what do you mean by MA of a lever is 3 , VR of a lever is 4 and efficiency of a machine is 60%​

Answer:

2 m/sec

Explanation:

speed = distance/time so v = 100/50 m/sec = 2 m/sec.

Answer:

129.6 seconds

Explanation:

Given that :

α = 0.0002°c-1​

θ1 = 20°C

θ2 = 5°C

Time t = one day ; Converting to seconds ; number of seconds in a day ; (24 * 60 * 60) = 86400 seconds

Let dT= change in time

Using the relation :

dT = 0.5* α * dθ * t

dθ = (20 - 5) = 15°C

dT = 0.5 * 0.0002 * 15 * 86400

dT = 129.6 seconds

Answer:

0%

Explanation:

There is no purple geneotype with either parents so there will be 0 purple and 100% white

The time elapsed between the first splash and the second splash is approximately 0.69 seconds.

To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.

We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.

For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).

Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.

Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.

For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.

Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.

To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.

Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.

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Answer:

Maximum Possible weight  = \(\frac{4}{3}\) HL\([\sqrt{\frac{H}{a} }\)] x 10,000 Newtons.

Explanation:

Solution:

Note: This question is incomplete, it lacks the sketch of the boat which is necessary to draw the volume equation. But I have found similar question and drawn the equation accordingly and solved the question.

In order to find the maximum possible weight for your boat and cargo,  we need to solve this definite integral equation of volume.

V = 2L\([Hx - \frac{ax^{3} }{3} ]^{\sqrt{\frac{H}{a} } }_{0}\)

With limits 0 and \(\sqrt{\frac{H}{a} }\)

Putting the Limits into the variable x, we will get.

V = 2L\([H\sqrt{\frac{H}{a} } - \frac{a(\sqrt{\frac{H}{a} } ^{3} }{3} ]\)

Solving the above equation further,

V = 2HL\([\sqrt{\frac{H}{a} } {\frac{3}{3} - \frac{1}{3} }\)]

V = 2HL\([\sqrt{\frac{H}{a} } {\frac{2}{3} }\)]

So, final equation of the volume after the integration is:

V = \(\frac{4}{3}\) HL\([\sqrt{\frac{H}{a} }\)]

Now, we know that Every cubic meter weighs 10,000 newtons. So,

Maximum Possible weight  = \(\frac{4}{3}\) HL\([\sqrt{\frac{H}{a} }\)] x 10,000 Newtons.

We have that the maximum possible weight for your boat and cargo  is mathematically given as

\(Maximum\ weight = \frac{4}{3}HL(\sqrt{H/a}) x 10,000 N\)

Question Parameters:

Every cubic meter of water weighs 10.000 newtons.

Generally the equation for the definite integral equation of volume  is mathematically given as

\(V = 2LHx-\frac{ax^3}{3}_0^{\sqrt{h/\alpha}}\\lim-->0 ,\sqrt{h/ \alpha}\\\\V = 2LH\sqrt{h/ \alpha}-\frac{a(\sqrtr{h/ \alpha})^3}{3}\\\\V = 2LH(\sqrt{h/ \alpha}*\frac{2}{3})\\\\V=\frac{4}{3}HL(\sqrt{H/a})\)

\(Maximum\ weight = \frac{4}{3}HL(\sqrt{H/a}) x 10,000 N\)

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The mass will stays the same because its a property of the ball that not change

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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Answer:

Explanation:

Without the FBD or a good description of the set up, I'd have to say we cannot tell.

If the set up is of the simplest form with a mass on a horizontal surface being acted on by a horizontal force, then that force must be 80 + 25 = 105 N.

As force is a vector, there are an infinite number of other possibilities for force magnitude depending on which direction the force is acting. The mass is also an unknown variable that would affect the applied force magnitude if the direction is not horizontal.

After pushing the pumpkin hard, you find yourself reversing direction at a speed of 4.0 m/s. 3.0 seconds after being pushed, the pumpkin will slide 12 m. Assume you weigh 60.0 kg.

We can use the conservation of momentum to solve this problem. After the push, the momentum of the system is given by:

p = (449 kg + 60 kg) * v

where v is the speed of the pumpkin and you after the push. Since you end up sliding backward at 4.0 m/s, we have:

v = -4.0 m/s

Substituting this into the expression for momentum, we find:

p = (449 kg + 60 kg) * (-4.0 m/s) = -2036 kg·m/s

The negative sign indicates that the momentum of the system is in the opposite direction of your motion.

During the sliding motion, the net force on the system is given by:

Fnet = (449 kg + 60 kg) * g * sin(θ)

where g is the acceleration due to gravity (9.81 m/s^2) and θ is the angle of the ramp. Since the ramp is smooth and horizontal, θ = 0 and Fnet = 0. Therefore, there is no net force to change the momentum of the system.

Using the equation for motion with constant acceleration, we can find the distance the pumpkin slides in 3.0 seconds:

x = x0 + v0t + (1/2)at²

Since the initial speed of the pumpkin is -4.0 m/s and there is no net force acting on it, its speed remains constant during the slide. Therefore, v0 = -4.0 m/s and a = 0. Substituting these values, we find:

x = x0 + v0t = (-4.0 m/s) * (3.0 s) = -12 m

The negative sign indicates that the pumpkin slides in the opposite direction to your motion. Therefore, the pumpkin slides 12 meters backward (i.e., towards you) in 3.0 seconds after the push.

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Answer:

molecule, a group of two or more atoms that form the smallest identifiable unit into which a pure substance can be divided and still retain the composition and chemical properties of that substance.Molecules are made up of atoms that are held together by chemical bonds. These bonds form as a result of the sharing or exchange of electrons among atoms. The atoms of certain elements readily bond with other atoms to form molecules. ... The atoms of some elements do not easily bond with other atoms. l

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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To model the discovery of electromagnetic induction, Tonya should use the procedure of moving a magnet into a coil of wire in a closed circuit.

Tonya should use the procedure of moving a magnet into a coil of wire in a closed circuit.

Electromagnetic induction refers to the phenomenon of generating an electric current in a conductor by varying the magnetic field passing through it. This concept was discovered by Michael Faraday in the early 19th century. To model this discovery, Tonya needs to recreate the conditions that led to this breakthrough.

In Faraday's experiment, he observed that when a magnet is moved into or out of a coil of wire, it induces an electric current in the wire. This occurs when the magnetic field passing through the coil changes. Therefore, Tonya should use a similar setup to replicate this process.

Out of the given options, the most appropriate procedure for Tonya would be to move a magnet into a coil of wire in a closed circuit. By having a closed circuit, it means that the ends of the wire are connected to form a complete loop. When the magnet is moved into the coil, the changing magnetic field induces an electric current to flow through the wire.

This procedure demonstrates the principle of electromagnetic induction and shows how a changing magnetic field can produce an electric current. It allows Tonya to visually observe the effects of the induced current, which is essential in modeling the discovery of electromagnetic induction.

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It takes approximately 9.05 seconds to roll the drum a distance of 36 meters.

We can use the formula for the circumference of a circle:

Circumference = 2 * π * radius

Given:

Radius (r) = 0.40 m

Circumference (C) = 2 * π * 0.40 m

We must figure out how many full rotations the drum makes to go 36 meters in order to calculate how long it takes to roll the drum. Since we are aware of the circumference, we can determine the number of full turns as follows:

Number of turns = Distance / Circumference

Given:

Distance = 36 m

Number of turns = 36 m / (2 * π * 0.40 m)

Now that we know how many turns there are, we can calculate the time by multiplying that number by the length of a turn, which is given as 8.0 seconds:

Time = Number of turns * Time per turn

Time = (36 m / (2 * π * 0.40 m)) * 8.0 s

By substituting the values into the equation, we can calculate the time:

Time = (36 / (2 * 3.14159 * 0.40)) * 8.0 s

Time ≈ 9.05 s

So, it takes approximately 9.05 seconds to roll the drum a distance of 36 meters.

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Answer:

A voltmeter measures the potential difference (or voltage) across a circuit element.

An ammeter measures the electric current across a circuit element.

Explanation:

This because a voltmeter is an electric device use to measure voltage or potential difference in a circuit. It is connected parallel to a device in the circuit. voltage is measure in volts.

An ammeter is an electric device that is use to measure currents in a circuit even to the smallest part of current. Current is measure in Ampere and ammeter is connected in direct series to a device in a circuit.

Answer:

a law stating that like charges repel and opposite charges attract, with a force proportional to the product of the charges and inversely proportional to the square of the distance between them.

Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.

In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.

The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.

A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.

Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.

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Answer:

D

Explanation:

The maximum height reached by a stone thrown straight up with an initial speed of 35 m/s can be found using the kinematic equation:

v^2f = v^2i - 2gh

where vf is the final velocity (0 m/s at the maximum height), vi is the initial velocity (35 m/s, the magnitude of the velocity with which the stone is thrown upwards), g is the acceleration due to gravity (-9.8 m/s^2), and h is the maximum height reached by the stone.

Rearranging the equation, we get:

h = (vi^2)/(2g)

Substituting the given values, we have:

h = (35 m/s)^2 / (2 * 9.8 m/s^2)

= 62.6 m

Therefore, the maximum height reached by the stone is approximately 63 m.

The answer is (d).

Since Two stars M1 and M2 of equal mass make up a binary star system.  their orbital speed is  2.69E4 m/s.

The orbital period of a binary star system is given by the equation:

T = 2 * pi * sqrt(a³ / (G * (M1 + M2)))

where T is the orbital period, a is the semi-major axis of the orbit (half of the distance between the two stars at their closest approach), G is the gravitational constant, and M1 and M2 are the masses of the two stars.

Substituting the given values into this equation, we get:

3.20 days = 2 * pi * sqrt(a³ / (6.67E-11 m³ kg^⁻¹ s^⁻² * (5.45 sm * 1.99E30 kg/sm + 5.45 sm * 1.99E30 kg/sm)))

Solving for the semi-major axis, we find that a = 2.11E11 m.

The speed of each star in the orbit can be found using the equation:

v = sqrt(G * (M1 + M2) / a)

Substituting the values we have calculated, we find that v = 2.69E4 m/s. This is the speed of each star in the orbit.

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The scientific study of all celestial objects is known as astronomy. Galaxies, planets, stars, comets, meteors, and other events affecting the celestial bodies are all observed and studied by astronomers.

The words "Astro," which means "star," and "nomos," which means "rule," are derived from ancient Greek. Astronomy, when combined, refers to "star law." The natural sciences are the ones that it is the oldest.

Since there are so many celestial objects to study, it is practical to divide astronomy into various branches.

Here are some of the more well-known astronomical fields-

1. Planetary Astronomy

2. Solar Astronomy

3. Stellar Astronomy

4. Galactic Astronomy

5. Observational Astronomy; etc.

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Explanation:

step 1. since the magnification is negative this means the object is real and is farther away from the lens than the focal point

step 2. 1/f = 1/o + 1/i where f is the focal length, o is the object distance from the lens and i is the image distance from the lens

step 3. 1/12 = 1/o + 1/i, -i/o = -2.5 (these are our 2 equations or system

step 4. 1/12 = 1/o + 1/2.5o

step 5. o = 12 + 12/2.5 = 16.8cm

step 6. i = 2.5o = 2 5(16) = 42cm

Answer:

4.80 seconds

Explanation:

The velocity of sound is obtained from;

V= 2d/t

Where;

V= velocity of sound = 329.2 ms-1

d= distance from the wall = 790.5 m

t= time = the unknown

t= 2d/V

t= 2 × 790.5/ 329.2

t= 4.80 seconds

The time is taken by the sound to reach the hiker will be  t= 4.80 seconds

The sound velocity is defined as the distance traveled by the sound wave in a particular direction with respect to time.

The velocity of sound  is given by the formula:

\(V=\dfrac{2d}{t}\)

Here;

V= velocity of sound = 329.2  \(\frac{m}{s^2}\)

d= distance from the wall = 790.5 m

t= time = the unknown

The time will be calculated as:

\(t=\dfrac{2d}{V}\)

\(t=\dfrac{2\times 790.5}{329.2}\)

\(t=4.80\ seconds\)

Hence the time is taken by the sound to reach the hiker will be  t= 4.80 seconds

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Explanation:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Answer:

11.5m/s

Explanation:

v=2.5

a=1.5

t=6s

vf=vi+at

vf=2.5+(1.5)(6)

vf=11.5

Answer:

dfsdfgsdfaefffsfffefefef

Explanation:

eg3g3gf3f3f3f3f3f3f3f3f3f3ggeg

Total Stopping Distance is the sum of the perception distance, reaction distance and braking distance.

The perception distance, response distance, and braking distance are added up to form the total stopping distance. Shortly after the motorist decides to slow down or stop, some time has passed. The response distance is the amount of time it takes to respond and enter the proper braking position.

If the surface is dry, a 4-second following distance, as depicted above in Area 1 of the space-management graphic, will allow you to maneuver or stop to safely avoid a danger on the roadway. You won't be able to avoid a collision if the car in front of you suddenly stops or slows down while you are following too closely.

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The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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Answer:

His general theory includes uniform and accelerated motion, but his special theory applies only to uniform motion.

Explanation:

According to Einstein's 1915 general theory of relativity, the force of gravity arises from the curvature of space and time.

According to theory of special relativity:

1. The laws of physics are the same for all non-accelerating observers

2. The speed of light in a vacuum was independent of the motion of all observers.

His general theory includes uniform and accelerated motion, but his special theory applies only to uniform motion.

Answer:

for those who dont like to read

the answer is A.

hope i helped

Explanation:

The mass of the Ball B is 1.35 x 10⁻⁶ kg.

Gravitational Force is described by Newton's law of universal gravitation, which states that the force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

The law of universal gravitation is important in many fields, including astronomy, physics, and engineering.

The gravitational force F between two objects of masses m1 and m2 separated by a distance r is given by:

F = G(m₁m₂)/r²

where G is the gravitational constant.

We can rearrange the equation to solve for the mass of Ball B:

m₂ = Fr²/Gm₁

Substituting the given values, we get:

m₂ = (8.7 x 10⁻¹⁰ N)(3.0 m)²/(6.6743 x 10¹¹ N(m^2/kg²))(30 N)

m₂ = 1.35 x 10⁻⁶ kg

Therefore, the mass of Ball B is approximately 1.35 x 10⁻⁶kg.

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