What happens to the current in the other two lamps
if one lamp in a three-lamp parallel circuit burns out?

The correct option about his position is : At 2L/9 you will see it tip over

Due to the fact that mass is the quantity of matter contained in an item and does not change with gravity, mass is always the same. As long as the amount of matter in an object doesn't change, its mass will remain constant. In contrast, an object's weight refers to the force of gravity acting on it.

No matter where you are in the cosmos, you have the same mass since mass is a measurement of how much matter is in an object. But because weight measures the force between an object and the body it is resting on, it fluctuates (whether that body is the Earth, the Moon, Mars, et cetera).

Given : A mass of student 40 kg

length is represented by l

Position of the pivot point from the board = l/3

The student should stand at 2L/9 you will see it tip over so as to weigh of 60kg.

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Answer: Yes

Explanation: It's possible to burn paper using convex (magnifying) lens during the day.

Answer:

1.56 m

Explanation:

First, we need to find the current in the wire, so we will use the following equation:

Where V is the voltage, R is the resistance and I is the current. Replacing the values and solving for I, we get:

So, the current is 0.17 A.

Now, the magnetic field generated by a wire with current I at a distance r is equal to:

Where μ is 4π x 10^(-7). So, replacing the values and solving for r, we get:

Therefore, the distance is 1.56 m

Answer:

4m/s²

Explanation:

Initial velocity (u) = 0 m/s

Final velocity (v) = 8 m/s

Time taken (t) = 2 sec

Acceleration (a) = ?

We know

\(a = \frac{v - u}{t} \\ = \frac{8 - 0}{2} \\ = \frac{8}{2} \\ = 4 \: m |s ^{2} \)

Hope it will help :)

The time period of oscillation is 2.09 units.

The equation of motion for a simple harmonic oscillator is given by:

\(\frac{d^2x}{dt^2} + (\omega^2)x = 0,\)

The time period of a periodic motion is the time required for one complete cycle of the motion. In other words, it is the time interval between two successive identical points in the motion.

where x is displacement, t is time, and ω is the angular frequency of the oscillator.

Comparing this equation to the given equation, we can see that \(\omega^2\) = 9, so ω = 3. The period T of the oscillation is given by:

T = 2π/ω

Substituting the value of ω, we get:

T = 2π/3

T = 2 (3.14)/3

T = 2.09

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A wind turbine with an efficiency of 45% for converting wind energy into electrical energy is designed to yield 10 kW of electrical power in a 20 mph wind. The density of air is 1.2 kg/m³. The length of rotor blades that this wind turbine

Given that electrical power is 10 kW.

Electrical Power = (efficiency) × (wind energy intercepted by the rotor blade).

The wind energy intercepted by the rotor blade can be defined as:

Wind energy intercepted by rotor blade = (1/2) × (density of air) × (area swept by the rotor blade) × (velocity³)A   = (2 × electrical power) ÷ (efficiency × density of air × velocity³)A = (2 × 10000) ÷ (0.45 × 1.2 × (20 × 0.447)³).

The area swept by the rotor blade is 128.6 m².

Since, Area of a circle = πr²

Where A = 128.6 m²πr² = 128.6 m²∴ r² = 41.016∴ r = 6.407 m.

So, the rotor blade of the wind turbine is 12.814 meters in length. Hence, the correct answer is 12.814 meters.

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Answer:

1: Because matter has many different forms.

2: The materials that are shown can be organized into 3 different forms; solid, liquid, and gas.

3: The image of the liquids is most likely a material that cannot be found in nature. Liquids have many useful properties, but it depends on the liquid. Bleach is a liquid that has is very useful for sterilizing. Water is useful because without it, life on earth would not exist. And there are many more liquids, but I am going to cut it short here because there too many to put down.

Explanation:

Pls mark Brainliest with the crown.

Answer:

5cm by 4cm by 10cm = 200

200 / 10 = 20

20 :>

Answer:

Yes

Explanation:

When the planet moves farther away, the speed and kinetic energy decrease, and the gravitational potential energy increases.

1. The angular speed of the system when the beads reach the ends of the rod is calculated using the conservation of angular momentum.

2. If the beads fly off the ends, the angular speed of the rod remains constant, option (a) is correct.

To solve this problem, we can apply the principle of conservation of angular momentum. Initially, the system has an angular momentum given by:

\(L_{initial} = I_{rod} * \omega_{initial}\)

where;

\(I_{rod}\) = moment of inertia of the rod

\(\omega_{initial}\) = initial angular speed.

1. To find the angular speed of the system when the beads reach the ends of the rod, we need to consider the conservation of angular momentum after the beads slide outward. At this point, the moment of inertia changes because the beads are no longer at the center.

The final moment of inertia, \(I_{final\), can be calculated as follows:

\(I_{final} = I_{rod} + 2 * (m_{bead} * (L_{rod}/2)^2)\)

where;

\(m_{bead}\) = mass of each bead

\(L_{rod}\) = length of the rod.

Since angular momentum is conserved, we have:

\(L_{initial} = L_{final}\)

\(I_{rod} * \omega_{initial} = I_{final} * \omega_{final}\)

Substituting the expressions for \(I_{final}\) and rearranging the equation, we get:

\(\omega_{final} = (I_{rod} * \omega_{initial}) / (I_{rod} + 2 * (m_{bead} * (L_{rod}/2)^2))\)

2. If the beads fly off the ends, they will carry away some angular momentum. In this case, the angular speed of the rod will decrease. The angular speed after this occurs can be determined by considering the conservation of angular momentum.

When the beads fly off, the final angular momentum is given by:

\(L_{final} = I_{rod} * \omega_{final}_{off}\)

Using the conservation of angular momentum, we have:

\(L_{initial} = L_{final}\)

\(I_{rod} * \omega_{initial} = I_{rod} * \omega_{final}_{off}\)

Since the moment of inertia of the rod doesn't change, the angular speed of the rod after the beads fly off will remain constant. Therefore, the answer is (a) remains constant.

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The composite beam is supported by a roller at A, pin attached at B, and fastened at C. (See pic). The sheer and moment diagrams' figures are included.

At the intersection of "A" and "B," the shear force remains constant. in the Shear diagram, the first incline plane.

Linear shifts in shearing force are present between "B" and "C." The bending moment diagram thus reveals the parabolic shape.

The moment is 0 at point "B."

By calculating the shear force and bending moment at a specific place on a structural element, such as a beam, shear and bending moment diagrams are analytical approaches that are used in conjunction with structural analysis to help structural design.

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Answer:

A compound has unique properties that are distinct from the properties of its elemental constituents. One familiar chemical compound is water, a liquid that is nonflammable and does not support combustion. It is composed of two elements: hydrogen, an extremely flammable gas, and oxygen, a gas that supports combustion.

Answer:

55.128kg

Explanation:

P= m×v

or, m=P/v = 430/7.8 = 55.128 kg

Answer:

55.13 kg

Explanation:

Momentum, P = m*v

P = m*v

m = P/v

m = 430/7.8

m = 55.13 kg

Answer:

7/10

Explanation:

The total number of apples is:

3 + 9 + 15 + 8 + 5 = 40

Of these 40 apples, the number that have a mass greater than 100 is:

15 + 8 + 5 = 28

Therefore, the probability that an apple selected at random will have a mass greater than 100 is:

28 / 40 = 7 / 10

The car travels 72 meters before it stops. When a car is being driven at a rate of 24 m/s when the brakes are applied.

To solve this problem, we need to use the equation:

distance = (initial velocity)^2 / (2 x acceleration)

where initial velocity is 24 m/s and acceleration is -4 m/s^2 (negative because it is decelerating).

Plugging in the values, we get:

distance = (24 m/s)^2 / (2 x -4 m/s^2)

distance = 576 m / (-8 m/s^2)

distance = -72 m

Note that the negative sign indicates that the car is traveling in the opposite direction of the initial velocity. To find the distance traveled in the original direction, we would take the absolute value of the answer, which is 72 m.


d = (v_f^2 - v_i^2) / (2 * a)

where d is the distance traveled, v_f is the final velocity (0 m/s in this case, since the car stops), v_i is the initial velocity (24 m/s), and a is the acceleration (which is negative because it's deceleration, so -4 m/s²).

d = (0^2 - 24^2) / (2 * -4)
d = (-576) / (-8)
d = 72 meters

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To determine the magnitude of the acceleration of the motorcycle, we need to know the force of friction acting on the wheels. The force of friction is equal to the coefficient of friction multiplied by the normal force acting on the wheels, which is equal to the weight of the motorcycle and rider. The weight of the motorcycle and rider can be calculated by multiplying the mass by the acceleration due to gravity (9.8 m/s^2). So, the force of friction acting on the wheels of the motorcycle is equal to 0.88 * 196 kg * 9.8 m/s^2 = 1661.28 N.

The acceleration of the motorcycle is equal to the force of friction divided by the mass of the motorcycle and rider. So, the acceleration of the motorcycle is equal to 1661.28 N / 196 kg = 8.45 m/s^2.

Answer:  8.45 m/s^2

Evidence of a chemical change includes

change in color

Answer:

After 3 seconds, the velocity is 4.5+3×1.5=9 m/s.

Answer:

temperature inside the balloon so it is warmer than the surrounding air

Explanation:

For the balloon to get an uplift , it should be lighter than air . That means the density of the gas inside should be less than the density of air outside . only then ,  weight of the balloon plus the weight of the air inside balloon  will become less than the weight of displaced air outside . This can be achieved by warming up the air inside. Its temperature must exceed that of outside air.

The option that best explain how the pilot can make the balloon rise is option D. The pilot can increase the temperature inside the balloon so it is warmer than the surrounding air

An object will float in air when the density of the object is lower than the density of the air.

Increase in temperature of a gas decreases the density of the gas.

For the pilot to make the balloon rise, he must find a way to make the balloon more lighter than air. To do this, he has to increase the temperature of the balloon.

In this question, the pilot can increase the temperature inside the balloon so it is warmer than the surrounding air in order for the balloon to quickly rise several feet higher above some trees in distance.

Therefore, option D best explain how the pilot can make the balloon rise.

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By solving the given equation on [² f(u)du = t_ -L₁ €² 2 f(u)du is obtained, we can find t.= J 1+e²t / 1 + e2t / 1-e²tdt. Now, we need to solve the integral,∫ 1+e²t / (1 + e2t)(1-e²t) dt.

For this integral, let u = 1+ e²tSo, du/dt = 2e²And, dt = du/2e²= 1/2e² ∫1+e²t / (u)(1-e²t) du= 1/2e² ∫ (1/u) - (e²/(1-e²t)) du= 1/2e² [ln|u| - ln|1-e²t|] + c.

Now, substituting back the value of u,= 1/2e² [ln|1+ e²t| - ln|1-e²t|] + c= 1/2e² ln|1+ e²t / 1-e²t| + c.

Now, putting the limits in the above expression and solving it, we get the value of t.= [1/2e² ln|1+ e²t / 1-e²t|] t = 1 2t / [1 + e²t] - L₁ 2t / [1-e²t].

Hence, the answer is D) f(t)= 2t / [1 + e²t] - L₁ 2t / [1-e²t].

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A white dwarf supernova occurs when a white dwarf accumulates enough mass to ignite carbon fusion in its core. The fusion rapidly spreads throughout the star, causing either a partial or complete explosion of the white dwarf.

A white dwarf is a compact remnant left behind after a low- to intermediate-mass star exhausts its nuclear fuel. In a binary star system, if the white dwarf accretes matter from a companion star or merges with another white dwarf, it can gain mass.

When the white dwarf's mass reaches a critical limit, known as the Chandrasekhar limit (about 1.4 times the mass of the Sun), the carbon in its core becomes dense enough for carbon fusion to initiate.

Carbon fusion, or carbon burning, releases a tremendous amount of energy. This fusion process occurs almost instantaneously throughout the star, leading to a runaway thermonuclear reaction. The sudden release of energy causes a violent explosion, resulting in a white dwarf supernova.

The explosion can be either partial or complete, depending on the exact conditions and dynamics of the star. In a partial explosion, some material is ejected into space while a fraction of the white dwarf remains intact.

In a complete explosion, the white dwarf is completely disrupted and scattered, leaving behind a remnant such as a neutron star or a black hole.

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In comparison to a galaxy and a planet, a star is heavier. an accurate comparison of the cosmological masses of various objects.

A galaxy has a mass that is between that of a moon and that of a planet. A planet has more mass than a star, which has less mass than a galaxy. The stars need a lot of mass to maintain nuclear fusion, which requires resulted in the production of each.

Planets and stars, solar systems, galaxies, and the cosmos are some key concepts to keep in mind in the following order: smallest to largest. Each phrase is a part of the following.

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The rest energy of an 18.5 g piece of chocolate is 1.6601 x 10⁻³ TJ. Answer: 1.6601 x 10⁻³ TJ.

The rest energy, in terajoules, of an 18.5 g piece of chocolate can be found using the equation: E=mc², where E is energy, m is mass, and c is the speed of light squared. Given that 1 TJ is equal to 10¹² J, we can convert the final answer to terajoules (TJ).Here's how to solve the problem:

Convert the mass of chocolate to kilograms. There are 1000 grams in a kilogram, so 18.5 g = 0.0185 kg.

Plug the mass into the equation E=mc²: E = (0.0185 kg) x (299792458 m/s)².

Simplify and solve: E = (0.0185 kg) x (8.98755178736818 x 10¹⁶ m²/s²).

E = 1.6601 x 10¹⁵ J.4.

Convert to terajoules: 1 TJ = 10¹² J, so 1.6601 x 10¹⁵ J = 1.6601 x 10⁻³ TJ.

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Answer:

The Interpretation of Dreams": Freud noticed that dreams played an important role in his analysis of neurotic and "hysterical" patients. When he asked his patients to talk about whatever came into their minds, they often referred to their dreams, which would set off other associations and often illuminate other important connections in their past experience. It took Freud about two years to write the book, finishing it in September 1897.

Answer:

Explanation:

operantly conditioned; positively reinforced

Answer:

Geothermal energy

Explanation:

The speed of your friend during the circular distance is 2 times greater than your speed.

The distance you travelled and the distance travelled by your friend during one rotation is calculated as follows;

your circular distance = 2πr

where;

your distance = 2π(4 m) = 8π m

your friend's circular distance = 2πd

where;

your friends distance = 2π(8 m) = 16π m

The speed of each person at equal time is calculated as;

v = distance / time

your speed = 8π/t

your friend's speed = 16π/t = 2(8π/t)

Thus, your friend's speed = 2 times your speed.

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The molar mass of a compound can be found by adding the molar masses of all of the atoms in the compound.

The molar mass of an atom can be found on the periodic table by looking at the atomic mass listed for that element.

For example, to find the molar mass of water (H2O), we would add the molar masses of two hydrogen atoms (2 x 1.01 g/mol) and one oxygen atom (16.00 g/mol) to get a total molar mass of 18.02 g/mol.

Another way is by finding the molecular formula of the compound, it can be done by analyzing the compound's chemical and physical properties and then using the mass spectrometer to determine the molecular weight.

In conclusion, the molar mass of a compound can be found by adding the molar masses of the atoms in the compound using the atomic masses listed on the periodic table, or by determining the molecular formula of the compound and using a mass spectrometer to find the molecular weight.

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How hard you must push down on the handle is by applying a force of 215.63 N

The moment of a force about a point is the turning effect of the force about that point.

The moment of a force M = Fd where

Now, for you to lift up the car, the moment due to your force about the fulcrum, M equals the moment due to the force on back of car. M'

M = M'

FD = F'd where

Making F subject of the formula,we have

F = F'd/D

Substituting the values of the variables into the equation,we have

F = F'd/D

F = 6900 N × 0.050 m/1.6 m

F = 345 Nm/1.6 m

F = 215.625 N

F ≅ 215.63 N

So, how hard you must push down on the handle is by applying a force of 215.63 N

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