What happens to the width of the central maximum if the wavelength is increased?

Answer:

True

Explanation:

The force experienced by a 27 μC charge is 51 N rounded off to 2 significant figures.

The force that a 27 μC charge would experience in the same field can be calculated by multiplying the field strength (1.92 N/C) by the charge (27 μC), giving a result of 52.24 mN with two significant figures.

The first part of the question requires us to calculate the field strength, whereas the second part of the question requires us to calculate the force that a 27 μC charge would experience in the same field. Therefore, we can start by calculating the field strength as shown below:

Field strength (E) can be calculated using the formula shown below:F = Eq => E = F/qWhere,F = 138 mNq = 72 nC=> F/q = (138 × 10^-3)/(72 × 10^-9) = 1916.7 × 10^3 N/C≈ 1.9 × 10^6 N/CTherefore, the field strength is 1.9 × 10^6 N/C rounded off to 2 significant figures.Next, we can calculate the force experienced by a 27 μC charge as shown below:

The force experienced by a 27 μC charge (F2) can be calculated using the formula shown below:F2 = Eq2=> F2 = E × q2Where,E = 1.9 × 10^6 N/Cq2 = 27 μC = 27 × 10^-6 C=> F2 = (1.9 × 10^6) × (27 × 10^-6) = 51.3 N ≈ 51 NTherefore, the force experienced by a 27 μC charge is 51 N rounded off to 2 significant figures.

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Answer:

u breathe lol nice ok bro

I would choose the option B.

F = ma

a = 75 / 25 = 3 m/s^2

The acceleration of the given object will be equal to 3 m/s². Therefore, option (B) is correct.

Acceleration of an object can be explained as the change in the velocity of an object with respect to time. The acceleration is a vector quantity as it exhibits magnitude and direction. Acceleration can be calculated from the 2nd derivative of the position of the object w.r.t. time.

The force is the product of the mass and acceleration, according to Newton's second law of motion.

F = ma

And,   a = F/m

From the above formula, we ca say that the acceleration is inversely proportional to mass.

Given, the force acting on the object, F = 75 N

The mass of the object, m = 25.0 Kg

The acceleration of the given object, a = 75/25 =3 m/s²

Therefore, the acceleration of the object is equal to 3 m/s².

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Answer:

I believe it is actually C

Explanation:

Matter and energy cannot be created or destroyed so A is incorrect

Since energy cannot be created, B is incorrect

while C and D both sound correct, D does not mention entering while C does so I believe C is correct. When i submit this answer into my quiz, i will add if i am right.

In the universe, all energy and matter are contained; no energy or matter enters or exits - the statement best describes why the universe could be considered an isolated system.

A thermodynamic system is said to be isolated if it cannot exchange either mass or energy with the outside world. In contrast to a closed system, energy can't move across isolated systems. Energy can move freely within and outside of closed systems; they are only closed to matter.

As both energy and matter can not exit from a universe, we can consider universe as a isolated system.

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Answer:

Explanation:

We build graphs of speed and acceleration.

Acceleration is positive in the interval  (0 - 8) s.

Acceleration is negative in the interval (8-10) s.

The work done by friction is μNd.

what is wotk done?

Work done is the amount of energy transferred by a force to an object when it moves through a distance.

It is calculated by multiplying the force applied to the object by the distance it moves.

Work done is measured in joules (J) and is represented by the equation W = F x d.

Work done by friction = Force x Distance

                                    = Friction coefficient (μ) x Normal Force (N) x Distance (d)

                                    = μNd

Therefore, The work done by friction is μNd.

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Answer:

I am really sorry but I can't understand the question.

Can you translate the question to English?

Explanation:

If you look away from the road for just two seconds, your chance of having a crash actually increases significantly. It is estimated that taking your eyes off the road for just two seconds doubles your risk of a collision.

This is because in that short amount of time, your vehicle can travel a considerable distance, and you may not be aware of potential hazards or changes in road conditions. It is essential to stay focused and alert while driving to ensure your safety and the safety of those around you.

A collision is an event in which two or more objects come into contact with each other, resulting in a transfer of energy and/or momentum between the objects. Collisions can be classified into different types based on the nature of the contact, the forces involved, and the resulting motion of the objects.

Elastic collisions occur when the objects bounce off each other without any deformation or loss of kinetic energy. In this type of collision, the total kinetic energy of the system is conserved. An example of an elastic collision is the collision between two billiard balls.

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Full question:

If you look away from the road for just two seconds, your chance of having a crash actually __________.

Looking away from the road for just two seconds significantly increases your chance of having a crash because it means you're not fully focused on driving. This lack of focus is a major cause of accidents. Therefore, continued attention on the road is vital.

If you look away from the road for just two seconds, your chance of having a crash actually increases significantly. This is because 2 seconds is a substantial amount of time in a high-speed situation, where situations and obstacles can arise suddenly. Taking your eyes off the road when driving means you are not fully focused on the task, which is a major cause of accidents. It is essential to maintain complete attention when driving to prevent potential hazards and to react quickly to changing circumstances.

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Answer:

Since the beat frequency is 2/sec and one of the players is moving towards the stationary observer (he will hear 660 / sec from the trumpet player that is also stationary), the player moving towards the observer will produce a frequency of 662/sec as heard by the observer.

f' = f * v / (v - vs) where vs is the speed of the source

We can use 331 m/s as the speed of sound in dry air

f' v - f' vs = f v        rearranging

vs = v (f' - f) / f'

vs = 331 m/s * (662 - 660) / 662 = 1 m/s

The rock would fall approximately 398.34 meters from rest in 9.5 seconds on Venus.

To find the distance a rock would fall on Venus under the influence of gravity, we can use the equation of motion:

distance = (1/2) × acceleration × time²

Given:

acceleration due to gravity on Venus = 8.87 m/s²

time = 9.5 s

Plugging these values into the equation, we have:

distance = (1/2) × 8.87 m/s² × (9.5 s)²

Calculating the distance:

distance = (1/2) × 8.87 m/s² × 9.5² s²

        = 0.5 × 8.87 m/s² × 90.25 s²

        = 398.34125 meters

Therefore, the rock would fall approximately 398.34 meters from rest in 9.5 seconds under the influence of gravity on Venus.

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Answer:

false

Explanation:

Answer:

No and yes it's like a 30%or 20%

Explanation:

"researchers say that there is no proof that dimples are inherited."

meaning that if the mom or dad had dimples it might have a chance or no since a dominant trait not a recessive trait

Answer:

50 m/s²

Explanation:

Givens:

F = 25N horizontally

m = 0.5 kg

a = ?

We are solving for a, so plug in the known values into the formula F = ma

25N = 0.5kg*a

Divide both sides by 0.5kg

(Note that 1N = 1kg*m/s², so when you divide, kg cancels out leaving you with m/s²)

50 m/s² = a

According to the question, the ranking in increasing momentum is: Object C < Object A < Object B.

To rank the objects in order of increasing momentum when they all have the same kinetic energy, we can use the equation for momentum:

Momentum (p) = mass (m) × velocity (v)

Given:

Object A: Mass = m

Object B: Mass = 4m

Object C: Mass = m/4

Since they all have the same kinetic energy, we can assume that their velocities are different. Let's consider the relationship between momentum and mass:

For objects with the same kinetic energy, momentum is directly proportional to the square root of mass.

Ranking the objects in order of increasing momentum:

Object C: Mass m/4 - The smallest mass results in the lowest momentum.

Object A: Mass m - A moderate mass compared to the other objects.

Object B: Mass 4m - The largest mass results in the highest momentum.

Therefore, the ranking in increasing momentum is:

Object C < Object A < Object B

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Answer:

initially- with positive potential differences - the current is directly proportional to the p.d. However, as the current through the filament increases, the heating effect caused in the lamp also increases and so the temperature of the filament rises. This increase in the filament's temperature also increases the resistance of the filament. As a result the rate of increase of the current decreases and a greater change in the potential difference is required to cause a change in the current. This can be seen on the curve as the gradient becomes more shallow (greater resistance). This same pattern is repeated when a negative potential difference is applied across the filament

The speed of the wave is 0.68 m/s.

Wave speed is the distance the wave travels in a given amount of time, such as the number of meters it travels per second.

V = Fλ

where;

This is the distance between two sequential troughs = 1.1 m

The frequency is number of complete oscillation per second.

f = n/t

where;

f = (9)/(14.5)

f = 0.62 Hz

V = 0.62 x 1.1

V = 0.68 m/s

Thus, the speed of the wave is 0.68 m/s.

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Answer:

Q=mc∆tita.

490J= m× 0.5J/Kg/C × (18-0°C)

490J= m × 9J/kg

490J

9J/Kg = m.

m= 54.4Kg

The anion radius is approximately 0.092 nm

To find the anion radius, we can use Coulomb's law, which states that the force of attraction between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. In this case, the force of attraction between the divalent cation and divalent anion is given as 1.50 x 10^-8 N.

The charge of a divalent cation is 2+, and the charge of a divalent anion is 2-. Therefore, the product of their charges is (2)(2) = 4.

Now, we can use Coulomb's law to calculate the anion radius:

Force of attraction = (k * (charge of cation) * (charge of anion)) / (distance^2)

1.50 x 10^-8 N = (k * 4) / (distance^2)

Now, we need to find the value of the constant k. It is equal to 8.99 x 10^9 Nm^2/C^2.

1.50 x 10^-8 N = (8.99 x 10^9 Nm^2/C^2 * 4) / (distance^2)

To find the anion radius, we need to rearrange the equation to solve for distance:

distance^2 = (8.99 x 10^9 Nm^2/C^2 * 4) / (1.50 x 10^-8 N)

distance^2 = (35.96 x 10^9 Nm^2/C^2) / (1.50 x 10^-8 N)

distance^2 = 2397.33 x 10^17 m^2/C^2/N

Now, we can solve for the anion radius by taking the square root of both sides:

distance = √(2397.33 x 10^17 m^2/C^2/N)

Plugging in the given values, we get:

distance = √(2397.33 x 10^17 m^2/C^2/N)

distance ≈ √(23.97 x 10^18 m^2/C^2/N)

distance ≈ √(2.397 x 10^19 m^2/C^2/N)

distance ≈ √(2.397) x √(10^19) m/C√N

distance ≈ √2.397 x 10^9 m/C√N

Finally, we convert the distance from meters to nanometers:

distance ≈ √2.397 x 10^9 m/C√N

distance ≈ √2.397 x 10^9 m/C√N x (10^9 nm/1 m)

distance ≈ (√2.397 x 10^9 x 10^9) nm/C√N

distance ≈ √(2.397 x 10^18) nm/C√N

distance ≈ √2.397 x 10^9 nm/C√N

Therefore, the anion radius is approximately 0.092 nm.

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Taking the square root of both sides, we find that the anion radius, r, is equal to the square root of (599.33 × \((q^2)\)).

The force of attraction between a divalent cation and a divalent anion is given as 1.50 x\(10^{-8\) N. We can use Coulomb's Law to solve for the anion radius. Coulomb's Law states that the force of attraction between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

The equation for Coulomb's Law is F = k × (q1 × q2) /\(r^2\), where F is the force of attraction, k is the electrostatic constant, q1 and q2 are the charges of the two particles, and r is the distance between them.

In this case, since the charges of the cation and anion are equal in magnitude, their product can be written as \(q^2\). Also, we can substitute the given force value of 1.50 x \(10^{-8\) N.

Therefore, the equation becomes 1.50 x \(10^{-8\) N = k × \((q^2) / r^2\).

To find the anion radius, we need to rearrange the equation to solve for r. Rearranging, we get \(r^2\) = k × (q^2) / (1.50 x\(10^{-8\) N).

Now, we can substitute the known values into the equation. The electrostatic constant, k, is approximately 8.99 x\(10^9 Nm^2/C^2.\)
Let's assume the radius of the cation is 0.092 nm, which is equal to 0.092 x \(10^{-9\) m.

Substituting the values, we have \(r^2\) = (8.99 x \(10^9 Nm^2/C^2\)) * (\(q^2\)) / (1.50 x\(10^{-8\)N).

Simplifying the equation further, we get \(r^2\) = 599.33 × (\(q^2\)).

Finally, taking the square root of both sides, we find that the anion radius, r, is equal to the square root of (599.33 × (\(q^2\))).

Therefore, the anion radius is dependent on the charge of the ion, q. To calculate the specific value, we need additional information about the charge of the ion.

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Answer:

Explanation:

It is still using F = m*a -- just in a disguised form.

Givens

F = 900 N

vf = 360 m/s

vi = 0

t = 40 second

Formulas

a = (vf - vi)//t

F = m * a

Solution

a = (360 - 0)/ 40

a = 9

F = m * a

900 = m * 9

m = 900/9

m - 100 kg.          Doesn't seem high enough.

Answer:

a= V- u/t

a= 360 - 0 /40 = 9 m/sec2

F = MA

900 = M * 9

M = 900/9

M= 100 kg

Answer:

potential - water behind a dam, car parked at the top of a hill, a yo-yo before being released, river water at top of waterfall, a book on a table before it falls, a child at the top of a slide, ripe fruit before it falls.

kinetic - moving car, bullet from a gun, wind mills, flying airplane, walking, running, cycling, rollercoasters.

The soccer ball is 38/5 or 7.6 meters high after 2 seconds.

The equation you've given is a quadratic function that models the height of the soccer ball over time, considering gravitational pull.

To find the height of the ball after 2 seconds, we substitute t = 2 into the equation:

h(t) = -4.9t² + 13.1t + 1.

Therefore,

h(2) = -4.9*(2)² + 13.12 + 1

= -4.94 + 26.2 + 1

= -19.6 + 26.2 + 1

= 7.6 meters.

So, the soccer ball is 7.6 meters high after 2 seconds.

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The height, h meters, of a soccer ball kicked directly upward can be modeled by the equation h(t)=-4.9t2 + 13.1t+1, where t is the time, in seconds, after the ball was kicked.

How high is the ball after 2 seconds?

Answer:

Following are the solution to this question:

Explanation:

Please find the complete question and its solution in the attached file.

Answer:

\(difference \: in \: weight = 150n - 100n = 50n\)

Now,buyantant force

\(difference \: in \: weight \: = volume(body) \times density \: of \: water \: \times g\)

so;

\(50 = {v}^{b} \times 1 \times {10}^{3} \times 9.8m {s}^{2}\)

\( {v}^{b} = \frac{50}{1000 } \times 9.8\)

\( = \frac{50}{9800} \)

\( = 0.0051\)

Now,

\(mass \: in \: air \: = 150n = \frac{150}{9.8kg} \)

\(density = \frac{weght}{volume} \)

\( = \frac{150}{0.0051} \times 9.8 \\ x = 3000\)

And now,

\(specific \: density \: = \frac{density of \: the \: body}{density \: of \: water} \)

\( = \frac{3000}{1000} \)

\( = 3\)

Hence that,specific density of a given body is 3

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Answer:B

Explanation:The ray above makes a 90 degree angle. The ray below makes a 60 degree angle.

Answer:

Matter, Force

Explanation:

In scientific contexts, mass is the amount of "matter" in an object (though "matter" may be difficult to define) whereas weight is the force exerted on an object by gravity. Objects on the surface of the Earth have weight, although sometimes the weight is difficult to measure.

Answer:

Principal focus of concave lens -

★ The point at which rays parallel to principal axis coming from infinity appear to converge after being refracted from concave lens is called the principal focus of concave lens.

________________________

• Additional information -

★ Principal focus - A number of rays parallel to the principal axis after reflection from a concave mirror meet at a point on the principal axis or appear to come from a point after reflection from a convex mirror on the principal axis. This is called principal focus.