what is 100 ft. converted to KM

Answer:

a) 2.0 x 10^5

b) 8.0 x 10^4

c) 9 x 10^9

d) 1 x 10^10

Answer:

A

Step-by-step explanation:

I think

The two equations with infinite solutions are D 3(x – 1) = 3x – 3 and E2x + 2 = 2(x + 1)

An equation has infinite solutions if we can remove the dependence of the variable, and we end with a true equation.

For example, option D is:

3(x - 1)  =3x - 3

Expanding the left side:

3x - 3 = 3x - 3

Subtract 3x in both sides:

-3 = -3

That is true for any value of x.

The other correct option is E:

2x + 2 = 2(x + 1)

2x + 2 = 2x + 2

2 = 2

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An equation of the tangent line to curve [y = e⁶ˣ cos x] at the given point  (0, 1) is y = x + 6.

At a given point, the tangent line of a curve is a line that really just contacts the curve (function). In calculus, the tangent line may connect the curve at any other point(s), and it may also cross the graph at any other point(s).

Now, as per the given question;

Because of this, point (0,1) is a tangent point;

y = f((0) = e⁰cos0 = 1.

We differentiate to get the slope of the tangent line m. Tangent line equation:

y' = 6e⁶ˣcosx - e⁶ˣ sinx;

Thus, the slope of the curve becomes;

m = f'(0) = 6.

Substituting the values of slope and coordinates (0, 1).

y = 6 + 1(x - 0),

Simplifying the equation.

y = x + 6

Thus, the equation of the tangent line to the given curve is y = x + 6.

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Answer:

independent

Step-by-step explanation:

independent

Answer:

10 yards (Add label!!)

Step-by-step explanation:

5x1/2=10

Clare can make 10 bows with ribbon.

The division in mathematics is one kind of operation. In this process, we split the expressions or numbers into the same number of parts.

Given:

Clare has 5 yards of ribbon.

It takes 1/2 yard to make a bow.

The number of bows = 5 ÷ 1/2 {division equation}

The number of bows = 5 x 2/1 = 10 {multiplication equation}

Therefore, the number of bows is 10.

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Step-by-step explanation:

B = J + 3

hope this helps. have a great day

The value of x from the equation is 1

The value of y from the equation is 7

-5x+2y= 9............equation 1

y= 7x...............equation 2

Substitute 7x for y in equation 1

-5x + 2(7x) = 9

-5x + 14x= 9

9x= 9

x= 9/9

x= 1

Substitute 1 for x in equation 2

y= 7x

y= 7(1)

y= 7

Hence the value of x is 1 and the value of y is 7

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In this problem, we have a binomial probability distribution

so

n=3

p=0.50

q=0.50

Find out P(X=2)

The percentage of the original activity that remains after 17.5 days, you can use the formula: Remaining percentage = \((1/2)^{(17.5/t)} * 100\), where "t" represents the half-life of the sample.

To calculate the percentage of the original activity that remains after 17.5 days, we can use the concept of half-life. The half-life is the time it takes for half of the radioactive substance to decay.
Let's assume that the half-life of the sample is "t" days.
To find the percentage of the original activity that remains after 17.5 days, we need to determine the number of half-lives that have passed. We can do this by dividing the given time (17.5 days) by the half-life (t).
Once we know the number of half-lives, we can use the formula:
Remaining percentage =\((1/2)^{(number of half-lives)} * 100\)
Since the sample has decayed to half its original activity after one half-life, the remaining percentage after 17.5 days can be calculated as:
Remaining percentage =\((1/2)^{(17.5/t) }* 100\)
This formula calculates the percentage of the original activity that remains after 17.5 days, taking into account the specific half-life of the sample.
To find the percentage of the original activity that remains after 17.5 days, you can use the formula: Remaining percentage = \((1/2)^{(17.5/t)} * 100\), where "t" represents the half-life of the sample.

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The roots of h(x)=x³−2x²+9x−18 is 2, -3i and 3i.

The breaking or decomposition of an entity (such as a number, a matrix, or a polynomial) into a product of another entity, or factors, whose multiplication results in the original number, matrix, etc., is known as factorization or factoring in mathematics.

Given:

h(x)=x³−2x²+9x−18

so, (x-2) is the solution of h(x).

Now, the synthetic division

                                  (x-2) | x³−2x²+9x−18 | x² + 9

                                            x³ −2x²

                                      __________

                                                0   + 9x - 18

                                                         9x - 18

                                                     __________

                                                               0

now, again factorize x² + 9 = 0

 x = ±3i

Hence, the roots are 2, -3i and 3i.

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Answer:

Step-by-step explanation:

35368

Answer:

16.5

Step-by-step explanation:

16+1/2

When we have negative exponents, we can move the term with the exponent to the bottom of the fraction. This is also known as multiplying by the reciprocal (and changing the negative exponent to be positive!).

The reciprocal of z^-3 would be 1 / z^3.

Hope this helps!! :)

A plot that will present the information that will highlight how many trees are in a range of heights, such as 60–64, 65–69, etc. : histogram

In this question, we have been given the tree heights recorded on a school campus.

A science teacher wants to choose a data display that will highlight how many trees are in a range of heights, such as 60–64, 65–69, etc.

We need to find a correct plot that will present the information in this way.

We know that in bar charts, each bar represents one value(category). And  in a histogram, each bar will represent a continuous data

Therefore, a plot that will present the information that will highlight how many trees are in a range of heights, such as 60–64, 65–69, etc. : histogram

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Answer:

Step-by-step explanation:

A plot that will display information highlighting the number of trees in a range of heights, such as 60-64, 65-69, and so on: histogram

We were provided the tree heights reported on a school grounds in this question. A science instructor needs to select a data presentation that will show how many trees are in a given height range, such as 60-64, 65-69, and so on. We must find a suitable plot to portray the data in this manner. We know that each bar on a bar chart represents one value (category). And each bar in a histogram represents continuous data.

Finding the missing number from the first 100 numbers in the given array arr[] of size N-1 with integers in the range [1, N] is the task. The list doesn't contain any duplicates.

Java method for locating a missing integer in an array of integers from 1 to 100

class GFG; import java.io.*; import java.util.*

public static void findMissing(int arr[], int N)

{

 int i;

 int temp[] = new int[N + 1];

 for (i = 0; i <= N; i++) {

  temp[i] = 0;

 }for (i = 0; i < N; i++) {

  temp[arr[i] - 1] = 1;

 } int ans = 0;

 for (i = 0; i <= N; i++) {

  if (temp[i] == 0)

   ans = i + 1;

 } System.out.println(ans);

}

public static void main(String[] args) {

 int arr[] = { 1, 3, 7, 5, 6, 2 };

 int n = arr.length; // Function call

 findMissing(arr, n);

}

}

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To correctly substitute the values a, b, and c from the equation 1 = –2x + 3x^2 + 1 into the quadratic formula, we can follow these steps:

1. Identify the coefficients of the quadratic equation. In this case, a = 3, b = -2, and c = 1.

2. Use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a).

3. Substitute the values of a, b, and c into the formula:
x = (-(-2) ± √((-2)^2 - 4(3)(1))) / (2(3)).

4. Simplify the equation:
x = (2 ± √(4 - 12)) / 6.
  = (2 ± √(-8)) / 6.

5. Notice that the expression inside the square root (√(-8)) is negative, indicating that there are no real solutions to the equation.

when we substitute the values a = 3, b = -2, and c = 1 from the equation 1 = –2x + 3x^2 + 1 into the quadratic formula, we find that there are no real solutions.

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Answer:

y = -28x²

Step-by-step explanation:

\({ \bf{ {y} = 4a {x}^{2} }} \\ { \tt{y = - 28 {x}^{2} }}\)

The amount of time that passes between iterations of the same behavior can vary depending on the specific behavior and the individual or situation involved. However, there is no specific time frame that can be universally applied to all behaviors.

When examining the frequency of a behavior, it is important to consider factors such as the complexity of the behavior, the availability of resources, and the motivation or reinforcement associated with the behavior. Additionally, individual differences and external influences can also affect the time between iterations of a behavior.

To determine the time between iterations, one can observe and record the occurrences of the behavior over a specific period. By analyzing the data collected, patterns can emerge, providing insights into the timing and frequency of the behavior.

In conclusion, the time between iterations of the same behavior is not fixed and can vary depending on various factors. Observing and recording the behavior over a period of time can help determine the frequency and time frame of the behavior.

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Answer:

Well there isn't really a question

Step-by-step explanation:

y=3x means anything on the x axis times 3 = the number on the y axis. This is an example of an proportional relation ship and will create a straight line on a graph.

The results generated in the map phase are combined in the _reduce_ phase.

In maps, the "reduced phase" refers to a technique used to remove the phase ambiguity present in interferometric synthetic aperture radar (InSAR) data. InSAR uses radar to measure the distance between a satellite or aircraft and the ground and can be used to create detailed maps of changes in the surface of the earth over time.

However, because InSAR data is collected using radar waves, which are sensitive to the phase of the signal, the data can be affected by phase ambiguities. The reduced phase technique is used to remove these ambiguities and create more accurate maps.

Therefore, The results generated in the map phase are combined in the _reduce_ phase.

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The area of region R2 is (sqrt(13)-1)/8 square units. To find the area of region R1, we need to integrate the difference between the two curves with respect to x. The curves intersect when 2x2 = 3 - x, which simplifies to 2x2 + x - 3 = 0. Solving for x, we get x = \((sqrt(13)-1)/4\)or x = (-sqrt(13)-1)/4. Since we only care about the positive value, the intersection point is x =\((sqrt(13)-1)/4.\)

So, the area of region R1 is given by:

∫[0,(sqrt(13)-1)/4] (3-x - \(2x^2\)) dx

Using the power rule and evaluating at the limits of integration, we get:

(3(sqrt(13)-1)/4) - (2(sqrt(13)-\(1)^3\)/48) = (3sqrt(13)-11)/12

Therefore, the area of region R1 is (3sqrt(13)-11)/12 square units.

B) To find the area of region R2, we can see that it is a triangle with height equal to the y-coordinate of the intersection point between y=\(2x^2\) and y=3-x (which we found in part A) and base equal to the x-coordinate of the intersection point. So, the area of region R2 is:

(1/2) [(sqrt(13)-1)/4] [2(sqrt(13)-1)/4] = (sqrt(13)-1)/8

Therefore, the area of region R2 is (sqrt(13)-1)/8 square units.

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Answer: The answer is 3

Step-by-step explanation:

Hope this helps you! Have a good day! :)

Answer: 6

Step-by-step explanation:

384,000 bacteria would be present at the end of 7 hours if it doubles itself every hour.

Initial number of bacteria=3000

Number of bacteria at the end = initial number of bacteria * (base)ⁿ

where, n= number of hours

Number of bacteria at the end=3000*2⁷

                                                    =3000*128

                                                     =384,000

Therefore, there will be 384000 bacteria at the end of seven hour if the bacteria doubles itself every hour.

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Answer: A

Step-by-step explanation

2.167x10^4 = 21,670

                   = 9,978

1.1x10^6      = 1100,000

                   = 56,344,000

2.468x10^5 =  246,800

Answer: A. 9,978

Based on the power, move the decimal point that many spaces to the right. (E.g., If it's 4.2 × 10^3, then move the decimal three spaces to the right, and you'd get 4200.)

2.167 × 10^4 = 21670

1.1 × 10^6 = 1100000

2.468 × 10^5 = 246800

Out of all the numbers mentioned in the question, 9,978 is the only one that's less than 2.167 × 10^4 = 21670.

Question 5

1) Given

2) Definition of congruent segments

3) Reflexive property of equality

4) Addition property of equality

5) Substitution

6) Commutative property of addition

7) Segment addition postulate

8) Substitution

9) Segments with equal measure are congruent

Question 6

1) Given

3) Segment addition postulate

4) Substitution

5) Subtraction property of equality

7) SSS