What is a solution to the equation 6t = 114?
A t = 19
B t = 108
C t = 120
D t = 684

Answer:

The letter "x" is often used in algebra to mean an unknown value. It is often called a "variable".

Example:

In x + 5 = 12, x is a variable, but we can work out its value if we try!

Answer:

The 90% confidence interval for the proportion of all letters mailed in the United States that were delivered the day after they were mailed is (0.7426, 0.8374). The lower limit is 0.7426 while the upper limit is of 0.8374.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \(\pi\), and a confidence level of \(1-\alpha\), we have the following confidence interval of proportions.

\(\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}\)

In which

z is the z-score that has a p-value of \(1 - \frac{\alpha}{2}\).

Suppose that 158 out of a random sample of 200 letters mailed in the United States were delivered the day after they were mailed.

This means that \(n = 200, \pi = \frac{158}{200} = 0.79\)

90% confidence level

So \(\alpha = 0.1\), z is the value of Z that has a p-value of \(1 - \frac{0.1}{2} = 0.95\), so \(Z = 1.645\).

The lower limit of this interval is:

\(\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.79 - 1.645\sqrt{\frac{0.79*0.21}{200}} = 0.7426\)

The upper limit of this interval is:

\(\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.79 + 1.645\sqrt{\frac{0.79*0.21}{200}} = 0.8374\)

The 90% confidence interval for the proportion of all letters mailed in the United States that were delivered the day after they were mailed is (0.7426, 0.8374). The lower limit is 0.7426 while the upper limit is of 0.8374.

Alison purchases lemons for $0.75 each is the required equation that is represented in the graph.

The equation is the relationship between variables and represented as y = ax + b is an example of a polynomial equation.

Here,
From the graph locate two points (0, 0) and (4, 3).
The equation of the line is given as,
y = 3/4x + c
or
y = 3/4x   [since the line is passing through the origin]

Now,
From the option, the above equation resembles with option D, because the slope of the equation represents the unit rate which is 0.75 same as in option D.

Thus, Ailison purchases lemons for $0.75 each is the required equation that is represented in the graph.

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The rate of the rowing team in still water is: 8.4 mph

Algebraic word problems are defined as problems that require converting a sentence into an equation and solving that equation. The equations that need to be written contain only basic arithmetic. and a single variable. Usually in real-life scenarios variables represent unknown quantities.

Let us denote the following:

Rowing boat speed = x mph with no current

Current speed = 6 mph

Speed against current = x - 6 mph

Speed with current =  x + 6 mph

Distance against current = 10 miles

Distance with current = 60 miles

Time is:

t = d/r

10 /(x- 6 ) = 60 /(x+ 6 )

10 *(x+ 6 )= 60 *(x- 6 )

10 x + 60 = 60 x -360

10 x -60 x = -360 + -60

-50 x = -420

-420/ -50

x = 8.4 mph

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Complete question is:

A rowing team rowed 60 miles while going with current in the same amount of time as it took to row 10 miles going against the current. The rate of the current was 5 miles per hour. Find the rate of the rowing team in still water.

a) 0.0138

b) 0.1103

Probability is the likelihood or chance that an event will occur. Mathematically;

where:

n(S) is the total outcome

n(E) is the total number of events

If a well- shuffled box contains 2 gold marbles, 6 silver marbles and 9 bronze balls, the total outcome is given as:

n(S) = 2 + 6 + 9

n(S) = 17 marbles

a) If the marbles selected are two gold marbles and replaced, the probability of selecting two gold marbles will be:

b) If two silver marbles are selected, the probability of selceting the first silver marble is given as:

If the first silver marble is not replaced, the probability of picking the second one will be:

The probability that they are both silver marbles if the first marble is not replaced is calculated as:

Hence the probability that they are both silver marbles if the first marble is not replaced is 0.1103

The taxi ride was 7 miles

Mia took a taxi from her house to the airport

The taxi charged a pick up fee of $1.30

They also charged $4.25 per mile

The total fare was $31.05

The number of miles can be calculated as follows

31.05 - 1.30 = 4.25x

29.75= 4.25x

Divide both sides by the coefficient of x which is 4.25

29.75/4.25= 4.25x/4.25

x= 7

Hence the taxi ride was 7 miles

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Answer:

a) 0.0668

b) 0.3085

c) 0.6247

Question:

A population is normally distributed with μ = 100 and σ= 20.

a. Find the probability that a value randomly selected from this population will have a value greater than

130.

b. Find the probability that a value randomly selected from this population will have a value less than 90.

c. Find the probability that a value randomly selected from this population will have a value between 90

and 130.

Step-by-step explanation:

a) The probability that a value randomly selected from this population will have a value greater than 130 = P(X >130)

A z-score also referred to as a standard normal table shows the number of standard deviations a raw score lays either above or below the mean.

Let's determine the z-score using:

z = (x - µ)/σ

µ = 100

σ = 20

z = (130-100)/20

z = 30/20 = 1.5

The probability from the standard normal table associated with z = 1.50 is 0.4332. This is the area between z = 1.50 and the mean.

The total area under any normal curve is 1. Due to the fact that the normal curve is symmetric about the mean, the area on either sides of the mean is 0.5.

The desired probability = 0.5000 - 0.4332

= 0.0668

Find attached the diagram.

b) The probability that a value randomly selected from this population will have a value less than 90 = P(X<90)

Using the z-score formula:

z = (x - µ)/σ

z = (90-100)/20

z = (-10)/20 = -0.5

The probability from the standard normal table associated with

z = -0.50 is 0.1915. This is the area between z = -0.50 and the mean.

The desired probability = 0.5000 - 0.1915

= 0.3085

Find attached the diagram.

c) The probability that a value randomly selected from this population will have a value between 90 and 130 = P(90≤X≤130)

We earlier found the z score when P(X<90) = -0.5

And the probability associated with

z = -0.50 is 0.1915.

The z score when P(X>130) = 1.5

And the probability associated with z = 1.50 is 0.4332.

The desired probability is the addition of the two probabilities:

P(90≤X≤130) = 0.1915+0.4332

P(90≤X≤130) = 0.6247

Answer:

C)  (2x + 1)(2x – 1)

Step-by-step explanation:

Answer:

x= -2

Step-by-step explanation:

x^4(x+ 1)= -1

x^4= -1.... math error so ignore

x+1= -1

x= -1-1

= -2

Answer:

0.04

Step-by-step explanation:

0.04854368932

know gimme brainly

The measure of PQ in the triangle is 28 units.

The line segment connecting the midpoints of  two sides of a triangle is parallel to the third side and is congruent to one half of the third side.

Therefore, using the mid point theorem, Let find the measure of PQ.

ST = -22 + 9x

PQ = 9x - 8

The measure of PQ can be found as follows:

ST = 1 / 2 (PQ)

-22 + 9x = 1 / 2 × (9x - 8)

-22 + 9x = 9x - 8 / 2

cross multiply

2(-22 + 9x) = 9x - 8

-44 + 18x = 9x - 8

-44 + 8 = 9x - 18x

- 36 = - 9x

x = - 36 / - 9

x = 4

Therefore,

PQ = 9(4) - 8 = 36 - 8 = 28 units

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Answer:

Step-by-step explanation:

40 + 15 + 0.25m = 45 + 0.35m

       55 + 0.25m = 45 + 0.35m

                       10 = 0.10m

                        m = 100 miles

Answer:

45

Step-by-step explanation:

- x - = +

=> - 5 x -9

=> 45

Answer:

Positive 45

(-5) . (-9) = positive 45

The output value of (f∘g)(x) is:  \((f \circ g)(x) = \frac{4x^2-29x+60}{x +3}\)

The domain of (f∘g)(x) is (-∞, -3) U (-3, ∞).

In this scenario, we would determine the corresponding composite function of f(x) and g(x) under the given mathematical operations (multiplication) in simplified form as follows;

\(f(x) = \frac{x-6}{x +3}\)

g(x) = 4x - 15

Next, we would write the numerators and denominators in factored form as follows;

(x - 6)(4x - 15)

4x² - 15x - 24x + 60

4x² - 29x + 60

Now, we can derive the corresponding composite function of f(x) and g(x);

\((f \circ g)(x) = \frac{4x^2-29x+60}{x +3}\)

For the restrictions on the domain, we would have to equate the denominator of the rational function to zero and then evaluate as follows;

x + 3 ≠ 0

x ≠ -3

Domain = (-∞, -3) U (-3, ∞).

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According to the above, the figure rotated 180° would remain as shown in the image in the fourth quadrant of the Cartesian plane (+ , -)

To rotate the figure 180 degrees we must take into account its initial position. Additionally, we must remember that each quadrant is equivalent to 90°, so we would have to rotate it two quadrants. In this case it is not important to know if it rotates counterclockwise or clockwise because we know it will be in quadrant #4.

In this case, we must be guided by the coordinates that the figure has to draw it again. From the above we can see that it has four coordinates at the top. In the case of the figure rotated in quadrant #4, these four coordinates would be at the bottom because the figure has been rotated 180°.

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Each silver bead costs $0.50, and each green bead costs $1.

Let's assume the cost of each silver bead is 's' dollars, and the cost of each green bead is 'g' dollars.

According to the given information, the necklace requires 25 silver beads and 15 green beads, and the bracelet requires 10 silver beads and 5 green beads.

The total cost of the necklace beads is $27.50, and the total cost of the bracelet beads is $10.

Using this information, we can set up the following system of equations:

25s + 15g = 27.50 (Equation 1)

10s + 5g = 10 (Equation 2)

We can solve this system of equations using any appropriate method, such as substitution or elimination.

Let's use the elimination method to solve the system:

Multiplying Equation 2 by 3, we get:

30s + 15g = 30 (Equation 3)

Subtracting Equation 3 from Equation 1:

25s + 15g - (30s + 15g) = 27.50 - 30

-5s = -2.50

s = 0.50

Now, substituting the value of s into Equation 2:

10(0.50) + 5g = 10

5 + 5g = 10

5g = 5

g = 1

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The given equation is:

Add (12/2)^2=36 on both sides of the equation.

Therefore, adding 36 to both sides of the equation complete the square.

Hence, option C is correct.

20,000 ten thousand equals 2000 Hundred thousand.

As per the question statement, we are provided with a value: "20,000 ten thousand".

We are required to calculate how many hundred thousand are equal to 20,000 ten thousand.

To solve this question, let us first write down 20,000 ten thousand into the numerical format, i.e, \((20000*10,000)=200000000\).

As we know, a hundred thousand when written down in the numerical format becomes 100,000, let us assume that 20,000 ten thousand equals to "x" number of Hundred thousand.

Therefore, we can form a linear equation in one variable "x" based on the condition, in the above-mentioned statement, which goes as  \((100,000*x)=200000000\)

\(or, (100,000x)=200000000\\or,x=\frac{200000000}{100,000}\\or,x=\frac{2*10^{8} }{10^5\\}or,x=(2*10^3)\\or,x=2000\)

Hence, 20,000 ten thousands equals 2000 Hundred thousands.

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Answer:

\(y=2x-1\)

Step-by-step explanation:

Take a look at the attachment...

Hope this helps! :)

Answer:

1/4 - 8n/5

Step-by-step explanation:

(1/4-3/5n)-n = 1/4 - 3/5 n - 5/5 n = 1/4 - 8/5 n = 1/4 - 8n/5

Answer:

The Pair Factors of 54 are (1, 54), (2, 27), (3, 18), and (6, 9) and its Prime Factors are 1, 2, 3, 6, 9, 18, 27, 54.

Step-by-step explanation:

hope this helped:)

brainliest for the brains........................

The Pair Factors of 54 are (1, 54), (2, 27), (3, 18), and (6, 9) and its Prime Factors are 1, 2, 3, 6, 9, 18, 27, 54.

Here, we have,

The factors of 54 are the numbers, that can divide 54 completely or evenly. When a pair of factors are multiplied together to produce the 54, then they are said to be pair factors. The factors divide the number completely. Hence, these factors cannot be a fraction.

Factors of 54: 1,2,3,6,9,18,27 and 54

Factor pairs of the number 54 are the whole numbers which are not a fraction or decimal number.

To find the factors of a number, 54, we will use the factorization method.

To find factors of 54, we have to divide 54 by all natural numbers from 1 to 54.

54 ÷ 1 = 54

54 ÷ 2 = 27

54 ÷ 3 = 18

54 ÷ 6 = 9

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Answer:

the cosine expressions are reversed

Step-by-step explanation:

edge 2020

Answer:

Step-by-step explanation:

To show that the expression \(\ln(\sqrt{2} + 1) - \ln\left(\frac{1}{\sqrt{2}}\right)\) is equal to \(-\ln\left(1 - \frac{1}{\sqrt{2}}\right)\), we can simplify both sides of the equation using the properties of logarithms. Here are the steps:

Step 1: Simplify the expression on the left side:

\(\ln(\sqrt{2} + 1) - \ln\left(\frac{1}{\sqrt{2}}\right)\)

Step 2: Apply the logarithmic property \(\ln(a) - \ln(b) = \ln\left(\frac{a}{b}\right)\) to combine the logarithms:

\(\ln\left(\frac{\sqrt{2} + 1}{\frac{1}{\sqrt{2}}}\right)\)

Step 3: Simplify the expression within the logarithm:

\(\ln\left(\frac{(\sqrt{2} + 1)}{\left(\frac{1}{\sqrt{2}}\right)}\right)\)

Step 4: Simplify the denominator by multiplying by the reciprocal:

\(\ln\left(\frac{(\sqrt{2} + 1)}{\left(\frac{1}{\sqrt{2}}\right)} \cdot \sqrt{2}\right)\)

\(\ln\left(\frac{(\sqrt{2} + 1) \cdot \sqrt{2}}{\left(\frac{1}{\sqrt{2}}\right) \cdot \sqrt{2}}\right)\)

\(\ln\left(\frac{(\sqrt{2} + 1) \cdot \sqrt{2}}{1}\right)\)

Step 5: Simplify the numerator:

\(\ln\left(\frac{(\sqrt{2} + 1) \cdot \sqrt{2}}{1}\right)\)

\(\ln\left(\sqrt{2}(\sqrt{2} + 1)\right)\)

\(\ln\left(2 + \sqrt{2}\right)\)

Now, let's simplify the right side of the equation:

Step 1: Simplify the expression on the right side:

\(-\ln\left(1 - \frac{1}{\sqrt{2}}\right)\)

Step 2: Simplify the expression within the logarithm:

\(-\ln\left(\frac{\sqrt{2} - 1}{\sqrt{2}}\right)\)

Step 3: Apply the logarithmic property \(\ln\left(\frac{a}{b}\right) = -\ln\left(\frac{b}{a}\right)\) to switch the numerator and denominator:

\(-\ln\left(\frac{\sqrt{2}}{\sqrt{2} - 1}\right)\)

Step 4: Simplify the expression:

\(-\ln\left(\frac{\sqrt{2}}{\sqrt{2} - 1}\right)\)

\(-\ln\left(\frac{\sqrt{2}(\sqrt{2} + 1)}{1}\right)\)

\(-\ln\left(2 + \sqrt{2}\right)\)

As we can see, the expression \(\ln(\sqrt{2} + 1) - \ln\left(\frac{1}{\sqrt{2}}\right)\) simplifies to \(\ln(2 + \sqrt{2})\), which is equal to \(-\ln\left(1 - \frac{1}{\sqrt{2}}\right)\).

Answer:

no it is not

Step-by-step explanation:

8 × 1 does not equal 2

The conclusion is option A, we cannot reject the null hypothesis.

An assumption or concept is given as a hypothesis for the purpose of debating it and testing if it might be true.

The null hypothesis cannot  be rejected for the entire population if your sample is not sufficiently incompatible with it, which can be determined if your P value is small enough.

Therefore, we can not reject the hypothesis.

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Answer:

Jiri is 48 years old

Step-by-step explanation:

STEP 1

Let Jill's age be equal to: x

Let Pamela's age be equal to :Jiri's age(x) - 15

STEP 2

Total sumof Jiri and Pamela's age= 81

Sum= Pamela's age + Jiri's age

81 = (x-15) + x

81 =x -15 + x

81 = x+x -15

81= 2x -15

Collect like terms

81 + 15= 2x ( recall - changes to + when crossing the =)

96=2x

Divide both sides by 2

96/2 =2x/2

48 = x

Recall Jiri's age is equal to x

Hence Jiri's age is equal to 48

The probability the at least of the people selected from 5 is vaccinated is 0.997.

The binomial distribution is a statistical probability distribution that summarizes the likelihood of a value taking one of two independent values under the specific set of assumptions or assumptions.

Because the five randomly chosen people are independent, the probability that they're all unvaccinated is (0.47)⁵,

The probability that at least one among them 5 has been vaccinated is;

= 1 - (0.47)⁵

= 0.997

Therefore, the probability that at least one of the five people chosen is vaccinated is 0.997.

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Answer:

Larry is incorrect

Step-by-step explanation:

A composite number is a number that is divisible by itself, 1, and any other number. He is incorrect. For example, the number 23 isn't composite, even though there is a 2 in the ones place. The number 23 is ONLY divisible by 23 and 1 -- not any other number.

Hope this helped :)

Answer:Larry is correct

Step-by-step explanation:

Larry is correct because if u were to write a list of how many prime numbers are between 1 and 100 u would get 2,3,5,7,11,13,17 and so and so u would not get a number that ends with a two and be prime.

Let \(f(x) = x^3 - 2x - 2\). Then differentiating, we get

\(f'(x) = 3x^2 - 2\)

We approximate \(f(x)\) at \(x_1=2\) with the tangent line,

\(f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18\)

The \(x\)-intercept for this approximation will be our next approximation for the root,

\(10x - 18 = 0 \implies x_2 = \dfrac95\)

Repeat this process. Approximate \(f(x)\) at \(x_2 = \frac95\).

\(f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}\)

Then

\(\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}\)

Once more. Approximate \(f(x)\) at \(x_3\).

\(f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}\)

Then

\(\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}\)

Compare this to the actual root of \(f(x)\), which is approximately 1.769292354, matching up to the first 5 digits after the decimal place.