what is 2 1/5 hours coverted to minutes​

Walter can stay within his budget by dropping Fes (option ii).

Walter's original itinerary includes trips to Marrakech, Fes, Kenitra, and Oujda, which will cost him a total of 478 + 478 + 778 + 683 = MAD 2,417. This exceeds his budget of MAD 2,500.

Option i suggests replacing Kenitra with Tangier and Oujda with Casablanca, which will cost a total of 610 + 466 + 610 + 466 = MAD 2,152. However, this still exceeds Walter's budget.

Option iii suggests replacing Marrakech with Casablanca, which will cost a total of 965 + 466 + 778 + 683 = MAD 2,892, which is over Walter's budget.

Therefore, the only option that allows Walter to stay within his budget is to drop Fes from his itinerary, which will cost a total of 478 + 778 + 683 = MAD 1,939. This is well within his budget of MAD 2,500. So optio 2 is correct.

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Answer:

The number of balloons varies directly with the number of tables. The two variables are directly proportional. The relationship of balloons to tables is the ratio 5:1, where 5 is the constant of variation. Use the equation y = kx, where k is the constant of variation resulting in the equation y = 5x.

Step-by-step explanation:

i just did it

Answer:

Step-by-step explanation:

The number of balloons varies directly with the number of tables. The two variables are directly proportional. The relationship of balloons to tables is the ratio 5:1, where 5 is the constant of variation. Use the

Answer:

7

Step-by-step explanation:

7^2 =49

49 -21 =28

28÷7 = 4

Properties of Special right angled triangle,

a) If the leg of a 45°-45°-90° right triangle is x units, then the length of hypotenuse is x√2 units.

b) If a 30°-60°-90° right triangle the hypotenuse is twice the shorter leg, then longer leg is √3 times the shorter leg.

We have to discuss properties of special Right Triangles :

a) Properties of 45°-45°-90° Triangles : The sides of a 45°-45°-90° right triangle have a special relationship.

Example 1: If the leg of a 45°-45°-90° right triangle is x units, show that the hypotenuse is x√2 units.

Using the Pythagorean Theorem with

a = b = x, then c² = a² + b²

=> c² = x² + x²

=> c² = 2x²

=> c = √2x²

=> c = x√2

Thus, hypotenuse is x√2 units.

b) The sides of a 30°-60°-90° right triangle also have a special relationship.

Example 1: In a 30°-60°-90° right triangle the hypotenuse is twice the shorter leg. Show that the longer leg is √3 times the shorter leg.

∆MNQ is a 30°-60°-90° right triangle, and the length of the hypotenuse MN is two times the length of the shorter side NQ. Use the Pythagorean Theorem, c² = a²+ b²

let length of shorter side of ∆MNQ, NQ= x units, so, length of hypotenuse,MN = 2x

=> MN² = NQ² + MQ²

=> MQ² = MN² - NQ²

=> MQ² = (2x)² - x²

=> MQ² = 4x² - x² = 3x²

=> MQ = √3x²

=> MQ = √3 x = √3 NQ

So, longer side of right angled triangle is √3 times the short side.

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Complete question:

8-3 study guide and intervention special right triangles

a) Properties of 45°-45°-90° Triangles

b) Properties of 30°-60°-90° Triangles

Answer:

Step-by-step explanation:

<B = 360 - <A

<B = 360 - 170

<B = 190

There are two angles present, depending on which way you look at it. One is larger than 180 (the one we found) and the other is slightly less than 180 (the one you gave us).

The height of the ball 8 seconds after launch is approximately 1254 feet (rounded to the nearest tenth).

To find the height of the ball 8 seconds after launch we need to use the given velocity function f(t) = -32t + 284.

The height function can be obtained by integrating the velocity function with respect to time:

h(t) = ∫[f(t)] dt = ∫[-32t + 284] dt

Integrating -32t gives us\(-16t^2,\) and integrating 284 gives us 284t. Adding the constants of integration, we have:

\(h(t) = -16t^2 + 284t + C\)

To determine the value of the constant C, we can use the initial condition that the ball is launched from a height of 6 feet when t = 0:

\(h(0) = -16(0)^2 + 284(0) + C\)

6 = C

Therefore, C = 6, and the height function becomes:

\(h(t) = -16t^2 + 284t + 6\)

To find the height of the ball 8 seconds after launch, we substitute t = 8 into the height function:

\(h(8) = -16(8)^2 + 284(8) + 6\)

= -1024 + 2272 + 6

= 1254

Therefore, the height of the ball 8 seconds after launch is approximately 1254 feet.

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Alisa should either fill out a new ticket or write the correct amount and append her signature beside it.

A deposit ticket is a little paper where you are required to fill in the details of the deposit that you seek to make into your savings account. All information in the ticket ought to be filled accurately.

The teller may have declined to receive the ticket due to incorrect total amount filled on the ticket. Alisa should either fill out a new ticket or write the correct amount and append her signature beside it.

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Answer:

a. the subtotal is calculated incorrectly

Step-by-step explanation:

I'm good at math ;)

When analyzing the combined functions, it is important to consider their effects on the domain, range, transformations, and general shape of the original functions.

Regarding the domain and range, it depends on the specific operations performed on the original functions. If the operations do not introduce any restrictions or exclusions, the combined function's domain and range will remain the same as the original functions. However, if there are operations that limit the inputs or outputs, the domain and range of the combined function may differ from those of the original functions.

In terms of transformations, combining functions can involve horizontal and vertical translations. Horizontal translations (h) shift the functions left or right, while vertical translations (v) shift the functions up or down. These transformations affect the position of the functions' graphs. The combined function will inherit these transformations from the original functions, meaning that the translations applied to the individual functions will also apply to the combined function.

The general shape of the combined function is determined by the operations performed on the original functions. If the operations maintain the key characteristics of the original functions, such as their concavity, increasing or decreasing nature, or asymptotic behavior, the combined function will retain the general shape. However, if the operations significantly alter these characteristics, the combined function may deviate from the original shape.

In conclusion, when combining functions, the domain and range of the combined function can either remain the same as the original functions or change depending on the operations involved. The transformations, such as horizontal and vertical translations, applied to the individual functions will be inherited by the combined function. The general shape of the combined function will depend on whether the operations preserve or alter the key characteristics of the original functions.

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Area:-

Answer:

\(A=\boxed{10.5}\; \;\rm sq. \; un.\)

Step-by-step explanation:

Area of a Trapezoid

\(\boxed{A=\dfrac{1}{2}(a+b)h}\)

where:

From inspection of the given diagram:

Substitute the found values into the formula and solve for A:

\(\implies A=\dfrac{1}{2}(2+5)(3)\)

\(\implies A=\dfrac{1}{2}(7)(3)\)

\(\implies A=\dfrac{7}{2}(3)\)

\(\implies A=\dfrac{21}{2}\)

\(\implies A=10.5\; \;\rm sq. \; un.\)

Answer:

The original price drops by 15%.

Step-by-step explanation:

What was the drop in price?  To answer that, subtract $21.25 from $25, which results in $3.75.

Now compare $3.75 to the original price, $25, through division, as follows:

   $3.75

-------------- * 100% = 15%

     $25

The original price drops by 15%.

Answer:

7+n

Step-by-step explanation:

More indicates that we are adding an amount to n.

So since it is 7 more, we need to add 7 to n.

Note that an expression does not include an equal sign, so we are done.

Other commonly seen phrases are:

less than ->  indicates subtraction

product of -> indicates multiplication

divided by -> division

The values of x and y in the given system of equations are x = 4.00 and y = 5.00. These values are obtained by solving the system using the method of substitution.

The given system of linear equations is:

0.50x + 0.20y = 3.00 ...(Equation 1)

x + y = 9.00 ...(Equation 2)

To solve this system of equations, we can use the method of substitution or elimination. Let's solve it using the method of substitution:

From Equation 2, we can express x in terms of y:

x = 9.00 - y

Substituting this expression for x in Equation 1, we have:

0.50(9.00 - y) + 0.20y = 3.00

Expanding and simplifying:

4.50 - 0.50y + 0.20y = 3.00

-0.30y = -1.50

Dividing both sides by -0.30:

y = -1.50 / -0.30

y = 5.00

Now, substitute this value of y back into Equation 2 to find x:

x + 5.00 = 9.00

x = 9.00 - 5.00

x = 4.00

Therefore, the values of x and y in the given system of equations are x = 4.00 and y = 5.00.

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The area of the given polygon is 9 square units.

To find the area of the polygon with vertices A(3,3), B(3,6), and C(9,3), we can use the formula for the area of a triangle. Since the given points form a triangle, we can calculate the area of this triangle and consider it as the area of the polygon.

First, we need to find the base and height of the triangle. The base can be determined as the distance between points A and C, which is the horizontal distance between their x-coordinates. In this case, the base is 9 - 3 = 6 units.

Next, we find the height of the triangle, which is the vertical distance between point B and the line formed by points A and C. In this case, the height is the difference between the y-coordinate of point B and the y-coordinate of point A, which is 6 - 3 = 3 units.

Now, we can calculate the area of the triangle using the formula:

Area = (base * height) / 2

Area = (6 * 3) / 2 = 9 square units

Therefore, the area of the given polygon is 9 square units.

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Infinitely many position vectors with length 2 in xyz-space are orthogonal to the nonzero position vector v. (D)

A position vector in xyz-space is a vector that starts at the origin and ends at a point in xyz-space. The length of a position vector is the distance from the origin to the point it ends at.

If we want to find position vectors with length 2 that are orthogonal (perpendicular) to a given nonzero position vector v, we can use the dot product.

Let w be a position vector with length 2 that is orthogonal to v. Then, the dot product of v and w must be zero, since they are orthogonal. That is, v · w = 0. Since the length of w is 2, we can write w as 2u for some unit vector u. Thus, v · w = v · (2u) = 2(v · u) = 0.

This means that v and u are orthogonal as well, since the dot product of two vectors is zero if and only if they are orthogonal.

There are infinitely many unit vectors u that are orthogonal to v, and therefore, there are infinitely many position vectors with length 2 that are orthogonal to v. Therefore, the answer is (d) infinitely many.

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The answers are (a) probability of getting a total of two 5's, which is approximately 0.0463, or 4.63% and (b) probability of getting two 5's gives us the overall probability of getting at least two 5's, which is approximately 0.0510, or 5.10%.

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The "Explain" step of this part of the problem solving approach is option  C. The "Explain" step is to ensure that the result is reasonable.

In this particular step, the solution is examined critically to ascertain its relevance in the given problem scenario. This aids in detecting possible mistakes, assessing the practicality of the resolution, and guaranteeing that the solution matches the needs of the given problem.

The "Explain" step validates the solution, ensuring accuracy and reliability by reviewing each step. During "Explain", ensure accuracy of solution by identifying errors/mistakes in calculations, formulas or methods used.

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Answer:

x < -32

Step-by-step explanation:

Answer:

C. \(x^{3}\) - 4\(x^{3}\) - 24x + 21

Step-by-step explanation:

(x - 7)(\(x^{2}\) + 3x - 3)

x(\(x^{2}\) + 3x - 3) + -7(\(x^{2}\) + 3x - 3)

(\(x^{3}\) + 3\(x^{2}\) - 3x) + (-7\(x^{2}\) + -21x + 21)

\(x^{3}\) - 4\(x^{3}\) - 24x + 21

Answer:

2x+4

Step-by-step explanation:

that is your answer

Each transformation affects the shape and position of the graph. It is important to carefully consider the order of the transformations and their impact on the equation.

1. Horizontal Shift (c):
If there is a horizontal shift, the equation becomes y = (x - c)^3.
For example, if there is a shift of 2 units to the right, the equation would be y = (x - 2)^3.

2. Vertical Shift (d):
If there is a vertical shift, the equation becomes y = x^3 + d.
For example, if there is a shift of 3 units upwards, the equation would be y = x^3 + 3.

3. Vertical Stretch (a):
If there is a vertical stretch or compression, the equation becomes y = a * x^3.
For example, if there is a vertical stretch by a factor of 2, the equation would be y = 2 * x^3.

4. Reflection (along the x-axis):
If there is a reflection along the x-axis, the equation becomes y = -x^3.
This flips the graph of the original function upside down.

5. Reflection (along the y-axis):
If there is a reflection along the y-axis, the equation becomes y = (-x)^3.
This mirrors the graph of the original function.

6. Combined Transformations:
If there are multiple transformations, we can apply them in the order they are given. For example, if there is a vertical stretch by a factor of 2 and a horizontal shift of 3 units to the right, the equation would be y = 2 * (x - 3)^3.

Remember, each transformation affects the shape and position of the graph. It is important to carefully consider the order of the transformations and their impact on the equation.

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Answer:

x=9

y=-5

Or

(9,-5)

Step-by-step explanation:

-x+y=-14

+x.    +x

y=x-14

2x-3(x-14)=33

2x-3x+42=33

-x+42=33

   -42. -42

-x=-9

/-1. /-1

x=9

-(9)+y=-14

+9.      +9

y=-5

Hopes this helps please mark brainliest

Answer:

the answer is c

Step-by-step explanation:

The correctly punctuated sentence is "The students line up in the afternoon to wait for the buses to arrive."

Punctuation is the use of proper spacing and punctuation marks to enchance the readability and understanding of a text.  

Types of punctuation marks:

The rules of using a comma in a sentence:

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In context of "group-diversity", a contributor is "data-driven", supplies the "necessary-information", and adheres to the high "performance-standards".

They actively contribute to the group's goals and objectives, bringing their expertise, skills, and knowledge to the table. A contributor may provide valuable insights and data-driven analysis regarding diversity-related matters, helping the group make informed decisions and take appropriate actions.

They are committed to achieving high performance standards and consistently deliver quality work. In the context of diversity, a contributor may actively participate in promoting inclusivity, supporting diverse perspectives, and advocating for equal opportunities within the group or organization.

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When the function f(x) =\(3(5^x)\) is written in the form .Answer is f(x) = \(3(e^_(ln 5))^ _(1/x)f(x)\)

= \(3*5^ (1/x)\)

When the function f(x) =\(3(5^x)\) is written in the form

f(x) = \(3e^_kx\). It is said that the function has been written in exponential form.

A function is a relation that specifies a single output for each input. For example, f(x) = x + 2 is a function that assigns to every value of x, the corresponding value of x + 2.f(x) :

A function is usually denoted by 'f' and is followed by a bracket containing the variable or the independent quantity, i.e., x. Thus f(x) represents a function of x.
Example: f(x) = 2x + 1
The form is the structure or organization of the function in terms of its function rule. The function rule describes the relationship between the input (independent variable) and the output (dependent variable).

Exponential Form: A function f(x) is written in exponential form if it can be expressed as \(f(x) = ab^x\), where a, b are constants and b > 0, b ≠ 1. For example, f(x) =\(2*3^x\) is written in exponential form.

f(x) = \(3(5^x)\)

To write this function in exponential form, we need to express it in the form f(x) = \(ab^x\), where 'a' is a constant and 'b' is a positive number. Here, 'a' is 3 and 'b' is 5, so the exponential form of the function is:

f(x) =\(3(5^x)\)

= \(3e^_(kx)\)

Comparing both the equations, we can write that b = \(e^k\) and

5 =\(e^(kx)\).

Now, we have to solve for the value of k.
To solve for k, take natural logarithm on both sides.
Therefore:ln 5 =\(ln (e^_(kx))\)

Using the property of logarithms that ln(e^x) = x, we can write it as:

ln 5 = kx ln e

So, we can write it as:ln 5 = kx * 1Since ln(e)

= 1,

we can write that:k = ln 5 / x
Hence, the exponential form of the function is:

f(x) =\(3e^_(ln 5 / x)\)
which can be further simplified to:

f(x) =\(3(e^_(ln 5))^_ (1/x)f(x)\)

=\(3*5^ _(1/x)\)

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If In a class of 29 students, 19 are female and 14 have an A in the class then 2 male students have an A in the class.

We can calculate the number of students who are male and have an A in the class by subtracting the given values from the total number of students.

Total students = 29

Female students = 19

Male students = Total students - Female students = 29 - 19 = 10

Students with an A = 14

Male students without an A = 8

To calculate the number of male students with an A, we subtract the number of male students without an A from the total number of male students.

Male students with an A = Male students - Male students without an A = 10 - 8 = 2

Therefore, there are 2 male students who have an A in the class.

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Answer:

\(k=-3\)

Step-by-step explanation:

Since the line passes through the origin, it must be a proportional/direct variation equation.

Direct variation equations have the form:

\(y=ax\)

Where a is the constant of proportionality.

Let’s solve for a. We know that when x=5, y=40. So:

\(40=5a\)

Divide both sides by 5:

\(a=8\)

Therefore, our equation is:

\(y=8x\)

We want to find the value of k such that y=-24. So, subsitute -24 for y and k for x:

\(-24=8k\)

Divide both sides by 8:

\(k=-3\)

Hence, the value of k is -3.