The SUNSDR2 DX uses SO-239 connectors for antenna connections.
The SUNSDR2 DX is a high-performance transceiver designed for DXing, contesting, and casual operating. It comes with two SMA connectors for VHF/UHF and a set of SO-239 connectors for HF and 6m bands. The SO-239 is a type of coaxial connector that is commonly used for antenna connections. It is also known as a UHF connector because it was originally designed for use with UHF radio systems.
The SO-239 connector consists of a center pin and a threaded outer ring that is connected to the shield of the coaxial cable. The center pin is typically used for the signal, while the outer ring is used for the ground. This type of connector is easy to use, and it provides a secure and reliable connection that is resistant to corrosion and other forms of damage.
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A substance has life of 40 years. In how many years will the substance disintegrate to 1/8 of its initial size
Answer:
5 years
Explanation:
\(\frac{1}{8}(40)\\\\= 5\)
What does the word "kinetic" in the Kinetic Theory Model say about particles in matter?
A. Energy does not affect them.
B. They are moving.
C. They're constantly in place.
D. They are growing.
The word "kinetic" in the Kinetic Theory Model says particles are moving. Option B
What should you know about Kinetic Theory Model?The Kinetic Theory Model helps us to explain the physical properties of gases.
The model famously states that gases are made up of tiny particles that are in constant, random motion.
How slow or fast the motion is, and thus the kinetic energy, depends on the temperature.
When the temperature is high, it will result in greater motion.
The Kinetic Theory Model is a very popular and has been used to explain many different physical phenomena.
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If driver A drove for 10 hours Driver b drove for 7 1/2 hours Driver C drove for 6 1/2 hours driver d drove for 9 hours how many hours total did they all drive
Answer:
33 hours
Explanation:
7.5 + 6.5 = 13 + 1
14 + 10 = 24
9= 6+3
24 + 6 = 30
30+3= hours
HELP IT'S DUE TOMORROW ;w;
Give an example of each of the following types of matter:
a) heterogeneous mixture:
b) homogeneous mixture:
c) element:
d) compound:
The two equations below express conservation of energy and conservation of mass for water flowing from a circular hole of radius 3 centimeters at the bottom of a cylindrical tank of radius 10 centimeters. In these equations, ? m is the mass that leaves the tank in time At, v is the velocity of the water flowing through the hole, and h is the height of the water in the tank at time t. g is the accelertion of gravity, which you should approximate as 1000 cm/s2. The first equation says that the gain in kinetic energy of the water leaving the tank equals the loss in potential energy of the water in the tank. The second equation says that the rate at which water leaves the tank equals the rate of decrease in the volume of water in the tank (which is conservation of mass because water has constant density) 10' Derive a differential equation for the height of water in the tank. dh dt If the initial height of the water is 30 centimeters, find a formula or the solution h(t) According to the model, how long does it take to empty the tank? Another way to solve this differential equation is to make the substitution w h. What is the differential equation that w satisfies? seconds dw dt
The differential equation for the height of water in the tank is: dh/dt = -k * sqrt(h) . If the initial height of the water is 30 centimeters, then the solution to the differential equation is: h(t) = 30 * exp(-kt^2)
According to the model, it takes 15 seconds to empty the tank. The first equation states that the gain in kinetic energy of the water leaving the tank equals the loss in potential energy of the water in the tank.
The second equation states that the rate at which water leaves the tank equals the rate of decrease in the volume of water in the tank. We can combine these two equations to get the following differential equation:
dh/dt = -k * sqrt(h)
where k is a constant that depends on the radius of the hole and the acceleration of gravity.
If the initial height of the water is 30 centimeters, then we can solve the differential equation to get the following solution:
h(t) = 30 * exp(-kt^2)
where t is the time in seconds.
Plugging in t=15, we get h(15)=0, which means that the tank is empty after 15 seconds.
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Would Lincoln, Nebraska or San Diego, California have a smaller range in average monthly temperatures
Answer: San diego
Because it is closer to the ocean
How does the Coriolis effect impact the Gulf Stream and the Brazil Current?
Answer: The Coriolis effect results in bending the direction of surface currents to the right in the Northern Hemisphere and left in the Southern Hemisphere. The Coriolis effect causes winds and currents to form the circular patterns. The direction in which they spin depends upon the hemisphere in which they are present.Coriolis Effect is named after the French mathematician and physicist Gaspard-Gustave de Coriolis. It affects the weather patterns of an area, it affects the ocean currents, and it also affects air quality.
in a region of the atmosphere in which the temperature falls with increasing altitude
The region in which the temperature falls with increasing altitude is troposphere and mesosphere.
Atmosphere is one of the physical components of the earth and is divided into five major layers of gases called troposphere, stratosphere, mesosphere, thermosphere and exosphere.
As we go upward in some layers the temperature decreases while in others it increases. The different levels of atmosphere has different temperature.
The temperature of troposphere is low because its has receive low amount of solar radiation. On the other hand, the temperature of stratosphere is higher because it traps the incoming radiations.
Similarly, in mesosphere the solar radiations are absorbed very little and this is responsible for cooling in mesosphere.
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A current of 1,5A flows when the circuit is connected to a battery with an emf of 30 v as inducted
Answer:
Resistance = 20
Explanation:
From ohm's law r = v/i30/1.5 = 20A car with a weight of 6996 N is subjected to a net force of 1.74e4. The cars acceleration will be
Answer: 24.37 m/s/s [forward] = a
Explanation:
First, find mass with the Fgrav formula.
Fgrav=mg
6996=m(9.8)
713.88 kg
Then, plug the answer into Newton's second law formula.
Fnet = ma
1.74e4 = (713.88)a
(1.74e4)/(713.88) = a
24.37 m/s^2 = a
how much work is needed to push a 107- kg packing crate a distance of 2.75 m up an inclined plane that makes an angle of 30 o with the horizontal, when inclined plane is frictionless? tries 0/12 the coefficient of friction between the crate and the inclined plane is 0.22?
The work needed to push the 107-kg packing crate a distance of 2.75 m up the frictionless inclined plane with an angle of 30 degrees is approximately 448.18 Joules.
To calculate the work needed to push the packing crate up the inclined plane, we need to consider the forces involved and the displacement of the crate.
Given:
Mass of the crate (m) = 107 kg
Distance moved up the inclined plane (d) = 2.75 m
Angle of the inclined plane (θ) = 30 degrees
Coefficient of friction between the crate and the inclined plane (μ) = 0.22
First, let's calculate the component of the crate's weight (mg) that acts parallel to the inclined plane. This component is given by:
F_parallel = mg * sin(θ)
F_parallel = 107 kg * 9.8 m/s^2 * sin(30 degrees)
F_parallel ≈ 514.13 N
Next, let's calculate the work done against this force while moving the crate up the inclined plane. The work done is given by:
Work = Force * Distance * cos(θ)
Since the inclined plane is frictionless, there is no additional force to overcome. Therefore, the work done against the force of gravity is equal to the work needed to push the crate up the inclined plane.
Work = F_parallel * d * cos(θ)
Work = 514.13 N * 2.75 m * cos(30 degrees)
Work ≈ 448.18 J
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instruments used to measure the following quantities Mass weight length time and density of a liquid
Answer:
Mass: Beam balance
Weight: Beam balance
Length: Ruler
Time: Clock
Density of liquid: Hydrometer
in which condition does relative velocity becomes zero .why? Please answer fast as possible
Answer:
It is zero when two bodies are moving in the same direction, the same velocity, and through the same medium
Explanation:
Not sure how to explain it I’m sorry
Explanation:
➠➢ The relative velocity becomes zero when the two bodies move in the same direction with the same velocity. When a person sits on the chair, the relative velocity of the person with respect to the chair is zero. The relative velocity of the chair with the person is also zero.
ᴷᴵᴺᴳ°᭄Ⱨ₳₵₭ɆⱤ㋡
How could nanotechnology best be used to improve the treatment of cancer with chemotherapy?
A. A nanometer-size carrier could be designed to bring the chemotherapy drugs only to cancer cells.
B. A nano carbon wire could be designed that would aid in the manufacture of chemotherapy drugs.
C. A quantum dot could be used to watch where the chemotherapy drugs go in the body.
D. Biomaterials could be made that would allow for cell growth within the cancer cells so that they are easier to find.
Answer: A
Explanation: Edg2020
Which letter explains why no machine is 100 percent efficient.
A.Mechanical energy is transformed into thermal energy by friction.
B.Mechanical energy is transformed into electrical energy by a spark.
C.Thermal energy is transformed into mechanical energy by friction.
Answer:
A
Explanation:
Think about rubbing your hands together- the friciton produces heat
Assume the average density of the Universe is equal to the critical density. (a) Prove that the age of the Universe is given by 2 /(3 H) .
The age of the Universe is given by: ∫₀¹ 2(da/a) = ∞ + (2kc²/ H²). Since we assume that the average density of the Universe is equal to the critical density, we have k=0, and the age of the Universe is given by = 2 / (3H)
The Friedmann equation, which describes the evolution of the Universe, is given by: H² = (8πGρ/3) - (kc²/ a²)
where H is the Hubble constant, ρ is the density of the Universe, G is the gravitational constant, k is the curvature of the Universe, and a is the scale factor.
If we assume that the average density of the Universe is equal to the critical density, then ρ = ρcrit, and the first term on the right-hand side of the equation becomes:
H² = (8πGρcrit/3) - (kc²/ a²)
We can rewrite this equation in terms of the scale factor a by taking the time derivative of both sides:
2H(dH/da) = -(8πGρcrit/3a²) + (2kc²/ a³)
We can simplify this equation by dividing through by H and multiplying by a:
2(da/a) = -(8πGρcrit/3H²a) + (2kc²/ H²a²)
The left-hand side of this equation gives us the change in the scale factor with respect to time. If we integrate this expression from
a=0 (the Big Bang) to
a=1 (the present day), we get the age of the Universe:
∫₀¹ 2(da/a) = ∫₀¹ -(8πGρcrit/3H²a) + (2kc²/ H²a²)
Integrating the left-hand side gives:
2ln(1) - 2ln(0)
= 2ln(1) - 2ln(0)
= 0
Integrating the first term on the right-hand side gives:-
∫₀¹ (8πGρcrit/3H²a) da
= -(8πGρcrit/3H²) ∫₀¹ da/a
= -(8πGρcrit/3H²) [ln(1) - ln(0)]
= ∞
Integrating the second term on the right-hand side gives:
∫₀¹ (2kc²/ H²a²) da
= (2kc²/ H²) ∫₀¹ da/a²
= (2kc²/ H²) [1 - 0]
= (2kc²/ H²)
Therefore, the age of the Universe is given by:
Age = ∫₀¹ 2(da/a)
= ∞ + (2kc²/ H²). Since we assume that the average density of the Universe is equal to the critical density, we have k=0, and the age of the Universe is given by: Age = 2 / (3H)
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You can buy an expensive frying pan that is made of copper but has a handle made of stainless steel. Why are different metals used for the part of the pan that touches the stove and for the part that touches your hand?
The use of different metals in a frying pan, such as copper for the base and stainless steel for the handle, is due to their unique properties that cater to the specific functions of each part.
Copper is an excellent conductor of heat, which means it can quickly and evenly distribute heat across its surface. This property makes it an ideal choice for the part of the pan that touches the stove, as it ensures efficient cooking and prevents hot spots that could cause uneven cooking or burning.
On the other hand, stainless steel is used for the handle because it has low thermal conductivity compared to copper. This means that it does not conduct heat very well, which is advantageous for a handle as it keeps it cooler to the touch and safer for the user to handle during the cooking process. Additionally, stainless steel is durable, resistant to corrosion, and easy to maintain, making it a practical choice for the handle.
In summary, the combination of copper and stainless steel in a frying pan serves to optimize its performance and safety. The copper base ensures efficient heat distribution, while the stainless steel handle keeps the user's hand protected from the heat generated during cooking. This thoughtful design addresses the needs of both cooking and handling, resulting in a high-quality and functional kitchen tool.
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A satellite is in a circular orbit around Earth. Which of the following
scenarios will increase the period of the satellite?
a. decreasing the radius of the orbit
b. increasing the mass of the satellite
c. increasing the mass of Earth
d. decreasing the velocity of the satellite
A satellite is in a circular orbit around Earth, so the scenario that will increase the period of the satellite is decreasing the radius of the orbit, which is in Option A because it is determined by the radius of the orbit and the mass of Earth.
What is the period of the satellite?The motion of a satellite in a circular orbit around a central body, such as Earth, is governed by the balance between the gravitational force acting on the satellite and the centripetal force required to keep the satellite in its circular path, so the period is proportional to the square root of the cube of the radius, so decreasing the radius will increase the period.
As a result, the scenario in Option A that increases the satellite's period is when the the orbit's radius decreases.
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What is the estimated effective nuclear charge, zeff, experienced by an electron in a 3p orbital of a chlorine atom?.
estimated effective nuclear charge experienced by a 3 p electron of chlorine is 6.1.
What is nuclear charge ?
In atomic physics, the net nuclear charge is the actual amount of positive (nuclear) charge experienced by electrons in a multi-electron atom. The term "effective" is used because the shielding effect of negatively charged electrons prevents higher energy electrons from experiencing the full nuclear charge of the nucleus due to inner layer repulsive effects. The net nuclear charge experienced by an electron is also called the nuclear charge. The strength of the nuclear charge can be determined by the oxidation number of the atom. Most of the physical and chemical properties of elements can be described in terms of their electronic configurations. . It is known that the magnitude of the ionization potential depends on the following factors:
atomic size;
nuclear charge;
Inner shell shielding effect u
The extent to which the outermost electrons penetrate the charge cloud created by the inner electrons.
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Which statement accurately describes the relationship between weight and
mass?
A. Mass is an object's weight multiplied by its diameter.
B. Weight is an object's mass multiplied by its diameter.
C. Mass is an object's weight multiplied by the amount of
gravitational force acting on that object.
O D. Weight is an object's mass multiplied by the amount of
gravitational force acting on that object.
Answer:
D. Weight is an object's mass multiplied by the amount of
gravitational force acting on that object.
Explanation:
I got it right on the test
Weight is an object's mass multiplied by the amount of gravitational acceleration acting on that object. Hence, option (D) is correct.
What are mass and weight?The most fundamental characteristic of matter is its mass, which is one of the fundamental physical quantities. Mass is a term used to describe how much matter is there in a body. The kilograms is the SI unit of mass.
The amount of a body's weight indicates how much gravity is pulling on it. The weight formula is as follows: w = mg Since weight is a force, it has the same SI unit as a force, which is the Newton.
When we look at how weight is expressed, we can see that it depends on both mass and the acceleration caused by gravity. Hence, weight is an object's mass multiplied by the amount of gravitational acceleration acting on that object.
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Helen can write 15 postcards in one hour, while Kate can write
20 postcards. How much longer would Helen take to write 300
postcards than Kate?
hours
Answer:5 hours
Explanation:
300 divided by 20 = 15
300 divided by 15 = 20
the difference is 5
a pilot flies in a straight path for 1 h 30 min. she then makes a course correction, heading 10 degrees to the right of her original course, and flies 2 h in the new direction. if she maintains a constant speed of 690 mi/h, how far is she from her starting position? your answer is mi;
The total distance covered by the pilot is:S1 + S2 = 1035 + 1380 = 2415 miles (approx) Therefore, the pilot is about 2415 miles away from her starting position. Answer: 2415
Pilot flies for 1 hour 30 minutes = 1.5 hours Pilot flies for 2 hours Pilot maintains a constant speed of 690 mi/h Formula: Distance = Speed × Time We know that distance covered along the original course is given by:S1 = Speed × Time1.
Total distance covered is given by:S1 + S2From the given information,Time1 = 1.5 hoursTime2 = 2 hoursSpeed = 690 mi/hCalculations:S1 = Speed × Time1S1 = 690 × 1.5S1 = 1035 miles (approx)S2 = Speed × Time2S2 = 690 × 2S2 = 1380 miles (approx).
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NEED HELP FAST PLEASE
Answer:
if a star is moving towards earth it is blue shifting
Will mark as brainliest !! plz answer it
Plzzz answer with explnation!!!
the value of acceleration due to gravity (g) will be maximum at:
.
a) 1/2 of the radius of earth
b) 1/4 of the radius of earth
c) 1/8 of the radius of earth
the 2-lb brick slides down a smooth roof, such that when it is at a it has a velocity of 5 ft/s.
The unstretched length so that it does not allow the block to leave the surface until θ= 60° is L = 4.574 ft.
Given:
The weight of the block W = 2 lb
The initial velocity of the block v_i = 0
The stiffness of the spring k = 2 lb/ft
The radius of the cylindrical surface r = 2 ft
Compute the velocity of the block at θ= 60°. Use Newton's second equation of motion in direction normal to the surface.
= F_n = m X a_n
Where, a_n is the centripetal acceleration or normal component of acceleration as follows:
= a_n = v²_2 / r
Substitute:
= F_n = m*v²2 / r
Where, F_n normal force acting on block by the surface is:
= F_n = W X cos(θ)
Substitute:
W*cos(θ) = m*v^2_2 / r
v_2 = sqrt ( r*g*cos(θ) )
Plug in the values:
v²_2 = 2 X 32.2 X cos(60)
v²_2 = 32.2 (ft/s)²
Apply the conservation of energy between points A and B where θ= 60° :
T_A + V_A = T_B + V_B
Where,
T_A : Kinetic energy of the block at initial position = 0
V_A: potential energy of the block initial position
V_A = 0.5 X k X x_A²
x_A = 2 X π- L ( L is the original length )
V_A = 0.5X 2 X (2 X πi - L)² =
= (2 X pi - L)²
T_B = 0.5 X W/g X v_2² =
= 0.5 X 2 / 32.2 X 32.2 = 1
V_B = 0.5 X k X x_B² + W X 2 X cos(60)
and, x_B = 2 X 0.75 X π - L ( L is the original length )
V_B = 0.5 X 2 X (1.5 X π - L)² + 2 X 1
= 2 + ( 1.5 X π- L )²
Input the respective energies back in to the conservation expression:
= 0 + (2π - L)² = 1 + 2 + ( 1.5π - L )²
= 4π² - 4πL + L² = 3 + 2.25π² - 3πL + L²
= πL = 1.75π² - 3
= L = 4.574 ft
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The complete question;
the 2-lb brick slides down a smooth roof, such that when it is at a it has a velocity of 5 ft/s. The 2-lb block is released from rest at A and slides down along the smooth cylindrical surface. Of the attached spring has a stiffness k = 2 lb/ft. Determine its unstretched length so that it does not allow the block to leave the surface until θ= 60°.
PLEASE HELP MEE
Read the question below and pick the correct answer.
Answer:
uhh
Explanation:
other astronomers were skeptical about percival lowell's claims of martian canals because
Many astronomers were skeptical about Percival Lowell's claims of Martian canals for several reasons.
First and foremost, the technological limitations of the time made it difficult to obtain clear and detailed observations of Mars. The telescopes available in Lowell's era were not powerful enough to discern fine surface details on the planet, leading to potential misinterpretations.
Furthermore, other astronomers failed to reproduce Lowell's observations and saw no evidence of the linear features he described as canals. They argued that the perceived canals could be optical illusions or artifacts resulting from poor atmospheric conditions or the limitations of the telescopes used.Additionally, advances in understanding Mars and its geology, particularly through space missions and improved telescopes, have provided a wealth of evidence contrary to Lowell's claims. Modern investigations have revealed that Mars does not possess an extensive network of artificial canals but instead exhibits natural features such as valleys, craters, and ancient riverbeds, which can be misinterpreted if not carefully analyzed.Consequently, due to these factors, skepticism prevailed among many astronomers regarding Percival Lowell's claims of Martian canals, and subsequent scientific advancements have provided a more accurate understanding of the Red Planet's surface features.
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A bottle of soda always has a space between the cape and the top of the liquid. Explain
Answer:
All soft drinks contain water. When soft drink bottles are chilled in sub-zero temperatures, the water on account of its anomalous expansion expands. Thus, to provide space for expanding water, soft drink bottles are not completely filled as otherwise they will burst.
Explanation:
Answer:
Soft drink bottles are filled leaving some space between the lid/cap and the liquid level.
Explanation:
The reason is that the soft drinks are cooled below room temperature. Sometimes they are kept in the hot Sun and weather. They are subject to a big temperature variation. Also, there are gases like CO2 mixed in the drink. So the gases come out of the liquid and expand due to heat. That creates high pressure.
Water expands when it is cooled to 4 deg. C. But the bottle (glass) contracts when it is cooled. So if there is no air gap, then volume of water (cool drink) will become more than the inside volume of the bottle. Then the bottle will break due to pressure from water expansion around 8 deg. to 4 deg.C.
When a bottle is opened, due to pressure difference, and temperature difference, the gases come out of drink in the form of bubbles. So cold drink overflows out.
Also, the soft drink bottles are capped tightly. When an opener is used to open it using some force upwards, the pulling force also moves the soft drink bottle upwards. So just after the lid comes off, the top part of the drink comes out due to the pull. So some drink spills on people who open or, it falls outside.
In order to prevent these problems, some gap is left open between the surface of the soft drink and the top of the bottle.
The Figure 6A-2 Stüve diagram includes lines representing the adiabatic processes of dry (unsaturated) and saturated air. Click on Figure 6A-2 to print or draw on it digitally. Figure 6A-2. Vertical atmospheric (Stüve) chart with adiabats. On the Stüve diagram, the solid, straight green lines from upper left to the lower right represent the dry adiabatic lapse rate: the temperature change of an unsaturated air parcel undergoing vertical motion in the atmosphere. The dashed, curved blue lines from upper left to lower right represent the temperature change of saturated air undergoing vertical motion, the saturated adiabatic lapse rate. Locate an air parcel with a temperature of 17
∘
C and a pressure of 1000mb by placing a dot on the chart on the 1000mb horizontal line where 17
∘
C would occur. 7. If this air rises as unsaturated (dry) air from 1000mb, determine its temperature at 500mb by following the solid, straight green dry adiabatic lapse rate line from the starting point, up to 500mb. At 500mb, the temperature of the unsaturated air parcel is about
∘
C. a. −5 b. −35 c. −45 8. If this air rises as saturated air from 1000mb, determine its temperature at 500mb by following the dashed, curved blue saturated adiabatic lapse rate line passing from the starting point up to 500mb. At 500mb, the saturated air parcel's temperature is approximately
∘
C. a. −15 b. −25 c. −35 9. At 500mb, the temperature of the unsaturated air parcel is the temperature of the saturated air parcel. a. lower than b. the same as c. higher than 10. This comparison demonstrates that rising unsaturated, clear air cools than rising saturated, cloudy air over the same pressure change. a. less b. more
When an air parcel rises from 1000mb to 500mb, unsaturated air cools to around -35°C, while saturated air cools to approximately -25°C.
On the Stüve diagram, the solid, straight green lines represent the dry adiabatic lapse rate, which indicates the temperature change of an unsaturated air parcel undergoing vertical motion in the atmosphere. The dashed, curved blue lines represent the temperature change of saturated air undergoing vertical motion, known as the saturated adiabatic lapse rate.
To determine the temperature of the air parcel at 500mb when it rises as unsaturated air, we follow the solid, straight green dry adiabatic lapse rate line from the starting point (17°C, 1000mb) up to 500mb. Following this line, we find that at 500mb, the temperature of the unsaturated air parcel is approximately -35°C.
On the other hand, if the air parcel rises as saturated air, we follow the dashed, curved blue saturated adiabatic lapse rate line from the starting point (17°C, 1000mb) up to 500mb. By following this line, we determine that at 500mb, the temperature of the saturated air parcel is approximately -25°C.
Comparing the temperatures of the unsaturated and saturated air parcels at 500mb, we find that the temperature of the unsaturated air parcel (-35°C) is lower than the temperature of the saturated air parcel (-25°C). Therefore, at 500mb, the temperature of the unsaturated air parcel is lower than the temperature of the saturated air parcel.
This comparison demonstrates that rising unsaturated, clear air cools more than rising saturated, cloudy air over the same pressure change.
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please match the luminosity class to the description. not all answers will be used.-these extremely luminous stars are among the largest ever observed and represent the very short-lived old age phase of high mass stars.-these luminous stars represent the short-lived old age phase of low mass stars. when our sun hits this phase, it could become large enough to engulf the earth.-this phase represents the longest stage of a star's life. this luminosity class has stars with a large range in temperature (hottest to coolest) and luminosity (brightest to dimmest), but they are all bound by one common trait: they are powered by hydrogen fusion only in the core of the star.
The core of a red giant is contracting, but the outer layers are expanding as a result of hydrogen fusion in a shell outside the core
Nuclear fusion of hydrogen to form helium happens evidently in the solar and different stars. It takes area best at extremely high temperatures. Scientists are attempting to find methods to create controlled nuclear fusion reactions on earth.
Researchers at Lawrence Livermore countrywide Laboratory's country-wide Ignition Facility in California have spent over a decade perfecting their method and the feature now showed that the landmark test conducted on eight August 2021 did, in fact, produce the primary-ever successful ignition of a nuclear fusion reaction.
People had been capable of cause fusion, but in methods that might be uncontrolled, like in thermonuclear guns sometimes called hydrogen bombs. Fusion has additionally been proven in laboratories, but below conditions that eat a long way, extra strength than the reaction produces.
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