what happens to the average kinetic energy when the average velocity of the molecules is increased by a factor of 2.

The magnitude of car's displacement is 17.78 m.

Given that, distance travelled due north is 11.8 m

Distance travelled due east is 13.3 m

As it is said that the car travels north and then east, it forms the two sides of a right-angled triangle. The magnitude of third side is the magnitude of car's displacement.

From Pythagoras theorem, the expression for car's displacement can be written as,

AC² = AB² + BC²

where, AB and BC are the sides of the right triangle

AC is the displacement of the car

Making AC as subject, we have,

AC = √(AB² + BC²) = √(11.8² + 13.3²) = √(139.24 + 176.89) = 17.78 m

Thus, the magnitude of car's displacement is 17.78 m.

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Answer:

This

Explanation:

Khan academy answer

Adjustment of the lens by the ciliary body is accommodation.

The correct option is D.

The lens is stretched and its refractive strength is changed by the zonule, a collective term for the suspensory ligaments that the ciliary bodies anchor. Relaxation of the zonule allows for accommodation for nearby items.

A section of the central portion of the eye's wall. The ring-shaped muscle that modifies the curvature of the lens whenever the eye focuses is part of the ciliary body, which is located behind the iris. Additionally, it creates the transparent liquid that fills the area between the iris and the cornea.

There are muscles, blood vessels, and epithelium in the ciliary body.

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Answer: Trough

Explanation: The point labeled C in the wave diagram above is the TROUGH of the wave motion. The trough of a wave motion identifies or signifies the point of least or minimum Displacement by measuring the downward Displacement of the wave. The point A is the CREST which is the opposite of the trough, signifying the point of maximum or upward Displacement of the wave cycle.

Point B is the wave amplitude which signifies the maximum extent of vibration from the equilibrium position of a wave. The point labeled D refers to the wavength of the wave motion which is the distance between successive crest or troughs of a wave motion.

Answer:

\(q{_{1}\) = 3C

\(q_{2}\)= 5C

r = 2m

where, q1 & q2 are the charges

& r is the distance between the charges.

Explanation: According, to the Coulombs law,

F = (k\(q_{1}\) \(q_{2}\) )/ r²

Therefore, F = {9×\(10^{9}\) ×3×5}/\(2^{2}\)

F = 33.75 × \(10^{9}\) will be the answer.

Here, k is the constant of proportionality.

The chief and his family should calculate the density of the glittering stone and match it with the density of pure gold.

The glittering stone can be correctly identified whether it is gold or not by calculating its density.

Density is the intrinsic property of matter and it is constant for every matter. Density can be calculated by dividing the mass of the stone by its volume.

Mass can be determined by weighing the stone and volume can determine by putting the stone into a known volume of water and calculate the volume of displaced water.

Therefore, the chief and his family should calculate the density of the glittering stone and match it with the density of pure gold.

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Light that has passed through two slits and formed bars on a surface is an example of constructive interference.

Constructive interference is the phenomenon where the total amplitude of two waves is equal to the sum of their separate amplitudes when two waves are in phase and their maxima add.

A single amplitude equal to the sum of the individual wave amplitudes is produced by the mutual reinforcement of two or more waves of similar frequency and phase during constructive interference. Phase differences between waves must be zero for constructive interference to occur.

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Answer:

no i haven't done it

Explanation:

clean yo computer tho

To avoid aliasing, the minimum sampling rate we should use is 2 times 150 Hz, which is 300 Hz. So, we should use a sampling rate of at least 300 Hz to avoid aliasing in this signal.

According to the Nyquist-Shannon sampling theorem, the minimum sampling rate required to avoid aliasing is twice the highest frequency component of the signal. In this case, the highest frequency component is 150 Hz. Therefore, the minimum sampling rate required to avoid aliasing is:

2 x 150 Hz = 300 Hz

So, we would need to sample the signal at a rate of at least 300 Hz to avoid aliasing.

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Answer:

The train's acceleration is 4.5 m/s²

Explanation:

The train's speed increased by 45 m/s after 10 seconds, which means that it's speed increased by 4.5 m/s each second, or rather 4.5m/s²

According to corollary discharge theory, movement is perceived when the brain receives a copy of the motor command and compares it with incoming sensory feedback to generate a perception of self-motion.

According to corollary discharge theory, movement is perceived through a mechanism involving two signals: the motor command signal and the corollary discharge signal. The motor command signal is sent from the brain to the muscles to initiate movement, while the corollary discharge signal is a copy of the motor command that is sent to sensory areas of the brain.

The corollary discharge signal allows the brain to predict the sensory consequences of the movement before they occur. By comparing the predicted sensory feedback with the actual sensory feedback received during movement, the brain can distinguish between self-generated sensory signals and external sensory signals, thus allowing the perception of movement.

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Answer: 5.26 x 10 -7 squared m

Explanation: I did the CK12 assignment :)

Answer:

a) The net momentum of the bullet-block system before the collision is 25 kilogram-meters per second.

b) The initial translational kinetic energy of the bullet before the collision is 625 joules.

c) The final speed of the bullet-block system after the collision is 7.143 meters per second.

d) The total energy of the bullet-block system after the collision is 89.289 joules.

e) 89.289 joules must be done to stop the bullet-block system.

f) The bullet-block system will travel 13.007 meters before stopping.

Explanation:

a) Since no external forces are applied on the system defined by the bullet and the block, then the net momentum is conserved and can be calculated by  the initial momentum of the bullet:

\(p = m\cdot v_{o}\) (1)

Where:

\(p\) - Net momentum, in kilogram-meters per second.

\(m\) - Mass of the bullet, in kilograms.

\(v_{o}\) - Initial speed of the bullet, in meters per second.

If we know that \(m = 0.5\,kg\) and \(v_{o} = 50\,\frac{m}{s}\), then the net momentum of the bullet-block system before the collision is:

\(p = (0.5\,kg)\cdot \left(50\,\frac{m}{s} \right)\)

\(p = 25\,\frac{kg\cdot m}{s}\)

The net momentum of the bullet-block system before the collision is 25 kilogram-meters per second.

b) The total energy of the bullet before the collision is its initial translational kinetic energy (\(K\)), in joules:

\(K = \frac{1}{2}\cdot m \cdot v_{o}^{2}\) (2)

\(K = \frac{1}{2}\cdot (0.5\,kg)\cdot \left(50\,\frac{m}{s} \right)^{2}\)

\(K = 625\,J\)

The initial translational kinetic energy of the bullet before the collision is 625 joules.

c) Both the bullet and the block experiments a complete inelastic collision, then the final speed of the bullet-block system is calculated solely by the Principle of Momentum Conservation:

\(v_{f} = \frac{m\cdot v_{o}}{m+M}\) (3)

Where:

\(v_{f}\) - Final speed, in meters per second.

\(M\) - Mass of the block, in kilograms.

If we know that \(m = 0.5\,kg\), \(v_{o} = 50\,\frac{m}{s}\) and \(M = 3\,kg\), then the final speed of the bullet-block system is:

\(v_{f} = \left(\frac{0.5\,kg}{0.5\,kg + 3\,kg} \right)\cdot \left(50\,\frac{m}{s} \right)\)

\(v_{f} = 7.143\,\frac{m}{s}\)

The final speed of the bullet-block system after the collision is 7.143 meters per second.

d) The total energy of the bullet-block system after the collision is the translational kinetic energy of the system (\(K\)), in joules, is:

\(K = \frac{1}{2}\cdot (m + M)\cdot v_{f}^{2}\) (4)

\(K = \frac{1}{2}\cdot (0.5\,kg + 3\,kg)\cdot \left(7.143\,\frac{m}{s} \right)^{2}\)

\(K = 89.289\,J\)

The total energy of the bullet-block system after the collision is 89.289 joules.

e) By Work-Energy Theorem, magnitude of the work done by friction must be equal to the magnitude of the translational kinetic energy of the system. Hence, 89.289 joules must be done to stop the bullet-block system.

f) The maximum travelled distance of the bullet-block after the collision can be determined by means of Work-Energy Theorem and definition of work:

\(W = \mu_{k}\cdot (m+M)\cdot g\cdot s\) (5)

Where:

\(W\) - Work done by friction, in joules.

\(g\) - Gravitational acceleration, in meters per square second.

\(s\) - Travelled distance, in meters.

\(\mu_{k}\) - Kinetic coefficient of friction, no unit.

If we know that \(m = 0.5\,kg\), \(M = 3\,kg\), \(\mu_{k} = 0.2\), \(g = 9.807\,\frac{m}{s^{2}}\) and \(W = 89.289\,J\), then the travelled distance of the bullet-block system is:

\(s = \frac{W}{\mu_{k}\cdot (m+M)\cdot g}\)

\(s = \frac{89.289\,J}{0.2\cdot (0.5\,kg + 3\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}\)

\(s = 13.007\,m\)

The bullet-block system will travel 13.007 meters before stopping.

Mugabe gained power by using political strategies, forming alliances, and exploiting his status as a liberation hero within ZANU-PF.

Robert Mugabe, the former president of Zimbabwe, was able to build power through a combination of political strategies and alliances. One key factor was his involvement in the liberation struggle against white minority rule in Rhodesia (now Zimbabwe).

Mugabe emerged as a prominent figure within the Zimbabwe African National Union (ZANU) party, which later merged with the Zimbabwe African People's Union (ZAPU) to form the Zimbabwe African National Union - Patriotic Front (ZANU-PF). Mugabe's role as a liberation hero and his ability to mobilize support among the majority black population of Zimbabwe gave him a strong power base.

Within ZANU-PF, Mugabe strategically positioned himself and gained influence by forming alliances and outmaneuvering rivals. He rose to become the party's leader and played a key role in negotiating the Lancaster House Agreement in 1979, which paved the way for Zimbabwe's independence in 1980. Mugabe became the country's first prime minister and later transformed the position into an executive presidency, consolidating his authority.

Mugabe maintained power through various means, including controlling key institutions such as the military, intelligence agencies, and the ruling party. He also utilized patronage networks, distributing resources and positions to loyal supporters within the party and government. Mugabe's policies, such as the controversial land reform program, further solidified his power base by appealing to nationalist sentiments and redistributing land from white farmers to black Zimbabweans.

However, Mugabe's consolidation of power was also marked by authoritarianism, human rights abuses, and a declining economy. His grip on power faced challenges over the years, including opposition movements, internal party factions, and economic crises. Ultimately, his rule came to an end in 2017 when he was ousted from power following a military intervention.

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Answer:

Input force of pulley system = 200 N

Explanation:

Given:

Mechanical advantage of pulley system = 5

Output force from pulley system = 1,000 N

Find;

Input force of pulley system

Computation:

Mechanical advantage = Output force / Input force

Mechanical advantage of pulley system = Output force from pulley system / Input force of pulley system

5 = 1,000 / Input force of pulley system

Input force of pulley system = 1,000 / 5

Input force of pulley system = 200 N

Answer:

Models are used to study atoms because we can never really see an atom up close, and a model is like a super magnified version of the atom. Plus, its easier to study from them because we can pin point the different characteristics of the atom (Protons, Neutrons, etc.)

Explanation:

Hope this helps! :>

Answer:

I believe its because the molecules are to small to see with the human eye and because the process would be very dangerous and somebody could get hurt.

e. Its location depends only on the masses of the particles and their locations.

The center of mass of a system of particles is defined as the point at which the entire mass of the system can be considered to be concentrated. It is a mathematical concept that simplifies the analysis of the motion of a system.

The center of mass does not necessarily have to be at rest or moving with constant velocity (option b). The center of mass can have any motion, depending on the forces and torques acting on the system.

While the center of mass generally moves in a straight line (option c), this is not always the case if the particles in the system are rotating about it. In such cases, the center of mass follows a curved path due to the rotational motion of the particles.

The kinetic energy of the system is not necessarily a maximum about any axis through the center of mass (option d). The kinetic energy depends on the distribution of mass and the velocities of the particles within the system.

The sum of external torques being equal to the sum of internal torques is a principle known as the conservation of angular momentum, which is not directly related to the definition of the center of mass (option f).

Therefore, the correct statement is that the location of the center of mass depends only on the masses of the particles and their locations (option e). The center of mass is determined by the mass distribution within the system and is independent of the motion or forces acting on the system.

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The number of pascal equivalent to 1 inch of mercury is 3386.53 pascal

From the question given above, we were told that:

29.92 inches of mercury = 1 atm

101325 pascal = 1 atm

Thus,

29.92 inches of mercury = 101325 pascal

29.92 inches of mercury = 101325 pascal

Therefore,

1 inches of mercury = 101325 / 29.92

Thus, the number of pascal equivalent to 1 inch of mercury is 3386.53 pascal

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To find the maximum force that can be exerted horizontally on the wooden crate without moving it, we need to consider the maximum static friction force that can be applied.

The maximum static friction force can be calculated using the equation:

\(F_static_max\) = μ_s * N,

where \(F_static_max\)is the maximum static friction force, μ_s is the coefficient of static friction, and N is the normal force.

The normal force is equal to the weight of the crate, which can be calculated as:

N = m * g,

where m is the mass of the crate and g is the acceleration due to gravity (approximately 9.8 m/s²).

In this case, the mass of the crate is given as 150 kg, so the normal force N is:

N = 150 kg * 9.8 m/s² = 1470 N.

Now, we can calculate the maximum static friction force:

\(F_static_max\) = 0.60 * 1470 N = 882 N.

Therefore, the maximum force that can be exerted horizontally on the wooden crate without moving it is 882 Newtons.

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Answer:

45 meters

3 (m/s) x 15 (s) = 45 meters

The charge in fig A is positive, in fig B is positive and in fig C is negative. this is given by the Fleming's left hand rule.

In magnetism and electromagnetic, the Fleming Left-Hand Rule and Fleming Right-Hand Rule are fundamental principles. They were created by John Ambrose Fleming in the late 19th century as an easy method of determining the direction of motion in an electric motor or the direction of electric current or electric positive charge in an electric generator. It is crucial to remember that these criteria only indicate the direction of the three parameters (magnetic field, current, and force) when the direction of the other two parameters is known and do not define their magnitude.

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Answer:

0.120m

Explanation:

Muscle contraction occurs during both normal day-to-day activities and physical activity. However, the intensity and duration of the contractions differ between the two scenarios.

Muscle contraction is a fundamental process that enables movement in organisms, including humans. During a normal day, muscle contraction is relatively mild and occurs in response to routine activities such as walking, breathing, and even maintaining posture.

These contractions are not very intense and do not last for extended periods as they are efficient and optimized for regular use.

On the other hand, during physical activity, muscle contraction is much more demanding and frequent.

This is because physical activity requires the body to exert an increased effort, leading to an increase in muscle activation.

This increased muscle activity may be coupled with other changes such as alterations in heart rate, oxygen uptake, and metabolism.

Physical activity muscle contractions are therefore more intense and sustained, leading to greater energy expenditure and often causing fatigue.

In conclusion, muscle contraction is vital in enabling movement, and it occurs in both normal day-to-day activities and physical activity. However, the intensity and duration of the contractions differ between the two scenarios.

Normal day-to-day activities involve mild and efficient contractions, while physical activity requires more demanding and prolonged contractions.

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Computerized axial tomography is a noninvasive roentgenography diagnostic technique.

Tomography can be described as imaging by sections or sectioning that uses any type of penetrating wave. The method is used in biology, radiology, archaeology, geophysics, atmospheric science, oceanography, plasma physics, astrophysics, materials science, quantum information, and other areas of science.

In some cases, the production of images will be based on the mathematical procedure of tomographic reconstruction, such as X-ray computed tomography being produced from projectional radiographs.

Most algorithms come into these two categories: filtered back projection (FBP) and iterative reconstruction (IR). Optical coherence tomography is transmission methods, they do not require movement of the transmitter to need data from different directions.

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Answer:

true

Explanation:

Answer:

10.1

Explanation:

10.1

Answer:

10.1

Explanation:

\(\frac{2*\pi *2.1}{1.3}\)

Answer:

40

as it goes up 2second

20+20=40

The net vertical force on the object is

∑ F[vertical] = n - mg = 0

where n is the magnitude of the normal force exerted by the surface, m is the object's mass, and g is the mag. of acceleration due to gravity. It follows that

n = mg = (25 kg) (9.8 m/s²) = 245 N

The net horizontal force is

∑ F[horizontal] = 300 N - f = ma

where f is the mag. of friction and a is the object's acceleration.

We have

f = µn

where µ is the coefficient of friction. Since the object starts at rest, it won't move and accelerate unless the applied force of 300 N is sufficient to overcome the maximum static friction, which is

f = 0.50 n = 0.50 (245 N) = 122.5 N

Since f < 300 N, the box will begin to slide, at which point the coefficient of kinetic friction kicks in and the mag. of friction is

f = 0.30 n = 0.30 (245 N) = 73.5 N

Now solve for a :

300 N - 73.5 N = (25 kg) a

a = (226.5 N) / (25 kg)

a = 9.06 m/s² ≈ 9.1 m/s²

You should disconnect both the blue and red wires connected to the power switch when opening up the Mr. Coffee.

When working on electrical appliances like the Mr. Coffee, it's crucial to ensure safety by disconnecting all power-related wires. In this case, both the blue and red wires are connected to the power switch, which means they are responsible for transferring electricity within the device.

By disconnecting both wires, you can prevent accidental electrical shock and damage to the device while working on it. Always remember to unplug the appliance from the power source and exercise caution when handling electrical components. If you're not confident or experienced in handling electrical devices, it's best to consult a professional for assistance.

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