what exactly is science?
( an answer that wld express a physics teacher please :) )

Answers

Answer 1

Answer:

he intellectual and practical activity encompassing the systematic study of the structure and behaviour of the physical and natural world through observation and experiment.


Related Questions

What is the speed of an airplane that travels 4500 miles in 6 hours?

Answers

Answer:

750 miles / hour

Explanation:

velocity = distance / time

             = 4500 miles / 6 hours

             = 750 miles / hour

Given:-

Speed of the airplane (s) = 4500 miles Time taken (t) = 6 h

To Find: Speed (v) of the particle (airplane).

We know,

s = vt

where,

s = Distance,v = Speed &t = Time taken.

Similarly,

v = s/t

→ v = (4500 miles)/(6 hours)

v = 750 miles/hour ...(Ans.)

What is the total charge of barium oxide?

Answers

Barium cation has +2 charge and oxide anion has −2 charge
+2-2 the answer on top or right

Which action can knowing the "Three Rs lead a person to do?
A) resolving conflicts
B) helping one's family create a disaster plan
C)staying safe in a natural disaster
D)protecting the environment

Answers

Answer:

d

Explanation:

What is tensor quantity?
Is Inertia a tensor? give reason​

Answers

Answer:

A tensor is a quantity, for example a stress or a strain, which has magnitude, direction, and a plane in which it acts. Stress and strain are both tensor quantities. ... A tensor is a quantity, for example a stress or a strain, which has magnitude, direction, and a plane in which it acts.

Inertia Tensor. where I = the inertia tensor. The angular momentum of a rigid body rotating about an axis passing through the origin of the local reference frame is in fact the product of the inertia tensor of the object and the angular velocity. ... As shown in [7], the inertia tensor is symmetric.

Explanation:

Hope dis help

Variable Radius Mass (kg) Period (s) 3 2 Radius (m) 1 2 3 3 Tangential speed (m/s) 3.14 3.14 3.14 3.14 3.14 4 Centripetal Force (N) 29.6 14.8 9.87 7.40 5.92 6 www 8 4 10 5 Analysis: Force vs Circle Radius 1. Looking at the Variable Radius table, what can you conclude about the relationship between the centripetal force and radius? What is the functional form of this relationship?

Answers

We can infer from the Variable Radius table that as the radius grows, the centripetal force decreases.

The centripetal force and radius have an inverse connection, which means that as one quantity changes, the other changes proportionally.

The mathematical formula for the functional form of this connection is F = k/r, where F is the centripetal force, k is a proportionality constant, and r is the radius.

The centripetal force equation, which describes this relationship, is a key idea in comprehending circular motion.

The Variable Radius table reveals that there is an inverse proportionality between the centripetal force and radius. The centripetal force reduces as the radius grows, and vice versa.

The centripetal force equation, F = k/r, where F is the centripetal force, k is a proportionality constant, and r is the radius, describes this relationship.

The travel of planets around the sun or the movement of cars around a curve are only two examples of how comprehending this relationship is crucial to understanding circular motion.

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Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93

Particles q +8.0 C, q2 +3.5 C, and93-2.5 C are in a line. Particles q and q2 areseparated by 0.10 m and

Answers

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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Why is the entropy change for process 2 larger than that for process 1? Match the words in the left column to the appropriate blanks in the sentences on the right: Make sure the sentences are complete before submitting your answer: Reset Help gas to liquid The substance changes from solid in process 1 and from liquid process 2. The volume and motional freedom of the greater phase causes AS for gas vaporization to (always) be larger than 4 S for fusion: larger less solid to gas liquid to gas smaller solid to liquid Submit Request Answer

Answers

The answer is: 1. Solid to Liquid; 2. Liquid to Gas; 3. Larger;  4. Greater;  5. Gas;

The substance changes from solid to liquid in 1, from liquid to gas in 2. The larger volume and greater motional freedom of the gas phase causes AS for vaporization to (always) be larger than AS for fusion.

We can define entropy as the degree of randomness or the possible states of a substance. As we go from solid to liquid to gas, the entropy increases. If the entropy change for 2 is larger than for 1, this probably means that 1 is a solid to liquid process, while 2 is a liquid to gas process. Moreover, we can define fusion as the phase change process between solid and liquid states.

Question:

Why is the entropy change for 2 larger than that for 1? Match the words in the left column to the appropriate blanks in the sentence on the right. Make the sentence is complete before submitting your answer.

gas

solid

liquid

gas to liquid

solid to liquid

liquid to gas

greater

smaller

less

solid to gas

larger

The substance changes from _____ in 1, from _____ in 2.

The  _____ volume and _____ motional freedom of the  _____ larger than AS for fusion. phase causes AS for gas vaporization to (always) be larger than AS for fusion.

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Which property of matter is conserved in chemical reactions and shown by balanced equations?
O mass
O volume

O density
O shape

Answers

Answer:

Mass.

Explanation:

I took the quiz and got the answer right

Your answer would be density

who will it benefit if they do butterfly groin stretch​

Answers

Answer:

ummmmm mmmmm butterflies :)

Explanation:

Answer:

It is a great stretch for athletes who play field or court sports, runners, and anyone who has tight hips or a history of groin injuries.

Its a great flexibility exercise

Explanation:

Hope that helps

What 2 factors do you need in order to calculate speed?

Answers

Answer:

Distance and time.

Explanation:

Speed=Distance/time

The two factors which we need in order to calculate the speed of an object are the distance covered by the object and the time taken to cover that distance.

What is Speed?

Speed is the rate of change of position of an object in any direction. Speed is a scalar quantity as it has only magnitude and no direction. It is measured as the ratio of the distance covered by an object to the time taken in which the distance was covered by that object.

Speed has the dimension of distance covered by the time taken. Thus, the SI unit of speed is the combination of the basic units of distance and the basic unit of Time. Thus, the SI unit of speed is meter per second (m/s).

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A 12 kg box is pulled across the floor with a 48 N horizontal force. If the force of friction is 12 N, what is the acceleration of the box?

Answers

Answer:

The acceleration of the box is 3 m/s²

Explanation:

Given;

mass of the box, m = 12 kg

horizontal force pulling the box forward, Fx = 48 N

frictional force acting against the box in opposite direction, Fk = 12 N

The net horizontal force on the box, F = 48 N - 12 N

The net horizontal force on the box, F = 36 N

Apply Newton's second law of motion to determine the acceleration of the box;

F = ma

where;

F is the net horizontal force on the box

a is the acceleration of the box

a = F / m

a = 36 / 12

a = 3 m/s²

Therefore, the acceleration of the box is 3 m/s²

Why was the government in giving support to addressing and researching the HIV epidemic ?

Answers

Do you mind adding the picture?? It’ helps me answer the question better :)


1. A 9.32 x 10³N Car is traveling West on 14 towards the "Affle" house. Let the force onto
the wheels be set to be twice that of the car's total weight. The coefficient of kinetic
friction is said to be 0.222.
a. Determine the acceleration of the car
2. Determine the acceleration of the crate. A rightward force of 302 N is applied to an 18.6
kg crate to accelerate it across the floor. The coefficient of friction between the crate and
the floor is 0.750.

Answers

(1) The acceleration of the car is determined as 17.42 m/s².

(2) The acceleration of the crate is determined as 8.89 m/s².

Acceleration of the car

The acceleration of the car is calculated from the net force acting on the car.

∑F = ma

F - Ff = ma

F - μW = ma

where;

F is the applied force on the car = 2 times weightW is weight of the carμ is coefficient of kinetic friction m is mass of the car

m = W/g

m = (9320)/(9.8)

m = 951.02 kg

2(9320) - 0.222(9320) = 951.02a

16,570.96 = 951.02a

a = 17.42 m/s²

Acceleration of the crate

F - μW = ma

F - μmg = ma

302 - 0.75(18.6 x 9.8) = 18.6a

165.29 = 18.6a

a = 8.89 m/s²

Thus, the acceleration of the car is determined as 17.42 m/s².

The acceleration of the crate is determined as 8.89 m/s².

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What will happen to the wavelength of light uf the frequency is doubled?What will happen to the wavelength of light uf the frequency is doubled?​

Answers

Answer:

if the frequency is double, the wavelength is only half as long

Explanation:

Considering the definition of wavelength, frequency and propagation speed, if the wavelength is doubled, the frequency is reduced by half.

In a periodic wave the wavelength (λ) is the physical distance between two points from which the wave repeats itself. That is, the wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

The frequency (f) is a measure of the number of cycles or repetitions of the wave per unit of time. Its unit is s⁻¹ or hertz (Hz).

The wavelength and its frequency are related from the speed at which the wave travels. The propagation speed (v) is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave's disturbance propagates along its displacement. So, the speed expression is:

v=λ×f

This indicates that the higher the frequency, the shorter the wavelength and the lower the frequency, the longer the wavelength.

All electromagnetic waves propagate in a vacuum at a constant speed of 300,000,000 m/s, the speed of light. Then, since an inversely proportional relationship is established between the frequency and the wavelength, if the wavelength is doubled, the frequency is reduced by half.

In summary, if the wavelength is doubled, the frequency is reduced by half.

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Suppose a small comet was on a path to collide with Earth. Its density is 0.5 g/cm3 (500 kg/m3 ). Earth’s radius is 6378 km and Earth’s density is about 5500 kg/m3 (5.5 g/cm3 ). At what height would it disintegrate? (3) Hint: the Roche limit = 2.5 [(density of planet)/(density of moon or other object)]1/3 (radius of planet)

Answers

The comet will disintegrate at a height of 70,479,900 m.

Comet's height problem

To find the height at which the comet would disintegrate, we need to determine Earth's Roche limit with respect to the comet.

Roche limit = 2.5 [(density of planet)/(density of moon or other object)]^(1/3) (radius of planet)

Let's assume that the moon has a similar density to the comet, so we can use the Roche limit formula with the following values:

density of planet = 5500 kg/m^3

density of moon or other object = 500 kg/m^3

radius of planet = 6378 km = 6,378,000 m

Roche limit = 2.5 [(5500 kg/m^3)/(500 kg/m^3)]^(1/3) (6,378,000 m)

Roche limit = 76,857,900 m

This means that any object that comes closer to Earth than 76,857,900 m would be torn apart by tidal forces.

Therefore, the comet would disintegrate at a height of 76,857,900 m - 6,378,000 m = 70,479,900 m above Earth's surface.

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*69. ssm A 1.0 x 10-kg spider is hanging vertically by a thread that
has a Young's modulus of 4.5 X 10 N/m² and a radius of 13 x 10 m.
Suppose that a 95-kg person is hanging vertically on an aluminum wire.
What is the radius of the wire that would exhibit the same strain as
the spider's thread, when the thread is stressed by the full weight of the
spider?

Answers

The radius of the wire that would exhibit some strain the same strain as a spider is 0.06m.

How to calculate the radius?

The strain in a wire is given by the change in length divided by the original length, and is equal to the force applied divided by the cross-sectional area times the Young's modulus.

The force applied to the spider's thread is the weight of the spider, which is 1.0 x 10⁻³ kg x 9.8 m/s² = 9.8 x 10⁻³N.

The original length of the spider's thread is L = h, where h is the height of the spider.

The change in length is given by ΔL = FL/AY, where F is the force applied, L is the original length, A is the cross-sectional area, and Y is the Young's modulus.

Solving for the cross-sectional area, A = FL/ΔL = FL/ (FY/Y) = FLY/F = LY/F = πr²

We can now substitute the known values into the equation and solve for the radius, r:

πr² = LY/F = hY/F = 4.5 x 10 N/m² x (13 x 10⁻⁶ m) / (9.8 x 10⁻³ N)

r = sqrt(hY/Fπ) = sqrt(4.5 x 10 N/m² x (13 x 10⁻⁶ m) / (9.8 x 10⁻³ Nπ))

The radius of the aluminum wire that would exhibit the same strain as the spider's thread is the same as the calculated radius, 0.06m.

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The magnetic field perpendicular to a single 16.7-cm-diameter circular loop of copper wire decreases uniformly from 0.750 T to zero.
If the wire is 2.25 mm in diameter, how much charge moves past a point in the coil during this operation? The resistivity of copper is 1.68Ã10â8Ωâm.
Express your answer to three significant figures and include the appropriate units.

Answers

Answer:

1.24 C

Explanation:

We know that the magnitude of the induced emf, ε = -ΔΦ/Δt where Φ = magnetic flux and t = time. Now ΔΦ = Δ(AB) = AΔB where A = area of coil and change in magnetic flux = Now ΔB = 0 - 0.750 T = -0.750 T, since the magnetic field changes from 0.750 T to 0 T.

The are , A of the circular loop is πD²/4 where D = diameter of circular loop = 16.7 cm = 16.7 × 10⁻²m

So, ε = -ΔΦ/Δt = -AΔB/Δt= -πD²/4 × -0.750 T/Δt = 0.750πD²/4Δt.

Also, the induced emf ε = iR where i = current in the coil and R = resistance of wire = ρl/A where ρ = resistivity of copper wire =1.68 × 10⁻⁸ Ωm, l = length of wire = πD and A = cross-sectional area of wire = πd²/4 where d = diameter of wire = 2.25 mm = 2.25 × 10⁻³ m.

So, ε = iR = iρl/A = iρπD/πd²/4 = 4iρD/d²

So,  4iρD/d² = 0.750πD²/4Δt.

iΔt = 0.750πD²/4 ÷ 4iρD/d²

iΔt = 0.750πD²d²/16ρ.

So the charge Q = iΔt

= 0.750π(Dd)²/16ρ

= 0.750π(16.7 × 10⁻²m 2.25 × 10⁻³ m)²/16(1.68 × 10⁻⁸ Ωm)

= 123.76 × 10⁻² C

= 1.2376 C

≅ 1.24 C

1. which of the following is the speed of light? 300,000 km/sec 186,283 kilometers per second 186,283 meters per second 186,283 meters per hour 300,000 km/hr

Answers

Speed of light, is generally 299,792,458 m/s. The appropriate choice is "186,283 kilometers per second.

The speed of light is approx. 299,792,458 m/s. This is equal to approximately 186,282.397 miles per second or approximately 300,000 kilometers per second.

Therefore, the correct answer is "186,283 kilometers per second" or "300,000 km/sec". The other choices are incorrect because they are not the correct units for the speed of light. Visible light is an example of electromagnetic radiation that moves at the speed of light. Light and other electromagnetic waves appear to move instantly for many practical uses, but their finite speed has dramatic implications for vast distances and particularly sensitive measurements. The starlight that can be seen from Earth has been out there for a very long time, allowing people to view far-off objects and learn about the evolution of the universe. It can take minutes to hours for signals to reach from Earth to a spacecraft when corresponding with far-off space missions. The absolute shortest communication delay between computers, to computer memory, and within a CPU is fixed in computing at the speed of light.

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A boy throws an arrow at an original velocity of 2m / s, aiming to create an angle 0, referring to the balloon at a distance of 3m from the point of departure. Calculate the angle 0 and the height of the arrow.

Answers

Answer:

s=0.204m

Explanation:

Assuming that the arrow is thrown horizontally and there is no air resistance, we can use the following formula to calculate the launch angle 0:

tan(0) = opposite/adjacent = height/distance

where opposite is the height that the arrow reaches and adjacent is the distance to the balloon.

Rearranging the formula, we get:

0 = arctan(height/distance)

0 = arctan(height/3)

Taking the tangent of both sides, we get:

tan(0) = tan(arctan(height/3))

tan(0) = height/3

Now, we need to find the height of the arrow. Using the kinematic equation:

v^2 = u^2 + 2as

where v is the final velocity (0m/s, at maximum height), u is the initial velocity (2m/s), a is acceleration (-9.8m/s^2, due to gravity) and s is the distance travelled vertically until the arrow reaches maximum height.

At maximum height, the final velocity is 0m/s. Therefore, we have:

0 = (2m/s)^2 + 2(-9.8m/s^2)s

Solving for s, we get:

s = 0.204m

Therefore, the height of the arrow is approximately 0.204m.

Frozen food will thaw more quickly when placed under running water than if it
is immersed in water. Why?

Answers

Answer:

google answers, i'm not 100% on how to type my own answer

Explanation:

Thaw food submerged under running water at a temperature of 70˚F (21˚C) or lower. The water flow must be strong enough to wash food particles into the overflow drain. In a microwave oven. You can safely thaw food in a microwave oven if the food will be cooked immediately.

The reason defrosting in water is preferable is because water conducts heat better than air. And the faster food is thawed, the better it tastes.

Answer:

The reason defrosting in water is preferable is because water conducts heat better than air. And the faster food is thawed, the better it tastes.

Select the correct answer. Based on the law of conservation of energy, which statement is correct? O A. Energy is always being added to all parts of the Universe. O B. Energy is often destroyed in some parts of the Universe. O C. Energy in a closed system cannot change forms. O D. Energy in an isolated system remains constant.

Answers

Answer:

d. energy in an isolated system remains constant.

Explanation:

energy can neither be replaced or destroyed

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.​

Answers

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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What information do you need to collect in order to study an object’s motion?

Answers

The information we will need to demonstrate that an object is in motion include;

initial position of the objectfinal position of the objecttime difference between the initial and final position of the object

What is an object in motion?

An object is in motion when it changes its position with time, relative to a stationary object.

Mathematically, we can use the following equation to demonstrate the motion of an object.

v = Δx / Δt

where;

Δx is the change in the position of the objectΔt is the change in time of motion of the object

So the data we will need to demonstrate that an object is in motion include;

initial position of the objectfinal position of the objecttime difference between the initial and final position of the object

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A 5.0-m-diameter merry-go-round is turning with a 3.7 s period. Part A What is the speed of a child on the rim

Answers

Answer:

Speed of a child on the rim is 4.25 m/s.

Explanation:

Given;

diameter of the merry-go-round, d = 5.0 m

period of the motion, t = 3.7 s

one complete rotation of the merry-go-round = πd

one complete rotation of the merry-go-round = π(5) = 15.71 m

Speed is given as distance / time

speed of a child on the rim = 15.71 / 3.7

speed of a child on the rim = 4.25 m/s

Therefore, speed of a child on the rim is 4.25 m/s.

At a tractor pull, one machine has a pull that produces 27,000 joules of power in 3 seconds. How many watts of power did this tractor produce?
3

Answers

Answer:

28230 joules

Explanation:

becasue yes

a sound is sent out from the sheep and it's reflection from the floor of the ocean return s over second later . Assuming that the velocity of sound in water is 1500metre per second .how deep is the ocean?​

Answers

The depth of the ocean is 3750 m

How do you find the depth of the ocean?

Echoing  is a method of measuring the depth of the ocean by sending sound waves down to the ocean floor and measuring the time it takes for the sound waves to bounce back. The depth is calculated by multiplying the time taken by the speed of sound in water.

Given that;

V = 2x/t

x = distance

Then we have that

Vt = 2x

x = Vt/2

x = 1500 * 5/2

= 3750 m

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Missing parts;

A sound is sent out from the sheep and it's reflection from the floor of the ocean return 5 s over second later . Assuming that the velocity of sound in water is 1500metre per second .how deep is the ocean?​

1. A 100-kg crate is pulled across a warehouse floor using a rope with a force of 250 N at an angle of 45o from the horizontal. The coefficient of friction between the crate and the floor is 0.12.

a) Calculate the net force and acceleration of the crate.

b) If the crate was moving at 1.0 m/s when it was pulled, what would be its velocity after pulling it for 5.0 s?

Answers

Answer:

(a) The net force is 80.394 N

    The acceleration of the crate is 0.804 m/s²

(b) the final velocity of the crate is 5.02 m/s

Explanation:

Given;

mass of the crate, m = 100 kg

applied force, F = 250 N

angle of inclination, θ = 45°

coefficient of friction, μ = 0.12

Applied force in y-direction, \(F_y = Fsin \theta = 250sin45 = 176.78 \ N\)

Applied force in x-direction, \(F_x = Fcos \theta = 250cos45 = 176.78 \ N\)

The normal force is calculated as;

N + Fy -W = 0

N = W - Fy

N = (100 x 9.8) - 176.78

N = 980 - 176.78 = 803.22 N

The frictional force is given by;

Fk = μN

Fk = 0.12 x 803.22

Fk = 96.386 N

(a) The net force is given by;

\(F_{net} = F_x - F_k\\\\F_{net} = 176.78-96.386\\\\F_{net} = 80.394 \ N\)

Apply Newton's second law of  motion;

F = ma

\(a = \frac{F_{net}}{m}\\\\ a = \frac{80.394}{100}\\\\ a = 0.804 \ m/s^2\)

(b) the velocity of the crate after 5.0 s

\(F = ma= \frac{m(v-u)}{t} \\\\Ft =m(v-u)\\\\v-u = \frac{Ft}{m}\\\\ v = \frac{Ft}{m} + u\\\\v = \frac{F_{net}*t}{m} + u\\\\v = \frac{80.394*5}{100} + 1\\\\v = 5.02 \ m/s\)

Bill drives and sees a red light. He slows down to a stop. A graph of his velocity over time is shown below.
What is his average acceleration from 0 to 10 seconds?

Bill drives and sees a red light. He slows down to a stop. A graph of his velocity over time is shown

Answers

Answer: its actually 0

Explanation: i read the khan academy hints and the answer is 0

yes the answer is 0 and if its not and have this graph its -2.0

4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V

4. Calculate the total resistance of the circuit if R1=4 , R2=30 , R3=10, R4=5 Determine the current

Answers

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

For more such questions on current, click on:

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What exactly are molecules, how do they function?

Answers

Answer:

molecule, a group of two or more atoms that form the smallest identifiable unit into which a pure substance can be divided and still retain the composition and chemical properties of that substance.Molecules are made up of atoms that are held together by chemical bonds. These bonds form as a result of the sharing or exchange of electrons among atoms. The atoms of certain elements readily bond with other atoms to form molecules. ... The atoms of some elements do not easily bond with other atoms. l

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