Answer:
work is done on the air in the cylinder
Explanation:
when using air pump to compress air in a cylinder; Work is done on the air in the cylinder and its surroundings
work done = F* d
= Magnitude of force * displacement
This is what happens when an air pump is used to compress air into a cylinder
When light reflects off a rough surface, what happens to the image?
A. It's clear but inverted
B. It's clear and upright
C. It's blurry and inverted
D. No image is formed
Answer:
D. NO MAGE IS FORMEDExplanation:
#CARRY ON LEARNING#MARK BRAINLITSThe light reflects off a rough surface, what happens to the image is that will occurs No image is formed.
How to explain the reflection of light?Reflection of light happens when a ray of light strikes a reflective surface and returns to its original medium. This phenomenon allows us to see all bodies that do not produce their own light, called secondary sources of light or simply illuminated bodies.
Diffuse reflection occurs when light reflects off a rough surface and forms a blurry image or no image at all.
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Walt ran 5 kilometers in 25 minutes going eastward what is his average velocity
Answer:
1/5 km/min
Explanation:
the formula for velocity is distance/time
so if i plug in the distance and time i get 5/25 or 1/5
Hope this helps!
Which part(s) of the electromagnetic spectrum are able to be seen by the human eye? question 2 options: radio waves microwaves infrared waves visible light ultraviolet rays x-rays gamma rays
Visible light is known as the fragment which is the part of electromagnetic spectrum that can be seen by humans.
The wavelength and frequency of light that is visible are 400nm to 700nm and 400THz to 800THz respectively. As we know, living beings are blind to a number of wavelengths of light, but it can be detected by specific instruments. But we can perceive easily that our world is aligned around this light.
For example, the sun is natural visible light. Everything around us that we’re able to see is a reflection of sunlight falling off the objects. Colour of any object that we’re able to see is actually just a reflection of light and other than that, all other colours get absorbed.
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2. Which of the following will have no effect on the reaction time of a person driving an
automobile?
age
of the driver
b) Distractions in the environment
c) The speed of the automobile
d) Talking on a cell phone while driving
a) The
when a 0.30 kg mass is suspended from a massless spring, the spring stretches a distance of 2.0 cm. let 2.0 cm be the rest position for the mass-spring system. the mass is then pulled down an additional distance of 1.5 cm and released.calculate the period of resulting oscillation in si units.
When a 0.30 kg mass is suspended from a massless spring, the spring stretches a distance of 2.0 cm, with an additional distance of 1.5cm,
Mass m= 0.30 kg
Distance x = 2.0 + 1.5 cm = 0.035 m
Since spring constant k = \({\frac{mg}{x}\) , (g=9.81)
k = \({\frac{0.3*9.81}{0.035}\) = 84.085 N/m
ω = \(\sqrt{\frac{k}{m} }\) = \(\sqrt{\frac{84.085}{0.3} }\) = 16.74 rad/sec
T = \(\frac{2\pi }{w}\) = \(\frac{2*3.14}{16.74}\) = 0.375 sec
The spring constant is the force required to stretch or compress the spring divided by the distance the spring is lengthened or shortened. It is used to determine the stability or instability of a spring and thus the system for which it is intended.
Therefore the time period of resulting oscillation is 0.375 sec.
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Suppose a weight of 1 kg is attached to an oscillating spring with friction constant b=7 and stiffness constant k=6. Suppose the external forces on the weight are: F ext
(t)=−6te −3t
+e −3t
. y ′′
+7y ′
+6y=−6te −3t
+e −3t
a) Show y(t)=te −3t
is a possible position function for this weight. y ′1
+7y ′
+6y=−6tc −3t
+e −3t
r 2
+7r+6=0
(r+a)(r+1)
e −6t
e −t
y=1e −4t
+1e −t
y ′
=−61)e −4t
+Ae t
y ′
=−609e −4t
+e −+
(6,6e −4t
)+Me −t
b) Find a general equation for all possible position functions. y=Ae −6t
+AC 2
=−6+e 3t
+e −3t
(10 points) c) Find the exact motion equation for this weight if its initial position is y(0)=3, and its initial velocity is v(0)=y ′
(0)=
a) y(t) = te⁻³ᵗ is a possible position function.
b) General equation: y(t) = C₁e^(-2t) + C₂e^(-3t) + t(e^(-3t))(At + B).
c) Exact motion equation: y(t) = (23/5)e^(-2t) - (8/5)e^(-3t) + t(e^(-3t))(At + B), with initial conditions y(0) = 3 and v(0) = -7.
a) To show that y(t) = te⁻³ᵗ is a possible position function, we substitute it into the differential equation:
y(t) = te⁻³ᵗ
y'(t) = e⁻³ᵗ - 3te⁻³ᵗ
y''(t) = -6e⁻³ᵗ + 9te⁻³ᵗ
Substituting these expressions into the differential equation, we have:
-6e⁻³ᵗ + 9te⁻³ᵗ + 7(e⁻³ᵗ - 3te⁻³ᵗ) + 6(te⁻³ᵗ) = -6te⁻³ᵗ - e³ᵗ
Simplifying this equation, we find that both sides are equal, thus confirming that y(t) = te⁻³ᵗ is a possible position function.
b) The general equation for all possible position functions can be written as:
y(t) = C₁e^(-2t) + C₂e^(-3t) + t(e^(-3t))(At + B)
c) Given the initial conditions y(0) = 3 and y'(0) = v(0) = -7, we substitute these values into the general equation and solve for the constants:
3 = C₁ + C₂
-7 = -2C₁ - 3C₂
Solving these equations, we find C₁ = 23/5 and C₂ = -8/5.
The exact motion equation for the weight is:
y(t) = (23/5)e⁻²ᵗ - (8/5)e⁻³ᵗ + t(e⁻³ᵗ)(At + B)
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Suppose a weight of 1 kg is attached to an oscillating spring with friction constant b = 7 and stiffness constant k = 6. Suppose the external forces on the weight are: Fₑₓₜ(t) = - 6te⁻³ᵗ - e³ᵗ
y" + 7y' + 6y = - 6te⁻³ᵗ - e³ᵗ
a) Show y(t) = te⁻³ᵗ is a possible position function for this weight.
b) Find a general equation for all possible position functions.
c) Find the exact motion equation for this weight if its initial position is y(0) = 3, and its initial velocity is v(0) = y'(0) = -7.
una llamada telefonica a brasil de 4 minutos costo el mes pasado 2430 si el valor por minuto se mantiene cualto debo pagar por una llamada de 6 minutos a ese pais
Answer:
Costo = 3645
Explanation:
Dados los siguientes datos;
Costo de la llamada = 2430
Duración = 4 minutos
En primer lugar, encontraríamos el costo por minuto;
Costo por minuto, Cpm = 2430/4
Cpm = 607.5
A continuación, para encontrar el costo de 6 minutos;
Costo = 607,5 * 6
Costo = 3645
A restoring force of magnitude F acts on a system with a displacement of magnitude x. In which of the following cases will the system undergo simple harmonic motion? a. F directly proportional to x^2 b. F directly proportional to x c. F directly proportional to 1/x
d. F directly proportional to sin x
The system will undergo simple harmonic motion in the case where the restoring force is directly proportional to the displacement (option b).
In simple harmonic motion, the restoring force acting on the system is directly proportional to the displacement from the equilibrium position. This relationship is given by Hooke's Law: F = -kx, where F is the restoring force, x is the displacement, and k is the spring constant.
Option a (F directly proportional to x²) does not correspond to simple harmonic motion because the force is proportional to the square of the displacement, which does not follow Hooke's Law.
Option c (F directly proportional to \(\frac{1}{x}\)) does not correspond to simple harmonic motion either because the force is inversely proportional to the displacement, which is not consistent with Hooke's Law.
Option d (F directly proportional to sin x) does not represent a linear relationship between the force and displacement. Simple harmonic motion requires a linear relationship, not a trigonometric one.
Therefore, only option b (F directly proportional to x) satisfies the conditions for the system to undergo simple harmonic motion.
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50 POINTS!! BRAINLEST
Answer:
The lines are parallel and the students data is 13
Explanation:
The amount of salt added
The x-component is 8 m/s east; the y-component is 14.5 m/s North. (a) What is the value of the resultant vector? (b) What is the angle of the resultant vector?
Explanation:
Given that,
The x-component is 8 m/s east and y-component is 14.5 m/s North.
(a) As both x and y components are perpendicular to each other. Their resultant is given by :
\(R=\sqrt{x^2+y^2} \\\\R=\sqrt{(8)^2+(14.5)^2} \\\\R=16.56\ m/s\)
(b) Let \(\theta\) is the resultant vector. So,
\(\tan\theta=\dfrac{y}{x}\\\\\theta=\tan^{-1}(\dfrac{y}{x})\\\\\theta=\tan^{-1}(\dfrac{14.5}{8})\\\\\theta=61.11^{\circ}\)
Hence, the resultant is 16.56 m/s and the angle of the resultant vector is 61.11 degrees.
Arrange the substances in the table from the MOST to the LEAST ordered particle arrangement es ) A) wood, water, neon gas B) wood, neon gas, water water, wood, neon gas D) water, neon gas, wood
Answer:
A) wood, water, neon gas
Explanation:
Matter, which constitutes every known substances is said to exists in three states namely: gaseous, solid and liquid. Each state of matter contain particles that make up their structure.
- Solids have well arranged particles that are tightly packed together to give it its solid shape. Example is wood
- Liquids have particles that are loosely packed together, hence, can still move about. Example is water
- Gases have particles that are not packed together, hence, their ability to roam freely. Example is neon gas
Based on this, the order of MOST to LEAST ordered particle arrangement is solid - liquid- gas i.e. wood - water - neon gas.
If I make a tortilla by mixing 55 grams of flour and 20 grams of water how much mass should my tortilla have
Answer:
Your tortilla would weigh 75 grams total.
Explanation:
55 grams of flour + 20 grams of water = 75 grams total
The tortilla should have a mass of 75 grams.
What is a mixture?A mixture is a combination of two or more substances that are not chemically bonded and can be separated by physical means. In a mixture, each substance retains its own chemical identity and properties. The properties of a mixture can vary depending on the relative amounts of the substances that are mixed together.
There are two main types of mixtures: homogeneous and heterogeneous.
1. Homogeneous mixtures: These are also called solutions, and they have a uniform composition throughout. The components of a homogeneous mixture are not visible to the bare eye and cannot be separated by simple mechanical means. Examples of homogeneous mixtures include salt water, sugar in water, and air.
2. Heterogeneous mixtures: These are mixtures that do not have a uniform composition throughout. The components of a heterogeneous mixture are visible to the bare eye, and they can be separated by mechanical means such as filtration, sedimentation, or decantation. Examples of heterogeneous mixtures include a mixture of oil and water, a salad, and a mixture of sand and pebbles.
Here in the Question,
The total mass of the tortilla will be the sum of the mass of flour and the mass of water used to make it. So, the tortilla should have a mass of:
55 grams (flour) + 20 grams (water) = 75 grams.
Therefore, the Total mass of the tortilla is 75 Grams.
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2. A parallel plate capacitor has an area of 10 cm2 and plate separation 5 mm. 300 V is applied between its plates. If Teflon is inserted between its plates, how much charge does the capacitor hold.
The capacitor holds a charge of approximately 5.3124 microcoulombs (µC) when the Teflon sheet is inserted between its plates.
When a Teflon sheet is inserted between the plates of a parallel plate capacitor with an area of 10 cm² and a plate separation of 5 mm, the amount of charge the capacitor holds can be calculated using the formula Q = CV. With the given values, the capacitance can be determined as C = ε₀A/d, where ε₀ is the vacuum permittivity, A is the area of the plates, and d is the plate separation. The charge held by the capacitor is then Q = CV, where V is the applied voltage. Using these formulas, the charge held by the capacitor can be calculated.
The capacitance (C) of a parallel plate capacitor is given by the formula C = ε₀A/d, where ε₀ is the vacuum permittivity (a constant value), A is the area of the plates, and d is the plate separation. In this case, the area of the plates is given as 10 cm², which is equivalent to 0.01 m², and the plate separation is 5 mm, or 0.005 m. The vacuum permittivity (ε₀) is approximately 8.854 x 10⁻¹² F/m. Substituting these values into the formula, we get C = (8.854 x 10⁻¹² F/m)(0.01 m²)/(0.005 m) = 1.7708 x 10⁻⁸ F.
The charge (Q) held by a capacitor is given by the formula Q = CV, where V is the applied voltage. In this case, the voltage is given as 300 V. Substituting the calculated capacitance value into the formula, we get Q = (1.7708 x 10⁻⁸ F)(300 V) = 5.3124 x 10⁻⁶ C.
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what acceleration of a refrigerator 30s after the person pushes with force of 400n
To calculate the acceleration of the refrigerator 30 seconds after a person pushes with a force of 400 N, we need to first determine the mass of the refrigerator. Let's assume that the mass of the refrigerator is 50 kg. We can use the formula F = ma, where F is the force applied, m is the mass of the object, and a is the acceleration.
To calculate the acceleration of the refrigerator 30 seconds after a person pushes with a force of 400 N, we need to first determine the mass of the refrigerator. Let's assume that the mass of the refrigerator is 50 kg. We can use the formula F = ma, where F is the force applied, m is the mass of the object, and a is the acceleration.
We know that the force applied is 400 N, so we can plug in the values we have:
400 N = 50 kg x a
Solving for a, we get:
a = 400 N ÷ 50 kg
a = 8 m/s²
This means that 30 seconds after the person pushes the refrigerator with a force of 400 N, the refrigerator will be accelerating at a rate of 8 m/s².
To further explain, acceleration is the rate of change of velocity with respect to time. An object accelerates if it changes its velocity with time. It is measured in meters per second squared (m/s²). The force applied to the object, as well as the mass of the object, determines the acceleration of the object.
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identify the distinguishing characteristics of each galaxy type. note: different galaxy types may have the same characteristics.
There are three main types of galaxies: spiral, elliptical, and irregular. Each has distinguishing characteristics that set them apart from one another.
Spiral galaxies are characterized by their rotating disk-like structure with spiral arms. They have a central bulge composed of older stars, surrounded by a flat disk containing younger stars, gas, and dust. Spiral galaxies can be further classified into barred and unbarred, with barred spirals having a central bar structure.
Elliptical galaxies are more spherical or elliptical in shape, and they consist mainly of older stars with little gas and dust. These galaxies have a smooth, featureless appearance and can vary in size from dwarf ellipticals to giant ellipticals. They do not exhibit spiral arms or a central bar like spiral galaxies do.
Irregular galaxies do not fit into the spiral or elliptical categories due to their chaotic shape and structure. These galaxies are rich in gas and dust, and often contain regions of active star formation. Irregular galaxies may be influenced by gravitational interactions with nearby galaxies or have experienced a collision or merger event.
In summary, spiral galaxies are known for their rotating disk and spiral arms, elliptical galaxies for their smooth, featureless appearance, and irregular galaxies for their chaotic structure and active star formation.
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A horizontal mass on a spring is oscillating such that it has a velocity of 5 meters per second when it passes through the equilibrium position. If the spring constant of the spring is 0.6, and the amplitude of the oscillation is 1.5 meters, what is the mass attached to the spring?
The equation for the motion of a mass-spring system undergoing simple harmonic motion is given by:
y = A cos(ωt)
where y is the displacement from equilibrium, A is the amplitude of the oscillation, ω is the angular frequency, and t is time. The angular frequency can be expressed in terms of the spring constant (k) and the mass (m) attached to the spring as:
ω = sqrt(k/m)
At the equilibrium position, the displacement y is zero and the velocity is at its maximum value. The maximum velocity can be calculated as:
v_max = Aω
Substituting the values given in the problem, we have:
v_max = Aω = 1.5 m × sqrt(0.6/m)
At the equilibrium position, the velocity is equal to v_max, so we can write:
v_max = 1.5 m × sqrt(0.6/m) = 0.8 m/s
Squaring both sides and rearranging, we get:
m = (0.6 × 1.5^2)/0.8^2 = 1.64 kg
Therefore, the mass attached to the spring is approximately 1.64 kg.
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How does mass affect the amount of kinetic energy in a moving object? Explain how you know by stating your claim, the evidence for your claim, and your reason why this evidence supports your claim.
A moving object's kinetic energy is inversely correlated with its mass and inversely correlated with the square of its speed.
What is the impact of mass on kinetic energy?If all other variables are maintained constant, mass and kinetic energy have a positive relationship, which indicates that as mass grows, kinetic energy increases. Accordingly, an object with the same mass and speed as another object will have twice the kinetic energy, and another object with the same mass and speed as another object will have four times the initial kinetic energy.
It is more difficult to move and stop heavier objects (i.e., items with more mass). Greater mass, or heavier items, resist change more than lighter ones do. Using a bicycle or a Cadillac while being pushed, or stopping them once they are moving. The difficulty of starting or stopping an object increases with its mass (or inertia).
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Can you give me an example of how sound passes through a solid?please help
Answer:
sound travels through steel about 15 times faster than through air.
Explanation:
The negative will be __________ to the positive. Therefore, they are pulling __________ each other, and creating and electrical force.
Answer:
attracted... (not sure) close to...
1. What is the kinetic theory?
2. What happens to a bimetallic strip when it is placed in heat?
3. Describe two applications of a bimetallic strip.
Answer:
1 =The kinetic theory of gases is a simple, historically significant model of the thermodynamic behavior of gases, with which many principal concepts of thermodynamics were established. The model describes a gas as a large number of identical submicroscopic particles, all of which are in constant, rapid, random motion.
2 =When this bimetallic strip is heated, the brass expands more than the steel and the strip curves with the brass on the outside. If the strip is cooled, it curves with the steel on the outside.
3 =Bimetal strips are also used in time-delay relays, gas oven safety valves, thermal flashers for older turn signal lamps, and fluorescent lamp starters.
Aang and Appa are flying over Ba Sing Se. They covered 500 m in 30 seconds while heading east. What was their velocity?
Answer:
Explanation:
I need help to marysol;)
An object is known to have balanced forces on it. Which of the following would be a true statement?
If an object has a balanced force on it, there is a possibility that the object may be in a position i.e. there is no change in speed and direction of the body.
If the forces acting on an object is balanced, it means that the net force acting on the body is zero.
According to Newton's law of motion, an object will continue in a state of motion in a straight line unless acted upon by an external force.
This external force might be a balanced or unbalanced force. Hence if an object has a balanced force on it, there is a possibility that the object may be in a position i.e. there is no change in speed and direction of the body.
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which two attributes are the most weakly correlated? engine size and cylinders acceleration and mpg engine size and mpg acceleration and vweight
Engine size and mpg (miles per gallon) are the two attributes that are most weakly correlated
Which two attributes are most weakly correlated?Engine size and mpg (miles per gallon) are the two attributes that are most weakly correlated. Engine size and mpg have a negative correlation, meaning as engine size increases, mpg decreases.
Acceleration and engine size have a positive correlation, meaning as engine size increases, acceleration also increases. This correlation is stronger than the correlation between engine size and mpg.
Acceleration and vehicle weight have a negative correlation, meaning as vehicle weight increases, acceleration decreases. This correlation is also stronger than the correlation between engine size and mpg.
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What is the maximum instantaneous power dissipated by a 2.5 −hp pump connected to a 240−Vrms ac power source?
What is the maximum current passing through the pump?
The maximum current passing through the pump is approximately 11 amperes.
To find the maximum instantaneous power dissipated by a 2.5-hp pump connected to a 240-Vrms AC power source, follow these steps:
1. Convert the horsepower (hp) to watts (W): 1 hp is equal to 746 watts, so 2.5 hp × 746 W/hp = 1865 W.
2. Determine the maximum power: For an AC power source, the maximum power is √2 times the RMS power. So, the maximum power = 1865 W × √2 ≈ 2637.4 W.
The maximum instantaneous power dissipated by the pump is approximately 2637.4 watts.
To find the maximum current passing through the pump:
1. Use the formula: Power (P) = Voltage (V) × Current (I).
2. Rearrange the formula to solve for current: I = P / V.
3. Calculate the maximum current: I = 2637.4 W / 240 V ≈ 11 A.
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Explain in terms of internal energy of the system how the evaporation of sweet cools down the body of the athlete after exercising.
The internal energy of the system how the evaporation of sweet cools down the body of the athlete after exercising are mentioned below.
What is evaporation ?
The water cycle's crucial step is evaporation. When a liquid transforms into a gas, evaporation takes place. As rain puddles "disappear" on a hot day or when wet clothing dries in the sun, it is simple to envision. The liquid water in these instances is evaporating into a gas known as water vapor rather than actually dissipating.
What is energy?
Examples and Definitions of Energy (Science) The capacity to work comes from energy. Energy types include chemical, nuclear, and electrical energy. Science and engineering both depend on the idea of energy. Here is a look at the classification of energy as well as its description and examples.
Therefore, The internal energy of the system how the evaporation of sweet cools down the body of the athlete after exercising are mentioned above.
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The count rate of a radioactive source decreases from 1600 counts per minute to 400 counts per minute in 12 hours. What is the half-life of the source?
Answer:
\(t_{1/2}=6 h\)
Explanation:
Let's use the decay equation.
\(A=A_{0}e^{-\lambda t}\)
Where:
A is the activity at t timeA₀ is the initial activityλ is the decay constantWe know that \(\lambda=\frac{ln(2)}{t_{1/2}}\)
So we have:
\(\lambda=\frac{ln(A/A_{0})}{t}\)
\(\frac{ln(2)}{t_{1/2}}=\frac{ln(A/A_{0})}{t}\)
\(t_{1/2}=\frac{t*ln(2)}{ln(A/A_{0})}\)
\(t_{1/2}=6 h\)
Therefore, the half-life of the source is 6 hours.
I hope it helps you!
GUYS COULD SOMEONE PLEASE HELP ME?
PLEASE ASAP
Write a summary of how the eye works:
Answer:
Eye function renders you the sense of sight. They convert light into electrical signals. Afterwards, the brain deciphers these electrical signals into images. Properly working healthy eyes are able to perform the following functions.
Explanation:
a 36 n force is required to push the block up the incline with constant velocity. what is the weight of the block?
Answer:
The weight of the block can be calculated using the equation of force balance, which states that the sum of all forces acting on an object is equal to zero.
Given that a 36 N force is required to push the block up the incline with constant velocity, we can assume that the only other force acting on the block is its weight, which is acting downwards. Therefore, we have:
36 N - the weight of block = 0
So, the weight of the block is 36 N.
The tires of a car make 62 revolutions as the car reduces its speed uniformly from 90.0 km/h to 59.0 km/h. The tires have a diameter of 0.86 m.(A) What was the angular acceleration of the tires? (B) If the car continues to decelerate at this rate, how much more time is required for it to stop? (C) If the car continues to decelerate at how far does it go? Find the total distance.
A) Angular acceleration = -2.47 rad/s²
B) 23.54 seconds
C) The total distance covered = 294.23m
Explanations:The number of revolutions = 62
Angular distance, θ = 62 x 2π
θ = 62 x 2 x 3.142
θ = 389.608 radians
Diameter, d = 0.86 m
Radius, r = d/2 = 0.86/2
r = 0.43m
Initial velocity, v₁ = 90 km/h = 90 x (1000/3600)
v₁ = 25 m/s
Angular velocity, w₁ = v₁ / r
w₁ = 25/0.43
w₁ = 58.14 rad/s
Final velocity, v₂ = 59 km/h = 59 x (1000/3600)
v₂ = 16.39 m/s
Angular velocity, w₂ = v₂ / r
w₂ = 16.39 / 0.43
w₂ = 38.12 rad/s
Using the equation of motion:
\(\begin{gathered} w^2_2=w^2_1\text{ + 2}\alpha\theta \\ 38.12^2=58.14^2\text{ + 2}\alpha(389.608) \\ 38.12^2-58.14^2=\text{ }779.216\alpha \\ 779.216\alpha\text{ = }-1927.1252 \\ \alpha\text{ = }\frac{-1927.1252}{779.216} \\ \alpha\text{ = }-2.47rad/s^2 \end{gathered}\)Angular acceleration = -2.47 rad/s²
B) Amount of time required for the car to stop if it continues to decelerate at this rate
Initial angular speed, w₁ = 58.14 rad/s
When the car stops, final angular speed, w₂ = 0 rad/s
Using the equation of motion below:
\(\begin{gathered} w_2=w_1+\text{ }\alpha t \\ 0\text{ = 58.14 + (-2.47)t} \\ -2.47t\text{ = -58.14} \\ t\text{ = }\frac{-58.14}{-2.47} \\ t\text{ = }23.54\text{ seconds} \end{gathered}\)C) The total distance
Use the equation of motion below:
\(\begin{gathered} S=v_1\text{t + }\frac{1}{2}at^2 \\ a\text{ = }\alpha r \\ a\text{ = (-2.47)(0.43)} \\ a\text{ = }-1.0621m/s^2 \end{gathered}\)\(\begin{gathered} S=v_1\text{t + }\frac{1}{2}at^2 \\ S\text{ = }25(23.54)+0.5(-1.0621)(23.54)^2 \\ S\text{ = }588.5-294.27 \\ S\text{ = }294.23\text{ m} \end{gathered}\)The total distance covered = 294.23m
A uniform electric field of 8 V/m exists between the plates of a parallel plate capacitor. How much work is required to move a 20 mC point charge from the negative plate to the positive plate if the plate separation is 0.050 m
Hello!
Recall the equation for the force experienced by a charged particle in an electric field:
\(F_E = qE\)
q = Charge of particle (20 mC)
E = Electric field strength (8 V/m)
We also know that 'Work' is equivalent to the following:
\(W = F \cdot d\)
W = Work (J)
F = Force (N)
d = distance (between the plates in this instance, 0.050 m)
If we substitute 'qE' for 'F':
\(W = qEd\)
Plug in the given values and solve.
\(W = (0.02)(8)(0.05) = \boxed{0.08 J}\)
**Since we are pushing a positive particle towards the positive plate, we are increasing its electric potential energy, so WE are doing positive work on the particle.