What determines whether or not a material is magnetic

Answer:

log = ( - 0.51 z 2) / ( 1 + ( / 305)

Explanation:

The relation between %TDS coffee and refractive index is given by the formula:

np = 0.00175 (% TDS Coffee) + 1.3342

In the given case

np = 1.3384

So, substituting the value of np in the equation above, we get:

1.3384 = 0.00174 (%TDS Coffee) + 1.3342

⇒ 1.3384 - 1.3342 = 0.00174 (%TDS Coffee)

⇒ 0.0042 = 0.00174 (%TDS Coffee)

⇒ (%TDS Coffee) = 0.0042/0.00174

⇒ %TDS Coffee = 2.4137

Hence the value of %TDS Coffee is 2.4137

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The correct molar mass for the compound CaBr₂ is 200 g/mole.

The molar mass of an element or compound is the mass of one mole of its particles, expressed in grams per mole (g/mol). To calculate the molar mass of CaBr₂, we need to add the atomic masses of one calcium atom and two bromine atoms:

Atomic mass of Ca = 40.078 g/mol

Atomic mass of Br = 79.904 g/mol

Molar mass of CaBr₂ = (1 x 40.078 g/mol) + (2 x 79.904 g/mol) = 200.960 g/mol

Rounding off to three significant figures, the molar mass of CaBr₂ is 200 g/mol.

What is molar mass?

Molar mass is the mass of one mole of a substance, expressed in grams per mole (g/mol). It is a physical property of a chemical element or compound that is determined by adding up the atomic masses of all the atoms in the substance's chemical formula.

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Considering the ideal gas law, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:

P×V = n×R×T

In this case, you know:

Replacing in the ideal gas law:

1.50 atm×V = 11.36 moles×0.082\(\frac{atmL}{molK}\) × 298 K

Solving:

V= (11.36 moles×0.082\(\frac{atmL}{molK}\) × 298 K) ÷ 1.50 atm

V= 184.899 L

Finally, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.

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The dissociation of cadmium chloride is as follows: CdCl₂(s) → Cd⁺²(aq) + 2Cl⁻(aq)

Dissociation is the process by which a compound body breaks up into simpler constituents; said particularly of the action of heat on gaseous or volatile substances.

It is a chemical reaction in which a compound breaks apart into two or more components. The general formula for a dissociation reaction follows the form:

AB → A + B

According to this question, cadmium chloride undergoes dissociation into cadmium and chlorine ions as follows:

CdCl₂(s) → Cd⁺²(aq) + 2Cl⁻(aq)

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Answer:

- tectonic plates above the currents move toward each other

- one plate will submerge beneath another plate

- a convergent boundary is formed at the site of the collision

Explanation:

Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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Although the data for the experiment was not provided, we can offer a generalized answer in that when performing an experiment to achieve absolute zero temperatures, the value will never match the exact value.

Absolute zero is the lower limit of temperature. It is considered the coldest possible temperature that can exist. However, any attempt to reach this temperature in a controlled environment has failed, scientists do not think it is possible to recreate this temperature.

Therefore, we can confirm that the value of the absolute zero experiments did not match the accepted value. If the hypothesis was that it would be difficult or impossible to achieve, then the data would support the hypothesis, otherwise, it would fail to do so.

In summary, absolute zero is a temperature that cannot be recreated in a lab, so the value in this experiment does not match the accepted value and there is no further exploration to be done on this matter.

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Answer:

The stratosphere

Explanation:

Answer:

A carboxylic acid group (-COOH) can form more hydrogen bonds with water than an ester group (-COO-).

Explanation:

The carboxylic acid group (-COOH) is found in the carboxylic acids. This group is ultimately responsible for the solubility of carboxylic acids in water. It is worthy of note that the high boiling points of low molecular weight carboxylic acids is often because they are capable of intermolecular hydrogen bonding which leads to the dimerization of carboxylic acid.

The solubility of carboxylic acids decreases as the length of the alkyl chain increases. Hence, a long chain carboxylic acid is less soluble in water than shorter chain carboxylic acids.

Ester molecules can't form hydrogen bonds with each other but they do form weak hydrogen bonds with water. This leads to the solubility of low molecular weight esters. However, if a carboxylic acid and an ester posses the same length of alky chain, the carboxylic acid will form more hydrogen bonds and thus be more soluble in water than than a corresponding ester of the same chain length.

The pressure of the environment affects the liquid's boiling point. The boiling point of the liquid is higher when it is under high pressure than when it is under normal atmospheric pressure. For a given pressure, various liquids have different boiling points.

The temperature at which a liquid's vapour pressure equals the surrounding atmosphere is known as the boiling point of the liquid. This temperature causes the liquid to become a vapour.

The temperature of the liquid, the pressure of the atmosphere, and the pressure of the vapour all affect its boiling point.

We know that change in temperature of a system is given by the following formula:

Initial boiling point (T₁) = 80.1 °C

ΔT = T₂ - T₁

2.25 = T₂ - 80.1

T₂ = 82.35  °C

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Answer:

82.35

Explanation:

acellus

Answer:

8 moles

Explanation:

The total moles of ions that would be formed is 8.

From the equation of dissociation:

    \(NaOH --> Na^+ + OH^-\)

1 mole of NaOH dissociates to give 1 mole  \(Na^+\) and 1 mole \(OH^-\).

Hence, 4 moles of NaOH will also give 4 moles of  \(Na^+\) and 4 moles of \(OH^-\).

Therefore, the total moles of ions that will be formed:

 4 moles \(Na^+\) + 4 moles \(OH^-\) = 8 moles.

Taking into account the definition of ion and a strong base, the total moles of ions that will be formed will be 8.

An ion is an atom or group of atoms with an electrical charge. Ions with a positive charge are called cations, while those with a negative charge are called anions.

On the other side, a Strong Base is that base that in an aqueous solution completely dissociates into the cation and hydroxide ion.

Let BOH be a Strong Base, then the dissociation reaction will be:

BOH → B⁺ + OH⁻

In this case, NaOH is a strong base. Then, the dissociation reaction will be:

NaOH → Na⁺ + OH⁻

Since NaOH will completely dissociate in water, 4 moles of NaOH will form 4 moles of Na⁺ and 4 moles of OH⁻.  Then 4 cations and 4 anions are formed.

The total moles of ions that will be formed will be the sum of the cations and anions formed:

4 cations + 4 anions= 8 ions

In summary, the total moles of ions that will be formed will be 8.

Learn more:

The mass percent of benzoic acid in the sample is 55.5%.

The equation of the reaction is; HC7H5O2(aq) + NaOH(aq) ----> NaC7H5O2(aq) + H2O(l)

Number of moles of NaOH reacted = concentration × volume

Number of moles of NaOH reacted = 10.59/1000 L × 0.1546 M

Number of moles of NaOH reacted = 0.0016 moles of NaOH

Since the reaction is 1:1, 0.0016 moles of HC7H5O2 reacted also.

Hence, mass of HC7H5O2 = 0.0016 moles × 122 g/mol = 0.1952 g

Mass percent of HC7H5O2 in the original sample = 0.1952 g/ 0.3518 g × 100 = 55.5%

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Answer:

Option D

Explanation:

Parent isotope has 83 protons, daughter isotope has only one more proton (84). Beta particle is very small, atomic mass of 212 stays the same in beta decay.

\(^2^1^2_8_3Bi\;\rightarrow\;^2^1^2_8_4Po\;+\;^0_-1e\) represents a beta decay. Parent isotope has 83 protons, daughter isotope has only one more proton (84). Beta particle is very small, atomic mass of 212 stays the same in beta decay.

In nuclear physics, beta decay (β-decay) is a type of radioactive decay in which a beta particle (fast energetic electron or positron) is emitted from an atomic nucleus, transforming the original nuclide to an isobar of that nuclide.

\(^2^1^2_8_3Bi\;\rightarrow\;^2^1^2_8_4Po\;+\;^0_-1e\)

In beta decay, one of the neutrons in the nucleus suddenly changes into a proton, causing an increase in the atomic number of an element.

Hence, option D is correct.

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Answer:

radius = 16 in ; height = 27 in

This problem is providing us with the volume of toluene, 0.16 m³, and the local ventilation rate 28.34 m³/min,  that is inside a drum at 30 °C and 1 atm. Thus, the time to evaporate all of the toluene is required as well as the parts per million in the drum, and found to be 96.2 min and 3.77 ppm respectively.

In mass transfer problems, ventilation involves mass transfer coefficients, cross-section area and saturation pressure, that we can calculate for this problem as shown below:

\(A=\frac{\pi}{4}*0.92m^2=0.665 m^2\\\\k=0.83\frac{cm}{s} (\frac{18.02g/mol}{92.13g/mol} )^{\frac{1}{3} }=0.482\frac{cm}{s}=0.00482\frac{m}{s}\\ \\ P_{sat}=exp(16.0137-\frac{3096.52}{53.67+303} )mmHg*\frac{1atm}{760mmHg}=2.01 atm\)

After that, we can calculate the rate at which the toluene is evaporated:

\(Qm=\frac{M_{tol}*k*A*P_{sat}}{RT}\\ \\Qm=\frac{(92.13\frac{g}{mol})(0.00482\frac{m}{s})(0.665m^2)(2.01atm)*\frac{1000L}{1m^3} }{(0.08206\frac{atm*L}{mol*K} )(303K)}=23.77\frac{g}{s}\)

Where all mol, m, atm, L and atm are cancelled out. Next, given the volume of toluene and its density at 30 °C, 0.8574 g/mL, one can calculate its mass and hence the time to evaporate it all:

\(m_T=0.16m^3*\frac{1x10^6 mL}{1m^3} *0.8574\frac{g}{mL}=137,184g\)

\(t=\frac{137,184g}{23.77\frac{g}{s} } =5771.3 s*\frac{1min}{60s} \\\\t=96.2min\)

Next, the concentration of toluene in parts per million can be calculated with the rate at which toluene is evaporated and the local ventilation rate via the following equation:

\(Cppm=\frac{Qm*R*T}{K*Qv*P*M_T} \\\\Cppm=\frac{(23.77\frac{g}{s}*\frac{1min}{60 s} )(0.08206\frac{atm*L}{mol*K} )(303K)}{(28.34\frac{m^3}{min}*\frac{1000L}{1m^3} )(1atm)(92.13\frac{g}{mol} )} *10^6\\\\Cppm=3.77ppm\)

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Explanation:

Find out number of molecules first. To find out number of molecules, first we need to know the number of moles present. The number of moles can be obtained by dividing the weight by molecular mass. The Molecular mass of water is 18. Now, by multiplying the moles with the Avogadro number we can find out the number of molecules. Avogadro number is 6×(10 to the power 23). Hence the final result is 3.7/18 ×6 × ( 10 to the power 23).

Hope this helps, if not I'm very sorry.

Answer:

Concepts and reason

Lewis structure is a structure that explains the bonding between atoms of a molecule and lone pair of electrons that is present in the molecule is called a Lewis structure.

With the help  of Lewis structure the electronic geometry of a molecule can be determine.

Fundamentals

According to Lewis structure, every atom and their position in the structure of a molecule by using its chemical symbol.

Lines connecting the atoms that are bonded to them are drawn. Lone pairs are expressed by pairs of dots and are located beside the atoms.

Lewis structure  of \(H_{2}O\) is, the total number of valence electrons is eight in \(H_{2}O\).

Approximately 766.08 grams of oxygen are required to completely react with 240g of C₂H₆.

To determine the amount of oxygen required to completely react with 240g of C₂H₆ (ethane), we need to set up a balanced chemical equation for the combustion of ethane.

The balanced equation for the combustion of ethane is as follows:

C₂H₆ + O₂ → CO₂ + H₂O

From the balanced equation, we can see that the stoichiometric ratio between C₂H₆ and O₂ is 1:3. This means that for every one mole of C₂H₆, three moles of O₂ are required for complete combustion.

To calculate the amount of oxygen required, we need to convert the given mass of C₂H₆ to moles using its molar mass, and then use the stoichiometric ratio to determine the moles of O₂ required. Finally, we can convert the moles of O₂ back to grams using the molar mass of oxygen.

The molar mass of C₂H₆ is calculated as follows:

(2 x atomic mass of carbon) + (6 x atomic mass of hydrogen)

(2 x 12.01 g/mol) + (6 x 1.01 g/mol) = 30.07 g/mol

Now, we can proceed with the calculation:

Calculate the moles of C₂H₆:

moles of C₂H₆ = mass of C₂H₆ / molar mass of C₂H₆

moles of C₂H₆ = 240 g / 30.07 g/mol ≈ 7.98 mol

Determine the moles of O₂ using the stoichiometric ratio:

moles of O₂ = moles of C₂H₆ x (3 moles of O₂ / 1 mole of C₂H₆)

moles of O₂ = 7.98 mol x 3 ≈ 23.94 mol

Convert moles of O₂ to grams:

mass of O₂ = moles of O₂ x molar mass of O₂

mass of O₂ = 23.94 mol x 32.00 g/mol = 766.08 g

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The mass of water that reacted in the equation is 29.5 g.The balanced chemical equation for the decomposition of water into hydrogen gas and oxygen gas helps us to determine this.

The balanced chemical equation for the decomposition of water into hydrogen gas and oxygen gas is:

2H₂O → 2H₂ + O₂

From the equation, we can see that 2 moles of water produce 1 mole of oxygen gas. We also know that the volume of the oxygen gas produced is 18.5 L at STP (standard temperature and pressure), which is 0 °C and 1 atm.

To find the amount of water that reacted, we need to use the ideal gas law to calculate the number of moles of oxygen gas produced. The ideal gas law is:

PV = nRT

Where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the gas constant, and T is the temperature of the gas in Kelvin.

At STP, the pressure is 1 atm and the temperature is 273 K, so we can simplify the ideal gas law to:

V = nRT/P

Substituting the given values, we have:

18.5 L = n x 0.0821 L atm/(mol K) x 273 K/1 atm

Solving for n, we get:

n = 0.819 mol

From the balanced chemical equation, we know that 2 moles of water produce 1 mole of oxygen gas. Therefore, the number of moles of water that reacted is:

0.819 mol O₂ x (2 mol H₂O/1 mol O₂) = 1.638 mol H₂O

Finally, we can convert the number of moles of water to mass using the molar mass of water, which is 18.015 g/mol:

1.638 mol H₂O x 18.015 g/mol = 29.5 g H₂O

Therefore, the mass of water that reacted is 29.5 g.

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Answer:

The characteristics of cathode rays do not depend upon the material of electrodes and the nature of the gas present in the cathode ray tube.

Answer:

In solids, the atoms are tightly packed together. In gases, atoms are spread out.

Explanation:

Answer::

Lower rate of reaction

Explanation:

Lower concentration of reactant in an experiment is indicative of fewer ions or atoms present, which means a slower rate of reaction. In a titration reaction for instance, the end point would take longer to be substantiated, thereby increasing volume of titres. This is further backed up by collision theory which states that more particles in a system improves combinations of molecules.

This however may not be the case if the iodine in question is  catalyst, in which case the change in concentration has no effect whatsoever on the reaction rte.

I hope this explanation fits the brief.

Answer:

To solve this problem, we can use the definition of percent concentration by mass:

percent concentration = (mass of solute ÷ mass of solution) x 100%

We know that the percent concentration of NaCl in the solution is 15% by mass, and we have a 500 gram sample of the solution. Let's assume that the mass of NaCl in the sample is x grams.

Using the percent concentration formula, we can write:

15% = (x ÷ 500) x 100%

Simplifying this equation, we get:

x = (15 ÷ 100) x 500 = 75 grams

Therefore, there are 75 grams of NaCl in a 500 gram sample of the solution.

The correct answer is c. 75 grams.

Answer:

water molecule...glucose..chloroplast...cell...leaf

The structure of the order from smallest to the largest should be shown below:

The order of the series are as follows:

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