The new angular momentum of the system would be 0.37 kg · m2/s if each of the masses were instead a solid sphere 10.5 cm in diameter.
To calculate the new angular momentum, we need to use the formula I = 2/5 * MR2, where I is the moment of inertia, M is the mass, and R is the radius of the object. Since each solid sphere has the same diameter, they have the same radius of 0.0525 m.
The mass of each sphere is given by the product of its density and volume, which is
(10 kg/m3) * (4/3 * pi * (0.0525 m)3) = 0.0038 kg.
Therefore, the moment of inertia for each sphere is
I = 2/5 * (0.0038 kg) * (0.0525 m)2 = 3.45 × 10^-6 kg·m^2.
The total moment of inertia for the system would then be
2 * 3.45 × 10^-6 kg·m^2 = 6.90 × 10^-6 kg·m^2.
Finally, using the formula L = I * w, where L is the angular momentum and w is the angular velocity, we get
L = (6.90 × 10^-6 kg·m^2) * (54 rad/s) = 0.37 kg·m^2/s.
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a uniform 135-g meter stick rotates about an axis perpendicular to the stick passing through its center with an angular speed of 3.50 rad/s. what is the magnitude of the angular momentum of the stick?
The correct option is A, the stick's angular momentum is measured at a magnitude of \(0.0394\:kg . m^2/s\).
In this case I is given as;
\(I = 1/12\:(m*L^2)\\I = 1/12\:( 0.135 * 1^2)\\I = 0.01125\:kg\:m^2\\\)
Following that, the angular momentum may be computed as
\(M = 0.01125\:kg\:m^2*3.50\:rads/s\\M = 0.039375\:kg\:m^2/s\\M = 0.0394\:kg\:m^2/s\)
The rotating motion of an object around an axis is described by the fundamental idea of angular momentum in physics. It is a vector quantity that is affected by the mass, velocity, and separation from the axis of rotation of the object. The ratio of an object's moment of inertia to its angular velocity determines how much angular momentum it has.
An object's angular momentum measures how much it rotates and how challenging it is to halt that revolution. The angular momentum of an object increases with its moment of inertia and angular velocity. Since angular momentum is conserved in isolated systems, a system's overall angular momentum stays constant until it is affected by an outside torque.
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Complete Question:-
A uniform 135-g meter stick rotates about an axis perpendicular to the stick passing through its center with an angular speed of 3.50 rad/s. What is the magnitude of the angular momentum of the stick?
A) 0.0394 kg · m^2/s
B) 0.473 kg · m^2/s
C) 0.0739 kg · m^2/s
D) 0.158 kg · m^2/s
E) 0.0236 kg · m^2/s
A dog walks 8.0 meters due north and then 6.0 meters due east.
Determine the magnitude of the dog's total displacement to the nearest tenths place.
Answer:
10.0mExplanation:
The displacement of the dog is the distance moved in a specified direction. It will be gotten using pythagoras theorem as shown;
d² = 8²+6²
d² =64+36
d² = 100
square root both sides
√d² = √100
d = 10m
Hence the displacement of the dog to the nearest tenth is 10.0m
The foot of a 60 kg sprinter is on the ground for 0.40 s while her body accelerates from rest to 2.0 m/s.
What is the magnitude of the friction force?
We can use the formula:v = u + atwhere:v = final velocity of the sprinter, which is 2.0 m/su = initial velocity of the sprinte, , the magnitude of the friction force is 300 N.
To determine the magnitude of the friction force, use the formula for force, F=ma, where m is the mass of the sprinter and a is the acceleration of the sprinter. The friction force is equal in magnitude and opposite in direction to the force of the sprinter's foot pushing backward against the ground.
Mass of the sprinter,
m = 60 kgTime the sprinter's foot is on the ground,
t = 0.40 sInitial velocity of the sprinter, u = 0 m/sFinal velocity of the sprinter,
v = 2.0 m/sWe need to calculate the friction force acting on the sprinter.To do this, we first need to calculate the acceleration of the sprinter. We can use the formula:v = u + where:
v = final velocity of the sprinter, which is 2.0 m/s
u = initial velocity of the sprinter, which is 0 m/st = time for which the foot is on the ground, which is 0.40 s
Substituting these values, we get:2.0
= 0 + a(0.40)Simplifying, we get:
2.0 = 0.4a
Dividing both sides by 0.4, we get:
a = 5 m/s² Substituting the values, we get:
F = 60 × 5F = 300 N
Therefore, the magnitude of the friction force is 300 N.
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if two objects, each with a mass of 4.1x10^2 kg, produce a gravitational force between them if 9.2x10^-6 N, what is the distance between them?
Taking into account the Universal Law of Gravitation, the distance between the objects is 1.10396×10⁻⁶ m².
Universal Law of GravitationThe Universal Law of Gravitation establishes that bodies, by the simple fact of having mass, experience a force of attraction towards other bodies with mass, called gravitational force.
This law states that the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them, expressed as:
\(F=G\frac{Mm}{d^{2} }\)
where:
G is the universal gravitational constant, with a value of 6.67×10⁻¹¹ \(\frac{Nm^{2} }{kg^{2} }\).M and m are the masses of the bodies that interact.d is the distance that separates them.Distance between two objectsIn this case, you know:
F= 9.2×10⁻⁶ NG= 6.67×10⁻¹¹ \(\frac{Nm^{2} }{kg^{2} }\)M= m= 4.1×10² kgd= ?Replacing in the Universal Law of Gravitation:
\(9.2x10^{-6} N=6.67x10^{-11}\frac{Nm^{2} }{kg^{2} } \frac{4.1x10^{2} kgx 4.1x10^{2} kg}{d^{2} }\)
Solving:
9.2×10⁻⁶ N÷ 6.67×10⁻¹¹ \(\frac{Nm^{2} }{kg^{2} }\)= \(\frac{4.1x10^{2} kgx 4.1x10^{2} kg}{d^{2} }\)
1.3793×10⁻¹⁷ kg²÷m²= \(\frac{168100 kg^{2} }{d^{2} }\)
1.3793×10⁻¹⁷ kg²÷m²× d²= 168100 kg²
d²= 168100 kg²÷ 1.3793×10⁻¹⁷ kg²÷m²
d²= 1.2187341×10⁻¹² m²
d= √1.2187341×10⁻¹² m²
d= 1.10396×10⁻⁶ m²
Finally, the distance is 1.10396×10⁻⁶ m².
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why does it hurt more to kick a bowling ball than a soccer ball
The combination of higher mass and lower elasticity in a bowling ball results in a more painful experience when compared to kicking a soccer ball.
Kicking a bowling ball is more painful than kicking a soccer ball because of the differences in their masses and elasticity. The pain experienced when kicking an object is determined by the transfer of kinetic energy and the interaction between the object and the body.
A bowling ball is much heavier and has a higher mass compared to a soccer ball. When you kick a bowling ball, it has a greater amount of momentum, which is the product of mass and velocity. The higher momentum results in a greater force being exerted on your foot upon impact, leading to a higher level of discomfort or pain.
In addition, the elasticity of the objects plays a role. Soccer balls are designed to be more elastic, allowing them to absorb and distribute the impact force more effectively. This elasticity helps to reduce the amount of force transmitted back to your foot, resulting in less pain. On the other hand, bowling balls are typically less elastic, leading to a greater transfer of force and more discomfort when kicked.
Overall, the combination of higher mass and lower elasticity in a bowling ball results in a more painful experience when compared to kicking a soccer ball.
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Hi! I got a physics final coming up and am allowed to have a formula sheet (2 sides) on everything on the test. I would appreciate it if someone could write this out for me (100 points and potential brainliest) the topics are for Physics 1 and are as follows:
2D kinematics
Block on an Inclined Plane
Gravity and Orbital Motion
Torque and Rotational Energy
Doppler Effect and Snells Law
Lenses and mirrors
Electric Fields
Resistors and Parallel Circuits
thanks in advance!
2D Kinematics deals with the motion of objects in two dimensions, typically represented by the x and y axes. It involves analyzing the position, velocity, and acceleration of objects as they move in a plane.
How to explain the informationGravity is the force of attraction between two objects with mass Orbital motion occurs when an object, such as a planet or a satellite, moves around another object under the influence of gravity.
Torque is a measure of the rotational force applied to an object. It depends on the force applied and the lever arm, which is the perpendicular distance from the axis of rotation to the point of application of the force. Rotational energy refers to the energy associated with an object's rotation. It depends on the moment of inertia and angular velocity of the object.
The Doppler Effect describes the change in frequency or wavelength of a wave as observed by an observer moving relative to the source of the wave. It explains phenomena such as the change in pitch of a siren as a vehicle approaches and then moves away from an observer. Snell's Law describes the behavior of light as it passes through the interface between two different media. It relates the angle of incidence and the angle of refraction of light rays at the boundary, taking into account the refractive indices of the media.
Lenses and mirrors are optical devices that manipulate the path of light. Lenses are transparent objects with curved surfaces that can converge or diverge light rays, leading to the formation of real or virtual images. Mirrors, on the other hand, reflect light and can create images through reflection.
An electric field is a region around an electrically charged object where a force is exerted on other charged objects. It is a vector field, meaning it has both magnitude and direction.
Resistors are components in electrical circuits that impede the flow of electric current. They are designed to have a specific resistance value and can be used to control the amount of current in a circuit.
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Why should a person warm up before physical activity?
Answer:
don't wanna pull anything
Explanation:
A good warm-up before a workout dilates your blood vessels, ensuring that your muscles are well supplied with oxygen. It also raises your muscles' temperature for optimal flexibility and efficiency. By slowly raising your heart rate, the warm-up also helps minimize stress on your heart.
Answer:
Here you go!
Explanation:
A good warm-up before a workout dilates your blood vessels, ensuring that your muscles are well supplied with oxygen. It also raises your muscles' temperature for optimal flexibility and efficiency. By slowly raising your heart rate, the warm-up also helps minimize stress on your heart. “Stretching allows for greater range of motion and eases the stress on the joints and tendons, which could potentially prevent injury. Warming up, such as low-heart rate cardio, prepares the circulatory and respiratory system for the upcoming ‘age- and type-appropriate target heart rate’ exercising, whether it’s endurance or sprint type of activities.” The cool-down is just as critical. It keeps the blood flowing throughout the body. Stopping suddenly can cause light-headedness because your heart rate and blood pressure drop rapidly. Before you exercise, think about warming up your muscles like you would warm up your car. It increases the temperature and flexibility of your muscles, and helps you be more efficient and safer during your workout. A warm-up before moderate- or vigorous-intensity aerobic activity allows a gradual increase in heart rate and breathing at the start of the activity.
Tips:
*Warm up for 5 to 10 minutes. The more intense the activity, the longer the warm-up.
*Do whatever activity you plan on doing (running, walking, cycling, etc.) at a slower pace (jog, walk slowly).
*Use your entire body. For many people, walking on a treadmill and doing some modified bent-knee push-ups will suffice.
how is rayleigh scattering and frequency related? double
Rayleigh scattering and frequency are related because the amount of scattering is inversely proportional to the fourth power of the frequency of the light. This means that as the frequency of the light increases, the amount of scattering decreases. This relationship is described by the Rayleigh scattering equation:
Is = I0 (1 + cos2θ) / (2r2) (λ0/λ)4
Where Is is the intensity of the scattered light, I0 is the intensity of the incident light, θ is the scattering angle, r is the distance from the scattering particle, λ0 is the wavelength of the incident light, and λ is the wavelength of the scattered light. This equation shows that the intensity of the scattered light is inversely proportional to the fourth power of the wavelength of the incident light, which is directly related to the frequency of the light.
Therefore, Rayleigh scattering and frequency are related in that the amount of scattering decreases as the frequency of the light increases.
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A bag of groceries is on the back seat of your car as you stop for a stop light. The bag does not slide. Apply your analysis to the bag
Answer:
This can be the FBD of the bag.
(my bag looks more like a box tho ^^")
Superman pulled against Spiderman with a force of 28N. Spiderman had a force of 25N.
What was the net force and in which direction? Explain.
The net force between Superman and Spiderman is 3 N, and it acts in the direction of Superman's force.
As per the question, the force exerted by :
Superman against Spiderman = 28 N
Spiderman against Superman = 25 N,
We can determine the net force and its direction by considering the following:
To find the net force, we need to subtract the forces exerted in opposite directions. Since Superman and Spiderman are pulling against each other, we have:
Net force = Force exerted by Superman - Force exerted by Spiderman
Net force = 28 N - 25 N
Net force = 3 N
The net force between Superman and Spiderman is 3 N.
To determine the direction of the net force, we need to consider the signs of the forces. Since Superman's force is greater than Spiderman's force, the net force will be in the direction of Superman's force.
Thus, the net force of 3 N is in the direction of Superman's force.
Therefore, the net force between Superman and Spiderman is 3 N, and it acts in the direction of Superman's force.
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how many seconds are there in 3 days and 36 hours
The answer is 388 800 sec
Answer:
388800 secs
Explanation:
1 day = 24 hrs
so 24 times 3 = 72
and 1 hour is equal to 60 min
108 x 60 = 6480
and 60 secs in a minute
6480 x 60= 388800
A heat lamp produces 32.8 watts of power at a wavelength of 6.5 mm. How many photons are emitted per second
Answer: 1.1x10^21 photons / sec
Explanation:energy per photon
.. E / photon = hc / L = (6.626x10^-34 J x sec) x (3.00x10^8 m/sec) / (6.5x10^-6m)
.. E / photon = 3.06x10^-20 J / photon
then
.. (32.7 watts) x (1 J/sec / 1watt) x (1 photon / 3.06x10^-20J) = 1.1x10^21 photons / sec
The number of photons are emitted per second will be "1.07".
According to the question,
Power,
P = 32.8 watts= 32.8 J/s
Wave length,
λ = 6.5 μm= \(6.5\times 10^{-6}\)
As we know,
→ \(E = \frac{hc}{\lambda}\)
By substituting the values, we get
\(= \frac{32.8}{\frac{(4.42\times 10^{-34})(3\times 10^{-4})}{4.5\times 10^{-6}} }\)
\(= \frac{32.8}{3.055e}\)
\(= 1.07\)
Thus the above answer is correct.
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gaya adalah...?? [tolong yaaa..]
I can try to help if you speak English
For the circuit in the figure
Find the rate of conversion of internal (chemical) energy toelectrical energy within the battery.
Find the rate of dissipation of electrical energy in thebattery.
Find the rate of dissipation of electrical energy in the externalresistor.
The rates of conversion and dissipation of energy can be found using the following equations:
Power = Voltage x Current
Power = Current^2 x Resistance
where power is the rate of energy conversion or dissipation in watts (W), voltage is the potential difference in volts (V), current is the flow of electric charge in amperes (A), and resistance is the opposition to the flow of current in ohms (Ω).
Assuming a battery of voltage V and internal resistance R is connected to an external resistor of resistance r, with a current I flowing through the circuit, we can use the following expressions to calculate the rates of energy conversion and dissipation:
Rate of conversion of internal energy to electrical energy in the battery:
P1 = VI
Rate of dissipation of electrical energy in the battery:
P2 = I^2R
Rate of dissipation of electrical energy in the external resistor:
P3 = I^2r
Note that the total power supplied by the battery must equal the total power dissipated in the circuit, according to the principle of conservation of energy.
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Describe the relationship between a moving object's mass and its kinetic energy.
Answer:
\(E=\dfrac{1}{2}mv^2\)
Explanation:
If m is the mass of the object and v is the velocity of the object. The kinetic energy is due to the motion of an object. It is given by the relation as follows :
\(E=\dfrac{1}{2}mv^2\)
The above formula is used to find the kinetic energy of an object.
If you told a policeman about a car traveling 44.704 m/s (100 mph) that was traveling in an eastward direction, you would be describing the car's ___.
Answer:
Velocity
Explanation:
You would be describing the velocity of the car.
Velocity in physics is defined as Vector quantity that describes the displacement of an object with respect to the time it takes to attain it. Displacement is the addition of direction to the speed of an object. The displacement is noted in the question, "traveling eastward". While it is stated that the car travels at 44.704 m/s. Ordinarily, it would have been tagged speed, if not for the direction added to it which makes it velocity.
I hope you understand.
What is the basic action of any muscle
The main and basic action of any single muscle that would have on a body would be the fact that it would contain "contraction" to which your muscle would practically contract each other, which would then give to power to force, push, push, and to make work, and also, to move.
PLEASE MARK ME AS BRAINLIEST
Answer:
The person above is correct, The Answer is "CONTRATION" just verified it by ap.ex ;)
Explanation:
7. What voltage is required to move 6A through 10?
Answer:
60V
Explanation:
Given parameters:
Current = 6A
Resistance = 10ohms
Unknown:
Voltage = ?
Solution:
From ohms law we know that:
V = IR
V is the voltage
I is the current
R is the resistance
V = 6 x 10 = 60V
If mass of an empty 7.0 mL pycnometer is 10.2g and the mass of the same pycnometer with an unknown liquid is 21.8g. Determine the density of the unknown liquid to ONE DECIMAL PLACE in g/mL.
The formula for calculating density is expressed as
Density = mass/volume
From the information given,
mass of empty pycnometer = 10.2
mass of the same pycnometer with an unknown liquid is 21.8.
Mass of unkown liquid = 21.8 - 10.2 = 11.6
volume of unknown liquid = 7
Thus,
Density = 11.6/7
Density = 1.7 g/ml
Sensors inside loT wearable devices typically collect information such as (A) pH and air pressure B D volume and light levels location and heart rate temperature and humidity
Sensors inside IoT wearable devices typically collect information such as location and heart rate, temperature and humidity.
IoT wearable devices are designed to monitor various aspects of human health and the surrounding environment. They incorporate sensors that can collect data to provide valuable insights and enable personalized experiences.
Location and heart rate monitoring are common features in many wearable devices. Location tracking allows users to track their movements and enables applications like fitness tracking or navigation. Heart rate monitoring provides real-time information about the user's heart rate, which is crucial for fitness monitoring, stress management, and detecting abnormal heart rhythms.
Temperature and humidity sensors are also commonly integrated into wearable devices. These sensors measure the ambient temperature and humidity levels, providing information about the surrounding environment. This data can be used for various purposes such as monitoring comfort levels, assessing heat stress, or tracking environmental conditions for specific applications like agriculture or sports.
Collecting pH and air pressure data is less common in consumer wearable devices but may be used in specialized applications. pH sensors can be used for monitoring sweat or other bodily fluids to gain insights into hydration levels or assess certain health conditions. Air pressure sensors can provide information about altitude changes, weather patterns, or even be used for indoor air quality monitoring.
Overall, the sensors integrated into IoT wearable devices are selected based on the specific purpose and application of the device, aiming to provide meaningful data for the intended use case.
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initially, a bowl holds 15 m^3 of water. an object is dropped into the bowl and the new volume of the water is 25 m^3. what is the buoyant force?
Explanation:
The new volume of water = 25 ml
The old volume of water = 15 ml
The difference = 25 - 15 but what are the units?
Since the question asks for force, the units must start out as 10 mL
In water 1 mL has a mass of 1 gram, so the answer is 10 grams.
Grams are units of mass, not weight. You should convert this into newtons.
10 grams = 1/1000 = 0.01 kg
1 kg has a weight of 9.81 Newtons
0.01 kg has a weight 0.081 Newtons
If you have never seen a Newton before, then the answer is 10 grams
A total of 645cal of heat is added to 5.00 g of ice at −20.0
∘
C. What is the final temperature of the water? T
final
= Two 20.0 g ice cubes at −12.0
∘
C are placed into 225 g of water at 25.0
∘
C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, T
f
, of the water after all the ice melts. At 1 atm, how much energy is required to heat 77.0 gHO(s) at −12.0
∘
C to H
2
O(g) at 137.0
∘
C ? Use the heat transfer constants found in this table.
The final temperature of the water after all the ice melts is approximately 8.6 °C.
Heat = mass × specific heat × temperature change
Heat of fusion = mass × heat of fusion
Heat of vaporization = mass × heat of vaporization
Let's solve each problem step by step:
A total of 645 cal of heat is added to 5.00 g of ice at -20.0 °C. What is the final temperature of the water?
a) Heat required to raise the temperature of ice to 0 °C:
Heat = 5.00 g × 0.5 cal/g°C × (0 °C - (-20.0 °C)) = 100 cal
b) Heat required to melt the ice at 0 °C:
Heat = 5.00 g × 80 cal/g = 400 cal
c) Heat required to raise the temperature of water from 0 °C to the final temperature:
Heat = 5.00 g × 1 cal/g°C × (T final - 0 °C)
Now, let's add up the heats from each step:
Total heat = 100 cal + 400 cal + 5.00 g × (T final - 0 °C) cal
We know that the total heat added is 645 cal:
645 cal = 500 cal + 5.00 g × (T final - 0 °C) cal
Simplifying the equation:
5.00 g × (T final - 0 °C) = 145 cal
Solving for T final:
T final = (145 cal / 5.00 g) + 0 °C = 29.0 °C
Therefore, the final temperature of the water is 29.0 °C.
Two 20.0 g ice cubes at -12.0 °C are placed into 225 g of water at 25.0 °C. Calculate the final temperature, T f, of the water after all the ice melts.
a) Heat required to raise the temperature of ice to 0 °C:
Heat = 2 × 20.0 g × 0.5 cal/g°C × (0 °C - (-12.0 °C)) = 480 cal
b) Heat required to melt the ice at 0 °C:
Heat = 2 × 20.0 g × 80 cal/g = 3200 cal
c) Heat required to raise the temperature of water from 25.0 °C to the final temperature:
Heat = 225 g × 1 cal/g°C × (T f - 25.0 °C)
Now, let's add up the heats from each step:
Total heat = 480 cal + 3200 cal + 225 g × (T f - 25.0 °C) cal
We know that the total heat added is 0 cal (no energy transferred to or from the surroundings):
0 cal = 3680 cal + 225 g × (T f - 25.0 °C) cal
Simplifying the equation:
225 g × (T f - 25.0 °C) = -3680 cal
Solving for T f:
T f = (-3680 cal / 225 g) + 25.0 °C ≈ 8.6 °C
Therefore, the final temperature of the water after all the ice melts is approximately 8.6 °C.
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Which aspect of health is best illustrated by the following example? I work well in a group and
respect my other classmates.
O social
O physical
O emotional
Which formula is used to find an object's acceleration?
Answer:
a = V/T
Explanation:
uh i think thats the answer let me know if im wrong
Erica forgot to put gas in her car (again) for two weeks. The graph below shows the last few seconds of her car being stalled along Elkins Drive st 7:23 am Friday. During the time shown, what was the acceleration of her car?
a 54 m
b 108 m/s
c 3 m/s^2
D -3 m/s^2
Answer:
Option (D) : - 3 m/s^2
Explanation:
Acceleration = Slope of v-t graph
= 18/6
= - 3 m/s^2 (-ive since the car is decelerating )
Until his seventies, henri lamothe (fig. 9-48) excited audiences by belly-flopping from a height of 12 m into 30 cm of water. Assuming that he stops just as he reaches the bottom of the water and estimating his mass, find the magnitude of the impulse on him from the water.
The magnitude of the impulse on him from the water is equal to -896 Ns.
Impulse is referred to as the integral of any force that is applied over a time interval for which it acts. In order to find the impulse we have the information as
Height = 12m
Mass = 64kg
The kinetic energy is expressed as 1/2mv² while potential energy is expressed as mgh. From the law of conversation:
1/2mv² = mgh
where m is mass of Henry, v is velocity, g is acceleration due to gravity and h is height/. Now, further solving
v = ✓2gh
v = ✓2 × ✓9.8 × ✓10
v = 14m/s
The change in velocity or the Impulse will be
Impulse = 64(0 - 14)
Impulse = 64 × -14
Impulse = -896Ns
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Complete Question:
Until he was in his seventies, Henri LaMothe excited audiences by belly-flopping from a height of 12 m into 30 cm. of water. Assuming that he stops just as he reaches the bottom of the water and estimating his mass to be 64 kg, find the magnitude of the impulse on him from the water.
Use what you know about the relationship between a wave's amplitude and the
wave's energy to describe how loud sound waves at a concert can damage your
hearing.
Answer:
A higher amplitude means a higher frequency which means a higher energy the higher the wavelength means lower energy because its not as precise and cant reach levels small wavelengths can the sound waves that usually damage our ears are small wavelengths because of the energy applied to them
Explanation:
How is the independent variable affected by the dependent variable
Answer:
A dependent variable is a variable that is tested in an experiment. An independent variable is that can be modified. Depending on what you are testing, the dependent variable will change accordingly to the dependent variable.
- I'm reading this back and it doesn't make much sense, if you want me to reword this I can
Convert: 8 mm: ____________ cm
-1^10
centi=10 mm and mm=1/10=10^-1 cm
What is electromagnetic radiation exactly? Give some examples except Light.
Answer:
the energy that is transmitted through free space or through a material medium in the form of electromagnetic waves
Explanation: