What fraction of the square is shaded if the line inside divides the square into two equal parts?​

The Answer is gonna be B. 324 square centimeters

Explanation :

A=b x h

A=27 x 12

A=324

This is the Answer for your question :3

The coordinates of A'', B'' and C'' are (-1, 4), (-4, 3) and (-1, 2) respectively.

Transformation of geometrical figures or points is the manipulation of a given figure to some other way.

Different types of transformations are Rotation, Reflection, Glide reflection, Translation and Dilation.

Given triangle has coordinates,

A(2, -2), B(5, -3) and C(2, -4).

First the triangle is translated by the rule (x, y) → (x - 1, y + 6)

A(2, -2) becomes A'(2 - 1, -2 + 6) = A'(1, 4).

B(5, -3) becomes B'(5 - 1, -3 + 6) = B'(4, 3)

C(2, -4) becomes C'(2 - 1, -4 + 6) = C'(1, 2)

Then the translated triangle is reflected across the Y axis.

When reflected a point (x, y) across the Y axis, y coordinate remains same and x coordinate flips.

A'(1, 4) becomes A''(-1, 4)

B'(4, 3) becomes B''(-4, 3)

C'(1, 2) becomes C''(-1, 2)

Hence the vertices of the triangle after undergoes translation and reflection becomes A''(-1, 4), B''(-4, 3) and C''(-1, 2).

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Value of mathematical expression by using integer are:

a=10+-2*-2*5

b=10-(-2*-2)+5

c=10-5*10-2*10

An integer is a mathematical term used to describe a whole number that is not a fraction or a decimal. Examples of integers are -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7and so on.

Multiplying 5 with -2 two times and adding it with 10

a=10+(-2×-2×5)

a=30

Multiplying -2 with -2 and subtracting it with 10 and 5

b=10-(-2×(-2))+5

b=-1

Subtracting 10 with multiplication of 5 and 10 and adding it with multiplication with 10 and -2.

a=10-5×10-2×10

a=-60
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Answer:

\(9i \sqrt{3} \)

The size sample would be needed to estimate the proportion of black with an error of no more than 0.05 and a confidence level of 95% is 289.

The size sample can be calculated with the equation as follows:

\(n=(\frac{Z_{1-\frac{a}{2} }^ }{a})^{2} P (1-P)\)

where,

n = size sample

\(Z_{1-\frac{a}{2} }^{2}\) = 1.96 for \(a\)=0.05

\(P\) = population

\(a\) = margin of error

Therefore,

\(n=(\frac{1.96^{}}{0.05})^{2} 0.25(1-0.25)\)

\(n=(\frac{1.96^{}}{0.05})^{2} 0.25(0.75)\)

\(n=288.12\) ≈ 289

The number of size sample is 289

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Answer: The value of x from the diagram is 50 degrees.

Vertical angles are angles that meets at a point of intersection. From the given diagram 150 and 50+2x are vertical angles showing that they are equal to each other so:

50 + 2x = 150

2x = 150 - 50

2x = 100

Divide both sides by 2

2x/2 = 100/2

x = 50

Therefore the value of x from the diagram is 50 degrees.

Answer:

x = 50

Step-by-step explanation:

150 = 50 + 2x

100 = 2x

x = 50

Answer:

between B and D.

probably D because is periodic and the line is not continuous.

Then, between the units 4 (max) and 6 (min) is decreasing

Answer: 1/2(m<TUV)= m<TUW

Step-by-step explanation: If you divide TUV by 2 then you would get 28 degrees which would be The < TUW

Answer:

Step-by-step explanation:

Please give brainliest if this helped:)

If pizza box measured 14 inches by 3. 5 inches ,the volume of the pizza box is 49 cubic inches.

To find the volume of the pizza box, we need to use the formula for the volume of a rectangular prism, which is:

Volume = length × width × height

In this case, the pizza box has a length of 14 inches, a width of 3.5 inches, and we need to know the height.

However, we are not given the height directly in the problem. Therefore, we can assume that the pizza box is a standard rectangular prism shape and has a height that is equal to the thickness of the box.

Assuming a standard thickness of 1 inch for the pizza box, we can plug in the values into the formula to find the volume:

Volume = 14 inches × 3.5 inches × 1 inch

Volume = 49 cubic inches

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Answer:

x + 12

Step-by-step explanation:

I would write the initial equation as

(x + 5) + 7

If we remove the parentheses and do the math we get

x + 12

I hope that is what you are looking for.

The given expressions, when A=1, B=0, and C=1, X evaluates to 1.001; when A=B=C=1, X evaluates to 1.111; and when A=B=C=0, X evaluates to 0.000. These evaluations are based on the given values of A, B, and C, and the notation ¯¯¯¯¯¯BC represents the complement of BC.

To evaluate the expression X = A.¯¯¯¯¯¯BC, we substitute the given values of A, B, and C into the expression.

(a) For A = 1, B = 0, and C = 1:

X = 1.¯¯¯¯¯¯01

To find the complement of BC, we replace B = 0 and C = 1 with their complements:

X = 1.¯¯¯¯¯¯01 = 1.¯¯¯¯¯¯00 = 1.001

(b) For A = B = C = 1:

X = 1.¯¯¯¯¯¯11

Similarly, we find the complement of BC by replacing B = 1 and C = 1 with their complements:

X = 1.¯¯¯¯¯¯11 = 1.¯¯¯¯¯¯00 = 1.111

(c) For A = B = C = 0:

X = 0.¯¯¯¯¯¯00

Again, we find the complement of BC by replacing B = 0 and C = 0 with their complements:

X = 0.¯¯¯¯¯¯00 = 0.¯¯¯¯¯¯11 = 0.000

In conclusion, when A = 1, B = 0, and C = 1, X evaluates to 1.001. When A = B = C = 1, X evaluates to 1.111. And when A = B = C = 0, X evaluates to 0.000. The evaluation of X is based on substituting the given values into the expression A.¯¯¯¯¯¯BC and finding the complement of BC in each case.

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To determine if a vector is a linear combination of u = (0, -2, 2) and v = (1, 3, -1), we need to check if there exist constants such that the given vector can be expressed as a linear combination of u and v.

Let's check each option:

(a) (2, 2, 2):

To express (2, 2, 2) as a linear combination of u and v, we would need to find constants a and b such that a*u + b*v = (2, 2, 2). However, this is not possible since the z-component of u is 2, while the z-component of (2, 2, 2) is different. Therefore, (2, 2, 2) is not a linear combination of u and v.

(b) (0, 4, 5):

Similarly, to express (0, 4, 5) as a linear combination of u and v, we would need to find constants a and b such that a*u + b*v = (0, 4, 5). However, this is not possible since the z-component of u is 2, while the z-component of (0, 4, 5) is different. Therefore, (0, 4, 5) is not a linear combination of u and v.(c) (0, 0, 0):

To express (0, 0, 0) as a linear combination of u and v, we would need to find constants a and b such that a*u + b*v = (0, 0, 0). This is possible by choosing a = 0 and b = 0. Therefore, (0, 0, 0) is a linear combination of u and v.

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Answer:

B.5t + 4t = 3

Step-by-step explanation:

Did test on edge and got 100%

Answer:

B 5t + 4t = 3

Step-by-step explanation:

Edg 2020

Step-by-step explanation:

Use the Pythagorean Theorem ( \(a^{2}+b^{2} =c^{2}\) )

The longest side is c = the hypotenuse, and a and b = the other sides of the triangle.

a = 4                              First: \(4^{2}+x^{2}=8.5^{2}\)

b = x                         Second: \(16+x^{2}=72.25\)  

c = 8.5                          Third: \(x^{2}=56.25\)

                                  Fourth: \(x=\sqrt{56.25}\)

                                      Fifth: x = 7.5

The largest prime number that divides the given expression is 229.

We can factorize the given expression as follows:

\($0! \times 1 \times 1! \times 2 \times 2! \times 3 \times 3! \times \cdots \times 50! \times 50$\)

Now, we can cancel out all the factorials from both sides, leaving us with:

\($1 \times 1 \times 2 \times 2 \times 3 \times 3 \times \cdots \times 50 \times 50$.\)

The largest prime factor of any composite number is the largest prime factor of its prime factorization. By the fundamental theorem of arithmetic, we know that the prime factorization of any composite number is unique.

The prime factorization of a number can be found by dividing the number by prime numbers and keeping dividing the quotient by prime numbers until the quotient is prime.

Now, we can start dividing the given number (the product of all numbers from 1 to 50) by the smallest prime number, 2, and keep dividing the quotient by the next prime number until the quotient is prime.

The largest prime factor of the given expression is the largest prime factor of the final quotient.

The final quotient is

\(2^{24} \times 3^{12} \times 5^9 \times 7^7 \times 11^5 \times 13^4 \times 17^3 \times 19^3 \times 23^2 \times 29^2 \times 31^2 \times 37^2 \times 41^2 \times 43^2 \times 47^2 \times 53^2 \times 59^2 \times 61^2 \times 67^2 \times 71^2 \times 73^2 \times 79^2 \times 83^2 \times 89^2 \times 97^2 \times 101^2 \times 103^2 \times 107^2 \times 109^2 \times 113^2 \times 127^2 \times 131^2 \times 137^2 \times 139^2 \times 149^2 \times 151^2 \times 157^2\)

\(\times 163^2 \times 167^2 \times 173^2 \times 179^2 \times 181^2 \times 191^2 \times 193^2 \times 197^2 \times 199^2 \times 211^2 \times 223^2 \times 227^2 \times 229^2$\)

The largest prime factor of the final quotient is the largest prime factor of the prime factorization, which is 229.

So the largest prime number that divides the given expression is 229.

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The slοpe οf the line that gοes thrοugh (-3,-5) and (-3,-6) is undefined.

Slοpe is a measure οf the steepness οr incline οf a line. It represents the rate at which the line is rising οr falling, and is defined as the change in the y-cοοrdinate (vertical change) divided by the change in the x-cοοrdinate (hοrizοntal change) between twο pοints οn the line.

The slope of the line that goes through (-3,-5) and (-3,-6) is:

\($ \rm m = \frac{y_2 - y_1}{x_2 - x_1}\)

y2 - y1 = m(x2 - x1)

-6 - (-5)= m(-3 - (-3))

-6 + 5 = m(-3 + 3)

-1 = m0

m = -1/0

Thus, The slope of the line that goes through (-3,-5) and (-3,-6) is undefined.

This is because the x-coordinates of the two points are the same, which means that the line is vertical and has no defined slope. In other words, the line is parallel to the y-axis and does not have a rate of change with respect to x.

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Given the exponential function f(x) and the logarithmic function g(x)  the true statement is given as

\(x- > \infty, f (x)- > \infty and g(x) - > \infty\)  Option A.

This is further explained below.

Generally, The exponential function is a kind of mathematical function that may be represented using the notation f(x)=exp or ex. The word, unless otherwise mentioned, usually refers to the function of a real variable that has a positive value; however, it may be extended to complex numbers or applied to other mathematical objects such as matrices or Lie algebras.

In conclusion, the Exponential equation x = ay is defined as analogous to the logarithmic function y = logan. Only when (x = ay), (a > 0), and (a 1) does (y = logan). It is referred to as the logarithmic function of base a. Think about what it implies when the exponential function is inverted: x = ay.

Given the exponential function f(x) and the logarithmic function g(x)  the true statement is given as

\(x- > \infty, f (x)- > \infty and g(x) - > \infty\)  Option A.

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Answer:

D.Mica spent $45.50 on 7 wiffle ball sets. How much does it cost for one set?

Step-by-step explanation:

A.Cost of 1 gallon=3.79

Cost of 10.3 gallon=\(3.79\times 10.3=39.037\)

It can not be solved b y division of decimals.

B.Let x be grade got by Maria in her next test.

Grades obtained by Marian in her 4 previous test are  given by

75.3,92.1,78.6 and 81.0

According to question

\(75.3+92.1+78.6+81.0\geq 400\)

\(327+x\geq 400\)

\(x\geq 400-327\)

\(x\geq 73\)

It can not be solved b y division of decimals.

C.Helena saved money=$45

Cost of dress=$78.00

78-45=33

She needs to save $33 more.

It can not be solved b y division of decimals.

D.Cost of 7 wiffle ball sets=$45.50

Cost of 1  ball set=\(\fra{45.50}{7}=\)$6.5

It can be solved b y division of decimals.

Option D is true.

D.Mica spent $45.50 on 7 wiffle ball sets. How much does it cost for one set?

Answer:

the answer is d

Step-by-step explanation:

Answer: $ 1361.04

Step-by-step explanation:

Discount will be 1060 * 20% = 212

Sales price 1060 + 212 = 1272

Tax 7% = 89.04

Kelly paid 1272 + 89.04 = 1361.04

The new coordinates after transformation of the original coordinates using the transformation rule (x, y) → (x, -y) are;

P(6, -4) → P'(6, 4)

Q(2, -2) → Q(2, 2)

R(2, -6) →  R(2, 6)

S(6, -6) → S(6, 6)

The given reflection transformation of (x, y) → (x, -y) simply means a reflection across the x-axis.

Thus, the new coordinates after undergoing the above transformation are;

P(6, -4) → P'(6, 4)

Q(2, -2) → Q(2, 2)

R(2, -6) →  R(2, 6)

S(6, -6) → S(6, 6)

Thus, we conclude that the new coordinates after transformation of the original coordinates using the transformation rule (x, y) → (x, -y) are;

P(6, -4) → P'(6, 4)

Q(2, -2) → Q(2, 2)

R(2, -6) →  R(2, 6)

S(6, -6) → S(6, 6)

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Answer:

A

Step-by-step explanation:

You solve for x so,

Y=3-5x

y-3=5x  <----- subtract by 3

3/5+y=x <------ divide by -5

Also (3/5,0) is at the x value

The required length of the missing side is 9.28 units for the given triangle.

As shown triangle:

∠A = 104°

∠B = 47°

∠C = 29°

Side c = 7 units

Let's denote the length of the missing side as x.

Using the Law of Sines:

sin(A)/a = sin(B)/b = sin(C)/c

We know the values of angles A, B, and C, as well as the length of side c. Plugging in these values, we get:

sin(104°)/x = sin(47°)/7

To find x, we can rearrange the equation and solve for x:

x = (7 × sin(104°)) / sin(47°)

Using a calculator, to get the value of x:

x ≈ 9.28

Therefore, the length of side a (in front of angle A) is approximately 9.28 units.

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Answer:

Step-by-step explanation:

(0+4)/2 = 4/2 = 2

(-2-4)/2= -6/2 = -3

(2, -3) midpoint

Answer: G, the initial water level was 16 ft

Step-by-step explanation:

I honestly don’t know lol I just looked up the answer on another app

The required quarterly payment over a 13-year period at an interest rate of 9.6% per year, we can use the formula for calculating the future value of a series of equal payments.

This formula is known as the future value of an annuity. By plugging in the values for the number of periods, interest rate, and compounding frequency, we can determine the quarterly payment amount.The future value of an annuity formula is given by: FV = P * [(1 + r)^n - 1] / r

Where:
FV is the future value
P is the periodic payment
r is the interest rate per period
n is the number of periods

In this case, the interest rate is 9.6% per year, compounded quarterly. Since the compounding frequency matches the payment frequency, we can use the formula as is. The number of periods is 13 years, and since we are making quarterly payments, the number of periods will be 13 * 4 = 52.

Plugging in these values, we have:

FV = P * [(1 + 0.096/4)^(13*4) - 1] / (0.096/4)

To find the required quarterly payment, we can rearrange the formula to solve for P:

P = FV * (r / [(1 + r)^n - 1])

Substituting the known values:

P = FV * (0.096/4) / [(1 + 0.096/4)^(13*4) - 1]

Evaluating this expression will give us the required quarterly payment. Remember to round the answer to the nearest cent as specified.

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Answer: σ: 2.76

Step-by-step explanation:

Count, N: 5

Sum, Σx: 125

Mean, μ: 25

Variance, σ2:  7.6

Steps

look at attached pic for formula

σ^2 = \(\frac{Σ(xi - μ)^{2} }{N}\)

\(\frac{(21 - 25)2 + ... + (29 - 25)2}{5}\)

⇒ \(\frac{38}{5}\)

⇒ 7.6

σ =  \(\sqrt{7.6}\)

⇒   2.756809750418

⇒ or 2.76

The remainder when the polynomial is divided by x + 1 is 2

Given the function P(x)=3x^4 −2x^3 +2x^2 −1, to get the rmainder if the polynomial is divided by x + 1, we will substitute x = - 1 into the function to have:

P(-1) = 3(-1)^4 −2(-1)^3 +2(-1)^2 −1

P(-1) = 3(1) - 2 + 2(1) - 1

P(-1) = 1 + 1

P(-1) = 2

Hence the remainder when the polynomial is divided by x + 1 is 2

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Answer:

6

Step-by-step explanation:

:)

\(\sqrt[4]{567x^9 y^{11}} ~~ \begin{cases} 567=3\cdot 3\cdot 3\cdot 3\cdot 7\\ \qquad ~~ ~ 3^4\cdot 7\\ x^9=x^{4+4+1}\\ \qquad ~x^4\cdot x^4\cdot x\\ y^{11}=y^{4+4+3}\\ \qquad ~~ y^4\cdot y^4\cdot y^3 \end{cases}\implies \sqrt[4]{3^4\cdot 7 \cdot x^4\cdot x^4\cdot x\cdot y^4\cdot y^4\cdot y^3}\)

\(\left( 3^4\cdot 7 \cdot x^4\cdot x^4\cdot x\cdot y^4\cdot y^4\cdot y^3\right)^{\frac{1}{4}}\implies 3^{\frac{4}{4}}\cdot 7^{\frac{1}{4}}\cdot x^{\frac{4}{4}}\cdot x^{\frac{4}{4}}\cdot x^{\frac{1}{4}}\cdot y^{\frac{4}{4}}\cdot y^{\frac{4}{4}}\cdot y^{\frac{3}{4}}\)

\(3\cdot 7^{\frac{1}{4}}\cdot x\cdot x\cdot x^{\frac{1}{4}}\cdot y\cdot y\cdot y^{\frac{3}{4}}\implies 3x^2y^2\cdot 7^{\frac{1}{4}}x^{\frac{1}{4}} y^{\frac{3}{4}} \implies 3x^2y^2(7xy^3)^{\frac{1}{4}} \\\\\\ ~\hfill {\Large \begin{array}{llll} 3x^2y^2\sqrt[4]{7xy^3} \end{array}}~\hfill\)