a 1,000 ml iv solution is to be administered over 6 hours. what is the rate of administration in ml/min?
Rate of administration
Amount/Time1000/360100/362.78ml/minThe rate of administration for the IV solution is approximately 2.778 mL/min.
To calculate the rate of administration in mL/min, we need to convert the total volume of the IV solution (1,000 mL) and the time it takes to administer it (6 hours) into the same unit of time (minutes).
1 hour = 60 minutes
Total volume of IV solution = 1,000 mL
Time for administration = 6 hours = 6 hours × 60 minutes/hour = 360 minutes
Now, we can calculate the rate of administration in mL/min:
Rate = Total volume / Time for administration
Rate = 1,000 mL / 360 minutes
Rate ≈ 2.778 mL/min
Hence, The rate of administration for the IV solution is approximately 2.778 mL/min.
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A toy car is moved 8m, right, then 1.5m, right, and finally 3.0m, left. If it took 5.0 seconds total for the car to travel its 3 routes, then what is the average speed of the toy car?
Answer:
2.7
Explanation:
V=s÷t
v=13.5÷5.0
V=2.7
In a gasoline engines cylinder, 45j of work is done by the gas and 175 j Is removed from the gas as heat. What is the change in the internal energy of gas?
Answer:
The first law of thermodynamics states that the change in internal energy of a system equals the net heat transfer into the system minus the net work done by the system. In equation form, the first law of thermodynamics is ΔU = Q − W.
The internal energy of ideal gas is U = cV The change in internal energy for ideal gas is therefore ∆U = cV ∆T, where cV is specific heat (at constant volume), and ∆T is change in tem- perature.
Explanation:
ihopeithelps
I need help! Use your observations to support or reject this claim "If the samples are at the same temperature, the amount of thermal energy in a sample depends on the type of material and the amount of the material" Its the Phet Lab
Answer:
i cannot see the the claim
Explanation:
Which expression correctly describes force using Sl units?O A. 1 J= 1 kg-m/s²OB. 1 N=1 kgm/sOC. 1 J= 1 kg-m/sD. 1 N = 1 kg-m/s²
D. 1 N = 1 kg-m/s²
Explanation
Force can be defined as the push or pull on an object with mass that causes it to change its velocity, for example the force of gravity , this force pushes us to the cneter of the earth,
so
\(Force=\text{ mass *acceleration}\)SI( international system of units) is the metric system that is used universally as a standard for measurements, the units for mass and acceleration are
\(\begin{gathered} mass\Rightarrow kilograms\Rightarrow kg \\ aceleration\Rightarrow meters\text{ per square second}\Rightarrow\frac{m}{s^2} \end{gathered}\)therefore, the units of force would be
\(\begin{gathered} Force=\text{ mass *acceleration} \\ Force=kg*\frac{m}{s^2} \\ \end{gathered}\)by definition
\(\begin{gathered} 1\text{ kg}\frac{m}{s^2}=1\text{ Newton\lparen N\rparen} \\ so \\ 1N=1\text{ kg}\frac{m}{s^2} \end{gathered}\)therefore, the answer is
D. 1 N = 1 kg-m/s²
I hope this helps you
6. What two factors influence the attraction between objects?
10. A car starts from rest and travels for 5.0 s with a constant acceleration of -1.5 m/s/s.
A. What is the final velocity of the car?
B. How far does the car travel in this time interval?
Answer:
a.-7.5 m/s
b.18.75 m
Explanation:
hope it helps
how big is the black hole at the center of the milky way
At the center of our galaxy lies the supermassive black hole Sagittarius A*, often abbreviated Sgr A*. This giant is about 4 million times the mass of the sun and about 14.6 million miles (23.6 million kilometers) in diameter.
In physics, the Milky Way refers to the galaxy in which our solar system resides. The Milky Way is a barred spiral galaxy, meaning it has a central bar-shaped structure with arms spiraling out from it. The galaxy is estimated to be around 13.6 billion years old and contains billions of stars, as well as gas, dust, and dark matter.
The Milky Way has a diameter of approximately 100,000 light-years and is located about 26,000 light-years from the galactic center. It rotates once every 240 million years, with stars closer to the center moving faster than those on the outer edges. The gravitational force of the Milky Way holds the solar system in its orbit.
The study of the Milky Way is important in astrophysics as it provides insight into the evolution and formation of galaxies.
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2. if one visible red wave is 700 nm in length, and one visible violet wave is 400 nm in length How many possible colors can there be?
Between the value 400 nm and 700 nm there is an infinite amount of real values that can represent the length of a wavelength.
If we consider that each differente wavelength represents a different color, therefore there are infinite possible colors in the interval from 400 nm to 700 nm.
But if we consider only certain intervals of wavelength as certain colors, we can have for example 7 colors:
Violet, Indigo, Blue, Green, Yellow, Orange, Red.
7. In an airplane crash a woman is holding an 8.18 kg, 18 pound, baby. In the crash the woman experiences a horizontal de-acceleration of 88.2 m/s2. How many g's is this de-acceleration? How much force must the woman exert to hold the baby in place?
Answer:
721.5 N
Explanation:
F= m X a F=8.18 kg x 88.2 m/s² = 721.5 N
not sure if this is correct just guessing
721.5 N
F= m X F=8.18 kg x 88.2 m/s² = 721.5 N
To reduce the speed slow down and decelerate a car. 2: to decrease the rate of progress of decelerate growth decelerate soil erosion. intransitive verb. : to move at decreasing speed.
What is called deceleration?Deceleration is a slowing down: the unexpected deceleration of your car might mean that you've run out of gas. Use the noun deceleration when you talk about a gradual decrease in speed.
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An object of height 2.3 cm is placed 27 cm in front of a diverging lens of focal length 17 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length. A 50% Part (a) Find the location of the final image, in centimeters beyond the converging lens. A 50% Part (b) What is the magnification of the final image? Include its sign to indicate its orientation with respect to the object.
(a) The location of the final image beyond the converging lens is 12.67 cm.
(b) The magnification of the final image is -0.82, indicating that it is inverted with respect to the object.
To find the location of the final image, we can use the lens formula for thin lenses, which is given by 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance.
For the diverging lens, u = -27 cm (since the object is in front of the lens), and f = -17 cm (negative for diverging lens). Using the lens formula, we find v1 = -153 cm.
For the converging lens, the object distance is -11 cm (since it is behind the diverging lens), and f = 17 cm. Using the lens formula again, we find v2 = 12.67 cm.
The magnification of the final image can be calculated using the formula magnification = v2/v1, which gives us -0.82. The negative sign indicates that the image is inverted with respect to the object.
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Which physical property is best measured using only a balance?
A. Color
B. Volume
C. Mass
D. Density
Answer:
The answer is Mass
Explanation:
I took the tests and study kinda yeahhhhhh
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A hairdryer has a power of 1.5kw and was used for 15 minutes how much did it cost?
The cost of using the hairdryer for 15 minutes would be approximately $0.05625.
To calculate the cost of using the hairdryer, we need to consider the power rating of the hairdryer and the duration of its use. The cost of electricity is typically measured in kilowatt-hours (kWh).
Given:
Power of the hairdryer = 1.5 kW
Duration of use = 15 minutes
To calculate the energy consumed by the hairdryer, we first need to convert the duration of use from minutes to hours:
Duration of use (in hours) = 15 minutes / 60 minutes per hour
Duration of use (in hours) = 0.25 hours
Next, we calculate the energy consumed by multiplying the power of the hairdryer by the duration of use:
Energy consumed = Power × Duration of use
Energy consumed = 1.5 kW × 0.25 hours
Energy consumed = 0.375 kWh (kilowatt-hours)
Finally, to determine the cost, we need to know the cost per kilowatt-hour (kWh) charged by the electricity provider. The cost can vary depending on your location and specific electricity rates. Let's assume a cost of $0.15 per kilowatt-hour.
Cost = Energy consumed × Cost per kilowatt-hour
Cost = 0.375 kWh × $0.15/kWh
Cost = $0.05625
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A police officer on a mountain bike is cruising at a speed of 3.50m/s, when he sees a wanted
criminal, standing on a corner, 75m ahead of him. If the police officer accelerates at a rate of
2.00m/s^2, how much time will he take to reach the corner?
Answer:
7 seconds
Explanation:
please see paper!
vf² = vo²+2ad
vf=vo+at
vf²=3.5²+2.2.75
vf²=312.25
vf=17.67 m/s
vf=vo+at
17.67 = 3.5 +2t
t=7.085 s
An ant on a picnic table travels 3.0 x 101 cm eastward, then 25 cm northward, and finally 15 cm westward. What is the magnitude of the ant's displacement relative to its original position?
The magnitude of the ant's displacement relative to its original position is 43 cm.
What is magnitude?Magnitude is a measure of the size or strength of something. It is usually expressed as a numerical value, such as a number on a scale. Magnitude can refer to physical and non-physical qualities, such as the size of a building or the intensity of an emotion. For example, an earthquake can be measured in terms of its magnitude, which is the amount of energy released during the earthquake. Magnitude can also refer to the brightness of a star, or the size of a hurricane. In astronomy, magnitude is used to measure the brightness of a star or other celestial object.
This is because the ant traveled 3.0 x 101 cm eastward, then 25 cm northward, and then 15 cm westward. The total magnitude of the displacement is the sum of the magnitudes of the individual displacements, which is 3.0 x 101 + 25 + 15
= 43 cm.
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016 (part 1 of 2) 10.0 points
A beaker of mass 1.3 kg containing 2.5 kg of
water rests on a scale. A 3.4 kg block of a
metallic alloy of density 3700 kg/m³ is sus-
pended from a spring scale and is submerged
in the water of density 1000 kg/m³ as shown
in the figure.
3.4 kg
What does the hanging scale read? The
acceleration of gravity is 9.8 m/s².
Answer in units of N.
017 (part 2 of 2) 10.0 points
What does the lower scale read?
Answer in units of N.
Answer: 0.85 N
Explanation: We can solve this problem using the principles of buoyancy and Newton's laws.
First, we need to find the buoyant force acting on the metallic alloy block. The buoyant force is equal to the weight of the water displaced by the block, which can be calculated using the block's volume and the density of water:
V = m_block / ρ_block = 3.4 kg / 3700 kg/m³ = 0.0009189 m³
F_buoyant = ρ_water x g x V = 1000 kg/m³ x 9.8 m/s² x 0.0009189 m³ = 8.96 N
So the buoyant force acting on the metallic alloy block is 8.96 N.
Next, we can calculate the tension force in the spring scale attached to the block. Since the block is in static equilibrium, the tension force must be equal in magnitude and opposite in direction to the weight of the block plus the buoyant force:
Tension force = weight of block + buoyant force
Tension force = m_block x g + F_buoyant
Tension force = 3.4 kg x 9.8 m/s² + 8.96 N = 42.04 N
So the hanging scale reads 42.04 N.
Finally, we can find the reading of the lower scale. The lower scale measures the weight of the beaker and the water in it, minus the buoyant force acting on the beaker. The weight of the beaker and the water is:
weight of beaker + weight of water = m_beaker x g + m_water x g
weight of beaker + weight of water = 1.3 kg x 9.8 m/s² + 2.5 kg x 9.8 m/s² = 35.35 N
The buoyant force acting on the beaker can be calculated using the volume of water displaced by the beaker:
V = m_water / ρ_water = 2.5 kg / 1000 kg/m³ = 0.0025 m³
F_buoyant = ρ_water x g x V = 1000 kg/m³ x 9.8 m/s² x 0.0025 m³ = 24.5 N
So the reading of the lower scale is:
Reading of lower scale = weight of beaker + weight of water - buoyant force
Reading of lower scale = 35.35 N - 24.5 N = 10.85 N
Therefore, the lower scale reads 10.85 N.
A string of christmas lights contains 20 lights. The lights are wired in series, so that if any light fails, the whole string will go dark. Each light has probability 0. 98 of working for a 3-year period. The lights fail independently of each other.
The probability that a string of Christmas lights containing 20 lights are wired in series, so that if any light fails, the whole string will go dark = 0.6676 = 66.76%
There are just two conceivable outcomes for each light: either it works or it doesn't. The binomial distribution is utilized to answer this question since the likelihood that a light will operate independently of all other lights.
It's a binomial experiment. Since the bulbs are independent and there is only one way the string can stay lit
The success probability is:
1 -0.02 = 0.98
Hence, the probability that the string of lights will remain bright for 3 years is:
(0.98)²₀ = 0.667
= 66.67%
The question is incomplete, it should be:
Merry and bright? A string of Christmas lights contains 20 lights. The lights are wired in series, so that if any light fails, the whole string will go dark. Each light has probability 0.98 of working for a 3-year period. The lights fail independently of each other. Find the probability that the string of lights will remain bright for 3 years.
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A 10 kg cart with a momentum of 10 kg• m/s hits a 20 kg cart at rest. Momentum is calculated by using
the formula p = mv, where m is the mass of an object and vis the velocity of an object.
Change in momentum formula
The change in momentum resulting from an external force is called the impulse (I=mv-mvo) and is related to the force applied through the Impulse-Momentum Theorem: I = F tc = mv - mvo . Here F is the external force applied and tc is the amount of time the force is in contact with the object.
The final velocity ( Vf ) of the cart at rest is : 0.5 m/s
Determine the final velocity of cart at restChange in momentum of the objects = m₁ * ΔV = m₂ * ΔV --- ( 1 )
Given that momentum ( p ) = m * v
where ; m₁ = 10 kg , p = 10 kg.m/s , v = ?
calculate for v
v = p/m = 10 kg.m/s / 10 kg
= 1 m/s
Back to equation ( 1 )
= 10 * ( 1 m/s ) = 20 * ( Vf - )
= 10 = -20 Vf
therefore Vf ( final velocity of cart at rest ) = 10 / 20
= 0.5 m/s
Hence we can conclude that The final velocity ( Vf ) of the cart at rest is : 0.5 m/s
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2. A block of mass 1.2 kg lies on a frictionless surface. A man slides the block
against a spring, compressing it .15m. When the man lets go of the spring, the
block moves at 5 m/s. What is the spring constant of the spring?
mm
.
Answer:
The spring constant will be "1333.33 N/m".
Explanation:
The given values are:
Mass,
m = 1.2 kg
Displacement compression,
x = 0.15 m
Block's velocity,
\(v_i=5 \ m/s\)
As we know,
⇒ \(E_i=E_f\)
or,
⇒ \(K_i+v_i=K_f+v_f\)
⇒ \(\frac{1}{2}mv_i^2+0=0+ \frac{1}{2}Kx^2\)
So,
⇒ \(K=\frac{mv_i^2}{x_2}\)
On substituting the values, we get
⇒ \(=\frac{1.2\times 5\times 5}{0.15\times 0.15}\)
⇒ \(=\frac{30}{0.0225}\)
⇒ \(=1333.33 \ N/m\)
what amount of charge can be placed on a capacitor if the area of each plate is 7.3 cm2 ? express your answer using two significant figures.
The amount of charge that can be placed on a capacitor depends on the capacitance, which is determined by the area of each plate.
The capacitance of a capacitor is given by the formula:
C = ε0 * (A / d)
Where:
C is the capacitance,
ε0 is the permittivity of free space (a constant value),
A is the area of each plate,
d is the separation between the plates.
To determine the amount of charge, we can rearrange the formula as:
Q = C * V
Where:
Q is the amount of charge,
V is the voltage across the capacitor.
Given that the area of each plate is 7.3 cm², we can use this information to calculate the capacitance. However, the question does not provide the voltage or any other information required to calculate the amount of charge accurately. Without knowing the voltage or other relevant parameters, it is not possible to determine the exact amount of charge that can be placed on the capacitor.
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A skydiver is descending towards the earth with her parachute open. The work done by the drag force from the air is o 0 o Positive o Negative
The work done by the drag force from the air on the skydiver is negative, as the force opposes the motion of the skydiver.
This means that the drag force is doing work to slow down the skydiver's descent. The drag force results from the interaction of the parachute with the air. When the parachute is open, air resistance increases, causing the drag force to act in an opposite direction to the skydiver's motion.
The drag force does work to reduce the speed of the skydiver's descent. The work done is equal to the force multiplied by the distance over which it is applied. The drag force pushes against the skydiver, thus performing negative work. The total amount of work done by the drag force is equal to the magnitude of the force multiplied by the distance the skydiver has descended while the force is applied.
To summarize, the work done by the drag force on the skydiver is negative because the force acts in an opposite direction to the skydiver's motion, slowing down their descent.
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disk 1 is traveling directly north at 5m/s. It collides with disk 2 (initially at rest). Disk 1's mass is twice that of disk 2. After the collision Disk 2 is traveling at 2.4 m/s at 33 degrees west of north. Calculate the final resultant velocity of Disk 1.
Final resultant velocity of Disk 1 is 4.45 m/s, traveling directly north.
What is velocity?A vector measurement of the rate and direction of motion is known as velocity
Initial momentum of the system before collision:
\(\rm p_{initial\) = m₁v₁ + m₂v₂
m₁ = 2m (mass of disk 1)
v₁ = 5 m/s (velocity of disk 1)
m₂ = m (mass of disk 2)
v₂ = 0 m/s (initial velocity of disk 2)
\(\rm p_{initial\) = (2m)(5 m/s) + (m)(0 m/s) = 10m m/s
After collision, momentum of the system is conserved:
\(\rm p_{final\) = (2m) × v₁' + m × v₂'
v₁' = final velocity of disk 1
v₂' = final velocity of disk 2
vx = 2.4 m/s × cos(33°) = 2.0 m/s
vy = 2.4 m/s × sin(33°) = 1.3 m/s
Total momentum of system after collision is: \(\rm p_{final\) = (2m) × v₁' + m × v₂' = (2m) × v₁' + m× (vx + vy)
(1/2) × m₁ × v₁²= (1/2)× m₁ × v₁'²+ (1/2) × m₂ × v₂'²
(2m) × v₁' + m × (vx + vy) = 10m m/s
(1/2) × (2m) × (5 m/s)² = (1/2) × (2m) × v₁'² + (1/2) × m × (2.4 m/s)²
v₁' = 4.45 m/s
Therefore, final resultant velocity of Disk 1 is 4.45 m/s, traveling directly north.
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what is the potential difference between xi=20cmxi=20cm and xf=40cmxf=40cm in the uniform electric field ex=3000v/mex=3000v/m ?
The potential difference between xi=20cmxi=20cm and xf=40cmxf=40cm in the uniform electric field ex=3000v/mex=3000v/m is 60V.
What is the electric field?
The electric field is a field that has an effect on electrically charged objects within the field. When electrically charged particles interact with the electric field, they experience a force. The force is proportional to the electric charge on the particle and the electric field strength.
What is the potential difference?
The potential difference is the difference in electric potential between two points in an electric field. The electric potential difference is calculated by subtracting the electric potential at the initial point from the electric potential at the final point. Mathematically, it is represented as ΔV = Vf - Vi.
Given that the electric field ex = 3000V/m.
The potential difference between xi = 20cm and xf = 40cm can be calculated as follows:
Given that xf = 40cm and xi = 20cm, the Potential difference, ΔV = Vf - Vi.
The potential difference can be calculated as ΔV = ExΔxΔV = 3000V/m (40cm - 20cm)ΔV = 3000V/m (0.2m)ΔV = 600VTherefore, the potential difference between xi = 20cm and xf = 40cm in the uniform electric field ex = 3000V/m is 60V.
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explain the differences among the observable universe expanding, the universe expanding, and the universe's expansion accelerating
The differences among the terms "observable universe expanding", "universe expanding", and "universe's expansion accelerating" are as follows:
1. "Observable universe expanding" refers to the growth of the portion of the universe that we can observe and gather information from. This is due to the ongoing expansion of the universe, which causes objects within the observable universe to move away from us, increasing the size of the region we can detect.
2. "Universe expanding" describes the overall increase in size of the entire universe, including both observable and unobservable regions. This expansion occurs as a result of the Big Bang and the subsequent stretching of space, causing galaxies and other cosmic structures to move apart from one another.
3. "Universe's expansion accelerating" refers to the observation that the rate at which the universe is expanding is not constant but is instead increasing over time. This acceleration is attributed to dark energy, a mysterious form of energy that works against gravity and drives the universe to expand at a faster pace.
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What is density?
O A. The net energy transferred between two objects
B. A measure of mass per unit volume
O C. A measure of the movement of molecules
O D. The force exerted on an area
Answer:
B. A measure of mass per unit volume
Explanation:
Mass and volume are intimately correlated with density. In reality, it explains the precise nature of the connection between the two. We can determine an object's density by dividing its mass by volume. Thus, option B is correct.
What best defines about density?The mass or amount per unit of volume of a substance determines its density. Density is calculated using the formula mass/volume. It is considered to have a low density if a mass has a high volume but a tiny mass.
The volume and subsequently the density of a material typically alter when it changes its phase or state of matter. Temperature is the primary component, even though pressure can also affect how a material changes state.
Water availability, climate, relief (the contour of the terrain), vegetation, soils, and the accessibility of renewable energy sources are physical elements that impact population density. Social, political, and economic variables altering humans all have an impact on population density.
Therefore, A measure of mass per unit volume.
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imagine another solar system, with a star of the same mass as the sun. suppose a planet with a mass twice that of earth (2mearth) orbits at a distance of 1 au from the star. what is the orbital period of this planet? view available hint(s)for part a imagine another solar system, with a star of the same mass as the sun. suppose a planet with a mass twice that of earth (2mearth) orbits at a distance of 1 au from the star. what is the orbital period of this planet? 2 years it cannot be determined from the information given. 6 months 1 year
1year is the orbital period of this planet.
The orbital period is the quantity of time a given astronomical object takes to complete one orbit around every other object. In astronomy, it generally applies to planets or asteroids orbiting the solar, moons orbiting planets, exoplanets orbiting different stars, or binary stars.
Kepler's third law - indicates the relationship among the length of an items orbit and the common distance that it's far from the issue it orbits. this could be used for something clearly orbiting round another factor.
Entire revolution is known as the orbital duration. At 200 km that is approximately ninety minutes. The orbital duration will increase with altitude for two motives. First, as the altitude increases, Earth's gravity decreases, so the orbital speed had to stability it decreases.
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a car starts from the rest and accelerates at 9.54m/s for 6.5 seconds. what is the distance covered by the car
Answer:
= 201.53 meters
Explanation:
A car started from rest and accelerated at 9.54 m/s^2 for 6.5 seconds. How much distance was covered by the car?
Use the formula d = \(\frac{at^{2} }{2} ,\)
where d is the distance, t is the time and "a" is the acceleration.
\(d=\frac{9*54*6*5^{2} }{2} = 201.53 m\)
Newton's third law is applicable only to objects at rest?
TRUE
FALSE
Answer:
false
Explanation:
5. Michael wanted to see what kitchen cleaner worked best for cleaning her counters. He used Lysol, Clorox, Pine-sol, and just water. For each cleaner, he put 5 milliliters of grape juice on the counter, sprayed the cleaner, and wiped it with one paper towel.
Answer:
Michael wanted to see what kitchen cleaner worked best for cleaning his counters. He used Lysol, Clorox, Pine-Sol, and water. For each cleaner, he used 5 milliliters of grape juice on the counter, sprayed the cleaner, and wiped it with one paper towel. Which of the following would be a constant?
answer choices:
-Lysol
-Cleaning products
-5 milliliters of grape juice
-Cleanest countertop recorded
5 milliliters of grape juice will be constant.
Explanation:
The different cleaning agents have different cleaning capabilities and some will require more of its quantity than others to clean the counter.
Secondly, only the grape juice has a measured amount of 5 milliliters
Two identical conducting spheres, separated by 50.0 cm, experience an attractive electrostatic force of 0.108 N. The spheres are then connected by a thin conducting wire. When the wire is removed, the spheres experience a repulsive electrostatic force of 0.0360 N. The total charge of the system is positive. In the initial configuration, what was a. the negative charge on one of them and b. the positive charge on the other
The initial configuration consists of two identical conducting spheres separated by a distance of 50.0 cm. The spheres experience an attractive electrostatic force of 0.108 N is \(1.33*10^{-8} C\)
After connecting the spheres with a conducting wire and then removing it, they experience a repulsive electrostatic force of 0.0360 N. The total charge of the system is positive. The question seeks to determine the negative charge on one sphere and the positive charge on the other.
To solve for the charges on the spheres, we can use the concept of electrostatic force and Coulomb's law. Initially, the spheres experience an attractive force, indicating opposite charges. Let's assume one sphere has a negative charge and the other has a positive charge.
Using Coulomb's law, we can calculate the magnitude of the initial force: \(F = k * (q1 * q2) / r^2\), where F is the force, k is the electrostatic constant, q1 and q2 are the charges, and r is the distance between the spheres. Since the spheres are identical, their charges can be represented as q and -q, respectively.
\(0.0360 N = (9 * 10^9 N*m^2/C^2) * (q1 * q2) / (0.50 m)^2q1q2 = (0.0360 N * (0.50 m)^2) / (9 * 10^9 Nm^2/C^2) = 4.0 * 10^8 C^2\)
\(1.33*10^{-8} C\)
By substituting the given values into the equation and solving for q, we can determine the negative charge on one sphere. Similarly, after connecting the spheres with a wire and removing it, they experience a repulsive force. This indicates that the charges have become the same on both spheres. Therefore, the positive charge on the other sphere can be determined as +q.
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