What does a lighting bolt and getting shocked by a doorknob have in common?

Answer:

30.5m

Explanation:

D = 12+3.5+15

= 30.5m

Answer:

The people's reliance on the environment's resources generated a deep practical and spiritual link between them and it.

Explanation:

Answer:

A -- Correct (what you have on the paper)

B -- (Sphere A - negative 6 ) (Sphere B - negative 6) (Sphere C - positive 9)

(Total - negative 3)

Explanation:

Hope this helps! Please let me know if you need more help, or if you think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!

Answer:

Explanation:

a. Total charge = sum of charges of A, B and C

= -4 + -8 + 9

= -3.0C

b. After touching each other, the charges on A and B will equalized. When separated, they have the same charge = (-4 + -8) / 2 = -6.

Charge on C and the total charge will not change.

A : -6.0C

B : -6.0C

C : +9.0C

Total : -3.0C

1: Average tangential acceleration = (12 m/s - 0 m/s) / 3.3 s ≈ 3.64 m/s²

2: radius = 3.64 m/s² / 11 rad/s² ≈ 0.331 m

3: θ = 0.5 * 11 rad/s² * (3.3 s)² ≈ 59.67 radians

4: The ant has traveled approximately 19.78 meters along the arc of the tire during the given time interval.

1: The average tangential acceleration of the tire can be determined using the formula:

Average tangential acceleration = (final tangential velocity - initial tangential velocity) / time

Given that the ant's speed increases from zero to 12 m/s in 3.3 seconds, the initial tangential velocity is 0 m/s and the final tangential velocity is 12 m/s. Plugging these values into the formula, we get:

Average tangential acceleration = (12 m/s - 0 m/s) / 3.3 s ≈ 3.64 m/s²

2: The radius of the tire can be determined using the formula:

Average tangential acceleration = rotational acceleration * radius

Given that the rotational acceleration of the wheel is 11 rad/s² and the average tangential acceleration is 3.64 m/s², we can rearrange the formula to solve for the radius:

radius = average tangential acceleration / rotational acceleration

Plugging in the values, we get:

radius = 3.64 m/s² / 11 rad/s² ≈ 0.331 m

3: The angle the ant has turned during this time interval can be calculated using the formula:

θ = 0.5 * rotational acceleration * (time)²

Plugging in the given values, we get:

θ = 0.5 * 11 rad/s² * (3.3 s)² ≈ 59.67 radians

4: The distance the ant has traveled along the arc during this time interval can be calculated using the formula:

Distance = radius * θ

Plugging in the values, we get:

Distance = 0.331 m * 59.67 radians ≈ 19.78 meters

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Yes, that is correct. The three types of voltage indicators/testers discussed in this lesson are:

1. Digital multimeter (DMM) type voltage tester: This type of voltage tester measures the voltage level using a digital multimeter and provides an accurate reading of the voltage level.

It can also measure other electrical properties like resistance and current.

2. No contact voltage indicator: This type of voltage tester detects the presence of voltage without making any physical contact with the electrical circuit or conductor. It typically uses an LED or audible alarm to indicate the presence of voltage.

3. Solenoid type voltage tester: This type of voltage tester uses a solenoid (electromagnet) to detect the presence of voltage. When the solenoid is exposed to voltage, it creates a magnetic field that causes a needle to move, indicating the presence of voltage.

This type of tester is commonly used for testing high-voltage circuits.

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Answer:

The answer is four hundred twenty six or 426

Answer:

426

Explanation:

Answer:

30 cm to 1 mm

Explanation:

30 cm to 1 mm

The wavelengths of sound that carry farther in air are relatively long.

In general, longer wavelengths tend to propagate or carry farther in air compared to shorter wavelengths. This is because longer wavelengths experience less attenuation or loss of energy as they travel through the air. They are less affected by factors such as scattering, diffraction, and absorption, allowing them to travel greater distances.On the other hand, shorter wavelengths are more prone to scattering and absorption by particles in the air, as well as obstacles in the environment. As a result, they tend to dissipate and lose energy more quickly, limiting their effective range of propagation.Therefore, when it comes to sound carrying farther in air, the relatively longer wavelengths are more advantageous.

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Answer:

Compound that consist of ions joined by electrostatic forces are called Ionic Compound....

Answer:

D. All of the above

Explanation:

Because it's the most logical answer.

Answer:

1.) The 1ˢᵗ three term is (-32), (-7) and 18

2.) The 1ˢᵗ three term is 127, 106 and 85

Step-by-step explanation:

Here,

First Term = a₁ = - 32

Common Difference = (d) = 25

Now, For 1ˢᵗ three term,

n = 1

a₁ = - 32

n = 2

aₙ = a + (n - 1)d

a₂ = (-32) + (2 - 1) × 25

a₂ = (-32) + 1 × 25

a₂ = (-32) + 25

a₂ = -7

n = 3

aₙ = a + (n - 1)d

a₃ = (-32) + (3 - 1) × 25

a₃ = (-32) + 2 × 25

a₃ = (-32) + 50

a₃ = 18

Thus, The 1ˢᵗ three term is (-32), (-7) and 18

Here,

First Term = a₁ = 127

Common Difference = (d) = -21

Now, For 1ˢᵗ three term,

n = 1

a₁ = 127

n = 2

aₙ = a + (n - 1)d

a₂ = 127 + (2 - 1) × (-21)

a₂ = 127 + 1 × (-21)

a₂ = 127 - 21

a₂ = 106

n = 3

aₙ = a + (n - 1)d

a₃ = 127 + (3 - 1) × (-21)

a₃ = 127 + 2 × (-21)

a₃ = 127 - 42

a₃ = 85

Thus, The 1ˢᵗ three term is 127, 106 and 85

-TheUnknownScientist

Thermohaline circulation is the part of the scale ocean circulation. This circulation takes place due to the global density gradient which is due to the surface heat. The thermohaline circulation begins at the Earth's polar region.

Thus, the thermohaline circulation takes place at the polar region on the surface.

Hence, the answer is true.

The he nickel has a greater density than the penny and quarter because it has the greater mass to volume ratio.

Density is the ratio of the mass and volume of a substance.

Density measures the compactness of the particles of a substance.

When comparing the density two objects of equal volume, the denser objects will have more mass or weight.

The model hypothesis is as follows:

If the nickel has a greater density than the penny and quarter, then it will have a greater mass to volume ratio. If the penny has a lower density than the nickel and quarter, then it will have a lower mass to volume ratio.

By taking measurements of the mass and volume of the nickel, penny and quarter, it will be observed that the nickel has the higher mass to volume ratio. Hence, nickel has a greater density than the penny and quarter.

In conclusion, the density of a substance is the mass and volume ratio of that substance.

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Answer:

A microwave

Explanation:

Car

Lightbulb is a really good one

Same with the sun. That one has Chemical as well

Answer:

A stove

Explanation:it transfers heat

Answer: hello i am a hacker

Explanation:

magnesium sulphate=(24*1)+(32*1)+(16*4)=120                                                             water=H2O=(1*2)+(1*16)=18                                                                                                        carbon dioxide=CO2=(12*1)+(16*2)=44                                                                                     ammonia=NH3=(14*1)+(1*3)=17                                                                                                   alminiumsulphate=AL2(SO4)3=(26*2)+(32*3)+(12*16)=340                                                          hydrogen peroxide=H2O2=(1*2)+(16*2)=34                                                              zinc sulphate=ZNSO4=(65*1)+(32*1)+(16*4)=161

Electricity is defined as the flow of electrical current through a conductor.

A fundamental type of energy that is produced by the presence and movement of electric charge is electricity. The passage of electrons or other charged particles across a conductor, like a wire, is what defines the phenomena. It includes the creation, transmission, and use of electric energy, as well as the full field of electric phenomena.

Therefore,

Electricity is defined as the flow of electrical current through a conductor.

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In this case, as described in the question, the spring is exerting a force. The spring exerts a force to the right on the hand.

When a spring is compressed or stretched, it exerts a restoring force in the opposite direction to return to its equilibrium position. To determine the direction of the force exerted by the spring, we need to consider Newton's third law of motion, which states that every action has an equal and opposite reaction.

The force exerted by the spring on the hand is the reaction force to the force exerted by the hand on the spring. Since the hand is pushing or pulling the spring, the force exerted by the hand on the spring is directed to the right.

According to Newton's third law, the reaction force exerted by the spring on the hand is equal in magnitude but opposite in direction. Therefore, the spring exerts a force to the left on the hand.

In summary, the spring exerts a force to the left on the hand.

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The minimum radius of the circle is 5249m

The 76kg pilot's effective weight at the bottom of the circle is 5214N

The pilot's effective weight at the top the circle is 3724N

Here's the complete question:

a jet pilot takes his aircraft in a vertical loop.

a) if the jet is moving at a speed of 2000 km/h at the lowest point of the loop, determine the minimum radius of the circle so that the centripetal acceleration at the lowest point does not exceed 6.0g's

b) calculate also the 76kg pilot's effective weight ( the force with which the seat pushes up on him) at the bottom of the circle.

c) calculate the pilot's effective weight at the top the circle. (Assume the same speed.)

a) To determine the minimum radius of the circle so that the centripetal acceleration at the lowest point does not exceed 6.0g's.

v =2000 km/h

v = 2000/3.6 m/s

v = 555.6 m/s

centripetal acceleration, a

a = v²/r

Therefore

6g = v²/r

r = v²/(6g)

r =555.6²/(6*9.8)

r = 5249 m

b) The 76kg pilot's effective weight at the bottom of the circle

   76*(6g + g) = 76*7*9.8 = 5214 N

c) The pilot's effective weight at the top the circle.

    76*(6g-g) = 76*5*9.8 = 3724 N

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1,000 watts of power consumed for one hour is equivalent to 3,412 BTUs of energy.

Watts and BTUs (British Thermal Units) are two common units of power and energy, respectively. Watts are commonly used to measure electrical power, while BTUs are used to measure thermal energy. To convert watts to BTUs, you need to consider the amount of time over which the power is being generated or consumed. Here are the steps to convert watts to BTUs:

Therefore, 1,000 watts of power consumed for one hour is equivalent to 3,412 BTUs of energy. This conversion is important when comparing the energy consumption or device output that use different units of measurement for power and energy.

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Answer:

the time of motion of the ball is 6.89 ms.

Explanation:

Given;

angular speed, ω = 38 rad/s

angular distance, θ = 15 degrees

Angular distance in radian;

\(\theta = 15^0 \times\frac{2\pi \ rad}{360^0} = 0.2618 \ rad\)

Time of motion is calculated as;

\(time = \frac{angular \ distance}{angular \ speed} \\\\t= \frac{\theta}{\omega} = \frac{0.2618 \ rad}{38 \ rad/s} \\\\t = 6.89 \ \times 10^{-3} \ s\\\\t = 6.89 \ ms\)

Therefore, the time of motion of the ball is 6.89 ms.

To calculate the Taguchi quality cost, we need to multiply the length of each piece by the Taguchi parameter T, and then sum up the costs.

Given:

Length of the first metal rod = 49.19 cm

Length of the second metal rod = 49.93 cm

a) Taguchi parameter T:

Since we don't have the specific value of T, we cannot calculate it.

b) Taguchi Quality Cost of the second metal rod:

Taguchi Quality Cost = Length of the second metal rod * Taguchi parameter T

c) Taguchi Quality Cost of the first metal rod:

Taguchi Quality Cost = Length of the first metal rod * Taguchi parameter T

d) Total Taguchi Quality Cost of the two units:

Total Taguchi Quality Cost = Taguchi Quality Cost of the first metal rod + Taguchi Quality Cost of the second metal rod

Since we don't have the Taguchi parameter T, we cannot calculate the specific values for parts (b), (c), and (d).

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Strong storms and hurricanes are the consequences of how the Earth is heated by the sun.

The upper troposphere becomes warmer as the lower stratosphere warms. When the troposphere and the planet's surface are at opposite temperatures, significant updrafts result, which intensifies storms and hurricanes. Updrafts and storm power are diminished during the height of the 11-year solar cycle.

Troposphere, stratosphere, mesosphere, and thermosphere are the layers of the atmosphere. The stratosphere, which contains the ozone layer, is the part of the Earth's atmosphere that is most affected by the sun. The stratosphere, which is where weather happens, is followed by the troposphere.

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Answer:

False

Explanation:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.

Only one star will be visible. Two stars are 0.1 arcseconds apart, and you use a telescope with a 1 arcsecond angular resolution to take pictures of them.

At radio frequencies, light pollution is more severe than at visible wavelengths. To improve their effectiveness, modern telescopes employ cutting-edge technology. Another slim triangular relation, b = s/fe, provides the angle as the apparent angular size of the pictures as seen via a magnifying lens. Just 206 * (pixel size) / pixels make up the scale (focal length). If your 30 mm guide scope is f/4, then the focal length would be 120 mm. The pixel scale for a typical guide camera, such as the ASI120MM, which has 3.8u pixels, is 206 * 3.8 / 130 = 6.0 arcseconds/pixel.

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Answer: There'll be just one star to see. You use a telescope with a 1-arcsecond angular resolution to snap photos of two stars that are 0.1 arcseconds apart.

Explanation: Compared to visible wavelengths, light pollution is worse at radio frequencies. The most recent technology is used by modern telescopes to increase their efficacy. The angle is given by another thin triangle relation, b = s/fe, which also gives the apparent angular size of the images when viewed via a magnifying glass. The scale is made up of only 206 * (pixel size) / pixels (focal length). The focal length would be 120 mm if your 30 mm guide scope were to be set at f/4. The ASI120MM guiding camera, which has 3.8u pixels, has a pixel scale of 206 * 3.8 / 130, or 6.0 arcseconds/pixel.

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A typical voltage for running an agarose DNA gel would be in the 4 - 10 volts/cm under horizontal electrophoretic conditions.

Agarose gel electrophoresis is a method of gel electrophoresis used in biochemistry, molecular biology, genetics, and clinical chemistry to separate a mixed population of macromolecules such as DNA or proteins in a matrix of agarose, one of the two main components of agarose.

Agarose is a natural polymer prepared from seaweed (red algae) and consists of the D-galactose and 3,6-anhydro-L-galactose.

Why agarose gel is used for DNA?

Agarose's high gel strength allows for the handling of low percentage gels for the separation of large DNA fragments.

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The speed of the Toyota at impact can be calculated using kinetic friction  which is equal to 7.9 m/s

The speed of the Toyota at impact can be calculated using the coefficient of kinetic friction.

The equation for the speed is: speed = √(2fμd), where f is the force of the impact, μ is the coefficient of kinetic friction, and d is the distance that the cars skid.

In this case, the force of the impact can be calculated by multiplying the masses of the two cars together, which comes to

4.4 x 10³ kg. With μ = 0.4 and d = 2.8 m

The speed of the Toyota at impact can be calculated to be 7.9 m/s.

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Answer:

⭐. cryptogams ( non-flowering & non-seed bearing)

⭐. phanerogams ( flowering & seed bearing)

Answer:

could and largejsjisj and we look like they can get to

The automaker that famously ran an ad campaign calling its car a "lemon" was Volkswagen (VW).

In the 1960s, the German car manufacturer, in collaboration with the renowned advertising agency Doyle Dane Bernbach (DDB), created a series of advertisements to promote their VW Beetle in the United States.

The "Lemon" ad campaign, which first appeared in 1960, was designed to highlight Volkswagen's dedication to quality control and rigorous inspection processes. The term "lemon" in this context referred to a faulty car. By using the term in a self-deprecating manner, VW sought to emphasize that even if one of their cars had minor flaws, it would never make it to the customer, as it would be caught during the inspection process.

This bold and unconventional approach to advertising was highly successful, as it managed to capture the attention of the American public and establish the Volkswagen brand as a reliable and trustworthy choice in the automotive market.

The "Lemon" ad campaign became an iconic example of creative advertising and is still studied and admired by marketing professionals to this day.

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