What dipeptides would be formed by heating a mixture of valine and n -protected leucine?

Answer:

B!

Explanation:

Answer:

i know im late but i just really want the points. the answer is b.

Explanation:

Answer:

129 units cubed

Explanation:

There are ten spaces between 120 and 130, so we can infer that each line represents a change in volume of 1 unit. The volume of the substance in the graduated cylinder looks like it's 1 under 130, so its volume is 129 units.

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"Hypotonic solution," refers to a solution with the highest water concentration due to its lower solute concentration compared to the other options, leading to water influx into cells.

A hypotonic solution would be most likely to have the highest water concentration. In a hypotonic solution, the solute concentration is lower than that inside the cell or compared to another solution. As a result, water tends to move into the cell or the solution to equalize the concentration.

When a cell is placed in a hypotonic solution, water molecules will move into the cell through the process of osmosis. This influx of water increases the water concentration inside the cell, leading to cell swelling or even bursting in extreme cases.

Compared to hypertonic and isotonic solutions, a hypotonic solution has a lower solute concentration, allowing for a higher concentration of water molecules. This results in a higher water concentration in the solution. It's important to note that the concept of tonicity is related to the relative solute concentrations between two solutions and their effect on cell osmosis. In this case, a hypotonic solution is characterized by a higher water concentration compared to the other options.

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Answer:

747 mol.

Explanation:

Carbon buildup can be removed from the metal portion of a pressing comb by immersing it in a solution containing an acid.

When a pressing comb is used for styling hair, it can accumulate carbon buildup over time. This buildup can affect the comb's performance and hinder smooth gliding through the hair.

To remove the carbon buildup, the metal portion of the comb can be immersed in a solution containing an acid. The acid helps to dissolve and break down the carbon deposits, making it easier to clean the comb.

Acids such as vinegar, lemon juice, or citric acid are commonly used for this purpose. These acids have properties that help in dissolving carbon and other residues. The comb should be soaked in the acid solution for a specific period of time, allowing the acid to work on the carbon buildup.

After soaking, the comb can be scrubbed gently with a brush or cloth to remove any remaining residue. Finally, rinsing the comb thoroughly with water and drying it properly completes the process.

Hence, immersing the metal portion of a pressing comb in a solution containing an acid is an effective method to remove carbon buildup and restore the comb's functionality.

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The best idea to explain the structure of the periodic table is the concept of periodicity.

Periodicity refers to the repeating pattern of chemical and physical properties of elements based on their atomic structure. The periodic table is structured in a way that elements with similar properties are grouped together in vertical columns, known as groups or families, while elements with increasing atomic number are arranged in horizontal rows, known as periods.

This arrangement reflects the periodic nature of the properties of elements, such as electronegativity, ionization energy, and atomic radius. Overall, the structure of the periodic table is based on the idea of periodicity and serves as a powerful tool for understanding the properties and behaviors of elements.

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The expected major product of the given reaction sequence is t-BuBr.

In the first step of the reaction sequence, t-BuOK (tert-butoxide potassium) and t-BuOH (tert-butanol) are involved. This combination typically results in the elimination of a proton (H⁺) from t-BuOH, generating the t-butoxide ion (t-BuO⁻). The t-BuO⁻ ion then acts as a strong base and abstracts a proton from t-BuBr, leading to the formation of t-BuBr as the major product.

Therefore, the expected major product of the reaction sequence is t-BuBr.

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Calorimetry Experiment: Calorimetry is a technique used to estimate changes in enthalpy of chemical reactions. There are two types of calorimetry experiments that are given below :

1. Enthalpy changes of reactions in solution.

2. Enthalpy changes of combustion.

According to question,

The biggest source of error in calorimetry is usually temperature measurements, unwanted heat loss to the surroundings, this can be fixed by adding a lid.

Stirring error : Calorimetry is not insulated in a proper way.

Personal sources of error : It contains many error one of the important and usual error is measurement error, error in the volume or weight.

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Answer:

C. 40

Explanation:

there are 40 moles of water in a 0.250 mole. use the formula to find out

40.0 = 40.0 + 0

Answer:

14660.75 kJ.

Explanation:

We are given from the question above that the pressure inside is represented by this equation:

P = Po + C(1-(D1/D))(D1/D).

Thus, P = 100 + C (1 - 1/4) (1/4). Therefore, P  which is = 400 is;

400 = 100 + C (1 - 1/4) (1/4).

Hence, C = 1600. And the equation can be written as P = 100 + 1600 (1 - (D1/D))(D1/D).

The work done during the entire process, w = (work done during the process 1 to 2) + (work done duringbthe process 2 to 3 ).

Therefore, work done during the process 1 to 2 = P(V2 + V1) = 100( π/6 - 0).

{NB: V2 is gotten from π/6 × D^3. Where D^3 = 1. }

Hence, work done during the process 1 to 2 = 52.36 kJ.

So, the work done duringbthe process 2 to 3 ) is going to be the integration of PdV. Where P = 100 + 1600 (1 - (D1/D))(D1/D) and dV = π/2 D^2 dD. Taking the upper and the lower limit as 4 and 1 respectively.

After the integration (kindly check attached picture for the process) the work done duringbthe process 2 to 3  = 14.61 × 10^3 kJ.  

Therefore, The work done during the entire process, w = (work done during the process 1 to 2) + (work done duringbthe process 2 to 3 ).

The work done during the entire process, w = 52.36 kJ + 14.61 × 10^3 kJ.   = 14660.75 kJ.

Answer:

"Energy Level" is the correct approach.

Explanation:

Answer:

california

Explanation:

Answer:

It is Soluble

Explanation:

Name- Magnesium acetate

It dissolves easily in water and alcohol.

Answer:

There are 12 neutrons and 11 electrons in 23Na+

Explanation:

An atomic number of 11 means this atom will have 11 protons. A mass number of 23 means 23 - 11 this atom will have 12 neutrons. Since this atom is neutral the positive protons must be equal to the negative electrons. This atom will have 11 electrons.

Answer:

0.1

Explanation:

300/(30*10*10)=0.1

When the Cu2 ion is present in nitrite reductase, the ion is a cofactor and the enzyme is an apoenzyme.

Nitrite reductase is an enzyme that reduces nitrite to nitric oxide in bacteria and plants. The enzyme contains two histidine amino acids that coordinate a Cu2+ ion, which is an important cofactor in the reaction. The Cu2+ ion is bound to the two histidine residues through its imidazole rings, forming a coordination complex.

When the Cu2+ ion is present in the enzyme, it is in a reduced form, which means that it has lost one electron and is positively charged. The ion is also in a low-spin state, which means that the electrons in its d-orbitals are paired.

The enzyme, on the other hand, is in an oxidized state when the Cu2+ ion is present. This is because the enzyme is responsible for catalyzing the reduction of nitrite, which involves the transfer of electrons from the nitrite molecule to the Cu2+ ion. Therefore, the enzyme is a reducing agent in this reaction.

In summary, when the Cu2+ ion is present in nitrite reductase, it is a reduced species and the enzyme is a reducing agent.

Therefore the complete line would be "When the Cu2 ion is present in nitrite reductase, the ion is a cofactor and the enzyme is an apoenzyme."

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In a liquid-liquid extraction (LLE) system with loratadine and pseudoephedrine sulfate, the choice of organic and aqueous phases is crucial for efficient separation.

Loratadine is a non-polar compound, while pseudoephedrine sulfate is more polar due to the presence of a sulfate group. To achieve effective separation, we need to choose a suitable organic phase and aqueous phase.

For the organic phase, a non-polar solvent such as diethyl ether, ethyl acetate, or chloroform can be used. These solvents have good solubility for loratadine. The non-polar organic phase will extract loratadine from the mixture, allowing for separation from the aqueous phase.

As for the aqueous phase, we need to choose a polar solvent that will selectively extract pseudoephedrine sulfate. Aqueous solutions of acids like hydrochloric acid (HCl) or sulfuric acid (H2SO4) can be used. The acidic conditions protonate the pseudoephedrine sulfate, making it more soluble in the aqueous phase.

To perform the extraction, the mixture of loratadine and pseudoephedrine sulfate is added to the LLE system consisting of the organic phase (non-polar solvent) and the aqueous phase (acidic solution). The mixture is then vigorously shaken to ensure thorough mixing and extraction.

After shaking, the phases are allowed to separate, with the more dense aqueous phase settling at the bottom and the less dense organic phase on top. The layers can be carefully separated, and each phase can be further processed to isolate the desired compounds.

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Record the 30 mL on the intake and output record. The nurse should document the amount of normal saline instilled into the intestinal tube on the intake and output record to accurately monitor fluid balance.

Subtracting the 30 mL from the gastric output or considering it as insensible losses would not provide an accurate picture of the patient's fluid status. Additionally, even small amounts of fluids should be documented on the intake and output record
The nurse should proceed by choosing option b. Record the 30 mL on the intake and output record.
This is because the normal saline instilled into the intestinal tube is considered part of the patient's intake, and it is important to accurately document both intake and output for a proper assessment of the patient's fluid balance.

Initial emergency department (ED) treatment of small-bowel obstruction (SBO) consists of aggressive fluid resuscitation, bowel decompression, administration of analgesia and antiemetic as indicated clinically, early surgical consultation, and administration of antibiotics.

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Answer:

The proportion of carbon and oxygen is different in different samples of the gas.

Answer:

Ag is under going reduction

The oxygen atom in a water molecule is now bound to two hydrogen atoms rather than to another oxygen molecule.

Molecules are created when atoms come together. Two hydrogen (H) atoms and one oxygen (O) atom make up the three atoms that make up a water molecule. Because of this, water is occasionally abbreviated as H2O.

A molecule formed by covalent bonding is a water molecule, for instance. The chemical symbol for water, H2O, denotes that it is composed of one oxygen atom and two hydrogen atoms.

The amount of oxygen gas dissolved in water is known as dissolved oxygen (DO). Through direct atmospheric absorption, which is facilitated by turbulence, oxygen enters water. Additionally, water takes in the oxygen that aquatic plants release during photosynthesis.

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Answer:

\(\boxed {\boxed {\sf 10.3 \ moles \ of \ ammonia}}\)

Explanation:

To convert from molecules to moles, we must Avogadro's Number.

This number is how many particles (atoms, molecules, ions, etc.) in 1 mole of a substance. In this case, it is molecules of ammonia in 1 mole of ammonia.

\(6.022*10^{23} \ molecules \ NH_3 / mol \ NH_3\)

Use Avogadro's number as a ratio.

\(\frac{6.022*10^{23} \ molecules \ NH_3}{1 \ mol \ NH_3}}\)

Multiply by the given number of ammonia molecules (6.21*10²⁴)

\(6.21*10^{24} \ molecules \ NH_3 *\frac{6.022*10^{23} \ molecules \ NH_3}{1 \ mol \ NH_3}}\)

Flip the fraction so the molecules of ammonia can cancel out.

\(6.21*10^{24} \ molecules \ NH_3 *\frac{1 \ mol \ NH_3}{ 6.022*10^{23} \ molecules \ NH_3}}\)

\(6.21*10^{24}*\frac{1 \ mol \ NH_3}{ 6.022*10^{23}}\)

Multiply to make 1 fraction.

\(\frac{6.21*10^{24} \ mol \ NH_3}{ 6.022*10^{23}}\)

Divide.

\(10.31218864 \ mol \ NH_3\)

The original measurement of molecules had 3 significant figures (6,2 and 1). Therefore we must round our answer to 3 sig figs.

For the answer we found, 3 sig figs is the tenth place. The 1 in the hundredth place tells us to leave the 3 in the tenth place.

\(10.3 \ mol \ NH_3\)

There are about 10.3 moles of ammonia in 6.21*10²⁴ molecules.

Answer

47.73 g CuO

Explanation

Given:

Chemical equation: 3CuO+ 2H3PO4 = Cu3(PO4)2 + 3H20

mass of orthophosphate acid (Cu3(PO4)2) = 39.2 g

Required: The mass of CuO

Solution:

Second method:

Step 1: Find the moles of H3PO4

n = m/M where m is the mass and M is the molar mass of H3PO4

n = 39.2g/97.994g.mol^-1

n = 0.400 mol

Step 2: Use the stoichiometry to find the moles of CuO

The molar ratio between CuO and H3PO4 is 3:2

Therefore the moles of CuO = 0.400 mol x (3/2) = 0.600 mol

Step 3: Find the mass of CuO, now that we have moles

m = n x M m is the mass, n is the moles and M is the molar mass

m = 0.600 mol x 79,545 g/mol

m = 47.73 g

Answer:

The EF of the compound is CH2O and the MF is C6H12O6.

Explanation:

To find the empirical formula (EF) of the compound, we need to determine the simplest whole number ratio of the atoms in the compound. We can assume we have 100 g of the compound, which means we have:

40 g of carbon

6.67 g of hydrogen

53.33 g of oxygen (since the rest of the compound is oxygen)

Next, we can convert the masses to moles:

Moles of carbon = 40 g / 12.01 g/mol = 3.33 mol

Moles of hydrogen = 6.67 g / 1.01 g/mol = 6.61 mol

Moles of oxygen = 53.33 g / 16.00 g/mol = 3.33 mol

We then divide each of the mole values by the smallest number of moles, which is 3.33, to get the simplest whole number ratio:

Carbon: 3.33 / 3.33 = 1

Hydrogen: 6.61 / 3.33 = 1.98 (rounded to 2)

Oxygen: 3.33 / 3.33 = 1

So the EF of the compound is CH2O.

To find the molecular formula (MF), we need to know the molecular mass of the EF. The empirical formula mass (EFM) of CH2O is:

EFM = (1 x 12.01 g/mol) + (2 x 1.01 g/mol) + (1 x 16.00 g/mol) = 30.03 g/mol

We can then calculate the molecular formula mass (MFM) by dividing the given molecular mass (180 g/mol) by the EFM:

MFM = 180 g/mol / 30.03 g/mol = 6

This means the MF is 6 times the EF, or C6H12O6. Therefore

Answer:

21. D (Food moves into the small intestine.)

22. C (Food is stored and further broken down by acid and powerful enzymes.)

23. A (Your saliva helps break down what you're eating and turn it into chemicals called enzymes.)

24. B (...Food moves through your esophagus.)

25. E (Anything left in the small intestine moves into the large intestine.)

Explanation:

Food first enters the mouth where it is chewed and broken down by salivary amylase. Then, it is swallowed, moving down the esophagus to the stomach where it is stored and further broken down by acids and enzymes. And, these broken down food molecules moves into the large intestine.

Answer:

700

Explanation:

How to find

Multiply the volume and pressure and divide the product by the temperature and the molar gas constant to calculate the moles of the hydrogen gas.

Solve: 204.83 × 27.88 / 8.76 = 651.901872146

Which is 651.90

In the nearest hundredths, the moles of gas is 700

Answer:

The periodic table was created to organize the elements and provide physical and chemical properties, also to group with elements like it.

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