What do you think ,is the factor that this cultural distinction still exists or does not exist?

Taking into account the definition of molarity and molar mass, the mass of fructose contained in 125ml of a 0.500M fructose solution is 11.43 grams.

Molarity is a measure of the concentration, which indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

molarity= number of moles of solute÷ volume

Molarity is expressed in units moles/L.

The molar mass of substance is defined as its mass per unit quantity of substance. In other words, molar mass is the amount of mass that a substance contains in one mole.

In this case, you have:

Replacing in the definition of molarity:

0.500 M= number of moles of fructose÷ 0.125 L

Solving:

0.500 M× 0.125 L= number of moles of fructose

0.0635 moles= number of moles of fructose

Being the molar mass of fructose 180 g/mole, the mass of the compound can be calculated as:

mass= molar mass× number of moles of fructose

mass= 180 g/mole× 0.0635 moles

mass= 11.43 grams

Finally, the mass of fructose is 11.43 grams.

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The statement "Superficial zone chondrocytes can get compacted under physiological loading: a multiscale finite element analysis" is true.

Superficial zone chondrocytes are the most exposed to mechanical loading and are therefore at risk of being compacted under physiological loading. A multiscale finite element analysis can be used to model and predict the mechanical behavior of cartilage under physiological loading, allowing for a better understanding of the factors that affect its mechanical properties.

This means that chondrocytes in the superficial zone of cartilage are at risk of being compacted under the physiological loading that it experiences in everyday life. A multiscale finite element analysis can be used to model and predict the mechanical behavior of cartilage under physiological loading, allowing for a better understanding of the factors that affect its mechanical properties.

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Answer:

A. it allows results to be reviewed and reproduced by other scientists.

The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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The directions that are likely to result in a warmer earth are the directions 3, 5 and 6.

The term global warming has to do with the gradual rise in the temperature of the earth as a result of the re-radiation of infrared rays back to the earth. We know that greenhouse gases are able to trap the infrared rays from the sun and reradiate same to the surface of the earth and this ultimately leads to a warmer earth.

As such, if we look at the image closely, we can see that there is a reradiation of the rays to the earth in the directions 3, 5 and 6. It then follows that the directions that are likely to result in a warmer earth are the directions 3, 5 and 6.

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Where is ur question ⁉️

Answer:

To calculate the number of moles of copper, we first need to determine the mass of copper present in the sample:

Mass of copper = 159 g (mass of copper(II) oxide) - 127 g (mass of copper)

Mass of copper = 32 g

Now, we can use the molar mass of copper to calculate the number of moles:

Molar mass of copper = 63.55 g/mol

Number of moles of copper = mass of copper / molar mass of copper

Number of moles of copper = 32 g / 63.55 g/mol

Number of moles of copper = 0.504 mol

Therefore, there are 0.504 moles of copper in the sample.

Explanation:

Answer:

2-5

Explanation:

I just did it.

The oxidation numbers of the atoms in this reaction are 0 for Mg(s) and H in H₂, -1 for Cl in HCl, +1 for H in HCl and +2 for Mg in MgCl₂

An oxidation number is a number assigned to atoms in molecules to show the general distribution of the electrons.

Oxidation state or number helps us describe the transfer of electrons.

The oxidation number/state is also used to determine the changes that occur in redox reactions.

Overall, the oxidation number of an atom in a molecule is the charge that the atom would have if all polar covalent and ionic bonds resulted in a complete transfer of electrons from the less electronegative atom to the more electronegative one.

Therefore, The oxidation numbers of the atoms in this reaction are 0 for Mg(s) and H in H₂, -1 for Cl in HCl, +1 for H in HCl and +2 for Mg in MgCl₂

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Explanation:

here's the answer to your question

The answer is True

Explanation:

Hope this helps

1.       Name the non-metal furthest to the left on the periodic table by its elemental name.

2.       Name the other non-metal by its elemental name and an -ide ending.

3.       Use the prefixes mono-, di-, tri-.... to indicate the number of that element in the molecule.

4.       If mono is the first prefix, it is understood and not written

Answer:

Rules for naming simple covalent compounds:

1.    Name the non-metal furthest to the left on the periodic table by its elemental name.

2.   Name the other non-metal by its elemental name and an -ide ending.

3.    Use the prefixes mono-, di-, tri-.... to indicate the number of that element in the molecule.

4.  If mono is the first prefix, it is understood and not written

Examples:

Here is a chart of those prefixes:

1 - mono

2 - di

3 - tri

4 - tetra

5 - penta

6 - hexa

7 - hepta

8 - octa

9 - nona

10 - deca

Answer:

concentration is the abundance of a constituent divided by the total volume of a mixture.

Explanation:

hope this helps <33

have a good afternoon:)

and also can i have brainliest plz? :D

Answer:

Cl (Chlorine) has higher electron affinity or electron gain enthalpy as compared to F(Fluorine) as though F is most electronegative in the whole periodic table and so has the highest tendency to attract electrons

Explanation:

Answer:

False

Explanation:

Water vapour exists in gas phase!

Approximately 70.57 mL of 1.00 M NaOH should be added to 250 mL of 0.50 M CH3CO₂H to produce a buffer with a pH of 4.50.

To determine the volume of 1.00 M NaOH required to produce a buffer with a pH of 4.50 when added to 250 mL of 0.50 M CH3CO₂H, we need to consider the Henderson-Hasselbalch equation and the stoichiometry of the reaction.

The Henderson-Hasselbalch equation for a buffer solution is given as:

pH = pKa + log([A-]/[HA])

In this case, CH3CO₂H (acetic acid) acts as the weak acid (HA) and CH3COO- (acetate ion) acts as its conjugate base (A-). We are given that the desired pH is 4.50, and we can determine the pKa value for acetic acid from reference sources, which is approximately 4.75.

Using the Henderson-Hasselbalch equation, we can rearrange it to solve for the ratio [A-]/[HA]:

[A-]/[HA] = 10^(pH - pKa)

[A-]/[HA] = 10^(4.50 - 4.75) = 10^(-0.25) = 0.5623

This means that the ratio of the acetate ion to acetic acid in the buffer solution should be approximately 0.5623.

To calculate the required volume of NaOH, we need to consider the stoichiometry of the reaction. Acetic acid reacts with hydroxide ions (OH-) to form acetate ions and water:

CH3CO₂H + OH- → CH3COO- + H2O

The stoichiometric ratio between acetic acid and hydroxide ions is 1:1. Therefore, the volume of 1.00 M NaOH needed can be calculated using the equation:

Volume (NaOH) × 1.00 M = Volume (CH3CO₂H) × 0.50 M × 0.5623

Volume (NaOH) = (Volume (CH3CO₂H) × 0.50 M × 0.5623) / 1.00 M

Volume (NaOH) = (250 mL × 0.50 M × 0.5623) / 1.00 M

Volume (NaOH) ≈ 70.57 mL

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Answer:

0.0104 moles of gas in the flask.

Explanation:

To calculate the number of moles of gas in the flask, you can use the ideal gas law equation: PV = nRT. Where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant and T is temperature.

First, you need to convert the pressure from mmHg to atm and the temperature from Celsius to Kelvin. The pressure in atm is 760.0 mmHg / 760 mmHg/atm = 1 atm. The temperature in Kelvin is 17.00°C + 273.15 = 290.15 K.

Next, you need to convert the volume from mL to L. The volume in L is 250.0 mL / 1000 mL/L = 0.2500 L.

Now you can plug all the values into the ideal gas law equation and solve for n: (1 atm)(0.2500 L) = n(0.08206 L·atm/mol·K)(290.15 K). Solving for n gives n = 0.0104 mol.

So there are approximately 0.0104 moles of gas in the flask.

Answer:

Scientists noticed that the mass of atoms was (usually) in excess of the known mass of protons present in those elements.

The discovery of neutral particles in the nuclei of atoms is attributed to Ernest Rutherford in 1920.

Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

Answer:

C because they are the same

Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\\)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{3.01 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{3.01}{6.02} \\ = 0.5\)

We have the final answer as

Hope this helps you

Answer:

D is the answer, 4 times 10 is 40

a) Step 1 - We need to balance the equation:

MO2 (s) 4 HCl (aq) -> MCl2 (aq) + Cl2 (g) + 2 H2O(l)

Reactant side:

M - 1

O - 2

H - 4

Cl - 4

Product side

M - 1

O - 2

H - 4

Cl - 4

Step 2 - We need to transform 0.20 grams of MO2 into moles using the following formula: mole = mass/molar mass

mass = 0.20 g

molar mass = 87 g/mol

mole = 0.002299

0.002299 moles of MO2

Step 3 - let's transform mL into L and then transform 0.15 M = 0.15 mol/L into moles.

1000 mL = 1 L

25 mL = 0.025 L

0.15 moles --- 1 L

x --- 0.025 L

x = 0.00375 moles

0.00375 moles of HCl

Step 4 - Let's see the proportion of the equation and compare with the real value of moles

1 mole of MO2 reacts with 4 moles of HCl

So:

1 MO2 --- 4 HCl

0.002299 MO2 --- x

x = 0.00919 moles of HCl

1 MO2 --- 4 HCl

x MO2 --- 0.00375

x = 0.0009375 moles of MO2

We should have 0.00919 moles of HCl reacting with 0.002299 moles of MO2, but we have just 0.00375. It means that the limiting reactant is HCl.

a) HCl is the limiting reactant.

b) Step 1 - We first need to find the atomic mass of M. For this, we know that molar mass of O is 16 and the molar mass of MO2 is 87.

So:

M + (2x16) = 87

M = 87 - 32

M = 55 g/mol

molar mass of M is 55 g/mol.

Step 2 - Now we need to find the molar mass of MCl2:

(1x55) + (35.45 x 2) = 125.9 g/mol

Step 3 - Now we use the equation proportion to find the quantity in moles of MCl2 produced:

1 mole of MO2 produces 1 mole of MCl2

0.0009375 moles of MO2 produces 0.0009375 moles of MCl2

Step 4 - Transform moles of MCl2 into grams:

125.9 g --- 1 mol

x --- 0.0009375 moles of MCl2

x = 0.118 grams

b) Mass of MCl2 produced is 0.118 grams.

c) To calculate the percentage yield we use the following formula:

Percent yield = (actual yield / theoretical yield) x 100%

actual yield = 0.078

theoretical yield = 0.118

Percent yield = (0.078 / 0.118) x 100%

c) Percent yield = 66%

Answer:

a) HCl is the limiting reactant.

b) Mass of MCl2 produced is 0.118 grams.

c) Percent yield = 66%

Answer:

Because Polar regions get less of the sun's direct rays, they are the coldest climates on Earth.

Explanation:

Explanation:

The half-life is the time taken for a radioactive substance to decay to half of its original composition.

    Let us assume that the original amount is x atoms;

                     Half - life   = 60days

Days                          Composition           Half-life number

0                                         x                                   0

60                                   x/2                                    1

120                                  x/4                                    2

180                                   x/8                                   3

240                                  x/16                                   4

300                                  x/32                                  5

360                                   x/64                                6

The fraction that would be left after 360 days will be \(\frac{1}{64}\)