what goes up but never comes down i know the answer but do you?

A diffraction grating resolves the wavelengths 662.2 nm and 662.4 nm in the first order. The number of slits in the grating is approximately 116,840.

To find the number of slits in a diffraction grating that just resolves wavelengths 662.2 nm and 662.4 nm in the first order, we can use the Rayleigh criterion for the resolution limit. The Rayleigh criterion is given by:
Δλ / λ = 1 / (m * N),
where Δλ is the difference in wavelengths, λ is the average wavelength, m is the order of the spectrum (1 in this case), and N is the number of slits in the grating.
First, find the difference in wavelengths: Δλ = 662.4 nm - 662.2 nm = 0.2 nm.
Next, calculate the average wavelength: λ = (662.2 nm + 662.4 nm) / 2 = 662.3 nm.
Now, plug these values into the Rayleigh criterion formula:
0.2 nm / 662.3 nm = 1 / (1 * N).
Solve for N:
N ≈ 116,840.
Therefore, there are approximately 116,840 slits in the diffraction grating.

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Answer: v=1,56(m/s)

Explanation: Called: g(Gravity acceleration) =10\(m/s^{2} \\\)(or 9,8\(m/s^{2}\))

                                 h=1,2m  ;   t=1,3s

Because the coin fell freely, the velocity is calculated by the formula:

v=\(\sqrt{2gh}\)  (1)

besides, you have time to touch the bottom of the water is 1,3s:

t=\(\sqrt\frac{2g}{h} }\) (2)

(1) and (2) => v=1,56 (m/s)

Answer:

He is running at the speed of 20*5/18 m/s

so for 400m ,he takes

400/(20*5)/18 = 72 sec

= 1 . 2 min =6/5 min

To determine the time taken to travel to Los Angeles you should consider the distance traveled.

The displacement of an object is known as the change in position of the object.

It is also the shortest distance between the final position and initial position of an object.

Displacement is a vector quantity because it has both direction and magnitude.

Distance is scalar quantity that measures the space between two points. It is a scalar quantity because it has only magnitude.

To determine the time taken to travel to Los Angeles we consider the speed of the motion, and the distance traveled.

time of motion = distance traveled/speed

Thus, To determine the time taken to travel to Los Angeles you should consider the distance traveled.

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The momentum of the van after the collision will be -9600 kg m/s.

Momentum is a concept in physics that is used to describe an object's resistance to changes in motion. It is based on the principle of inertia, which states that an object will remain in a state of rest or constant motion unless acted upon by an outside force. Momentum is calculated by multiplying the mass of an object by its velocity. Momentum is a vector quantity, meaning that it has both magnitude and direction. Momentum is also conserved, meaning that the total momentum of any closed system remains constant.

Momentum is a measure of an object's mass multiplied by its velocity. Before the collision, the momentum of the van was 9600 kg m/s (80kg x 72m/s). After the collision, both vehicles will be travelling in the opposite direction, meaning that the momentum of the van will be the same as before, but in the opposite direction. Therefore, the momentum of the van after the collision will be -9600 kg m/s. The change in momentum, or delta momentum, of the van after the collision is the difference between the before and after momentum, or 9600 kg m/s.

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Answer:

International Bureau of Weights and Measures (BIPM), French Bureau International des Poids et Mesures, international organization founded to bring about the unification of measurement systems, to establish and preserve fundamental international standards and prototypes, to verify national standards, and to determine fundamental physical constants. The bureau was established by a convention signed in Paris on May 20, 1875, effective January 1876. In 1921 a modified convention was signed.

Answer:

The function that describes the acceleration of the particle at time t is:

a(t) = -6 m/s^2.

Explanation:

To find the function that describes the acceleration of the particle at time t, we need to take the second derivative of the position function s(t).

Given:

s(t) = -3t^2 - 4t + 1

Taking the derivative of s(t) with respect to t will give us the velocity function v(t):

v(t) = d/dt [-3t^2 - 4t + 1]

= -6t - 4

Now, we can take the derivative of v(t) with respect to t to find the acceleration function a(t):

a(t) = d/dt [-6t - 4]

= -6

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Answer:

2910

Explanation:

970 × 3. 970 in one hour × 3 hrs. 2910 kilometers

The solution is since the molar enthalpy of combustion for magnesium is 620 kJ/mol.

Enthalpy of Combustion (EoC) is the amount of energy released when a fuel is oxidized by an oxidizing agent.

25.5 kj of energy are released during the burning of a 1.0 g sample of magnesium to create MgO.

Magnesium has a molecular weight of 24.35g.

A mole of magnesium weighs 24.35 g.

1g = 1/24.35

The release of 25.5 kJ is for 0.04 moles.

25.5 * 1/.04 for 1 mole

= 620 kj/mol

As a result, magnesium has a molar enthalpy of combustion of 620 kJ/mol.

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Answer:

yes you are totally right

Answer:

The value is \(t = 5.124 \ s\)

Explanation:

From the question we are told that

   The height of the tree is \(s = 20 \ m\)

    The angle the ball leaves is  \(\theta = 45^o\)

    The initial velocity  is  \(u = 30.0 \ m/s\)

Generally the vertical of the ball's initial velocity is mathematically evaluated as

      \(u_y = u * sin (45)\)

=>   \(u_y =- 30 * sin (45)\)

=>   \(u_y = -21.21 \ m/s\)

Here  \(u_y\) is negative because it is in the direction of the negative y-axis

Generally from kinematic equation we have

      \(s = u_yt + \frac{1}{2} g t^2\)

=>   \(20= -21.21 t +4.9 t^2\)

=>   \(4.9 t^2 -21.21 t- 20= 0\)

Solving using quadratic formula we have that

        \(t = 5.124 \ s\)

Answer:

Power is 4373.25 W

Explanation:

We have,

The lift raises a car of mass 850 kg to a height of 2.1 m. It uses a force of 8330 N and takes 4 seconds to raise the car. It is required to find the power of the lift. Power is equal to the rate at which the work is done. So,

\(P=\dfrac{Fd}{t}\\\\P=\dfrac{8330\times 2.1}{4}\\\\P=4373.25\ W\)

So, the power of the lift is 4373.25 W.

Answer:  Any push/pull on any object is made by a force of some sort.

Explanation:

Given data:

* The mass of the student is m = 65 kg.

* The distance covered by the student is d = 100 m.

* The time taken by the student to cover the distance is t = 12 seconds.

Solution:

(a). The velocity of the student is,

Thus, the velocity of the student is 8.33 meters per second.

(b). The kinetic energy of the student is,

Thus, the kinetic energy of the student is 2255.14 J.

(c). The mechanical energy of the student is the energy acquired by the student during its motion.

Thus, the mechanical energy of the student is 2255.14 J.

Answer: 1.6958*10^3 kW-hr

Explanation:

The barrel of oil contains around 6.1*10^9 J of energy.

We want this energy expressed in kW-hr.

We know that:

1J = 2.78*10^(-7) kW-hr

Then  6.1*10^9 J will be equal to 6.1*10^9  times the above amount.

This is:

E =  (6.1*10^9)*(2.78*10^(-7) kW-hr) = (6.1*2.78)*(10^9*10^(-7)) kW-hr

  = 16.958*10^(9 - 7) kW-hr

  =  16.958*10^2 kW-hr

  = 1.6958*10^3 kW-hr

Energy is the ability to do work. There are a few types of energy, these types are as follows:-

The barrel of oil contains around 6.1*10^9 J of energy.  We want this energy expressed in kW-hr.

One joule of energy has   1J = 2.78*10^(-7) kW-hr .

Therefore, the \(6.1*10^9\)J will be equal to \(6.1*10^9\) times the above amount.

Hence, the energy will be

E =  \((6.1*10^9)*(2.78*10^7 )\)  

 =\(16.958*10^9-7\)

=  \(1.6958*10^3 kW-hr\)

Hence, the correct option is    \(1.6958*10^3 kW-hr\)

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Answer:

gravitational force. in my view but m not sure

We can use the inverse square law to solve this problem. The inverse square law states that the intensity of a point source of waves decreases as the square of the distance from the source increases.

The formula for the intensity (I) of a point source of waves is:

I = P/4πr^2

where P is the power (in watts) of the source, r is the distance from the source (in meters), and π is the mathematical constant pi.

We can rearrange this equation to solve for the distance (r) when the electric field amplitude (E) is known:

E = c√(2I/ε0)

where c is the speed of light (3 x 10^8 m/s) and ε0 is the permittivity of free space (8.85 x 10^-12 F/m).

Substituting the given values, we get:

r = √(P/4πI)

r = √(18 x 10^6 W / (4π x 0.090 V/m)^2)

r ≈ 14.1 m

Therefore, the electric field amplitude will be 0.090 V/m at a distance of approximately 14.1 meters from the 18 mW point source of electromagnetic waves

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Answer:

ΔK = -6 10⁴ J

Explanation:

This is a crash problem, let's start by defining a system formed by the two trucks, so that the forces during the crash have been internal and the moment is preserved

initial instant. Before the crash

        p₀ = m v₁ + M 0

final instant. Right after the crash

        p_f = (m + M) v

        p₀ = p_f

        mv₁ = (m + M) v

        v = \(\frac{m}{m+M} \ v_1\)

we substitute

        v = \(\frac{20}{20+40}\)   3

        v = 1.0 m / s

having the initial and final velocities, let's find the kinetic energy

        K₀ = ½ m v₁² + 0

        K₀ = ½ 20 10³ 3²

        K₀ = 9 10⁴ J

        K_f = ½ (m + M) v²

        K_f = ½ (20 +40) 10³  1²

        K_f = 3 10⁴ J

the change in energy is

       ΔK = K_f - K₀

       ΔK = (3 - 9) 10⁴

       ΔK = -6 10⁴ J

The negative sign indicates that the energy is ranked in another type of energy

Answer:

Bacteria

Fungi

Viruses

Parasites

The drag force depends on the size and shape of the truck, as well as its velocity and the properties of the air (density, viscosity, etc.). Without this information, I cannot provide a meaningful estimate.

To estimate the drag force on a truck with an air temperature of 59°F and standard pressure, you'll need more information, such as the truck's velocity, frontal area, and drag coefficient. The drag force (F_d) can be calculated using the following formula:

F_d = 0.5 * ρ * v^2 * C_d * A

Where:
- F_d is the drag force
- ρ is the air density (affected by temperature and pressure)
- v is the velocity of the truck
- C_d is the drag coefficient
- A is the

of the truck

Please provide the additional information to accurately estimate the drag force on the truck.

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Answer:

When sunlight shines through an orange solution, the violet, blue and green wavelengths are absorbed. The other colors pass through.

According to relativity, the clocks on the spaceship move more slowly when viewed from the spaceship.

Relativity is the measure of relative motion of objects.

According to Einstein's theory of relativity in 1905 its postulates state that

Now, since Clocks on a spaceship moving at high speed relative to the earth. Since the clock on the spaceship is moving, using the third postulate, we see that the clock on the spaceship runs more slowly when viewed from the spaceships moving frame, since it is moving relative to the earth.

So, we can see that the clocks on the spaceship move more slowly when viewed from the spaceship.

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Explanation:

The true statement about gravity is that it is the force of attraction between two objects with masses and also, based on the distance between these objects.

Gravity is a force of attraction.

The best scientific overview of the force of gravity is given by the Newton's law of universal gravitation which states that "the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them",

So, gravitational force of attraction is dependent on mass and the distance between two bodies.

A spring of force constant 120N/m is acted upon by a constant force of 240N. The elastic potential energy stored in the spring is 240 Nm.

The elastic potential energy stored in a spring is given by the formula:

= U = 1/2 x k x x^2

Where U is the elasticity potential energy, k is the force constant of the spring, and x is the displacement of the spring from its equilibrium position. In this case, the force constant of the spring is 120 N/m, and the constant force acting on the spring is 240 N. To find the displacement of the spring, we can use the formula:

= F = k x x

Where F is the force applied to the spring, k is the force constant, and x is the displacement.

Solving for x, we get:

= x = F / k

= 240 N / 120 N/m

= 2 m

Substituting this value for x into the formula for elastic potential energy, we get:

= U = 1/2 x 120 N/m x 2 m^2

= 240 Nm

So the elastic potential energy stored in the spring is 240 Nm.

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Answer:

The mechanical energy of the cardboard box, M.E. = K.E. + P.E.

Where;

P.E. = The potential energy of the cardboard box = m·g·h

K.E. = The kinetic energy of the cardboard box = (1/2)·m·v²

Where;

m = Mass of the cardboard box

g = The (constant) acceleration due to gravity ≈ 9.81 m/s²

h = The height of the cardboard box

v = The velocity of the cardboard box

At the top of the fall, where h = The height of the platform = \(h_{platform}\), and v = 0 (the box is initially at rest at the top), the M.E. is given as follows;

\(M.E._{top}\) = P.E. + K.E. = m·g·\(h_{platform}\) + (1/2) × m × 0² = m·g·\(h_{platform}\)

However, at the bottom of the fall, the height of the box, h = 0, the velocity of the box, v = 0, therefore, the total energy at the bottom, after the box comes to rest, \(M.E._{bottom}\) = 0

Therefore;

The total energy of the box at the top of the fall, .\(M.E._{top}\) = m·g·\(h_{platform}\) was more than the total energy of the box at the bottom of the fall,

\(M.E._{bottom}\) = 0

Explanation:

The reason behind this that giant elliptical galaxies are at the centers of old, dense clusters is that there would be many interactions and collisions near the center, which would ultimately result in the formation of giant ellipticals. The correct option is b.

Elliptical galaxies are elliptical in shape. They have a much higher proportion of older stars than spiral galaxies.

Galaxies are classified into four types: spiral, barred spiral, elliptical, and irregular.

The reason giant elliptical galaxies are located at the mid between of old, dense clusters is that there are the possibilities of many interactions and collisions near the center, resulting in the formation of giant ellipticals.

Thus, the correct option is b.

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Your question seems incomplete, the probable missing options are:

a) Giant ellipticals were probably formed there initially and attracted all the other galaxies closer to it over time.

b) There would be many interactions and collisions near the center, which would ultimately result in the formation of giant ellipticals.

c) Most of the gas and dust would settle to the center of the cluster, and we know that giant ellipticals contain vast amounts of gas/dust butts.

Answer:

the potential energy is 19.6J

the kinetic energy is 0.0.004J

Explanation:

using the formulas

P.E = mgh while

K.E =mv²/