what hall voltage (in mv) is produced by a 0.160 t field applied across a 2.60 cm diameter aorta when blood velocity is 59.0 cm/s?

Answers

Answer 1

A 0.160 t field applied across a 2.60 cm diameter aorta when blood velocity is 59.0 cm/s will give Hall voltage of 2.3712 mV.

For calculating this, we know that:

VH = B * d * v * RH

In this instance, the blood flow rate is given as 59.0 cm/s, the magnetic field strength is given as 0.160 T, the aorta diameter is given as 2.60 cm (which we will convert to metres, thus d = 0.026 m), and the magnetic field strength is given as 0.160 T.

Let's assume a value of RH = \(3.0 * 10^{-10} m^3/C.\)

VH = (0.160 T) * (0.026 m) * (0.59 m/s) *  \(3.0 * 10^{-10} m^3/C.\)

VH = 0.0023712 V

Or,

VH = 2.3712 mV

Thus, the Hall voltage produced in the aorta is approximately 2.3712 mV.

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Related Questions

If a young girl holds a 16-cm-radius convex mirror so that her face is 5.0 cm from the vertex of the mirror, what will be the magnification and orientation of her image? a)m= 0.62, upright image b)m = 0.62, inverted image c)m = 1.3, inverted image d)m = 0.85, upright image e)m = 0.75, upright image

Answers

To determine the magnification and orientation of the image formed by a convex mirror, we can use the mirror equation:

1/f = 1/do + 1/di,

where

f = focal length of the convex mirror,

do = object distance (distance from the girl's face to the mirror),

di = image distance (distance from the mirror to the image).

In this case, the girl's face is 5.0 cm from the vertex of the mirror (do = 5.0 cm). The focal length of a convex mirror is half its radius of curvature (f = R/2). Given the radius of the convex mirror is 16 cm, we have:

f = 16 cm / 2 = 8 cm.

Now, we can use the mirror equation to find the image distance (di). Substituting the known values, we have:

1/8 = 1/5 + 1/di.

Simplifying this equation, we find:

1/di = 1/8 - 1/5 = (5 - 8) / (8 * 5) = -3 / 40.

Taking the reciprocal of both sides, we get:

di = -40 / 3 cm.

The negative sign indicates that the image formed by a convex mirror is virtual and upright.

The magnification (m) of the image can be calculated using the formula:

m = -di / do.

Substituting the values, we have:

m = -(-40 / 3 cm) / 5.0 cm = 40 / (3 * 5.0) = 40 / 15.0 ≈ 2.67.

The magnification of the image is approximately 2.67.

However, none of the given answer options match this result exactly. Therefore, none of the provided options (a), (b), (c), (d), or (e) are correct for this specific case.

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a ball is swung in a vertical circle such that at one point along its circular path the forces exerted on the ball can be represented by the free body diagram. the magnitude of the tension force exerted on the ball, t, is twice that of the force due to gravity exerted on the ball from earth, fg. what is the location of the ball, and what is the magnitude of the centripetal acceleration of the ball?

Answers

Location of the ball is top of the circle and acceleration is 3g.

Since tension force is more, surely ball is having net force upward and hence, the location of the ball in this case is top of the circle.

Any object that moves in a circle has an acceleration vector towards the center of that circle. This is known as Centripetal acceleration.

total force/ net force when ball is top of the circle is sum of tension force and gravity force.

\(F_{net\) = T + mg

Because of this net force, there is centripetal acceleration towards the center.

so, T + mg = ma

2mg + mg = ma

3mg = ma

a = 3 × force of gravity

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One pot has a water height of 8cm. Calculate the water pressure at the bottom of the pot. They give g = 10N / kg p = 1000kg / m3

Answers

Answer:

P = 800 Pa

Explanation:

The pressure of water at the bottom of the pot can be given by the following formula:

\(P = \rho g h\)

where,

P = Pressure at the bottom of the pot = ?

ρ = density = 1000 kg/m³

h = height of water = 8 cm = 0.08 m

Therefore,

\(P = (1000\ kg/m^3)(10\ m/s^2)(0.08\ m)\)

P = 800 Pa

7. A volcanic island arc is formed when

7. A volcanic island arc is formed when

Answers

A I believe ^^^^^^ luck!!!

If a bug crawls 100 meters per second, how long will it take the bug to crawl 2 meters?

Answers

Answer:

Below

Explanation:

rate * time = distance       <====you should know this .....re-arrange as

time = distance / rate        sub in the values given

 time = 2 m / 100 m/s

  time =  .02 s

a 65.0-kg boy and 40.0-kg girl, both wearing skates, face each other at rest on a skating rink. the boy pushes the girl, sending her eastward with a speed of 4.00 m/s. describe the subsequent motion of the boy.

Answers

6.5 m/s is the velocity of the boy when a 65.0-kg boy and 40.0-kg girl, both wearing skates, face each other at rest on a skating rink.

Mass of the boy, = 65kg

girl's mass given  , = 40 kg

Final velocity of the girl , = -4.00 m/s

By law of conservation of momentum

\(m_bv_ib+m_gv_ig=m_bv_fb+m_gv_fg\)

\(0=65kg(-4.0m/s)+40kgv_fg\)

\(v_fg=6.5m/s\)

When a body is travelling in a straight line, its velocity is the "rate of change of displacement with relation to time."Because it always has a direction, velocity is a vector. As a result, when the displacement to time ratio for linear velocity is determined, it provides both the direction and the magnitude.

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Complete the following statement: The magnetic field around a current-carrying, circular loop ismost like that of(a) the earth.(b) a short bar magnet.(c) a current-carrying, rectangular loop.(d) a long straight wire that carries a current.(e) two long straight wires that carry currents in opposite directions.

Answers

The correct answer is (b) a short bar magnet because the circular loop of current creates a magnetic field that looks similar to the field created by a bar magnet.

The magnetic field around a current-carrying, circular loop is similar to that of a bar magnet because the circular loop acts as a magnetic dipole, with a north and south pole, just like a bar magnet. The magnetic field lines around the circular loop are also circular, just like the field lines around a bar magnet.

    The other options, such as a current-carrying, rectangular loop or long straight wire, do not produce a magnetic field that is similar to a bar magnet. Additionally, the strength of the magnetic field is greatest at the center of the circular loop and decreases with distance. This is similar to the field of a bar magnet, where the field is strongest at the poles and diminishes with distance.

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Oersted found the direction of the magnetic field around a wire carrying current by placing a (fill in the blank)
in many places
around the wire.

Answers

Answer: he used a compass to find the direction of the magnetic field

Explain why a metal box does not fall through a table to the floor???

Answers

Answer:

the table is strong enough to hold the metal

A sheet of steel 5.0 mm thick has nitrogen atmospheres on both sides at 900∘C and is permitted to achieve a steady-state diffusion condition. The diffusion coefficient for nitrogen in steel at this temperature is 46.70 m2/s and the diffusion flux is found to be 53.81 kg/m2.s. Also, it is known that the concentration of nitrogen in the steel at the high-pressure surface is 39.52 kg/m3. How far into the sheet (in mm ) from this highpressure side will the concentration be 29.12 kg/m3 ? Assume a linear concentration profile.

Answers

The concentration of nitrogen will be 29.12 kg/m³.

The thickness of the steel sheet, l = 5.0 mm

The diffusion coefficient of nitrogen in steel, D = 46.70 m²/s

The diffusion flux, J = 53.81 kg/m²s

The initial concentration of nitrogen in steel, C1 = 39.52 kg/m³

The final concentration of nitrogen in steel, C2 = 29.12 kg/m³

The required distance, x = ?

The concentration profile is linear. The formula for diffusion flux is J = -D * (dC/dx), where dC/dx is the concentration gradient in the x direction. Here, the negative sign represents the diffusion of nitrogen in the direction of decreasing concentration.

Since the concentration profile is linear, we can use the following equation: dC/dx = (C2 - C1) / x

We can now substitute the given values in the diffusion flux formula:

J = -D * (dC/dx) = -D * (C2 - C1) / x

Solving the above formula for x, we get

x = -D * l / (J * (C2 - C1)) = -46.70 * 5.0 / (53.81 * (29.12 - 39.52))

≈ 1.53 mm

Therefore, the concentration of nitrogen will be 29.12 kg/m³ at a distance of approximately 1.53 mm from the high-pressure surface.

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What happens to a circuit's resistance (R), voltage (V), and current (1) when
you change the thickness of the wire in the circuit?
A. V and I will also change, but R will remain constant.
B. R and I will also change, but V will remain constant.
O C. R, V, and I will all remain constant.
OD. R and V will also change, but I will remain constant.

Answers

When you change the thickness of the wire in a circuit, option B. the resistance (R) and current (I) will also change, but the voltage (V) will remain constant.

The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area (thickness). As the thickness of the wire changes, the cross-sectional area changes, which in turn affects the resistance. Thicker wires have a larger cross-sectional area, resulting in lower resistance, while thinner wires have a smaller cross-sectional area, resulting in higher resistance. Therefore, changing the thickness of the wire will cause a change in resistance.

According to Ohm's Law (V = IR), the voltage (V) in a circuit is equal to the product of the current (I) and the resistance (R). If the voltage is kept constant, and the resistance changes due to the thickness of the wire, the current will also change to maintain the relationship defined by Ohm's Law. When the resistance increases, the current decreases, and vice versa.

However, it's important to note that changing the thickness of the wire will not directly affect the voltage. The voltage in a circuit is determined by the power source or the potential difference applied across the circuit and is independent of the wire thickness. As long as the voltage source remains constant, the voltage across the circuit will remain constant regardless of the wire thickness. Therefore, the correct answer is option B.

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a) The mass of a box is 250 kg. The lower surface area is 150 cm². What is the pressure exerted by the box on the surface? ​

Answers

Mass=250kg

\(\\ \sf\longmapsto Force=ma=250(10)=2500N\)

Area=150cm^2=0.015m^2

\(\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\)

\(\\ \sf\longmapsto Pressure=\dfrac{2500}{0.015}=1.6666.6Pa\)

If I push on the wall with 75 Newtons of force, the wall will push back with __

Answers

Answer: 0

Explanation:

75 newtons will push back canceling it out make it 0

If I push on the wall with 75 Newtons of force, the wall will push back with 75 Newtons of force.

What is force?

Force is defined as a cause which is capable of changing the motion of an object. It can cause an object which has mass to change it's velocity. It is also simply a push or a pull . It has both magnitude as well as direction.Hence, it is a vector quantity.

It has SI units of Newton and is represented by'F'.Newton's second law states that force which acts on an object is equal to momentum which changes with time. If mass of object is constant, acceleration is directly proportional to net force acting on an object.

The concepts which related to force are thrust and torque .Thrust increases the velocity of an object and torque produces change in rotational speed of an object.

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a basketball referee tosses the ball straight up for the starting tip-off. at what velocity (in m/s) must a basketball player leave the ground to rise 1.09 m above the floor in an attempt to get the ball?

Answers

Given data is,The height at which the player jumps = 1.09 mNow, we can find the initial velocity required for the basketball player to jump that height using the following formula:

v² = u² + 2asHere, u is the initial velocity, a is the acceleration due to gravity (9.8 m/s²), s is the distance the player moves vertically, and v is the final velocity (0 m/s at the top of the jump).So, the formula can be rearranged as:u = √(v² - 2as)Now, we know that the final velocity (v) is zero because the player reaches the maximum height at which the initial velocity was imparted to him by jumping.

Thus,u = √(0² - 2 × 9.8 × 1.09)u = √(- 21.392)u = ± 4.626 m/sAs we know that velocity cannot be negative, we will take the positive value.u = 4.18 m/sTherefore, the velocity at which the player must leave the ground to rise 1.09 m above the floor in an attempt to get the ball is 4.18 m/s.

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Block X of mass 2 kg travels across a horizontal surface toward block Y of unknown mass that is initially at rest. Block X then collides elastically with block Y A graph of the position as a function of time for block X is shown. Block X and block Y are made of the same material. Which of the following predictions is correct about the motion of block Y immediately after the collision? The acceleration of block Y immediately after the collision is greater than the acceleration of block Y immediately before the collision The kinetic energy of block Y immediately after the collision is greater than the kinetic energy of block X immediately after the collision The change in momentum of block Y from immediately before the collision to immediately after the collision is more than the change in momentum of block X The momentum of the system consisting of block X and block Y immediately after the collision is less than the momentum of the system immediately before the collision

Answers

Since the collision between block X and block Y is elastic, the total momentum and total kinetic energy of the system are conserved. This means that the sum of the momenta of block X and block Y immediately after the collision is equal to the sum of their momenta immediately before the collision. Similarly, the sum of their kinetic energies immediately after the collision is equal to the sum of their kinetic energies immediately before the collision.

Based on this information, we can eliminate options 2 and 4:

- The kinetic energy of block Y immediately after the collision is greater than the kinetic energy of block X immediately after the collision: This cannot be true, as the total kinetic energy of the system is conserved in an elastic collision.
- The momentum of the system consisting of block X and block Y immediately after the collision is less than the momentum of the system immediately before the collision: This cannot be true, as the total momentum of the system is conserved in an elastic collision.

Next, we can consider options 1 and 3:

- The acceleration of block Y immediately after the collision is greater than the acceleration of block Y immediately before the collision: This is possible if block Y has a smaller mass than block X, as the acceleration of an object is inversely proportional to its mass in an elastic collision. However, we do not have enough information to determine the mass of block Y.
- The change in momentum of block Y from immediately before the collision to immediately after the collision is more thanthe change in momentum of block X: This is not necessarily true, as the total change in momentum of the system is zero, and the change in momentum of one block is equal in magnitude but opposite in direction to the change in momentum of the other block.

Therefore, we cannot determine with certainty which of the two remaining options is correct based on the given information. If we knew the masses of both blocks, we could use the conservation of momentum and conservation of kinetic energy equations to calculate the velocities and accelerations of the blocks after the collision and determine which option is correct.

The collision between block X of mass 2 kg and block Y (of unknown mass) is an elastic collision. It is given that block X is traveling across a horizontal surface towards block Y, which is initially at rest. Also, block X and block Y are made of the same material. The position as a function of time graph for block X is also provided.

.Prediction 1: The acceleration of block Y immediately after the collision is greater than the acceleration of block Y immediately before the collision.This prediction is not true as the acceleration of block Y after the collision will be less than the acceleration of block Y before the collision. The reason is that block Y initially is at rest and then has to gain some speed. So, the acceleration of block Y after the collision is less than the acceleration of block Y before the collision.

Prediction 2: The kinetic energy of block Y immediately after the collision is greater than the kinetic energy of block X immediately after the collision.This prediction is not true as the collision is an elastic collision. In an elastic collision, kinetic energy is conserved, meaning the total kinetic energy before the collision is equal to the total kinetic energy after the collision. Thus, the kinetic energy of block Y immediately after the collision cannot be greater than the kinetic energy of block X immediately after the collision.

Prediction 3: The change in momentum of block Y from immediately before the collision to immediately after the collision is more than the change in momentum of block X.This prediction is true. In an elastic collision, both momentum and kinetic energy are conserved. So, the change in momentum of block Y will be more than the change in momentum of block X.

Prediction 4: The momentum of the system consisting of block X and block Y immediately after the collision is less than the momentum of the system immediately before the collision.This prediction is not true as momentum is conserved in an elastic collision. The momentum of the system consisting of block X and block Y immediately after the collision will be the same as the momentum of the system immediately before the collision.

Therefore, the prediction that is correct about the motion of block Y immediately after the collision is: The change in momentum of block Y from immediately before the collision to immediately after the collision is more than the change in momentum of block X.

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Suppose your answer to the preceding question is v. if the hose is attached to a nozzle with a diameter of 0.750 cm, what is the speed of the water in the nozzle?

Answers

The speed of the water in the nozzle is equal to the speed determined in the previous question, which is v.

To determine the speed of the water in the nozzle, we can use the principle of continuity, which states that the flow rate of an incompressible fluid remains constant along a streamline.

The flow rate (Q) is given by the equation:

Q = A * v

Where:

Q is the flow rate

A is the cross-sectional area of the nozzle

v is the velocity of the water

Given that the diameter of the nozzle is 0.750 cm, we can calculate the radius (r) as half the diameter:

r = 0.750 cm / 2 = 0.375 cm = 0.00375 m

Using the radius, we can calculate the cross-sectional area (A) of the nozzle:

\(A = π * r^2\)

\(A = π * (0.00375 m)^2\)

Now, let's substitute the values into the equation to solve for v:

Q = A * v

Since the flow rate is constant, the flow rate at the attachment point (QBC) is equal to the flow rate at the nozzle (Qnozzle):

QBC = Qnozzle

Since we know the flow rate at the attachment point (QBC) is given as v (from the previous question), we can equate it with the flow rate at the nozzle:

QBC = Qnozzle

A * v = A * vnozzle

Canceling out the cross-sectional area (A) on both sides, we have:

v = vnozzle

Therefore, the speed of the water in the nozzle is equal to the speed determined in the previous question, which is v.

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A battery provides a potential difference of 20 V. What size current will flow through a 5 ohm resistor in
this circuit

Answers

the answer is 4A i believe

When compared to winds at the surface, winds at 2,000 feet areA. higher due to absence of frictionB. higher and go at right angles to the isobars due to frictionC. higher because they move from an area of higher pressure to lower pressure

Answers

When compared to winds at the surface, winds at 2,000 feet are typically higher due to the absence of friction.

At the surface, winds are affected by friction with the Earth's surface, which slows them down and causes them to move in a more turbulent and erratic fashion. However, as winds move up in altitude, they encounter less and less friction, allowing them to increase in speed and flow in a more uniform and predictable manner.
While friction may still have some influence on winds at 2,000 feet, it is not as significant as at the surface. Therefore, winds at this altitude tend to move more smoothly and follow a more consistent path, often perpendicular to the isobars (lines of equal pressure) on a weather map. This makes them useful for aviation purposes, as pilots can use this information to plan their flight paths and take advantage of favorable tailwinds or avoid dangerous crosswinds.
In contrast, winds at the surface are more affected by local topography, temperature gradients, and other factors that can cause them to vary widely in direction and speed. Overall, winds at 2,000 feet are an important component of the Earth's atmospheric circulation system, and understanding their behavior is essential for predicting weather patterns and ensuring safe air travel.

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an astronaut on an eva has wandered dangerously far away from the shuttle. she has also exhausted all the fuel in her jet pack. how can she get back to the shuttle?

Answers

The conservation of the momentum allows to find the result of how the astronaut can return to the spacecraft is:

Throwing the thruster away from the ship.

The momentum is defined as the product of the mass and the velocity of the body, for isolated systems the momentum  is conserved. If we define the system as consisting of the astronaut and the evo propellant, this system is isolated and the internal forces become zero. Let's find the moment in two moments.

Initial instant. Astronaut and thrust together.

        p₀ = 0

Final moment. The astronaut now the thruster in the opposite direction of the ship.

       \(m_f\) = m v + M v '

where m is propellant mass and M the astronaut mass.

As the moment is preserved.

       0 = m v + M v ’

      v ’= \(- \frac{m}{M} \ v\)  

We can see that the astronaut's speed is in the opposite direction to the propeller, that is, in the direction of the ship.

The magnitude of the velocity is given by the relationship between the masses.

In conclusion, using the conservation of the momentun we can find the result of how the astronaut can return to the ship is:

Throwing the thruster away from the ship.

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What is the speed of a 180 g ball if its kinetic energy is 100 J?

Answers

Answer:

Velocity, V = 33.33 m/s

Explanation:

Given the following data;

Mass = 180grams to kilograms = 180/1000 = 0.18 kg

Kinetic energy = 100J

To find the speed;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

\( K.E = \frac{1}{2}MV^{2}\)

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Substituting into the equation, we have;

100 = ½*0.18*V²

Cross-multiplying, we have;

200 = 0.18*V²

V² = 200/0.18

V² = 1111.11

Taking the square root of both sides, we have;

Velocity, V = 33.33 m/s

within an atom particles called ____________ constantly move around the central nucleus

Answers

within an atom particles called Electrons constantly move around the central nucleus

Do orbitals revolve around the nucleus?

Electrons do not orbit a nucleus as a planet does the Sun, but instead exist as standing waves. As a result, the lowest attainable energy for an electron is equivalent to the fundamental frequency of a wave on a string. Higher energy levels are analogous to basic frequency harmonics.

In brief, the electron is kept in orbit by electrical attraction to the nucleus, and this attraction is free of charge. It may seem strange that anything may continue to move eternally without requiring a power source, yet it is real.

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determine the equivalent resistance of the circuit shown in the figure. (figure 1) express your answer to three significant figures and include the appropriate units.

Answers

The figure given in the question shows a circuit with resistors that are not all in parallel or series. As a result, it will be necessary to determine the equivalent resistance of each group of resistors separately.

The groups of resistors in this circuit are as follows:R2 and R3 are connected in series, and their equivalent resistance can be calculated using the following equation:

R23 = R2 + R3

= 47 Ω + 100 Ω

= 147 Ω

R5 and R6 are connected in series, and their equivalent resistance can be calculated using the following equation:R56 = R5 + R6 = 150 Ω + 47 Ω = 197 ΩR23 and R4 are connected in parallel, and their equivalent resistance can be calculated using the following equation:

1/R234 = 1/R23 + 1/R4

= 1/147 Ω + 1/220 Ω

= 0.0105 ΩR234

= 95.238 Ω

Finally, R1 and R56 are connected in series, and their equivalent resistance can be calculated using the following equation:

R156 = R1 + R56

= 100 Ω + 197 Ω

= 297 Ω

Therefore, the equivalent resistance of the entire circuit is

R = R156 + R234

= 297 Ω + 95.238 Ω

= 392.238 Ω

= 3.92 × 10² Ω (expressed to three significant figures).

Therefore, the equivalent resistance of the circuit is 3.92 × 10² Ω.

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What is 165 Centimeters in Feet and Inches?

Answers

The value is 5.4 in feet and 65 inches

What is a conversion factor?

A conversion factor is a ratio of equivalent measurements used to convert a quantity from one unit of measurement to another. Conversion factors are often used in mathematics and science to ensure that quantities are expressed in consistent units, which makes it easier to perform calculations and make comparisons.

For example, consider a situation where you want to convert a quantity from inches to centimeters. The conversion factor for this conversion would be:

1 inch = 2.54 centimeters

This is the conversion factor that we used to obtain then values above.

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What happens when an object reaches terminal velocity?

Answers

At terminal velocity, drag equals the weight of the falling object. The two forces are in opposite directions, so the total force on the object is zero and the object's velocity is constant.

When terminal velocity is reached, the net acceleration of an object falling through a liquid is zero. After reaching terminal velocity, the body continues to move at the same speed. Once the terminal velocity is reached, the velocity becomes constant. A free-falling object reaches terminal velocity when the downward force of gravity equals the upward force of drag. This results in zero net force on the object and zero acceleration. 

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if an object is speeding​ up, . its acceleration is positive its acceleration can be positive or negative depending on the direction of motion its acceleration is negative

Answers

If an object is speeding up its acceleration can be positive or negative depending on the direction of motion.

What is positive and negative acceleration?

According to mathematics, a negative acceleration indicates that the velocity will be subtracted, while a positive acceleration indicates that the velocity will be increased.

In physics,

A positive acceleration indicates a rising velocity over time.

Negative acceleration describes a speed decrease over time.

A bus or car going at an accelerating rate is said to have positive acceleration.

We may say that it is speeding up in the direction it is moving.

When we use the brake in the previous example, the speed of the car reduces.

Then it experiences a deceleration.

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what is the most important bone in your body plz help I will mark brainly

Answers

Answer:

Your skull protects the most important part of all, the brain. You can feel your skull by pushing on your head, especially in the back a few inches above your neck.

Explanation:

Answer:

Obviously the skull . because it protects you brain and keeps it in place.

Explanation:

normal or random variations that are considered part of operating the system at its current capability are :

Answers

Normal or random variations that are considered part of operating the system at its current capability are known as process variation.

These variations can be caused by factors such as changes in raw materials, environmental conditions, and human factors. It is important for businesses to understand and monitor process variation to ensure that their systems are operating within acceptable limits and producing consistent and high-quality products or services. These variations occur naturally within the process and are inherent to the system, reflecting its inherent stability and predictability.

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5. What is one difference between landslides and mudflowes?
A. Mudflows are caused by gravity.
B. Landslides can occur on gental slopes.
C. Mudflows can occur on gentle slopes.
D. Landslides occur suddenly.

Answers

The difference between landslides and mudflows is mudflows are caused by gravity. The correct option is option A.

Landslides

Landslides are caused by disturbances in the natural stability of a slope. A landslide is defined as the movement of a mass of rock, debris, or earth down a slope.

The impact of a landslide can be extensive, including loss of life, destruction of infrastructure, damage to land and loss of natural resources. Landslide material can also block rivers and increase the risk of floods.

Mudflows

It is a form of mass wasting involving fast moving flow of debris and dirt that has become liquefied by the addition of water. A river of liquid and flowing mud on the surfaces of normally dry land areas, as when earth is carried by a current of water.

They can happen after heavy rains, droughts, earthquakes or volcanic eruptions.

They are both examples of natural disaster.

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what is the longest wavelength of electromagnetic radiation that will ejectphotoelectrons from sodium metal for which the work function is 2.28 ev?

Answers

The longest wavelength of electromagnetic radiation that will eject photo-electron from the sodium metal is 544 nm.

What is electromagnetic radiation ?

Electromagnetic radiation consists of waves of electromagnetic field, which propagates through space and carries momentum and electromagnetic radiant energy.

Minimum energy required to knock out an electron from the surface of the metal is called the work function.

As we know that, W= hc/λ

h -- Planck's constant ; c -- Speed of light

and λ is Longest wavelength

Given, work function of sodium metal is 2.28 eV

As 1 eV = 1.6021 * 10^-19 J

=2.28 * 1.6021 * 10^-19

= 3.65 *10^-19 J

W= hc/ λ

3.65 *10^-19 = 6.62 *10^-34 * 3 *10^8/ λ

λ = 5.44 * 10 ^-7m

λ =544 nm

The longest wavelength of electromagnetic radiation that will eject photo-electron from the sodium metal is 544 nm.

To know more about electromagnetic radiation, refer

https://brainly.com/question/1408043

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Star meaning plz :) I need help

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a fixed luminous point in the night sky which is a large, remote incandescent body like the sun. or a conventional or stylized representation of a star, typically one having five or more points.
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