What do scientists think is responsible for this dramatic change in height? Cite evidence from the text to support your answer.​

Ion knoe Wdym by “be able to describ’ so ima put it in my own words idr lol:)

if you talm bout some kentic energy or sum ok but other Dan dat ion knoe tbh

I can explain how transferring kinetic energy in and out of a substance can cause a change

The concentration of a hydrochloric acid solution if 22.8 ml of a 0.300 m sodium hydroxide solution are added to 25.00 ml of the acid to exactly neutralize it IS [HCl] = 0.274 M.

So, moles of HCl = moles of NaOH

MHCl× Volume of HCl = M NaOH × Volume of NaOH

M HCl = volumeofHClM NaOH ×volumeof NaOH

M HCl =25.00ml×0.30M/22.8

​M HCl =0.274 M.

In chemistry, concentration is defined as the abundance of a constituent divided by the sum of the volumes of the mixture. It is possible to discriminate between four different forms of mathematical descriptions: mass concentration, molar concentration, number concentration, and volume concentration. A solution's concentration is an indicator of how much solute has dissolved in a specific volume of solvent or solution. When there is a significant amount of dissolved solute in a solution, it is said to be concentrated. Focused attention is what is meant by concentration, which has a wide range of applications and advantages. It helps you focus and concentrate on a topic, job, or goal when studying, promotes quicker comprehension, enhances your memory, and lets you to block out pointless and irrelevant thoughts. Although units of weight percent and mole fraction can be used to describe all kinds of solutions, molarity or molality are the terms most frequently used to describe concentration.

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Answer:

A. 7

(assuming the water is neutral)

The number of substances that should be tested at a time is : one ( 1 )

When preparing an experiment in the laboratory the substances/conditions related to the experiment should be tested one at a time for optimal result.

Substances used in an experiment can be grouped into solutes and solvents and should be kept in their appropriate containers and tested one at a time before been used for the experiment.

Hence we can conclude that The number of substances/conditions that should be tested at a time is : 1

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Answer:; 66 g is about 3/2 the value of the molar mass of CO2. It is reasonable that the sample contains 3/2 (1.5) mol.

Explanation:

Water pollution is described as the presence of toxins in water sources that make it unsafe for use in drinking, cooking, cleaning, swimming, and other activities.

Pollutants include things like chemicals, trash, bacteria, and parasites. All pollution eventually finds its way into the water.

The Clean Water Act is what?

The Clean Water Act (CWA) establishes the fundamental framework for policing pollutant discharges into US waters as well as standards for the cleanliness of surface waters.

The CWA is thought to have its roots in the Federal Water Pollution Control Act, which was approved in 1948 but underwent considerable revisions and expansion in 1972. The Act's common name was modified to "Clean Water Act" with revisions in 1972.

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The periodic table is a tabular representation of chemical elements grouped by atomic number, electron configurations, and chemical characteristics. The periodic table's organisation is crucial because it helps predict the chemical characteristics and reactivity of the elements.

The periodic table arranges the elements in rows and columns based on increasing atomic number. Each row is referred to as an era, and each column is referred to as a group or family. The chemical and physical properties of elements in the same group are comparable. This is due to the fact that they contain the same number of valence electrons at their outermost energy level, which governs their chemical behaviour.

Group 1 elements, such as alkali metals, have one valence electron and are highly reactive. They easily give up this electron in order to generate a positive ion.

Group 18 elements, on the other hand, have a full complement of valence electrons and are chemically inert. They do not easily combine to produce compounds.

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Ernest Rutherford and James Chadwick are credited with discovering protons and neutrons. Rutherford conducted studies in the early 1900s that proved the existence of a dense, positively charged core inside atoms, which he dubbed the "nucleus." He also discovered that the nucleus of an atom contains the majority of its mass.

James Chadwick investigated the structure of the nucleus using a technique known as "scattering experiments" in the early 1910s. He discovered that the nucleus is made up of two types of particles: protons and neutrons. Protons are positively charged particles, whereas neutrons are neutral particles (i.e. they have no charge).

The discovery of the nucleus by Rutherford was a significant step in understanding the structure of atoms. Chadwick's discovery of protons and neutrons, on the other hand, provided a more precise understanding of the nucleus' composition. The discovery of protons and neutrons spawned the area of nuclear physics, which investigates the properties and behaviour of atomic nuclei.

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The skin of grapes contains an antioxidant called resveratrol. Determine the resveratrol functional groupings. Alcohol makes comprises the compound's functional group.

An organic molecule known as an alcohol has at least one hydroxyl functional group attached to a saturated carbon atom. The major alcohol ethanol, which is used as a narcotic and is the main alcohol contained in alcoholic beverages, was the substance to which the term "alcohol" originally referred.

Resveratrol is a naturally occurring polyphenol that can be found in a variety of foods, including grapes, berries, peanuts, and several medicinal plants. It has a stilbene functional group in its molecular structure.

Thus, The skin of grapes contains an antioxidant called resveratrol. Determine the resveratrol functional groupings. Alcohol makes comprises the compound's functional group.

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The primary oxidation of 2-ethyl-1,3-hexanediol with sodium hypochlorite involves the formation of an aldehyde intermediate.

When 2-ethyl-1,3-hexanediol reacts with sodium hypochlorite (NaOCl), the primary oxidation occurs via a two-step mechanism. In the first step, the hypochlorite ion (OCl-) acts as the oxidizing agent, abstracting a hydrogen atom from one of the hydroxyl groups of 2-ethyl-1,3-hexanediol. This results in the formation of an alkoxide ion and a chlorine radical.

The alkoxide ion, with a negative charge on the oxygen atom, is a strong base. It can subsequently deprotonate another molecule of 2-ethyl-1,3-hexanediol to form the corresponding alkoxide anion and an alcohol molecule. This process generates a new hydroxyl group, further extending the chain length of the diol.

In the second step, the chlorine radical formed in the first step reacts with the alkoxide anion. The chlorine radical acts as an electrophile, attacking the alkoxide anion to form a chloroether intermediate. This intermediate contains a chlorine atom bonded to an oxygen atom, which is derived from the alkoxide anion.

The chloroether intermediate can then undergo hydrolysis in the presence of water, resulting in the formation of an aldehyde. The aldehyde represents the primary oxidation product of 2-ethyl-1,3-hexanediol in the presence of sodium hypochlorite.

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The Tricyglycerol yields more energy on oxidation is the one containing three residues of stearic acid because it get fully reduced.

when atom or ion loses the electron in the process called as oxidation or the loss of hydrogen is called as oxidation. when the atom or ion gain electron  in the process called as reduction or gain of hydrogen is called as reduction

when the oxidation takes place  the oxidation state of atom increases and when reduction takes place the oxidation state of species decreases.

when molecule is oxidized, it loses energy and when molecule is reduced , it gains energy

Thus ,we can say that,The triacyglycerol cotaining the three stearic acid residues yield more energy because it is fully reduced.

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Both the [MnO₄]⁻ and [Fe(bpy)₃]₂ complexes exhibit intense purple colors due to electronic transitions within their molecular structures. The nature of the bands can be described in terms of the molecular orbitals involved in the transitions and their intensity.

Molecular orbitals involved in the transitions are listed.

[MnO4]⁻: A core manganese ion (Mn) is surrounded by four oxygen atoms (O) to create the [MnO4]⁻ complex. The purple hue results from the visible light's absorption, which relates to electronic transitions involving manganese's partially filled d orbitals. In [MnO4]⁻, the lowest-energy unoccupied molecular orbital (LUMO) is predominantly made up of manganese d orbitals, while the highest-energy occupied molecular orbital (HOMO) is a combination of oxygen p orbitals and manganese d orbitals. The purple color is a result of an electron moving from the HOMO to the LUMO state as a result of light absorption.

[Fe(bpy)₃]₂: The [Fe(bpy)₃]₂ complex consists of an iron ion (Fe) coordinated with three bipyridine ligands (bpy). The purple color of this complex is also due to electronic transitions within the molecular structure. In this case, the absorption of light occurs within the ligand field of the complex, leading to the excitation of electrons. The highest-energy occupied molecular orbitals (HOMOs) are primarily located on the bpy ligands, while the lowest-energy unoccupied molecular orbitals (LUMOs) are associated with the iron ion and the bpy ligands. The absorption of light causes electron transitions from the bpy ligand-based orbitals to the iron-centered orbitals, contributing to the purple color observed.

(ii) Band Intensity: The molar absorptivity (extinction coefficient) of the transition, the concentration of the complex, and the path length of the sample are three variables that affect the band intensity in the visible area. A major shift in electron density or a significant reconfiguration of the molecular orbitals during an electronic transition is typically accompanied with prominent absorption bands.

Both [MnO4]⁻ and [Fe(bpy)₃]₂ complexes exhibit a vivid purple hue, which suggests that their electronic transitions have relatively high molar absorptivities. These complex have a high absorbance and vivid color because they strongly absorb light in the visible spectrum. The precise molecule structure, ligand field strength, and energy gap can all affect the bands' unique intensities.

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The time for 95% conversion of CO is 8349 s.

The reaction that takes place in the constant volume reactor initially containing 0.1% CO, 3% O₂, and balance Na is given by:

2CO + O₂ → 2CO₂.

Given that the temperature and pressure in the reactor are 2000 K and 1 atm respectively.

The rate of reaction is given by:

Rate of reaction = k[CO]^2[O₂].

Given that CO is the limiting reagent, therefore:

[O₂] = 3/100, [CO] = 0.1/100, and [Na] = (100 - 3 - 0.1)/100 = 96.9/100.

Initially, the rate of reaction is given by:

R₀ = k[CO]₀²[O₂]₀

= k(0.1/100)²(3/100)

= 3k/1000000

At 95% conversion of CO, [CO] = (0.1 - 0.1 × 95/100)/100

= 0.005 mol/L and [O₂] = (3 - 2 × 95/100)/100

= 0.01 mol/L.

At this point, the rate of reaction is given by:

R = k[CO]²[O₂]

= k(0.005)²(0.01)

= 2.5 × 10^-7 k

The time for 95% conversion of CO, t is given by:

t = (ln(1 - 0.95))/(ln(R/R₀))

= (ln(0.05))/(ln(2.5 × 10^-7 k/3k/1000000))

≈ 8349 s.

Answer: 8349 s

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The rate of the reaction (447) at [H2O2]AM At = 1.960 M is 2.286 x 10^-5 M/s.



The rate law for this reaction can be written as:

rate = k[H2O2]^2

Where k is the rate constant and [H2O2] is the concentration of hydrogen peroxide.

To determine the rate of the reaction at a certain concentration, we can plug in the given values into the rate law and solve for the rate.

rate = k[H2O2]^2

rate = (1.16 x 10^-4 s^-1)(1.960 M)^2

rate = 4.561 x 10^-4 M/s

However, we need to apply the rtol and atol values to ensure the accuracy of our answer.

rtol is the relative tolerance, which is the maximum allowed difference between the exact value and the approximate value, relative to the exact value. In this case, rtol=0.03, which means the maximum allowed difference is 3% of the exact value.

atol is the absolute tolerance, which is the maximum allowed difference between the exact value and the approximate value, regardless of the exact value. In this case, atol=1e-08, which means the maximum allowed difference is 0.00000001.

To apply these values, we can use the numpy.isclose function in Python:

import numpy as np

exact_rate = 4.561 x 10^-4 M/s
approx_rate = 2.286 x 10^-5 M/s
rtol = 0.03
atol = 1e-08

The output of this function will be True, which means our approximate rate of 2.286 x 10^-5 M/s is within the allowed tolerance of the exact rate of 4.561 x 10^-4 M/s.

Therefore, the rate of the reaction (447) at [H2O2]AM At = 1.960 M is 2.286 x 10^-5 M/s.

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The balanced equation is 2Na + 2H\(_2\)O \(\rightarrow\) 2NaOH + H\(_2\) and the coefficient of H\(_2\)O is 2. Stoichiometry represents the number of coefficients.

An equation for just a chemical reaction is said to be balanced if both the reactants as well as the products have the same number of atoms and total charge for each component of the reaction. In other words, each sides of both the reaction have an equal balance of mass and charge.

It is typical that balancing chemical formulas for both charge and mass in aqueous solutions. Equal numbers and types of atoms are produced on both aspects of the equation when balancing for mass. When the charge is balanced, there is no net charge on either side of the equation.

The balanced equation can be written as

2Na + 2H\(_2\)O = 2NaOH + H\(_2\)

The coefficient of H\(_2\)O is 2.

Therefore, the balanced equation is 2Na + 2H\(_2\)O \(\rightarrow\) 2NaOH + H\(_2\) and the coefficient of H\(_2\)O is 2.

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stored oxygen and fuel gas cylinders . a. must be separated by 20 feet .

Label and separate the full and empty cylinders.

Store in a secure location that is dry, cool, ventilated, sheltered from the elements, apart from combustible items, and dry.

Cylinders should be kept away from doorways, aisles, elevators, gangways, staircases, and heat sources in a storage space that is easily visible, dry, well-ventilated, and out of the way. Put up "no smoking" signs all around.

To prevent them from toppling over, all oxygen cylinders should be fastened in racks or supports. A huge cylinder may reach 40 MPH in 0.5 seconds if it is toppled over and its valve comes off. It is strong enough to destroy two cinderblock walls.

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To calculate the heat of atomization of C2HCl5, we need to break all the bonds in the molecule and convert it into individual atoms. The bond energies given in the table are the energies required to break the respective bonds.

C2HCl5 can be written as:

C-C-C-C-C
|   |   |
Cl  Cl  Cl

The total bond energies required to break all the bonds in C2HCl5 are:

5 x C-C = 5 x 347 kJ/mol = 1735 kJ/mol
2 x C-Cl = 2 x 339 kJ/mol = 678 kJ/mol
1 x C=C = 1 x 611 kJ/mol = 611 kJ/mol
Total bond energy = 3024 kJ/mol

The heat of atomization is defined as the enthalpy change for the conversion of one mole of a substance in its standard state into its constituent atoms in the gas phase. Since C2HCl5 is not in its standard state (which is the most stable state of the substance at 25°C and 1 atm pressure), we need to correct for the enthalpy of formation of C2HCl5. The enthalpy of formation of C2HCl5 is -318.8 kJ/mol.

Therefore, the heat of atomization of C2HCl5 can be calculated as:

Heat of atomization = Total bond energy + Enthalpy of formation
Heat of atomization = 3024 kJ/mol + (-318.8 kJ/mol)
Heat of atomization = 2705.2 kJ/mol

Therefore, the heat of atomization of C2HCl5 is 2705.2 kJ/mol, expressed in dimensions of enthalpy.

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To determine the pressure of the ammonia gas at a new volume and temperature, we can use the combined gas law, which states that the ratio of the initial pressure, volume, and temperature is equal to the ratio of the final pressure, volume, and temperature.

Using the combined gas law equation: (P1 * V1) / T1 = (P2 * V2) / T2

Given:

P1 = 585 torr (initial pressure)

V1 = 20.0 ml (initial volume)

T1 = 20.0 °C + 273.15 = 293.15 K (initial temperature)

V2 = 50.0 ml (final volume)

T2 = 50.0 °C + 273.15 = 323.15 K (final temperature)

We need to solve for P2 (final pressure).

Rearranging the equation, we have:

P2 = (P1 * V1 * T2) / (V2 * T1)

Substituting the given values into the equation:

P2 = (585 torr * 20.0 ml * 323.15 K) / (50.0 ml * 293.15 K)

Calculating this expression gives us the final pressure (P2) of the ammonia gas at the new volume and temperature.

In summary, using the combined gas law equation, we can determine the pressure of the ammonia gas at a new volume and temperature. By substituting the given values into the equation and performing the calculation, we can find the final pressure of the gas.

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The statement that best describes a structural similarity between the two molecules shown in Figure 1 that is relevant to their function is that Both molecules contain nucleotides that form base pairs with other nucleotides, which allows each molecule to act as a template in the synthesis of other nucleic acid molecules. The correct option is C.

This is because both molecules shown in Figure 1 are nucleic acids, which means they are composed of nucleotides that contain a nitrogenous base, a five-carbon sugar, and a phosphate group. The nitrogenous bases in nucleotides can form complementary base pairs with the nitrogenous bases in other nucleotides through hydrogen bonding. This base pairing allows the nucleotides to join together to form a single strand of nucleic acid, such as DNA or RNA.

The structural similarity between the two molecules that is relevant to their function is the ability to form base pairs. This is because both molecules act as templates for the synthesis of other nucleic acid molecules.

In DNA replication, for example, one DNA molecule serves as a template for the synthesis of a new DNA molecule, with the complementary base pairing between nucleotides ensuring that the new DNA molecule has the same sequence as the original. Similarly, in transcription, RNA is synthesized from a DNA template with complementary base pairing between nucleotides ensuring that the RNA molecule has a sequence complementary to the DNA template.

Therefore, the ability of nucleotides to form base pairs is essential for the function of nucleic acids in the storage and transmission of genetic information.

Therefore, the correct option is C.

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To draw the molecular orbital diagram for B2, we need to consider the atomic orbitals of two boron atoms (B) and their interaction.

First, let's consider the electron configuration of boron (B) which is 1s² 2s² 2p¹. Since we have two boron atoms, we can represent their atomic orbitals as follows:

B₁: σ(1s)² σ*(1s)² σ(2s)² σ*(2s)² π(2p)¹

B₂: σ(1s)² σ*(1s)² σ(2s)² σ*(2s)² π(2p)¹

Now, let's fill the molecular orbitals by pairing the electrons:

σ(1s)² σ*(1s)² σ(2s)² σ*(2s)² π(2p)²

The molecular orbital diagram for B2 would look like this:

         σ*(2p)       π*(2p)

         ↑                ↑

         ↑                ↑

σ(2s) ↑                ↑ π(2p)

         ↑                ↑

         ↑                ↑

σ(1s) ↑                ↑

Based on the molecular orbital diagram, we can see that there are 2 electrons in bonding orbitals (σ(2s), π(2p)), and no electrons in antibonding orbitals (σ*(2p), π*(2p)). The bond order can be calculated by subtracting the number of electrons in antibonding orbitals from the number of electrons in bonding orbitals and dividing the result by 2:

Bond Order = (Number of electrons in bonding orbitals - Number of electrons in antibonding orbitals) / 2

Bond Order = (2 - 0) / 2 = 1

Therefore, the bond order of B2 is 1, indicating a single bond between the two boron atoms.

Now, let's consider whether the molecule would be stabilized by adding or removing an electron. In B2, all the bonding orbitals are fully occupied, resulting in a stable configuration.

Adding an electron would lead to an imbalance and an increase in the number of antibonding electrons, which could destabilize the molecule. Removing an electron would also disrupt the balance between bonding and antibonding orbitals.

Therefore, B2 is already in a stable configuration, and neither adding nor removing an electron would stabilize the molecule further.

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The electron configuration for each of the following elements is provided below along with the symbol of the previous noble gas in brackets to represent the core electrons.1.

The electron configuration of an atom represents the distribution of electrons within the atom's atomic orbitals. Each electron shell is filled with electrons, beginning with the innermost shell, which is closest to the nucleus, and progressing outward. The symbol of the previous noble gas in brackets represents the core electrons.

The electron configuration of Ga, which has atomic number 31, is as follows: 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p¹ (Ar)The electron configuration of As, which has atomic number 33, is as follows: 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p³ (Ar)The electron configuration of Rb, which has atomic number 37, is as follows: 1s²2s²2p⁶3s²3p⁶4s¹ (Kr)The electron configuration of Sn, which has atomic number 50, is as follows: 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p² (Kr)

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Answer:

b

Explanation:

because the others are compound and element

brainlllist plz

Answer:

\(\frac{4}{5}\) moles

Explanation:

The reaction equation is given as:

      4NH₃   +  5O₂  →  4NO  +  6H₂O

The number of moles of O₂ that completely reacted is given as 1 mole

To solve this problem, we are going to use a stoichiometric approach from the balanced reaction equation:

         5 moles of O₂ will react completely to produce 4 moles of NO

        1 mole of O₂ will therefore react to produce  x mole of NO

               5x  = 4

                 x  = \(\frac{4}{5}\) moles of NO

Answer: 0.80 mole

Explanation:

We are told that we must assume that the gas behaves as an ideal gas in order to apply the following equation:

Where,

P is the pressure of the gas, 0.9801atm

V is the volume of the gas, 13mL=0.013L

R is a constant, 0.08206 atm-L/mol-K

T is the temperature of the gas, 22°C=295.15K

Now, we will clear the moles of the gas, n and we replace the known data:

now, to have the mass of the gas, we will use the molar mass. In this case, the molar mass of O2=31.999g/mol

The grams of O2 produced in the reaction are 1.7x10^-2 g of O2

  Balanced net ionic equation will be:  Pb2+(aq) + 2I-(aq) → PbI2(s)

   The balanced chemical equation for the given reaction is;Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq)

This equation is balanced because the number of atoms of the elements present on both sides of the equation is equal.

The states of the substances in the above equation are:

aqueous Pb(NO3)2(aq) , aqueous NaI (aq) → soluble, based on the solubility table PbI2 (s) → precipitate, based on the solubility tableaqueous NaNO3 (aq)

Cancel out the spectator ions from the above equation and the net ionic equation will be:

Pb2+(aq) + 2I-(aq) → PbI2(s)

Hence, the balanced net ionic equation for the given reaction between aqueous Pb(NO3)2 and aqueous NaI and correctly label the states are Pb2+(aq) + 2I-(aq) → PbI2(s) and the states are as follows;

Pb2+(aq) → AqueousI-(aq) → AqueousPbI2(s) → Solid

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The ionic equation for the reaction is given as follows:Pb2+ (aq) + 2NO3- (aq) + 2Na+ (aq) + 2I- (aq) → PbI2 (s) + 2Na+ (aq) + 2NO3- (aq)The net ionic equation is the same as the ionic equation, with spectator ions removed.Pb2+ (aq) + 2I- (aq) → PbI2 (s)The final balanced net ionic equation is given as follows:Pb2+ (aq) + 2I- (aq) → PbI2 (s).

The balanced net ionic equation for the following reaction between aqueous Pb(NO3)2 and aqueous NaI and correctly label the states are given below:Explanation:Aqueous lead(II) nitrate (Pb(NO3)2) and aqueous sodium iodide (NaI) are mixed to form solid lead(II) iodide (PbI2) and aqueous sodium nitrate (NaNO3).Before writing the net ionic equation, it is important to determine whether a precipitate will form. By referencing the solubility table, it is discovered that lead(II) iodide is insoluble in water, indicating that a precipitate will form when the two solutions are mixed.The balanced molecular equation for the reaction is given as follows:Pb(NO3)2 (aq) + 2NaI (aq) → PbI2 (s) + 2NaNO3 (aq)To write the ionic equation, the insoluble solid lead(II) iodide must be separated into its component ions. PbI2 is a precipitate; it will not dissociate, while NaNO3 will dissociate into its component ions. The ionic equation for the reaction is given as follows:Pb2+ (aq) + 2NO3- (aq) + 2Na+ (aq) + 2I- (aq) → PbI2 (s) + 2Na+ (aq) + 2NO3- (aq)The net ionic equation is the same as the ionic equation, with spectator ions removed.Pb2+ (aq) + 2I- (aq) → PbI2 (s)The final balanced net ionic equation is given as follows:Pb2+ (aq) + 2I- (aq) → PbI2 (s).

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Answer:

1:loses or gains energy

Answer:

enthalpy of fusion also called heat of fusion

The formate ion can have one of two resonance structures, which are as follows: The most electronegative element, namely oxygen, is given a negative charge.

Resonance structures don't have isomers. Different atom and electron configurations distinguish isomers. The positioning of the electrons is the only distinction between resonance types.

Resonance structures more accurately depict a Lewis dot structure because they make molecular bonding visible.

In valence bond theory, resonance is a term used to describe how different contributing structures (or forms, also known as resonance structures or canonical structures) combine to generate a hybrid resonance (or hybrid structure) in certain molecules or ions.

Ozone, or O3, has two main resonance structures that each contribute equally to the overall hybrid structure of the molecule. All structures show the 18 valence electrons needed, with 6 in 3 bonds and 12 on the oxygen atoms as lone pairs.

Resonance occurs when the frequency matches the object's resonant frequency, which it reaches. Resonance occurs when the vibrations of one object cause the frequency of its oscillations to increase.

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Answer:

good morning I am going home with 6