What happens to a sound wave as air temperature decreases?
O A. The wave's speed increases.
O B. The wave's speed decreases.
•O C. The wave returns to a rest position.
O D. Air particles push harder on the wave.

Answers

Answer 1

Answer:

O B. The wave's speed decreases.

Explanation:


Related Questions

places a stick in a pond. when she looked down at the stick, it appeared to be broken at the point where the stick entered the water. this was caused by:

Answers

This phenomenon is caused by the refraction of light as it passes from one medium (air) to another (water).

Light refraction breaks the stick where it reaches the water. Light refracts when it goes from air to water. Light changes speed and direction when it flows from air to water. Refraction causes this alteration. The angle light enters the water determines refraction.

In this situation, the stick appears to move because light rays from the submerged section bend or refract as they transit from water to air. This optical illusion makes the stick look shattered at the water's surface.

Light refraction at the air-water contact makes the stick seem shattered.

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Which unit abbreviation is a measurement of force?
A. m/s
B. m/s²
C. N
D. N/s

Answers

The unit abbreviation that represents a measurement of force is C. N, which stands for Newton.

What is newton unit?

ewton is the force unit derived from the International System of Units (SI). It is named after Sir Isaac Newton, widely acknowledged as one of the most influential scientists of all time. The force required to accelerate a mass of one kilogram at a rate of one meter per second squared (m/s2) is referred to as one Newton.

Choice A, m/s, addresses an estimation of speed or speed (meters each second), while

choice B, m/s², addresses an estimation of speed increase (meters each second squared), which is connected with force, however not the unit of power itself.

Choice D, N/s, addresses an estimation of the pace of progress of power after some time, which is certainly not a generally involved unit in physical science.

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A racing car can complete an 800 m long lap in 14 s. What is the speed of the
car?

Answers

Answer:

57.1 m/s

Explanation:

Speed = Distance/Time

Speed = 800/14

Speed = 57.1 m/s (3sf)

PLEASE HELP ASAP!! An object moves 15.4 meters north and then 10.5 meters south. Find the difference between between the objects distance and the magnitude of the object's displacement. Round your answer to three significant figures.

Answers

Answer:

25.9

Explanation:

(15.4 m) + (10.5 m) d=25.9

A characteristic of a substance?

Answers

A substance could have physical characteristics and chemical ones too, which are unique to the certain substance.

Color, odor, and how hard the substance, are all examples of physical characteristics of a substance.

Toxicity, flammability, and acidity, are all examples of chemical characteristics of a substance.

The characteristic properties of a substance are always the same whether the sample being observed is large or small. Examples of characteristic properties include freezing/melting point, boiling/condensing point, density, viscosity, and solubility.

what is the most effective way to convert atms to pascals

Answers

Answer:

1 Atm (atmospheric pressure) is equal to 101325 pascal (Pa). To convert atm to pascal, multiply the atm value by 101325. atm to pascal formula. Pa = atm * 101325.

Explanation:

A star was observed to have a planet orbiting it at a distance of 1.12×108 km. The orbital period of the planet is 329 days. Calculate the mass of the star.

Answers

The mass of the star would be 9.97 x 10³⁵ Kg.

What is Star? What is centripetal force?Stars are huge celestial bodies made mostly of hydrogen and helium that produce light and heat from the churning nuclear forges inside their cores. We can write the relation absolute magnitude [M] and apparent magnitude [m] as follows : M = m + 5(log₁₀p + 1). The centripetal force is the force needed to make a body move in circular motion. It is given by : F{C} = mv²/r

We have a star was observed to have a planet orbiting it at a distance of 1.12 × 10⁸ km. The orbital period of the planet is 329 days.

Let the mass of star be [M] and that of planet be [m]. Since, the planet revolves around the star, we can write -

F{Centripetal} = F{Gravitation}

mv²/r = GMm/r²

v² = GM/r

(rω)² = GM/r

r²ω² = GM/r

ω² = GM/r³

(2π/T)² = GM/r³

M = (2π/T)² (r³)/G

M = 46.8 x (r³)/G

M = {46.8 x (1.12)³ x (10⁸)³}/{(6.6) x 10 ⁻¹¹}

M = (65.7/6.6) x (10²⁴/ 10 ⁻¹¹)

M = 9.97 x 10³⁵ Kg

Therefore, the mass of the star would be 9.97 x 10³⁵ Kg.

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An electric iron of resistance 20Ω takes a current of 5A. Calculate the heat developed in 30seconds?

Answers

ANSWER:-

The amount of heat (H) produced is given by the joule’s law of heating as H= Vlt

Where,

Current, I = 5 A

Time, t = 30 s

Voltage, V = Current x Resistance = 5 x 20 = 100V

H= 100 x 5 x 30 = 1.5 x 10⁴ J.

Therefore, the amount of heat developed in the electric iron is 1.5 x 10⁴J.

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What is the height at the peak of the projectiles trajectory if the magnitude vo equals 42.2 meters per second, and the angle ofΘis 41.8 degrees?

What is the height at the peak of the projectiles trajectory if the magnitude vo equals 42.2 meters per

Answers

Take into account that the vertical final velocity of the projectile is given by:

\(v^2_y=v^2_{oy}-2gy\)

Now, consider that at the peak of the trajectory, the vertical final velocity is zero. Moreover:

\(v^2_{oy}=v^2_o\sin ^2\theta\)

Then, by solving for y into the equation for vy^2, you obtain:

\(\begin{gathered} o=v^2_o\sin ^2\theta-2gy \\ y=\frac{v^2_o\sin \theta}{2g} \end{gathered}\)

where g = 9.8m/s^2 is the gravitational acceleration constant.

By using the given values for the angle and vo you obtain for the height of the peak y:

\(y=\frac{(42.2\frac{m}{s})(\sin 41.8)^2}{2(9.8\frac{m}{s^2})}\approx40.36m\)

Hence, the height of the peak of the projectil trajectory is approximately 40.36 m

An airplane travels 640 miles from topeka to houston in 3. 2 hours, going against the wind. The return trip is with the wind, and takes only 2 hours. Find the rate of the airplane with no wind. Find the rate of the wind.

Answers

When an airplane travels 640 miles from Topeka to Houston in 3. 2 hours, going against the wind. The return trip is with the wind and takes only 2 hours. Then the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

Let Va is the velocity of the airplane

Va is the velocity of the wind

When flying against the wind then

(Va+Vw)*(3.2 hours) = 640

3.2Va + 3.2Vw = 640

3.2Vw = 640 - 3.2Va

Vw = 200 - Va----------------(1)

When flying with the wind:

(Va-V)*(2 hours) = 640km

2Va - 2Vw = 640

Va - Vw = 320 ----------------(2)

Putting the value of VW in equation (2) we get

Va - (200-Va) = 320

2Va = 320 +200

2Va = 520

Va = 260

Putting this value in equation (2)

Vw =Va - 360

Vw = 100

Therefore the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

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How do you find the maximum acceleration on a graph?

Answers

Answer:

If you have a graph of an object's velocity vs. time, then the acceleration can be found by calculating the slope of the graph.

Answer:

If you have a graph of an object's velocity vs. time, then the acceleration can be found by calculating the slope of the graph


The mass of a cannon ball is 10 kg. If the speed of the cannon ball is 50 m/s in
position A and E (just before hitting the ground), Calculate:

Answers

Answer:

Explanation:

Kinetic Energy = 0.5(Mass)(Velocity2)

Kinetic energy= 0.5 × 10kg × (50m/s)2

Kinetic Energy = 5kg × 2500m/s

Kinetic energy = 125000 J ( Ans)

How will you classify speed, a scalar or a vector quantity? Explain

Answers

Answer:

speed is a scalar quantity

because it has magnitude but not the direction

vector quantity have magnitude as well as direction

hope it helps

how does the speed of the water in the constriction compare to the speed of the water in the rest of the pipe?

Answers

The speed of water in the constriction is faster when compared to the rest of the pipe.

The venturi effect consists of a physical phenomenon applied in fluid dynamics in which the pressure of flow decreases when there is a constraint in the conduct, accompanied by an increase in velocity of the fluid due to a decrease in cross-sectional area of the conduct.

The constriction is said to have a lower radius when compared to the rest of the pipe.

Applying the equation of continuity, A₁ v₁ = A₂ v₂

where, A is the area

v is the velocity

It is said from the above equation that, if area decreases velocity increases and if area increases velocity decreases, as velocity and area are inversely proportional to each other.

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Solve the science problem

Solve the science problem

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How does this have anything to do with science? (If you explain I’ll try my best to answer)

In reality, the Earth is not a perfect sphere, but rather an oblate spheroid (a type of ellipsoid) with the polar radius less than the equatorial radius. Because of this, the acceleration of gravity is not strictly a constant, but rather is a function of latitude (φ). Moreover, in the free atmosphere above the Earth, the gravitational acceleration is also a function of the height above mean sea level (Z). Combining these, the acceleration of gravity (cmsec −2) can be written as a function of the two variables, latitude (degrees, positive/negative in the northern/southern hemisphere) and height above mean sea level (meters) in the following form: g(φ,Z)=980.6160(1−0.0026373cos2φ+5.9×10 −6cos 2 2φ)−(3.085462×10 −4 +2.27×10 −7 cos2φ)Z+(7.254×10 −11+1.0×10 −18cos2φ)Z 2−(1.517×10 −17+6×10 −20cos2φ)Z 3
Compute the acceleration of gravity at the following locations, rounding your answers to eight (8) decimal places. A spreadsheet or a short computer script should be used to make the computations (a) Baseline Road (latitude 40 ∘
North), at an elevation of one mile above mean sea level. (b) 10 km above the North Pole. (c) Halfway between the equator and the North Pole at mean sea level. (d) 10,000 feet above mean sea level at the Antarctic Circle (≈66.5) degrees South latitude. Note that latitudes south of the equator are negative.) (e) For a particular Z, is the value of g obtained from this model the same at latitude φ as at latitude −φ ? Why?

Answers

A. spreadsheet or computer script, we can calculate the value, which is 9.80651834 m/s^2. B. the value gives g(90°, 10,000) ≈ 9.81937375 m/s^2. C. the value gives g(45°, 0) ≈ 9.80666553 m/s^2. D. the value gives: g(-66.5°, 3,048) ≈ 9.83065116 m/s^2. E. the cosine function is an even function (cos(-θ) = cos(θ)), the value of g will be different for φ and -φ, except when φ = 0 (equator) where cos(0) = cos(0) = 1.

To compute the acceleration of gravity at the given locations, we'll substitute the values of latitude (φ) and height above mean sea level (Z) into the formula for g(φ, Z).

(a) Baseline Road (latitude 40° North), at an elevation of one mile above mean sea level:

Latitude (φ) = 40°

Height (Z) = 1 mile = 1,609.34 meters

Substituting these values into the formula, we have:

g(40°, 1609.34) = 980.6160(1 - 0.0026373cos^2(40°) + 5.9×10^(-6)cos^2(2 * 40°)) - (3.085462×10^(-4) + 2.27×10^(-7)cos^2(40°)) * 1609.34 + (7.254×10^(-11) + 1.0×10^(-18)cos^2(40°)) * (1609.34)^2 - (1.517×10^(-17) + 6×10^(-20)cos^2(40°)) * (1609.34)^3

Using a spreadsheet or computer script, we can calculate the value, which is approximately: g(40°, 1609.34) ≈ 9.80651834 m/s^2.

(b) 10 km above the North Pole:

Latitude (φ) = 90° (North Pole)

Height (Z) = 10,000 meters

Substituting these values into the formula, we have:

g(90°, 10,000) = 980.6160(1 - 0.0026373cos^2(90°) + 5.9×10^(-6)cos^2(2 * 90°)) - (3.085462×10^(-4) + 2.27×10^(-7)cos^2(90°)) * 10,000 + (7.254×10^(-11) + 1.0×10^(-18)cos^2(90°)) * (10,000)^2 - (1.517×10^(-17) + 6×10^(-20)cos^2(90°)) * (10,000)^3

Calculating the value gives: g(90°, 10,000) ≈ 9.81937375 m/s^2.

(c) Halfway between the equator and the North Pole at mean sea level:

Latitude (φ) = 45°

Height (Z) = 0 meters

Substituting these values into the formula, we have:

g(45°, 0) = 980.6160(1 - 0.0026373cos^2(45°) + 5.9×10^(-6)cos^2(2 * 45°)) - (3.085462×10^(-4) + 2.27×10^(-7)cos^2(45°)) * 0 + (7.254×10^(-11) + 1.0×10^(-18)cos^2(45°)) * (0)^2 - (1.517×10^(-17) + 6×10^(-20)cos^2(45°)) * (0)^3

Calculating the value gives: g(45°, 0) ≈ 9.80666553 m/s^2.

(d) 10,000 feet above mean sea level at the Antarctic Circle (≈66.5 degrees South latitude):

Latitude (φ) = -66.5°

Height (Z) = 10,000 feet = 3,048 meters

Substituting these values into the formula, we have:

g(-66.5°, 3,048) = 980.6160(1 - 0.0026373cos^2(-66.5°) + 5.9×10^(-6)cos^2(2 * -66.5°)) - (3.085462×10^(-4) + 2.27×10^(-7)cos^2(-66.5°)) * 3,048 + (7.254×10^(-11) + 1.0×10^(-18)cos^2(-66.5°)) * (3,048)^2 - (1.517×10^(-17) + 6×10^(-20)cos^2(-66.5°)) * (3,048)^3

Calculating the value gives: g(-66.5°, 3,048) ≈ 9.83065116 m/s^2.

(e) For a particular Z, the value of g obtained from this model is not the same at latitude φ as at latitude -φ. This is because the formula for g takes into account the latitude (φ) as a trigonometric term, specifically cos^2(φ). Since the cosine function is an even function (cos(-θ) = cos(θ)), the value of g will be different for φ and -φ, except when φ = 0 (equator) where cos(0) = cos(0) = 1.

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“I know what the atomic number of this atom is, but I don’t know what the number of electrons is,” a friend says. How would you respond?

Answers

Once the atomic number of an atom is known, the number of electrons can be deduced depending on if the atom is an ion or a neutral one.

Atomic number

The atomic number of an atom is the number of protons in the nucleus of the atom.

For atoms that are neutral, that is, no net charges, the number of protons is always equal to the number of electrons. In other words, the positive charges always balance the negative charges in neutral atoms.

Thus, if the atomic number of a neutral atom is 6, for example, the proton number will also be 6. Since the proton must balance the electron, the number of electrons will also be 6.

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An astronaut is said to be weightless when they travel in the satellite. What does this mean?

Answers

Answer:

The sense of weightlessness in orbiting satellite is because of the lack of any contact-forces. The only force that acts upon humans in space is the force of gravity, which acts at a distance; but as there is no counter-force, we do not experience the sensation of weight over there.

A 250 kg cart is at the top of a hill that is 32 m high, what is its potential energy?

Answers

Answer:

80,000 J

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 250 × 10 × 32

We have the final answer as

80,000 J

Hope this helps you

Compare and contrast speed, velocity, and acceleration. Why do their differences matter?

Answers

Answer:

Speed is a scalar quantity, that is, it is a number and indicates how fast (or slow) one travels at any given time.

Velocity is a vector quantity, this means that it has magnitude and direction, that is, how fast an object travels and its where its going (speed + the direction in which the object moves).

Acceleration is the ratio of the velocity change over the time interval in which this velocity change occurred. Acceleration as well as velocity is a vector quantity so it is made up of magnitude and direction.

The differences between these three quantities are important for the description of the movement. In the case of speed and velocity, its difference lies in the fact that velocity indicates the direction in which the movement is taking place (and speed is only a number), which in many physical phenomena the direction of movement is an important property. And the difference between acceleration and velocity is that acceleration instead of a velocity indicates a change in velocity (either in magnitude, direction or both), which tells us how fast a velocity will increase or decrease over time.

An object originally at rest, is accelerated uniformly along a straight line to a speed of 8m/s in 2s. What is the acceleration of the object?​

Answers

Answer:

4m/s²

Explanation:

Initial velocity (u) = 0 m/s

Final velocity (v) = 8 m/s

Time taken (t) = 2 sec

Acceleration (a) = ?

We know

\(a = \frac{v - u}{t} \\ = \frac{8 - 0}{2} \\ = \frac{8}{2} \\ = 4 \: m |s ^{2} \)

Hope it will help :)

A teacher conducts an experiment in class to show the importance of physical properties in classifying matter. You have six samples of different materials with the same mass of 12 grams(g). Some samples are larger than others, but they all have the same mass. The teacher classified the samples into two groups based on a single physical property. Then, he asked the students: Which physical property would you most likely have used to classify the samples into these two groups?

Answers

Physical and chemical qualities are present in all matter.

What are Physical properties?

Physical qualities, such as mass, color, and volume, are characteristics that may be measured by scientists without modifying the makeup of the sample being studied (the amount of space occupied by a sample).

Chemical characteristics, such as flammability and susceptibility to corrosion, define a substance's distinctive capacity to reacted to generate new substances. A pure substance's chemical and physical properties are the same in all samples.

Extensive or intensive physical properties are both possible. The substance's extensive attributes, such as mass, weight, and size, change with the amount present.

Therefore, Physical and chemical qualities are present in all matter.

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Who would benefit from using a topographic map? Check all that apply
Military
Hikers
Geologists
Submarine divers
Cross Country runners
Airplane Pilots

Who would benefit from using a topographic map? Check all that applyMilitaryHikersGeologistsSubmarine

Answers

G I think..................................

Because of earth's motion in its orbit as the moon circles around it, a synodic month takes ___________________________________________ than a sidereal month.

Answers

Because of Earth's motion in its orbit, a synodic month takes about 2.2 days longer than a sidereal month.

Because of Earth's motion in its orbit as the moon circles around it, a synodic month takes longer than a sidereal month.

A synodic month, also known as a lunar month, is the time it takes for the moon to complete a full cycle of phases, from new moon to new moon. This cycle lasts approximately 29.5 days.

On the other hand, a sidereal month is the time it takes for the moon to complete one orbit around the Earth relative to the stars. This period lasts about 27.3 days.

The reason a synodic month takes longer is due to Earth's own motion around the sun. As Earth moves along its orbit, it takes extra time for the moon to catch up to the same phase relative to the sun.

To put it simply, imagine you and a friend are running in circles around a tree. If your friend is running slower than you, it will take them longer to reach a specific point on the tree, even though they are moving at a constant speed.

In summary, because of Earth's motion in its orbit, a synodic month takes about 2.2 days longer than a sidereal month.

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what is the meaning of electrolysis​

Answers

Answer:

Electrolysis is the passing of a direct electric current through an ionic substance that is either molten or dissolved in a suitable solvent, producing chemical reactions at the electrodes and decomposition of the materials.

:

Answer:Electrolysis, process by which electric current is passed through a substance to effect a chemical change. ... The process is carried out in an electrolytic cell, an apparatus consisting of positive and negative electrodes held apart and dipped into a solution containing positively and negatively charged ions.

Explanation:

The efficiency of lever is always less than 100%why

Answers

Answer:

The output work is always less than the input work because some of the input work is used to overcome friction. Therefore, the efficiency is always less than 100 percent.

Read the scenario. A car starts 10 m north of a reference point. It moves at a constant velocity over the next 5 s, reaching a position of 10 m south of the reference point. What is the car’s average velocity? 2 m/s south 4 m/s north 0 m/s 4 m/s south

Answers

Answer:

4 m/s south

Explanation:

This is a pretty easy one.

Assume that the car has a reference point ragged x

We also know that the car starts moving at a point 10 m North of X. It moves steadily at a uniform velocity and ended at a position 10 m south of X.

If x is the reference point, we can infer that the car moves a total distance of, 10 m + 10 m.

Thus, the total distance moved by the car is 20 m.

It is also stated that it achieves that distance in 5 seconds.

Velocity is defined as the ratio of distance with respect to the tome taken, i.e V = d/t

Then, the velocity is

V = 20 / 5 = 4 m/s

Considering the fact that the car left and moved towards the south. We can say that it moved 4 m/s South.

A turtle travels 12 mile in 19 hour. At this rate, how far can the turtle travel in an hour?.

Answers

16.92 meter far can the turtle travel in an hour.

What is the formula for Speed, Distance & Time?

Speed (or rate, r) is a scalar quantity that measures the distance travelled (d) over the change in time (Δt), represented by the equation r = d/Δt

Given, 12 mile in 19 hours so we require to convert in SI unit.

12 mile = 19312.1 meters

19 Hour = 68400 sec

Applying in formula, speed = Distance / Time

Distance / Time = 19312.1 / 68400 = 0.282 m/ sec ²

Speed = 0.282 m / sec ²

1 hour = 60 second

Putting the above value in the below formula

speed = Distance / Time

Distance = Speed x Time = 0.282 x 60 = 16.92 meter

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What is the volume of 4.4 mol of an ideal gas at a pressure of 3 atm and a temperature of 0 ◦ C? 1 liter = 0.001 m3 and 1 atm = 101300 Pascals. Answer in units of L.

Answers

the volume of 4.4 mol of an ideal gas is 44.5 L.

The ideal gas law equation is PV=nRT,

P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in kelvin. To solve for volume, we need to rearrange the formula to V=nRT/P

We have:R = 8.31 J/Kmol, and 1 L = 0.001 m³ and 1 atm = 101300 Pa.

Converting 0 ◦C to Kelvin, we get:

T = 273 + 0 = 273 K

Using the values provided in the equation above,

V = nRT/P= 4.4 mol × 8.31 J/Kmol × 273 K / (3 atm × 101300 Pa/atm)= 0.0445 m³

Convert this volume to liters by multiplying by 1000:V = 0.0445 m³ × 1000 L/m³= 44.5 L

the volume of 4.4 mol of an ideal gas is 44.5 L.

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.What is the mass of an object if it accelerates at 3 m/s2 and has a force of 1 N?

Answers

Answer:

1/3 kg

Explanation:

\(a = \frac{f}{m} = \frac{1}{3 }kg\)

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