what distance in miles can you drive in your new Prius hybrid, if your car gets 56 miles per gallon and you have 15.5 gallons of gas?

Answer:

I can say that knowledge of separating mixtures can help us in daily life and within society in the following ways:

1. Purification of water: Separation techniques are used to purify water for drinking and industrial purposes. It is essential to remove impurities from water to prevent diseases.

2. Recycling: Separation techniques are used to separate materials for recycling. This helps reduce the amount of waste in landfills and helps conserve resources.

3. Food industry: Separation techniques are used in the food industry to separate unwanted particles from food products. This helps ensure that the food we eat is safe and free from contaminants.

4. Medicine: Separation techniques are used in the pharmaceutical industry to separate and purify chemicals for use in medicine. This helps ensure that medicines are safe and effective.

5. Environmental protection: Separation techniques are used to remove pollutants from the environment. This helps protect our natural resources and prevent pollution-related health problems.

6. Oil and gas industry: Separation techniques are used to separate crude oil and natural gas into their various components. This helps in the production of energy and other useful products.

In summary, knowledge of separating mixtures is essential in our daily lives and within society. It helps ensure that we have access to safe and clean water, food, medicine, and energy, and also helps protect the environment.

Explanation:

Answer:

D  The dinosaur could have died due to an meteor crash.

Explanation:

Answer:

D

Explanation:

The dinosaurs fossils were found ten miles away from the meteor crash site. Correct me if I'm wrong

Answer:

SBr2: Electron geometry-tetrahedral; molecular geometry-trigonal pyramidal

PI4+: Electron geometry-tetrahedral; molecular geometry-tetrahedral

IBr2−: Electron geometry- Trigonal bipyramidal ; molecular geometry- linear

Explanation:

In SBr2, the molecule is of the structure type AX2E2 hence it is based on a tetrahedron but have two lone pairs of electrons hence the molecular geometry is trigonal pyramidal.

PI4+ has four electron domains and all of them are bond pairs hence both electron geometry and molecular geometry are both tetrahedral.

IBr2- is of the structure type AX2E3 hence it is based on a trigonal bipyramd and has a linear molecular geometry.

2)

SiF4 has a tetrahedral molecular and electron domain geometry because the central atom(Si) has no lone pairs.

SeF4 has a trigonal bipyramidal electron geometry with the structure AX4E. Its molecular geometry is See-saw since it has one lone pair of electrons that causes a deviation from its ideal trigonal bypyramidal geometry.

XeF4 has  an octahedral electron domain geometry and the molecule is AX4E2. The two lone pairs are positioned above and below the plane of a square hence the molecule is square planar.

Answer: 14.0

Explanation: 14.0 is a base. The more basic, the less hydrogen ion concentration.

Disaccharides are sugars made up of two saccharides units linked together by a COC bond.

Like any other carbohydrate, disaccharides serve as the body's energy source. Disaccharides are converted by our bodies into simple sugars (simple sugars) for the small intestine to absorb when we ingest meals containing them.

Disaccharide, commonly known as double sugar, is any material made up of two simple sugar molecules (monosaccharides) joined together.

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The number of moles in 44 g of CO₂ is one mole. Number of moles of 98 g of O₂ is 3 moles. Similarly the number of moles in 12 g of MgCl₂ is 0.12.

Any substance that contains 6.02 × 10²³ atoms or molecules is called one mole of that substance. This number is called Avogadro number. One mole of every element contains Avogadro number of atoms.

The mass of one mole of a compound is called its molar mass. We can determine the number of moles in a given mass of the compound by dividing the mass by molar mass.

no.of moles = given mass/molar mass.

Molar mass of CO₂ = 44 g

hence 44 g of is one mole.

Molecular mass of O₂ = 32 g

moles in 98 g = 98/32 = 3 moles.

Molar mass of   MgCl₂ = 95 g/mol

moles in 12 g = 12 /95 = 0.12 moles.

In the similar way, the number of moles of all compounds for the given mass can be calculates.

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Answer:

  Field experiments can often have the potential to give scientists opportunities that are not possible in a lab setting.

Explanation:

  Having people "act natural" in a lab setting is impossible to truly achieve, as we all know what happens to our mental state and behavior when we are being actively observed. This is also especially helpful when conducting wildlife research, as there are a myriad of different things influencing animal and plant behavior that would be nigh impossible to recreate perfectly in a controlled lab setting.

  Field research can have its disadvantages as well, as it is very hard to only have one thing change (make an independent variable) in a wild environment with ever-changing weather, social effects, etc. Also, you, as the researcher, as causing an impact on the very location that you are observing, which can alter your results in unpredictable ways.

  The thing to remember is that each type of study has its advantages and disadvantages; if they didn't, then we'd all do the same type of research! You have to weigh your research options and figure out which one works best for your situation :)

The grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g. None of the options provided match the calculated value of 466.64 g.

To determine the grams of magnesium hydroxide (Mg(OH)2) needed to yield 8.00 moles of magnesium chlorate (Mg(ClO3)2), we need to consider the balanced chemical equation for the reaction between magnesium hydroxide and chlorine.

The balanced equation is as follows:

2 Mg(OH)2 + 6 Cl2 → 2 Mg(ClO3)2 + 2 H2O

From the balanced equation, we can see that 2 moles of Mg(OH)2 react with 6 moles of Cl2 to produce 2 moles of Mg(ClO3)2.

Therefore, the stoichiometric ratio is 2 moles of Mg(OH)2 : 2 moles of Mg(ClO3)2.

To calculate the grams of Mg(OH)2 needed, we can use the stoichiometric ratio and the given moles of Mg(ClO3)2.

Given:

Moles of Mg(ClO3)2 = 8.00 moles

Using the stoichiometric ratio, we have:

8.00 moles Mg(ClO3)2 × (2 moles Mg(OH)2 / 2 moles Mg(ClO3)2) = 8.00 moles Mg(OH)2

To convert moles to grams, we need to multiply by the molar mass of Mg(OH)2.

The molar mass of Mg(OH)2 = (24.31 g/mol) + (2 * 16.00 g/mol) = 58.33 g/mol

Grams of Mg(OH)2 = 8.00 moles Mg(OH)2 × 58.33 g/mol = 466.64 g

Therefore, the grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g.

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1. The % concentration is 20.7% and the molar concentration, Cm, is 1.5 M.

2. 7.8 grams of potassium sulfate will be formed.

3. 10.7 grams of ammonium chloride will be formed.

4. The volume of hydrogen gas that will be produced is 3.86 liters.

5. 21.43 grams of the 70% acetic acid is needed to prepare 500 grams of 3% acetic acid solution.

1. Mass of potassium sulfate = 1.5 moles * (174.26 g/mol) = 261.39 g

Mass of water (H₂O) = 1000 g

% = (mass of solute/mass of solution) x 100

% = (261.39 g / (261.39 g + 1000 g)) x 100

% ≈ 20.7%

Cm = moles of solute / volume of solution

Moles of potassium sulfate (K2SO4) = 1.5 moles

Volume of water (H2O) = 1000 g / (density of water) = 1000 g / 1 g/mL = 1000 mL = 1 L

Cm = 1.5 moles / 1 L

Cm = 1.5 M

2. The balanced equation for the reaction is:

H₂SO₄ + 2 KOH → K₂SO₄ + 2 H₂O

Molar mass of sulfuric acid (H₂SO₄) = 98.09 g/mol

Moles of sulfuric acid = 10 g / 98.09 g/mol

Moles of sulfuric acid = 0.102 mol

Based on the mole ratio of the reaction, 0.102 moles of sulfuric acid will react to form 0.102 moles of potassium sulfate.

Molar mass of potassium sulfate = 174.26 g/mol

Mass of potassium sulfate = 0.102 mol x 174.26 g/mol

Mass of potassium sulfate ≈ 17.8 g

3. The balanced equation for the reaction is:

Molar mass of hydrochloric acid (HCl) = 36.46 g/mol

Moles of hydrochloric acid (HCl) = 7.3 g / 36.46 g/mol

Moles of hydrochloric acid ≈ 0.2 mol

Based on the mole ratio of the reaction, 0.2 moles of hydrochloric acid will react to form 0.2 moles of ammonium chloride.

Molar mass of ammonium chloride (NH₄Cl) = 53.49 g/mol

Mass of ammonium chloride = 0.2 mol x 53.49 g/mol

Mass of ammonium chloride ≈ 10.7 g

4. The balanced equation for the reaction is:

Molar mass of zinc (Zn) = 65.38 g/mol

Moles of zinc = 13 g / 65.38 g/mol

Moles of zinc ≈ 0.199 mol

Based on the mole ratio of the reaction, 0.199 moles of zinc will react to produce 0.199 moles of hydrogen gas.

Volume of sulfuric acid = 30 g / (density of H₂SO₄ )

The density of H₂SO₄ is 1.84 g/mL

Volume of sulfuric acid  = 30 g / 1.84 g/mL

Volume of sulfuric acid ≈ 16.3 mL or 0.0163 L

Using the ideal gas law, the volume of hydrogen gas produced will be:

V = nRT / P

V = (0.199 mol)(0.0821 L·atm/(mol·K))(273 K) / (1 atm)

V ≈ 3.86 L

5. Assuming that the concentrated original solution of acetic acid is 100% acetic acid (CH₃COOH).

Mass of acetic acid = 500 g x (3/100) = 15 g

The concentrated original solution, however, is 70% acetic acid.

70% acetic acid (mass) = 100% acetic acid (unknown mass)

0.7 * (unknown mass) = 15 g

Solving for the unknown mass:

unknown mass = 15 g / 0.7

unknown mass ≈ 21.43 g

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The number of molecules in the permanganate is 4.8 * 10^22 molecules

We know that if we are to obtain the number of molecules form the number of the moles of the substances then as a matter of necessity we would have to turn to the Avogadro's law and that is what we are going to do here.

We have that;

If 1 mole contains about 6.02 * 10^23 molecules

0.08 moles would contain 0.08 * 6.02 * 10^23/ 1

= 4.8 * 10^22 molecules

Hence, we have about 4.8 * 10^22 molecules in the permanganate

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Bromine has larger ionic radius and atomic radius than fluorine.

Fluorine has larger ionisation energy and electronegativity than bromine.

Halogen are those elements that are found in group 7 of the periodic table.

Fluorine is in period two of the periodic table, meaning that it contains electrons in only the first two energy levels at ground state. It has a higher ionization energy and electronegativity than bromine.

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Indicate whether fluorine or bromine has a larger value for each of the following properties. a. electronegativity b. ionic radius c. atomic radius d. ionization energy

0.02314 moles of  NO₂ can be formed from the decomposition of 1.25 g of dinitrogen pentoxide.

The balanced equation for the decomposition of dinitrogen pentoxide is:

2 N₂O₅ → 4 NO₂ + O₂

The molar mass of N₂O₅  is 108.01 g/mol.

To determine the number of moles of N₂O₅  present in 1.25 g, we use the following calculation:

moles N₂O₅  = mass / molar mass

moles N₂O₅ = 1.25 g / 108.01 g/mol

moles N₂O₅ = 0.01157 mol

From the balanced equation, we can see that 2 moles of N₂O₅  decompose to form 4 moles of NO2. Therefore, the number of moles of NO2 produced can be calculated as:

moles  NO₂ = (0.01157 mol N2O5) × (4 mol NO2 / 2 mol N2O5)

moles  NO₂ = 0.02314 mol

Therefore, 0.02314 moles of  NO₂ can be formed from the decomposition of 1.25 g of dinitrogen pentoxide.

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Answer:

17 reactions

Explanation:

Answer:

this the one i needed help on pleasee sb help meh out

Explanation:

Answer:

A cold front is moving to the north and west before a warm front moves through.

Explanation:

Answer:

The value of pOH of a solution is 2.28

We need to find the [OH-] in a solution. We know that,

pOH=-\text{log}[OH^-]pOH=−log[OH−]

Put all the values,

\begin{gathered}2.28=-\log[OH^-]\\\\=0.00524\end{gathered}2.28=−log[OH−]=0.00524

So

Answer:

Q = -535 J.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the lost energy according to the following and generic heat equation:

\(Q=mC(T_F-T_i)\)

Thus, since the specific heat of iron is 0.450 in the SI units, we can plug in the mass and temperatures to obtain:

\(Q=28.3g*0.450\frac{J}{g\°C} (24.0\°C-66.0\°C)\\\\Q=-535J\)

Regards

Answer:

b) maintains the pH of blood near 7.4.

c) regulates the blood pH at 7.4 +/- one pH unit.

f) is facilitated by the enzyme carbonic anhydrase, which interconverts carbon dioxide and water to carbonic acid (ionizes into bicarbonate and H^+).

Explanation:

The pH of human blood is slightly acidic i. e. 7.4. The enzyme carbonic anhydrase is responsible for the regulation to neutral and prevent it from acidic. the enzyme carbonic anhydrase helps in the conversion of carbon dioxide to carbonic acid and bicarbonate ions. When the blood reach to lungs, the bicarbonate ions convert back to CO2 and this carbondioxide is exhaled from the body.

Answer:

Solvent - water

solute - lemonade powder

Explanation:

You should learn the definitions of al them words. I made them notes in grade 7 dont judge and was bored while studying so i highlited everything and i thought it looked cute back then. We all did that.

There are 0.2107 moles of KBr are dissolved in 60.2 mL of a 3.50 M solution.

The molarity of a substance is defined as the number of moles of solute present in 1 litre of a solution.

According to the given data, the molarity of the solution tells us that there are 3.50 moles of KBr in 1000mL of solution. But we only have 60.2mL of solution, so with a mathematical rule of three we can calculate the amount of moles in 60.2mL:

1000 ml - 3.50 moles

60.2 ml -x = 60.2 ml× 3.50 moles/1000 ml

x= 60.2 ml -0.2107 moles

So, there are 0.2107 moles of KBr.

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The enthalpy change for the reaction \(C2H4(g) + H2(g) → C2H6(g)\) is -137.15 kJ/mol.

Given:C2H4(g) + H2(g) → C2H6(g)The enthalpy of formation of C2H6(g) is -84.68 kJ mol-1The enthalpy of formation of C2H4(g) is 52.47 kJ mol-1The enthalpy of formation of H2(g) is 0 kJ mol-1Hence, using Hess's Law, the enthalpy change for the reaction \(C2H4(g) + H2(g) → C2H6(g)\) can be calculated by considering the formation of reactants and products from their respective elements. It can be given as:

\($$C_2H_4 + H_2 → C_2H_6$$$$\Delta H = H_f(C_2H_6) - [H_f(C_2H_4) + H_f(H_2)]$$$$\Delta H = -84.68 - [52.47 + 0]$$$$\Delta H = -84.68 - 52.47$$$$\Delta H = -137.15 kJ/mol$$.\)

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The mass of oxygen in 4 moles of C2H4O2 is 128g.

The mass of a substance can be calculated by multiplying the number of moles of the substance by its molar mass.

Molar mass of C2H4O2 = 12(2) + 1(4) + 16(2) = 60g/mol

mass of C2H4O2 = 60g/mol × 4 moles = 240grams

However, the mass of oxygen in the compound can be calculated as follows:

molar mass of oxygen/molar mass of compound × 240 grams

32g/mol ÷ 60g/mol × 240g

= 128g

Therefore, the mass of oxygen in 4 moles of C2H4O2 is 128g.

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Answer:

It gives the same result when an experiment is repeated.

Explanation:

Below are the possible answers to the question:

It is biased.

It cannot be verified.

It cannot add new evidence to existing evidence.

It gives the same result when an experiment is repeated.

The correct answer would be that it gives the same result when an experiment is repeated.

If a reaction is conducted in chemistry and certain results are obtained, once a detailed procedure of the experiment is known along with all the chemicals involved, such reaction/experiment can be repeated anywhere in the world and the same result would be obtained.

The repeatability of experiments always makes the experiments to be reliable. Hence, chemistry is reliable because it gives the same result without any variation when experiments are repeated under similar conditions.

Answer:

1.674 x 10^-23 grams

Explanation:

Hydrogen-1 is called Protium

wikipedia

atomic mass of Protium is 1.00794 amu

sciencedirectcom

atomic mass of 10 Protiums is 10.0794 amu

10.0794 amu in grams is

1.6737236x10^-23 grams

Answer:

a. mass of glucose required = 4.50 g

b. mass of glucose required = 0.05 g

c. mass of glucose required = 25g

Explanation:

1a. molar mass of glucose = 180.156 g/mol

volume of solution = 250 mL or 250 mL * 1 L/1000 mL = 0.25 L

concentration of solution = 100 mM or 100mM * 1 M/1000 mM = 0.10 M

amount in moles = mass/ molar mass = concentration * volume

mass in grams = concentration * volume * molar mass

mass = 0.10 * 0.25 * 180.156

mass of glucose required = 4.50 g

b. mass concentration of 0.05 % solution = 0.05 g/100 ml = 0.5 g/L

volume of solution = 100 mL = 0.1 L

mass in grams = mass concentration * volume

mass in grams =  0.5 g/L * 0.1 L

mass of glucose required = 0.05 g

c. mass concentration of solution = 50 mg/ mL = 0.05 g/ 0.001 L = 50 g/L

volume of solution = 500 mL = 0.5 L

mass of solute required = concentration * volume

mass required = 50 g/L * 0.5 L

mass of glucose required = 25g

Answer:

209

83 Bi

Explanation:

213 213 - 4 4

85 At = 85 - 2 Y + 2 He

Answer:

All of the above.

Explanation:

For a scientific hypothesis to be considered a hypothesis, it has to be testable. When conducting a lab experiment, it also allows the tester to predict what might occur during and after the experimentation. They are also explanatory. For example, theories are hypotheses that have been verified and can explain why something in nature takes place.

Using Avogadro's Law, we have

In the fourth column, we have to find n2.

Where V1 = 8.66 L, V2 = 10.9 L, and n1 = 0.0021 mol.

Therefore, n2 = 0.0026 moles.

In the given reaction, the limiting reactant is C₆H₆ (benzene).

To determine the limiting reactant as well as calculate the mass of HCl produced, compare the moles of each reactant.

The number of moles for each reactant:

Molar mass of Cl₂ = 35.5 g/mol + 35.5 g/mol = 71 g/mol

Moles of Cl₂ = mass of Cl₂ / molar mass of Cl₂

                     = 45 g / 71 g/mol

                     = 0.634 moles of Cl₂

Molar mass of C₆H₆ (benzene) = 12 g/mol + 6(1 g/mol) = 78 g/mol

Moles of C₆H₆ = mass of C₆H₆ / molar mass of C₆H₆

                        = 45 g / 78 g/mol = 0.577 moles of C₆H₆

Determine the stoichiometry between Cl₂ and HCl:

Cl₂ + C₆H₆ → C₆H₅Cl + HCl

Here, we can see that 1 mole of Cl₂ produces 1 mole of HCl.

Thus, the limiting reactant is C₆H₆ (benzene).

Calculate the mass of HCl produced:

Molar mass of HCl = 1 g/mol + 35.5 g/mol = 36.5 g/mol

Moles of HCl produced = moles of C₆H₆ = 0.577 moles

Mass of HCl produced = moles of HCl produced × molar mass of HCl

Mass of HCl produced = 0.577 moles × 36.5 g/mol

                                     ≈ 21.04 g

Therefore, approximately 21.04 grams of HCl will be produced.

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