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Related Questions
1) In hydrogen, the transition from level 2 to level 1 has a rest wavelength of 121.6 nm.
Find the speed for a star in which this line appears at wavelength 120.8 nm .
3) Find the speed for a star in which this line appears at wavelength 121.1 nm ..
5) Find the speed for a star in which this line appears at wavelength 121.8 nm .
7)Find the speed for a star in which this line appears at wavelength 122.4 nm .
Answers
To find the speed of a star in which the hydrogen transition from level 2 to level 1 appears at wavelength 120.8 nm, we can use the Doppler effect. The Doppler effect states that the observed wavelength of light (λobs) emitted by a moving object will be shifted relative to its rest wavelength (λrest) by an amount proportional to the object's velocity (v) with respect to the observer:
λobs = λrest * (1 + v/c)
where c is the speed of light.
In this case, we can use the known rest wavelength of the transition (121.6 nm) and the observed wavelength (120.8 nm) to solve for the velocity:
120.8 nm = 121.6 nm * (1 + v/c)
Solving for v, we get:
v = c * (120.8 nm - 121.6 nm) / 121.6 nm = -12.5 * 10^5 m/s
This is the velocity of the star away from the observer.
To find the speed for a star in which this line appears at wavelength 121.1 nm, we can use the same formula:
v = c * (121.1 nm - 121.6 nm) / 121.6 nm = -2.5 * 10^5 m/s
To find the speed for a star in which this line appears at wavelength 121.8 nm, we can use the same formula:
v = c * (121.8 nm - 121.6 nm) / 121.6 nm = -0.8 * 10^5 m/s
What is the doppler effect?The doppler effect is a physics phenomenon related to the perceived frequency variation of a moving wave relative to an observer.
This effect was studied by the Austrian physicist Christian Doppler (1803-1853) and the discovery was named after him. Hence, the doppler effect.
The doppler effect can be observed in any and all electromagnetic waves, such as light, or mechanical waves, such as sound.
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The arrow strikes a deer in the woods with the speed of 55 m/sec at an angle of 315 degrees. Calculate the Horizontal and vertical components of the arrow’s velocity.
Answers
Answer:
100 m
Explanation:
all points in a rigid body move with the same velocity and acceleration if the rigid body is subjected to all points in a rigid body move with the same velocity and acceleration if the rigid body is subjected to general plane motion translation rotation about a fixed axis none of the above
Answers
All points in a rigid body move with the same velocity and acceleration if the rigid body is subjected to general plane motion.
The general plane motion refers to the movement of a rigid body in two dimensions, where the body can translate (move in a straight line) and rotate about a fixed axis. When a rigid body is subjected to general plane motion, all points on the body will move with the same velocity and acceleration, as the body is rigid and does not deform.
This is in contrast to translation, which refers to movement in a straight line, and rotation about a fixed axis, which refers to rotation around a fixed point. In these cases, the points on the body will not necessarily move with the same velocity and acceleration, as the body is able to deform and rotate.
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A hare and a tortoise compete in a race over a straight course 1.55 km long. The tortoise crawls at a speed of 0.100 m/s toward the finish line. The hare runs at a speed of 7.85 m/s toward the finish line for 1.240 km and then stops to tease the slow-moving tortoise as the tortoise eventually passes by. The hare waits for a while after the tortoise passes and then runs toward the finish line again at 7.85 m/s. Both the hare and the tortoise cross the finish line at the exact same instant. Assume both animals, when moving, move steadily at their respective speeds.
Required:
How far is the tortoise from the finish line when the hare resumes the race?
Answers
Answer:
The tortoise is 3.95 m from the finish line when the hare resumes the race
Explanation:
Since, both the tortoise and the rabbit continue with the same uniform speed. Therefore, we will use the equation for constant speed, that is:
s = vt
t = s/v
where,
s = distance covered
v = speed
t = time taken
Now, we consider the motion of tortoise:
t₁ = s₁/v₁
For hare:
t₂ = s₂/v₂
According to the given condition both hare and tortoise cross the finish line at same instant. Therefore, time for both must be equal.
t₁ = t₂
using values:
s₁/v₁ = s₂/v₂
where,
s₁ = distance of tortoise from finish line when hare starts = ?
v₁ = speed of tortoise = 0.1 m/s
s₂ = distance of hare from finish line when he starts = 1.55 km - 1.24 km = 0.31 km = 310 m
v₂ = speed of hare = 7.85 m/s
Therefore,
s₁/(0.1 m/s) = (310 m)/(7.85 m/s)
s₁ = (0.1 m/s)(39.5 s)
s₁ = 3.95 m
What improvements were made in measuring system with the introduction of standard units?
Answers
Answer:
Standard units are commonly used units of measurement, which help us measure length, height, weight, temperature, mass and more. These units are standardised, which means that everyone gets the same understanding of the size, weight and other properties of objects and things.
Explanation:
Name the charcteristic which help us distinguish berween aman's voice and awamen's seeing them
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Answer:
Asalamalikum maryam
Following are the characteristics that help to distinguish between man's and women's voice
Mans have low pitched sound while as women have hight pitched sound.Mans voice is thick while as women's voice is thin.7. A motorcycle accelerates from rest at a rate of 4 m/s2 while traveling 60m. What is the motorcycle's velocity at
the end of this motion, to the nearest whole number?
A. 240 meters/second
B. 22 meters/second
c. 15 meters/second
D. O meters/second
Answers
Answer: C
Explanation: 60 divided by 4 =15
Velocity can be defined as the rate of change of distance with time
Given data
Acceleration = 4/ms^2
Distance = 60m
Initial Velocity U= 0
Final Velocity V= ?
The expression for velocity is given by
V^2= U^2+2as
Let us substitute our given data into the expression
V^2 = 0^2 + 2*4*60
V^2 = 480
Square both sides
V= √480
V= 21.9 meters/second
V= 22 meters/seconds Approx.
The correct answer is option B
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A car passes point “A” and then 120 meters later. It’s velocity was measured 21 m/s. If it’s acceleration was constant at 0.853 m/s2. What was the car’s velocity at point “A”?
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Recall that
\({v_f}^2-{v_i}^2=2a\Delta x\)
where \(v_i\) and \(v_f\) are the initial and final velocities, respecitvely; \(a\) is the acceleration; and \(\Delta x\) is the change in position.
So we have
\(\left(21\dfrac{\rm m}{\rm s}\right)^2-{v_i}^2=2\left(0.853\dfrac{\rm m}{\mathrm s^2}\right)(120\,\mathrm m)\)
\(\implies v_i\approx\boxed{15.4\dfrac{\rm m}{\rm s}}\)
(Normally, this equation has two solutions, but we omit the negative one because the car is moving in one direction.)
What is the medium of the wave shown in the photograph?
A. The water
B. Kinetic energy
C. The duck
D. Gravity
Answers
Answer:
A. The water
Explanation:
i got it right on A-P-E-X
Two loudsspeakers emit identical sound waves along the x axis. THe osund at a point on the axis has maximum intensity when the speakers are 40 cm apart. The sound intensity decreases as the distance between the speakers is increased, reaching zero at a separation of 50 cm. If the distance between the speakers continuse to increase, at what separation will the sound intensity again be a maximum?
Answers
Answer: 30 cm.
Solving
The situation described is that of two sources of sound waves that are separated by some distance. The two waves interfere with each other constructively at some points and destructively at others. When they interfere constructively, the amplitude (and intensity) of the sound wave is greater than when they interfere destructively.
When the speakers are 40 cm apart, the waves that they produce are in phase at some points on the axis, leading to constructive interference and a maximum in the intensity of the sound. As the distance between the speakers is increased beyond 40 cm, the points of constructive interference move farther apart, and the intensity of the sound decreases. When the speakers are 50 cm apart, the waves that they produce are exactly out of phase at some points on the axis, leading to complete destructive interference and a minimum in the intensity of the sound.
If the separation between the speakers continues to increase, the points of constructive interference will move closer together again, and the intensity of the sound will increase. The separation between the speakers at which the intensity of the sound will again be a maximum can be found using the following equation:
d = λ/2 + nλ
where d is the separation between the speakers, λ is the wavelength of the sound wave, and n is an integer that represents the number of half-wavelengths between the speakers.
At the maximum, the separation is an even multiple of half the wavelength, so we can use the formula above with n = 1. The wavelength can be found from the distance between the speakers at the minimum, which is 50 cm, and the distance at the maximum, which is 40 cm:
λ = 2(d_max - d_min) = 20 cm
Substituting λ and n into the formula gives:
d = λ/2 + nλ = 10 cm + 20 cm = 30 cm
Therefore, the sound intensity will be a maximum again when the separation between the speakers is 30 cm.
which of the following statements are true? group of answer choices a negative charge initially at rest will move toward lower potential and a positive charge initially at rest will move toward higher potential.
Answers
The statement "a negative charge initially at rest will move toward lower potential and a positive charge initially at rest will move toward higher potential" is true.
This is because the direction of motion of a charged particle is determined by the direction of the electric field it is placed in. Electric field lines go from higher potential to lower potential, so a negative charge (which moves in the opposite direction of the electric field) will move towards the lower potential, while a positive charge (which will moves in the direction of the electric field) will move towards higher potential.
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What holds a moon in its orbit?
OA. its own internal magnetism
OB. the heat generated by the planet it orbits
OC. the gravitational pull of the star it orbits
OD. the gravitational pull of the planet it orbits
Answers
Answer:
D
Explanation:
The gravitational pull of the planet it orbits holds a moon in its orbit.
What is the effect of clouds on the "output" of a Solar PV module?
Answers
Answer:
What is the effect of clouds on the "output" of a Solar PV module?
Clouds do impact photovoltaic panels. The quantity of power your photovoltaic panels can produce is directly dependent on the level of light they receive. ... They will see complete direct sunlight “plus” reflected light from the clouds! They will drink in more energy than they could on a cloudless day!
Explanation:
I hope it will help you...
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(b) A ball is dropped from a very large height.
The graph shows how the velocity of the ball changes until just before it hits the ground.
Explain why the velocity of the ball changes in this way. Refer to ideas about forces in your answer.
Answers
When a ball is dropped from a height, its velocity increases linearly due to gravity.
The initial velocity of the ball is zero. As soon as the ball is dropped, velocity starts to increase linearly because of acceleration due to gravity in the downward direction. This is also called free fall. The force of the Earth's gravitational pull causes the ball to accelerate towards the Earth.\(v = u + at\), this is the first equation of motion.Here, "u" is the initial velocity of the ball before it is dropped, "v" is the velocity of the ball at any particular time-"t" before it hits the ground, and 'a' is the acceleration due to gravity.\(u = 0 m/s\) because the ball is at rest before it is dropped.\(a = g = 9.8 m/s^{2}\), this is the acceleration due to gravity.\(v = 0 + (9.8) * t\), this equation shows that the velocity "v" is directly proportional to time "t" for a ball which is dropped from a very large height.To learn more about free fall visit :
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What order does energy flow: sun prodecer consumer?
Answers
Energy flows from the Sun to producers, then to primary consumers, secondary consumers, and potentially to tertiary consumers, forming a pyramid-shaped structure that represents the transfer of energy through different trophic levels in an ecosystem.
Energy flows in a specific order through various components of an ecosystem, starting with the Sun and progressing through producers and consumers. This flow of energy is known as the energy pyramid or trophic levels.
At the base of the energy pyramid is the Sun, which is the ultimate source of energy for most ecosystems on Earth. Sunlight provides the energy needed for photosynthesis, a process carried out by plants, algae, and some bacteria, collectively known as producers. These organisms convert solar energy into chemical energy through photosynthesis, using carbon dioxide and water to produce glucose and oxygen. This process captures and stores energy in the form of organic compounds.
The next level in the energy pyramid consists of primary consumers, also known as herbivores. These are animals that feed directly on producers, such as grazing animals or insects that consume plants. Herbivores obtain energy by consuming plant material and breaking down the organic compounds present in the plants into simpler forms, such as sugars and amino acids, through digestion.
Above the primary consumers are the secondary consumers, which are carnivores or omnivores that feed on herbivores. They obtain energy by consuming primary consumers and breaking down the organic compounds in their prey through digestion. This energy transfer continues up the trophic levels, with each level consuming the one below it.
At the top of the energy pyramid are tertiary consumers, which are typically apex predators. They are carnivores that consume other carnivores. Tertiary consumers obtain energy by consuming secondary consumers and breaking down the organic compounds in their prey.
It's important to note that energy is not efficiently transferred between trophic levels. Only a fraction of the energy consumed at each level is converted into biomass and passed on to the next level. This inefficiency is due to processes such as respiration, heat loss, and incomplete digestion.
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How do magnets work and what effect do they have on their surroundings?
Answers
Answer:
Explanation: Magnets can be used in space. ... Magnets don't need gravity or air. Instead, their power comes from the electromagnetic field they generate all by themselves. One class of magnets, called electromagnets, does need electricity to work.
Answer:
magnets work due to a magnetic field and attract or repel an electrically charged or magnetic objects
Explanation:
its magnetism works due to alignment of atoms in a magnetic object
Which is an example of a non-contact force?
A. A woman pulls open a door.
B. A magnet pulls an item toward it.
C. A student pushes his chair in at his desk.
D. A rolling ball slows down from friction
! Will give brainliest if you help !
Answers
Answer:
B - magnet pulls an item toward it.
Explanation:
It's the answer trust bro
Answer:
B.
Explanation:
Because your not physically touching the item getting pulled towards the magnet. hope this helps
A student measures the speed of sound by echo destiny classes hands and then measures the time to hear the echo his distance to the wall is 300 m The time delay between clap an echo is 1.5 seconds. Calculate the speed of sound
Answers
Explanation:
∆x=300 m×2
∆t=1.5 s
v=∆x/∆t → v=2×300/1.5 = 400 m/s
how does the sun affect the other planets in the solar system
Answers
Answer:
Explanation:
Returning to the scene of the (possible) crime, you estimate that the bathtub in which Polly was found contained around 0.3 m3 (around 80 gallons), which corresponds to 300 kg (since the density of water is 1000 kg/m3), of water as you scoop the water out of the tub. The temperature of this water is 7oC. You assume that the water was initially at its lowest temperature, 2oC, which you find by turning on the cold tap only.
With these measurements, first determine the amount of heat that transferred from Polly and the external environment to warm the cold water. The specific heat of water is about 4186 J/(kgoC). Give your answers in units of kilojoules (kJ).
Answers
This indicates that to increase the temperature of the water in the bathtub from 2°C to 7°C, roughly 62,760 kJ of heat energy were added.
What is the water's temperature?While scientists typically use the Centigrade (or Celsius) scale, where water freezes at 0 degrees and boils at 100 degrees, we typically measure temperature in the United States using the Fahrenheit scale, where water freezes at 32 degrees and boils at 212 degrees.
According to the data given, the bathtub once held 300 kg of water at 2°C.
we can use the specific heat capacity of water and the formula:
Q = m * c * ΔT
The specific heat capacity of water is 4.184 J/(g°C), or 4184 J/(kg°C). Therefore, the amount of heat energy absorbed by the water is:
Q = 300 kg * 4184 J/(kg°C) * (7°C - 2°C)
Q = 62,760 kJ
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a 27 kg is accelerated at a rate of 1.7m/s/s . what force does the object experience
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Complete the ray diagram below:
A concave mirror is shown with curvature positioned at 7 on a ruler that goes from 0 to 14 centimeters. The object is located at 3.5, and the focal point is located at 5.5.
Describe the image characteristics (real or virtual, orientation, size).
Submit your completed ray tracing diagram as an image attachment to this question. Ensure your name and today's date are visible in the image capture.
Answers
The image characteristics will be real ,inverted and formed between centre of curvature and focal point.
Why would you use a concave mirror?
Telescopes that use reflection employ concave mirrors. They also offer an enlarged view of the face for shaving or applying makeup.
Concave mirrors are frequently employed as reflectors in headlights, torchlights, railroad engines, and other parts of autos and motor vehicles. Since the light source is positioned near the mirror's focal point, the light rays are reflected and travel over a considerable distance as parallel, highly intense light beams. Since a convex mirror reflects light outward, it cannot be utilized to concentrate light. Because the focus and center of curvature are fictitious positions inside the mirror and are therefore unreachable, convex mirrors or curved mirrors always produce a virtual image.
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The speed of a 2.0-kg object changes from 30 m/s to 40 m/s during a 5.0-second time interval.
During this same time interval, the velocity of the object changes its direction by 90°. What is the
magnitude of the average total force acting on the object during this time interval?
a. 30 N
b. 20 N
c. 15 N
d. 40 N
e. 10 N
Which is the correct answer?
Answers
Answer:
F = 2 * 30 / 5 = 12 N to stop forward motion
F = 2 * 40 / 5 = 16 N to accelerate to 90 degrees
(12^2 + 16^2)^1.2 = 20 N average force applied
The magnitude of the average total force acting on the object during this time interval is 20 N.
The given parameters:
Mass of the object, m = 2.0 kgInitial velocity, u = 30 m/sFinal velocity, v = 40 m/sTime of motion, t = 5.0 sThe magnitude of the average total force acting on the object during this time interval is calculated as follows;
\(F = \frac{mv }{t} \\\\F_1 = \frac{2(40)}{5} \\\\F_1 = 16\ N\\\\F_2= \frac{2(30)}{5} \\\\F_2 = 12 \ N\\\\F = \sqrt{F_1^2 + F_2^2} \\\\F = \sqrt{16^2 + 12^2} \\\\F = 20 \ N\)
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what is true about ocean water that is more dense?
1. It is generally warmer water.
2. It sinks to the bottom.
3. It has a lower salinity than less dense water.
4. It rises to the surface.
Answers
Answer:
Ocean water is more dense because of the salt in it. ... Temperature has a greater effect on the density of water than salinity does. So a layer of water with higher salinity can actual float on top of water with lower salinity if the layer with higher salinity is quite a bit warmer than the lower salinity layer.
A power plant running at 39 % efficiency generates 330 MW of electric power. Part A At what rate (in MW) is heat energy exhausted to the river that cools the plant
Answers
516.154 megawatts of heat are exhausted to the river that cools the plant.
By definition of energy efficiency, we derive an expression for the energy rate exhausted to the river (\(Q_{out}\)), in megawatts:
\(Q_{out} = Q_{in} - W\)
\(Q_{out} = \left(\frac{1}{\eta}-1 \right)\cdot W\)(1)
Where:
\(\eta\) - Efficiency.\(W\) - Electric power, in megawatts.If we know that \(\eta = 0.39\) and \(W = 330\,MW\), then the energy rate exhausted to the river is:
\(Q_{out} = \left(\frac{1}{0.39}-1 \right)\cdot (330\,MW)\)
\(Q_{out} = 516.154\,MW\)
516.154 megawatts of heat are exhausted to the river that cools the plant.
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The phrase that best describes a field is:
a tower of power
a source of momentum
a sphere of influence
a lever arm
Answers
Answer:
a sphere of influence mmmmmmmmmmm not actually right
what change in the gravitation occurs if the distance between two bodies is doubled by keeping the mass constant?
Answers
Explanation:
Force of gravity = G m1 m2 / r2
now double 'r'
Force = G m1 m2 / (2r) ^2
Force = 1/4 G m1 m2 / r^2 <=====this is 1/4 of the original force of gravity
Calculate the magnetic field at point P in the image below.
Answers
Answer:
B. 10.08
C.2448
Explanation:
Hint: sin2θ + cos2θ = 1 .
Consider the 692 N weight held by two
cables shown below. The left-hand cable had
tension 570 N and makes an angle of θ2 with
the ceiling. The right-hand cable had tension
530 N and makes an angle of θ1 with the
ceiling. a) What is the angle θ1 which the righthand cable makes with respect to the ceiling?
Answer in units of ◦.
b) What is the angle θ2 which the left-hand
cable makes with respect to the ceiling?
Answer in units of ◦.
Answers
a) The angle θ1 which the righthand cable makes with respect to the ceiling is sin^(-1)(692 N / 530 N).
b) The angle θ2 which the left-hand cable makes with respect to the ceiling is sin^(-1)(692 N / 570 N).
We may utilise the tension of the right-hand cable as well as its vertical and horizontal components to determine the angle 1. θ2 = sin^(-1)(692 N / 570 N).
We may apply the ideas of trigonometry and vector addition to address this issue.
a) The tension of the right-hand wire as well as its vertical and horizontal components can be used to determine the angle 1.
T1sin(1) calculates the vertical component of the right-hand cable's tension, which is equal to the object's weight (692 N).
T1sin(θ1) = 692 N
We may rearrange the equation to find 1:
θ1 = sin^(-1)(692 N / T1)
We can find 1 by substituting the given tension value, T1 = 530 N:
θ1 = sin^(-1)(692 N / 530 N)
b) Similarly, we can use the formula to determine the angle 2 the left-hand cable's tension and its vertical and horizontal components.
The vertical component of the left-hand cable's tension is given by T2sin(θ2), and it should also be equal to the weight of the object (692 N).
T2sin(θ2) = 692 N
To find θ2, we can rearrange the equation:
θ2 = sin^(-1)(692 N / T2)
Substituting the given tension value T2 = 570 N, we can solve for θ2:
θ2 = sin^(-1)(692 N / 570 N)
Calculating these angles using the given tension values will provide the answers in degrees.
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If we want to find the size of the force necessary to just barely overcome static friction (in which case fs=μsNfs=μsN), we use the condition that the sum of the forces in both directions must be 0. Using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as:
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Complete Question
Two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. The block in ( The diagram is shown on the first uploaded image ) has a mass m= 10kg and is being pulled by a force F on a table with coefficient of static friction μs=0.3. Four forces act on it:
The applied force F (directed θ=30∘ above the horizontal).
The force of gravity Fg=mg (directly down, where g=9.8m/s2).
The normal force N (directly up).
The force of static friction fs (directly left, opposing any potential motion).
If we want to find the size of the force necessary to just barely overcome static friction (in which case fs=μsN), we use the condition that the sum of the forces in both directions must be 0. Using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as:
Fcosθ−μsN=0
Fsinθ+N−mg=0
In order to find the magnitude of force F, we have to solve a system of two equations with both F and the normal force N unknown. Use the methods we have learned to find an expression for F in terms of m, g, θ, and μs (no N)
Note the diagram is shown on the first uploaded image
Answer:
The expression for F is \(F = \frac{\mu_s * m* g}{[\mu_s * sin (\theta )] * cos (\theta)}\)
Explanation:
Generally from the diagram we see that
\(Fcos\theta -f_s = 0\)
From the question we are told that
\(f_s = \mu_s * N\)
So
\(Fcos\theta - \mu_s * N = 0\)
=> \( N = \frac{Fcos(\theta)}{\mu_s}\)
Also from the diagram
\(Fsin(\theta )+N - F_g = 0\)
Here \(F_g = m * g\)
So
=> \(Fsin(\theta )+ \frac{Fcos(\theta)}{\mu_s} - m* g = 0 \)
=> \(F = \frac{\mu_s * m* g}{[\mu_s * sin (\theta )] * cos (\theta)}\)
