,9) (5,11)​

The value of the given expression  15.75 / (p +3p) for p = 3.15 will be 1.25.

An expression is a combination of some mathematical symbol such that an arithmetic operator and variable such that are all constrained and create an equation.

In other meaning, expression is very useful to determine the end or root value of constraint.

As per the given expression,

15.75 / (p +3p)

Put p = 3.15

15.75/(3.15 + 3 x 3.15) = 1.25

Hence "For p = 3.15, the value of the provided expression 15.75 / (p + 3p) will be 1.25".

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The correct answer to the question is b. Congruent figures.

Congruent figures are figures that have the same size and shape. In other words, if you were to compare two congruent figures, they would be identical in every way. This means that all corresponding sides and angles of the figures are equal.

For example, if you have two triangles that are congruent, their corresponding sides and angles will be equal. So if one triangle has a side length of 5 cm, the corresponding side of the other triangle will also have a length of 5 cm. Similarly, if one angle in one triangle measures 60 degrees, the corresponding angle in the other triangle will also measure 60 degrees.

It's important to note that congruence applies to all types of figures, including triangles, quadrilaterals, circles, and so on. When determining if two figures are congruent, you need to compare their corresponding sides and angles.

To summarize, figures that have the same size and shape are called congruent figures.

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The solution to the Laplace equation V²u = 0 with the given function f(θ) as \(u(r, \theta) = \sum[0 * r^\lambda+ (100 * \sqrt{2}) * r^{(-\lambda)}][Ccos(\lambda\theta) + Dsin(\lambda\theta)]\)

To solve the Laplace equation V²u = 0 with the given boundary condition u(1, θ) = f(θ), where f(θ) is defined as:

f(θ) = \(\left \{ {100 {if} 0 \leq \theta < \pi/4} \atop {0 if \pi/4 < \theta < 0}} \right}} \right.\)

We will use separation of variables to find the solution. Let's assume the solution can be written as u(r, θ) = R(r)h(θ), where R(r) represents the radial component and h(θ) represents the angular component.

Using separation of variables, we can write the Laplace equation as:

\((1/r)(d/dr)(r(dR/dr)) + (1/r^2)(d^2h/d\theta^2) = 0\)

To separate the variables, we set each term equal to a constant, denoted by -λ²:

\((1/r)(d/dr)(r(dR/dr)) = \lambda^2 (1)\)

\((1/r^2)(d^2h/d\theta^2) = -\lambda^2 (2)\)

Solving equation (1), we obtain the radial equation:

\(r(d^2R/dr^2) + (dR/dr) - \lambda^2R = 0\)

This is a standard differential equation with solutions of the form \(R(r) = Ar^{\lambda} + Br^{-\lambda}\), where A and B are constants.

Solving equation (2), we obtain the angular equation:

d²Θ/dθ² + λ²Θ = 0

This is a standard differential equation with solutions of the form

Θ(θ) = Ccos(λθ) + Dsin(λθ), where C and D are constants.

Now, we can combine the radial and angular components to form the general solution:

\(u(r, \theta) = \sum[Ar^\lambda + Br^{-\lambda}][Ccos(\lambda\theta) + Dsin(\lambda\theta)]\)

Next, we apply the boundary condition u(1, θ) = f(θ):\(u(1, \theta) = \sum[Ar^\lambda + Br^{-\lambda}][Ccos(\lambda\theta) + Dsin(\lambda\theta)] = f(\theta)\)

Comparing the terms on both sides, we can determine the coefficients A, B, C, and D using the given function f(θ).

To solve these equations, we'll use trigonometric identities and properties. Let's begin with the first equation:

\(Acos(\lambda\theta) + Bsin(\lambda\theta) = 100\)

We can rewrite this equation using the identity sin(π/4) = cos(π/4) = \(\sqrt2\):

\(Acos(\lambda\theta) + Bsin(\lambda\theta) = 100\)

(A/\(\sqrt2\) ) * \(\sqrt2\)  * cos(λθ) + (B/\(\sqrt2\) ) * \(\sqrt2\) * sin(λθ) = 100

Now, we can equate the coefficients of cos(λθ) and sin(λθ) separately to determine A and B. Since cos(λθ) and sin(λθ) are orthogonal functions, their coefficients must be zero:

(A/\(\sqrt2\)) * \(\sqrt2\) = 0 (coefficient of cos(λθ))

(B/\(\sqrt2\)) * \(\sqrt2\)= 100 (coefficient of sin(λθ))

From the first equation, we can conclude that A = 0. Substituting this into the second equation:

(B/\(\sqrt2\)) * \(\sqrt2\) = 100

B = \(\sqrt2\) * 100

B = 100 * \(\sqrt2\)

Therefore, we have A = 0 and B = 100 * \(\sqrt2\).

For the interval π/4 < θ < 2π, we have:

\(Acos(\lambda\theta) + Bsin(\lambda\theta) = 0\)

Again, equating the coefficients of cos(λθ) and sin(λθ) separately:

\(Acos(\lambda\theta) + Bsin(\lambda\theta) = 0\)

A * 0 + B * 1 = 0

B = 0

From this equation, we conclude that B = 0.

To summarize, we found A = 0, B = 100 * \(\sqrt2\) for the interval 0 ≤ θ < π/4, and B = 0 for the interval π/4 < θ < 2π.

Using these coefficients, we can now write the solution to the Laplace equation V²u = 0 with the given function f(θ) as:

\(u(r, \theta) = \sum[0 * r^\lambda+ (100 * \sqrt{2}) * r^{(-\lambda)}][Ccos(\lambda\theta) + Dsin(\lambda\theta)]\)

Therefore, the solution to the Laplace equation V²u = 0 with the given function f(θ) as \(u(r, \theta) = \sum[0 * r^\lambda+ (100 * \sqrt{2}) * r^{(-\lambda)}][Ccos(\lambda\theta) + Dsin(\lambda\theta)]\)

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A formula one race car will travel for 193.45 miles before changing its tires.

From the case, we know that:

tires diameter = 26 in.

1 set of tires = 150,000 rotations

12 in = 1 ft

1 miles = 5280 ft

We need to find the circumference of the tires before finding the total travel length.

Circumference = πd

Circumference = π(26in)

Circumference = 81.714 in.

We need to find the tires circumference in mile scale:

Circumference = 81.714 in : (12 inc/ft) : (5280 ft/miles)

Circumference = 0.0013 miles

Total travel distance = tires circumference x rotations

Total travel distance = 0.0013 x 150,000

Total travel distance = 193.45 miles

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Answer:

\(5^{-13}\)

Step-by-step explanation:

\(\frac{5^{-5}}{5^8}=5^{-5-8}=5^{-13}\)

Answer: 5^-13

Step-by-step explanation:

You can first convert the division to a multiplication :

Dividing by 5^8 is the same as multiplying by the inverse, so :

5^-5 / 5^8 = 5^-5 * 1/5^8

You can rewrite 1/5^8 as 5^-8

so 5^-5 * 1/5^8 = 5^-5 * 5^-8

you then just need to add the exponents in a multiplication

5^-5 * 5^-8 = 5^(-5-8) = 5^-13

Answer: Your answer is B! Hope you have an awesome day, and be kind be You!!! <3

Step-by-step explanation: Also, I'm 3D printing the Tesla Cyber truck, and this is the design I have so far. What do you think?

Answer:

45

Step-by-step explanation:

\(\huge\text{Hey there!}\)

\(\large\text{Guide to follow:}\)

\(\large\text{The word \boxed{\rm{difference}} means subtraction/subtract.}\)

\(\large\text{The word \boxed{\rm{product}} means addition/add.}\)

\(\large\text{The word \boxed{\rm{quotient}} means division/divide.}\)

\(\large\text{The word \boxed{\rm{product}} means multiplication/multiply.}\)

\(\large\text{Also guide to follow:}\)

\(\large\text{2 negatives gives you a positive}\)

\(\large\text{2 positives gives you a positive as well}\)

\(\large\text{1 negative \& 1 positive gives you a negative}\)

\(\large\text{1 positive \& 1 negative gives you a negative as well}\)

\(\large\textsf{So, in this particular question we're doing multiplication because the}\\\large\textsf{key term in the word phrase is \boxed{\textsf{product}}. }\)

\(\large\text{Now, that we have that information out of the way we can answer}\\\large\text{your given question.}\)

\(\large\text{The product of }\large\text{-15 and -3 is translated to \boxed{\rm{-}\large\text{15 }\times\ -\large\text{3}}}\)

\(\large\text{Equation: }\rm{-15\times-3}\)

\(\large\text{Simplify the equation we have gathered above and you should have}\\\large\text{pverall answer.}\)

\(\large\text{We have received was 45}\)

\(\huge\text{Therefore, your answer should be \boxed{\mathsf{45}}}\huge\checkmark\)

\(\huge\text{Good luck on your assignment \& enjoy your day!}\)

Answer:

\(\frac{1}{c^{3} }\) or \(c^{-3}\)

Step-by-step explanation:

\(c^{-5} * c^{2}\) = \(\frac{1}{c^{5}}\) * \(c^{2}\) = \(\frac{c^{2} }{c^{5} }\) ; simplify to \(\frac{1}{c^{3} }\) = \(c^{-3}\)

The partial derivative diffusivity equation for spherical flow is ∂²p/∂r² + (1/r) ∂p/∂r = ϕμC/k ∂p/∂t, and for hemispherical flow, it is the same equation.

1. The partial derivative diffusivity equation for spherical flow is derived from the spherical coordinate system and applies to radial flow in a spherical geometry. It can be expressed as ∂²p/∂r² + (1/r) ∂p/∂r = ϕμC/k ∂p/∂t.

2. The partial derivative diffusivity equation for hemispherical flow is derived from the hemispherical coordinate system and applies to radial flow in a hemispherical geometry. It can be expressed as ∂²p/∂r² + (1/r) ∂p/∂r = ϕμC/k ∂p/∂t.

1. For the derivation of the partial derivative diffusivity equation for spherical flow, we consider a spherical coordinate system with the radial direction (r), the azimuthal angle (θ), and the polar angle (φ). By assuming steady-state flow and neglecting the other coordinate directions, we focus on radial flow. Applying the Laplace operator (∇²) in spherical coordinates, we obtain ∇²p = (1/r²) (∂/∂r) (r² ∂p/∂r). Simplifying this expression, we arrive at ∂²p/∂r² + (1/r) ∂p/∂r.

2. Similarly, for the derivation of the partial derivative diffusivity equation for hemispherical flow, we consider a hemispherical coordinate system with the radial direction (r), the azimuthal angle (θ), and the elevation angle (ε). Again, assuming steady-state flow and neglecting the other coordinate directions, we focus on radial flow. Applying the Laplace operator (∇²) in hemispherical coordinates, we obtain ∇²p = (1/r²) (∂/∂r) (r² ∂p/∂r). Simplifying this expression, we arrive at ∂²p/∂r² + (1/r) ∂p/∂r.

In both cases, the term ϕμC/k ∂p/∂t represents the source or sink term, where ϕ is the porosity, μ is the fluid viscosity, C is the compressibility, k is the permeability, and ∂p/∂t is the change in pressure over time.

These equations are commonly used in fluid mechanics and petroleum engineering to describe radial flow behavior in spherical and hemispherical geometries, respectively.

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Based on the significant difference between the relative frequencies of 0.21 and 0.79, along with the calculated sum of 1.0, the data supports the conclusion that there is likely an association between the categorical variables.

Based on the data, if the relative frequencies being compared are 0.21 and 0.79, we can draw some conclusions. Firstly, the sum of the relative frequencies is 1.0, indicating that they account for all the occurrences within the data set. However, the more crucial aspect is the comparison of the relative frequencies themselves.

Considering that the relative frequencies of 0.21 and 0.79 are significantly different, it suggests that there may be an association between the categorical variables. When there is a strong association, we would generally expect the relative frequencies to be similar or close in value. In this case, the disparity between the relative frequencies supports the notion of an association between the categorical variables.

Therefore, the conclusion most likely supported by the data is that there is likely an association between the categorical variables because the relative frequencies are not similar in value. The fact that the sum of the relative frequencies is 1.0 does not provide evidence for or against an association, but rather serves as a validation that they represent the complete set of occurrences within the data.

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Since S satisfies both defining properties of an ideal in R, we can conclude that S is indeed an ideal in R.

To prove that the subset S = {λ1r1 +···+ λnrn | λ1,...,λn ∈ R} is an ideal in R, we need to show that it satisfies the two defining properties of an ideal:

1. S is a subgroup of R under addition.
2. S is closed under multiplication by elements of R.

First, let's show that S is a subgroup of R under addition.

- Closure under addition: Let x,y ∈ S, so that x = λ1r1 + ··· + λnrn and y = μ1r1 + ··· + μnrn for some λi,μi ∈ R. Then their sum is x + y = (λ1 + μ1)r1 + ··· + (λn + μn)rn, which is in S since each coefficient is still in R.

- Additive inverse: Let x ∈ S, so that x = λ1r1 + ··· + λnrn for some λi ∈ R. Then its additive inverse is -x = (-λ1)r1 + ··· + (-λn)rn, which is also in S since each coefficient is still in R.

Therefore, S is a subgroup of R under addition.

Next, let's show that S is closed under multiplication by elements of R.

- Closure under left multiplication: Let r ∈ R and x ∈ S, so that x = λ1r1 + ··· + λnrn for some λi ∈ R. Then their product is rx = (rλ1)r1 + ··· + (rλn)rn, which is in S since each coefficient is still in R.

- Closure under right multiplication: This follows from the distributive property of multiplication over addition.

Therefore, S is closed under multiplication by elements of R.

Since S satisfies both defining properties of an ideal in R, we can conclude that S is indeed an ideal in R.

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Answer:

7.01.

Step-by-step explanation:

We can use the Law of Cosines to solve for c:

c^2 = a^2 + b^2 - 2ab*cos(C)

We are given a = 7, m∠A = 50°, and m∠B = 60°. We can use the fact that the angles in a triangle add up to 180° to find m∠C:

m∠C = 180° - m∠A - m∠B

m∠C = 180° - 50° - 60°

m∠C = 70°

Now we can substitute the known values into the Law of Cosines and solve for c:

c^2 = 7^2 + b^2 - 27bcos(70°)

c^2 = 49 + b^2 - 14bcos(70°)

We don't know b, but we can solve for it using the given equation:

3/2 + b = 7/4

Subtracting 3/2 from both sides:

b = 7/4 - 3/2

b = 1/4

Now we can substitute b = 1/4 into the equation for c^2:

c^2 = 49 + (1/4)^2 - 14*(7/4)*(1/4)*cos(70°)

c^2 = 49.1709

c ≈ 7.01

Therefore, the length of side c is approximately 7.01.

The first left endpoint of any partition of an interval [a, b] is the value of 'a'.

An interval [a, b] represents a range of real numbers between the values of 'a' and 'b', including both endpoints.

The left endpoint, 'a', is the smaller value of the two, and the right endpoint, 'b', is the larger value.

Now, let's consider the concept of partitioning an interval.

Partitioning an interval means dividing it into smaller subintervals.

In this context, typically refer to a partition as a set of points that divides the interval into subintervals.

For example, let's consider the interval [a, b] and a partition P = {x₁, x₂, x₃, ..., xₙ}.

This partition divides the interval into subintervals [a, x₁], [x₁, x₂], [x₂, x₃], ..., [xₙ₋₁, xₙ], [xₙ, b].

Each subinterval represents a smaller range within the larger interval.

Now, coming to the first left endpoint of any partition, it refers to the leftmost point of the first subinterval in the partition.

Since the interval [a, b] includes the left endpoint 'a', the first left endpoint of any partition will always be the value of 'a'.

Therefore, the first left endpoint of an interval [a, b] for any partition is the value 'a', as it represents leftmost point of first subinterval in partition.

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Charles Dickens was born on a Saturday. By calculating the number of days between his birthdate and February 7, 2012, we determine that there were 4 extra days. Adding gives Saturday. So, the correct answer is B).

To determine the day of the week when Charles Dickens was born, we can calculate the number of days between his birthdate and February 7, 2012.

The year 2012 is a leap year because it is divisible by 4 but not divisible by 100. In a leap year, there are 366 days.

Since 2012 is a leap year, we need to calculate the number of days between February 7, 2012, and Charles Dickens' birthdate. The difference is 200 years, which is equal to 200 * 365 days for non-leap years plus an additional 49 days for the leap years in between (as there are 49 leap years in 200 years).

Total days = (200 * 365) + 49 = 73,049 days

Now, if we divide 73,049 by 7, the remainder will give us the day of the week.

73,049 divided by 7 = 10,435 remainder 4

Therefore, the remainder is 4, indicating that there were 4 extra days beyond Tuesday. Counting forward, Tuesday + 4 days gives us Saturday.

So, the answer is (B) Saturday.

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--The given question is incomplete, the complete question is given below " A year is a leap year if and only if the year number is divisible by 400 (such as 2000) or is divisible by 4 but not 100 (such as 2012). The 200th anniversary of the birth of novelist Charles Dickens was celebrated on February 7, 2012, a Tuesday. On what day of the week was Dickens born?

(A) Friday

(B) Saturday

(C) Sunday

(D) Monday

(E) Tuesday"--

Answer:

C=100.53 CM²

Step-by-step explanation:

Formula to the circumference of a circle is 2π·r

2π=6.28

6.28·16=100.53 CM²

Answer:

4+8+6=18

6+4+8=18

6+12=18

A Is Correct

Step-by-step explanation:

use ur smartness and brain will help u out

Answer:

-168

Step-by-step explanation:

8 × -7 × 3

-56 × 3

-168

The required time is mathematically given as

t-150 minutes.

This is further explained below.

We know that the volume of the prism is given by.

\(\text{Volume}=\text{(Base Area)}\times\text{height}\)

\(\text{Base Area}=\dfrac{1}{2}\times(1.4+0.6)\times2\)

\(\text{Base Area}=2\ \text{m}^2\)

Now,

\(\text{Volume}=2\times1=2\ \text{m}^3\)

Given that there is a twenty percent drop in the level of the pond during the first thirty minutes.

Because of this, the volume increases.

\(\text{Volume}=2\times0.8=1.6\ \text{m}^3\)

Now, the rate of emptying the tank is,

\(=\dfrac{2-1.6}{30} =\dfrac{1}{75} \ \text{m}^3/ \text{min}\)

In conclusion, We also know that,

$$

\(\text{time}=\dfrac{\text{volume}}{\text{rate}}\)

\(\text{time}=\dfrac{2}{\frac{1}{75} } =150 \ \text{min}\)

Therefore, Colin must wait for the pond to drain for a total of 150 minutes.

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Thus, the time rocket spent in the air before it impacted the ground by keeping in mind that after it reaches the ground, the rocket's height is zero is 0.168 seconds.

Quadratics and parabolas are frequently used in practical settings. Situations that can be approximated by quadratic functions include tossing a ball, firing a cannon, jumping off a platform, and hitting a golf ball.

Input/ output data for the quadratic regression equation

Time (s) 1 2 3 4

Height (ft) 91.1 135.7 148.5 129.1

quadratic regression equation is found using the calculator for the values given in table.

y = 14.4x² + 92.68x - 16

You may calculate how long that rocket spent in the air before it impacted the ground by keeping in mind that after it reaches the ground, the rocket's height is zero.

Put x = t and y  = 0

0 =  14.4t² + 92.68t - 16

Using the quadratic formula, find the time t.

t = [-b ± √(b² - 4ac)] / 2a

a = 14.4 , b = 92.68 , c = -16

Put the values:

t = [-92.68 ± √(92.68² - 4* 14.4* (-16))] / 2* 14.4

t =  [-92.68 ± 97.52] / 28.8

t = (-92.68 + 97.52)/28.8 and t =  (-92.68 - 97.52)/28.8

t = 0.168 seconds  and  t = -6.6  seconds

Negative values not taken.

Thus, the time that rocket spent in the air before it impacted the ground by keeping in mind that after it reaches the ground, the rocket's height is zero is 0.168 seconds.

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Answer:

Step-by-step explanation:

The type of study was cross-sectional study.

An example of an observational study design is the cross-sectional study design. In a cross-sectional study, the researcher simultaneously assesses the participants exposures and outcomes.

After choosing the study subjects, the researcher conducts the study in order to evaluate the exposure and results.

For population-based surveys and to determine the prevalence of illnesses in clinic-based samples, cross-sectional designs are employed.

These studies are typically affordable and reasonably quick to carry out.

An illustration of a cross-sectional study might be a medical investigation into the incidence of cancer in a particular community.

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The volume of the solid obtained by rotating the region bounded by the curves about the x-axis is π/77 (243 - 9sqrt(3)).

To find the volume of the solid obtained by rotating the region bounded by the curves about the x-axis, we can use the method of cylindrical shells. This involves integrating the circumference of a cylindrical shell times its height to obtain the volume of each shell, and then adding up the volumes of all the shells to get the total volume.

First, let's find the points of intersection of the two curves:

2/7 x^2 = 9/7 - x^2

9/7 = 9/7 x^2 + 2/7 x^2

9/7 = 11/7 x^2

x^2 = 9/11

x = ±sqrt(9/11)

The solid we obtain by rotating this region about the x-axis will have cylindrical shells with height dx, radius x, and circumference 2πx. Therefore, the volume of each shell will be:

dV = 2πx × h × dx

where h is the difference between the y-values of the curves at x:

h = (9/7 - x^2) - (2/7 x^2) = 9/7 - 9/7 x^2

Therefore, the total volume of the solid will be:

V = ∫(from x = -sqrt(9/11) to x = sqrt(9/11)) 2πx * (9/7 - 9/7 x^2) dx

V = 2π/7 ∫(from x = -sqrt(9/11) to x = sqrt(9/11)) x(9 - 9x^2) dx

We can simplify the integrand by setting u = 9x^2:

du/dx = 18x

dx = du/18x

Substituting:

V = 2π/7 ∫(from u = 9/11 to u = 81/11) (1/2)u^(1/2) (9/2) (du/18x)

V = π/7 ∫(from u = 9/11 to u = 81/11) u^(1/2) / x du

V = π/7 ∫(from u = 9/11 to u = 81/11) u^(1/2) / sqrt(9/11 - u/11) du

This integral can be evaluated using a trigonometric substitution. Let u = 9/11 sin^2 θ, then:

du/dθ = (18/11) sin θ cos θ dθ

Substituting:

V = π/7 ∫(from θ = π/6 to θ = π/2) (81/121) sin^3 θ dθ

V = π/7 [(81/121) * (3/4) - (9/121) × (sqrt(3)/2)]

V = π/77 (243 - 9sqrt(3))

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Answer:

590 > 5 × 10^2

Step-by-step explanation:

Answer:

>

Step-by-step explanation:

5×10^2=5×10×10=500, therefore 590>500