This is necessary in the calculation of the shape of the orbitals. In simple terms, the motion of an electron plays a significant role in defining its shape.
To determine the general shape of an orbital, it is necessary to have some information. These are:Electron Quantum Numbers: This comprises four numbers (n, l, m, and s) that offer info regarding the electron’s state in an atom. They are needed for the specification of the type of orbital. While n offers the size, l offers the shape, and m offers the orientation of the orbital.
Wave Functions: These depict how a wave function can be used to explain the position of an electron in an atom. While the probability of finding the electron in a particular region is linked to the absolute value of the wave function squared, the wave function itself offers details regarding the wave's behavior. Orbital Diagrams: The electrons' distribution in an atom can be portrayed using orbital diagrams.
The shape of an orbital can be determined by considering the diagrams, and how the electrons are organized within the subshells. Angular Momentum: This refers to the electron's motion, which takes place in three directions. This is necessary in the calculation of the shape of the orbitals. In simple terms, the motion of an electron plays a significant role in defining its shape.
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The shape of an orbital is primarily determined by the angular momentum quantum number (l). This, along with the principal quantum number (n), which defines the energy level and distance from the nucleus, and the orientation quantum number (m), which defines the orientation of the orbitals, are used to describe the properties of the orbital.
Explanation:To determine the general shape of an orbital, you need to understand some specific quantum numbers. These include the principal quantum number (n), the angular momentum quantum number (l), and the orientation quantum number (m).
The principal quantum number, n, determines the energy level of the electron and the probable distances that the electron can be from the nucleus. The angular momentum quantum number, l, specifies the shape of the orbital. Orbitals of the same n and l have the same general shape. Lastly, the orientation quantum number, m, defines the the orientation of the orbitals of the same l value with respect to one another.
So, to determine the shape of an orbital, we primarily look at the l quantum number. For example, if l=0, the orbital is spherically symmetrical and known as an 's' orbital. If l=1, the orbital has a two-lobed shape and is known as a 'p' orbital. If l=2, the orbital is a 'd' orbital and so forth.
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how far will a rock travel if it is thrown upward at an angle of 35.00 with respect to the horizontal and with a speed of 21.3 m/s? what is the maximum range that can be achieved with the same initial speed?
The maximum range that can be achieved with the same initial speed is 69.6 m.
The distance that a rock will travel when thrown upward at an angle of 35.00 with respect to the horizontal and with a speed of 21.3 m/s is determined by the equations of projectile motion.
The maximum range that can be achieved is calculated by using the equation for the range of a projectile, which is R = (V2sin2θ)/g,
where V is the initial speed (21.3 m/s in this case), θ is the angle with respect to the horizontal (35.00 in this case), and g is the acceleration due to gravity (9.8 m/s2). The range can be calculated to be 69.6 m.
The motion of the rock can be broken down into two components:
the vertical component, which is determined by the equation h = (Vsinθ)t - ½gt2, and the horizontal component, which is determined by the equation x = Vcost.
The maximum height that the rock reaches is calculated by substituting t = (Vsinθ)/g into the equation for the vertical component, resulting in hmax = (V2sinθ)/2g.
As the rock falls back to the ground, the time taken for it to reach the ground is calculated by substituting hmax into the equation for the vertical component, resulting in ttotal = 2(Vsinθ)/g.
The range of the projectile is then calculated by substituting ttotal into the equation for the horizontal component, resulting in the equation for the range of a projectile given above.
The distance that a rock will travel when thrown upward at an angle of 35.00 with respect to the horizontal and with a speed of 21.3 m/s is determined by the equations of projectile motion,
and the maximum range that can be achieved with the same initial speed is 69.6 m.
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b. Local action and polarization
Explanation:
The local action of a battery is the deterioration of the battery due to currents that are flowing from and to the same electrode. ... Polarization is a defect that occurs in simple electric cells due to the accumulation of hydrogen gas around the positive electrode.
A train has an initial velocity of 44meter per second and an acceleration of 4meter per second caculate it's velocity after 10 second
A train has an initial velocity of 44meter per second and an acceleration of 4meter per second.The final velocity after 10 seconds is 84m/s.
As we know,
Acceleration= Final velocity-Initial velocity /time.
where acceleartion = a=4m/s².
Initial velocity= u= 44m/s
let final velocity be v
Time =t = 10seconds.
Therefore, the equation is:
a=v-u/t
Substituting the values in the given equation, we get:
4=v-44/10
Now cross multiplying,
4×10 = v-44
40=v-44
40+44=v
v=84m/s
Therefore, the final velocity after 10 seconds is 84m/s.
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if you want to make 4 ml of 2.5 mg/l nitrogen and 0.1 mg/l phosphorus solution by using 100mg/l nitrogen stock and 50mg/l phosphorus stock, how much volume of the each stock do you need?
We need 0.1 ml of a 100 mg/l nitrogen stock solution and 8 µl of a 50 mg/l phosphorus stock solution.
For nitrogen: The final concentration of nitrogen should be 2.5 mg/l and we have a 100 mg/l stock solution. We need to dilute the stock solution 100/2.5 = 40 times. So, the volume of the nitrogen stock solution required will be (4 ml / 40) = 0.1 ml.
For phosphorus: The final concentration of phosphorus should be 0.1 mg/l and we have a 50 mg/l stock solution. Dilute the stock solution 50/0.1 = 500 times. So, the volume of the phosphorus stock solution required will be (4 ml / 500) = 0.008 ml or 8 µl.
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Energy is defined as ____________.
The ability of an object to produce a change in the environment or itself
motion
the effort required to perform work
power
Answer:
The effort required to perform work
Explanation:
True/False
1.lenses bend light by reflection- true/false
2.converging lenses bring rays of light to a point - true or false
3.light bends towards the normal when it goes from air to glass - true/false
4.light bends away from the normal when it goes from air to water - true/false
Answer:
True
Explanation:
A 22.5-kg mass was set on a spring whose spring constant was 563 newtons per meter. How far was the spring compressed?(a) 0.0400 m(b) 0.196 m(c) 0.392 m(d) 2.55 m
a person starts from his home and walks the following distances: i) 1500 yards, 50° n of e ii) 1800 yards, 50° w of n iii) 1000 yards, due south how far is the person from his home?
To determine the total distance from the person's home, we can use vector addition to combine the individual displacements.
i) Distance: 1500 yards
Direction: 50° north of east
ii) Distance: 1800 yards
Direction: 50° west of north
iii) Distance: 1000 yards
Direction: Due south
To calculate the total distance from the home, we need to resolve the displacements into their north-south and east-west components.
i) For the first displacement:
North component: 1500 yards * sin(50°)
East component: 1500 yards * cos(50°)
ii) For the second displacement:
North component: 1800 yards * cos(50°)
West component: 1800 yards * sin(50°)
iii) For the third displacement:
South component: 1000 yards
Next, we can add up the north-south and east-west components separately.
North component: (1500 yards * sin(50°)) + (1800 yards * cos(50°))
South component: 1000 yards
East component: 1500 yards * cos(50°) - 1800 yards * sin(50°)
West component: 0
Finally, we can use the Pythagorean theorem to find the total distance from the home:
Total distance = √((North component)^2 + (South component)^2 + (East component)^2 + (West component)^2)
Substituting the calculated values into the formula will give us the total distance from the home.
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Three two-port circuits, namely Circuit 1 , Circuit 2 , and Circuit 3 , are interconnected in cascade. The input port of Circuit 1 is driven by a 6 A de current source in parallel with an internal resistance of 30Ω. The output port of Circuit 3 drives an adjustable load impedance ZL. The corresponding parameters for Circuit 1, Circuit 2, and Circuit 3, are as follows. Circuit 1: G=[0.167S0.5−0.51.25Ω] Circuit 2: Circuit 3: Y=[200×10−6−800×10−640×10−640×10−6]S Z=[33534000−3100310000]Ω a) Find the a-parameters of the cascaded network. b) Find ZL such that maximum power is transferred from the cascaded network to ZL. c) Evaluate the maximum power that the cascaded two-port network can deliver to ZI.
a) The A-parameters of the cascaded network are defined by (4 points)Answer:a_11 = 0.149 S^0.5 - 0.0565a_12 = -0.115 S^0.5 - 0.0352a_21 = 136 S^0.5 - 133a_22 = -89.5 S^0.5 + 135b) Find ZL such that maximum power is transferred from the cascaded network to ZL. (2 pointsZ). The maximum power transfer to load impedance ZL occurs when the load is equal to the complex conjugate of the source impedance.
We can calculate the source impedance as follows: Rs = 30 Ω || 1/0.167^2 = 31.2 ΩThe equivalent impedance of circuits 2 and 3 connected in cascade is: Zeq = Z2 + Z3 + Z2 Z3 Y2Z2 + Y3 (Z2 + Z3) + Y2 Y3If we substitute the corresponding values: Zeq = 6.875 - j10.75ΩNow we can determine the value of the load impedance: ZL = Rs* Zeq/(Rs + Zeq)ZL = 17.6 - j8.9Ωc) Evaluate the maximum power that the cascaded two-port network can deliver to ZI. (2 points). The maximum power that can be delivered to the load is half the power available in the source.
We can determine the available power as follows: P = (I_s)^2 * Rs /2P = 558 mW. Now we can calculate the maximum power transferred to the load using the value of ZL:$$P_{load} = \frac{V_{load}^2}{4 Re(Z_L)}$$$$V_{load} = a_{21} I_s Z_2 Z_3$$So,$$P_{load} = \frac{(a_{21} I_s Z_2 Z_3)^2}{4 Re(Z_L)}$$Substitute the corresponding values:$$P_{load} = 203.2 m W $$. Therefore, the maximum power that can be delivered to the load is 203.2 mW.
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are two quantities considered to be “directly proportional” and “indirectly
proportional” to each other?
brainliest for answer
Yes, two quantities are considered to be “directly proportional” and “indirectly proportional” to each other.
What are “directly proportional” and “indirectly proportional”?The term “directly proportional” refers to the relationship between two quantities when one factor increases the other factor or quantity is also increases while on the other hand, “indirectly proportional” refers to the relationship between two quantities when one factor increases the other factor or quantity is decreases. Indirectly proportional is also known as inversely proportion because one increases and the other increases.
So we can conclude that Yes, two quantities are considered to be “directly proportional” and “indirectly proportional” to each other.
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a 26.0-g object moving to the right at 19.0 cm/s overtakes and collides elastically with a 11.0-g object moving in the same direction at 15.0 cm/s. find the velocity of each object after the collision.
The velocity of first object after the collision is 16.62cm/s and the velocity of second object after collision is 32.783cm/s.
Given initial mass of object (m1) = 26g = 26x10-3kg
initial velocity of object (u1) = 19cm/s = 0.19m/s
mass of second object (m2) = 11g = 11x10-3kg
initial velocity of second object (u2) = 15cm/s = 0.15m/s
Let the velocity of first object after collision = v1
the velocity of second object after collision = v2
These objects are elastically collided. Then from law of conservation of momentum we can see that m1u1+m2u2 = m1v1+m2v2
Here kinetic energy is also conserved. Then
1/2m1u1^2 + 1/2m2u2^2 = 1/2m1v1^2 + 1/2m2v2^2
Then v1 = (m1-m2)/(m1+m2)×v1 + 2×m2/(m1+m2)×v2
v1 = (26-11)/(26+11)×(19) + 2×(11)/(26+11)×(15)
v1 = 7.702 + 8.918 = 16.62cm/s
Then v2 = 2×m1/(m1+m2)×v1 + (m2-m1)/(m1+m2)×v2
v2 = 2×(26)/(26+11)×(19) + (11-26)/(26+11)×(15)
v2 = 26.702 + 6.081 = 32.783cm/s
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Starting from rest a car travels a distance 60km at a uniform acceleration of 2ms-2. How much time it takes?
Answer:
t = 30000 seconds
Explanation:
Given that,
Initial velocity of the car, u = 0
Final velocity of the car, v = 60 km = 60000 m
The acceleration of the car, a = 2 m/s²
W need to find the time taken by the car. The acceleration of the object is given by :
\(a=\dfrac{v-u}{t}\)
or
\(t=\dfrac{v-u}{a}\\\\t=\dfrac{60000-0}{2}\\\\t=30000\ s\)
So, the required time is 30000 seconds.
why water is optically denser than air
Answer: Speed of light in air is more than speed of light in water, which means water is optically denser than air.
Answer:
There
Explanation:
A medium is denser when the speed of light gets reduced when light travels through that medium. When water travels through water, its speed gets reduced. Hence, it is a optically denser medium. Speed of light in air is more than speed of light in water, which means water is optically denser than air.
The deflection produced by the Coriolis force is caused by O the Earth's rotation on its axis. O differing pressure gradients. O air temperature differences. O the uneven heating of Earth's surface. O friction caused by gravitational force.
The Planet on its axis often contributes to the deflection created by the Coriolis force.
Coriolis force: what is it?Moving objects in a reference point that rotates relative to an inertial frame are affected by an imagined or inertial force known as the Coriolis force. the force acting left of a object . an object in a frame of reference rotating in a clockwise direction.
Rotation: Rotation, often known as spin, is the cyclical motion of an object about a fundamental axis.
A two-dimensional rotating object can only have one possible central axis.
Such things have an axis that may rotate either counterclockwise or clockwise.
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A baseball coach shouts loudly at an umpire standing 2.7 m away. If the sound power produced by the coach is 14.58 ✕ 10-3 W, what is the decibel level of the sound when it reaches the umpire? (Hint: Use the table below.)
The formula for calculating the speed of sound is speed of sound = square root. 67.9 dB is the decibel level of the sound when it reaches the umpire
What is the dB formula?A decibel (0.1 bel) is equivalent to ten times the common logarithm of the power ratio. S1 and S2 are the strengths of the two sounds, and 10 log10 (S1/S2) is a mathematical expression for the intensity of a sound .Doubling a sound's intensity results in an increase of little more than 3 dB.
Calculation:PART A)
L = 97.4 dB
PART B)
I = 6.11 × 10⁻⁶W/m²
PART C)
L = 67.9 dB
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The properties of metals depend mainly on the number and arrangement of neutrons
True
False
Answer:
False
Explanation:
Electrons
Which term is defined by the force that moving, charged particles exert on one another?.
Electromagnetic force is the force that moving, charged particles exert on one another.
What is Electromagnetic force?The electromagnetic force acting between the electrically charged atomic nuclei and electrons of the atoms can explain all the forces involved in interactions between atoms.Additionally, electromagnetic forces account for how these particles move with momentum. This includes the forces we feel when "pushing" or "pulling" commonplace material items, which are caused by the intermolecular forces acting between the molecules in the objects and the individual molecules in our bodies.All types of chemical phenomena involve electromagnetic force. The study of the electromagnetic force, a sort of physical interaction that takes place between electrically charged particles, is at the heart of the area of physics known as electromagnetism.Electric fields and magnetic fields combine to form electromagnetic fields, which carry electromagnetic force.To learn more about Electromagnetic force with the given link
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peer meditation definition
how far should an object be from a converging mirror of radius 36cm to form a real image one - ninth of its size
Answer:
focal length :
\({ \tt{f = \frac{r}{2} }} \\ focal \: length = \frac{36}{2} = 18 \: cm\)
From linear magnification:
\({ \tt{ \frac{1}{m} + 1 = \frac{u}{f} }} \\ \frac{1}{9} + 1 = \frac{u}{18} \\ \\ u = \frac{18 \times 10}{9} \\ u = 20 \: cm\)
The object must be at 20 cm
While participating in a blood drive at school, Keona learns that blood has a density of 1.06 g/mL. She donates one pint of blood, which is equal to 473.176 mL.
The mass of the blood denoted is 501.6 g.
What is the mass of the blood she denoted?The mass of the blood denoted by Keona is calculated by applying the formula for density of a liquid as shown below.
density = mass/volume
mass = density x volume
The given parameters include;
density of the blood = 1.06 g/mLvolume of the blood, = 473.176 mLThe mass of the blood is calculated as follows;
mass = 1.06 g/mL x 473.176 mL
mass = 501.6 g
Thus, the mass of the blood is calculated from the formula of density.
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The complete question is below
While participating in a blood drive at school, Keona learns that blood has a density of 1.06 g/mL. She donates one pint of blood, which is equal to 473.176 mL. find the mass of the blood denoted.
A fully charged capacitor initially has an air gap and is disconnected from the battery. A dielectric material is inserted between the plates
What happen to the free charge at surface of the capacitor plates and the total charge free and bound at the surface of the capacitor plates?
The total charge (free and bound) at the surface of the capacitor plates will be equal to the initial charge on the capacitor, minus the amount of charge that has been transferred to the dielectric material.
What is the dielectric ?A dielectric is an electrical insulator material which can be polarized by an electric field. It is a material that is used to increase the capacitance of an electrical circuit, allowing for a greater flow of electric current. Dielectrics are commonly used in capacitors, where the material separates two conducting plates, allowing a charge to build up between them. They are also used in electric motors, generators, and other electric components. Dielectrics are typically made from a variety of materials including glass, plastic, ceramic, and rubber.
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What is simple and composite signal?
Answer:
Periodic analog signals can be classified as simple or composite. A simple periodic analog signal, a sine wave, cannot be decomposed into simpler signals. A composite periodic analog signal is composed of multiple sine waves.
Explanation:
hope this helps!
Hence, the force of gravitation between Earth and Jupiter is 8.16 * 10 N
Enample 5: An apple with the mass of 200 g falls from a tree. What is the acceleration
of the apple towards the earth? What is the acceleration of the earth towards the apple?
(Given: mass of the earth = 6*10kg radius of the earth 6.4 10 m, G=6.67 * 10 " Nm
kg and neglecting height of the tree).
Answer:
Acceleration of the apple towards the earth is: 9.7705 m/s2.
Acceleration produced on earth towards the apple
\(0.325*10^{-24} \ \ m/s2.\)
Explanation:
Given :
\(m = 200 g\)
We have to convert into the kg ,
so
\(m=0.2 kg\)
M=\(6*10^{24}\) kg
\(R=6.4*10^{6} m\)
\(G= 6.67*10^{-11} \ Nm^{2} kg-2\)
As the gravitational force is existing among the earth and the apple
so
\(F=\frac{GMm}{R^{2} }\)
Putting the value of G,M,m and \(R^{2}\), we get
\(\frac{6.67*10^{-11} *6*10^{24} *0.2 }{(6.4*10^{6} )^{2} } \\\\F= 1.9541\ N\)
Consider a1 and a2 be a acceleration due to the gravitational force of earth attraction created on the apples
F= a1 *m
\(a1\ =\ \frac{F}{m}\)
a1=\(\frac{1.9541}{0.2}\)
\(a1=9.7705 \ m/s2\)
Acceleration of the apple towards the earth is: 9.7705 m/s2.
again
\(F= a2 *M\)
a2=\(\frac{F}{M}\)
\(a2=\frac{ 1.9541}{6**10^{24} } \\a2=0.325* 10^{-24}\ m/s2\)
So, Acceleration produced on earth towards the apple
\(0.325*10^{-24} \ \ m/s2.\)
Thirteen resistors are connected across points A and B as shown in the figure. If all the resistors are
accurate to 2 significant figures, what is the equivalent resistance between points A and B?
The equivalent resistance between points A and B in the diagram is 22 Ω
How do I determine the equivalent resistance?We shall begin by obtaining the equivalent resistance in parallel (i,e the three 6 Ω resistor). Details below:
Resistor 1 (R₁) = 6 ΩResistor 2 (R₂) = 6 ΩResistor 3 (R₃) = 6 ΩEquivalent resistance (Rₜ) = ?1/Rₜ = 1/R₁ + 1/R₂ + 1/R₃
1/Rₜ = 1/6 + 1/6 + 1/6
1/Rₜ = 3/6
1/Rₜ = 1/2
Rₜ = 2 Ω
Finally, we shall determine the equivalent resistance between A and B (i.e series arrangement). Details below:
Resistor 1 (R₁) = Resistor 2 (R₂) = ... = Resistor (R₁₁) = 2 ΩEquivalent resistance (R) =?R = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ + R₇ + R₈ + R₉ + R₁₀ + R₁₁
R = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2
R = 22Ω
Thus, we can conclude that the equivalent resistance is 22 Ω
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The resistance to the motion of an object is
Answer:
Inertia
Explanation:
Part of Newton's Laws of Motion
2.Calcular el flujo magnético a través de una bobina con 460 espiras de 2 m² de superficie cuyo eje forma un ángulo de 60° con un campo magnético uniforme de 2 .
El flujo magnético a través de una bobina con 460 vueltas de superficie de 2 m² cuyo eje forma un ángulo de 60 ° con un campo magnético uniforme de 2 es 779.42 Weber
La fórmula para calcular el flujo magnético a través de una bobina se expresa como:
\(\phi = NABsin\theta\) dónde:
N es el número de vueltas A es el área de la sección transversal B es el campo magnético es el ángulo formado con el campo uniforme
Dados los siguientes parámetros
N = 450 turns
A = 2 m²
B = 2
\(\theta\) = 60degrees
Sustituya los parámetros dados en la fórmula como se muestra:
\(\phi=450 \times 2\times 2sin60^0\\\phi = 900sin60^0\\\phi = 900(0.8660)\\\phi=779.42Weber\)
El flujo magnético a través de una bobina con 460 vueltas de superficie de 2 m² cuyo eje forma un ángulo de 60 ° con un campo magnético uniforme de 2 es 779.42 Weber
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the strength of gravity between two objects depends on their distance apart and their
The strength of gravity between two objects depends on two factors:
a) The masses of the objects and
b) The distance between them.
Score for Question 1: Click or tap here to enter text. of 10 points) 1.A sailboat moves north for a distance of 20.0 km when blown by a wind from the exact southwest with a force of 3.50 x 10^4 N. The sailboat travels the distance in 2.5 h. a) How much work was done by the wind? b) What was the wind’s power? Your response should include all of your work and a free-body diagram. 2, 2. A worker applies 170 N of force on a lever to lift a 1250 N crate 0.10 m. a) If the lever is 100% efficient, how far does he need to push his side? Your response should include all of your work. 2. A worker applies 170 N of force on a lever to lift a 1250 N crate 0.10 m. a) If the lever is 100% efficient, how far does he need to push his side? Your response should include all of your work.
a) To find the work done by the wind, we use the formula: work = force * distance * cos(angle)
The angle is the angle between the direction of the force and the direction of motion. In this case, the wind is blowing from the southwest, which is 45 degrees relative to north. work = (3.50 x 10^4 N) * (20.0 km) * cos(45 degrees) work = (3.50 x 10^4 N) * (20.0 km) * 0.7071. Make sure to convert the distance from kilometers to meters and the angle from degrees to radians if necessary. b) To find the power, we use the formula: power = work / time. Plug in the value of work from part a and the given time of 2.5 hours. For question 2: a) If the lever is 100% efficient, it means that the work done on one side of the lever is equal to the work done on the other side. The work done can be calculated using the formula: work = force * distance. Plug in the given values of force and distance.
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Kiran's mother placed a candle in the bowl as shown and lit it . A little while later , kiran opened a bottle of pepsi and poured it quickly into the bowl .What will happen ?
Answer:
The candle stick flame will burn brighter.
Explanation:
I majored in Physics.
How are frequency, wavelength, and energy related? Choose all that apply.
Explanation:
The energy of a wave is given by :
\(E=\dfrac{hc}{\lambda}\)
Where
h is Planck's constant
c is the speed of light
\(\lambda\) is wavelength
Energy is inversely proportional to wavelength. Also, the relation between frequency and wavelength is inverse.
If the frequency is high, the wavelength will be shorter.
Hence, the correct options are :
Higher frequencies have shorter wavelengths.
Shorter wavelengths have lower energy.
Lower frequencies have lower energy.