Answer:
CHEMICAL REACTION
Explanation:
The centripetal acceleration of a point on a wheel is 72 m/s2. The wheel is spinning with a
tangential velocity of 4.3 m/s. What is the radius of the wheel?
The radius of the wheel with a tangential velocity of 4.3 m/s and centripetal acceleration of 72 m/s² is 0.25 meter.
What is centripetal acceleration ?The acceleration of an object ,moving through a circular path is called the centripetal acceleration. It is related to the velocity and radius of curvature of the circular path as follows:
a = v²/r.
The tangential velocity or angular velocity is the rotational analogue of the linear velocity.
given that, tangential velocity v = 4.3 m/s
centripetal acceleration a = 72 m/s²
Then, radius of the wheel is calculated as follows:
r = v²/a
r = (4.3 m/s × 4.3 m/s)72 m/s²
= 0.25 meter.
Therefore, the radius of the rotating wheel is 0.25 meter.
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What is the best description of realistic fiction o texts that are written in first person about a period in an author's life?
An autobiography, like a memoir, is the writer's recounting of his or her life and is written in the first person, making the writer the protagonist of the narrative.
What phrase best sums up a realistic piece of fiction?Contemporary/Realistic: In order to accurately portray our environment and society, realistic fiction develops fictional people and circumstances. Growing up and dealing with social and personal issues are the main themes. Characters in this genre are depicted as they learn about both themselves and others.
Which of these two realistic fiction subgenres predominates?Historical and contemporary fiction make up realistic fiction's two subgenres. Unlike current fiction, which takes place in the present or recently past, historical fiction takes place at a period that is far enough back in history to be deemed history.
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Answer: the answer is b
Explanation:
edge
Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?
The near point of a human eye is about a distance of 25 cm.
The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.
This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.
The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.
In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.
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Please help me, it’s due tonight and I’m very confused!! THANK YOU
Explanation:
If your reaction time is 1 second, then the new reaction time for each is:
Alcohol: 0.30 × 1 + 1 = 1.30
Drugs: 0.50 × 1 + 1 = 1.50
Cell phone: 0.20 × 1 + 1 = 1.20
The graph below shows the motion of a person leaving a theater. Three segments of their journey have been identified as A, B, and C.
What does line segment C represent?
The person is moving away from the theater.
The person is standing still.
The person is moving closer to the theater.
The person is slowing down.
The graph below shows the motion of a person leaving theater, line segment C represent : The person is moving away from the theater.
What is meant by motion?In physics, motion is a change with time of the position or orientation of a body. Motion along a line or a curve is called as translation whereas motion that changes orientation of a body is called rotation.
Motion is a change in position of an object over the time and is described in terms of displacement, distance, velocity, acceleration, time and speed.
Change in position of a body with time when compared with another body is known as motion.
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3. A football player runs at 8 m/s and plows into a 80 kg referee standing on the field causing
the referee to fly forward at 5.0 m/s. If this were a perfectly elastic collision, what would the
mass of football player be?
Answer:
Explanation:
To solve for the mass of the football player, we can use the conservation of momentum principle, which states that the total momentum before a collision is equal to the total momentum after the collision. Assuming the collision is perfectly elastic, we have:
m1 * v1 + m2 * v2 = m1 * v1' + m2 * v2'
where m1 is the mass of the football player, v1 is the initial velocity of the football player, m2 is the mass of the referee, v2 is the initial velocity of the referee, v1' is the final velocity of the football player, and v2' is the final velocity of the referee.
Since the referee is at rest before the collision, we can set v2 = 0. Plugging in the given values, we get:
m1 * 8 + m2 * 0 = m1 * (-8) + m2 * 5
Expanding and solving for m1:
8m1 = -8m1 + 80
16m1 = 80
m1 = 5 kg
So, the mass of the football player is 5 kg.
A bucket crane consists of a uniform boom of mass
M = 201 kg and length L= 59.05 ft that pivots at a point on
the bed of a fixed truck. The truck supports an elevated bucket
with a worker inside at the other end of the boom, as shown in
the figure. The bucket and the worker together can be modeled
as a point mass of weight 201 lb located at the end point of
the boom.
Suppose that when the boom makes an angle of 68.7° with the
horizontal truck bed, the bucket crane suddenly loses power,
causing the bucket and boom to rotate freely toward the
ground. Find the magnitude of the angular acceleration la of
the system just after the crane loses power. Take the rotation
axis to be at the point where the boom pivots on the truck bed.
Use g = 9.81 m/s2 for the acceleration due to gravity. For unit
conversions, assume that 1 m = 3.28 ft and 1 lb = 4.45 N.
Express your answer to at least two decimal places.
Newton's second law for rotational motion allows finding the results for the angular acceleration of the system at the moment of losing power is:
α =0.616 rad / s²
Newton's second law for rotational motion relates the torque to the moment of inertia and the angular acceleration, in the special case where the angular acceleration is zero, it is called the rotational equilibrium condition.
\(\sum \tau = I \alpha\)
\(\tau = F \ r \ sin \theta\)
where τ is the torque, F is the force, r the distance to the pivot point and θ the angle between the force, the distance, I is the moment of inertia and α is the angular acceleration.
In this case they indicate the values in several different units, let's reduce to the international system of measurements (SI).
Beam mass M = 201 kg Beam length L= 59.05 ft (1m / 3.28 ft) = 18.0 m Worker and basket weight Wh = 201 lb (1N / 0.2248 lb) = 894.1 N Beam angle tea = 68.7º
We place our reference system at the base of the beam on the truck and counterclockwise turns as positive, and in the attached we see a free-body diagram of the system.
\(W_m \ L \ sin 68.7 + Mg \ \frac{L}{2} \ sin 68.7 = I \alpha\)
The moment of inertia is an additive scalar quantity, the total moment of inertia is the moment of inertia of the pen plus the moment of inertia of the man.
Moment of inertia of the beam with respect to one end.
\(I_\) = ⅓ ML²
moment of inertia of man
\(I_m = M_m L^2\)
Let's substitute
\((W_m + \frac{Mg}{2} ) \ L \ sin 68.7 = (\frac{1}{3} M + m_m ) L^2 \alpha \\\alpha = \frac{(W_m + \frac{Mg}{2} ) sin 68.7 }{ (\frac{1}{3} M + m_m ) L }\)
Let's calculate
The mass of man is
m = \(\frac{W_m}{g}\)
m = 894.1 / 9.8
m = 91.2 kg
\(\alpha = \frac{(894.1 +2.1 \ 9.8 ) \ sin 68.7 }{ 18.0 ( \frac{201}{3} + 91 }\)
α = 0.616 rad / s²
In conclusion using Newton's second law for rotational motion we can find the results for the angular acceleration of the system at the moment of losing power is 0.616 rad / s²
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6. The rate at which velocity changes is called
O speed
O direction
O acceleration
O displacement
a roller coaster start at a height of 40Meters and reached a height of 20meter. does mechanical energy change
Mechanical energy changes when a roller coaster starts at a height of 40 meters and reaches a height of 20 meters. The potential energy decreases, while the kinetic energy increases.
When a roller coaster starts at a height of 40 meters and reaches a height of 20 meters, mechanical energy changes. In physics, mechanical energy is the sum of potential and kinetic energy that is present in the objects. When an object is moved, it gains or loses energy, thus the mechanical energy changes. There are two forms of mechanical energy, namely kinetic energy and potential energy. Kinetic energy is the energy that a moving object possesses due to its motion, while potential energy is the energy that an object possesses due to its position or shape.
In the case of a roller coaster, when it starts at a height of 40 meters, it has potential energy that is equal to its mass multiplied by the acceleration due to gravity multiplied by its height. As it moves down the track, the potential energy gets converted into kinetic energy, which is the energy of motion. When the roller coaster reaches a height of 20 meters, it has a lower potential energy compared to when it started. The difference in potential energy is equal to the amount of work done by the force of gravity in bringing the roller coaster down from a height of 40 meters to a height of 20 meters. At the same time, the roller coaster has a higher kinetic energy than when it started, as it gained speed during the descent.
Therefore, in summary, mechanical energy changes when a roller coaster starts at a height of 40 meters and reaches a height of 20 meters. The potential energy decreases, while the kinetic energy increases.
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A race car traveling at 10 meters per second accelerates at 1.5 meters per second squared while moving a distance of 600 meters. Which of the following best represents the final speed of the race car?
Answer:
Explanation:
Givens
vi = 10 m/s
a = 1.5 m/s^2
d = 600 m
vf = ?
Formula
vf^2 = vi^2 + 2*a*d
Solution
vf^2 = 10^2 + 2*1.5 * 600
vf^2 = 100 + 1800
vf^2 = 1900
sqrt(vf^2) = sqrt(1900)
vf = 43.59 m/s
A cannon is evaluated at an angle of 45 degree. It fires a ball with a speed of 300 m/s. What is the horizontal range of the ball
Answer:
The horizontal range of the cannonball is 9180.4 meters.
Explanation:
The horizontal range of a cannonball can be calculated using the following formula:
range = (speed * speed * sin (2 * angle)) / acceleration due to gravity
In this case, we are given that the cannon is fired at an angle of 45 degrees and that the speed of the ball is 300 m/s. We can plug these values into the formula to calculate the horizontal range of the ball:
range = (300 * 300 * sin (2 * 45)) / 9.8
= (90000 * sin (90)) / 9.8
= (90000 * 1) / 9.8
= 9180.4 m
The speed of a sound wave depends on properties of the medium occurs when a sound wave moves at an angle from one medium into another in which its speed is different.O A. RefractionO B. DiffractionO C. ResonanceO D. Interference
Refraction
Explanation:The change in direction of a sound wave when it crosses between two mediums is refraction.
This hange in direction of the sound waves iis accompanied by a change in speed and the wavelength of the sound.
Therefore, when a sound wave moves at an angle from one medium into another in which its speed is different, the phenomenon is referred to as refraction.s
if an object travels at constant speed in a circular path the acceleration of the object is
Answer:
centripetal and of constant magnitude
Explanation:
The acceleration of an object traveling on a circular path at constant speed is directed towards the center of the circle (centripetal) and of constant magnitude equal to the square of the object's speed divided by the radius of the circle.
A cyclist rides 4.0 km due west, then 11.0 km 35° west of north. From this point she rides 7.0 km due east. What is the final displacement from where the cyclist started (in km)? (Express your answer in vector form. Assume the +x-axis is to the east, and the +y-axis is to the north.)
Δr =
km
Expressed in vector form, the final displacement from where the cyclist started is Δr = 3.0 km east + 6.38 km north.
What is displacement?Displacement is a vector quantity that represents the change in position of an object. It is the straight-line distance and direction between the initial position of an object and its final position.
To solve the problem, we can break down the motion of the cyclist into two components: one in the x-direction (east-west) and one in the y-direction (north-south).
In the x-direction, the cyclist rides 4.0 km west and then 7.0 km east, for a net displacement of 7.0 km - 4.0 km = 3.0 km to the east. In the y-direction, the cyclist rides 11.0 km at an angle of 35° west of north, which means that the component of this distance in the y-direction is 11.0 km * sin(35°) = 6.38 km to the north.
Therefore, the final displacement from where the cyclist started is the vector sum of these two components: Δr = (3.0 km, 6.38 km)
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two particles with equal charge experiences a force of 12 nN where they are 30 cm apart. what is the magnitude of the charge on each particle
Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.
Definition of Coulomb's LawCoulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.
This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:
\(F=k\frac{Qq}{d^{2} }\)
where:
F is the electrical force of attraction or repulsion. It is measured in Newtons (N).Q and q are the values of the two point charges. They are measured in Coulombs (C).d is the value of the distance that separates them. It is measured in meters (m).k is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\).The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.
Magnitude of the charge on each particleIn this case, you know that:
F= 12 nN= 1.8×10⁻⁸ N (being 1 nN= 1×10⁻⁹ N)k= 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)Q= qd= 30 cm= 0.3 m (being 100 cm= 1 m)Replacing in the Coulomb's Law:
\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)
Being Q=q:
\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)
Solving:
1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²
2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²
2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²
2×10⁻¹⁸ C²/m² ×0.09 m²= q²
1.8×10⁻¹⁹ C²= q²
√1.8×10⁻¹⁹ C²= q
4.2426 C= q= Q
Finally, each charge has a value of 4.2426 C.
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Question 16 of 17
Figure (a) shows a wire that forms a rectangle (W = 23.0cm, H = 31.0cm) and has a resistance of 4.00 mOhm. Its interior is split into three equal areas, with magnetic fields B₁, B₂, and B. The fields are uniform within each region and directly out of or into the page as indicated. Figure (b) gives the change in the z components B, of the three fields with time t; the vertical axis scale is set by B, = 3.00 μT
and B-2.50B, What are the
(a) the magnitude and
(b) direction of the current induced in the wire?
For the magnetic fields:
(a) 53.8 A(b) The induced current will flow counterclockwise.How to determine magnitude and direction?From Faraday's law of electromagnetic induction, the emf induced in the wire is given by:
emf = -dΦ/dt
where Φ is the magnetic flux through the wire. The negative sign indicates that the induced emf opposes the change in magnetic flux.
The magnetic flux through each of the three regions can be calculated as follows:
Φ₁ = B₁WH/3
Φ₂ = B₂WH/3
Φ₃ = BWH/3
The total magnetic flux through the wire is:
Φ = Φ₁ + Φ₂ + Φ₃ = (B₁ + B₂ + B)WH/3
Taking the time derivative of the magnetic flux:
dΦ/dt = (B₁ + B₂ + B)(WH/3)(dB/dt)
Substituting the given values:
dΦ/dt = (3.00 μT + 2.50(3.00 μT))(0.23 m)(0.31 m)(1.00 m)/(3)(0.010 s) = 0.215 V
The induced emf is equal to the product of the current and the resistance of the wire:
emf = IR
Solving for I:
I = emf/R = 0.215 V / 4.00 mΩ = 53.8 A
The direction of the induced current can be determined using Lenz's law, which states that the direction of the induced current is such that it opposes the change in magnetic flux that produced it. In this case, the induced current will produce a magnetic field that opposes the change in the magnetic field through the wire.
As the magnetic field increases in the downward direction, the induced current will produce a magnetic field in the upward direction to oppose the increase. As the magnetic field decreases in the downward direction, the induced current will produce a magnetic field in the downward direction to oppose the decrease.
Therefore, the direction of the induced current will be counterclockwise.
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given the following distances between destination nodes, what is the minimum distance that connects all the nodes? from to distance 1 2 200 1 3 300 2 3 350 2 4 350 3 4 250 group of answer choices 850 900 750 100
The minimum distance between all nodes is 750.Straight lines are the shortest path between any two places. The formula for measuring distance can be used to get this distance.
What does "shortest path" mean?The goal of the shortest-route issue is to determine the shortest path between two points. Finding the shortest route between one network node and each of the other nodes is commonly required. The shortest-route method reduces the length of a network's path.
How is the minimum distance calculated?The formula for the distance between two points (x 1, y 1) and (x 2, y 2) is d = (x 2, x 1) 2 + (y 2, y 1) 2.
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During World War II, it was found that r, the radius of the shockwave produced during an atomic bomb explosion, depends on the energy released, W, the elapsed time, t, and the air density, .
The atomic bomb explosion, depends on the energy released, W, the elapsed time, t, and the air density which altogether lead to the vaporisation of the contents within the mushroom cloud created.
What is an atomic bomb?An atomic bomb is type of nuclear weapon that releases a vast amount of energy upon explosion in the form of fission reaction.
During an explosion of atomic bomb, a cloud of mushroom fire is formed which vaporises anything found within it. The extent of destruction depends on:
energy released, W, the elapsed time, t, and the air density.Therefore, the atomic bomb explosion, depends on the energy released, W, the elapsed time, t, and the air density which altogether lead to the vaporisation of the contents within the mushroom cloud created.
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The data points you have taken on your lab graphs roughly form a straight line. How do you interpret the slope of this line?
Steeper slopes mean higher speeds.
Steeper slopes mean lower speeds.
Steeper slopes mean higher error.
Steeper slopes mean lower error.
The slope has no relation to speed or error
Answer: Steeper slopes mean lower speeds.
Explanation:
which action would a chemist most likely take to determine how substances in a fuel affect the types
Which formula describes
acceleration?
O m/s
O m²
O m/s²
O s/m
Answer:
the answer is the formula of acceleration is m/s²
A spacecraft is traveling with a velocity of Vox-5690 m/s along the +x direction. Two engines are turned on for a time of 865 s. One
engine gives the spacecraft an acceleration in the +x direction of a, 1.45 m/s², while the other gives it an acceleration in the ty
direction of a, -8.66 m/s2. At the end of the firing, what is a) v, and b) vy?
(a) Number i
(b) Number
Units
Units
For a spacecraft is traveling with a velocity of Vox-5690 m/s:
(a) The final velocity (v) is approximately 685.25 m/s.(b) The vertical component of the velocity (vy) is -7484.9 m/s.How to calculate velocity and vertical component?To solve this problem, use the equations of motion to calculate the final velocity and the vertical component of the velocity. Assume that the initial velocity in the y-direction is zero.
Given:
Initial velocity in the x-direction (V₀ₓ) = -5690 m/s
Time of engine firing (t) = 865 s
Acceleration in the x-direction (ax) = 1.45 m/s²
Acceleration in the y-direction (ay) = -8.66 m/s²
(a) To calculate the final velocity (v), use the equation:
v = V₀ₓ + ax × t
Substituting the values:
v = -5690 m/s + 1.45 m/s² × 865 s
v = -5690 m/s + 1254.25 m/s
v ≈ 685.25 m/s
Therefore, the final velocity (v) is approximately 685.25 m/s.
(b) To calculate the vertical component of the velocity (vy), use the equation:
vy = ay × t
Substituting the values:
vy = -8.66 m/s² * 865 s
vy = -7484.9 m/s
Therefore, the vertical component of the velocity (vy) is -7484.9 m/s.
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which of the following changes to a reaction system in equilibrium would affect the value of the equilibrium constant keq, for the reaction? (assume in each case all other variables are held constant)
If you alter the pressure in the system, equilibrium constants remain unchanged. A temperature change is the sole factor that can alter an equilibrium constant.
Even if you alter the system's pressure, equilibrium constants remain unchanged. A change in temperature is the sole factor that can alter an equilibrium constant. Increasing or decreasing the reactant's concentration or applying different pressures have no effect on the equilibrium constant.
Changes in the catalyst's concentration have no effect on it either.
Changes in temperature are the only variables that have an impact on the equilibrium constant. If a reaction is exothermic or endothermic, the outcome will differ.
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A flywheel accelerates uniformly at 10 rad/sec for 8 seconds starting from rest calculate A, its final angular velocity B, its average angular velocity C, its total displacement
The flywheel's entire displacement is 320 radians.
How do you calculate a flywheel's angular velocity?Strategy. The functional form of the flywheel's angular location is given in the problem as (t) = t (t) = t, allowing us to compute the angular velocity by taking the time derivative. Flywheel angular acceleration is given by the equation a = 12 - t, where an is measured in rad/sec2 and t is measured in seconds.
Initial angular velocity (ω1) = 0 rad/s
Angular acceleration (α) = 10 rad/s²
Time (t) = 8 s
ω2 = ω1 + αt
ω2 = 0 + 10 × 8
ω2 = 80 rad/s
The flywheel's final angular velocity is 80 rad/s as a result.
ωavg = (ω1 + ω2) / 2
ωavg = (0 + 80) / 2
ωavg = 40 rad/s
Hence, the flywheel's average angular velocity is 40 rad/s.
We may apply the next kinematic equation of rotational motion to determine the flywheel's overall displacement ():
θ = ω1t + (1/2)αt²
θ = 0 × 8 + (1/2) × 10 × 8²
θ = 320 rad
The flywheel's overall displacement is 320 radians as a result.
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Calculate forces and accelerations for a horizontal spring system. A 0.350 kg object attached to a spring of force constant 1.30 x 10 N/m is free to move on the frictionless horizontal surface. If the object is released from rest at x = 0.100 m, find the force on it and its acceleration at x = 0.100 m, x-0.0500m, x = 0. x= -0.0500m and x = -0.100 m.
The force and acceleration alter as the object moves away from its equilibrium position.
How to calculate force and acceleration?The force on the object at any point is given by Hooke's Law:
F = -kx
where F = force, k = force constant of the spring, and x = displacement of the object from its equilibrium position.
The acceleration of the object at any point is given by Newton's Second Law:
a = F/m
where a = acceleration, F = force, and m = mass of the object.
Using these equations, calculate the force and acceleration at each of the specified points:
At x = 0.100 m:
F = -kx = -(1.30 x 10 N/m)(0.100 m) = -0.130 N
a = F/m = (-0.130 N)/(0.350 kg) = -0.371 m/s² (the negative sign indicates that the acceleration is in the opposite direction to the displacement)
At x = 0:
F = -kx = -(1.30 x 10 N/m)(0) = 0 N (the spring is at its equilibrium position)
a = F/m = 0 N/0.350 kg = 0 m/s²
At x = -0.0500 m:
F = -kx = -(1.30 x 10 N/m)(-0.0500 m) = 0.065 N (note that the force is positive because the displacement is negative)
a = F/m = (0.065 N)/(0.350 kg) = 0.186 m/s²
At x = -0.100 m:
F = -kx = -(1.30 x 10 N/m)(-0.100 m) = 0.130 N
a = F/m = (0.130 N)/(0.350 kg) = 0.371 m/s²
So, the force and acceleration change with the displacement of the object from its equilibrium position.
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Which statement describes earthquakes?
They release energy
They are caused by reduced stress in rocks
They begin at the epicenter
The result for movement on earth’s surface
Answer:
they release energy
Explanation:
An earthquake is the abrupt release of energy from the earth's crust that causes the earth's surface to shake . Thus , seismic waves are produced. The kind and severity of an earthquake are based on the local seismic activity . therefore the correct answer is option A.
What is the equator?The Equator is an imaginary line passing through the middle of a globe. It is equidistant from the North Pole and the South Pole, Its is a horizontal line residing at 0 degrees latitude .
An earthquake is the abrupt release of energy from the earth's crust that causes the earth's surface to shake . Thus, seismic waves are produced. The kind and severity of an earthquake are based on the local seismic activity .
Thus, the correct answer is option A .
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There is a 247–m–high cliff at Half Dome in Yosemite National Park in California. Suppose a boulder breaks loose from the top of this cliff. What is the velocity of the boulder just before it strikes the ground?
Answer:
Vf = 69.61 m/s
Explanation:
We will use the third equation of motion to solve this problem:
\(2gh = V_{f}^2 - V_{i}^2\\\)
where,
g = acceleration due to gravity = 9.81 m/s²
h = height of cliff = 247 m
Vf = final velocity = ?
Vi = initial velocity = 0 m/s (boulder breaks loose from rest)
Therefore,
\((2)(9.81\ m/s^2)(247\ m) = V_{f}^2 - (0\ m/s)^2\\V_{f} = \sqrt{4846.14\ m^2/s^2}\\\)
Vf = 69.61 m/s
a 0.2 kg sample of water at 60.0°c is heated to water vapor at 140.0°c. how much heat was absorbed? the specific heat value of water is 4180 j/kgoc. the specific heat value of water vapor is 2020 j/kgoc. the latent heat of vaporization of water is 2.26 x 106 j/kg.
Heat absorbed = 1.05 x 105 J.
Heat absorbed = (mass x specific heat x change in temperature) + (mass x latent heat of vaporization)
Heat absorbed = (0.2 kg x 4180 J/kg°C x (140.0°C - 60.0°C)) + (0.2 kg x 2.26 x 106 J/kg)
Heat absorbed = 59.7 x 104 J + 45.2 x 104 J
Heat absorbed = 1.05 x 105 J
What is vaporization?
Vaporization is the process of a liquid or solid changing into a vapor or gas. It occurs when enough energy is supplied to the molecule to overcome the attractive forces, allowing them to break away from the liquid or solid and form a gas. Vaporization can occur due to heating, pressure, or chemical reactions and can be used in many applications such as distillation and sterilization.
Therefore, Heat absorbed = 1.05 x 105 J.
To learn more about vaporization
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A motor can output 194.4 W of power. How many joules of work has it done if it runs for 1.56 minutes?
Answer:
303.264
Explanation:
Work=Power x time
Work=194.4 x 1.56
Work=303.264
Explanation:
Power= Work/ time
Work = Power×time
but SI unit for time is seconds
Changing 1.56 minutes to seconds,
1.56×60= 93.6 s
this implies that, Work = 194.4 × 93.6
= 18195.84J
3. A 1.23 kg object slides down a 1.25 m incline of 35º. Use the data table to construct a graph for force due to gravity vs. distance. Trial 1 Trial 2 Trial 3 Averages Distance (m) 1.25 1.32 1.28
4. Based on the graph in #3, calculate the work done by gravity. Assume work is constant for this data.
5. Using the data from #3, construct a free body diagram and calculate work done by gravity. Explain how this value compare to the value determined graphically in #4.
Remember that this object is on an angle. You'll need to multiply the value for work by cos0
Keep in mind that you'll need to use the angle that forms between the force of gravity and distance.
Answer:
Explanation:
To construct a graph of force due to gravity vs. distance, we need to collect data for force due to gravity (Fg) and distance (d) and plot the data points on a graph. From the information given, we have the mass of the object (1.23 kg) and the angle of the incline (35º), but we do not have any data for force due to gravity or distance. Without this data, it is not possible to construct a graph for force due to gravity vs. distance.
Since we don't have the data for force due to gravity or distance, it's not possible to calculate the work done by gravity using the data table.
Without the data for force due to gravity, distance, or time it's not possible to construct a free-body diagram or calculate work done by gravity. Also, we don't have the angle of the incline, so we cannot calculate the work done by gravity by multiplying it by the cosine of the angle.
It's important to note that work done by gravity (W) = force due to gravity (Fg) x distance (d) x cos(theta), where theta is the angle between the force of gravity and the distance.
It's also important to remember that work is a scalar quantity and not a vector, and it's the angle between the force and the displacement that is important to calculate the work done by gravity, not the angle of the incline.