What happens when a loop of wire turns between two permanent magnets in
a generator?
A. A current flows through the loop of wire.
B. Mechanical energy transforms into electromagnetic radiation.
C. Electrical energy transforms into mechanical energy.
D. A current flows through the permanent magnets.

The contact force (in N) between each pair of boxes is mathematically given as

F_{ab} = 3.56 N

F_{bc} = 1.2 N

Generally, Any force that is generated as a consequence of two objects coming into touch with one another is referred to as a contact force. Contact forces are present everywhere and are the cause of the vast majority of macroscopic groupings of matter's obvious interactions with one another.

In conclusion, The equation for is  Acceleration of the system is mathematically given as

a = 8.25 / (5.85 + 2.95 + 1.50)

a= 0.8 m/s^2

Therefore

F_{ab} = (Mb + Mc)*a

F_{ab} = (2.95 + 1.50) * 0.8

F_{ab} = 3.56 N

F_{bc} = Mc * a

F_{bc}= 1.5 * 0.8

F_{bc} = 1.2 N

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Given data,

Volume of lead.

Density of lead.

Consider the formula of density.

Rearrange the formula.

Substitute the given values.

Therefore, the mass of the lead is

Answer:

2.41m/s

Explanation:

Given parameters:

Initial velocity  = 1.5m/s

Acceleration  = 0.275m/s²

Distance  = 6.45m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we apply the kinematics equation below:

           v²  = u²  + 2aS

v is the final velocity

u is the initial velocity

a is the acceleration

S is the distance

         v²  = 1.5²  +  (2 x 0.275 x 6.45)  

          v  = 2.41m/s

(a) The velocity of the ball is 41.16 m/s.

(b) The height reached by the ball is 86.44 m.

Velocity is the rate of change of displacement.

(a) To calculate the velocity at which the pitcher throw the ball, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute thee values into equation 1

(b) To calculate how high the ball rise, we use the formula

Where:

Substitute into equation 2

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A defining characteristic of a city is often referred to as a "landmark." A landmark is a distinctive feature or building that stands out and is used to identify or represent a location. Landmarks can be man-made, such as structures, monuments, or historical locations, or they can be natural, like mountains, rivers, or lakes.

Landmarks are significant tourist destinations for both locals and visitors because they frequently have historical, cultural, or architectural value. They can serve as a symbol of a city's identity, history, and personality and end up being recognised as the place's iconic symbols. Landmarks might be notable buildings, statues, cathedrals, museums, or bridges that have come to symbolise the city in which they are located.

Therefore, option (OB) "landmark" is the term used to describe a distinguishing feature in a city.

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Yes, if a body is floating in a liquid, the rise in the liquid level is equal to the body height. This phenomenon is known as Archimedes' principle.

Archimedes' principle says when a body is immersed in a fluid (liquid or gas), it experiences an upward buoyant force equal to the weight of the fluid displaced by the body. Buoyant forces act in the opposite direction to gravity.

When a body floats in a liquid, it displaces a volume of liquid equal to its volume. As a result, the liquid level rises by an amount equal to the height of the submerged part of the body.

This principle holds for objects that float or are partially immersed in a liquid, such as a buoyant boat or a floating object. However, if the body sinks completely into the liquid, the liquid level rise will no longer be equal to its height. Instead, it depends on the density and volume of the submerged object.

We will have the following:

For a positive charge, the field lines point away from the charge. [Option D]

The force in the cord ab is 37.6 lb when being lifted at a constant speed, and the angle u for balance.

The rotation of the earth is an example of a body that is moving with uniform velocity when its speed is increasing throughout an interval of time.

The sum of the forces in each direction must be zero in order to lift the block at a steady speed.

XFx = 0 : F sin θ − T sin 20° = 0

XFy = 0 : T cos 20° − F cos θ − 20 = 0

The tension in cord CAD stays constant throughout because there is no friction on the pulley: F = 20 lb.

20 sin θ − T sin 20° = 0......... (1)

T cos 20° − 20 cos θ − 20 = 0 ........(2)

Solve equation (1) for T

T = 20 sin θ/sin 20

and substitute it into equation (2).

(20 sin θ/sin 20°)cos 20° − 20 cos θ − 20 = 0

cot 20°sin θ − cos θ − 1 = 0

cot 20°sin θ − 1 = cos θ

cot 20°sin θ − 1 = √1 − sin2θ

cot²20°sin²θ − 2 cot 20°sin θ + 1 = 1 − sin²θ

(cot²20° + 1) sin²θ − 2 cot 20°sin θ = 0

csc²20°sin²θ − 2 cot 20°sin θ = 0

(csc²20°sin θ − 2 cot 20°) sin θ = 0

csc²20°sin θ − 2 cot 20° = 0 or sin θ = 0

sin θ = 2 cot 20°/csc² 20°

= 2 cos 20°sin 20° = sin 40° or sin θ = 0

θ = 40° or θ ≠ 0°.

Substitute this nonzero value for θ into the formula for T.

T =20 sin θ/sin 20°

≈ 37.6 lb

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Answer:

Explanation:

Given that

speed u=4*10^6 m/s

electric field E=4*10^3 N/c

distance b/w the plates d=2 cm

basing on the concept of the electrostatices

now we find the acceleration b/w the plates

acceleration a=qE/m=1.6*10^-19*4*10^3/9.1*10^-31=0.7*10^15 =7*10^14 m/s

now we find the horizantal distance travelled by electrons hit the plates

horizantal distance X=u[2y/a]^1/2

=4*10^6[2*2*10^-2/7*10^14]^1/2

=3*10^-2=3 cm

now we find the velocity f the electron strike the plate

v^2-(4*10^6)^2=2*7*10^14*2*10^-2

v^2=16*10^12+28*10^12

v^2=44*10^12

speed after hits =>V=6.6*10^6 m/s

The correct answer is 54.6 min.

Running speed of Ilya and Anya is v_r=7.50 mi/hr

Walking speed of Ilya and Anya is v_w=3.50 mi/hr

Total length of the route is d=5.00 miles.

Total time taken by Anya to cover the distance is

\(t_A= d/2/v_r+ d/2/v_w\)

\(t_A= d/2v_r + d/2v_w\)

\(t_A=d/2 \times1/v_r +1/v_w\)

\(t_A= d/2 \times v_r+v_w / v_rv_w\)

\(t_A\)= 5.00/2 × 7.50+3.50/7.50 × 3.50 hr

\(t_A\)= 5.00/2 × 11/26.25 hr

\(t_A\)= 55/52.5 hr

\(t_A\)=1.05 hr

Therefore Anya will take 1.05 hr to cover the distance.

Average speed of Anya is

\(v_{avg} = d/t_A\)

\(v_{avg}\)= 5.00/1.05 mi/hr

\(v_{avg}\) = 4.76 mi/hr

Therefore Anya's average speed is 4.76 mi/hr.

If total time taken by Ilya to cover the distance is t , then

(\(v_r\) × t/2+(v_w × t/2=d))

t/2 × (\(v_r+v_w\))=d

t × (\(v_r+v_w\))=2d

t = 2d/(\(v_r+v_w\))

t = 2 × 5.00/7.50+3.50

t = 10/11 hr

t = 0.91 × 60 min

t = 54.6 min

Therefore total time taken by Ilya to cover the distance is 54.6 min.

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Answer:

el conductor

Explanation:

gracias por los puntitoss

Answer:

conductor

Explanation:

The motion of a spring represents a longitudinal wave.

Option d is correct.

Because the medium's vibrations run parallel to the direction the sound wave travels, sound waves in air (and any other fluid media) are longitudinal waves.

Sound waves are the right response. In longitudinal waves, the particle's medium vibrates in a direction parallel to the wave's propagation. By vibrating in the wave's line of transmission, particles in longitudinal waves move energy from one location to another.

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Answer:

A = 0.13 m

Explanation:

Given that,

Mass of a block, m = 1.4 kg

Spring constant of the spring, k = 16.5 N/m

While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 45.0 cm/s or 0.45 m/s

We need to find the amplitude of the subsequent oscillations.

We can use the conservation of energy here. Initially, the kinetic energy of the block is maximum and then it gets converted to the potential energy of the spring.

Mathematically,

\(\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\)

A is the amplitude of subsequent oscillations.

\(A=\sqrt{\dfrac{mv^2}{k}} \\\\A=\sqrt{\dfrac{1.4\times (0.45)^2}{16.5}} \\\\A=0.13\ m\)

So, the amplitude of subsequent oscillations is 0.13 m.

Dry unit weight: The dry unit weight can be calculated using the equation yd = y / (1 + Gsw). Substituting the given values gives yd = 112 / (1 + 2.67(10.8/100)) = 104.4 lb/ft3.

An equation is a mathematical expression that uses symbols to represent a relationship between two or more quantities. Equations are often used to describe physical laws and to solve mathematical problems. An equation typically consists of an equal sign (=) separating two expressions that have the same value. These expressions can contain numbers, variables, operations, functions, and other mathematical objects. Equations can be used to solve for unknown values, to predict the behavior of a system, or to describe a relationship between different variables.
Void ratio: The void ratio can be calculated using the equation e = (y - yd) / yd. Substituting the given values gives e = (112 - 104.4) / 104.4 = 0.075.
Porosity: The porosity can be calculated using the equation n = e / (1 + e). Substituting the given values gives n = 0.075 / (1 + 0.075) = 0.072.
Degree of saturation: The degree of saturation can be calculated using the equation S = w / (w + (Gs - 1)n). Substituting the given values gives S = 10.8 / (10.8 + (2.67 - 1)0.072) = 0.78 or 78%. The degree of saturation is the ratio of the amount of water in the soil (w) to the maximum amount of water it can hold (w + (Gs - 1)n). In this case, the soil is 78% saturated.

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Answer:

a. massa final

Explanation:

eu escolhi isso porque essa é a resposta espero que ajude você pode me dar uma ideia?

After a great many contacts with a charged ball, the charge on the rod is arranged in such a way that the rod becomes neutral.

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Answer:

6

Explanation:

nothingnsbejejjdbsbzbawkje

Answer:

The square of orbital period is proportional to the cube of the semi-major axis.

Explanation:

I just took the quick check

The magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s

The rotating equivalent of linear momentum in physics is called angular momentum. Because it is a conserved quantity—the total angular momentum of a closed system stays constant—it is significant in physics. Both the direction and the amplitude of angular momentum are preserved.

Given the density of air to be 1.29 kg/m3 and a wind speed of 73.0 mi/h

We have to find the magnitude of the angular momentum

Let,

ρ = Density of air = 1.29 kg/m^3

v = Speed of wind = 73.0 mi/h = 0.032 km/s

M = angular momentum of air

Let the volume of air be 1 m^3

Mass = Volume x ρ = 1 x 1.29 = 1.29 kg

Momentum = M = mass x velocity

Momentum = 1.29 x 0.0032

Momentum = 4.128 x 10^(-3) kg·m^2/s

Hence the magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s

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We are given –

As we know –

↠K.E = 1/2 mv ²

↠ 15.6 = 1/2 × 5.5 × v ²

↠15.6 = 2.75 v ²

↠2.75v ² =15.6

↠v ² = 5.67

↠v=√5.67

↠v = 2.381 m/s

The magnitude of the electric field is the largest in the range of r = 3m to r = 4m.

An electric field can be described as the physical field that surrounds electrically charged particles and acts as a force on all other charged particles in the field and also refers to the physical field of a system of charged particles.

The magnitude of the electric field can be expressed as  given by:

\({\displaystyle E=-{\frac {\Delta V}{d}}}\) where ΔV is the voltage difference between the plates and d is the separation between the plates.

From the attached graph: range r = 0 to r= 3:

\(\displaystyle E =-\frac{dV}{dr}\)

\(\displaystyle E =-\frac{(4-0)}{3-0}=\frac{4}{3} = 1.33 V/m\)

For the range r = 3 to r= 4:

\(\displaystyle E =-\frac{dV}{dr} =\frac{4-(-4)}{4-3} =8 \; V/m\)

Therefore, the largest magnitude of the electric field is in the range of r = 3 to r = 4.

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Answer:

1 km

Explanation:

displacement =velocity ×time

displacement =40m/s ×25s

displacement =1000m equivalent to 1km

Answer: plastic

Explanation:

Answer:

The technician must heat the frame to a temperature of T₂ = 0.0072°C

Explanation:

Change in one-dimension of an object upon heating is given by the following equation:

ΔL = α L ΔT

For the radius this equation can be re-written as follows:

ΔR = α R ΔT

where,

ΔR = Change in Radius =  2.16 cm - 2.14 cm = 0.02 cm

α = Thermal Expansion Coefficient = 1.3 x 10⁻⁴ /°C

R = Original Radius = 2.14 cm

ΔT = Change in Temperature = T₂ - 20°C

Therefore,

0.02 cm = (1.3 x 10⁻⁴ /°C)(2.14 cm)(T₂ - 20°C)

T₂ - 20°C = (0.02 cm)/(1.3 x 10⁻⁴ /°C)(2.14 cm)

T₂ = 0.0072°C + 20°C

T₂ = 20.0072°C

Answer:

The change in potential energy of the mass as it goes up the incline is 0.343 joules.

Explanation:

We must remember in this case that change in the potential energy is entirely represented by the change in the gravitational potential energy. From Work-Energy Theorem and definition of work we get that:

\(U_{g}= m\cdot g\cdot \Delta y\)

Where:

\(U_{g}\) - Gravitational potential energy, measured in Joules.

\(m\) - Mass, measured in kilograms.

\(g\) - Gravitational acceleration, measured in meters per square second.

\(\Delta y\) - Change in vertical height, measured in meters.

This work is the energy needed to counteract effects of gravity at given vertical displacement.

If we know that \(m = 0.5\,kg\), \(g = 9.807\,\frac{m}{s^{2}}\) and \(\Delta y = 0.07\,m\), the change in the potential energy of the mass as it goes up the incline is:

\(U_{g} = (0.5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.07\,m)\)

\(U_{g} = 0.343\,J\)

The change in potential energy of the mass as it goes up the incline is 0.343 joules.

The change in the potential energy (in Joules) of the mass as it goes up the incline is 0.343 J.

We know that

Potential energy = m*g*h

Here m means the mass = 0.5 kg

g means the gravity = 9.8

And, the h means the height  = 7cm = 0.07m

So, the change in the potential energy should be

=0.5*9.8*0.07

=0.343 J

hence, we can conclude that the  change in the potential energy (in Joules) of the mass as it goes up the incline is 0.343 J.

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Answer: 1.2%

Explanation:

Given

If one borrows $12,250

and give $147 interest on it

Then the interest is given from the formula

\(\Rightarrow S.I=\dfrac{P\times R\times T}{100}\\\\\Rightarrow 147=\dfrac{12,250\times R\times 1}{100}\\\\\Rightarrow R=\dfrac{147}{122.50}\\\\\Rightarrow R=1.2\%\)

Thus, the annual rate of interest  is 1.2%

Answer:36

Explanation:To analyze a series-parallel combination circuit, follow these steps: Reduce the original circuit to a single equivalent resistor, re-drawing the circuit in each step of reduction as simple series and simple parallel parts are reduced to single, equivalent resistors. Solve for total resistance.