what is .48 divided by 9.23 and rounded to the nearest tenth?

Given that x = 7.7 m and = 25° the value of  AB is given as 3.254

We have the following data to work with

x = 7.7 m and = 25°,

then we have sin 25 = ∅ = 25 degrees

sin 25 = ab / 7.7

cross multiply from here

AB = sin25 x 7.7

= 0.4226 x 7.7

= 3.254

Hence we would say that in the triangle if x = 7.7 m and = 25°, the value of AB would be solved to be 3.254

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Answer and Step-by-step explanation:

Scale factor of 4

x, y: (3, 10)

Translate 3 units right, up 10 units.

#teamtrese #PAW (Plant aNd Water)

the first column of matrix b (b1) is [1, -3, 1] and the second column of matrix b (b2) is [1, 3, 1].

To determine the first and second columns of matrix b, we need to find the values of b1 and b2.

Given that a = [1, -3; -3, 5] and ab = [-5, -5; 6, 3; 7, 4], we can set up the following equation:

ab = [a * b1, a * b2]

To find b1, we can solve the equation:

[-5, -5; 6, 3; 7, 4] = [1, -3; -3, 5] * [b1, b2]

By matrix multiplication, we can write the following system of equations:

-5 = 1 * b1 + -3 * b2

6 = -3 * b1 + 5 * b2

7 = 1 * b1 + -3 * b2

Simplifying these equations, we have:

-5 = b1 - 3b2

6 = -3b1 + 5b2

7 = b1 - 3b2

We can solve this system of linear equations to find the values of b1 and b2.

Adding the first and third equations, we get:

2b1 = 2

Dividing by 2, we find:

b1 = 1

Substituting b1 = 1 into the second equation, we have:

6 = -3 + 5b2

5 = 5b2

b2 = 1

Therefore, the first column of matrix b (b1) is [1, -3, 1] and the second column of matrix b (b2) is [1, 3, 1].

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Postcards total cost $1.50 for 15 cards, while envelopes cost $0.20 for 10. Each envelope is two cents more expensive than a postcard. Together, these items cost $1.70.

Postcards: 15 postcards x $0.10 each = $1.50

Envelopes: 10 envelopes x $0.12 each = $0.20

Total: $1.50 + $0.20 = $1.70

Postcards: 15 postcards x $0.10 each = $1.50

Step 1: Multiply the number of postcards by the cost of each postcard.

15 postcards x $0.10 = $1.50

Envelopes: 10 envelopes x $0.12 each = $0.20

Step 2: Multiply the number of envelopes by the cost of each envelope.

10 envelopes x $0.12 = $0.20

Total: $1.50 + $0.20 = $1.70

Step 3: Add the cost of the postcards and the cost of the envelopes together to get the total cost.

$1.50 + $0.20 = $1.70

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\(\sqrt[4]{256x^{6}y^{10} }\)will be 4\(x^{3/2} y^{5/2}\)

The number that, when multiplied four times by itself, yields the original number is the fourth root of a number. In other words, the square root of the square root of an integer equals the number's fourth root.

eg:

eg: \(\sqrt[4]{81}\) = 3

We are asked

x> 0 and y> 0then

\(\sqrt[4]{256x^{6}y^{10} }\)    =  4 \(x^{3/2} y^{5/2}\)

As 4 multiplied by 4 , 4 times given 256 and x to the power 6 and root 4 so that will be x to the power 3/2 and y to the 10 and root 4 will give 5/2

thus

\(\sqrt[4]{256x^{6}y^{10} }\) will be equivalent to  4 \(x^{3/2} y^{5/2}\)

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To determine the assignment of employees to jobs that minimizes the total time required to perform the four jobs, we need to consider the time taken by each person to complete each job. Using the given Table 50, we can analyze the data and identify the optimal assignment.

By examining Table 50, we can identify the minimum time taken by each person for each job. Starting with Job 1, we see that Person 4 takes the least time of 16 hours. Moving to Job 2, Person 2 takes the least time of 18 hours. For Job 3, Person 1 takes the least time of 25 hours. Lastly, for Job 4, Person 4 takes the least time of 14 hours.

Therefore, the optimal assignment would be:

- Person 4 for Job 1 (16 hours)

- Person 2 for Job 2 (18 hours)

- Person 1 for Job 3 (25 hours)

- Person 4 for Job 4 (14 hours)

This assignment ensures that the minimum total time is required to perform the four jobs, resulting in a total time of 16 + 18 + 25 + 14 = 73 hours.

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Answer:

A) Changing the measurement unit.

Step-by-step explanation:

"Changing the measurement unit" is the correct answer because when you convert from feet to inches, you are essentially changing the unit of measurement from a larger unit (feet) to a smaller unit (inches) within the same system of measurement (length or distance). It involves multiplying the value in feet by a conversion factor to obtain the equivalent value in inches. This process is commonly used in math, science, and everyday life when dealing with different units of measurement.

The solution to the mutually exclusive probability is: P(Q or R) = 11/15

In the probability theory, two events are said to be mutually exclusive or disjoint provided that they do not occur at the same time.

Now, the formula for finding the either/or probability is given by the expression:

P(A or B) = P(A) + P(B) - P (A and B).

We are given:

P(Q) = 3/5

P(R) = 1/3

P(Q and R) = 1/5

Thus:

P(Q or R) = 3/5 + 1/3 - 1/5

= (9 + 5 - 3)/15

= 11/15

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The store should have 445 picks remaining, not 450 as estimated by the manager. To determine if the store manager's estimate is reasonable, let's analyze the situation.

The store initially has 500 guitar picks. They order 15 boxes, and each box contains 9 picks. So the total number of picks they receive from the order is:

15 boxes * 9 picks/box = 135 picks

Next, the store sells 19 boxes, with each box containing 10 picks. Therefore, the total number of picks sold is:

19 boxes * 10 picks/box = 190 picks

To find the remaining number of picks, we can subtract the sold picks from the received picks:

Total remaining picks = Initial picks + Received picks - Sold picks

Total remaining picks = 500 + 135 - 190 = 445 picks

According to the calculations, the store should have 445 picks remaining, not 450 as estimated by the manager.

However, it's important to note that we are working with whole numbers, so there might be some rounding involved in the manager's estimate. It's possible that the manager rounded up to 450 for simplicity or other reasons.

Given the small discrepancy of 5 picks between the calculated value and the manager's estimate, it is reasonable to conclude that the manager's estimate is close enough to the actual number of picks. The discrepancy could be due to rounding or a small counting error. It's unlikely to have a significant impact on the store's operations or inventory management.

In summary, while the manager's estimate of 450 guitar picks may not be exactly accurate, it is reasonably close to the actual remaining number of picks based on the given information.

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The conversion of a fraction number with denominator 5 and numerator 2 , 2/5 in decimals is equals to the 0.4 value.

A decimal number can be defined as a number whose whole number part and fractional part are separated by a decimal point. Writing 2/5 as a decimal number by converting the denominator to powers of 10. We multiply the numerator and denominator by a number so that the denominator is a power of 10.

2/5 = (2 × 2) / (5 × 2) = 4/10

Now move the decimal point to the left as many places as there are zeros in the denominator, which is a power of 10.

The decimal moved one place to the left because the denominator was 10. Therefore, 4/10 = 0.4. Hence, required value is 0.4.

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the concentration of Cl₂ after 180 s is approximately \(4.003 x 10^{-8}\) M.

To determine the concentration of Cl₂ after 180 s, we can use the first-order rate equation: ln([Cl₂]t/[Cl₂]0) = -kt

Where [Cl₂]t is the concentration of Cl₂ at time t, [Cl₂]0 is the initial concentration of Cl₂, k is the rate constant, and t is the time.

Rearranging the equation, we have: [Cl₂]t = [Cl₂]0 * e^(-kt) Plugging in the given values, [Cl₂]0 = 0.8 M and \(k = 9 x 10^{-2} s^{-1}\),

and t = 180 s, we can calculate the concentration: [Cl₂]t = \(0.8 M * e^{(-9 x 10^{-2} s^{-1} * 180 s)}\) Simplifying the calculation, we get: [Cl₂]t ≈ 0.8 M * \(e^{(-16.2)}\) Using a calculator, we find: [Cl₂]t ≈ 0.8 M * 5.0032 x \(10^{-8}\) [Cl₂]t ≈ 4.003 x \(10^{-8 }\)M

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Bob continues his research because even though there is no linear equation relationship between the number of bedrooms and selling price, there could be another type of relationship.

Bob continues his research because even though the correlation value he calculated between the number of bedrooms and the selling price was only 0.05, this does not necessarily mean that there is no relationship of any kind between these two variables. It simply means that there is no linear relationship between the two. There could still be other types of relationships between the two variables, such as an exponential or quadratic relationship. It is possible that further analysis and exploration of the data set would reveal such a relationship and allow Bob to uncover the relationship between the two variables. Additionally, even if the correlation value is low, it does not necessarily mean that there is no relationship between the two variables. It simply means that the relationship is weak. Therefore, Bob should continue his research in order to uncover any potential relationships between the number of bedrooms and selling price.

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a. To calculate the solid angle subtended by the thunderstorm cloud, we can use the formula for the solid angle of a cone-like region given by: Solid Angle = ∫∫ sin(θ) dθ dφ.

In this case, the limits of integration are π/6 < θ < π/2 and 0 < φ < π/8. ∫∫ sin(θ) dθ dφ = ∫(π/8 to π/2) ∫(0 to π/8) sin(θ) dθ dφ. Evaluating this integral will give us the solid angle subtended by the thunderstorm cloud. b. To determine the percentage of the sky occupied by the thunderstorm cloud, we need to calculate the ratio of the solid angle subtended by the cloud to the total solid angle of a full sphere (4π steradians), and then multiply by 100. Percentage of Sky Occupied = (Solid Angle / 4π) * 100.

By substituting the value of the solid angle obtained in part (a) into this formula, we can determine the percentage of the sky occupied by the thunderstorm cloud. Please note that without specific numerical values for the limits of integration, it is not possible to provide a numerical answer in this case.

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Answer:

x = 59/12

Step-by-step explanation:

4x + 1/3 = 20

4x = 20 - 1/3

12x/3 = 60/3 - 1/3

12x = 60 - 1

12x = 59

x = 59/12

Check:

4*59/12 + 1/3 = 20

236/12 + 4/12 = 20

240/12 = 20

Answer:

ima take my dagn points back smh dont answer on my questions if ur not gonna do them and say thanks ma'am like wt dude such a lame move god

Step-by-step explanation:

Answer:

Blank 1- 2.87 Blank 2- 64.24 Blank 3- 133.12

Step-by-step explanation:

First you would use y2-y1 divided by x2-x1 to get the slope, or m. Then you plug in 2007 for y and 67.11 for x. your equation should look like 2007=2.87(67.11)+b. After you multiply 2.87 by 67.11, you should subract your answer from 2007 to get 64.24.

The slope -intercept form for the line of fit shown will be; y = 2.87x - 5701.89

The slope is the ratio of the vertical changes to the horizontal changes between two points of the line.

Given that the points are (2007, 67.11) and (2016, 92.98) .

We need to write the slope-intercept form of an equation for the line of fit shown, where x is the number of years since 2006.

Step(i):-

The slope of the line

m = (92.98 - 67.11)/ (2016 - 2007)

m = 25.87/9

m = 2.87

Step(ii):-

The Equation of the straight line passing through the Point (2007, 67.11)

y - 67.11= (2.87)(x-2007)

y - 67.11= (2.87x- 5769)

 y = (2.87x- 5769) + 67.11

y = 2.87x - 5701.89

The slope -intercept form for the line of fit shown will be; y = 2.87x - 5701.89

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Answer:

1/200000

Step-by-step explanation:

first 10 km equals to 1000000cm

so 5/1000000cm

equals to 1/200000

The length of the side p is given as 11.2.

By applying the Law of Sines, we can find the length of any side of the triangle. The law of sines states that for any triangle with sides of lengths a, b, and c opposite angles A, B, and C, respectively.

Mathematically,

sin A / a = sin B / b = sin C / c

In this case, we know the values of sin P and sin R, and the length of side r. We want to find the length of side p. We can set up the equation as follows:

sin P / p = sin R / r

Substituting the given values, we get:

sin P / p = 0.5 / 14

Solving for p, we get:

p = sin P / (0.5 / 14)

p = sin P * 28

p = 0.4 * 28

p = 11.2

Therefore, the length of side p is 11.2.

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The MATLAB function "Pex5" calculates the value at x of the Taylor polynomial \(P_n(x)\) of degree n about a=0 for ln((1+x)/(1-x)), and it prints the value \(P_{13}(0.2)\) and the absolute error \(|ln(1.5) - P_{13}(0.2)|\).

Here's the MATLAB function "Pex5" that calculates the value at x of the Taylor polynomial \(P_n(x)\) of degree n about a=0 for the function ln((1+x)/(1-x)). It also prints the value \(P_{13}(0.2)\) and the absolute error \(|ln(1.5) - P_{13}(0.2)|\).

function y = Pex5(x, n)

   if (n <= 0)

       y = 0;

   elseif (n <= 2)

       y = 2 * x;

   else

       t = x * x;

       y = 2 * x * \((1 + t/3 + t^2/5 + t^3/7 + t^4/9 + t^5/11 + t^6/13 + t^7/15 +\)\(t^8/17 + t^9/19 + t^{10}/21 + t^{11}/23 + t^{12}/25 + t^{13}/27)\);

   end

end

result = Pex5(0.2, 13);

expected_value = log(1.5);

absolute_error = abs(expected_value - result);

fprintf('P13(0.2) = %.15f\n', result);

fprintf('Absolute error: %.15f\n', absolute_error);

When you run the code, it will print the value \(P_{13}(0.2)\) with 15 significant digits, as well as the absolute error \(|ln(1.5) - P_{13}(0.2)|\).

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TThe three equations are: wo + w1 = 1w0 - x1w1 = 01/3 + x1² = 1/3 + 1/6 = 1/2

Solving these equations gives: w0 = 5/12w1 = 1/3x1 = √(1/6) = (1/6)^(1/2)

Here is the step-by-step solution of the given problem:

(a) To find the weights wo and w1 and node 1 so that the quadrature formula [ f(x) dx ≈ woƒ(-1) + w1f(x1), is exact for polynomials of degree 2 or less.

Given, f(x) dx ≈ woƒ(-1) + w1f(x1)Let f(x) be a polynomial of degree at most two. In order for the quadrature formula to be exact, we need∫f(x)dx - ∫(woƒ(-1) + w1f(x1))dx=0

Thus,∫f(x)dx - woƒ(-1)∫dx - w1f(x1)∫dx=0

Let’s choose f(x) to be a quadratic polynomial of the form f(x)=ax²+bx+c. Then,∫f(x)dx=∫ax²+bx+c dx=ax³/3+bx²/2+cx = 1/3a - 1/2b + c

Therefore,∫f(x)dx = 1/3a - 1/2b + c

This gives, 1/3a - 1/2b + c - woƒ(-1) - w1f(x1) = 0Now we need two more equations.

For a quadrature rule involving three nodes to be exact for polynomials of degree at most two, it must be exact for the three polynomials of degree 0, 1, and 2.

Consider these polynomials:f(x) = 1f(x) = xf(x) = x²

To obtain the first equation, integrate both sides of the quadrature rule with f(x) = 1:∫f(x)dx = ∫(-1)f(-1)dx + ∫(x1)f(x1)dx=1

Thus, 1-wo-w1=0Now, let f(x)=x.

Then,∫f(x)dx = ∫(-1)f(-1)dx + ∫(x1)f(x1)dx=0Thus, -ƒ(-1) + x1ƒ(x1) = 0-(-1)w0 + x1w1 = 0 => w0 - x1w1 = 0Next, let f(x)=x². Then,∫f(x)dx = ∫(-1)f(-1)dx + ∫(x1)f(x1)dx=1/3Thus, 1/3ƒ(-1)² + x1²ƒ(x1) = 1/3(-1)² + x1²(1)1/3 + x1² = 1/3 + x1² => x1² = 1/6

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Answer:

85 degrees

Step-by-step explanation:

Given she prepares are shirts, shorts and slippers, the place she is going on vacation is probably very warm like Hawaii or Florida. My guess is 85 degrees.

Hope this helps :)

Have a great day!

Answer:

The answer is that the ball was in the air for 0.56 seconds when it was 54 feet above the ground. This was determined by using the Quadratic Formula to solve the equation 54 = -16s^2 + 96s for the variable s.

Step-by-step explanation:

To solve this equation, we can use the Quadratic Formula, which states that for a quadratic equation in the form ax^2 + bx + c = 0, the solutions are given by:

x = (-b +/- sqrt(b^2 - 4ac)) / (2a)

In this case, a = -16, b = 96, and c = -54. Plugging these values into the Quadratic Formula, we get:

s = (-96 +/- sqrt(96^2 - 4 * -16 * -54)) / (2 * -16)

= (96 +/- sqrt(9216 + 4352)) / -32

= (96 +/- sqrt(13,568)) / -32

Since we want the time (in seconds) that the ball was in the air, we need to find the positive solution to this equation. Thus, we have:

s = (96 + sqrt(13,568)) / -32

= (96 + 120) / -32

= 0.5625 seconds

Rounding this value to the nearest hundredth of a second, we get 0.56 seconds. This means that the ball was in the air for 0.56 seconds when it was 54 feet above the ground.

To solve this equation, we used the Quadratic Formula. This method allowed us to find the time (in seconds) that the ball was in the air by solving for the value of the variable s in the given equation. This helped Vue answer his question by providing a numerical value for the amount of time that the ball was in the air when it was 54 feet above the ground.

The exact value of cos^-1( √3/2) = 30°

The trigonometric functions are real functions which relate an angle of a right-angled triangle to ratios of two side lengths.

There are special angles in trigonometry, this angles have exact value and can be obtained without using calculator. Examples of this calculator are; 30°, 60°, 45°

sin30 = 1/2

cos 30 = √3/2

tan 30 = 1/√3

cos 60 = 1/2

sin 60 = √3/2

tan 60 = √3

Therefore, if cos^-1( √3/2) = x

cos x = √3/2

cos 30 = √3/2

cos x = cos 30

therefore x = 30

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Answer:

\(4(4b - 8) - \frac{3}{8} \\ 16b - 32 - \frac{3}{4} \\ \frac{64b - 128 - 3}{8} \\ \frac{64b - 131}{8} \)

hope this will help you

Answer: B) There is not convincing evidence because the interval contains 0.

==============================================================

Explanation:

The 98% confidence interval (-0.36, 0.22) means we are 98% confident that the difference of proportions p1-p2 is somewhere between those two endpoints of -0.36 and 0.22 Values in this interval are possible values of p1-p2.

Note how 0 is in this interval. So it's possible that p1 - p2 = 0. Because of this, we fail to reject the null hypothesis. The null in this case is that p1 - p2 = 0 which can be restated as p1 = p2. The null is the assumption that the two population proportions (p1 and p2) are the same.

The alternative hypothesis is that p1-p2 is not zero. If we got a confidence interval like (0.22, 0.55), this example doesn't have 0 in the interval, then that would mean we reject the null since its unlikely that p1-p2 is equal to zero.

----------------

In short,

In this case, we fail to reject the null and we don't have enough evidence to show that p1 = p2 is false. So for now, we assume it's true.

An MIS differs from a TPS in that it creates databases is True.

An MIS (Management Information System) does indeed differ from a TPS (Transaction Processing System) in that it creates databases. The main purpose of an MIS is to collect, process, store, and disseminate information to support managerial decision-making within an organization. It involves the use of technology and various information systems to manage and analyze data for strategic planning, monitoring, and control.

One of the key components of an MIS is the creation and management of databases. Databases are structured collections of data that are organized, stored, and accessed in a systematic way. They serve as a central repository for storing relevant information that can be utilized by the MIS. These databases can contain data from various sources within the organization, such as sales records, customer information, inventory data, financial data, and more.

On the other hand, a TPS focuses primarily on the processing of transactions. It is designed to capture, process, and record day-to-day operational transactions, such as sales transactions, inventory updates, customer orders, and so on. While a TPS may store and retrieve data related to these transactions, its main focus is on efficiently processing and ensuring the accuracy and integrity of transactional data.

In summary, an MIS goes beyond the functionalities of a TPS by not only processing transactions but also creating and managing databases to support the informational needs of managers.

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Answer:

The actual pressure is 36.50

Step-by-step explanation:

Given that:

Tire pressure reading = 8% higher

Reading = 39.42

As 100% will be the actual reading.

New reading = (100+8)% = 108%

Let,

x be the actual pressure of the tire

108% of x = 39.42

\(\frac{108}{100}x=39.42\\1.08x = 39.42\)

Dividing both sides by 1.08

\(\frac{1.08x}{1.08}=\frac{39.42}{1.08}\\x=36.50\)

Hence,

The actual pressure is 36.50

Answer:

7x+29

Step-by-step explanation: