ANSWER:
781.25 meters
STEP-BY-STEP EXPLANATION:
Given:
Time (t) = 25 sec
Acceleration (a) = 2.5 meters/sec/sec
Initial speed (u) = 0 meters/sec
Using the following formula, we calculate the distance traveled:
\(\begin{gathered} d=u+\frac{1}{2}at^2 \\ \\ \text{ We replacing} \\ \\ d=0+\frac{1}{2}\cdot2.5\cdot25^2 \\ \\ d=781.25\text{ meters } \end{gathered}\)The distance traveled is equal to 781.25 meters
A 500-nm wavelength light in vacuum illuminates a soap film with an index of refraction of 1.33. Air (n=1.00) is on both sides of the film. If the light strikes the film nearly perpindicularly, what is the smallest film thickness such that the film appears bright?
ANS --> 94.0
Please show your work as to how to end up with this answer.
Answer:
Wavelength of light in film (let y = lambda)
y = 500 nm / (4/3) = 375 nm
There will be a phase change at the air/film interface (not the other side)
S = 4 t thickness of film = S/4 where S equals 1 wavelength
This is because of the phase change at one surface
375 nm = 4 * t
t = 93.8 nm
Which pair of objects would be most strongly attracted to each other?
A. A positively charged particle and a negatively charged particle
B. Two positively charged particles
C. Two negatively charged particles
D. A negatively charged particle and a neutral particle
Answer:
Its A
Explanation:
Just did the quiz
The pair of objects that should be strongly attracted is option A. A positively charged particle and a negatively charged particle.
Pair of objects that are most strongly attracted:When there is a positively charged particle & the negatively charged particle so due to this it should be strongly attracted. Also, when there are two positively charged particles, or a negative one or a include negative one or neutral one so it should not be strongly attracted. Therefore, the option A is correct.
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Which has more mass electron or ion?
Which statement best compares gamma rays to the other components of the electromagnetic spectrum?
Am I correct ???
Answer:
no
Explanation:
gamma rays do have the most frequency, but they also have the highest amount of energy because they happen the most often.
What is sound waves
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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How much current is in a circuit with a 1.5 V battery and three
2-ohm resistances (bulbs) in series?
Answer: 0.25A
Explanation: To calculate the current in the circuit, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):
I = V / R
In this case, the total resistance of the circuit is the sum of the individual resistances of the three bulbs in series, which gives us:
R = 2 + 2 + 2 = 6 ohms
The voltage of the battery is given as 1.5V.
So, using Ohm's Law, we can calculate the current in the circuit as:
I = V / R = 1.5 / 6 = 0.25 amps
Therefore, the current in the circuit is 0.25 amps.
The current in the circuit is 0.25 A.
Voltage across the circuit, v = 1.5 V
Resistance in each resistors, R = 2Ω
Since, the resistors are connected in series combination, their effective resistance,
R' = 3R
R' = 3 x 2
R' = 6Ω
According to Ohm's law, if the temperature and all other physical factors remain constant, the voltage across a conductor is directly proportional to the current that is flowing through it.
So, according to Ohm's law,
V = IR
Therefore, current flowing through the given circuit,
I = V/R
I = 1.5/6
I = 0.25 A
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Please help I’m about to fail
Answer:
B
Explanation:
The cost of manufacturing would have to be taken away from your profits becuase its costing you to build and get the materials. I believe this question is hard.
How much net- work is required to accelerate a 1200-kg car from 25 m/s to 45 m/s?
The net-work required to accelerate the car of mass 1200 kg is 840000 J.
What is work done?Work can be deifned as the product of force and distance.
To calculate the amount of net-work required to accelerate 1200 kg car from 25 m/s to 45 m/s, we use the formula
Formula:
W' = m(v²-u²)/2............ Equation 1Where:
W' = Net-work required to accelerate the carm = Mass of the carv = Final velocityu = Initial velocityFrom the question,
Given:
m = 1200 kgv = 45 m/su = 25 m/sSubstitute these values into equation 1
W' = 1200(45²-25²)/2W' = 1200×1400/2W' = 840000 JHence, the net-work required is 840000 J.
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Two spheres, 1.00 kg each, whose centers are 2.00 m apart, would have what gravitational force between them? A. 3.14 X 10-17 N
B. 1.67 X 10-11 N
C. 8.17 X 10-6N
D. 5.78 X 10-6 N
Answer: B
Explanation: the teacher just told us the answer
The gravitational force between the two spheres is \(1.67 \times 10^{-11} \ N\).
The given parameters;
mass of each sphere, m = 1.00 kgdistance between their center mass, r = 2 mThe gravitational force between the two spheres is determined by applying Newton's law of universal gravitation as shown below;
\(F = \frac{Gm_1 m_2 }{r^2} \\\\\)
where;
G is universal gravitation constant = 6.67 x 10⁻¹¹ N/m\(F = \frac{(6.67\times 10^{-11})\times (1\times 1)}{2^2} \\\\F = 1.67 \times 10^{-11} \ N\)
Thus, the gravitational force between the two spheres is \(1.67 \times 10^{-11} \ N\).
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I
An arrow fired horizontally at 41 m/s travels 23 m horizontally before it hits
the ground. From what height was it fired?
Answer:
Height = 1.54 m
Explanation:
Given:
Velocity = 41 m/s
Distance = 23 m
Find:
Height
Computation:
We know that
a = 9.8 m/s²
Time = Distance / Velocity
Time = 23 / 41
Time = 0.56 second
Height = (1/2)(9.8)(0.56)²
Height = 1.54 m
Mr. MacDougall got his vehicle stuck in the snow. Being the nice student that you are, you stop to help Mr. MacDougall out of the snow. You exert a force of 350N on his vehicle and manage to push it 15m and completely out of the snow. How much work was done on the vehicle?
Answer:
Explanation:
work done=force*displacement
=350N*15m
=5250 joule
A 2.50 kg ball moving at 7.50 m/s is caught by a 70.0 kg man while the man is standing on ice. How
fast will the man / ball combination be moving after the ball is caught by the man?
Explanation:(2.5kg) (7.5) m/s +70 kg(0) =(2.5kg +70 kg (v3) 18. 75 =72.5 =v3
v3=.26m/s 2.5+70
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.
The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.
The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.
Initially, the capacitor is uncharged, so the second term is zero.
Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.
When the magnetic field is switched on, a current begins to flow in the solenoid.
This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.
Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.
The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.
Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.
This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.
The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)
The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)
The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)
This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.
The solution is t = 1.74 ms.
The units are in seconds.
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Please see Attached.
The values for the work done to the nearest 10 is as follows:
(a) WA = 13,200 J.(b) Wg = 0 J.(c) WN = 0 J.(d) WF = 3,550 J.(e) WNet = 16,750 J.(f) WNet = 16,750 J.What is the work done?(a) The work done by the applied force can be calculated using the formula:
WA = FAdcosθ,
where FA is the applied force, d is the distance moved, θ is the angle between the force and the displacement, and cosθ is the cosine of that angle.
In this case, FA = 216 N, d = 71.0 m, and θ = 30.0° below the horizontal. Therefore,
WA = (216 N)(71.0 m)cos(-30.0°)
WA = 13,200 J.
(b) The force of gravity on the box is given by Fg = mg
The work done by the force of gravity is given by Wg = Fgd,
Fg = (51.0 kg)(9.81 m/s^2)
Fg = 500.31 N, and the box does not move vertically, so d = 0.
Therefore, the work done by the force of gravity is zero.
Wg = 0 J.
(c) The normal force on the box is equal in magnitude and opposite in direction to the force of gravity, so FN = Fg. Since the box does not move vertically, the normal force does not do any work.
Therefore,
WN = 0 J.
(d) The force of friction on the box can be calculated using the formula:
FF = μFN,
where μ is the coefficient of kinetic friction between the floor and the box, and FN is the normal force on the box.
In this case, μ = 0.100 and FN = Fg = 500.31 N. Therefore,
FF = (0.100)(500.31 N) = 50.03 N
The work done by the force of friction can be calculated using the formula:
WF = FFd
In this case, the box moves a distance of 71.0 m.
Therefore,
WF = (50.03 N)(71.0 m)
WF = 3,550 J.
(e) The net work on the box is the sum of the works done by each individual force.
Therefore,
WNet = WA + Wg + WN + WF = 13,200 J + 0 J + 0 J + 3,550 J
WNet = 16,750 J.
(f) Alternatively, we can find the net work by first finding the net force on the box.
The horizontal component of the applied force is FAcosθ, where θ = 30.0° below the horizontal.
Therefore,
FNet,x = FAcosθ - FF = (216 N)cos(30.0°) - (0.100)(500.31 N)
FNet,x = 91.10 N
The vertical component of the applied force is FAsinθ, where θ = 30.0° below the horizontal. Therefore,
FNet,y = Fg - FAsinθ = (51.0 kg)(9.81 m/s^2) - (216 N)sin(30.0°)
FNet,y = 247.16 N
The net force on the box can be found using the Pythagorean theorem:
FNet = √(FNet,x² + FNet,y²)
FNet = √((91.10 N)² + (247.16 N)²)
FNet = 264.36 N
The direction of the net force is given by the angle θ between FNet,x and FNet:
θ = atan(FNet,y / FNet,x)
θ = atan(247.16 N / 91.10 N
θ = 70.9°
The net work done on the box is given by the formula:
WNet = FNetdcosθ, where d is the distance moved by the box.
In this case, d = 71.0 m.
Therefore,
WNet = (264.36 N)(71.0 m)cos(70.9°) = 16,750 J
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The vector A= 90m/s towards north and vector B = 125 m/s towards west. Find the magnitude of the resultant vector using pythagorean theorem
154.03 m/s
Explanation
The Pythagorean theorem states that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse (the side opposite the right angle)
\(a^2+b^2=c^2\)so, to add the vectors we solve use tht P.T and solve for c
s
Step 1
a) let
\(\begin{gathered} a=\text{ Vector A=90 }\frac{m}{s} \\ b=\text{ Vector B=125 }\frac{m}{s} \\ c=\text{ unknown= maginutude of the resultant} \end{gathered}\)b) now, replace in the formula:
\(\begin{gathered} a^2+b^2=c^2 \\ 90^2+125^2=c^2 \\ 8100+15625=c^2 \\ 23725=c^2 \\ square\text{ root in both sides} \\ \sqrt{23,725}=\sqrt{c^2} \\ 154.03=c \end{gathered}\)therefore, the answer is
154.03 m/s
I hope this helps you
40 POINTS!!!
A wave travels along a stretched horizontal rope. The vertical distance from crest to trough for this wave is 18 cm and the horizontal distance from crest to trough is 26cm.
Part A
What is the wavelength of this wave?
Express your answer using two significant figures
Part B
What is the amplitude of this wave?
Express your answer using two significant figures.
part a. the wavelength of this wave is 26 cm
part b. The amplitude (A) of a wave is 9 cm
What is wavelength?The wavelength (λ) of a wave is described as the distance between two consecutive points on the wave that are in phase.
In this scenario, the distance between two corresponding points on the wave will be equal to the horizontal distance from crest to trough, which is 26 cm.
Hence, the wavelength of the wave is: λ = 26 cm
The amplitude (A) of a wave is described as the maximum displacement of a particle from its rest position as the wave passes through it.
In this scenario, the vertical distance from crest to trough is 18 cm, which is equal to twice the amplitude.
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What is the result of two displacement vectors having opposite directions? Question 6 options: The resultant is the sum of the two displacements, having the same direction as the smaller vector. The resultant is the sum of the two displacements, having the same direction as the larger vector. The resultant is the difference of the two displacements, having the same direction as the smaller vector. The resultant is the difference of the two displacements, having the same direction as the larger vector.
The resultant of two displacement vectors having opposite directions is the difference of the two displacements, having the same direction as the smaller vector.
When two displacement vectors have opposite directions, it means they are pointing in opposite ways. In other words, one vector is in the opposite direction of the other. To find the resultant of these vectors, we need to subtract one vector from the other.
If we consider two displacement vectors, let's say vector A and vector B, and they have opposite directions, we can represent them as A and -B.
To find the resultant, we subtract vector B from vector A: A - (-B) or A + B.
The resultant will have the same direction as the smaller vector. This is because when we subtract a larger vector from a smaller vector, the resultant will have the direction of the smaller vector.
Therefore, the correct option is: "The resultant is the difference of the two displacements, having the same direction as the smaller vector."
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A school bus drives north and then east through the city as it takes students to school. The bus crosses a city block every 10 seconds. If all the city blocks are the same length, what can be said about the motion of the bus?
Answer:
The bus is moving at a constant speed.
Explanation:
We have the following facts from the question;
- The bus crosses a city block every 10 seconds.
- all the city blocks are the same length
Since all the city block are the same length, let's say the distance is d.
Since it crosses the city block every 10 seconds, we know that;
Speed = distance/time
Thus, Speed = d/10
Thus,it is moving at this speed of d/10 all through.
Therefore we can conclude that the bus is moving at a constant speed.
identify and explain the climate cycle shown
below. Illustrate how conditions change during
the summer
Answer:
wnd change
Explanation: wnd chsnge
Military rifles have a mechanism for reducing the recoil forces of the gun on the person firing it. An internal part recoils over a relatively large distance and is stopped by damping mechanisms in the gun. The larger distance reduces the average force needed to stop the internal part. (Assume the gun is fired in the positive direction.) (a) Calculate the recoil velocity (in m/s) of a 1.23 kg plunger that directly interacts with a 0.0200 kg bullet fired at 561 m/s from the gun. (Indicate the direction with the sign of your answer.) (b) If this part is stopped over a distance of 22.2 cm, what average force (in N) is exerted upon it by the gun? (Indicate the direction with the sign of your answer.) (c) Compare this to the force exerted on the gun if the bullet is accelerated to its velocity in 13.4 ms (milliseconds). (Include the sign of the value in your answer.) force on plunger by gun / force on gun by bullet =
We will have the following:
a)
\(\begin{gathered} (0.02kg)(561m/s)=(1.23kg)v_f\Rightarrow v_f=\frac{11.22kg\ast m/s}{1.23kg} \\ \\ \Rightarrow v_f=\frac{374}{41}m/s\Rightarrow v_f\approx9.12m/s \end{gathered}\)So, the recoil is approximately -9.12 m/s.
b) Now, we determine the average force of the rifle:
First, we determine the time it took to have the final velocity the bullet:
\(\begin{gathered} -0.222m=\frac{1}{2}(0m/s-9.12m/s)t\Rightarrow t=\frac{4551}{93500}s \\ \\ \Rightarrow t\approx0.049s \end{gathered}\)Now, we determine the average force:
\(\begin{gathered} F=\frac{(1.23kg)(374/41\text{ }m/s-0m/s)}{(4551/93500s)}\Rightarrow F=230.5141727...N \\ \\ \Rightarrow F\approx230.51N \end{gathered}\)So, the average force was approximately 230.51 N.
c) If th bullet is accelerated to this velocity in 13.4 ms we will have that:
\(F=\frac{(1.23kg)(374/41m/s-0m/s)}{(0.0134s)}\Rightarrow F\approx837.31N\)So, the force would be much greater.
if a car travels 125 miles in 2.5 hours, what was the cars average speed over the 2.5 hours?
Answer:
50 miles per hour
Explanation:
125/2.5 which equals to 50
Answer:
50 miles per hour
Explanation:
125 divided by 2.5 = 50
A 6.25 g quarter sits 25 cm from the axis of rotation on a turntable that has a period of rotation of 1.8 seconds.
What must the coefficient of static friction be in order to keep the quarter from sliding outward when the
turntable is in motion?
The coefficient of static friction be in order to keep the quarter from sliding outward when the turntable is in motion will be 0.31.
What is the friction force?It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).
Mathematically it is defined as the product of the coefficient of friction and normal reaction.
On resolving the given force and acceleration in the different components and balancing the equation gets. The friction force balances centripetal force.
The given data in the problem will be;
m is the mass =6.25 g
r is the radius =25 cm=0.25 m
t is the time = 0.18 sec
μ is the coefficient of static friction =?
\(\rm F_c= mw^2r \\\\ f= \mu mg \\\\ F_C=f\\\\ mw^2r= \mu mg \\\\ \rm \mu = \frac{\omega^2r}{g} \\\\ \rm \mu = (\frac{2\pi}{1.8} )^2\frac{0.25}{9.81} \\\\ \rm \mu = 0.31\)
Hence the coefficient of static friction will be 0.31.
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sliding a box is work against friction.
Answer:
If you are reffering true or false, its true! <3
Answer:
yes, sliding a box is work against friction .
an ice sheet 5m thick covers a lake that is 20m deep. at what is the temperature of the water at the bottom of the lake?
Answer:
4°C
Explanation:
Water is densest at 4°C. Since dense water sinks, the bottom of the lake will be 4°C.
a car is traveling at velocity of 15m/s.it accelerates to a velocity 35m/s in 10s calculate the acceleration?
Hope it helps
pls mark as Brainliest
Your mother is sure that you were driving too fast because she knows (2 points)
1.when you arrived and the direction you came from
2.how long it took you to get home and how far you traveled
3.what time you left and how long it took you to get home
4.the direction you were driving and how far you traveled
PLEASE HELP
S
ai
5
The regular polygon has the following measures.
a = 9√3 m
s = 18 m
Segment a is drawn from the center of the polygon
perpendicular to one of its sides.
What is the vocabulary term for segment a?
What is the area of the polygon?
Round to the nearest tenth and include correct units.
Segment a, which is drawn from the center of the polygon perpendicular to one of its sides, is called the apothem.
The typical hexagon has a surface area of around 874.6 square meters.
How to determine area of a hexagon?To find the area of a regular polygon, use the formula:
Area = (1/2) x Perimeter x Apothem
Find the perimeter of the polygon. Since the polygon has n sides, use the formula:
Perimeter = n x s
where s = length of one side.
Since s = 18m, find n by using the formula:
n = 360° / (180° - (360° / n))
where n = number of sides.
Plugging in the values:
n = 360° / (180° - (360° / n))
n = 360° / (180° - (360° / 6))
n = 6
So the polygon has 6 sides, which makes it a hexagon.
Now find the perimeter:
Perimeter = n x s
Perimeter = 6 x 18
Perimeter = 108m
Next, find the apothem, use the formula:
Apothem = s / (2 x tan(π/n))
Plugging in the values:
Apothem = 18 / (2 x tan(π/6))
Apothem = 9√3 m
Now use the formula for the area:
Area = (1/2) x Perimeter x Apothem
Area = (1/2) x 108 x 9√3
Area ≈ 874.6 m²
Therefore, the area of the regular hexagon is approximately 874.6 square meters.
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ASAP PLEASE :)
How can we add kinetic energy to a baseball or football?
Answer:
Hitting it or throwing it with force.
Research DNA phenotyping and make a list of pros and cons. What are its possible advantages? What might go wrong? Would it change investigations for the better, or create unfair bias? Think about how this technology would impact forensics, law enforcement, and the public in general. List at least three arguments for and three arguments against it. (1 sentence/phrase each)
Answer:
Pros of DNA phenotyping:
-Phenotypical characteristics can be predicted such as eye color, hair color, skin pigmentation, and many more.
-predict ancestry of an organism
-Use to find criminals
Cons of DNA phenotyping:
-Some phenotypical traits could not be predicted
- Invading privacy
This technology will surely help forensics, law enforcement as it helps track down unknown perpetrators of crime.
3 arguments for it:
- accurate in narrow down researches
- finding biological ancestry
3 arguments against it
It violates the privacy policy of an individual
Racial discrimination is done of public
Equality policies are not followed by it.
1. A rock is initially launched from ground level vertically reaching its highest
point 4.2 seconds after being launched. Calculate the initial velocity of the
rock, to the nearest 100th, as the rock is launched. Calculate the maximum
height of the rock to the nearest 10th.
Explain and show all steps of your solution.
the kinematics allows searching for the variables of movement of the body, finding the initial velocity and the height of the body
v₀ = 41.16 m/s and y = 86.4 m
given parameters
time to reach the highest point t = 4.2 sto find
Initial velocity The maximum height
The kinematics allows finding the relationships between the position, velocity and relationship of a body, for its use a reference system must be defined with respect to which to carry out the measurements. Let's set a rule system with the y-axis vertical and the upward direction as positive.
v = v₀ - g t
Where v and v₀₀ are the velocity at the initial point e, respectively, g is the acerlation of gravity (g = 9.8 m / s²) and t is the time
At the highest point the velocity is zero
0 = v₀ - g t
v₀ = g t
v₀ = 9.8 4.2
v₀ = 41.16 m / s
To find the maximum height we use
v² = vo² - 2 g y
where y is the height reached.
At the point of maximum height the velocity is zero
0 = vo² - 2 g y
y = \(\frac{v_o^2}{2g}\)
y = \(\frac{41.16^2}{2 \ 9.8 }\)
y = 86.44 m
using the criterion that the result is with a tenth
y = 86.4 m
Using the kinematics relations we can find the initial velocity and the height of the body
v₀ = 41.16 m / s and y = 86.4 m
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