What happens to digital signals sent wirelessly over long distances?

Answer:

air above a wild fire

Explanation:

the type of current formed in the pot is referred to as a convectional current which forms when the heated fluid rises making the cool fluid descend the same happens with the air above a wildfire a convectional current will form when the warm air rises and the cool air descends.the main reason for tge descending and ascending is that the air or liquid closest to the source of heat will get heated making it lighter but the air or liquid tgat was further from the source of heat will not be as light so as the warm fluid rises, the cool fluid descends.

Answer:

air above a wildfire

Explanation

Answer:

17m/s

Explanation:

v=u+at

v=5+3*4

v=17m/s

Pregunta completa :

Un zapato de golf tiene 10 tacos cada uno con un área de 0.01 pulgadas en contacto con el piso suponga que al caminar hay un instante en que los tacos soportan el peso completo de una persona de 180 libras ¿cuál es la presión ejercida por los tacos sobre el suelo?

Responder:

12230825.435 pascal

Explicación:

Dado que:

Peso (W) = 180 libras

Número de tacos = 10

Área por montante = 0.01 in²

Área total (10 * 0.01) = 0.1 pulg²

Usando la calculadora de conversión:

180 libras = 81.647 kg

0.1 pulg² = 6.452 × 10 ^ -5 m²

Recordar :

Presión = Fuerza (Newton) / Área (m²)

Fuerza = masa * aceleración debida a la gravedad

Aceleración por gravedad = 9,8 m / s²

Presión = (81.647 * 9.8) / (6.452 * 10 ^ -5)

Presión = 800.1406 / 6.452 * 10 ^ -5

Presión = 12230825.435 pascal

rate is primarily compared with time but can also be distance. Prime answer is C

Answer:

B. percentage

Explanation:

Rate, in the dictionary, means probability. When you use a percentage, you calculate either the amount of a certain thing out of the whole group, or the PROBABILITY of something.

The spring constant is:

                                             \(\Large\displaystyle\text{$\begin{aligned}k &= 612.5\ \dfrac{\text{N}}{\text{m}}\end{aligned}$}\)

To calculate the spring constant we must remember the law for it, the Hooke's Law:

                                            \(\Large\displaystyle\text{$\begin{aligned}\vec{F} = -k\Delta \vec{x} \end{aligned}$}\)

Where k is the spring constant [N/m].

So if the mass is suspended it means that its weight is equal to the elastic force (values), then we can write:

                                           \(\Large\displaystyle\text{$\begin{aligned}\vec{W} = k\Delta \vec{x} \end{aligned}$}\)

Therefore:

                                          \(\Large\displaystyle\text{$\begin{aligned}mg &= k\Delta x \\ \\k &= \dfrac{mg}{\Delta x} \\ \\\end{aligned}$}\)

Now we just have to put the values and calculate:

                                              \(\Large\displaystyle\text{$\begin{aligned}k &= \dfrac{mg}{\Delta x} \\ \\k &= \dfrac{5\cdot 9.8}{0.08} \\ \\k &= 612.5\ \dfrac{\text{N}}{\text{m}}\end{aligned}$}\)

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Answer:

the correct answer is actually refelcts

Explanation:

The time taken for the motor to raise the piano is 6.67 s

The time taken for the motor to raise the piano can be obtained as follow:

P = mgh / t

7500 = (500 × 10 × 10) / t

7500 = 50000 / t

Cross multiply

7500 × t = 50000

Divide both side by 7500

t = 50000 / 7500

t = 6.67 s

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Answer:

Hope the pictures will help you

Answer:

yes

Explanation:

because you will be hydrated

Answer:

Its good because you can survive without food but you cant survive without water. Extra water can replace empty, sugary calories many people drink with meals.

Explanation:

Answer:

Temperature, density

Explanation:

Physical properties of a substance are those properties that do not change the chemical composition of the substance. There are two types of physical properties namely: intensive property and extensive property.

Intensive properties are those physical properties that does not depend on the sample size of the substance involved. Examples of intensive physical properties are temperature, density, boiling point. For example, the size or amount of a substance does not determine the the TEMPERATURE or BOILING POINT of the substance.

Answer:

a. Please find the attached velocity time graph of the car's motion created with Microsoft Excel

b. The total distance traveled by the car is 8,725 meters

c. The average speed of the car is 22.9605263 m/s

Explanation:

The given parameters of the motion are;

The initial speed of the car, v₁ = 15 m/s

The time during which the car runs at the initial speed, t₁ = 30 seconds

The new speed the car then accelerates at 'a₁' to, v₂ = 25 m/s

The duration it takes for the car to accelerate to the new speed = 20 seconds

The time during which the car runs at the initial speed = 300 seconds

The time it takes the car to be brought to rest with a deceleration, 'a₂' from the new speed (20 m/s) = 30 seconds

The final speed of the car at rest, v₃ = 0 m/s

The acceleration, a₁ = (v₂ - v₁)/t₁ = (25 - 15)/20 = 1/2 m/s²

The deceleration , a₂ = (v₃ - v₂)/t₁ = (0 - 25)/30 = -5/6 m/s²

a. Please find attached the drawing of the velocity time graph of the motion created with Microsoft Excel

b. The total distance traveled by the car, 'Δx', is given b the area under the velocity time graph as follows;

Area of trapezoid, A₁ = (320 + 300)/2 × 10 = 3,100

Area of rectangle, A₂ = 15 × 350 = 5,250

Area of triangle, A₃ = 1/2×30×25 = 375

The total area under the velocity time graph = A₁ + A₂ + A₃ = 3,100 + 5,250 + 375 = 8,725

The total area under the velocity time graph = The total distance traveled by the car, Δx = 8,725 meters

c. The average speed of the car is given as follows;

\(The \ average \ speed \ of \ the \ car, \overline v =\dfrac{\Delta x}{\Delta t} = \dfrac{The \ total \ distance \ traveled by \ the \ car}{The \ total \ time \ the \ car \ travels}\)

Where;

Δt = The total time during which the car travels

∴ The average speed of the car = 8,725 m/(380 s) = 22.9605263 m/s

The light energy absorbed by a surface depends on D. the tilt of the surface.

A beam of light becomes more spread out as E. the beam of light is spread out more.

Some energy is absorbed by Earth's surface when C. the beam of light reaches Earth.

Energy is less concentrated near

G. Earth's poles.

Less energy reaches the poles because

E. the beam of light is spread out more.

Earth is warmest at the equator because

F. energy is concentrated there.

Earth is coldest at the poles because

H. tilt is the greatest there.

Surface temperature depends on the amount of energy absorbed by the surface.

Less energy is received in regions where

E. the beam of light is spread out more.

Earth is warm at the equator and cold at

G. Earth's poles.

The Earth moves in a variety of ways through space. Its main motions are:

Rotation: The Earth rotates on its axis, an imaginary line passing through the North and South Poles. This motion causes day and night to occur, and it takes approximately 24 hours for the Earth to complete one rotation.

Revolution: The Earth revolves around the sun in an elliptical orbit, completing one revolution in approximately 365.25 days. This motion is responsible for the changing of the seasons and the length of the year.

Precession: The Earth's axis wobbles as it rotates, like a spinning top.

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Answer:

42secs

Explanation:

v=u-gt

0=7-10t

10t=7

t=7/10

t=7/10*60

t=42

Given,

The image distance, v=17.22 cm

The focal length of the lens, f=3.05 cm

From the thin lens formula,

Where u is the object distance.

On rearranging the above equation,

On substituting the known values,

Thus the object distance should be 3.71 cm

The amount of heat needed to warm 2 kg of liquid water by 5°C is 41,860 Joules. Temperature is a measure of hotness or coldness that can be described in terms of any number of arbitrary scales.

It also indicates the direction in which heat energy would spontaneously flow, i.e., from a hotter (body) to a colder (body) body.

To warm 2 kg of liquid water by 5°C, we need to calculate the amount of heat required using the formula:
Q = m × c × ΔT
Where:
Q = Amount of heat needed (in Joules)
m = Mass of water (in kilograms)
c = Specific heat of water (4186 J/kg°C)
ΔT = Change in temperature (in °C)
Plugging in the given values, we get:
Q = 2 kg × 4186 J/kg°C × 5°C
Q = 41,860 Joules

The sensible heat of water will rise from 50 to 100 degrees Celsius at this point, and a second phase shift will occur as the temperature rises from 100 to the final temperature of superheated steam.

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It will take approximately 1,428.57 hours, or about 59.5 days, for the space shuttle to travel from Earth to Venus

To calculate the time it takes for the space shuttle to travel from Earth to Venus:

Time = Distance / Speed

Where distance is the distance between Earth and Venus, and speed is the speed of the space shuttle.

Plugging in the given values, we get:

Time = 25,000,000 miles / 17,500 miles per hour

Simplifying the equation, we get:

Time = 1,428.57 hours

Therefore, it will take approximately 1,428.57 hours, or about 59.5 days, for the space shuttle to travel from Earth to Venus at a speed of 17,500 miles per hour.

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Mass of cyclist = 100 kg

Mass of gorilla = 50 kg

Initial speed = 4.5 m/s

Let Final speed = s

100 x 4.5 = (100 + 50) x s

450 = 150s

S = 450/150

S = 3

The new speed is 3m/s

Rounding to two decimal places, the magnification of the image after calculations is -0.57

Using the formula for magnification, we have:

magnification = - image distance / object distance

where the negative sign indicates that the image is inverted.

We can use the thin lens equation to find the image distance:

1/f = 1/do + 1/di

where f is the focal length, do is the object distance, and di is the image distance.

Substituting the given values, we get:

1/75.2 = 1/74 + 1/di

Solving for di, we get:

di = 41.95 cm

Now we can substitute the values for di and do into the magnification formula:

magnification = - di / do

magnification = -41.95 cm / 74 cm

magnification = -0.57

Rounding to two decimal places, the magnification of the image is -0.57.

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The car is going at 24.6 m/s after undergoing an acceleration of 4.2 m/s2 over a distance of 450 m.

The velocity of the car initially was 9.6 m/s and the distance covered by the car is 450 m. The acceleration of the car is 4.2 m/s2. We need to determine the velocity of the car after undergoing an acceleration of 4.2 m/s2. We can use the kinematic formula to determine the final velocity of the car. v2 = u2 + 2aswherev = final velocityu = initial velocitya = acceleration of the objectss = distance covered by the caru = 9.6 m/sa = 4.2 m/s2s = 450 mLet's plug in the values and solve for the final velocity of the car. We have:v2 = u2 + 2asv2 = (9.6)2 + 2(4.2)(450)v2 = 92.16 + 3780v2 = 3872.16Taking the square root of 3872.16, we get:v = 62.22 m/s. Therefore, the car is going at 24.6 m/s after undergoing an acceleration of 4.2 m/s2 over a distance of 450 m.

Given that the velocity of the car initially was 9.6 m/s, the distance covered by the car is 450 m, and the acceleration of the car is 4.2 m/s2. We need to determine the velocity of the car after undergoing an acceleration of 4.2 m/s2.The kinematic equation we use is:v2 = u2 + 2asaWherev = final velocityu = initial velocitya = acceleration of the objectss = distance covered by the carWe have:v2 = u2 + 2asv2 = (9.6)2 + 2(4.2)(450)v2 = 92.16 + 3780v2 = 3872.16Taking the square root of 3872.16, we get:v = 62.22 m/sTherefore, the car is going at 24.6 m/s after undergoing an acceleration of 4.2 m/s2 over a distance of 450 m.

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When a white dwarf star collects matter from a neighboring star in a binary system, fusion reactions on the surface of the white dwarf can cause a phenomenon known as a nova or a thermonuclear runaway.

The process begins when the white dwarf accretes matter from its companion star, typically through a process called Roche lobe overflow. As the accumulated matter builds up on the surface of the white dwarf, it undergoes compression and increases in temperature and pressure.

When the temperature and pressure reach a critical point, the conditions become favorable for nuclear fusion to occur. In particular, hydrogen fusion reactions can take place on the surface of the white dwarf. The fusion of hydrogen nuclei (protons) releases a tremendous amount of energy in the form of light and heat.

This sudden increase in energy output causes a rapid and intense brightening of the white dwarf, resulting in a nova event. The nova can become visible as a temporary, bright stellar explosion, often outshining the original white dwarf and the companion star.

The fusion reactions responsible for novae are different from those that power main-sequence stars like our Sun, which rely on sustained fusion processes. In novae, the fusion reactions are relatively short-lived and occur in a runaway fashion due to the rapid accumulation of matter and the consequent increase in temperature and pressure on the white dwarf's surface.

After the nova event, the white dwarf's luminosity gradually fades as the accumulated matter is dispersed into space. The white dwarf may continue to accrete matter from its companion star, leading to potential future nova events if the conditions are met again.

It's important to note that if the mass of the white dwarf reaches a critical limit known as the Chandrasekhar limit (approximately 1.4 times the mass of the Sun), a different type of explosion called a Type a supernova can occur, with even more significant energy release.

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--The given question is incomplete, the complete question is:

"When a white dwarf star collects matter from a neighboring star, fusion reactions on the surface of the white dwarf cause:

(A)supernovas.

(B) novae.

(C) a planetary nebula.

(D) re-expansion to a red giant."--

Answer:

C

Explanation:

Answer:

C) an investigation of conduction through collisions between particles in space

The rate at which the man's shadow is increasing in length is 0.392 meters per second.

We can use similar triangles to solve this problem. Let's denote the height of the man as h and the length of his shadow as x. Then, we can form a right triangle with the lamppost, the man, and his shadow, where the height of the lamppost is 5 meters and the distance the man walks is given by d = vt, where v is his speed and t is the time elapsed.

Since the triangles are similar, we can write:

x/h = (5 + d)/5

Differentiating with respect to time t, we get:

(dx/dt)/h = v/5

Solving for dx/dt, we get:

dx/dt = (v/5)h

Substituting h = 1.4 meters and v = 1.4 m/s, we get:

dx/dt = (1.4/5)(1.4) = 0.392 m/s

Therefore, the rate at which the man's shadow is increasing in length is 0.392 meters per second.

This problem illustrates how the concepts of similar triangles and related rates can be applied in real-life situations. As the man moves away from the lamppost, his shadow gets longer at a constant rate, proportional to his speed and the height of the lamppost. This is useful in many fields, such as engineering, physics, and economics, where the relationships between different quantities can be analyzed using mathematical models and related rates.

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a) The flow rate will be Q = 84 cm³ per second.

b) The flow speed in the capillaries will be 0.028 cm /s.

The flow rate is defined as the volume of the fluid passing across the cross-section of the pipe in a unit of time.

To calculate the flow rate of blood in the aorta, we can use the equation:

Flow rate = Area x Velocity x Density

Where the area is the cross-sectional area of the aorta, the velocity is the flow speed of the blood in the aorta, and the density is the density of blood (p = 1.0 g/cm³).

Substituting the values we know, we get:

Flow rate = 2.0 cm²x 42 cm/s x 1.0 g/cm³

Flow rate = 84 g/s

Therefore, the flow rate of blood in the aorta is 84 grams per second.

b. According to the principle of continuity, the flow rate of blood must remain constant as it moves from the aorta to the capillaries. Therefore, we can use the equation:

Flow rate = Area x Velocity x Density

To calculate the flow speed in the capillaries, given the combined cross-sectional area of the capillaries.

We know that the flow rate in the capillaries must be the same as the flow rate in the aorta, which we calculated in part a:

Flow rate = 84 g/s

The combined cross-sectional area of the capillaries is given as 3.0 x 10³ cm². Substituting these values in the equation, we get:

84 g/s = 3.0 x 10³cm² x Velocity x 1.0 g/cm³

Solving for the velocity, we get:

Velocity = 84 g/s / (3.0 x 10³ cm² x 1.0 g/cm³)

Velocity = 0.028 cm/s

Therefore, the flow speed in the capillaries is 0.028 cm/s.

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Answer:

Explanation:

Magnetic field due to current carrying wire at a distance r from the  wire is

\(B=\frac{\mu_0I}{2r}---(1)\)

In our case

\(I=\frac{I_0}{2}\)

where,

I₀ = max current or peak current

and r = h (where h is the height of power line)

\(\therefore B=\frac{\mu (I_0/2)}{2h} \\\\=\frac{\mu_0 I_0}{4h} ----(2)\)

put

h ≈ 370m

I₀ ≈ 3KA

\(B= \frac{(1.26*10^-^6)(3*10^3)}{4*(370)} \\\\=2.5*10^-^6 T\)

Two vectors vector a and vector b, each located in a different position in the plane, have equal magnitude and the same direction, both vectors are considered to be parallel to each other.

Two vectors are said to be parallel if and as it were in case the angle between them is degrees. Parallel vectors are too known as collinear vectors, that is two parallel vectors will be continuously parallel to the same line but they can be either within the same direction or within the exact inverse direction. The cross product of any two parallel vectors could be a zero vector. For any two parallel vectors a and b, their dot product is equal to the product of their magnitudes.

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Answer:

79%

Explanation:

Energy expelled / Energy absorbed = 415/525 = 0.79 = 79%

In one cycle, an engine burning a mixture of air and methanol absorbs 525 J and expels 415 J , then the efficiency of engine would be 20.95 %

The efficiency of an Indian can be defined as the ratio of the total useful work done by the engine to the total heat absorbed by the engine
It can be represented in the form of percentage or in terms of fraction as well.

In general the efficiency of an engine represented by the greek symbol η.

The mathematical expression for the efficiency of an Indian can be presented as follows

Efficiency = useful work done /total heat absorbed

Total useful work = total heat absorbed - total heat rejected

For the given problem,An engine burning a mixture of air and methanol absorbs 525 Jules and expel 415 Jules

The total useful work done by the engine = 525 J - 415 J
                                                                       =110 J

η = 110 / 525

  =0.2095

For getting the percentage we have to multiply the fraction with 100.

Thus ,efficiency of the engine comes out to be 20.95%.

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Angular momentum and linear momentum are both important concepts in physics. Both quantities are conserved and have similar mathematical expressions. However, they have different properties and are calculated differently. The answer to the question is c) both of these.

Linear momentumLinear momentum is defined as the product of an object's mass and velocity. It is a vector quantity, meaning it has both magnitude and direction. Linear momentum is always conserved in a closed system. Mathematically, linear momentum can be expressed as:

The difference between the two involves radial distance. Linear momentum depends on the object's mass and velocity, while angular momentum depends on the object's moment of inertia and angular velocity. Both types of speed are also involved in calculating these two quantities. Therefore, the correct answer to this question is c) both of these.

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At each end of a long bone is an expanded portion called an "epiphysis," which articulates (or forms a joint) with another bone.

An epiphysis is a rounded or flat surface located at the ends of a long bone and is covered by a layer of smooth articular cartilage. This cartilage provides a low-friction surface that allows for smooth and pain-free movement between the bones at the joint. The epiphysis is separated from the main shaft of the bone (the diaphysis) by the epiphyseal plate, a layer of hyaline cartilage that allows for growth in children and adolescents. The epiphysis and diaphysis are joined together by a strong and flexible tissue called the epiphyseal line, which eventually fuses in adulthood and forms a solid connection between the two parts of the bone. The epiphysis and diaphysis work together to provide strength, stability, and support to the bones of the skeleton, and the joints formed by the articulation of the epiphysis and another bone play a crucial role in enabling movements such as walking, jumping, and twisting.

In short, an epiphysis is an expanded portion at the end of a long bone that articulates with another bone to form a joint, and it plays an important role in the movement and stability of the skeleton.

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